Answers
first off you have to find out the meanings of the symbols add together then follow the insturctions
Related Questions
In determining the density of a rectangular metal bar, a student made the following measurements length 8 53 cm, width, 24 cm, height 10 cm, mass, 527064 g Calculate the
density of the metal to the correct number of significant figures
Answers
Answer:
d = 2.57456 g/cm³
Explanation:
Given data:
Length of metal bar = 853cm
Width = 24 cm
Height = 10 cm
Mass = 527064 g
Density of metal = ?
Solution:
Volume of metal bar:
Volume = length × width × height
Volume = 853 cm × 24 cm × 10 cm
Volume = 204720 cm³
Density:
d = m/v
d = 527064 g / 204720 cm³
d = 2.57456 g/cm³
Predict and explain the structure of the major and minor products when hydrogen bromide is added to 2-methylbut-2- ene, (Ch3)2CCHCH3
Pls help with homework!!!!
Answers
When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.
The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.
In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.
The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.
On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.
In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.
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What is the reactant(s) in the chemical equation below?
2Al(s) + 2NaOH(aq) + 2H2O()
2NaAlO2(aq) + 3H2(9)
A. 2Al(s) + 2NaOH(aq) + 2H200)
B. 2NaAlo2(aq) + 3H2(g)
C. 2Al(s)
D. 3H2(g)
Answers
Answer:
A
Explanation:
They are all found in the reactants side
define standard solution , molarity titrant and titrand
Answers
Answer:
In analytical chemistry, the titrant is a solution of known concentration that is added (titrated) to another solution to determine the concentration of a second chemical species. The titrant may also be called the titrator, the reagent, or the standard solution.
hope it helps (^^)
# Cary on learning
Why is it important to use scientific notation when talking about our solar system
and galaxies?
Answers
Answer:
The main purpose for converting numbers into scientific notation is to make calculations with surpisingly large or small numbers less complicated. Since zeros are not used to place the decimal point, all of the digits in a number in scientific notation are meaningful and easier to read. Hope this helps!
Explanation:
5) Read each Eco fact. Propose a solution to prevent the environmental problems of the
seaport of troy described in the eco fact.
Answers
Answer:
The creation of regulations that limit timber activities and the exploitation of wood can prevent soil erosion in Troy.
Explanation:
The exploitation of the wood was an intense activity and that did not have any regulation that would limit its damages, caused by its exploratory activities.
As the timber market was totally undisciplined, the exploitation of the wood caused a strong deforestation, leaving the soil totally unprotected and susceptible to strong erosion.
Soil erosion has a very negative impact on the environment, requiring regulations to be made to prevent this from happening.
Based on this, we can say that one way to prevent environmental problems in the seaport of troy is by establishing laws and regulations that limit logging activities.
What are the derived SI units?
Answers
3- There are 8
basic elements of
life. True or false?
Answers
Answer: No that is false.
Explanation: There are 6 basic elements of life here they are. Have cells, have chemicals, respond to stimuli, reproduce, grow and develop, and use energy.
sorting substances
below are some common substances. put in your experiences with these substances in the table below. we've filled out conductivity for you
Answers
Table salt does not melt on the stove, it dissolves in water and does not conduct electricity.
The nature of the substancesThere are several substances listed in the table Epsom salt is another one of these substances. It does not melt on a stove, it dissolves in water and also conducts electricity.
Finally, potassium chloride does not melt on the stove, it dissolves in water and it does conduct electricity. These are the experiences one can have with these common substances.
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50 points, and I’ll mark as brainliest!!!
Problem 1. Sea water contains dissolved salts at a total ionic concentration of about 1.13 mol×L–1. What pressure must be applied to prevent osmotic flow of pure water into sea water through a membrane permeable only to water molecules (at 25oC)?
Problem 2. What is the osmotic pressure of a solution prepared by adding 6.65 g of glucose to enough water to make 350 mL of solution at 35°C?
Problem 3. What is the osmotic pressure of a solution prepared by adding 9.0 g of glucose to enough water to make 450 mL of solution at 35°C?
Problem 4. What is the osmotic pressure of a solution prepared by adding 11.0 g of propanol to enough water to make 850 mL of solution at 25°C?
Problem 5. What is the osmotic pressure of a solution prepared by adding 65 g of glucose to enough water to make 35000 mL of solution at 15°C?
