I NEED HELP PLEASE!!!!!!

Answer:

g=20

Step-by-step explanation:

3g−10+10=50+10

3g=60

3g / 3 = 60/3

g=20

The second hand moves 6 degrees in one second, it will take it: 294/6 = 49 seconds to move from halfway between 1 and 2 to 4/5 of the way from 1 to 2.

The measure of the arc is 144 degrees.

When the second hand of the clock moves from halfway between the 1 and the 2 to 4/5 of the way from the 1 to the 2, it moves a total of 144 degrees.

This can be calculated as follows: The second hand of a clock completes one full revolution every 60 seconds or 1 minute.

This means that in 1 second, it moves 360/60

= 6 degrees.

To find the measure of the arc when the second hand moves from halfway between the 1 and the 2 to 4/5 of the way from the 1 to the 2, we need to find the difference between the two positions in degrees.

The position halfway between the 1 and the 2 is 1.5 on the clock face.

This is equivalent to 45 degrees (since the clock face is divided into 12 hours, each hour marking is 30 degrees apart, so halfway between 1 and 2 is 30+15 = 45 degrees).

4/5 of the way from the 1 to the 2 is 4/5 x 30 = 24 degrees from the 1 mark.

Therefore, the total angle between halfway between 1 and 2 and 4/5 of the way from 1 to 2 is:

24 + (360 - 45)

= 339 degrees.

However, we need to find the difference between these two positions, not the total angle.

Therefore, we need to subtract the position of the second hand at halfway between 1 and 2 from the position at 4/5 of the way from 1 to 2:

339 - 45

= 294 degrees.

Since the second hand moves 6 degrees in one second, it will take it:

294/6 = 49 seconds to move from halfway between 1 and 2 to 4/5 of the way from 1 to 2.

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Answer:

A

Step-by-step explanation:

espero que mi respuesta ayude

hope my answer helps

Daniel's method is incorrect, as the interquartile range is given by the difference between the third quartile and the first quartile.

The interquartile range of a data-set is by the difference of the 75th percentile(Q3) by the 25th percentile(Q1) of the data-set.

The quartiles are described as follows:

From this, we get that the quartiles are related to the median of the set, that is, neither is given by the highest and by the lowest values, hence the interquartile range is given by the difference between the third quartile and the first quartile.

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Step-by-step explanation:

The mean absolute deviation is:

MAD = ∑ᵢ₌₁ⁿ│xᵢ − μ│/ n

First, find the mean.

μ = (x + 2x + 3x + 4x) / 4

μ = 2.5x

Now find the mean absolute deviation:

MAD = (│x − 2.5x│+│2x − 2.5x│+│3x − 2.5x│+│4x − 2.5x│) / 4

MAD = (│-1.5x│+│-0.5x│+│0.5x│+│1.5x│) / 4

MAD = (1.5x + 0.5x + 0.5x + 1.5x) / 4

MAD = (4x) / 4

MAD = x

Option C, 2.58, is the correct choice for determining the control lines (UCL and LCL) in the "p" chart for a desired confidence level of 97 percent.

In statistical quality control, a "p" chart is used to monitor the proportion of nonconforming items or defects in a process. The UCL and LCL on the chart represent the control limits within which the process is considered in control. To calculate the control limits, we need to consider the desired confidence level. A confidence level of 97 percent corresponds to a significance level (alpha) of 0.03. The critical value "z" at this significance level can be obtained from a standard normal distribution table. The value of 2.58 corresponds to a cumulative probability of 0.995, which means that 99.5 percent of the area under the standard normal curve lies below this value. By using 2.58 as the value of "z," we ensure that the control limits encompass 97 percent of the data, leaving 1.5 percent in the tail on each side.

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Answer: (I worked left-right instead of column 1, then column 2. That's why the answers are jumbled up. 2 on my work corresponds to 4 in the pic, 3 corresponds to 2, 4 corresponds to 5, and 5 corresponds to 3.)

1. 75 degrees

2. 112 degrees

3. 89 degrees

4. x is 8, so 111 degrees

5. x is 3 in both cases, so 90 degrees each

6. x is -7, so 130 degrees

Step-by-step explanation:

1. Adjacent angles are the same measurement. Since the one labeled is 75 degrees, and the question marked angle is adjacent, it is also 75 degrees.

