i need the answer asap plz!!
A sample of water vapor has a pressure of 36.0 Pa and a temperature of 300.0 K. If the pressure is
reduced to 32.0 Pa, what will the new temperature be?

The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.

The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.

emf = N(dФ/dt)

where;

Ф = BA

where;

emf = NBA/t

A = πr²

A = π x (0.13)²

A = 0.053 m²

emf = NBA/t

emf = (1 x 3.746 x 0.053)/(1.16)

emf = 0.171 V

Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.

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1) The force is 3.8 * 10^-6 N

2) The force will increase since the force is proportional to the masses of the trucks

Gravitational force is a fundamental force of nature that exists between any two objects that have mass or energy. It is the force of attraction that exists between any two objects in the universe, and is responsible for holding planets in their orbits, causing objects to fall towards the Earth, and keeping galaxies together.

Given;

F = Gm1m2/r^2

F = 6.6 * 10^-11 * 3,650 * 9,850/(25)^2

F = 3.8 * 10^-6 N

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(a) The velocity of the ball is 41.16 m/s.

(b) The height reached by the ball is 86.44 m.

Velocity is the rate of change of displacement.

(a) To calculate the velocity at which the pitcher throw the ball, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute thee values into equation 1

(b) To calculate how high the ball rise, we use the formula

Where:

Substitute into equation 2

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Answer:

q₂ = -4.80 10⁻⁴  C  = - 0.48 mC, charge is negative

Explanation:

Let's use coulomb's law

           F = \(k \frac{q_1 q_2}{r^2}\)

and the sum of forces, remember that charges of the same sign repel and of different sign attract

           ∑ F = F₁₃ + F₂₃           (1)

Let's start by fixing a reference system located at charge 1 with the positive direction to the right.  In the problem it indicates that the net force on charge 3 is F = - 20.0 N, the negative sign indicates that the force is towards the left

let's look for every force, the charge q₁ = 12 10-⁻³ C and q₃ = 15 10⁻³ C

           F₁₃ =\(k \frac{q_1 q_3}{x_{13}^2}\)

           F₁₃ = 9 10⁹ 12.0 15.0 10⁻⁶ / (5-0)²

           F₁₃ = 64.8 10 3 N

This force is repulsive, that is, it is directed to the right

          F₂₃ = k \frac{q_2 q_3}{x_{23}^2}

          F₂₃ = 9 10⁹ q₂ 15.0 10⁻³ / (5-4)²

          F₂₃ = 135 10⁶ q₂  N

we substitute in equation 1

          -20.0 = 64.8 10³ + 135 10⁶ q₂

           q₂ = (-20 - 64.8 10³) / 135 10⁶

           q₂ = -4.80 10⁻⁴  C

the sign indicates that the charge is negative

Answer:

Negative electric charges

Answer:

Layer C

Explanation:

Hope this helps!

-Liyah<3

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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(a) The time taken the block to reach the ground once it flies off the edge of the table is 0.47 s.

(b) The initial horizontal velocity of the block as it flies off the table is 3.91 m/s.

(c) The initial speed of the bullet is 237.5 m/s.

The time of motion of the block is calculated as follows;

h = ¹/₂gt²

where;

t = √(2h/g)

t = √( (2 x 1.08) / 9.8)

t = 0.47 s

x = vt

v = x/t

v = (1.84)/(0.47)

v = 3.91 m/s

m1u1 + m2u2 = v(m1 + m2)

where;

0.00611(u1) + 0.365(0) = 3.91(0.00611 + 0.365)

0.00611u1 = 1.451

u1 = 1.451/0.00611

u1 = 237.5 m/s

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Answer:

P = 517.5 [kg*m/s]

Explanation:

We must remember that momentum is defined as the product of force by the time of force duration.

\(P=F*t\)

where:

P = momentum [kg*m/s]

F = force [N]

t = time [s]

\(P=345*1.5\\P=517.5[kg*m/s]\)

Answer:

To solve the problem, we use the equations of equilibrium to find the tension in each cable holding up the loudspeaker. Since the loudspeaker is in equilibrium, the sum of the forces acting on it is zero. The weight of the loudspeaker is calculated first, and then we use trigonometry to find the horizontal and vertical components of the tension in one of the cables. We then apply the equation of equilibrium in the y direction to find the tension in each cable. The final answer is that the tension in each cable is approximately 81.1 N, which balances the weight of the loudspeaker.

