Answer:
Part A: chosen method is by factoring
Part B: First rewrite the equation by writing -24 as a difference so you get x² -9x - 15x + 135 = 0. Then factor out the x and the -15 from the equation so you get x(x-9) - 15(x-9) = 0. Then factor out x-9 from the equation so you have (x-9)(x-15) = 0. Finally, set each expression to 0: x-9=0 and x-15=0 and then solve: x=9 and x=15
Part C: x=9, x=15
f:x-2x+3 is a mapping defined on the set R of real numbers. Determine the pre-images of (a) 1 (b) -1 (c) 7 (d) -5
F[g(x-1)] has a value of 2x2-4x+9. Applying the multiplication operation to functions and replacing the functions led to the discovery of the answer.
What are Operations on functions?The functions can be added, subtracted, multiplied, or divided in the same manner that we add, subtract, multiply, and divide the terms in a function.
Consider f(x) and g, two functions (x). These are the notations:
To add, use the formula (f+g)(x) = f(x) + g(x)
for subtraction (f-g)(x) = f(x) - g(x)
To multiply, use the formula (fg)(x) = f(x)* g(x)
The division formula is (f/g)(x) = (f(x))/(g(x)).
A function that considers one function to be a component of another function is created when we replace one function for another.
So now, f(g) = 2g-3.
When provided, g = x^2+5
So, g(x-1) = (x-1)^2+5
By changing g's value (x-1)
F[g(x-1)] has a value of 2x²-4x+9. Applying the multiplication operation to functions and replacing the functions led to the discovery of the answer.
F[g(x-1)] has a value of 2x²-4x+9. Applying the multiplication operation to functions and replacing the functions led to the discovery of the answer
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Everyday Math
426. Heating Oil A 275 gallon oil tank costs $400 to fill. How much would it cost to fill a 180 gallon oil tank?
Answer:
261.81818181
Step-by-step explanation:
400÷275=x
x×180
Answer:
If 275 gallon of oil tank costs $400 to fill.
Then 180 gallon of oil tank costs $261.8 to fill.
Step-by-step explanation:
Given that a 275 gallon of oil tank costs $400 to fill.We need to find how much it would cost to fill a 180 gallon oil tank.Use the unitary method to find the answer.Step 1 of 2
If 275 gallon of oil tank costs $400 to fill.
Then the cost to fill 180 gallon of oil tank can be found by forming a proportion.
Let the required cost be x.
\($$\begin{aligned}\frac{\text { cost }}{\text { Gallons of Gas }} &=\frac{\text { cost }}{\text { Gallons of Gas }} \\\frac{\$ 400}{275} &=\frac{x}{180}\end{aligned}\)
Multiplying both sides by 180 we get,
\($$\begin{aligned}\frac{\$ 400}{275} \times 180 &=\frac{x}{180} \times 180 \\x &=\frac{\$ 400}{55} \times 36 \\x &=\$ 261.8\end{aligned}$$\)
Step 2 of 2
To check if the answer is reasonable, we substitute it back in the formed proportion
\($\frac{\$ 400}{275}=\frac{x}{180}$$\)
We found x=$261.8 hence,
\($\frac{\$ 400}{275}=\frac{\$ 261.8}{180}$$$\$ 1.45=\$ 1.45$$Here, $L H S=R H S$\)
Hence, our answer is correct.
A traditional children’s riddle concerns a farmer who
is traveling with a sack of rye, a goose, and a mischievous dog.
The farmer comes to a river that he must cross from east to west. A
boat is ava
The riddle mentioned in the question is about a farmer who is traveling along with a sack of rye, a goose, and a mischievous dog.
He comes to a river that he must cross from east to west, and there is a boat available to do so. Therefore, the farmer takes the goose back to the east side and leaves it there. He then takes the sack of rye across the river, drops it off with the dog, and goes back to the east side to pick up the goose. In this manner, all of the farmer's possessions can be safely transported across the river without any of them being lost to the dog or the goose.This riddle is a classic example of a type of logical puzzle known as a "transport problem."
The goal of a transport problem is to determine how to transport one or more objects from one location to another while satisfying certain constraints, such as the size of the transport vehicle or the safety of the objects being transported.
