I need answers to these please number them.

Answer:

av58&3+6-0/（7+6）so answer is

The value of the quantity d is 0.0462 m^2/s.

Here,

The quantities a=3.7m, b=3.7s, c=80m/s.

We have to find the value of d = a^3/cb^2

What is quantity?

A quantity is an amount, number, or measurement that answers the question 'how much?' Quantities can be expressed in numbers or non-standard units.

Now,

The quantities a=3.7m, b=3.7s, c=80m/s.

The value of d;

\(d = \frac{a^{3} }{cb^{2} }\)

\(d = \frac{3.7*3.7*3.7 }{80 * 3.7^{2} }\)

\(d = \frac{3.7}{80}\)

\(d = 0.0462\)

Hence, The value of the quantity d is 0.0462 m^2/s.

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Answer:

Simplified form of \(\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}\) is \(\mathbf{\frac{1}{(x+3)(x+4)} }\)

Option A is correct answer.

Step-by-step explanation:

We need to find simplified form of \(\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}\)

Solving the given expression:

\(\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}\)

First we find factors of \(x^2+x-6\)

\(x^2+x-6 \\= x^2+3x-2x-6\\= x(x+3)-2(x+3)\\=(x-2)(x+3)\)

So, factors of \(x^2+x-6\) are \((x-2)(x+3)\)

Now, fining the factors of \(x^2+5x+4\)

\(x^2+5x+4\\=x^2+4x+x+4\\=x(x+4)+1(x+4)\\=(x+1)(x+4)\)

So, factors of \(x^2+5x+4\) are \((x+1)(x+4)\\\)

Now the given expression will become:

\(\frac{x+1}{(x-2)(x+3)}\div \frac{(x+1)(x+4)}{x-2}\)

Now, converting division sign into multiplication sign:

\(=\frac{x+1}{(x-2)(x+3)}\times \frac{x-2} {(x+1)(x+4)}\\Cancelling, \:common\:terms\\=\frac{1}{(x+3)(x+4)}\)

So, simplified form of \(\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}\) is \(\mathbf{\frac{1}{(x+3)(x+4)} }\)

Option A is correct answer.

Answer:Let's call the distance of the boat trip "d".

Since the whole trip took 5 hours, and Maxwell was driving for part of it, we know that:

d/40 + x/60 = 5

where x is the number of hours Maxwell spent driving.

We also know that the distance he drove is equal to the total distance minus the boat trip:

275 - d = x * 60

So we can substitute this into the first equation:

d/40 + (275 - d)/60 = 5

Expanding and simplifying this equation gives us:

6d = 1800

Finally, dividing both sides by 6 gives us:

d = 300

So the boat trip was 300 miles long.

Step-by-step explanation:

Let's call the distance of the boat trip "d".

Since the whole trip took 5 hours, and Maxwell was driving for part of it, we know that:

d/40 + x/60 = 5

where x is the number of hours Maxwell spent driving.

We also know that the distance he drove is equal to the total distance minus the boat trip:

275 - d = x * 60

So we can substitute this into the first equation:

d/40 + (275 - d)/60 = 5

Expanding and simplifying this equation gives us:

6d = 1800

Finally, dividing both sides by 6 gives us:

d = 300

So the boat trip was 300 miles long.

Answer:

5

Step-by-step explanation:

If Lisa has x quarters and Brenda has 3x quarters, we can write:

80% * 3x = 4 + (20% * 3x + x) -- We write 4 because 1 dollar =  4 quarters

0.8 * 3x = 4 + (0.2 * 3x + x)

2.4x = 4 + 1.6x

0.8x = 4

x = 5

Answer:

9

Step-by-step explanation:

RST = 90

90 - (22 + 41) = 27.

3x = 27

27/3 = 9

x = 9

Answer:

D

Step-by-step explanation:

when graphing inequalities if the shaded region is below the line then it is less than. Solid line makes it equal to. Line is going downwards so slope is negative. y intercept is in the negative region.

