I need HELP please:( 1. Both of the equations shown have the same solution when solved for x. What is
the value of k? Show or explain all your work. *
5x + 34 = -2(1 – 7x) and – 3 (4x + 3) +4(6x + 1) = k
Your answer

Answer:

-18.76 , -18 7/25 , 18 9/36 , 18 19/20

Convert all of them to decimals then compare them

Answer: $37.50

Step-by-step explanation:

The probability of having zero errors is approximately 0.711.

The probability distribution that can be used to calculate the probability that zero errors will be found in a 255-word bond transaction is the Poisson distribution.

The Poisson distribution is a discrete probability distribution that is used to model the number of events occurring within a fixed interval of time or space, given the average rate of occurrence of the events.

In this case, the average rate of occurrence of errors is 6 per hour, which can be converted to 0.1 errors per minute. Therefore, the expected number of errors in a 255-word bond transaction is (255/75)*0.1 = 0.34 errors.

Using the Poisson distribution, the probability of having zero errors in a 255-word bond transaction can be calculated as:

\(P(X = 0) = (e^{(-\lambda)} * \lambda^0) / 0! = e^{(-0.34)} * 0.34^0 / 1! \approx 0.711\)

where λ is the expected number of errors in the 255-word bond transaction.

Therefore, the probability distribution used to calculate the probability of having zero errors in a 255-word bond transaction is the Poisson distribution, and the probability of having zero errors is approximately 0.711.

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The sides are given of the triangle.

Apply the heron's formula, to find the area of triangle.

The area of triangle obtained is 105.85 sq.cm.

To determine if a function has a vertical asymptote, you need to consider its behavior as the input approaches certain values.

A vertical asymptote occurs when the function approaches positive or negative infinity as the input approaches a specific value. Here's how you can determine if a function has a vertical asymptote:

Check for restrictions in the domain: Look for values of the input variable where the function is undefined or has a division by zero. These can indicate potential vertical asymptotes.

Evaluate the limit as the input approaches the suspected values: Calculate the limit of the function as the input approaches the suspected values from both sides (approaching from the left and right). If the limit approaches positive or negative infinity, a vertical asymptote exists at that value.

For example, if a rational function has a denominator that becomes zero at a certain value, such as x = 2, evaluate the limits of the function as x approaches 2 from the left and right. If the limits are positive or negative infinity, then there is a vertical asymptote at x = 2.

In summary, to determine if a function has a vertical asymptote, check for restrictions in the domain and evaluate the limits as the input approaches suspected values. If the limits approach positive or negative infinity, there is a vertical asymptote at that value.

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Answer:

The answer is 2+/- 2 over(/) 3

Step-by-step explanation:

You use the discriminant formula :)

The recommended approach when choosing between one-tailed and two-tailed tests is to use a two-tailed test only.

The choice between a one-tailed or two-tailed test should be based on the research hypothesis and the specific question being investigated.

If you have a convincing reason for not predicting a direction, and use the one that is most likely to produce significant results.

If the research hypothesis or question does not make a clear directional prediction, then a two-tailed test would be appropriate.

This is because a two-tailed test will consider the possibility of significant results in both directions of the distribution.

And is more conservative in its estimation of significance.

If the research hypothesis or question does make a clear directional prediction, then a one-tailed test would be appropriate.

This is because a one-tailed test will only consider the possibility of significant results in one direction of the distribution.

And is more powerful in detecting significant results in that specific direction.

Therefore, the answer is to use a two-tailed test only if you have a convincing reason for not predicting a direction, and use the one that is most likely to produce significant results.

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The ratio of the probability of flipping a tail to the probability of flipping a head when the probability of getting three heads is the same as the probability of getting exactly two tails in three flips is 1/3.

Let p be the probability of flipping a head and q be the probability of flipping a tail.

The probability of getting three heads in three flips is \((p)^3.\)

The probability of getting exactly two tails in three flips is 3pq².

