i havve a question. answer ASAP

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Answer 1
what’s the question???

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A Pump discharges water at 1MPaa and 165 deg C. Determine the specific volume and internal energy of the water at the discharge point.

Answers

This problem is describing a pump from which water is discharged at 1 MPa and 165 °C and is asking for the specific volume and internal energy at those conditions, thus, we can use the steam tables for resolving this requirement.

First of all, we need to remember that water can be a saturated liquid, vapour or liquid-vapour mixture, and this is determined for the temperature and pressure it is at.

In this case, we find that at 165 °C the saturation pressure is about 0.6178 MPa; this means we are referring to a saturated liquid so that both the specific volume and internal energy can be simply read from the steam tables as vf and uf as follows:

\(v=0.001127\frac{m^3}{kg}\\\\u=761.67 \frac{kJ}{kg}\)

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3A ball rolls off a 1.0 m high table with a speed of 4.0 m/s, as shown in the figure below. Calculate the speed as the ball strikes the floor:
4.0 ms¹
1.0 m

3A ball rolls off a 1.0 m high table with a speed of 4.0 m/s, as shown in the figure below. Calculate

Answers

Answer:

Vy = g T       where T is the time taken to fall

1 = 1/2 g T^2      time to fall 1 m

T = (2 / 9.8)^1/2 = .45 sec

Vy = 9.8 * .45 = 4.43 m/s

V = (Vx^2 + Vy^2)^1/2 = (16 + 19.6)^1/2 = 5.97 m/s

.

if 145kl of energy is added to water, what mass of water can be heated from 35C to 100C then vaporized at 100C

Answers

Answer:

m = 0.057 kg = 57 g

Explanation:

Energy Added to Water = Heat added to raise the temperature of water + Heat used to vaporize water

\(E = mC\Delta T + mH\\E = m(C\Delta T + H)\)

where,

E = Energy added to water = 145 KJ

m = mass of water = ?

C = specific heat capacity of water = 4.2 KJ/kg.°C

ΔT = change in temperature = 100°C - 35°C = 65°C

H = Latent heat of vaporization of water = 2260 KJ/kg

Therefore,

\(145\ KJ = m[(4.2\ KJ/kg.^oC)(65^oC)+2260\ KJ/kg]\\\\145\ KJ = m(2533\ KJ/kg)\\\\m = \frac{145\ KJ}{2533\ KJ/kg}\)

m = 0.057 kg = 57 g

The mass of water that can be heated is equal to 0.527 kilograms.

Given the following data:

Quantity of energy = 145 kJ = 145,000 Joules.Initial temperature = 35.0°CFinal temperature = 100.0°C

Scientific data:

Specific heat capacity of water = 4200 J/kg°CLatent heat of vaporization of water = 2260 KJ/kg

To calculate the mass of water that can be heated:

The quantity of energy and heat.

Note: The quantity of energy added to water is equal to the quantity of heat used to vaporize water and the quantity of heat that is added to raise the temperature of water.

Mathematically, this is given by this expression:

\(E=mc\theta + mH\\\\E= m(c\theta + H)\)

Making m the subject of formula, we have:

\(m=\frac{E}{c\theta + H}\)

Substituting the parameters into the formula, we have;

\(m=\frac{145000}{[42000\times (100-35)] + 2260}\\\\m=\frac{145000}{(4200\times 65) + 2260}\\\\m=\frac{145000}{273000 + 2260}\\\\m=\frac{145000}{275260}\)

Mass, m = 0.527 kilograms.

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What instrument is used to records EQ waves?

Answers

Answer:

I believe it's a Seismograph

Explanation:

seismographs are used to record EQ waves

/ Assignment 01 Science teachers think practical science is a good thing. a. Agree b. Disagree c. Uncertain​

Answers

It is reasonable to conclude that science teachers generally agree that practical science is beneficial. Therefore, option (A) is correct.

Practical science refers to hands-on activities, experiments, and applications of scientific concepts in real-world settings. Science teachers, who are experts in their field and experienced in teaching science, understand the importance of practical science in facilitating students' understanding, engagement, and application of scientific principles.