The inequality which is shown in this graph is y ≥ 2x - 2, the correct option is C.

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

An inequality is a mathematical statement that compares two values or expressions using a relational operator, such as less than (<), greater than (>), less than or equal to (≤), greater than or equal to (≥), or not equal to (≠). Inequalities are used to describe relationships between quantities or to express constraints or conditions.

We are given that;

The graph

Now,

The inequality that is shown in this graph is C. y ≥ 2x - 2. This is because the graph shows a solid line with a slope of 2 and a y-intercept of -2, which is the equation y = 2x - 2. The solid line means that the points on the line are included in the solution set of the inequality. The shaded region above the line means that the points in that region satisfy the inequality.

Therefore, by the inequality the answer will be y ≥ 2x - 2.

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The given information that X0=1, X1=4, X2=1, X3=3, and X4=3 further restricts the possible values that X5 can take.

The realization of the stochastic process implies that the values of the stochastic process are observed at particular points in time. It is denoted by x(t) and takes the form of a function of time t.

If the process is discrete, then the function is a sequence of values at discrete points in time.

A stochastic process is one that evolves over time and the outcomes are uncertain.

The given expression P(X5=3|X4=3,X3=3,X2=1,X1=4, X0=1) gives the probability of X5 being equal to 3 given that X4 is equal to 3, X3 is equal to 3, X2 is equal to 1, X1 is equal to 4, and X0 is equal to 1.

To understand the above expression, suppose we have a stochastic process with values X0, X1, X2, X3, X4, and X5.

The given expression provides the conditional probability of the value of X5 being equal to 3 given that X0, X1, X2, X3, and X4 take specific values.

The given information that X0=1, X1=4, X2=1, X3=3, and X4=3 further restricts the possible values that X5 can take.

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Answer:

Tommy bought 6 boxes

Step-by-step explanation:

subtract 35 from 191, and you get 156. 156 divided by 26 = 6. so 6 boxes

As the interest rate increases from 10 percent to 11 percent, the present value of the bond decreases from $1,074.47 to $1,058.31. Conversely, when the interest rate decreases to 9 percent, the present value increases to $1,091.19. This is because the discount rate used to calculate the present value is inversely related to the interest rate, meaning that as the interest rate increases, the present value decreases, and vice versa.

To compute the present value of a five-year, 10 percent coupon bond with a face value of $1,000, we need to discount the future cash flows (coupon payments and face value) by the appropriate interest rate.

Step 1: Calculate the present value of each coupon payment.
Since the bond has a 10 percent coupon rate, it pays $100 (10% of $1,000) annually. To calculate the present value of each coupon payment, we need to discount it by the interest rate.

Using the formula: PV = C / (1+r)^n
Where PV is the present value,

C is the cash flow,

r is the interest rate, and

n is the number of periods.

At an interest rate of 10 percent, the present value of each coupon payment is:
PV1 = $100 / (1+0.10)^1 = $90.91

Step 2: Calculate the present value of the face value.
The face value of the bond is $1,000, which will be received at the end of the fifth year. We need to discount it to its present value using the interest rate.

At an interest rate of 10 percent, the present value of the face value is:
PV2 = $1,000 / (1+0.10)^5 = $620.92

Step 3: Calculate the total present value.
To find the present value of the bond, we need to sum up the present values of each coupon payment and the present value of the face value.
Total present value at an interest rate of 10 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,074.47

When the interest rate goes to 11 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 11 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,058.31

When the interest rate goes to 9 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 9 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,091.19

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Answer:

y = -1/7x -6/7

Step-by-step explanation:

y = mx +b

m = -1/7

y = -1/7x +b

-4 = -1/7(-2)

-4 = -2/7

-4 + -2/7 = b

b = -6/7

y = -1/7x -6/7

I save $2.34  on each play by buying a season ticket.

A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.