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z2−(3+i)z+4+3i=0
solve the equation
Find the SURFACE AREA of the shape below. Do NOT label your answer! *
Answer:
The surface area of the triangular prism is 142.919 m^2.
Step-by-step explanation:
Evaluate 4(x - 3) + 5x - x² for x = 3.
O A. -6
OB. -2
O C. 6
OD. 2
I WILL GIVE BRAINLY!!!!!!!!!
Samuel earns $5 per hour plus 65% commission on all his sales. If y represents
his sales for one day, which expression represents Samuel’s total earnings for a
day when he worked 6 hours?
A. 5(6) + 65y
B. 5(65) + 6y
C. 5(6) + 0.65y
D. 5(6) + 1.65y
PLSS SHOW YOUR WORK PLSSS
What is the value of m in the figure below? In this diagram, ΔABD ~ ΔBCD.
Answer:
√126Option D is the right option.
solution,
\( \frac{ac}{bc} = \frac{bc}{dc} \\ or \: \frac{18}{ m} = \frac{m}{7} \\ or \: m \times \: m = 18 \times 7(cross \: multiplication) \\ or \: {m}^{2} = 126 \\ m = \sqrt{126} \)
Hope this helps..
Good luck on your assignment.
Hope
Find the point on the curve r (t) = (2 cos t , 2 sin t, et), 0 ≤ t ≤ π, where the tangent line is para! le! to the plane √3x+ y = 1.
The point on the curve where the tangent line is parallel to the plane is (cos t0, sin t0, e^t0), where t0 is the solution of the equation et0/√3 = -2 sin t0.
To find t0, we need to take the derivative of r(t) with respect to t, which gives us the tangent vector: T(t) = (-2 sin t, 2 cos t, e^t).
Next, we need to find a vector normal to the given plane. We can do this by taking the coefficients of x, y, and z in the equation of the plane: N = (√3, 1, 0).
Since the tangent line is parallel to the plane, the dot product of the tangent vector and the normal vector should be zero: T(t0) · N = 0.
Substituting the components of T(t0) and N, we get:
-2sin(t0)√3 + 2cos(t0) + 0 = 0
Simplifying and rearranging, we get:
tan(t0) = 1/√3
Solving for t0 in the given range 0 ≤ t ≤ π, we get:
t0 = π/6
Substituting t0 into the equation of the curve, we get:
r(t0) = (2cos(π/6), 2sin(π/6), e^(π/6)) = (√3, 1, e^(π/6))
Therefore, the point on the curve where the tangent line is parallel to the plane √3x + y = 1 is (√3, 1, e^(π/6)).
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Find the slope of the line passing through the points (3, 4) and (8,-3).
Answer:
-1.4
Step-by-step explanation:
For what value of x is line m parallel to line n?
x=?
In this exercise, you’ll create a form that accepts one or more
scores from the user. Each time a score is added, the score total,
score count, and average score are calculated and displayed.
I ne
In this exercise, you’ll create a form that accepts one or more scores from the user. Each time a score is added, the score total, score count, and average score are calculated and displayed.
In order to achieve this, you will need to utilize HTML and JavaScript. First, create an HTML form that contains a text input field for the user to input a score and a button to add the score to a list. Then, create a JavaScript function that is triggered when the button is clicked.
To update these values, you will need to loop through the array of scores and calculate the total and count, and then divide the total by the count to get the average.
Finally, the function should display the updated values to the user. You can use HTML elements such as `` or `
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--- Ensures items requested match item numbers on DA Form 3151-R
--- Loads and secures the ammunition
--- Placards the vehicle
Which of the following tasks does the unit personnel perform when receiving ammunition?
When receiving ammunition, unit personnel perform three tasks: ensuring items requested match item numbers on DA Form 3151-R, loading and securing the ammunition, and placarding the vehicle.
The first task performed by unit personnel when receiving ammunition is to ensure that the items requested match the item numbers on DA Form 3151-R. This form serves as a record of the types and quantities of ammunition being received. By comparing the requested items with the item numbers on the form, personnel ensure accuracy and prevent any discrepancies or errors in the delivery.