Practical science allows students to develop critical thinking, problem-solving, and inquiry skills, as well as promoting a deeper understanding of scientific concepts. It also fosters curiosity, creativity, and a passion for science, making it an effective and essential component of science education.

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An astronomy class is so excited by the discovery of planets around other stars that they decide to do a library exhibit on the subject so that everyone in the school can learn about it. In this exhibit they want to pay tribute to both the astronomers of today who have done the work AND some of the scientists of the past whose work was essential to making the discoveries possible (and directly related to the techniques involved). Which of the following scientists of the past should definitely be included in the exhibit?

a. George Herbigâ
b. Ejnar Hertzsprungâ
c. Ptolemyâ
d. Gerard Kuiperâ
e. Christian Dopplerâ

Answers

Answer: e. Christian Dopplerâ

Explanation:

Based on the information given, the scientist of the past that should definitely be included in the exhibit is Christian Dopplera.

He described how the frequency of sound waves and light is being affected by the relative speed of both the source and also the observer. This was referred to as the Doppler effect.

In this scenario, the Doppler effect can be used to show how the universe is expanding. Therefore, the correct option is E.

How does the lens from which you view the world shape your approach to research inquiry?
Why is it important as a scholar-practitioner engaged in research to acknowledge your worldview ?

LEARNING RESOURCES Required Readings

Babbie, E. (2017). Basics of social research (7th ed.). Boston, MA: Cengage Learning.
Chapter 1, “Human Inquiry and Science”


Burkholder, G. J., Cox, K. A., Crawford, L. M., & Hitchcock, J. H. (Eds.). (2020). Research designs and methods: An applied guide for the scholar-practitioner. Thousand Oaks, CA: Sage.
Chapter 1, "Introduction to Research"
Chapter 2, “Philosophical Foundations and the Role of Theory in Research”

Answers

Acknowledging one's worldview as a scholar-practitioner is crucial as it influences research inquiry. It shapes research questions, methods, and interpretations. Recognizing biases and being open to diverse perspectives ensures reliable and valid research.

As a scholar-practitioner engaged in research, it is important to acknowledge your worldview because your worldview affects the approach you take to research inquiry. It shapes your research questions, methods, and interpretations. The lens through which you view the world is informed by your background, culture, experiences, and beliefs. Therefore, two scholars may approach the same research question differently based on their worldviews. For instance, a scholar from an individualistic culture may approach a research question on teamwork differently from a scholar from a collectivistic culture. The individualistic scholar may focus on the individual's contribution to the team, while the collectivistic scholar may focus on the team's contribution to the individual.To conduct research that is reliable and valid, it is crucial for the scholar-practitioner to acknowledge their worldview and recognize that it shapes their approach to research inquiry. By acknowledging their worldview, the scholar-practitioner can identify and manage their biases and take steps to minimize them. They can also be open to multiple perspectives and incorporate them into their research to enhance its credibility. In conclusion, acknowledging your worldview as a scholar-practitioner is essential for conducting research that is reliable and valid. It helps you identify and manage your biases and be open to multiple perspectives.

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Mr. Daumer wants to create a magnet. He attaches a battery to a metal wire and
wants to wrap the wire around an object. Which object should he wrap the wire around?
a) A battery
b) A pencil
c) A ruler
d) A piece of steel metal.

Answers

A piece of steel metal

which experimental evidence indicates that. electron are negatively charged particles​

Answers

Answer:

Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

Answer:

thomsons experiment he used ray tubes that showed all electrons contain negatively cahrged particles

Please help I need finish by 10:57

Please help I need finish by 10:57

Answers

Answer:

to answer it just get the distance traveled (m) and divide it by the time it took

