i need help ' please

Answer:

"The polar regions have long winters and short, cool summers."

Explanation:

Climate is the average of that weather. The climate record also includes extreme values such as record high temperatures or record amounts of rainfall.

For Climate example:

You can expect snow in the Northeast in January or for it to be hot and humid in the Southeast in July.

Answer:

hey mateee

Boyle's law :-  the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.

Boyle's law can also be formularized as P1V1 = P2V2

Charle's law :-  the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

Charle's law can also be formularized as V1/T1 = V2/T2  

Answer:

A small positively charged nucleus surrounded by revolving negatively charged electrons in fixed orbits

This means the molar mass of CH is

\(12.011+1.00794=13.01894 \text{ g/mol}\)

Dividing the given molar mass by this,\(\frac{104.1}{13.01894} \approx 8\)

This means the molecular formula is \(\boxed{\text{C}_{8}\text{H}_{8}}\)

To have 175ml is needed of a 9.0M \(H_{2} SO_{4}\) solution are needed to make 0.45 L of a 3.5 M (Morality).

The Morality unit (M) is \($ \frac{\text { moles of solute }}{\text { liters of solution }}=\mathrm{mol} / \mathrm{L} $\)

The volume of a solution grows when it is diluted, while the solute concentration stays constant.

The following is the formula for dilution of a solution:

\(\mathrm{M}_1 \mathrm{~V}_1=\mathrm{M}_2 \mathrm{~V}_2\)

here \(\mathrm{M}_1 , \mathrm{M}_2\) represents morality and \(\mathrm{~V}_1 , \mathrm{~V}_2\) represents volume of solution in litres (L).

We are given the values: \(&\mathrm{M}_1=9.0 \mathrm{M}=9.0 \mathrm{~mol} / \mathrm{L} \\&\mathrm{M}_2=3.5 \mathrm{M}=3.5 \mathrm{~mol} / \mathrm{L} \\&\mathrm{V}_2=0.45 \mathrm{~L}\)

Now to calculate the volume of the solution i.e. \(\mathrm{V}_1=\frac{\mathrm{M}_2 \mathrm{~V}_2}{\mathrm{M}_1}\)

\($\mathrm{V}_1=\frac{3.5 \mathrm{M} \times 0.45 \mathrm{~L}}{9.0 \mathrm{M}}=0.175 \mathrm{~L}$\)

In milliliters \($\mathrm{V}_1=0.175\mathrm{~L} \times \frac{1000 \mathrm{mL}}{1 \mathrm{L}}=175 \mathrm{~mL}$\)

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Answer:

Group 12

Explanation:

Answer:

I got all answers correct on my test and got 100%, this question was in the test which got correct

so your answer is group 12

Explanation:

Answer:

save it for future references

Explanation:

Answer:

some clothes or maybe even some makeup

Answer:

210

Explanation:

according to vectors since they are in two different direction u minus them

F1 =10 F2=220

F1 has a forward direction

while f2 goes backward

Answer:

-210N

Explanation:

you say acting force minus opposing force 10N-220N= -210N

When the temperature is constant and pressure is decreased the sample may undergo a phase transition or no change at all. When the pressure is constant and temperature is increased, the sample may undergo a phase transition or no change.

To determine the state of the sample of pure X at -216°C and 22.0 atm, we can use the phase diagram of the substance. Unfortunately, the phase diagram of pure X is not provided, so we cannot precisely determine its state. However, we can discuss the effects of changing pressure and temperature on the sample.

1. When the temperature is held constant at -216°C, and the pressure is decreased by 4.5 atm (to 17.5 atm), the sample will move along the isothermal line on the phase diagram. Depending on the initial state of the sample and the phase boundaries of pure X, the sample may undergo a phase transition (e.g., from solid to liquid or liquid to gas) or remain in the same phase.

2. If the pressure is held constant at 22.0 atm and the temperature is increased by 103°C (to -113°C), the sample will move along the isobaric line on the phase diagram. As the temperature increases, the sample is likely to undergo a phase transition (e.g., from solid to liquid or liquid to gas) depending on the specific phase boundaries of pure X.

Without more information on the phase diagram of pure X, we cannot definitively determine the state of the sample in these scenarios. However, these explanations demonstrate how the changes in pressure and temperature may affect the sample's state based on the general principles of phase diagrams.

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First of all, Z is unknown. I hope it is a mistake.

        Now, it is given that the element X has nineteen electrons. This proves that X is actually Potassium.

        As per the periodic table, both Potassium and Lithium belongs to group 1 as their valency is 1 because of the presence of only one electron in the outermost shell of electrons i.e., they lose an electron during a chemical reaction to form a stable compound. Furthermore, both are metallic.

        Magnesium belongs to group 2 and hence its valency is two, which is different from potassium though it is metallic. Similiarly, bromine belongs to group 17 and gains one electron during a reaction in contrast to potassium.

( No internal links available for reference. For clarification, check the periodic table).