Given that these probabilities are equal, we have:

\((p)^3\)= 3pq²

Simplifying this equation gives:

p = 3q

Dividing both sides by q gives:

p/q = 3

Therefore, the ratio of the probability of flipping a tail to the probability of flipping a head is 1/3.

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Answer:

1) Pr(all three) = 0.064

2) Pr(none) = 0.216

3) Independent event

Step-by-step explanation:

Let Probability of homes constructed in the Quail Creek area with a security system = Pr (security)

Where Pr = probability

This is a binomial distribution problem. There ate only two outcomes in this distribution: a success and a failure

Where p = success, q = failure

For n trials,

Pr(X = x) = n!/[(n-x)!x!] × p^x × q^(n-x)

Pr (security) = 40% = 0.4

p = 0.4

q = 1-p = 1-0.4 = 0.6

Numbers selected at random = n = 3

See attachment for more details on the workings.

1) Probability all three of the selected homes have a security system = Pr(all three)

Pr(all three) = 1× (0.4)³ (0.6)^0 = 0.4³

= 0.4×0.4×0.4

Pr(all three) = 0.064

2) Probability none of the three selected homes have a security system

= Pr(none)

Pr(none) = 1 × (0.4)^0 × (0.6)³

= 0.6³ = 0.6×0.6×0.6

Pr(none) = 0.216

3) The events were assumed to be independent as the selection of one house doesn't affect the outcome of the selection of another.

Answer:

The answer is the last one - X= 9.9 Y= 7

Answer:

x = 92

Step-by-step explanation:

Equation: x + 12 = 104

104 - 12 = 92

Answer:

x+12=104

x=92

Step-by-step explanation:

Subtract 12 from 104 to get your answer

Answer:

The decimal number system in use today was first recorded in Indian mathematics.

Step-by-step explanation:

In the classical period of Indian mathematics (400 AD to 1200 AD), important contributions were made by scholars like Aryabhata, Brahmagupta, Bhaskara II, and Varāhamihira. The decimal number system in use today was first recorded in Indian mathematics.

Answer:

Decimal point system.

Step-by-step explanation:

Answer:

41

Step-by-step explanation:

360-(104+104+111)=41

The profit to an investor who buys the call for $5.0 in the given scenarios:

(a) Profit = -$5.0

(b) Profit = $0

(c) Profit = $5.0

(d) Profit = $10.0

(e) Profit = $15.0

If the stock price is below the strike price of $40 in 6 months, the call option will expire worthless and the investor will lose the $5.0 premium paid for the call option.

If the stock price is above the strike price of $40 in 6 months, the call option will have some value, which will depend on the stock price at expiration.

(a) If the stock price is $40 at expiration, the call option will have no intrinsic value, and the investor will lose the entire $5.0 premium paid for the call option.

(b) If the stock price is $45 at expiration, the call option will have an intrinsic value of $5.0 (the difference between the stock price and the strike price), and the investor will break even (excluding transaction costs).

(c) If the stock price is $50 at expiration, the call option will have an intrinsic value of $10.0, and the investor will make a profit of $5.0 (excluding transaction costs).

(d) If the stock price is $55 at expiration, the call option will have an intrinsic value of $15.0, and the investor will make a profit of $10.0 (excluding transaction costs).

(e) If the stock price is $60 at expiration, the call option will have an intrinsic value of $20.0, and the investor will make a profit of $15.0 (excluding transaction costs).

In summary, the profit to an investor who buys the call for $5.0 will depend on the stock price at expiration. If the stock price is below the strike price of $40, the investor will lose the entire premium paid for the call option. If the stock price is above the strike price of $40, the investor will make a profit that depends on the difference between the stock price and the strike price.

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The answer for 2 + 2 in the addition is determined as 4.

Addition is a mathematical operation that involves combining two or more quantities or values to find their total or sum.

