I FORGOT HOW TO DO THIS I NEED HELP ASAP!!!

Answer:

on her first quiz

Step-by-step explanation:

27/30=

27÷30=

0.9=

09×100/100=

0.9×100%=

(0.9×100)% =

90%

Answer:

first quiz

Step-by-step explanation:

100 divided by 30 times 27<92%

Answer:

The first one is 1/2.

The second blank is 1 1/6

The third blank is 3/2

The fourth blank is 5/3

The fifth blank is 2 2/3.

The sixth blank is 2 5/6.

The sprinkler should be set to rotate through  the angle 6.42 degrees.

What is an angle?

Two lines intersect at a location, creating an angle. An "angle" is the term used to describe the width of the "opening" between these two rays. Angles are used in the design of buildings, roadways, and sports venues by engineers and architects.

r =  50 yards

Area, A = 140 square yards

Θ = angle

A= (Θ /360) πr²

140 = (Θ /360) * 3.14 * 50*50

Θ = (140*360)/(3.14*25*100) = 6.42 degrees

The sprinkler should be set to rotate through  the angle 6.42 degrees.

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Answer:

1°

Step-by-step explanation:

Answer:

Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain:(−∞,∞),{x|x∈R}Range: (−∞,∞),{y|y∈R}

Step-by-step explanation:

Answer:

43.8

When you round look at the number after the one your rounding up to. If its greater than 5 round up. If its lower than 5 keep it the same number

Answer:

2/25

Step-by-step explanation:

8% = 8/100 = 2/25

To sketch the graph of the function `f(x) = - 5 sin 6 5 4 3 2 -&t -7n -65-4n -3n-2n - j -2 -3 -4 -5 -6 + - (a) 27 3 4 5 \ / 67 8`, we first need to identify its key features, which are:Amplitude = 5

Period = 2π/6

= π/3

Phase Shift = 2

The graph of the function `f(x) = - 5 sin 6x + 2` can be obtained by starting with the standard sine graph and making the following transformations:Reflecting it about the x-axis by multiplying the entire function by -1.

Multiplying the entire function by 5 to increase the amplitude.

Shifting the graph to the right by 2 units.For the specific domain provided in the question, we have:27 < 6x + 2 < 67 or 25/6 < x < 65/6.

This gives us a range of approximately 4.17 ≤ x ≤ 10.83.

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Answer:

\(\boxed {x = 6}\)

Step-by-step explanation:

Solve for the value of \(x\):

\(0.4x + 0.4 = 0.6x - 0.8\)

-Take \(0.6x\) and subtract it from \(0.4x\):

\(0.4x + 0.4 - 0.6x = 0.6x - 0.6x - 0.8\)

\(-0.2x + 0.4 = - 0.8\)

-Subtract \(0.4\) to both sides:

\(-0.2x + 0.4 - 0.4 = - 0.8 - 0.4\)

\(-0.2x = -1.2\)

-Divide both sides by \(-0.2\):

\(\frac{-0.2x}{-0.2} = \frac{-1.2}{-0.2}\)

-Expand by multiplying the numerator and the denominator by \(10\):

\(x = \frac{-12}{-2}\)

\(\boxed {x = 6}\)

So, the value of \(x\) is \(6\).

The double integral ∫∫x(\(sec^2\))(y) dA over the region R = {(x, y) | 0 ≤ x ≤ 6, 0 ≤ y ≤ π/4} is equal to 3π/8.

To evaluate the given double integral ∫∫x(sec^2)(y) dA over the region R = {(x, y) | 0 ≤ x ≤ 6, 0 ≤ y ≤ π/4}, we follow the process of integrating with respect to one variable at a time.

First, we integrate with respect to x. Since the bounds of x are from 0 to 6, the integral becomes:

∫[0, π/4] ∫[0, 6] x(sec^2)(y) dx dy

Integrating x with respect to x, we get:

(1/2)x^2(sec^2)(y) |[0, 6]

Plugging in the limits of integration, we have:

(1/2)(6^2)(sec^2)(y) |[0, π/4]

Simplifying, we get:

(1/2)(36)(sec^2)(y) |[0, π/4]

= 18(sec^2)(y) |[0, π/4]

Next, we integrate the remaining expression with respect to y. The integral of sec^2(y) is tan(y), so we have:

18(tan(y)) |[0, π/4]

Evaluating the limits of integration, we get:

18(tan(π/4) - tan(0))

= 18(1 - 0)

= 18

Therefore, the double integral ∫∫x(sec^2)(y) dA over the given region R is equal to 18.

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From this proportion of days he does the activities, sometimes they will meet in one day.

He will do both in the same day when the day is a common factor of 3 and 4.

Since today he did both, the next time he will do so will be in the least common factor of 3 and 4.

To get the least common factor of these, we can identify the divisors of each and makes the divisions until both get to 1. If one of the divisiors is divisior for both, we don't repeat it.

So, from 3 and 4, we can start by the divisior of 2. 2 Is a divisior of 4, but not of 3, so we divide only the number for:

3, 4 | 2

3, 2 |

Now, we have 3 and 2, so we can divide for 2 again:

3, 4 | 2

3, 2 | 2

3, 1 |

Now, we have 3 and 1, so we can only divide by 3 now:

3, 4 | 2

3, 2 | 2

3, 1 | 3

1 , 1 |

So, in the end we have 2, 2 and 3, so the least common factor is 2*2*3 = 12.

