i need the answer asap plz!!
A sample of water vapor has a pressure of 36.0 Pa and a temperature of 300.0 K. If the pressure is
reduced to 32.0 Pa, what will the new temperature be?

Answers

Answer 1

Answer:

266.7k

Explanation:

Given parameters:

Initial pressure  = 36Pa

Initial temperature  = 300k

New pressure  = 32Pa

Unknown:

New temperature  = ?

Solution:

To solve this problem, we have to apply the combined gas law when the volume is constant;

in this instant, when the volume is constant, the pressure of a given mass of gas varies directly with the absolute temperature.

          \(\frac{P_{1} }{T_{1} }\)   = \(\frac{P_{2} }{T_{2} }\)  

P and T are pressure and temperature

1 and 2 are initial and final states

  Insert the parameters and solve;

       \(\frac{36}{300}\)   = \(\frac{32}{T_{2} }\)  

      T₂  = 266.7k


Related Questions

19 a.) The length of a white board is 80 cm
and breadth its 65cm. calculate the area.

Answers

area l*b

so,80*65

=5200

Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105

. The figure illustrates the configuration.

A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.

Answers

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height as the point of release.

(a) What is the acceleration of the ball while it is in flight?
magnitude
_____ m/s2
direction
---Select---

(b) What is the velocity of the ball when it reaches its maximum height?
magnitude
_____ m/s
direction
---Select---

(c) Find the initial velocity of the ball.
____ m/s upward

(d) Find the maximum height it reaches.
____ m

A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height

Answers

(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.

Using the equation, we can solve for the acceleration:

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s

Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.

(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.

(c) To find the initial velocity of the ball, we can use the equation:

v = u + at

At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s upward

Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.

(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:

s = ut + (1/2)at^2

At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.

0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2

0 = 47.864 + (-5.5294)

5.5294 = 47.864

Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.

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The side of a cube of metal is measured to be (1.00±0.06) cm and its mass is measured to be (41.0±0.4) g. Determine the uncertainty in the density of the solid in kilograms per cubic meter.

Answers

The density of the solid is (4.10 ± 0.78) × 10^3 kg/m^3.

To calculate the density of the cube below formula can be used:

ρ = m/V

where ρ is density, m is mass, and V is volume. For a cube, the volume is given by:

V = (side)^3

Therefore, the uncertainty in density can be calculated using the formula:

δρ/ρ = sqrt[(δm/m)^2 + 3(δs/s)^2]

where δρ is the uncertainty in density, δm is the uncertainty in mass, δs is the uncertainty in side, and s is the value of the side.

Now, putting in the given values:

s = (1.00 ± 0.06) cm = 0.01 ± 0.0006 m

m = (41.0 ± 0.4) g = 0.0410 ± 0.0004 kg

Volume, V = (0.01 m)^3

                  = 1.0 × 10^-6 m^3

Therefore, the density is:

ρ = m/V

  = 0.0410 kg/1.0 × 10^-6 m^3

  = 4.10 × 10^4 kg/m^3

Now substituting the values and calculating the uncertainty in density:

δρ/ρ = sqrt[(δm/m)^2 + 3(δs/s)^2]

δρ/ρ = sqrt[(0.0004/0.0410)^2 + 3(0.0006/0.01)^2]

δρ/ρ = 0.019

Therefore, the uncertainty in density is:

δρ = (0.019)(4.10 × 10^4 kg/m^3)

     = 779 kg/m^3

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mc2
Describe the process of nuclear fission and how the famous equation E
relates to this process.

Answers

frfyuegffffjhAnswer:

frjhgfjgresjytgfejygfjse

Explanation:


PLEASE HELP AND SHOW WORK,THANK YOU!!
4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?