___

Given:

Mass of loudspeaker (m) = 15.0 kg

Distance from ceiling (h) = 1.00 m

Length of cable (l) = 2.70 m

Acceleration due to gravity (g) = 9.80 m/s^2

Weight of loudspeaker:

Fg = mg

Fg = (15.0 kg)(9.80 m/s^2)

Fg = 147 N

Horizontal and vertical components of tension in one cable:

sinθ = h/l

sinθ = 1.00 m / 2.70 m

θ = sin^(-1)(1.00/2.70)

θ ≈ 21.6°

T_x = T sinθ

T_y = T cosθ

where T is the tension in the cable.

Equation of equilibrium in y direction:

ΣF_y = 2T cosθ - Fg = 0

Solving for T:

2T cosθ = Fg

T = Fg / (2 cosθ)

Plugging in the values:

T = (147 N) / (2 cos(21.6°))

T ≈ 81.1 N

Answer:

∙ Temperature

∙ Concentration of electrolyte

∙ Nature of the electrolyte added

∙ Nature of solvent and its viscosity

Explanation:

Answer:

Explanation:

According to the Fleming's right hand rule, if we spread our right hand such that the thumb, fore finger and the middle finger are mutually perpendicular to each other, then the thumb indicates the direction of force, fore finger indicates the direction of magnetic field, then the middle finger indicates the direction of induced current.

According to the Lenz's law, the direction of induced emf is such that it always opposes the cause due to which it is produced.

(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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The equipotential surfaces associated with a point charge are concentric shells.

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge.

The equipotential surface is the region where all points with the same potential are located. On the equipotential surface, a charge can be moved from one point to another without exerting any effort.

Thus,a point charge's related equipotential surfaces are concentric shells.

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Answer:

model is viable if the assumptions that answer it are in accordance with the fundamental principles or laws of physics and if it gives conclusions that can be tested with experiments.

Explanation:

A model in physics must be verified by experiments that are carried out to measure the consequences derived from it.

A model is viable if the assumptions that answer it are in accordance with the fundamental principles or laws of physics and if it gives conclusions that can be tested with experiments. Models that meet these conditions are said to be viable

Answer:

150 km/h

Explanation:

After the first two hours, you have traveled 150km (given) which means that you still have 300km - 150km = 150km left to travel. Since you have already traveled 2 hours, that means you must travel the remaining 150km in 3hours - 2hours = 1hour. Assuming the answer is in km/hour, you will need to travel at a speed of 150km/1h = 150km/h for the remaining of the distance.

Answer:

- 670 kg.m/s

Explanation:

Newton's third law states that to every action, there is equal and opposite reaction force. Since the force will be same but different in direction and acted in the same time then the impulses ( force multiply by time) of the two car be same in magnitude but different in direction - 670 kg.m/s

a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.

(b) the angle of the landing ramp is 30°.

(a)

Launch speed = 55.0 mph * (1.467 ft/s)

= 80.685 ft/s

Horizontal distance = Launch speed * Time of flight

Vertical velocity = Launch speed * sin(30.0°)

Time to reach maximum height = Vertical velocity / g

Vertical distance = (1/2) *g * t²

and Time = √(2 * Vertical distance / g)

Total time of flight = 2 * Time to reach maximum height + Time for descent

Horizontal distance = Launch speed * Total time of flight

The Vertical velocity = 80.685 ft/s * sin(30.0°)

= 40.3425 ft/s

Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²

Time to reach maximum height  = 1.253 s

Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)

Time of descent  = 0.913 s

Total time of flight = 2 * 1.253 s + 0.913 s

Total time of flight = 3.419 s

In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s

horizontal distance = 276.298 ft

b.

the angle of the landing ramp is  30.0 be the same as the launch angle.

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Answer:

can you tell me about this property

The simple machines can help make work easier by working quicker than the people and making other peoples jobs easier.

Explanation:

I hope this helped.

Answer:

2.54 seconds

Explanation:

The period of a swing on a playground swing set can be calculated using the formula:

T = 2π√(L/g)

where T is the period, L is the length of the swing's chain, and g is the acceleration due to gravity, which is approximately 9.81 m/s².

Substituting the given values, we get:

T = 2π√(4.0 m/9.81 m/s²)

T = 2π√0.407

T = 2.54 s (rounded to two significant figures)

Therefore, the period of the swing is 2.54 seconds.

Hope this helps!

The core of the Sun is the interior or center part of this star.

The sun is one of the stars of the solar system that gives life to the planet earth. All the other planets revolves round it.

The features of the sun include the following:

The sun is also made up of several parts which include:

The innermost or central part of the sun is the core that is made up of the highest amount of hydrogen atoms.