2. The angles shown are complementary, so they both equal 180 degrees. To find the angle marked with "?", subtract 68 from 180 for 112 degrees.

3. The angle labeled is 89 degrees. The one labeled with "?" should be the same, as it is below it, and on the same point as the labeled one. So, 89 degrees is the measurement.

4. The labeled angle is 69 degrees. 180 - 69 is 111 degrees. The equation shown now becomes 12x + 15 = 111. 111 - 15 is 96, which means 12x = 96. Divide both sides by 12 to get x equalling 8.

5. These lines are all perpendicular, so they're all 90 degrees. 29x + 3 = 90, and 31x - 3 = 90 are the new equations. I will attempt x as 3, to see if it's a true value. 29(3) is 87, and 87 + 3 is 90, so 3 is true there. 31(3) is 93, and 93 - 3 is also 90. So x is 3 in both cases

6. We already know one of the angles is 50 degrees. These are complementary, so subtract 50 from 180 to get 130 degrees. So, the equation is x + 137 = 130, which then becomes, 137 + -x = 130. 137 minus 30 is 7, so x is -7.

Answer:

1.) 75°

2.) 89°

3.) 90°  x = 3

4.) 112°

5.) 111°   x = 8

6.) 130°  x = -7

Step-by-step explanation:

1.) They are vertical so they measure the same

2.) They are corresponding angles so they equal the same

3.) They should equal up to 180.

29x + 3 = 31x - 3 (subtract 29x on both sides)

3 = 2x - 3 (add 3 on both sides)

6 = 2x (divide by 2 on both sides)

3 = x Plug in. 29(3) + 3 = 90 Both angles equal 90 degrees

4.) They should equal up to 180. 180 - 68 = 112

5.) They should equal up to 180. They are same side interior angles.                                                                             69 + 12x + 15 = 180 (collect like terms)

84 + 12x = 180 (subtract 84 on both sides)

12x = 96 (divide by 12 on both sides)

x = 8 Plug in 12(8) + 15 = 111 degrees

6.) They should equal up to 180.

x + 137 + 50 = 180 (collect like terms)

x + 187 = 180 (subtract 187 on both sides)

x = -7 Plug in -7 + 137 + 50 = 180 (collect like terms) 180= 180

Hope this helps ya!

My ans. is ...

Please mark me as a brainlist

The probability that among 10 random reactions, 5 have a final temperature of 271K and at least 4 have a final temperature of 274K is approximately 0.072.

To calculate the probability, we need to consider the number of ways we can choose 5 reactions with a final temperature of 271K and at least 4 reactions with a final temperature of 274K, out of the total possible combinations of 10 reactions.

1. The total number of combinations of 10 reactions is given by the binomial coefficient, which can be calculated using the formula C(n, k) = n! / (k! * (n - k)!). In this case, n = 10 and k = 5.

2. The number of ways to choose 5 reactions with a final temperature of 271K out of the 60 available reactions is C(60, 5).

3. The number of ways to choose at least 4 reactions with a final temperature of 274K out of the 92 available reactions is the sum of the combinations of choosing 4, 5, 6, ..., up to 10 reactions. We can calculate this by summing the individual binomial coefficients: C(92, 4) + C(92, 5) + C(92, 6) + ... + C(92, 10).

4. To find the probability, we divide the number of favorable outcomes (the combination of 5 reactions at 271K and at least 4 reactions at 274K) by the total number of possible outcomes (the total combinations of 10 reactions).

5. Finally, we calculate the probability by dividing the favorable outcomes by the total outcomes and round the result to three decimal places.

In this case, the probability is approximately 0.072.

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Answer:

About 4.44

Step-by-step explanation:

Let x represent the unknown amount of CD's sold each day. Thus, the linear equation is formed:

40-x = 2x + 3 (2x) Next collect like terms by adding x to both sides.

40-x+x= x + 2x + 3 (2x)

40 = 3x + 3 (2x)

40 = 3x + 6x

40= 9x

40/9 = 9x/9

x= 4.44

Note: 2x represents doubling up the sales amount, which was left.

3x represents tripling the sales amount left.