Answers

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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An enclosed amount of nitrogen gas undergoes thermodynamic processes as follows: from an initial state A to a state B to C to D and back to A, as shown in the P-V diagram. Assume that the gas behaves ideally. (a) If the process A-B is isothermal, determine the pressure of the gas in the state B. (b) Calculate the heat transferred to the gas in the process A-B. (c) Calculate the work done on the gas, the heat transferred to the gas and the change in internal energy for the process B-C. (d) What is the change in internal energy of the gas for the entire process, A-B-C-D-A? point A(0.10,13.0) point B(0.12, P) C(0.135, 5.00) D(0.10, 5.00)........(V,P)

Answers

Answer:

(a) 10.833 kPa

(b) 237.02 J

(c) The work done = -43.75 J

The heat transferred = 43.09 J

The change in internal energy = -0.6575 J

(d) The total change in internal energy for the entire process = 57.5 J

Explanation:

The parameters given are;

p₁ = 13 kPa

V₁ = 0.1 m³

p₂ = p

V₂ = 0.12 m³

p₃ = 5 kPa

V₃ = 0.135 m³

p₄ = 5 kPa

V₄ = 0.10 m³

(a) For isothermal process, we have

p₁V₁ = p₂V₂

p₂ = p₁V₁/V₂

∴ p₂ = 13 × 0.1/0.12 = 10.833 kPa

(b) The heat transfer for a constant temperature process is given by the relation;

\(Q = V_1 \cdot p_1 \cdot ln \left (\dfrac{V_2}{V_1} \right) = 0.10 \times 13 \times ln \left (\dfrac{0.12}{0.10} \right) = 0.237 kJ = 237.02 J\)

(c) For process BC, we have

The work done is given by the area under the curve which between B and C which is given as follows;

0.5 × (V₃ - V₂) × (p₃ - p₂) = 0.5 * (0.135 - 0.12) * (5 -10.833) = -0.0437475 kJ = -43.75 J

For ideal gas, γ = 1.4

The heat transferred Q for a polytropic process is given by the relation

Q = W×(n - γ)/(γ - 1)

W = (V₂ × p₂ - V₃×p₃)(n - 1)

0.0427475  = (10.833 *0.12 - 5*0.135)/(n - 1)

(n - 1) = (10.833 *0.12 - 5*0.135)/0.0437475  =

n = 1 + 0.00575

n = 1.006

Q = -43.75*(1.006 - 1.4)/(1.4 - 1) = 43.09 J

The change in internal energy, u₃ - u₂ = Q + W = 43.09 J - 43.75 J = -0.6575 J

(d) For the constant pressure process DC, we have;

\(Q = c_p \times p \times\dfrac{V_4 - V_3}{R} = \dfrac{5}{2} \times 4 \times (0.1 - 0.135) = -0.35 \ kJ\)

W = p×(v₄ - v₃) = 4*(0.1 - 0.134) = -0.136 kJ

u₄ - u₃ = Q + W = -0.35 - 0.135 = -0.485 kJ

For the constant volume process DA, we have;

\(Q = \dfrac{c_v}{R} \times V \times (p_1 - p_4) = \dfrac{3}{2} \times 0.1 \times (12 - 4) = 1.2 \ kJ\)

Q = u₁ - u₄ = 1.2 kJ

Since process 1 to 2 is a constant temperature process we have u₁ - u₂ = 0

The total change in internal energy = u₁ - u₂ + u₃ - u₂ + u₄ - u₃ + u₁ - u₄

The total change in internal energy = 0 - 0.6575 - 0.485 + 1.2 = 0.0575 kJ = 57.5 J

The total change in internal energy for the entire process = 57.5 J.

Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)

Answers

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Which statement accurately describes what happens when ice melts in terms of energy? The ice absorbs energy which causes in water molecules to have to have more kinetic and potential energy, changing their configuration from solid to a linguist. The ice releases energy which causes chemical bonds to break Changing the ice to matter The ice absorbs energy which causes chemical bonds to break changing ice to water. The ice realeases energy which causes the water molecules to have less kinetic and potential energy changing their configuration from solid to linguistic to liguid

Answers

Answer:

The first one

Explanation:

But I'm not sure though

in a hockey game, player A passes the puck to player B, who is standing on the blue line, as shown in the diagram. The puck travels distance d1=24.1m on its way to player B, making an angle = 52.5 degrees with the x axis. Player B then passes the puck so that it moves d2=7.9m on the blue line in the negative x direction. A) What is the magnitude of the total displacement in meters? B) What angle, in degrees, does the total displacement make with the x axis?

in a hockey game, player A passes the puck to player B, who is standing on the blue line, as shown in

Answers

The magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

Total displacement

The total displacement of the player is calculated as follows.