Addition is one of the four basic arithmetic operations, along with subtraction, multiplication, and division.

In addition operation, the two or more numbers are often added to produce result called the sum.

For example, in the equation; 2 + 2 = 4.

2 and 2 are the addends, and 4 is the sum.

We can also preform addition on fractions. decimas, percentages, etc.

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Statement II is false and statement III is true.

Thus, the correct answer is (B) I and III.

Since the utility function is U = X + 8Y, the partial derivative of U with respect to Y gives the marginal utility of good Y:

MUy = ∂U/∂Y = 8

Therefore, statement I is true.

The marginal rate of substitution (MRS) is the rate at which the consumer is willing to trade off good X for good Y, while maintaining the same level of utility. It is given by the ratio of the marginal utilities:

MRS(X,Y) = MUx/MUy

Substituting the given values gives:

MRS(X,Y) = 1/8

Multiplying both sides by 8 gives:

MRS(X,Y) = 1

Therefore, statement II is false and statement III is true.

Thus, the correct answer is (B) I and III.

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Answer:

30

Step-by-step explanation:

The total earnings of the bus driver in a year is $28500.

A function, according to a technical definition, is a relationship between a set of inputs and a set of potential outputs, where each input is connected to precisely one output.

The bus driver works 2000 hours each year and makes $14 per hour.

If the bus driver gets $50 for each new recruit he hired.

Let y be his total earnings and x be the number of new drivers he recruits.

Then his total earnings can be represented by the function:

y = 14 × 2000 + 50 × x

If the bus driver recruits x = 7 new drivers.

y = 28000 + 50 × 7

y = 28000 + 350

y = $28350

The total earnings of the bus driver are $2850.

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Answer:

D)  1.0

Step-by-step explanation:

if y = 1 then x = 1

Answer:

Below

Step-by-step explanation:

Pick a bunch of values of 'x' .....calculate the corresponding 'y' values then plot the ordered pairs and connect the dots with a smooth curved line ...

Answer:

-3,5,-10,16

Step-by-step explanation:

The second graph  represents the function \(f(x)=8^{\frac{1}{3} x}\)

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The given function is

\(f(x)=8^{\frac{1}{3} x}\)

At x=0, f(0)=1

At x=1, f(1)=2

At x=2, f(2)=4

The graph of f(x) passing through the points (0,1), (1,2), (2,4),(3,8).

According to these coordinates we can say that the graph of f(x) is represented by option 2.

Therefore correct option is 2.

Hence, the second graph  represents the function \(f(x)=8^{\frac{1}{3} x}\)

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The value of vector field  F(2, 1) is 2i + 4j. The correct option is a. 2i + 4j.

To find the value of the vector field F(x, y) at the point (2, 1), we substitute x = 2 and y = 1 into the components of the vector field.

A vector field is a mathematical concept used to describe a vector quantity that varies throughout a region of space. It associates a vector with each point in space, forming a field of vectors. In other words, at each point in space, the vector field assigns a vector with a specific magnitude and direction.

Vector fields are commonly used in physics, engineering, and mathematics to represent physical phenomena such as fluid flow, electromagnetic fields, gravitational fields, and more. They provide a way to visualize and analyze the behaviour of vector quantities in different regions of space.

F(2, 1) = y(2i) + x²y²(j)

F(2, 1) = 1(2i) + (2²)(1²)(j)

F(2, 1)

= 2i + 4j

Therefore, the value of F(2, 1) is 2i + 4j. The correct option is a. 2i + 4j.