Given, A season ticket to the Olde Theater costs $76 and admits you to 6 plays.

∴ The cost of 1 play is,

= $76/6.

= $12.66.

Now, single tickets to each play cost $15.

∴ I save on each play by buying a season ticket is,

= $(15 - 12.66).

= $2.34.

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The company will need 25,877,136 gumdrops to fill 3,234,642 bags.

Explanation:

If a candy company puts 8 gumdrops in each bag, we need to find the total number of gumdrops the company needs to fill 3,234,642 bags.

Step 1: Calculate the total number of gumdrops in one bag.

The company puts 8 gumdrops in each bag.

So, the total number of gumdrops in one bag is 8.

Step 2: Calculate the total number of gumdrops the company needs to fill 3,234,642 bags.

To calculate the total number of gumdrops the company needs to fill 3,234,642 bags, we need to multiply the number of gumdrops in one bag (8) by the number of bags (3,234,642).

Therefore, the calculation is:

Total number of gumdrops = 8 × 3,234,642

Total number of gumdrops = 25,877,136

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Answer:

12

Step-by-step explanation:

Answer:

q = 10

Step-by-step explanation:

-3(q - 7) = -9

-3q + 21 = -9

-3q = -9 - 21

q = -30/-3

q = 10.

Answer:

125

Step-by-step explanation:

In ΔPTO we are given that

∠PTO = 90° (indicated by the right angle)

and ∠TPO = 35°

And we need to find the exterior angle (∠TOB)

If you didn't know this is the rule about exterior angles

Exterior angles of a triangle are equal to the sum of the opposite interior angles of a triangle

So more specifically for this problem

∠TOB = ∠PTO + ∠TPO

Now that we have created an equation we want to plug in the values that we are given

∠TOB = 90 + 35

90 + 35 = 125

Therefore the answer is 125

we need to understand the concept of probability and how it is related to the mean and emissions. Probability is the likelihood or chance of an event occurring.

In this case, the event is the number of alpha particle emissions of carbon-14 counted by a Geiger counter per second. The mean is the average value of these emissions. The question asks us to find the probability that it takes no longer than 1 second for the second count.

This means that we need to find the probability of observing a count of alpha particle emissions equal to or less than the mean value of 25 in one second.

We can use the Poisson distribution to calculate this probability. The Poisson distribution is used to model the number of occurrences of an event in a given time period or space.

It assumes that the occurrences are independent and random, and that the mean and variance of the distribution are equal. In this case, the mean and variance are both 25.

Using the Poisson distribution formula, we can calculate the probability of observing a count of alpha particle emissions equal to or less than 25 in one second.

The formula is: P(X ≤ 25) = e^(-λ) * Σ(λ^k / k!), where λ is the mean value, k is the number of occurrences, and Σ is the sum from k=0 to k=25. Plugging in the values, we get: P(X ≤ 25) = e^(-25) * Σ(25^k / k!) Using a calculator, we can evaluate this sum and get: P(X ≤ 25) = 0.3841.

Therefore, the probability of observing a count of alpha particle emissions equal to or less than 25 in one second is 0.3841 or 38.41%. In conclusion,

the probability of observing a count of alpha particle emissions equal to or less than the mean value of 25 in one second is 0.3841. This means that there is a 38.41% chance of observing this event in one second.

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From the graph of the system of equations y = 3x - 8 and 6x - 2y = 10, there is no solution

An equation is an expression that uses mathematical operations to show the relationship between numbers and variables. Types of equations are linear, quadratic, cubic and so on.

The standard form of a linear equation is:

Ax + By = C

Where A, B and C are constants

The slope intercept form of a linear equation is:

y = mx + b

Where m is the slope and b is the y intercept

The slope of the line passing through points (x₁, y₁) and (x₂, y₂) is:

m = (y₂ - y₁) / (x₂ - x₁)

Given the system of equations:

y = 3x - 8        (1)

and:

6x - 2y = 10     (2)

From the graph of the equations, there is no solution

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Answer:

1/11

Step-by-step explanation:

probability =total number of items ÷ 1

=11÷1

=1/11

Answer:

Speed of the car is equivalent to 159.39 KM/hour or 2.6565 Km/min.