Apply cosine rule as shown below;

d² = d₁² + d₂² - 2d₁d₂ cos(θ)

d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)

d² = 411.42

d = √411.42

d = 20.28 m

Angle of the displacement with horizontal

Apply sine rule as shown below;

d/sinD = d₂/sinD₂

20.28/sin(52.5) = 7.9/sinD₂

25.562 = 7.9/sinD₂

sinD₂ = 7.9/25.562

sinD₂ = 0.309

D₂ = sin⁻¹(0.309)

D₂ = 18⁰

angle with x axis =  18⁰ + θ

                            =  18⁰ +  52.5⁰

                            = 70.5⁰

Thus, the magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

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6. Problem 3.100 A torque T is applied to the 20-mm-diameter steel rod AB. Assuming the steel to be elastoplastic with G= 77.2 GPa and t, -145 MPa, determine (a) the torque T when the angle of twist at A is 25°, (b) the corresponding diameter of the elastic core of the shaft. 20 mm A 1.5 m Fig. P3.100

Answers

The answers are : (a) Torque T = 1.27 kN·m when twist at A is 25°. (b) Elastic core diameter is zero.

To take care of this issue, we can involve the twist recipe for strong roundabout shafts:

τ = (T/J) * r

where τ is the shear pressure, T is the applied force, J is the polar snapshot of dormancy, and r is the span of the shaft.

The polar snapshot of idleness for a strong round shaft is given by:

J = (π/2) * \(r^4\)

where r is the sweep of the shaft.

From the given information, we can track down the range of the shaft as 20/2 = 10 mm = 0.01 m and the length of the shaft as 1.5 m.

(a) To find the force T when the point of contort at An is 25°, we can utilize the accompanying condition:

θ = (TL/GJ)

where θ is the point of contort, L is the length of the shaft, G is the shear modulus, and J is the polar snapshot of idleness.

Improving this condition, we get:

T = (θGJ/L)

Subbing the given qualities, we get:

J = \((π/2) * (0.01)^4 = 7.854 x 10^-9 m^4\)

T = \((0.25 * 77.2 x 10^9 * 7.854 x 10^-9)/1.5\)

T = 1.27 kN·m

Consequently, the force T when the point of bend at An is 25° is 1.27 kN·m.

(b) To find the relating width of the flexible center of the shaft, we can utilize the most extreme shear pressure hypothesis. As per this hypothesis, the most extreme shear pressure anytime in a shaft shouldn't surpass the versatile furthest reaches of the material.

The flexible furthest reaches of the material is given as σ_el = - 145 MPa. The greatest shear pressure τ_max can be tracked down involving the twist recipe as:

τ_max = (T/J) * r

Subbing the given qualities, we get:

τ_max = (T/7.854 x \(10^-9\)) * 0.01

τ_max = 1.61 * T

For the material to stay versatile, we should have:

τ_max <= σ_el

Subbing the given qualities, we get:

1.61 * T <= - 145 x \(10^6\)

T <= - 90.06 kN·m

This implies that the force applied should be not exactly - 90.06 kN·m for the material to stay flexible. Since we have previously observed the force T to be 1.27 kN·m, we can accept that the material has surpassed its versatile cutoff and has gone through plastic distortion.

In this manner, the breadth of the flexible center of the shaft is zero.

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How much work is required to slide a 3.00 kg box 6.90 m along (up) a frictionless incline plane that is inclined at an angle of 25 degrees?

Answers

The amount of work required to slide the 3 Kg box 6.90 m along (up) the frictionless incline plane is 183.85 J

What is work done?

Work is defined as the product of force and distance moved in the direction of the force. mathematically it is expressed as:

Work done (Wd) = force (F) × distance (d)

Wd = fd

Where height is involved, the workdone is given as as:

Work done (Wd) = mass (m) × acceleration due to graity (g) × height (h)

Wd = mgh

Considering angle projection,

Wd = mghCosθ

Thus, we can detertmine the work done as follow:

Mass (m) = 3 KgHeight (h) = 6.9 mAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 25°Workdone (Wd) =?