Answers
Answer:
Problem 1:
The osmotic pressure, π, can be calculated using the formula:
π = iMRT
where i represents the van't Hoff factor (the number of particles into which a solute dissociates), M represents the molar concentration, R represents the gas constant (0.082 Latm/molK), and T is the temperature in Kelvin.
The osmotic pressure of pure water is 0. As a result, sea water's osmotic pressure must be equal to the pressure necessary to prevent osmosis.
Assuming that sea water is an ideal solution, the total dissolved ion concentration is 1.13 mol/L. Because each dissolved salt molecule dissociates into two ions, the effective particle concentration is 2.26 mol/L.
Filling in the blanks in the formula:
0.918 atm = (2)(2.26 mol/L)(0.082 Latm/molK)(298 K)
Therefore, a pressure of 0.918 atm must be applied to prevent osmotic flow of pure water into sea water.
Problem 2: Glucose has a molar mass of 180.16 g/mol. The solution contains the following number of moles of glucose:
n = 6.65 g / 180.16 g/mol = 0.0369 mol
The molarity of the solution is:
M = n / V = 0.0369 mol / 0.350 L = 0.105 M
Substituting the values into the formula:
π = iMRT = (1)(0.105 M)(0.082 L·atm/mol·K)(308 K) = 2.74 atm
As a result, the osmotic pressure of the solution is 2.74 atm.
Problem 3:
Following the same procedure as in Problem 2, the molarity of the solution is:
M = n / V = 0.02 mol / 0.450 L = 0.044 M
Substituting the values into the formula:
π = iMRT = (1)(0.044 M)(0.082 L·atm/mol·K)(308 K) = 1.14 atm
As a result, the osmotic pressure of the solution is 1.14 atm.
Problem 4:
The molar mass of propanol is 60.10 g/mol. The number of moles of propanol in the solution is:
n = 11.0 g / 60.10 g/mol = 0.183 mol
The molarity of the solution is:
M = n / V = 0.183 mol / 0.850 L = 0.215 M
Substituting the values into the formula:
π = iMRT = (1)(0.215 M)(0.082 L·atm/mol·K)(298 K) = 4.59 atm
Therefore, the osmotic pressure of the solution is 4.59 atm.
Problem 5:
Following the same procedure as in Problem 2, the molarity of the solution is:
M = n / V = 65 g / (180.16 g/mol × 35 L) = 0.104 M
Substituting the values into the formula:
π = iMRT = (1)(0.104 M)(0.082 L·atm/mol·K)(288 K) = 2.06 atm
Therefore, the osmotic pressure of the solution is 2.06 atm.
Anisole (PhOCH3) reacts with iodine and H2O2 to yield p-iodoanisole. Below, draw
the single most important resonance contributor for the carbocationic intermediate
of this reaction that best explains this regiochemical selectivity.
Answers
The delocalization of the positive charge onto the oxygen atom also helps explain why the reaction is regioselective for the para position.
What is oxygen ?Oxygen is a chemical element with the symbol O and atomic number 8. It is a member of the chalcogen group on the periodic table and is a highly reactive nonmetallic element that readily forms compounds (notably oxides) with almost all other elements. By mass, oxygen is the third-most abundant element in the universe, after hydrogen and helium.
What is an element ?An element is a substance composed of atoms that have the same number of protons in the atomic nucleus. Elements are characterized by their atomic number, which represents the number of protons in the nucleus. The periodic table of elements is a tabular arrangement of the chemical elements, organized on the basis of their atomic number, electron configurations, and chemical properties.
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Stephan’s mother cuts a twig from a rose bush and plants it in the soil. After a few days, Stephan observes a new plant growing. Which characteristic does the growth of the new plant depict?
Answers
The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.
Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.
The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.
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What is the greatest
source of light in the
ocean?
Answers
Answer:
the greatest source of light in the ocean is the sun.
What volume (in mL) of water must you add to 25.0 mL of a 0.250 M NaBr solution to produce a 0.0275 M solution? Assume the volumes are additive.
Answers
Answer:
The volume of water added to make the diluted solution is 118.68 mL.
To solve this question, we'll begin by calculating the volume of the diluted solution. This can be obtained as follow:
Volume of stock solution (V₁) = 25 mL
Molarity of stock solution (M₁) = 0.250 M
Molarity of diluted solution (M₂) = 0.0435 M
Volume of diluted solution (V₂) =?