Answer:

y=3x+1=4

y=5x-1=4

Step-by-step explanation:

DO THE MATH

Answer:

Here is the ans ...hope it helps:)

Answer:

\(m\angle Y=30^{\circ}\)

Step-by-step explanation:

In any right triangle, the cosine of an angle is equal to its adjacent side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\(\cos Y=\frac{42\sqrt{3}}{84},\\Y=\arccos(\frac{42\sqrt{3}}{84})=\boxed{30^{\circ}}\)

The connection string for SQL Server using Windows Authentication is as follows:

Server=myServerAddress;Database=myDataBase;Trusted_Connection=True;

Specify the server address in the format "Server=myServerAddress". Replace "myServerAddress" with the name or IP address of the SQL Server instance you want to connect to.

Specify the name of the database you want to connect to in the format "Database=myDataBase". Replace "myDataBase" with the name of the database.

Use Windows Authentication by setting "Trusted_Connection=True". This means that the user running the application is authenticated using their Windows credentials, rather than a SQL Server login.

Use semicolons (;) to separate the different parts of the connection string.

Using Windows Authentication is a more secure and convenient way to connect to a SQL Server database, as it eliminates the need to store and manage login credentials in the application.

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Answer

SOLUTION

Problem Statement

The question asks us to insert the correct operator symbol depending on which number is greater, smaller or whether the two numbers are equal

The numbers given are:

Solution

To solve this problem, we need to ensure the two numbers are in the same form. Either they are both decimals or they are both fractions.

For this solution, we should make the fraction into a decimal and then compare the two numbers.

We should note that for negative numbers if a negative number is larger in magnitude than another negative number, then the negative number with the larger magnitude is actually the smaller number.

To illustrate this, take the following example:

Now that we understand the logic to use to solve the question, we can proceed to solve the question.

Let us now convert the fraction into a decimal:

After this, we can now compare the two numbers:

Therefore, the solution is:

Sarah's prediction for the number of online customers on May 14 follows a sinusoidal function, denoted as S(t). The formula for S(t) within the given time range of 0≤t≤12 is not provided in the question.

Jasmine's prediction, on the other hand, follows a quadratic function, denoted as J(t), where t represents the number of hours after 8 am. The formula for J(t) within the given time range of 0≤t≤12 is not provided in the question.

To determine the number of online customers predicted by each model at 7 pm on May 14, we need to substitute t = 11 (since 7 pm is 11 hours after 8 am) into the respective functions. Unfortunately, without the formulas for S(t) and J(t), we cannot calculate the specific number of online customers predicted by each model at that time.

To find the time(s) at which the difference in predicted online customers between the two models is greatest, we would need to plot the two functions on a graph and analyze their intersection points or highest/lowest points of discrepancy. However, since the formulas for S(t) and J(t) are not provided, we cannot determine the exact times or discrepancy values.

Similarly, without the formulas for S(t) and J(t), we cannot identify the specific times at which the two models predict the same number of online customers. To find these points, we would need to solve the equation S(t) = J(t), but without the functions, it is not possible.

In summary, without the formulas for S(t) and J(t), we are unable to provide the specific values for the number of online customers predicted by each model at 7 pm on May 14, determine the times with the greatest discrepancy, or identify the times at which the two models predict the same number of online customers.

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1) The lower class limits: 100, 200, 300, 400, 500, 600 .

2) The upper class limits:  199, 299, 399, 499, 599, 699.

3) The class width: 100.

4) Class midpoints: 149.5, 249.5, 349.5, 449.5, 549.5, 649.5.

5) Class boundaries : 99.5, 199.5, 299.5, 399.5, 499.5, 599.5, 699.5.

6) The number of individuals included in the summary : 155

The lower class limit in each class: 0,100, 200, 300, 400, 500, 600.

The upper-class limit is the biggest value in each class.

so the upper-class limit is:  99, 199, 299, 399, 499, 599, 699.

As we know the class width is the difference between the lower limit of one class and the lower limit of the previous class.

For example, 300 is the lower limit of one class and the lower limit of the previous class is 200 , so 300 - 200 = 100.

We know that, the class midpoints are the average of the limits of a class.

So, using midpoint formula the class midpoints are:

\(\frac{100+199}{2} = 149.5\\\\\frac{200+299}{2} = 249.5\\\\\frac{300+3199}{2} = 349.5\\\\\frac{400+499}{2} = 449.5\\\\\frac{500+599}{2} = 549.5\\\\\frac{600+699}{2} = 649.5\\\)

We know that the class boundaries are nothing but the end points of an open interval which contains the class interval.