Explanation:

so for the first one just do 100 divided by 47 which would equal 2.12 m/s

In a certain region of space near earth's surface, a uniform horizontal magnetic field of magnitude B exists above a level defined to be y = 0. Below y = 0 , the field abruptly becomes zero (seethe figure). A vertical square wire loop has resistivity rho mass density rhom, diameter d, and side length l. It is initially at rest with its lower horizontal side at y = 0 and is then allowed to fall under gravity, with its plane perpendicular to the direction of the magnetic field.
a) While the loop is still partially immersed in the magnetic field (as it fallsinto the zero-field region), determine the magnetic "drag" forcethat acts on it at the moment when its speed is v.
b) Assume that the loop achieves a terminal velocity vt before its upper horizontal side exits the field. Determine a formulafor vt
c) If the loop is made of copper and B = 0.80 T find vt

Answers

Answer:

a) F = \(\frac{\pi d^2B^2lv}{16p}\)  

b) attached below

c) 0.037 m/s

Explanation:

a) Determine the magnetic "drag" force acting  at the moment

speed = v

first step: determine current in the loop

I = \(\frac{\pi d^2}{16pl} B lv\)   ----- ( 1 )

given that the current will induce force on the three sides of the loop found in the magnetic field

forces on vertical sides = + opposite

we will cancel out

hence equation 1 becomes

F = \(\frac{\pi d^2B^2lv}{16p}\)   ( according to Lenz law we can say that the direction of force is upwards and this force will slow down the decrease in flux )

b) Determine the formula for Vt

attached below

c) Find Vt

given :

B = 0.80 T

density of copper = 8.9 * 10^3 kg/m^3

resistivity of copper = 1.68 * 10^-8 Ωm

∴ Vt = 16 ( 8.9 * 10^3 kg/m^3 ) ( 1.68 * 10^-8 Ωm ) ( 9.8 m/s^2 ) / ( 0.08 T)^2

       = 0.037 m/s

In a certain region of space near earth's surface, a uniform horizontal magnetic field of magnitude B

explain why something falling reaches a top speed, draw free diagrams

Answers

when the sum of the drag force (Fd) and the buoyancy is equal to the downward force of gravity (FG) acting on the object.

c. is what percent of 125?​

Answers

Answer:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=125$.

Step 4: In the same vein, $x\%=125$.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$.

Explanation:

A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C. ​

Answers

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.

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The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths (the reddest colors) to the shortest wavelengths (the deepest violet colors) our eyes can detect. Wavelengths near 655 nm are perceived as red. Those near 515 nm are green and those near 475 nm are blue. Calculate the frequency of light (in Hz) with a wavelength of 655 nm, 515 nm, and 475 nm.

The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths

Answers

The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and  475 nm is\(6.31 x 10^14 Hz\)

The equation that links the speed of light to wavelength and frequency is

c = λν

Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.

Calculating the frequency of light with a wavelength of

655 nm:λ = 655 nm = \(6.55 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)

Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).

Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)

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Compare the freezing point of water in the aquanaut’s apartment to its value at the surface. Is it higher, lower, or the same?

Answers

Answer:

Freezing Point - Lower

Boiling Point - Higher

Solid- liquid transition line in the phase diagram has a negative slope, but the liquid-gas transition line has a positive slope. Since there is more air pressure at 100m it will take less to freeze the water but more to boil it since it requires a larger temperature under larger pressures

Which term is most applicable to a discussion of angular momentum in the context of black holes?
A. photon
B. curvature
C. spin
D. time

Answers

Answer:

Curvature

Explanation:

What are patients most likely to prepare as part of their right to make decisions about end of life care under federal legislation

Answers

Patients are most likely to prepare "advance directives" as part of their right to make decisions about end-of-life care under federal legislation.

Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.

Answers

The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?

Answers

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

a man walks 6 km north, then turns and walks 6 km east what is the resultant and angle

Answers

That would depend on the man’s starting latitude. If 6.7 mi south of the north pole, for example, the resultant would be 6.7 mi due north of the starting point.

g initial angular velocity of 39.1 rad/s. It starts to slow down uniformly and comes to rest, making 76.8 revolutions during the process. a) What is its angular acceleration (in rad/s2 )

Answers

Answer:

Approximately \(-1.58\; \rm rad \cdot s^{-2}\).

Explanation:

This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.

This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:

\(v^2 - u^2 = 2\, a\, x\),

where

\(v\) is the final velocity of the moving object, \(u\) is the initial velocity of the moving object,\(a\) is the (linear) acceleration of the moving object, and\(x\) is the (linear) displacement of the object while its velocity changed from \(u\) to \(v\).