The volume of the diluted solution can be obtained as follow:
M₁V₁ = M₂V₂
0.25 × 25 = 0.0435 × V₂
6.25 = 0.0435 × V₂
Divide both side by 0.0435
V₂ = 6.25 / 0.0435
V₂ = 143.68 mL
Thus, the volume of the diluted solution is 143.68 mL
Finally, we shall determine the volume of water added to make the diluted solution.
Volume of stock solution (V₁) = 25 mL
Volume of diluted solution (V₂) = 143.68 mL
Volume of water added =?
Volume of water added = (Volume of diluted solution) – (Volume of stock solution)
Volume of water added = 143.68 – 25
Volume of water added = 118.68 mL
Therefore, the volume of water added to make the diluted solution is 118.68 ml
HOPE IT'S HELPFULMARK ME BRAINLIESTIn the following equation, how many grams of O2 are needed to react with 24.0 g of NH3?
4 NH3(g)+302(g) → 2N2(g)+6H₂O(1)
a) 45.1
b) 22.6
c) 33.9
d) 45.0
e) 135.5
Answers
33.6 g grams of O2 are needed to react with 24.0 g of NH3.
The molecular mass of NH3 = 14 + 3 = 17g
Given mass of NH3 = 24g
Firstly, we will calculate the number of moles.
Moles is defined as the ratio of given mass of substance to the molecular mass of substance.
Moles = given mass/ molecular mass
Number of moles of NH3 = 24/17
= 1.4 mole
Chemical reaction4 NH3(g)+302(g) → 2N2(g)+6H₂O(1)
4 moles of NH3 require 3 moles of O₂ to react.
1 moles of NH3 require 3/4 moles of O₂ to react.
1.4 moles of NH3 require 1.05 moles of O₂ to react.
Now we calculate the grams of O₂.
1.05 × 32 = 33.6 g.
Thus, we concluded that the 33.6 g grams of O2 are needed to react with 24.0 g of NH3.
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help What is the bestmethod for the preservation of water quality?
Answers
In an ecosystem, the best method for the preservation of water quality is that humans should cease all recreational and agricultural uses of water resources.
Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other. Components present include air, water, soil,etc.
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4.The voltaic cell has with Pt/H+/H2 and Ag/AgC/Cl- half cells is a possible design for an electronic pH meter, in that the actual cell E depends on [H3O+].
(a) Write out (under each half cell) the electrode reactions, and give below the overall cell equation.
(b) Indicate with arrows the direction of motion of the ions and electrons as the cell reacts spontaneously.
(c) Mark the electrodes as + or – and cathode or anode.
(d) What is the standard cell potential, Eo?
Eo = _______________________
(e) Calculate the actual cell potential, E, if the unknown [H3O+] is 1.0 x 10-4 M.
E = _________________________
(f) If [H+] remains variable, then for this cell E = A + B.pH. What are the values of the Constants A and B?
A = ____________ , B = ______________
Answers
Answer:
(a) Electrode reactions:
Pt/H+/H2: 2H+(aq) + 2e- -> H2(g) (reduction)
Ag/AgCl/Cl-: AgCl(s) + e- -> Ag(s) + Cl-(aq) (reduction)
Overall cell equation: 2AgCl(s) + H2(g) -> 2Ag(s) + 2HCl(aq)
(b) Direction of motion of ions and electrons:
In the Pt/H+/H2 half-cell, hydrogen ions (H+) move towards the platinum electrode and accept electrons to form hydrogen gas (H2). In the Ag/AgCl/Cl- half-cell, silver ions (Ag+) move towards the silver chloride (AgCl) electrode and accept electrons to form silver (Ag) metal while chloride ions (Cl-) move away from the electrode. Electrons move from the hydrogen electrode to the silver electrode through the external circuit.
(c) Electrode labeling:
The Pt/H+/H2 electrode is the cathode (-) and the Ag/AgCl/Cl- electrode is the anode (+).