So, the class boundaries for the first class = (99.5, 199.5)

the class boundaries for the second class = (199.5, 299.5)

the class boundaries for the third class = (299.5, 399.5)

the class boundaries for the fourth class = (399.5, 499.5)

the class boundaries for the fifth class = (499.5, 599.5)

The total of individuals is equal to the sum of all the frequencies of each class: 3 + 54 + 76 + 21 + 0 + 0 + 1 = 155

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The complete question is:

Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary. Blood Platelet Count of Males ​(1000 ​cells/mu​L) Frequency 0​-99 3 100​-199 54 200​-299 76 300​-399 21 400​-499 0 500​-599 0 600​-699 1 Identify the lower class limits​ (in 1000 ​cells/mu​L).

The writer's profit is $84.00. To calculate the writer's profit, you need to consider the premiums collected from selling the call options, the interest earned on those premiums, and the cost of buying the shares to complete the call contract.The premiums collected from selling the call options are:$0.91 x 100 = $91.00The interest earned on those premiums over 30 days at 5% is:($91.00 x 0.05 x 30) / 365 = $0.38The total amount of cash available to the writer at expiry is therefore:$91.00 + $0.38 = $91.38The cost of buying the shares to complete the call contract is:100 x $42 = $4,200.00Since the underlying asset is worth $39 at expiry, the writer can buy the necessary shares for:100 x $39 = $3,900.00The writer's profit is therefore:$91.38 - $3,900.00 = $84.00Since the writer made a profit, the answer is $84.00.

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The scale factor of the flagpole is 1/300.

A scale factor is a representative factor that can be used to either increase or decrease the size of a given object. This is majorly used in scale drawing.

scale factor = length on drawing/ original length

Given a flagpole of height 4.5 m but represented as 1.5 cm, then;

1.5 cm = 0.015 m

Then;

scale factor = 0.015/ 4.5

                    = 15/ 4500

                    = 1/ 300

The scale factor of the representation in the picture is 1/300.

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Answer:

102 degrees

Step-by-step explanation:

angle in a point is equal to 360 degrees

so 163+95=258

360-258=102

Answer: Im a banana

Step-by-step explanation:

Answer: −6x7+7x−1

Step-by-step explanation:

Distribute:

=(7)(x)+(7)(1)+−6x7+−8

=7x+7+−6x7+−8

Combine Like Terms:

=7x+7+−6x7+−8

=(−6x7)+(7x)+(7+−8)

Answer:

B

Step-by-step explanation:

Becuase 1 divide 1/2

You make the division sign a multiplication sign

1 time 1/2

get the recipricol of 1/2 wich is 2

1 times 2/1

is 2

Step-by-step explanation:

check it.. i have solved this for you

Answer:

18

Step-by-step explanation:

Using the product rule

Given

y = f(x). g(x) , then

\(\frac{dy}{dx}\) = f(x). g'(x) + g(x). f'(x)

Here

f(x) = \((2x+3)^{5}\) ⇒ f'(x) = 5\((2x+3)^{4}\) × \(\frac{d}{dx}\) (2x + 3) , then

f'(x) = 10\((2x+3)^{4}\)

g(x) = \((x+2)^{8}\) ⇒ g'(x) = 8\((x+2)^{7}\) × \(\frac{d}{dx}\) (x + 2) , then

g'(x) = 8\((x+2)^{7}\)

Thus

\(\frac{dy}{dx}\) = \((2x+3)^{5}\) . 8\((x+2)^{7}\) + \((x+2)^{8}\) . 10\((2x+3)^{4}\) ← factor expression

    = \((2x+3)^{4}\) \((x+2)^{7}\) [ 8(2x + 3) + 10(x + 2)

    = \((2x+3)^{4}\) \((x+2)^{7}\) (16x + 24 + 10x + 20)

    = \((2x+3)^{4}\) \((x+2)^{7}\) (26x + 44)

Thus

\(\frac{dy}{dx}\) ( x = - 1)

= \(1^{4}\) × \(1^{7}\) × 18

= 1 × 1 × 18

= 18