I NEED HELP WITH THIS ASAP

It's difficult to say whether the conditions for constructing a t-confidence interval are met based on the information provided. To construct a t-confidence interval, three conditions must be met:

The sampling method must be random. It's not specified in the problem whether the method of selecting the vehicles was random or not, so it's impossible to say whether this condition is met.

The sample size must be large enough. A sample size of 100 vehicles is considered to be large enough for the normal/large sample condition to be met.

The population must be approximately normally distributed or the sample size must be large. Since the problem does not specify anything about the distribution of the population, it is not clear if this condition is met.

Given that the information provided does not give enough details to state whether the conditions for constructing a t-confidence interval are met or not.

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Equivalent expressions are expressions of equal values

The equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6   and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)

The first expression has been solved.

So, we have the following expressions

4x−7y−5z+6 and -3x−8y−4−87z

4x−7y−5z+6

We have:

4x-7y-5z+6

Rewrite as:

4x+ (y - 8y) + (2z-5z) +6

-3x−8y−4−87z

We have:

-3x−8y−4−87z

Rewrite as:

3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)

Hence, the equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6   and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)

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If the parent function \(\sf y=(1.6)^x\) is translated 5 units up and 9 units to the right, then you should subtract 9 from x and add 5 to the whole function. Thus,

1) translation the parent function \(\sf y=(1.6)^x\) 9 units to the right gives you the function \(\sf y=(1.6)^{x-9}\).

2) translation the function \(\sf y=(1.6)^{x-9}\) 5 units up gives you the function \(\sf y=(1.6)^{x-9}+5\)

Therefore, the correct choice is C

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Answer:

2/8

Step-by-step explanation:

The number of classes in the frequency table as represented in the task content is; 5.

It follows from the task content that the number of classes in the frequency table as given in the task content is to be determined.

By observation, the data representation in the task content is a group data representation and hence, the classes are as follows;

On this note, the number of classes in the frequency table as given in the task content is; 5.

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Answer:

5 7/20

Step-by-step explanation:

Yw

Answer:

\(5\frac{7}{20}\)

Step-by-step explanation:

First see if both mixed numbers have the same common denominators.

\(9\frac{1}{10} -3\frac{3}{4}\)   different common denominators.

Find the LCM for both mixed numbers.

Answer: 20

10: 10, 20

4: 4, 8, 12, 16 and 20

Next convert each of the mixed numbers into a common denominator of 20.

\(9\frac{1}{10} =9\frac{2}{20}\)   \(3 \frac{3}{4} = 3\frac{15}{20}\)

For \(9\frac{1}{10}\) multiply the denominator by 2 to get a common denominator of 20. Whatever number you multiplied to the denominator, you multiply it to the numerator. Except the whole number of course.

Same thing goes to the other fraction! I'm running out of time :(

The volume of the solid generated by revolving the region bounded by the parabola y = x²/4 and the line y = 1 is 15π/4, and the line y = 2 is  37π/3 and the line y= -1 is 7π.

The parabola is y = x²/4 and the line is y = 1, y = 2 and y = -1 and it is needed to find the volume of the solid generated by revolving the region bounded by the parabola y = x²/4 and the line y = 1, 2 and -1 about these lines.

We sketch the parabola and the line y = 1. They intersect at points (-2, 1) and (2, 1). We rotate this shaded region about the line y = 1. So, the method of disks (washers) is appropriate here. We can integrate with respect to x, and so we slice perpendicular to the axis of rotation and integrate along x.

Axis of rotation: y = 1

Outer radius: R(x) = 1

Inner radius: r(x) = 1 - x²/4

Volume: V = π int_-2^2 (1² - (1 - x²/4)²)dx

On solving this, we get the volume of the solid generated by revolving the region bounded by the parabola y = x²/4 and the line y = 1 about the line y = 1 is V = 15π/4.

Now, we rotate this shaded region about the line y = 2. So, the method of disks (washers) is appropriate here. We can integrate with respect to x, and so we slice perpendicular to the axis of rotation and integrate along x.

Axis of rotation: y = 2

Outer radius: R(x) = 2 - x²/4

Inner radius: r(x) = 1

Volume: V = pi int_-2^2 ((2 - x²/4)² - 1²)dx

On solving this, we get the volume of the solid generated by revolving the region bounded by the parabola y = x²/4 and the line y = 1 about the line y = 2 is V = 37π/3.

Now, we rotate this shaded region about the line y = -1. So, the method of disks (washers) is appropriate here. We can integrate with respect to x, and so we slice perpendicular to the axis of rotation and integrate along x.

Axis of rotation: y = -1

Outer radius: R(x) = 1 + x²/4

Inner radius: r(x) = 1

Volume: V = pi int_-2^2 (1² - (1 + x²/4)²)dx

On solving this, we get the volume of the solid generated by revolving the region bounded by the parabola y = x²/4 and the line y = 1 about the line y = -1 is V = 7pi.

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An inequality which best models the situation described above is: D. 52 + 3w ≥ 90.

An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments (symbols):

In order to solve this word problem, we would assign a variable to the number of weeks and then translate the word problem into algebraic equation as follows:

Let w represent the number of weeks.