Wd = mghCosθ

Wd = 3 × 9.8 × 6.9 × Cos 25

Wd = 183.85 J

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You push a box out of a carpeted room and along a hallway with a waxed linoleum floor. While pushing the crate 3 m out of the room you exert a force of 28 N; while pushing it 4 m along the hallway you exert a force of 14 N. To bring it to a stop you exert a force of 5 N through a distance of 1.2 m, opposite to the motion. How much work do you do in all

Answers

The total work done is equal to 134 J.

Work

The work formula is characterized as the multiplication of the force performed and the distance in which the movement was performed, so that:

                                           \(W = F \times d\)

Thus, it is enough to calculate the value of the work in each movement and add to find the total work, so that:

                                          \(W_1 = 3 \times 28 = 84J\\W_2= 4 \times 14 = 56J\\W_3 = (-1.2) \times 5 = 6J\)

                                        \(84 + 56 + (-6) = 134J\)

So, the total work done is equal to 134 J.

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what is the formula of magnetic force ​

Answers

Answer:

F = qvB sinθ

(Hope this helps! Btw, I am the first to answer. Brainliest pls! :D)


5. A body travels in a circle at a constant speed, it
a) has same acceleration
b) has no acceleration
c) has a centripetal acceleration

Answers

A the same acceleration
No acceleration as the term acceleration describes change in velocity so if its speed is same there will be no acceleration

You are asked to design a spring that will give a 1110 kg satellite a speed of 3.55 m/s relative to an orbiting space shuttle. Your spring is to give the satellite a maximum acceleration of 5.00g. The spring's mass, the recoil kinetic energy of the shuttle, and changes in gravitational potential energy will all be negligible.
(a) What must the force constant of the spring be?
(b) What distance must the spring be compressed?

Answers

Answer:

Explanation:

Kinetic energy of satellite = 1/2 m v²

= .5 x 1110 x 3.55²

= 6994.39 J

This energy comes from the elastic energy of  compressed spring

elastic energy = 1/2 k d² where k is elastic constant and d is compression in spring .

1/2 k d²  = 6994.39 J

kd² = 13988.77 --------------------------- (1)

force created by spring = k d

acceleration = force / mass

= k d / 1110

Given ,

k d / 1110  = 5 x g = 5 x 9.8 = 49

kd = 54390  ------------------------------------------------- ( 2 )

dividing ( 1 )  and ( 2 )

d =  13988.77 / 54390

= .25719 m

= 25.72 cm

kd = 54390

k x .25719 m = 54390

k = 211477.9 N /m

A tuning fork is vibrating the air around it. What best describes the waves produced by the tuning fork?

Answers

The waves produced by a vibrating tuning fork are longitudinal waves, also known as compression waves.

What are Longitudinal Waves?

Longitudinal waves are waves that oscillate along the direction of propagation, meaning they create alternating regions of compression and rarefaction in the medium through which they travel.

In the case of a vibrating tuning fork, the tines of the fork move back and forth, causing the surrounding air to alternately compress and expand. These pressure changes propagate through the air as longitudinal waves.

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what kind of energy bombarded the seeds were included on the outside of the ISS?​

Answers

Explanation:

ultraviolet radiation

Bombarded with energy

They stored the seeds in a single layer on the outside of the ISS behind a special kind of glass that let in ultraviolet radiation only at wavelengths between 110 and 400 nanometers

how much power an appliance uses

Answers

Answer:

it depends on the appliance

Explanation:

bigger appliances will use more power, smaller appliances will use a lesser amount

Does the mass of an object make it need more force to move, and to stop?

Answers

Answer:

Yea

Explanation:

Let's compare a brick to a small table, does it take more force and strength to push a car or a small table? A car, because it's heavier and has more mass.

Answer:

Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects. Example: Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop.

Explanation:

☝️

5. Bradley rode his bike 14.2 km in 2.3 hours Calculate his average speed.

Answers

His average speed is equal to total distance divided by total time:

12.2km / 2.3 hours

= 5.3 km/h

If an elevator accelerates upward at 10 ms−2 , what is the average blood pressure in the brain? What is the average blood pressure in the feet? If the elevator accelerates downward with the same acceleration, what is the average blood pressure in the brain and feet? take g = 10 ​

Answers

The average blood pressure in the brain will be higher than the average blood pressure in the feet. the average blood pressure in the brain will be lower than the average blood pressure in the feet.