The second task involves the loading and securing of the ammunition. Unit personnel are responsible for safely and efficiently loading the ammunition onto the designated vehicle or storage area. This includes following proper handling procedures, using appropriate equipment, and adhering to safety protocols. The ammunition must be securely stored and arranged to prevent shifting or damage during transportation.
The final task is to placard the vehicle. Placarding involves visibly displaying the necessary warning signs or labels on the vehicle that indicate the presence of ammunition. This step is crucial for safety and compliance purposes, as it alerts other personnel and drivers to exercise caution when approaching or handling the vehicle. Clear and prominent placarding helps prevent accidents and ensures that everyone involved is aware of the potential hazards associated with transporting ammunition.
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Why don’t the properties of parallelograms applied to trapezoids?
SOLUTION:
Step 1:
In this question, we are given the following:
Why don’t the properties of parallelograms applied to trapezoids?
Step 2:
The details of the solution are as follows:
A parallelogram cannot be a trapezium as a parallelogram has one pair of opposite sides parallel and equal to each other, while a trapezium has only one pair of opposite sides parallel to each other, not equal.
A trapezium is not a parallelogram because a parallelogram has 2 pairs of parallel sides. But a trapezium only has 1 pair of parallel sides.
After a discount of 20 %, Marjorie paid $ 180 for a dress. The original price of the dress was
=============================================
Explanation:
x = original price
If she saves 20%, then she still pays the remaining 80% which then converts to the decimal form 0.80
The expression 0.80x represents the new price, or sale price, of the dress. We're told this price is $180
Equate the two expressions and solve for x
0.80x = 180
x = 180/0.80
x = 225
The original price is $225
------------------------
Checking the answer:
20% of 225 = 0.20*225 = 45
She saves $45
225 - 45 = 180
This confirms the answer.
Calculate the future value of a three year uneven cash flow given below, using 11% discount rate:
Year 0 Year 1 Year 2 Year 3
0 $600 $500 $400
Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.
To calculate the future value of a three-year uneven cash flow given below, using an 11% discount rate, we need to use the formula;
Future value of uneven cash flow = cash flow at year 1/(1+discount rate)¹ + cash flow at year 2/(1+discount rate)² + cash flow at year 3/(1+discount rate)³ + cash flow at year 4/(1+discount rate)⁴
Given the cash flows;
Year 0: $0
Year 1: $600
Year 2: $500
Year 3: $400
Then the Future value of uneven cash flow
= $600/(1+0.11)¹ + $500/(1+0.11)² + $400/(1+0.11)³
= $600/1.11 + $500/1.23 + $400/1.36
=$540.54 + $405.28 + $293.00
=$1,238.82
Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.
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of the following, which population is most dense? please choose the correct answer from the following choices, and then select the submit answer button. answer choices 100 individuals per 100 square meters 5000 individuals per 200 square meters 100,000 individuals per 20,000 square meters 15,000 individuals per 10,000 square meters
The population that is most dense is the one for 5000 individuals per 200 square meters
Given the following information:
100 individuals per 100m^2
5000 individuals per200m^2
100,000 individuals per 20,000m^2
15,000 individuals per 10,000m^2
We find the population that is most dense using the formula:
Population density=(No. of people/Land area)
For 100 individuals per 100m^2,
Population density=100/100=1
For 5000 individuals per200m^2
Population density=5000/200=25
For 100,000 individuals per 20,000m^2
Population density=100,000/20,000=5
For 15,000 individuals per 10,000m^2
Population density=15,000/10,000=1.5
Hence, highest population density is 25 for 5000 individuals per200m^2
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Solving systems by substitution
39% of 80 74% of 240 91% of 82 66% of 160
9% of 71 126% of 80 234% of 145 97.9% of 39
52% of 57.9 33% of 15.3
Answer:
39% of 80 = 39.2
74% of 240 = 177.6
91% of 82 = 74.62
66% of 160 = 105.6
9% of 71 = 63.9
126% of 80 = 100.8
234% of 145 = 339.3
97.9% of 39 = 38.181
52% of 57.9 = 30.108
33% of 15.3 = 5.049
Step-by-step explanation:
In order to find the percentage of each equation, we will use the first one as an example. We take the 39%, and convert it to 0.39 and get rid of the %. Then, "of" means multiplication.