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The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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Given:

To be calculated:

Calculate the acceleration of given object ?

Formula used:

Acceleration = v - u / t

Solution:

We know that,

Acceleration = v - u / t

☆ Substituting the values in the above formula,we get

Acceleration ⇒ 300 - 200 / 20

⇒ 100/20

⇒ 5 m/s²

Answer:

A)     t = 0.40816 s , y = 0.916 m

Explanation:

A) For this problem we use the kinematic relations

           v = v₀ - g t

the highest point zero velocities (v = 0)

           t = (v₀-v) / g

           t = (4 - 0) / 9.8

           t = 0.40816 s

to calculate the height let's use

          v² = v₀² - 2 g y

          y = vo2 / 2g

           y = 4 2 / (2 9.8)

          y = 0.916 m

To find the number of photos, we can use a direct proportions rule, if you take 30 photos in a second in 0.40816 s how many photos does it take

          # _photos1 = 0.40916 (30/1)

          # _photos1 = 12

yes i take 120 fps

          #_fotod = 0.40916 (120/1)

          #photos = 5.87 10³

B) The ball is released from a latura h how long it takes to reach the floor

           v² = v₀² + 2 g y

where the initial velocity is zero and the velocity with which the expert leaves is equal to the velocity with which v = 4 m / s leaves

            v² = 2gy

             v = √ (2 9.8 0.916)

             v = √ (2.1397 101)

             v = 4.6257 m / s

c) we ask us for the time for latura

             y = L / 2

             y = 0.916 / 2

             y = 0.458 m

now we can use the formula

             y = v₀ t - ½ g t²

           0.458 = 4.00 t - ½ 9.8 t²

            4.9 t² - 4t + 0.458 = 0

            t² -0.8163 t +0.09346 = 0

we solve second degree execution

           t = [0.8163 ±√ (0.8163² - 4 0.09346)] / 2

           t = [0.8163 ± 0.540] / 2

           t₁ = 0.678 m

           t₂ = 0.2763 m

the shortest time is for when the ball goes up and the longest when it goes down

D) the graph of vs Vs is expected to be a closed line

and the graph of position versus time a parabola

Answer:

Explanation:

Time of flight is the time taken by the bulet in air. Time of flight is expressed as T = Usinθ/g where;

U is the initial velocity = 180m/s

θ is the angle of launch = 90° (Since the bullet is shot upwards)

g is the acceleration due to gravity = 9.81m/s²

T = 180sin90/9.81

T = 180/9.81

T = 18.35s

Hence the bullet will spend 18.35s in air

The height covered by the bullet is the maximum height. Maximum height is expressed as;

H = u²sin²θ/2g

H = 180²sin²90/2(9.81)

H = 180/19.62

H = 9.17m

Hence the bullet will go 9.17m high

The correct answer is 4.14456 mi/hour.

The entire distance that an object travels in a given amount of time is the definition of average speed for that object. You can figure it out by dividing the overall distance traveled by the overall journey time.

When an object travels a distance at a variety of speeds, its average speed is the speed at which, if the object moves uniformly, it will travel the same distance in the same amount of time.

average speed= total distance / total time

total distance = 1 mile

The total time = 2 / ( 3 × 3.5 ) = 0.190 hour

time for coming = 1 / (3 × 6.5 ) = 0.05128 hour

Thus the average speed = 1 / ( 0.190 + 0.05128 ) = 1 / 0.24128 = 4.14456 mi/hour.

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Answer:524 Hz

Explanation:

Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.

Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.

For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,

\(f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1\)

Here, \(V_s\) is the speed of the sound.

Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.

Convert the unit of velocity of the car as,

\(\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s\)

As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.

Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,

\(f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz\)

The approximate frequency heard in the other car before they cross each other is 524 Hz.

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ANSWER

• x = 0.944a

• y = 1.333a

EXPLANATION

x- coordinate

The x-coordinate of each pair of piled blocks are:

• x₁ = x₂ = a/2

• x₃ = x₄ = 3a/2

The weights of the blocks are:

• W₁ = 20N

• W₂ = 80N

• W₃ = 70N

• W₄ = 10N

The total weight is the sum of the individual weights,

By the definition of center of gravity, the x-coordinate is,

Replace with the values and solve,

y- coordinate

The same equations apply to the y-coordinate. The y-coordinates of each weight are:

• y₁ = y₄ = a/2

• y₂ = y₃ = 3a/2

The y-coordinate of the center of gravity is,

Replace with the values and solve,

Hence, the coordinates of the center of gravity are (0.944a, 1.333a).