When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain and feet of a person changes.

Similarly, when the elevator accelerates downward with the same acceleration, the blood pressure in the brain and feet of a person changes.

Let's discuss them one by one:Blood Pressure When Elevator Accelerates Upward at \(10 ms^{-2}\)

When the elevator accelerates upward at \(10 ms^{-2}\),  the blood pressure in the brain of a person increases, while the blood pressure in the feet of a person decreases.

This happens due to the gravitational force acting on the body.

Since the gravitational force on the head is greater than the gravitational force on the feet, the blood pressure in the brain increases while the blood pressure in the feet decreases.

Therefore, the average blood pressure in the brain will be higher than the average blood pressure in the feet.

Blood Pressure When Elevator Accelerates Downward at  \(10 ms^{-2}\) When the elevator accelerates downward at \(10 ms^{-2}\), the blood pressure in the brain of a person decreases, while the blood pressure in the feet of a person increases.

This also happens due to the gravitational force acting on the body. Since the gravitational force on the head is less than the gravitational force on the feet, the blood pressure in the brain decreases while the blood pressure in the feet increases.

Therefore, the average blood pressure in the brain will be lower than the average blood pressure in the feet.

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In an experiment a student adds baking soda to vinegar and observes that a large amount of gaseous carbon dioxide is released what is the scientific reason for this change

Answers

The scientific reason for the change is that baking soda underwent a chemical change to evolve a gaseous carbon dioxide.

What is a chemical change?

A chemical change is any process in which reactants are changed into products by the breaking or creation of chemical bonds.

In a chemical change, the chemical bonds in the reactants are broken and rearranged to form new substances called products. One of the evidences that a chemical change has occurred is gas evolution.

According to this question, a student adds baking soda to vinegar and observes that a large amount of gaseous carbon dioxide is released.

Therefore, it can be said that the scientific reason for the change is that baking soda underwent a chemical change to evolve a gaseous carbon dioxide.

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A 5 cm radius conducting sphere has a charge density of 2.0x10-6 C/m2 on its surface. Find the electric potential of the sphere.7.2x10^6 V1.1x10^4V3.6x10^5 V2.3x10^5 V2.2x10^4 V

Answers

Given that the radius of the conducting sphere is r = 5 cm = 0.05 m

The charge density on the surface of the sphere is

\(\sigma\text{ = 2}\times\frac{10^{-6}C}{m^2}\)

We have to find the electric potential.

To calculate electric potential, first, we need to calculate charge.

The charge will be

\(\begin{gathered} \sigma=\frac{Q}{4\pi r^2} \\ Q=4\pi r^2\times\sigma \\ =\text{ 4}\times3.14\times(0.05)^2\times2\times10^{-6} \\ =\text{ 6.28}\times10^{-8}\text{ C} \end{gathered}\)

The electric potential is given by the formula

\(V=\text{ k}\frac{Q}{r}\)

Here K is Coulomb's constant whose value is

\(K=\text{ 8.99 }\times\frac{10^9Nm^2}{C^2}\)

Substituting the values, the electric potential will be

\(\begin{gathered} V=\text{ }\frac{8.99\times10^9\times6.28\times10^{-8}}{0.05} \\ =11291.44 \\ =1.1\times10^4\text{ V} \end{gathered}\)

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Two traveling sinusoidal waves are described by the wave functions

Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds

Answers

The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].

The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.

The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.

To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]

Y = 4.95sin[π(3.80x - 1180t - 0.206)]

The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.

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-- The given question is incomplete, the complete question is

"Two traveling sinusoidal waves are described by the wave functions

Y1 : 4.95sin[π(3.80x-1180t)]

Y2 : 4.95sin[π(3.80x-1180t-0.250)]

Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --

he generation of a magnetic field by an electric current is

Answers

Answer: electromagnetism.