-Step by Step-:

-The speed of the car is given as  99 mi/hour.

Now, WE know that 1 Mile = 1.61 KM

Hence, in order to calculate the speed of the car in KM/hour we will multiply the speed of the car in miles with 1.61.

⇒The speed of the car in KM/hour = 99 × 1.61 KM = 159.39 KM/hour

Also, 1 hour = 60 minutes

⇒ Speed of the car in KM/min = (159.39) ÷ 60 = 2.6565 K/min

Answer:

x=65

Each NBA team can have a maximum of 15 players, 13 of which can be active each game.

65/5=13 so it's safe to say tgat 5 team can be crated

Step-by-step explanation:

x/5-2=11-->transposing x/5=11+2---->x=13×5--->x=65

verification 65/5-2=11--->13-2=11

The point (-7,4) is the farthest from the point and the distance is 11 units away, the correct option is (d).

We have to find that which point is the farthest from the point (4,4),

The distance(d) between two points (x₁, y₁) and (x₂, y₂) can be calculated by the distance formula : √((x₂-x₁)² + (y₂-y₁)²);

Using this formula, we can find the distance between each of the points and (4, 4):

⇒ For point (-7, 4):

d = √((4 - (-7))² + (4 - 4)²)

d = √(11²)

d = 11 units

⇒ For point (4, 4):

d = √((4 - 4)² + (4 - 4)²)

d = 0 units

⇒ For point (4, -5):

d = √((4 - 4)² + (-5 - 4)²)

d = √(9²)

d = 9 units,

Therefore, the point farthest away from (4, 4) is (d) Point (-7, 4), and the distance is 11 units.

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The given question is incomplete, the complete question is

A graph with the x-axis starting at -10, with tick marks every one unit up to 10. The y-axis starts at -10, with tick marks every one unit up to 10. A point is plotted at (-7, 4), at (4, 4) and at (4, -5).

Which of the points plotted is farther away from (4, 4), and what is the distance?

(a) Point (4, -5), and it is 9 units away

(b) Point (4, -5), and it is 11 units away

(c) Point (-7, 4), and it is 9 units away

(d) Point (-7, 4), and it is 11 units away

Answer:

Step-by-step explanation:

<3 = 55° ( vertically opposite angles )

<4 = 180 - 105 = 75° ( linear pair )

<5 = 180 - ( 55 + 75 ) ( angle sum property of a triangle )

    = 180 - 130

    = 50°

<1 = <2 ( angles opposite to equal sides )

let < 1 and < 2 be x

55 + 2x = 180 ( angle sum property of a triangle )

2x = 180 - 55

2x = 125

x = 125 / 2

x = 62.5

therefore, < 1 = <2 = 62.5°

Hope this helps

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Answer:

The number of miles traveled is the independent variable.

The amount of money spent is the dependent variable.

Step-by-step explanation:

They keyword here is "per". You are spending .6 dollars for every mile traveled

Answer:

C = dependent

M = independent

Step-by-step explanation:

Hopefully this helps you  :)

pls mark brainlest. ;)

The most appropriate choice for area of rectangle will be given by:

Width of rectangle is 2 ft

What is area of rectangle?

Area of rectangle is the total space taken by the rectangle.

If the length of rectangle be \(l\) ft and breadth of rectangle be \(b\) ft, area of rectangle \(l \times b\)  \(ft^2\)

Here,

Let the width of the rectangle be w ft

Length = 7ft

Area  = 7 x w \(ft^2\)

By the problem,

7 x w = 14

w = \(\frac{14}{7}\)

w = 2 ft

Width of rectangle is 2 ft

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Problem 1

We're given that QE = RW and QW = RE. This is given both in terms of symbols, and also visually in terms of the tickmarks. We have two pairs of congruent sides.