The angular analogue of that equation will be:

\((\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta\), where

\(\omega(\text{final})\) and \(\omega(\text{initial})\) are the initial and final angular velocity of the rotating object,\(\alpha\) is the angular acceleration of the moving object, and\(\theta\) is the angular displacement of the object while its angular velocity changed from \(\omega(\text{initial})\) to \(\omega(\text{final})\).

For this object:

\(\omega(\text{final}) = 0\; \rm rad\cdot s^{-1}\), whereas\(\omega(\text{initial}) = 39.1\; \rm rad\cdot s^{-1}\).

The question is asking for an angular acceleration with the unit \(\rm rad \cdot s^{-1}\). However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:

\(\begin{aligned}\theta &= 76.8\; \rm \text{revolution} \\ &= 76.8\;\text{revolution} \times 2\pi\; \rm rad \cdot \text{revolution}^{-1} \\ &= 153.6\pi\; \rm rad\end{aligned}\).

Rearrange the equation \((\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta\) and solve for \(\alpha\):

\(\begin{aligned}\alpha &= \frac{(\omega(\text{final}))^2 - (\omega(\text{initial}))^2}{2\, \theta} \\ &= \frac{-\left(39.1\; \rm rad \cdot s^{-1}\right)^2}{2\times 153.6\pi\; \rm rad} \approx -1.58\; \rm rad \cdot s^{-1}\end{aligned}\).

Calculate the eccentricity for the planet if the distance between foci is 5,000,000 km and the distance of the major axis is 299,000,000 km.(1 point)
Responses

A 0.0167
B 0.598
C 59.8
D 0.167

Answers

The eccentricity of the planet with a distance between foci is 5,000,000 km and the distance of the major axis is 299,000,000 km is 0.0167 (option A).

What is eccentricity?

Eccentricity is the ratio, constant for any particular conic section, of the distance of a point from the focus to its distance from the directrix.

The eccentricity of an elliptical orbit is defined by the ratio:

e = c/a

where;

c is the distance from the center of the ellipse to either focuse = eccentricitya = positive for an elliptical orbit

According to this question, the distance between foci is 5,000,000 km and the distance of the major axis is 299,000,000 km. The eccentricity can be calculated as follows:

e = 5 × 10⁶km ÷ 299 × 10⁶km

e = 0.0167

Therefore, 0.0167 is the eccentricity of the planet.

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heeeeeeeeeeeeeeeeeeeeeeeelp

Answer and I will give you brainiliest ​

heeeeeeeeeeeeeeeeeeeeeeeelp Answer and I will give you brainiliest

Answers

Answer:

They are affected by weather changes

Answer:

I'm pretty sure it's D. ;)

During a tennis match, a player serves the ball at 26.6 m/s, with the center of the ball leaving the racquet horizontally 2.43 m above the
court surface. The net is 12.0 m away and 0.900 m high. When the ball reaches the net. (a) what is the distance between the center of
the ball and the top of the net? (b) Suppose that, instead, the ball is served as before but now it leaves the racquet at 5.00° below the
horizontal. When the ball reaches the net, what now is the distance between the center of the ball and the top of the net? Enter a
positive number if the ball clears the net. If the ball does not clear the net, your answer should be a negative number. Use g = 9.81 m/s?.

Answers

a). The distance between the center of the ball and the top of the net is 0.707 m

b). The distance between the center of the ball and the top of the net is 1.021 m, which is greater than the height of the net (0.9 m). Therefore, the ball clears the net.

How the answers were obtained

Let's first find out how long it takes for the ball to reach the net. We can use the formula:

time = distance / velocity

where the distance is the distance between the player and the net, and the velocity is the horizontal component of the ball's velocity, which remains constant throughout the flight.