(d) Standard cell potential (Eo):
The standard cell potential can be calculated using the standard reduction potentials for each half-cell:
Eo(cell) = Eo(reduction, Ag/AgCl/Cl-) - Eo(reduction, Pt/H+/H2)
Eo(reduction, Ag/AgCl/Cl-) = +0.222 V (from standard reduction potential tables)
Eo(reduction, Pt/H+/H2) = 0 V (by definition)
Eo(cell) = +0.222 V - 0 V = +0.222 V
(e) Actual cell potential (E):
E(cell) = Eo(cell) - (0.0592 V / n) * log[H3O+]
where n is the number of electrons transferred in the balanced equation (2 in this case)
E(cell) = +0.222 V - (0.0592 V / 2) * log(1.0 x 10^-4 M)
E(cell) = +0.222 V - (0.0296 V) = +0.1924 V
(f) Values of constants A and B:
E(cell) = A + B.pH
At pH 7 (neutral), E(cell) = Eo(cell) = +0.222 V
Therefore, A = +0.222 V and B = -0.0592 V/pH
Write the electron configuration for O^2- ion
Answers
Answer:
\(1 {s}^{2} 2 {s}^{2} 2 {p}^{2} \)
Explanation:
The solution is in the image
Answer:
[He] 2s² 2p⁴
What is electron configuration?The arrangement of electrons in an atom, molecule, or other physical structure like a crystal. Electron configuration describes the distribution of electrons among different orbitals (including shells and subshells) within atoms and molecules.
a molecule is the ___________particle of a substance that can normally exist independenty
Answers
Answer:
a molecule is the smallest particle of a substance that can normally exist independenty
What is the male reproductive part of the plant that produces pollen
Answers
Answer:
Stamen
Explanation:
Answer:
stamen
Explanation:
The stamen is the male reproductive organ. It consists of a pollen sac (anther) and a long supporting filament.
molar solubility of chromium(III) hydroxide in a water solution to be 1.28×10-8 M. what is the solubility product CONSTANT? 6.7 × 10-31 is the ksp at 25 c
Answers
At 25 °C, chromium(III) hydroxide has a dissolution rate constant (Ksp) of 6.74 10–31.
Why would someone employ hydroxide?Manufacturers can use sodium hydroxide to create products including soap, rayon, paper, explosives, pigments, and petroleum goods. Sodium hydroxide can also be used for cleaning or processing metal, oxidizing surfaces, electroplating, and electrolytic extraction.
Cr(OH)3(s) = Cr(OH)3(aq) + 3OH- (aq)
Ksp = [Cr3+] is the expression for the Ksp in this equilibrium.
[OH-]^3
It is said that Cr(OH)3 is 1.28 10-8 M molar solubility. Hence, the saturated solution's Cr3+ and OH- ion concentrations are both 1.28 10-8 M.
The Ksp expression is obtained by substituting the concentration values: Ksp = [Cr3+].
[OH-]^3 = (1.28×10^-8 M)(3(1.28×10^-8 M))^3 = 6.74×10^-31
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8. Match the following:
1.Warp
2. Retting
3.Ginning
4.Weft
a. Removal of gunny matter from the stem of a flax or jute plant by bacterial action in stagnant water.
b. The length wise yarn in the loom.
c. The cross wise yarn in the loom. d.. Removal of seeds from cotton
Answers
Answer:
c
Explanation:
Teeth and long bones are good indicators of age in children; ribs and joints are better for adults.
1. True
2. False
Answers
The answer is True not False
I need help answering these
How many significant figures are in each of the following numbers?
a. 225.0
c. 0.0003210
b. 1000.0
d. 0.0067
e. 1,000,000.
f. 2.00001
Round off each of the following numbers to three significant figures.
a. 15.9994
c. 0.6654
e. 87,550
b. 1.0080
d. 4885
f. 0.027225
3. Perform the indicated arithmetic operations, and round the results to the appropriate number of significant figures or decimal places.
a. 77.981 x 2.33
b. 4 x 0.0665 =
c. 17.344.900 + 23.1
d. 9.80 4.762 =
e. 3.9 X 6.05 X 420 =
f. 14.1/5
g. 1001 + 16.23 =
h. 424.5+ 2.8461 =
i. 9.9-9.54
j. 7.3778 0.000265 =
k. (24.358)(6.4)
1. (48.6)(0.6959)
Answers
a. 225.0 has 4 significant figures.
b. 1000.0 has 4 significant figures.
c. 0.0003210 has 6 significant figures.
d. 0.0067 has 4 significant figures.
e. 1,000,000 has 7 significant figures.
f. 2.00001 has 6 significant figures.
Question 2
a. 15.9994 rounded to three significant figures is 16.0.
b. 1.0080 rounded to three significant figures is 1.01.
c. 0.6654 rounded to three significant figures is 0.665.
d. 4885 rounded to three significant figures is 4885.
e. 87,550 rounded to three significant figures is 88,000.
f. 0.027225 rounded to three significant figures is 0.0272.