So, we have:
0.39 x 80 = 39.2
Write an equation in slope-intercept form for the line.
(-7,2) and (5,8)
The equation in slope-intercept form for the line that passes from the points (-7,2) and (5,8) is y = (1/2)x -3/2.
We know that, the slope intercept form is given by:-
y = mx + b
Where,
(x,y) is the ordered pair of every point on the line
m is the slope of the line
b is the y-intercept of the line
We know that, slope = (8-2)/(5-(-7)) = 6/12 = 1/2
Putting (-7,2) in (x,y) and m = 1/2 in the slope intercept form, we get,
2 = (1/2)(-7) + b
2 = -7/2 + b
b = -3/2
Hence, the slope intercept form of the line is y = (1/2)x -3/2.
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An account earning interest at a rate of 4. 6% per year, compounded continuously, will be worth $2174. 30 in 18 years. How much is invested in the account today, if no additional deposits or withdrawals are made?.
To make the given statements true, $967.72 should be invested in the account today, with no additional deposits or withdrawals being made.
Compound interest refers to the amount of interest added on the principal amount plus interest. The formula for compound interest is:
B = P(1 + r/n)^t
where B is the ending balance, P is the principal amount or original balance, r is the interest rate in decimal form, n = number of times interest is compounded annually, and t is the time in number of year
Based on the given information, P is the unknown and
B = $2174. 30
t = 18
r = 4. 6% = 0.046
n = 1
Plug in the values and solve for P or the amount that should be invested today.
B = P(1 + r/n)^t
$2174. 30 = P(1 + (0.046/1))^18
$2174. 30 = P(1.046)^18
P = $2174. 30 / (1.046)^18
P = $967.72
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testing to see if there is evidence that the correlation between two variables is negative.
If an older television with an aspect ratio of 4:3 has a screen of 2500 square inches, but the image displayed has an aspect ratio of 16:9, how much area does the image actually occupy?
The image occupy 1250 inches².
What is Ratio?A ratio is a comparison between two amounts that is calculated by dividing one amount by the other. The quotient a/b is referred to as the ratio between a and b if a and b are two values of the same kind and with the same units, such that b is not equal to 0. Ratios are represented by the colon symbol (:). As a result, the ratio a/b has no units and is represented by the notation a: b.
Given:
The aspect ratio of screen 4:3 and the screen is 2500 square inches.
so, the width of the screen is = 2500/ 4.3 = 581.40 inches
As, the image displayed has an aspect ratio of 16:9.
The Area of image is
= 581.40 x 9/16
= 1250 inches².
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100 POINTS AND BRAINLIEST! FULLY CORRECT AND EXPLANITORY ANSWERS ONLY!
You have been hired as a consultant by Mr. Robbins of the large Ice Cream company Dachshund Robbins. As part of assisting them with determining things like the number of cones that can be made per container of ice cream, they’ve asked you to determine the amount of ice cream in a properly filled cone.
Please note Mr. Robbins is very insistent that all cones be properly filled according to the sketch above, and that he’s running an honest business.
PART A: What shapes is the cone composed of that we can find the volume of?
PART B: What is the volume of those shapes?
PART C: Find the volume of the composite shape for Mr. Robbins, and make sure to show your work.
THERE ARE 3 PARTS! ANSWER ALL CORRECTLY AND EXPLANITORY FOR 100 POINTS AND BRAINLIEST! Thank you!!
Answer:
2714.34 in³ (nearest hundredth)
Step-by-step explanation:
A) Cone and hemisphere
B) volume of a cone = \(\dfrac13\pi r^2h\)
volume of a hemisphere = \(\dfrac23\pi r^3\)
(where r is the radius and h is the height)
C)
\(\implies \textsf{volume of cone}=\dfrac13\pi \times 9^2\times 14=378 \pi\)
\(\implies \textsf{volume of hemisphere}=\dfrac23\pi \times 9^3=486 \pi\)
\(\implies \textsf{total volume}=378 \pi+486 \pi=864\pi =2714.34 \textsf{ in}^3 \textsf{ (nearest hundredth)}\)
How many solutions does 7(x - 2) + 5 = 3 (2x - 1) + 1 have?