Translating the word problem into an algebraic equation, we have;

Next, we would combine the above parameters to form an algebraic equation as follows:

52 + 3w ≥ 90

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Complete Question:

Antonina needs to have worked at least 90 volunteer hours to graduate. She has already volunteered with a housing organization over the summer for 52 hours. Antonina needs to tutor after school for 3 hours per week to complete the remainder of her volunteer hours. If www is the number of weeks that Antonina needs to tutor in order to complete her volunteer hours, which of the following inequalities best models the situation described above?

answer choices

A. 52w + 30w ≥ 90

B. 52w + 30w ≤ 90

C. 52 + 3w ≤ 90

D. 52 + 3w ≥ 90

Answer:

Its 2

Step-by-step explanation:

Answer:

(5,7,8.6)

Step-by-step explanation:

Create a line on each the x axis and the y axis which intersects at a right triangle. The x axis line is 7 squares and the y axis is 5 squares. Now you can use the Pythagorean theorem.

a^2+b^2=c^2

7^2+5^2=c^2

49+25=c^2

74=c^2

8.6=c

Answer: C

Step-by-step explanation:

Answer:

35 rows and 35 numbers of plants in a row.

Step-by-step explanation:

Mark as brainliest

The forecast for May using a five-month moving average is 39 (Option E).

Moving average is used for smoothing out time series data to find any trends or cycles within the data. A five-month moving average is the average of the past five months. To calculate the moving average, add up the sales for the previous five months and divide it by five.

According to the question, the sales for the previous five months are: Nov. 39 Dec. 27 Jan. 40 Feb. 42 Mar. 41 April 47

We have to add the sales of these five months, which gives:

27 + 40 + 42 + 41 + 47 = 197

To find the moving average for May, we divide this sum by 5:

197 / 5 = 39.4

Since we have to round the answer to the nearest whole number, we round 39.4 to 39, which is option E.

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Answer:

V = 126 yd3

Step-by-step explanation:

The base: \(\frac{(9)(4)}{2} =\frac{36}{2} =18\)

The volume: \(v=(18)(7)=126yd^{3}\)

Hope this helps

The equation of the function is y = 10 * sin(x/2pi) + 5.

What is the sinusoidal function?

The period of a sinusoidal function is the time it takes for the sinusoidal function to complete one cycle of revolution.

The graph of a sinusoidal function can be represented by the equation:

y = A * sin(B(x - C)) + D

where A is the amplitude, B is the frequency, C is the horizontal shift, and D is the vertical shift.

From the information given, we know that the maximum point is at (0,5) and the minimum point is at (2pi,-5). We can use this information to find the values of A, B, C, and D.

The amplitude is the distance between the maximum and minimum points. In this case, it is 5 - (-5) = 10. So A = 10.

The period of the function is the distance between two consecutive maximum or minimum points. In this case, it is 2π.

So the frequency is 1/2π.

The horizontal shift is the amount by which the function is shifted along the x-axis. In this case, the maximum point is at x = 0, so the function is not shifted horizontally. So C = 0.

The vertical shift is the amount by which the function is shifted along the y-axis. In this case, the maximum point is at y = 5, so the function is shifted upward by 5. So D = 5.

So the equation of the function is:

y = 10 * sin(1/2pi (x - 0)) + 5

y = 10 * sin(x/2pi) + 5

where x is entered in radians.

Hence, the equation of the function is y = 10 * sin(x/2pi) + 5.

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Answer:

15 cm

Step-by-step explanation:

Since the square's side length is 8 cm, and one of its sides is the short leg of the triangle, the short leg of the triangle is 8 cm

Using the pythagorean theorem, solve for b (the missing side length x)

a² + b² = c²

8² + b² = 17²

64 + b² = 289

b² = 225

b = 15

So, the missing side length is 15 cm

When chemist mixes Chemical A and Chemical B to make a solution

Part A

When the quantity of chemical B = 48 ml, then the quantity of chemical A = 4 ml

Part B

When the quantity of chemical A = 9 ml, then the quantity of chemical B = 108 ml

A chemist mixes Chemical A and Chemical B to make a solution

She uses the same ratio of chemicals for each batch

The solution A and B are in linear relationship

y = kx

Where y is the quantity of chemical A

x is the quantity of chemical B

k is the constant

Substitute the values in the table and find k

36 = k × 3

k = 36 /3

k = 12

Part A

When chemical B = 48 ml

48 = 12 × x

x = 48 / 12

x = 4 ml

Part B

When chemical A = 9 ml

y = 12 × 9

y = 108 ml

Therefore, when Chemical B = 48 ml, chemical B is 4ml . When chemical A = 9 ml, Chemical B = 108 ml

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Answer:

  $0.187 per mile

Step-by-step explanation:

The sum of the expenses for the year is ...

  $1,187.25 +$118.80 +$300.00 +$75 +$614.80 +$34.90 +$1,780.00

  = $4110.75

Then the cost per mile is ...

  cost/miles = $4110.75 / 21986 ≈ $0.18697

The cost per mile is about $0.187, or 18.7¢ per mile.