The third pair of sides is the overlapping shared segment of segment WE. So WE = WE by the reflexive property.

From here we use the SSS congruence property to conclude the proof that triangle QWE = triangle REW

==============================================

Problem 2

Segments BC and AE bisect each other. The term "bisect" means "to cut in half".

BC bisecting AE means AD = DE

AE bisecting BC means BD = DC

So we have two pairs of congruent sides. So far, we're on a similar path compared to problem 1. This time however, we'll use a pair of congruent angles instead of the third pair of sides.

Specifically we'll use the fact that

angle ADB = angle CDE

by the vertical angle theorem

Once we know that, we then use the SAS congruence theorem to prove triangle ABD = triangle ECD

To be honest, I'm not sure what you meant by "median", but we don't use any triangle medians here (none of the triangles shown have any medians drawn). You might be thinking of a previous problem.

Step-by-step explanation:

i hope this helps this is how u answerd to my question

If the researcher had used H0 >= 38 as the alternative hypothesis instead of H1 < 38, the p-value would have been (1-0.0627) = 0.9373. This can be calculated using the complement rule for probabilities. So, the correct option is A).

The given hypothesis is

H0: µ = 38 (null hypothesis)

Ha: µ < 38 (alternative hypothesis)

Given: Sample mean = 35 and p-value = 0.0627

We need to find the p-value if the researcher had used Ha: µ > 38 instead of Ha: µ < 38.

The new alternative hypothesis is

Ha: µ > 38

We can find the new p-value as follows

p-value = P(Z ≤ z-score) [For a one-tailed test]

where z-score = (sample mean - hypothesized mean) / (standard deviation / sqrt(sample size))

Here, hypothesized mean (µ) = 38, sample mean (X) = 35, standard deviation is not given, so we cannot calculate z-score directly.

But, we know that z-score is the number of standard deviations the sample mean is from the hypothesized mean.

Therefore, we can calculate the z-score indirectly using the formula

z-score = (X - µ) / (s / √n)

where s = sample standard deviation, n = sample size

We do not have the sample standard deviation, so we will assume it is equal to the population standard deviation or use a t-distribution if we have the sample size and degrees of freedom.

Assuming a standard normal distribution, the z-score can be calculated as

z-score = (35 - 38) / (σ / √(n))

where n = sample size

We do not have the value of σ, so we cannot calculate the z-score. However, we can still find the new p-value using the given p-value.

The p-value for the original test (Ha: µ < 38) is 0.0627.

For a one-tailed test, the p-value for the opposite direction (Ha: µ > 38) is:

p-value = 1 - 0.0627

p-value = 0.9373

Therefore, if the researcher had used Ha: µ > 38 instead of Ha: µ < 38, the new p-value would have been 0.9373. So, the correct answer is A).

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--The given question is incomplete, the complete question is given

" A researcher conducted a test of the hypotheses used H. <38 as the alternative hypothesis? 38 versus H. 38. The sample mean was 35 and the p value for the test was 0.0627 What would the pvalue have been if the researcher had A 1-0.0627 B) 1-2(0.0627) C 1-0) (0.0627) D) 2(0.0627) (E 0.0627)"--

The value of x in the equation 9x+7=15+6x is 2.66

When we have an equation, we can divide it into two parts, the left and right sides. In short, we call the equation LHS and RHS.

If we get both LHS and RHS as equal values, we can say that the equation is true; otherwise, the equation does not hold for at least some real-number values.

Given that,

9x+7=15+6x

Bring x terms to LHS and constants to RHS

9x-6x=15-7

we get,

3x= 8

taking 3 to RHS

in LHS we multiply with two so it becomes divided on RHS

so

x=8/3

x=2.66

Thus, the value of x in the equation 9x-6x=15-7 is 2.66

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