Explanation:The use of coils of wires produces a relationship between electricity and magnetism that gives us another magetism called electromagnetism.

reasons why X-rays are used in crystallization

Answers

Answer:

The reason X-rays are used in this process is because the clouds of electrons are at the same scale as the X-ray radiation wavelength. This means that the radiation is deflected and scattered by the electrons of the atoms in the crystal. The deflected X-ray beams produce a scattering distribution which is proportional to the scattering angle.

Explanation:

Answer:

Because X-rays have wavelengths similar to the size of atoms, they are useful to explore within crystals. Thus, since X-rays have a smaller wavelength than visible light, they have higher energy. With their higher energy, X-rays can penetrate matter more easily than can visible light.

Explanation:

3) Vector A is 2.8 cm at 60° above the positive x-axis. Vector B is 1.90 cm at 60 below the
positive x-axis. Use components to find the following
a) A+ B
b) A-B
c) B-A

3) Vector A is 2.8 cm at 60 above the positive x-axis. Vector B is 1.90 cm at 60 below thepositive x-axis.

Answers

The following vector components are:

a) A+ B - 84.21°

b) A-B - 18.74°

c) B-A - -84.21°

How to find vector components?

To use components to find the given vectors, break each vector into its x and y components using trigonometry.

Assume the positive x-axis points to the right and the positive y-axis points up.

For vector A, the magnitude of the x-component is given by Acos(60°) and the magnitude of the y-component is given by Asin(60°),

Ax = Acos(60°) = 2.8 cm × 0.5 = 1.4 cm

Ay = Asin(60°) = 2.8 cm × 0.866 = 2.425 cm

For vector B,  the negative sign since the vector is below the x-axis,

Bx = Bcos(60°) = 1.9 cm × 0.5 = 0.95 cm

By = -Bsin(60°) = -1.9 cm × 0.866 = -1.6494 cm

a) To find A + B, add the x and y components separately:

(A + B)x = Ax + Bx = 1.4 cm + 0.95 cm = 2.35 cm

(A + B)y = Ay + By = 2.425 cm - 1.6494 cm = 0.7756 cm

Then, the vector A + B has a magnitude of √[(2.35 cm)² + (0.7756 cm)²] = 2.466 cm and an angle of tan⁻¹(0.7756 cm / 2.35 cm) = 18.74° above the positive x-axis.

b) To find A - B, subtract the x and y components separately:

(A - B)x = Ax - Bx = 1.4 cm - 0.95 cm = 0.45 cm

(A - B)y = Ay - By = 2.425 cm + 1.6494 cm = 4.0744 cm

Then, the vector A - B has a magnitude of √[(0.45 cm)² + (4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(4.0744 cm / 0.45 cm) = 84.21° above the positive x-axis.

c) To find B - A, subtract the x and y components separately:

(B - A)x = Bx - Ax = 0.95 cm - 1.4 cm = -0.45 cm

(B - A)y = By - Ay = -1.6494 cm - 2.425 cm = -4.0744 cm

Then, the vector B - A has a magnitude of √[(-0.45 cm)² + (-4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(-4.0744 cm / -0.45 cm) = -84.21° below the positive x-axis.

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The lons entering the mass spectrometer have the same charges. After being accelerated through a potential difference of 8.20 kV, a
singly charged 12c+ ion moves in a circle of radius 19.4 cm in the magnetic field of a mass spectrometer. What is the magnitude of the
field? Use these atomic mass values: 12C, 12.0 u; 14C, 14.0 u; 160, 15.99 u. The conversion between atomic mass units and kilograms is
1u=1.66 x 10-27 kg.

Answers

The calculated magnitude is  6.73 x 10³ V/m.

AMU is described as being one-twelfth the mass of a carbon-12 atom (12C). C makes up more than 98% of the carbon that can be found in nature, making it the most prevalent isotope. The magnitude of the field is the change in potential across a small distance in the indicated direction divided by that distance.

Potential difference = 8.20 kV= 8.20 x 10³ V

radius= 19.4/100=0.194 m

total distance that is circumference of the circle= 2πr =2 x 3.14 x 0.194

                                                                               = 1.218 m

therefore Magnitude= 8.20 x 10³ / 1.218

                                  =6.73 x 10³ V/m

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