__

If you need whole cents, that's about $0.19 per mile.

Answer:189 hours

Step-by-step explanation: 398 divided by 2 =199 -10 =189

Answer:

3 .62 lt

4 4300 g

5 1.78 mt

6 .0031 g

7 500 lt

8 .083 g

Answer:

X≤3

Step-by-step explanation:

This is because the arrow is moving down the number line

The discriminant of the given equation 6x² - 2x + k as required is; 4 - 24k.

The value of k for which the equation will result in two different real solutions is; k < 1/6.

Since the discriminant for the standard form quadratic equation; y = ax² + bx +c is given by the formula;

Discriminant, D = b² - 4ac

On this note, since; a = 6, b = -2 and c = k.

Discriminant, D = (-2)² - (4 × 6 × k).

D = 4 - 24k

Recall, when discriminant, D > 0; the equation would result in two different real solutions.

Therefore; 4 - 24k > 0

-24k > -4

k < 1 / 6.

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The statements that are true for Larry's Auto Shop, with regards to the fixed cost and variable cost of the organization is the option A.

A. Statement I and II are true

A fixed cost of production is a cost that remains the same as the production level changes. The basic infrastructure, rent, salaries, insurance, and taxes on the property are associated with the fixed cost of the organization.

The possible equation for the total cost for Larry, obtained from a similar question in the internet;

T = 50 + 10·q²

Where;

q = The quantities of repairs made by Larry's Auto Shop

I. When 0 repairs are produced, the variable cost is 0, therefore, the fixed cost = The total cost = 50 + 10 × 0² = 50

The fixed cost = The total cost

II. The above equation used to calculate the total cost = the fixed cost when 0 repairs are produced, indicates that the fixed cost = $50

III. The fixed cost is a fixed amount which remains the same for all amount of output produced, therefore, the the statement Larry Auto Shop's fixed cost depends on the level of output that is produced.

The possible statements in the question are;

I. When Larry's Auto Shop produces 0 repairs, its fixed cost equals its total cost

II. Larry's Auto Shop's fixed cost is equivalent to $50

III. The fixed cost of Larry Auto Shop depends on the level of output that is produced.

The options are;

(A) I and II are true

(B) I and III are true

(C) I, II, and III are true

(D) Statement I is true

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a) To maximize its net savings, the company should use the new machine for 7 years.  b) The net savings during the first year of use of the machine are $405 (rounded off to the nearest dollar).  c) The net savings over the period determined in part a are $1,833.33 (rounded off to the nearest cent).

Step-by-step explanation: a) To determine for how many years should the company use the new machine to maximize its net savings, we need to find the value of x that maximizes the difference between the savings and the costs.To do this, we need to first calculate the net savings, N(x), which is given by:S'(x) - C'(x) = 175 - x² - (x² + 11x) = -2x² - 11x + 175To find the maximum value of N(x), we need to find the critical values, which are the values of x that make N'(x) = 0:N'(x) = -4x - 11 = 0 ⇒ x = -11/4The critical value x = -11/4 is not a valid solution because x represents the number of years of operation of the machine, which cannot be negative. (i.e., not use it at all).However, this answer does not make sense because the company would not introduce a new machine that it does not intend to use. Therefore, we need to examine the concavity of N(x) to see if there is a local maximum in the feasible interval.

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Answer:

168...................

The critical numbers of the function f(x) = x¹⁰(x - 4)⁹are 0, 4. At x = 0, the function has a local minimum. At x = 4, the function has a local maximum.

The function f(x) = x¹⁰(x - 4)⁹has critical numbers where its derivative equals zero or is undefined. To find these critical numbers, we need to take the derivative of the function. Applying the product and chain rules, we obtain the derivative f'(x) = 10x⁹(x - 4)⁹ + 9x¹⁰(x - 4)⁸.

To find the critical numbers, we set f'(x) equal to zero and solve for x. By factoring out common terms, we have 10x⁹ (x - 4)⁸(x + 9) = 0. This equation yields three solutions: x = 0, x = 4, and x = -9.

Next, we examine the behavior of f(x) at these critical numbers. At x = 0, the function has a local minimum. As x approaches 0 from the left, f(x) decreases. As x approaches 0 from the right, f(x) increases. Thus, at x = 0, the function reaches a minimum point.

At x = 4, the function has a local maximum. As x approaches 4 from the left, f(x) increases. As x approaches 4 from the right, f(x) decreases. Therefore, at x = 4, the function reaches a maximum point.

The critical number x = -9 is not included in the given intervals, so we do not consider it further.

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Answer:n= 27

Sorry solved for 48 instead of 8 first time around.

Step-by-step explanation:

Answer:

C. 126

Step-by-step explanation:

We can use ratios to solve for corresponding side lengths.

\(\frac{140-x}{81} =\frac{x}{9}\)

Cross multiply.

\(9(140-x)=81x\)

\(140-x=9x\)

\(140=10x\)

\(14=x\)

Plug x as 14.

\(140-14=126\)

Area of a square: side length ^2

Side lenght = 3 inches

Replacing:

A = 3 ^2 = 9 in2

Answer= 9 squared inches