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Answer:

Following are the solution to this question:

Step-by-step explanation:

For incentive A

The car value = 57000

Calculating debt\(= 57000 - 10000\)

                            \(= 47000\)

Calculating the debt value after incentive \(= 47000 - 5000\)

                                                                    \(= 42000\)

\(PMT = \frac{P(\frac{r}{n})}{(1 - (1 + (\frac{r}{n}))^(-nt))}\)

         \(= \frac{42000 \times (\frac{6.06 \%}{12})}{(1-(1+(\frac{6.06 \%}{12}))^{(-12 \times 4)})}\)

         \(= \frac{42000 \times (0.00505)}{(1-(1+(0.00505))^{(-48)})}\\\\= \frac{212.1}{(1-(1+(0.00505))^{(-48)})}\\\\=\frac{212.1}{-1.74}\\\\= - 121.89 \ \ or \ \ 121.89\)

For incentive  B

The car value = 57000

Calculating the debt value \(= 57000 - 10000\)

                                            \(= 47000\)

Calculating the monthly payment =\(\frac{47000}{(12*4)}\)

                                                        \(= \frac{47000}{(48)}\\\\= \frac{47000}{(48)}\\\\=979.166\)

difference:

\(=121.89 - 979.166\\\\ = - 854.276\)

It gradually decreases as alcohol is metabolized. The function C(t)=0.135 t e^{-2.802 t}models the mean BAC measured in g/mL.

The maximum average BAC during 3 hours is 0.0001358 g/mL.

f(t) = α t e−βt --(1)

Let's rewrite this in a simple form:

f(t)= α eˡⁿ ᵗ e⁻βt = αe^(ln t −βt)

Since e^x is strictly increasing and it will be maximized exactly when its argument is maximized, so we can maximize instead:

g(t)=ln t −βt

differentiating with respect to t , and g'(t) = 0

g′(t)=1/t − β = 0

=> t =1/β

we have given a function

C(t)=0.135 t e⁻²·⁸⁰²ᵗ

if we compare it with (1) we get

β = 2.802, 0.135 = α

For it's maximized we need to check the second order condition, and that of g will differentiate again , g′′(t)= −1/t² < 0

We have to compute the derivative of C(t):

C′(t) = 0.135 t⋅(−2.802)e⁻²·⁸⁰²ᵗ + 1.35e⁻²·⁸⁰²ᵗ

For optimum at t₀ if C′(t₀)=0 and C′′(t₀)≠0. Here, we have

C′(t₀) = 0.135t₀⋅(−2.802)e⁻²·⁸⁰²ᵗ₀+ 0.135e⁻²·⁸⁰²ᵗ₀ =e⁻²·⁸⁰²ᵗ₀(−0.135* 2.802t₀+ 0.135)=0

It is clear that e⁻²·⁸⁰²ᵗ₀ not equal to zero for all t₀∈R, so that

=> −0.135* 2.802t₀+0.135=0

=> t₀ = 1/2.802 ≈0.36

let us consider t is in hours, so that it makes t₀ =0.36h≈21.41min. This is the only optimum and one should verify it is indeed a maximum, i.e. C′′(t₀)<0.

Now, easily compute the maximum average BAC, which is C(t₀)=C(0.36) = 0.135 (0.36)e⁻²·⁸⁰²⁽⁰·³⁶⁾

= 0.0486(0.3678) = 0.01787508

Hence, the maximum average BAC, is 0.017 g/dL.

Maximum average BAC during the first 3 hours,

t = 3 , C(t)=C(3) = 0.135 (3)e⁻²·⁸⁰²⁽³⁾ = 0.0001358 g/mL

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Answer:

10

Step-by-step explanation:

Answer:

I believe its a triangular prism

Answer:

Triangular Prism

Step-by-step explanation:

Fold the shape at the dotted lines and you will see what shape it is. It's hard to explain but look up Triangular Prism and it will make sense.  

Answer:

70% of people surveyed liked the plan.

Step-by-step explanation:

Given that,

No. of people that liked the plan = 2,800

No. of people that did not like the plan = 1,200

We need to find what percentage of the people surveyed liked the plan. It can be given by :

\(\%=\dfrac{2800}{2800+1200}\times 100\\\\=70\%\)

So, 70% of people surveyed liked the plan.