So, the time taken by the ball to reach the net is:

time = 12.0 m / 26.6 m/s = 0.451 m/s

(a) The vertical distance between the center of the ball and the top of the net can be found using the formula:

distance = initial height + (initial vertical velocity x time) - (0.5 x acceleration x time^2)

where the initial height is 2.43 m, the initial vertical velocity is 0 m/s (since the ball is not moving up or down initially), the time is 0.451 s, and the acceleration is -9.81 m/s^2 (negative because it acts downwards).

So, the distance between the center of the ball and the top of the net is:

distance = 2.43 m + (0 m/s x 0.451 s) - (0.5 x 9.81 m/s^2 x (0.451 s)^2) = 0.707 m

Therefore, the distance between the center of the ball and the top of the net is 0.707 m.

(b) Now, let's consider the second case where the ball leaves the racquet at 5.00° below the horizontal. We can find the initial horizontal and vertical components of the velocity using trigonometry:

horizontal velocity = velocity x cos(5°) = 26.6 m/s x cos(5°) = 25.30 m/s

vertical velocity = velocity x sin(5°) = 26.6 m/s x sin(5°) = 2.32 m/s

The time taken by the ball to reach the net is still the same (0.451 s).

The initial height of the ball is still 2.43 m, but now the initial vertical velocity is 2.32 m/s (upwards).

Using the same formula as before, the distance between the center of the ball and the top of the net is:

distance = 2.43 m + (2.32 m/s x 0.451 s) - (0.5 x 9.81 m/s^2 x (0.451 s)^2)

= 1.021 m

Therefore, the distance between the center of the ball and the top of the net is 1.021 m, which is greater than the height of the net (0.9 m). Therefore, the ball clears the net.

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A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?

Answers

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

What is Speed ?

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

h = 52 mu = 0Range R = 35 mg = 9.8 m/s²

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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A heat-engine cycle is executed with steam in the saturation dome between the pressure limits of 7 MPa and 2 MPa. If heat is supplied to the heat engine at a rate of 150 kJ/s, the maximum power output of this heat engine is _____. Solve using appropriate software. Multiple Choice

Answers

Answer: 19.72kW

Explanation:

At P1 = 7 MPa, the saturated temperature T1 = 285.83°C. This will be converted to Kelvin

= 285.83 + 273

= 558.83K

At P2 = 2 MPa, the saturated temperature T1 = 212.38°C. This will be converted to Kelvin

= 212.38 + 273

= 485.38K

Then, the maximum possible efficiency which is the Carnot efficiency will be:

= 1 - T2/T1

= 1 - 485.38/558.83

= 1 - 0.8686

= 0.1314

Then, the the maximum power output of this heat engine will be:

= 0.1314 × 150 kJ/s

= 19.72kW

I'm stuck on b(i), because I don't understand what equation to use with what values.

I'm stuck on b(i), because I don't understand what equation to use with what values.
I'm stuck on b(i), because I don't understand what equation to use with what values.

Answers

Answer:

Apparently, it takes 3 * 5E-3 sec to travel from D to G

The distance is given as .68 m

V = S / t = .68 m / (3 * 5E-3 s) = 45 m/s

Share an experience you've had with the bureaucracy. In thinking about that experience, how would you describe the bureaucracy? What characteristics of the bureaucracy did you observe in that experience? Please explain. (Refer to Weber's theory of bureaucracy in the module.)

Answers

Bureaucracy theory explains the basis of the systematic formation of any organization and ensures efficiency and economic effectiveness.

Bureaucracy is the theory proposed by Max Weber. It forms the ideal model for the management and administration of the organization and ensures its efficiency of organization into focus.

It includes six basic principles. They are Authority Hierarchy, Division of labor, impersonality, Career Orientation, Formal rules and regulations, and Selection process.

The characteristics of bureaucracy include: It can control and regulate the behavior of people in an organization. It is the organization that has the power to make decisions. The organizations have certain rules to follow by the people.

Bureaucracy is found in large organizations like governments and corporations. It has standardized methods, and procedures to practice. It doesn't allow any flexibility for the organization.

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How many stars are in the universe (approximately)? O 40 sixtillion 0 365 billion O 86.4 million O one​

Answers

Answer:

a i belive

Explanation:

the univerce is VERY large so a, if im wrong i apologise :(

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