Question 3
a. 77.981 x 2.33 = 181.081 (rounded to 3 significant figures)
b. 4 x 0.0665 = 0.266 (rounded to 3 significant figures)
c. 17,344,900 + 23.1 = 17,344,923.1 (rounded to 7 significant figures)
d. 9.80 - 4.762 = 5.038 (rounded to 3 significant figures)
e. 3.9 x 6.05 x 420 = 8,595.89 (rounded to 2 decimal places)
f. 14.1 / 5 = 2.82 (rounded to 2 decimal places)
g. 1001 + 16.23 = 1017.23 (rounded to 4 significant figures)
h. 424.5 + 2.8461 = 427.3461 (rounded to 4 decimal places)
i. 9.9 - 9.54 = 0.36 (rounded to 2 decimal places)
j. 7.3778 / 0.000265 = 27,864.345 (rounded to 3 decimal places)
k. (24.358) x (6.4) = 156.3712 (rounded to 4 decimal places)
(48.6) x (0.6959) = 33.88594 (rounded to 5 decimal places)
What is significant figures?Significant figures of a number in positional notation are described as digits in the number that are reliable and necessary to indicate the quantity of something.
Decimal places on the other hand are described as positions of the digits to the right of a decimal point. Rounding numbers to decimal places is shortening a decimal number to a given degree of accuracy.
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classify each acid as strong or weak. if the acid is weak, write an expression for the acid ionization constant (ka). a. hf b. hcho2 c. h2so4 d. h2co3
Answers
The kinds of the acids are;
a - Weak acid
b) Weak acid
c) Strong acid
d) Weak acid
What is Weak acid?We know that a strong acid is an acid that is able to ionize completely in solution. As a result of this, the ionization constant would be large. On the other hand, a weak acid is the kind of acid that can not be able to ionize completely when it is in solution.
Having said this, we have to look at the ionization of each of the acids and this would help us to know which of the acids is a strong or a weak acid as the case may be.
a) \(Ka = [H^+] [F^-]/[HF]\)
b) \(Ka = [H^+] [CHO_{2} ^-]/[HCHO_{2}]\)
c) \(Ka = [H^+]^2 [SO_{4} ^{2-} ]/[H_{2} SO_{4}]\)
d) \(Ka = [H^+] [HCO_{3} ^-]/[H_{2} CO_{3}]\)
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3. How did you distinguish if the given sample is a mixture or a substance? (3 points)
Answers
Answer:
Explanation:
If a substance can be separated into its elements, it is a compound. If a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture.
how is she ddv hbggobyg khggub
Answers
What do you think all the stuff around you and in the universe itself is made from??
Answers
The universe contains practically incalculable numbers of planets, moons, asteroids, comets, and clouds of dust and gas, all of which are whirling around in the expanse of space together with billions of galaxies and trillions of stars.
What Is the Universe Made of?Helium is the second most prevalent element in the universe after hydrogen, and the two together make up almost all ordinary stuff. But only a little portion of the universe—about 5%—is represented by this. Everything else is constructed of materials that are invisible and can only be identified indirectly. About 100 seconds after the Big Bang, the temperature dropped to a still-seething 1 billion degrees Kelvin, during which all of the matter that makes up the known elements in the periodic table, as well as all other objects in the universe, such as black holes, massive stars, and specks of space dust, were created.About 380,000 years later, the universe had cooled to the point that protons and neutrons could combine to make lithium, helium, and the hydrogen isotope deuterium, while free electrons were trapped to create neutral atoms.To learn more about Big bang theory, refer
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What is the male portion of a zygote referred to.
egg cell
sperm cell
Answers
Answer:
sperm cell
Explanation:
The male portion of a zygote is called the sperm cell. The sperm cell are produced by the male organism and they fertilize the eggs.
The female portion of the zygote is called the egg cell. During fertilization, the male sperm cell and the female egg cells unites. The unity forms a zygote. This zygote continues to develop into a viable offspringBalancing redox reaction
Answers
The balanced redox reaction equation can be given as;
2BrO2 + 4OH- + N2O4 → 2BrO3- + 2H2O + 2NO2-
How do you balance the redox reaction?
Making sure that the number of electrons acquired in the reduction half-reaction equals the number of electrons lost in the oxidation half-reaction is necessary to balance a redox (reduction-oxidation) reaction.
Give each element in the chemical equation an oxidation number. This process aids in identifying how the oxidation states vary throughout the reaction. Find the total redox equation's oxidation half-reaction and reduction half-reaction.
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