The enthalpy change for the reaction that is represented above would be = 97 KJ/mol.

To calculate the enthalpy change(∆H⁰) of the above given reaction, the formula that should be used will be given below as follows:

∆H⁰ = ∆H of products- ∆H of reactants.

Where;

Reactants= 941+3(436)= 2,249KJ/mol

Product= 6(391) = 2,346KJ/mol

Therefore the enthalpy change(∆H⁰);

= 2,346-2,249

= 97 KJ/mol

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Answer:

Gap 1, S-Phase, Gap 2, Prophase, Metaphase, Anaphase, Telophase, Cytokinesis

Hope this helps.

The volume base added for the titration of 25.0 mL of 0.20 M hydrofluoric acid with 0.20 M sodium hydroxide is 25.0 mL.

To determine the volume of base added when pH is certain, we need to use the equation for the titration of a weak acid with a strong base, which is:

pH = pKa + log([base]/[acid])

Where pH is the desired pH, pKa is the acid dissociation constant of the weak acid, [base] is the concentration of the base (in this case, sodium hydroxide), and [acid] is the concentration of the acid (in this case, hydrofluoric acid).

Since we are given the initial concentration and volume of hydrofluoric acid (0.20 M, 25.0 mL), we can calculate the number of moles of hydrofluoric acid present:

n(acid) = C × V

= 0.20 M × 0.025 L

= 0.005 moles

Since hydrofluoric acid is a weak acid, we need to use the dissociation constant (Ka) to calculate the pKa:

Ka = [H⁺][F⁻]/[HF] = 7.2 x 10⁻⁴

pKa = -log(Ka) = 3.14

Now we can use the pH equation to calculate the concentration of sodium hydroxide needed to achieve a certain pH. For example, if we want a pH of 5.0:

5.0 = 3.14 + log([base]/[acid])

log([base]/[acid]) = 1.86

[base]/[acid] = \(10^{1.86}\)

= 75.13

[base] = 75.13 x [acid]

= 75.13 x 0.20 M

= 15.03 M

To find the volume of sodium hydroxide needed to reach this concentration, we can use the following equation:

n(base) = C x V

n(acid) = n(base) since they react in a 1:1 ratio

V(base) = n(base) / C(base)

= 0.005 moles / 0.20 M

= 0.025 L or 25.0 mL

Therefore, the volume of 0.20 M sodium hydroxide needed to achieve a pH of 5.0 when titrating 25.0 mL of 0.20 M hydrofluoric acid is 25.0 mL.



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Answer:5

Explanation:

Answer:

physical change

Explanation:

Answer:

0.33 moles

Explanation:

to find the number of moles,

moles = number of atoms / avogadro's number ie 6.02 x \(10^{23}\)

moles = 2.0 x \(10^{23}\) / 6.02 x \(10^{23}\)

moles = 0.33 mol

Answer:

23

Explanation:

From the Rutherford results of the atom, we can say that it would fit a planetary model of the atom.

We know that that atom is the smallest particle of a substance that can take part in a chemical reaction. There were various models of the atom that could be explained based on the empirical results that were obtained by the experiments of a lot of scientists.

In the case of the Rutherford model of the atom, we know that experiment had to do with the bombardment of the thin gold foil with alpha particles and some of the alpha particles were scattered at large distances.

A zinc sulfide screen was used to identify the positions of the alpha particles that were scatted in the course of the experiment as shown.

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Answer:

d

Explanation:

d

The solubility of NaCl when a saturated solution of NaCl is formed by adding 500g of NaCl to 0.500l of water where the excess solid NaCl is filtered from the solution is 5.23.

Given the mass of NaCl (m1) = 500g

The volume of water (V) = 0.5L

The reduced mass of NaCl (m2) = 346.8g

Filtered from the solution, the excess solid NaCl is dried in an oven.

The mass of NaCl dissolved in water = m1 - m2 = 500 - 346.8 = 153.2g

The mass of NaCl that will dissolve in 1L of water is = 2 x 153.2 = 306.4g/dm³

58.5g/mole is The molecular weight of NaCl

The amount of a substance in mol that will dissolve in 1 L or 1 dm³ of solution is known as its solubility.

Solubility in (g/dm³)/molar mass equals solubility in (mol/dm³).

(mol/dm³) solubility = 306.4/58.5

5.23 mol/dm³ is the solubility in (mol/dm³)

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The Bohr model is a representation of the electronic configuration of the atom. According to this model, each energy level can hold a certain number of electrons. In the first energy there can only be 2 electrons, in the second and the following energy levels there can be a maximum of 8 electrons.

Sodium, Na which has 11 electrons in total so in the first level it will have two electrons, in the second level it will have 8 electrons and in the third level it will have the missing electron.

In the model proposed by the student, the electrons are represented in blue. The model proposed by the student is incorrect.

We see that in the second energy level he drew 9 electrons, this is incorrect since from the second energy level there can only be 8 electrons, the remaining electron must be located in the third energy level.