Answer:
one, x = 7
Step-by-step explanation:
7(x - 2) + 5 = 3 (2x - 1) + 1
reduce:
7x - 14 + 5 = 6x - 3 + 1
x = 7
Find the surface area. 7 In 5 in helppppp
andre drew a plan of a courtyard at a scale of 1 to 60. in his drawing, one side of the courtyard is 2.75 inches. what is the actual measurement of that side of the courtyard (in inches)?
The actual measurement of that side of the courtyard = 165 inches
In this question, we have been given Andre drew a plan of a courtyard at a scale of 1 to 60. in his drawing, one side of the courtyard is 2.75 inches.
We need to find the actual measurement of that side of the courtyard.
In order to calculate the real length,
real length = scale length / scale ratio
here, scale length = 2.75 inches
scale ratio = (1/60)
so, the real length would be,
real length = 2.75/ (1/60)
real length = 2.75 * 60
real length = 165 inches
Therefore, the actual measurement of that side of the courtyard = 165 inches
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HELP IM BEING TIMESD KHAN ACADEMY
Answer:
a
Step-by-step explanation:
Shore Company reports the following information regarding its production cost.
Units produced 44,000 units
Direct labor $ 39 per unit
Direct materials $ 40 per unit
Variable overhead $ 10 per unit
Fixed overhead $110,920 in total
Compute product cost per unit under absorption costing.
Multiple Choice
o $85.00
o $91.52
o $79.00
o $39.00
o $40.00
A sporting goods manufacturer budgets production of 53,000 pairs of ski boots in the first quarter and 44,000 pairs in the second quarter of the upcoming year. Each pair of boots requires 2 kilograms (kg) of a key raw material. The company aims to end each quarter with ending raw materials inventory equal to 25% of the following quarter's material needs. Beginning inventory for this material is 25,500 kg and the cost per kg is $7. What is the budgeted materials purchases cost for the first quarter?
Multiple Choice
o $742,000
o $710,500
o $556.500
o $773,500
o $927,500
Ratchet Manufacturing's August sales budget calls for sales of 4,000 units. Each month's unit sales are expected to grow by 5%. The product selling price is $25 per unit. The expected total sales dollars for September's sales budget are:
Multiple Choice
o $100,000.
o $95,000
o $105,000
o $110.000
o $4,200.
Fortune Company's direct materials budget shows the following cost of materials to be purchased for the coming three months:
January February March
Haterial purcha $ 13,180 $ 15,290 $ 12,110
Payments for purchases are expected to be made 50% in the month of purchase and 50% in the month following purchase. The December Accounts Payable balance is $7,900. The expected January 31 Accounts Payable balance is:
Multiple Choice
o $7,900
o $7,645
o ST3180
o $6.590.
o $10,540
The product cost per unit under absorption costing is $91.52.
The budgeted materials purchases cost for the first quarter is $710,500.
The expected total sales dollars for September's sales budget are $105,000.
The expected January 31 Accounts Payable balance is $7,645.
To calculate the product cost per unit under absorption costing, sum up the direct labor, direct materials, variable overhead, and fixed overhead per unit. In this case, it is $39 + $40 + $10 + ($110,920 / 44,000 units) = $91.52.
To calculate the budgeted materials purchases cost for the first quarter, multiply the total material needs for the quarter by the cost per kg of raw material. In this case, it is (53,000 pairs * 2 kg/pair) * $7 = $742,000.
To calculate the expected total sales dollars for September's sales budget, multiply the August sales by the growth rate and the selling price per unit. In this case, it is 4,000 units * 1.05 * $25 = $105,000.
To calculate the expected January 31 Accounts Payable balance, sum up the December Accounts Payable balance, purchases in January, and 50% of purchases in February. In this case, it is $7,900 + $13,180 + ($15,290 / 2) = $7,645.
Therefore, the product cost per unit under absorption costing is $91.52, the budgeted materials purchases cost for the first quarter is $710,500, the expected total sales dollars for September sales budget are $105,000, and the expected January 31 Accounts Payable balance is $7,645.
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Dilate the vector (-3,5) by a factor of 3
Answer:
-9, 15
Step-by-step explanation: