Answer:
humen body temperature 98.6f 37c 310.15k
room temperature 68f 20 to 22c 293k
frezing poknt of water tempreture 32f 0c 273.2 K
A car is moving along a road at 28.0 m/s with an engine that exerts a force of
2,300.0 N on the car to balance the drag and friction so that the car maintains a
constant speed. What is the power output of the engine?
Answer:
Power = Force × Distance/time
Power = Force × Velocity
Power = 2,300.0 N × 28.0 m/s²
Power = 64400 Nm/s
Explanation:
First show the formula of Power
Re-arrange formula and used to work out Power
Pretty simple stuff!
Hope this Helps!!
Boxes are dragged along a rough surface. Calculate the acceleration of the following object below
Given:
The coefficient of friction, μ=0.37
The mass of the box, m=8 kg
The force applied to the box, F=32 N
To find:
The acceleration of the box.
Explanation:
The net force acting on the box is given by,
\(\begin{gathered} F_n=F-f \\ =F-mg\mu \end{gathered}\)Where g is the acceleration due to gravity.
On substituting the known values,
\(\begin{gathered} F_n=32-8\times9.8\times0.37 \\ =2.992\text{ N} \\ \approx3\text{ N} \end{gathered}\)From Newton's second law, the net force acting on the object is given by,
\(F_n=ma\)Where a is the acceleration of the object.
On substituting the known values,
\(\begin{gathered} 3=8\times a \\ \Rightarrow a=\frac{3}{8} \\ =0.375\text{ m/s}^2 \end{gathered}\)Final answer:
The acceleration of the box is 0.375 m/s²
Find the y-component of this
vector:
47.3 m
39.4°
Answer: 36.55
Explanation:
Answer:it is 30.03
Explanation:
Find series expansion of 1/ z^2-3z+2 in region |z| <2
Expand the given expression into partial fractions.
\(\dfrac1{z^2 - 3z + 2} = \dfrac1{(z-2)(z-1)} = \dfrac1{(2 - z) (1 - z)} = \dfrac1{1 - z} - \dfrac1{2 - z}\)
Recall the infinite geometric series,
\(\displaystyle \sum_{n=0}^\infty z^n = \dfrac1{1-z}\)
which converges in the unit disk |z| < 1.
The unit disk is a subset of the given region |z| < 2, so there are no issues with the convergence of series expansion of the first expression. For the second expression, we rearrange terms as
\(\dfrac1{2 - z} = \dfrac12 \times \dfrac1{1 - \frac z2}\)
Then if |z/2| < 1, or equivalently |z| < 2, the series expansion for this term is
\(\displaystyle \frac1{2-z} = \frac12 \sum_{n=0}^\infty \left(\frac z2\right)^n = \sum_{n=0}^\infty \frac{z^n}{2^{n+1}}\)
Putting everything together, the series expansion of the given expression over |z| < 2 is
\(\displaystyle \frac1{z^2-3z+2} = \sum_{n=0}^\infty \left(1 + \frac1{2^{n+1}}\right) z^n\)
PLEASE HELP ASAP
When you taste food, your brain processes the taste information so that you
are aware of it. Most of this processing occurs in the mind.
A. preconscious
B. conscious
C. selective attentive
D. unconscious
Answer:
D: unconscious
Explanation:
Apex have a nice day :)
Answer: D. Unconscious
Explanation:
a p e x
Sweating is one of the main mechanisms with which the body dissipates heat. Sweat evaporates with a latent heat of 2430 kJ/kg at body temperature, and the body can produce as much as 1.4 kg of sweat per hour. If sweating were the only heat dissipation mechanism, what would be the maximum sustainable metabolic rate, in watts, if 80% of the energy used by the body goes into waste heat?
The maximum sustainable metabolic rate of the body is 1140.8 W.
Latent heat of the sweat, L = 2340 x 10³ kJ/kg
Amount of sweat produced, m' = 1.4 kg/hr = 3.9 x 10⁻⁴ kg/s
Given that 80% of the energy used by the body goes into waste heat.
Power is equal to the heat dissipated by the body per unit time.
P = m'L
0.8P = 3.9 x 10⁻⁴x 2340 x 10³
P = 3.9 x 10⁻⁴x 2340 x 10³/0.8
P = 912.6/0.8
P = 1140.8 W
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The charge of an electron is 1.6x10^'' C. How many electrons does it take to make 1 C of charge?
Answer:
If the charge on an electron be 1.6X10^-19 C, find the approximate number of electrons in 1 C. ANSWER: - As it is given that 1.6 X 10-19charge is of 1 electron, So 1 C charge is of = 1/1.6X10-19electron Now number of electrons = 1019/1.6 = (100 X 1018) / 16
what is the springs constant?
The spring constant, symbolized k, is a proportionality constant that shows the relationship between the force applied to a spring and the amount of stretch or compression it undergoes in response.
In simple terms, the spring constant relates the force that is required to extend or compress a spring by a certain distance.
This is what is known as Hooke's Law, named after the scientist Robert Hooke.
According to Hooke's Law, the force required to compress or stretch a spring is directly proportional to the distance that the spring has been compressed or stretched.
Hooke's law can be expressed mathematically as: F = -kx, where F is the force being applied to the spring, x is the distance the spring is stretched or compressed from its equilibrium position, and k is the spring constant.
The negative sign in the equation indicates that the direction of the force is opposite to the direction of displacement of the spring.
The units of the spring constant depend on the units of the force and displacement used in the equation.
In SI units, the spring constant is measured in Newtons per meter (N/m).
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which of the following is an example of a nonrival resource? responses national park camping sites that can be reserved by anyone national park camping sites that can be reserved by anyone farmland that can be used to grow corn or soybeans farmland that can be used to grow corn or soybeans solar energy solar energy fish in the ocean fish in the ocean timber in a forest
Radio and the internet are two instances of nonrival resource. They can be accessed by many individuals simultaneously without compromising their quality or increasing the chance that the supply would run out.
What is a nonrival resource example?Radio stations and the internet are two instances of nonrival goods. They are available to many individuals at once, and they can been consumed repeatedly without lowering their quality or increasing the chance that the energy will run out.
Which of the below economic models allocates resources and distributes goods primarily based on prices?In a market economy, market forces govern the resources that are distributed and the costs of goods and services. mainly demand and supply. Since there is little government interference in market economies, all management choices are made by private ownership.
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What type of tv uses a VfL for backlighting
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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Select the correct answer from each drop-down menu.
Rocky metallic objects found between the orbits of Mars and Jupiter are(drop down). The largest known of these is(drop down).
Answer:
Blank 1 (asteroids)
Blank 2 (Ceres)
Explanation:
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
What are asteroids?Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]
A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
The correct option from the drop-down menu is asteroids and ceres.
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Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.
The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.
What is hydrostatic pressure?Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.
The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:
P = ρgh + Po
where:
P is the absolute pressure at the given depth
ρ is the density of the water
g is the acceleration due to gravity (assumed to be 9.81 m/s²)
h is the depth of the ocean
Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)
Substituting the given values, we get:
P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa
P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa
P = 1.002 x 10^8 Pa.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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For a circuit find the total potential differences if two resistors
of resistance R1 and R2 respectively kept series wise for a
current I passing through it.
-- If the two resistors are connected in series, then they behave like a single resistor whose resistance is (R₁ + R₂) ohms.
-- For any resistance, the potential difference (volts) across the resistance is V = (current) x (resistance) .
-- So in THIS circuit, V = I x (R₁ + R₂) .
Background information:
We know that power is the rate that work is done; what that
really means is that power tells up how much work is done every
second. To calculate power we just divide the amount of work that
was done by the time it took to do it (Power=work/time). Work is
measured in Joules and time is measured in seconds, we end up with Joules/sec when we calculate power. A Joule/sec is a Watt; we’ll use Watts to measure and compare power.
We also know that the work done on an object is the amount of energy it has gained. For this activity, you’ll be raising your body up as you do pushups which means you’ll be giving your body gravitational potential energy (GPE). To calculate the amount of GPE we multiply mass time gravity times the height raised (GPE=mgh).
What to do (record everything in the table):
1. You need to have a decent estimate of your mass in kilograms: On earth, every
kilogram weighs 2.2 pounds. Either measure your weight on a scale or just
estimate it (in pounds) then divide by 2.2 to get your mass in kilograms.
2. Measure or estimate the length of your upper arm from your elbow to your
shoulder in centimeters...this is how high you raise yourself for every pushup.
3. Decide if you’ll do regular pushups (on your toes) or simpler pushups (knees). If
you are doing regular pushups, multiply your mass by 0.68 because you’ll only be lifting about 68% of your mass each time; if you’re doing simpler pushups, multiply your mass by 0.52 because you’ll only be lifting about 52% of your mass each time.
4. Measure the time it takes for you to do 10 pushups.
Answer:
Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation. The standard metric unit of power is the Watt.
Explanation:
A constant force of 5KN pulls a crate along a distance of 15 m in 75s.What is the power
Explanation:
We know,
1KN = 1000N
Then, Force(F) = 5*1000N
=5000N
Here,
Power (P)=Work(W)/Time(T)
=Force * distance/ Time (W = F*s)
= 5000*15/75
=1000
So, The power of body or object is 1000Watt.
I hope this will be helpful for you.
laser light (λ = 568.7 nm) is incident on a single slit. what is the maximum width of the slit (in nm) for which no diffraction minima are observed? round to the closest integer.
The maximum width of the slit (in nm) for which no diffraction minima are observed is 569 nm.
What is the maximum width of the slit?The maximum width of the slit (in nm) for which no diffraction minima are observed is calculated by applying the following equation.
sinθ = mλ/a
where;
m is = 1 order integerthe maximum angle for diffraction to occur = 90⁰λ is the wavelength = 568.7 nma is the maximum width of the slitSubstitute the given parameters and solve for the maximum width of the slit (in nm) for which no diffraction minima are observed.
sin(90) = (1 x 568.7 nm) / a
1 = (568.7 nm) / a
a = (568.7 nm) /1
a = 568.7 nm
to the closest integer = 569 nm
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can anyone write for me all the equation of linear motion
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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A toy helicopter with a mass of 20 kg experiences a gravitational force of 200 N. (a) What is the resultant force on the toy helicopter if it is ascending with a constant speed of 5 ms ¹? (b) What is the force acting on the helicopter if the rotor suddenly stops working? (c) What will happen to the helicopter in (b)?
(a) The resultant force on the toy helicopter if it is ascending with a constant speed of 5 m/s is zero.
(b) The force acting on the helicopter if the rotor suddenly stops working is 200N.
(c) In (b), if the rotor suddenly stops working, the helicopter will fall downward due to the force of gravity. If there is no other force to oppose the force of gravity, the helicopter will accelerate downward at a rate of approximately 9.81 m/s².
(a) The resultant force on the toy helicopter if it is ascending with a constant speed of 5 m/s is zero. The force of gravity, which is 200 N, is equal in magnitude and opposite in direction to the force of the toy helicopter exerting on the air to ascend with a constant speed of 5 m/s. Therefore, the resultant force is zero.
(b) The force acting on the helicopter if the rotor suddenly stops working is 200 N, which is equal in magnitude and opposite in direction to the force of the toy helicopter exerting on the air. When the rotor suddenly stops working, there is no longer a force to keep the toy helicopter in the air. The force of gravity then takes over, causing the helicopter to fall downward at an increasing speed due to the acceleration due to gravity, which is approximately 9.81 m/s².
(c) In (b), if the rotor suddenly stops working, the helicopter will fall downward due to the force of gravity. If there is no other force to oppose the force of gravity, the helicopter will accelerate downward at a rate of approximately 9.81 m/s². This acceleration due to gravity will cause the speed of the helicopter to increase as it falls. Without any means of propulsion or control, the helicopter will continue to fall downward until it reaches the ground or collides with an object.
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Question 5 of 10
The graph below shows the downloads of two songs over time.
70
Song 1
60
50
40
Number of downloads
(spopunu)
Song 2
30
20
10
O
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Time (minutes)
Which term describes the slope of the graph of song 2 between minute 6 and
minute 7?
A. Positive
B. Zero
C. It is impossible to calculate
D. Negative
SUBMIT
Answer:
b
Explanation:
write down the value of
920 kg in g
Answer:
920000
Explanation:
Each kg contains 1,000 grams
An airplane flies 2500 miles east in 245 seconds what is the velocity of the plane?
Speed = (distance) / (time)
Speed = (
Velocity = speed, and its direction
The velocity of the plane is 10.2 miles per second East.
(about 48 times the speed of sound)
A sample of helium behaves as an ideal gas as it is heated at constant pressure from 283 K to 358 K. If 70 J of work is done by the gas dur- ing this process, what is the mass of the he- lium sample? The universal gas constant is 8.31451 J/mol · K. Answer in units of g.
The mass of the helium sample is approximately 0.187 g.
To solve this problem, we can use following formula:
w = nR(T2 - T1)
We can rearrange this formula to solve for n:
n = w / (R * (T2 - T1))
To find the mass of the helium sample, we can use following formula:
m = n * M
where m is the mass of the sample, n is number of moles of gas, and M is the molar mass of helium.
Substituting the given values into the first equation, we get:
70 J = n * 8.31451 J/mol*K * (358 K - 283 K)
Simplifying this equation, we get:
n = 0.0467 mol
Substituting this value into the second equation, we get:
m = 0.0467 mol * 4 g/mol = 0.187 g
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In the event of a car collision, car 1 (m=1300 kg, v=12.5 m/s) collides with a stationary car (m=1500 kg). The two cars slide off with a velocity of 6.3 m/s, how much energy is lost to friction, sound, etc., during the collision?
*
The amount of energy lost to friction, sound, and other factors during the collision is 48620.15 J.
In the event of a car collision, the momentum of the two vehicles changes as a result of the impact, and energy is transferred from one vehicle to the other.
The impact will result in a loss of energy due to friction, sound, and other factors. Therefore, to calculate the amount of energy lost during the collision, we need to determine the total kinetic energy of the system before and after the collision, and the difference between the two is the energy lost.
To calculate the initial kinetic energy, we need to use the formula 1/2mv², where m is the mass of the object and v is its velocity. Therefore, the initial kinetic energy of car 1 is:KE1 = 1/2 x 1300 kg x (12.5 m/s)² = 101562.5 J The stationary car has no initial kinetic energy since it is at rest.
The total initial kinetic energy of the system is therefore: KE initial = KE1 + KE2 = 101562.5 J To calculate the final kinetic energy, we need to use the velocity of the two cars after the collision.
The problem states that the two cars slide off with a velocity of 6.3 m/s. Therefore, the final kinetic energy of the system is: KE final = 1/2 x (1300 kg + 1500 kg) x (6.3 m/s)² = 52942.35 J.
The energy lost during the collision is the difference between the initial and final kinetic energy: Energy lost = KE initial - KE final = 48620.15 J.
Therefore, the amount of energy lost to friction, sound, and other factors during the collision is 48620.15 J.
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A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs.
time t.
What is the instantaneous velocity of the crow at t = 9 s ?
A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs. time t.
What is the instantaneous velocity of the crow at t = 9 s?
Answer: -0.50 m/s
A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
From the figure, it shows that from t = 8sec to t = 12 sec the displacement is decreasing, so velocity will be the slope of the straight line.
The velocity is given by:
velocity = -Δx ÷ Δt
velocity = (-2) ÷ (12-8)
velocity = -2 ÷ 4
velocity = -0.5 m/s
Therefore, A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
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A pair of closely spaced parallel conducting plates, charged with equal and opposite electric charges, produces a uniform electric field in the region between them. In designing a cutting‑edge device that will revolutionize the electronics industry, Leticia sets up such a pair of plates separated by a distance 0.999 mm, then charges them so that the direction of the electric field in their interior region points from plate A to plate B. Her idea requires that electrons, when released from rest at one of the plates, reach the other plate at the speed of 1.71% of the speed of light. The speed of light is =3.00×108 m/s. 2 questions:
At which plate should the electrons be released?
B
either A or B
A
cannot be determined
What is the strength of the electric field?
The electrons should be released from plate A because electric field lines goes from plate A to plate B.
What are cathode and anode?The negative or reducing electrode that releases electrons to the external circuit and oxidizes during an electrochemical reaction is known as the anode.
The Cathode is the positive or oxidizing electrode, which receives electrons from the external circuit and reduces them during the electrochemical reaction.
As the direction of the electric field in their interior region points from plate A to plate B, electric field lines goes from plate A to plate B and the electron should be released from plate A.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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name a type of relationship between current and potental difference for a resistor at constant temperature
Answer:
The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.
Explanation:
I Looked It Up. So It May Be Wrong But I Hope This Helps!
Answer:
The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.
Let the force of the Moon on the Earth be F1. Let the force of the Earth pulling on the Moon be F2. Which of the following is greater?
The magnitude of the electric field due to a point charge object at a distance 4.0 m is 9 N/C. From the same
charged object the electric field of magnitude, 16 N/C will be at a distance of
The electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.
The magnitude of the electric field due to a point charge object follows the inverse square law, which states that the magnitude of the electric field is inversely proportional to the square of the distance from the charged object. Mathematically, this is expressed as:
\(E = k*q/r^2\)
where E is the electric field, k is Coulomb's constant (\(k = 9 x 10^9 N*m^2/C^2\)), q is the charge of the object, and r is the distance from the object.
We can use this formula to find the distance at which the electric field has a magnitude of 16 N/C. Let's call this distance x:
16 = \(k*q/x^2\)
We can rearrange this equation to solve for x:
x = \(\sqrt(k*q/16)\)
To find q, we need another piece of information. We know that the electric field has a magnitude of 9 N/C at a distance of 4.0 m. Using the same formula as before, we can solve for q:
9 = \(k*q/4^2\)
q = \(9*4^2/k\)
Now we can substitute this value for q into the equation for x:
x =\(\sqrt(k*(9*4^2/k)/16)\)
x =\(\sqrt(9*4^2/16)\)
x = \(\sqrt(36)\)
x = 6.0 meters
Therefore, the electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.
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