Answer:

I say 20 is ur best option

Answer:he

H

Explanation:

541 grams is the mass of \(4.98\times 10^{24}\) atoms of Zn.

Explanation:

Given

The number of zinc atoms =\(4.98\times 10^{24}\)

To find:

The mass of given atoms of zinc atoms

Solution:

The number of zinc atoms =N=\(4.98\times 10^{24}\)

According to mole concept:

1 mole = Avogadro 's Number = \(N_A= 6.022\times 10^{23} atoms/ molecules/ions\)

Let the moles of zinc be = n

Number of atoms in n moles of zinc will be:

\(N=n \times N_A\\4.98\times 10^{24} atoms= n\times 6.022\times 10^{23} atoms\\n=\frac{4.98\times 10^{24} atoms}{ 6.022\times 10^{23} atoms}=8.27\)

Moles of zinc = 8.27 mol

Molar mass of zinc = 65.38 g/mol

Mass of 8.27 moles of zinc:

\(=8.27\times 65.38 g/mol=540.67 g\approx 541 g\)

541 grams is the mass of \(4.98\times 10^{24}\) atoms of Zn.

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Answer: A

Explanation:

Extreme weather events follow normal climate patterns.

Answer:

16 atm

Explanation:

Answer:

Below are some patterns in the charge for elements in each group.

Group 1 elements : 1 valence electron and form ions with charge +1

Group 2 elements : 2 valence electrons and form ions with charge + 2

Group 3 elements : 3 valence electrons and form ions with charge + 3(there are some exceptions as well)

Elements in groups 4 and 5 are unpredictable also the D block elements consist of multiple oxidation states..

Group 6 elements : 6 valence electrons, form ions with charge -2

Group 7 elements: 7 valence electrons, form ions with charge -1  

The octet rule is being followed, the elements form either ionic bond or covalent bond to fulfill it.

eg: when a K atom forms a K+ ion, the ion has the same electron configuration as the noble gas Ar (argon).

When an O atom gains 2 electrons to form the O²⁻ ion, the ion has the same electron configuration as the noble gas Ne (neon).  

Note: Boron (B) is in Group 3 but doesn't form ions.

A noticeable pattern in the charge for elements in each group of the periodic table is that: Elements in the same group have the same charge.

Discussion:

The pattern in the charge for elements in each group is characterized by the adoption of the same charge for elements in the same group irrespective of the period they are situated in.

An example is evident in the alkali metal, halogen and alkali Earth metals group.

The alkali metals lose their only Valence electron, to assume the octet configuration of the preceeding noble gas.

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0.10 moles per liter solution of the conjugate base sodium acetate is likely to have a pH greater than 7.

When acetic acid (CH3COOH) donates a proton, it forms its conjugate base, acetate ion (CH3COO-). In the given scenario, the acetic acid solution has a pH of 2.87, indicating acidity. The lower pH value suggests a higher concentration of H+ ions. As a weak acid, acetic acid partially dissociates, releasing H+ ions and acetate ions. When sodium acetate (CH3COONa) dissolves in water, it completely dissociates into sodium ions (Na+) and acetate ions. The presence of acetate ions (the conjugate base) from sodium acetate will react with the excess H+ ions in the solution, shifting the equilibrium towards the formation of acetic acid and water. This process, called the hydrolysis of salts, will consume the H+ ions, thereby increasing the pH of the solution. Consequently, the 0.10 mole per liter solution of sodium acetate is likely to have a pH greater than 7, making it basic.

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Answer:

20.25 W

Explanation:

Applying,

P = I²R.................... Equation 1

Where P = Power, I = current drawn by the test light, R = Resistance of the test light

From the question,

Given: I = 1.5 A, R = 9.00 Ω

Substitute these values into equation 1

P = (1.5²)(9)

P = 2.25×9

P = 20.25 W

Answer:

× = and

Explanation:

person and person

Approximately 108,066 J of heat is required to heat 352 g of water from 20.0°C to 93.7°C in an electric kettle.

To determine the quantity of heat required to heat 352 g of water from 20.0°C to 93.7°C, we need to use the specific heat capacity of water and the equation:

q = m × c × ΔT

ΔT = change in temperature (in °C)

First, we need to calculate the change in temperature:

ΔT = final temperature - initial temperature

ΔT = 93.7°C - 20.0°C

ΔT = 73.7°C

Substituting the given values into the equation, we get:

q = 352 g × 4.184 J/g·°C × 73.7°C

q = 108,066.496 J

q ≈ 108,066 J (rounded to three significant figures)

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A constant net force acting on an object of fixed mass produces accelerated motion.

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The equation that represents this relationship is:

F = ma

If the net force acting on an object is constant and the mass is fixed, the acceleration of the object will also be constant. This means that the object will undergo uniform acceleration, maintaining a consistent rate of change in its velocity over time.

In summary, a constant net force acting on an object of fixed mass produces accelerated motion with a constant acceleration.

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