Since the common factor of 3 and 4 is 12, Tyler will lift and jog on the same day 12 days after today.

Answer:

11.4

Step-by-step explanation:

Divid the numerator (57) by the denominator (5) and you'll get 11.4

Answer:

11.4

Step-by-step explanation:

To turn a fraction into a decimal, divide the numerator (top number) by the denominator(bottom number).

57 divided by 5 is 11.4

Answer:

6ft/hour

Step-by-step explanation:

Answer:

6 feet/hour

Step-by-step explanation:

I first found out exactly the amount of feet that was added. \(80-32=48\)

Then I divided that by the amount of hours.  48 ÷ 8 = 6

The five number summary for the test scores and other measures are:

To find the mean test score, sum up all the test scores and divide by the total number of students:

mean = (42 + 68 + 70 + 72 + 74 + 75 + 79 + 80 + 82 + 83 + 84 + 85 + 86 + 87 + 91 + 92 + 94 + 95 + 97 + 98) / 20

mean = 1628 / 20

mean = 81.4

To find the median test score, find the middle value(s) of the ordered scores.

median = (83 + 84) / 2

median = 167 / 2

median = 83.5

The mode is the score that appears most frequently. In this case, there is no mode, as all scores appear only once.

To calculate the Mean Absolute Deviation (MAD), find the mean of the absolute differences between each score and the mean score:

MAD = (|42-81.4| + |68-81.4| + ... + |98-81.4|) / 20

MAD = 246.6 / 20

MAD = 12.33

To calculate the range, subtract the smallest score from the largest score:

range = 98 - 42

range = 56

To find Q1 (the first quartile), find the median of the lower half of the data.

Q1 = median of (42, 68, 70, 72, 74, 75, 79, 80, 82, 83)

Q1 = (74 + 75) / 2

Q1 = 74.5

To find Q3 (the third quartile), find the median of the upper half of the data.

Q3 = median of (84, 85, 86, 87, 91, 92, 94, 95, 97, 98)

Q3 = (91 + 92) / 2

Q3 = 91.5

To calculate the Interquartile Range (IQR), subtract Q1 from Q3:

IQR = Q3 - Q1

IQR = 91.5 - 74.5

IQR = 17

The only score outside the lower bound (below 49) is 42. There are no scores above the upper bound (117). So, the only outlier in the data set is the score of 42.

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The forecast for May using a five-month moving average is 39 (Option E).

Moving average is used for smoothing out time series data to find any trends or cycles within the data. A five-month moving average is the average of the past five months. To calculate the moving average, add up the sales for the previous five months and divide it by five.

According to the question, the sales for the previous five months are: Nov. 39 Dec. 27 Jan. 40 Feb. 42 Mar. 41 April 47

We have to add the sales of these five months, which gives:

27 + 40 + 42 + 41 + 47 = 197

To find the moving average for May, we divide this sum by 5:

197 / 5 = 39.4

Since we have to round the answer to the nearest whole number, we round 39.4 to 39, which is option E.

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To find a vector in the same direction as u but with 6 times the length of u, we can multiply the vector u by a scalar factor of 6. A vector in the same direction as u but with 6 times the length of u is -18i - 54j + 30k.

The vector u is given as u = -3i - 9j + 5k.

To find a vector with 6 times the length of u, we multiply each component of u by 6:

6u = 6(-3i) + 6(-9j) + 6(5k) = -18i - 54j + 30k.

The vector u is represented by its components along the x, y, and z axes, which are -3, -9, and 5, respectively. To find a vector with 6 times the length of u, we multiply each component by 6, resulting in -18i, -54j, and 30k. This new vector has the same direction as u but is 6 times longer. Multiplying a vector by a scalar factor only changes its length, not its direction. Therefore, the vector -18i - 54j + 30k is in the same direction as u but has 6 times the length.

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well if you look at it it comes at a slope

Answer:

The answer is 15.

Step-by-step explanation:

When dividing 225 by 15 you can multiply 15 by 15 and you will get 225.

The count of the class will be a discrete random variable.

Discrete random variable in which we can count the value of the variable for example students in class.

A discrete random variable can be added directly no integration is needed but in a continuous random variable, we need integration.

For example, x is -2 to 4 is a continuous random variable.

Given that,

A teacher records the number of students present in her 1st-period class each day.

Since a number of students are a countable thing so it will come under the discrete random variable.

For example, if the number of students is 46 then the random variable will be 46 on that day.

Hence " The count of the class will be a discrete random variable".

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Answer:

It will be D 2.5

Step-by-step explanation:

Hope this Helped

Answer:

The scale factor is 2.5

Step-by-step explanation:

took test on k-12

a) The set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.

To find the set of values of k for which the line and curve meet at two distinct points, we need to solve the equation:

x^2 - kx + 2 = 3kx - 2k

Rearranging, we get:

x^2 - (3k + k)x + 2k + 2 = 0

For the line and curve to meet at two distinct points, this equation must have two distinct real roots. This means that the discriminant of the quadratic equation must be greater than zero:

(3k + k)^2 - 4(2k + 2) > 0

Simplifying, we get:

5k^2 - 8k - 8 > 0

Using the quadratic formula, we can find the roots of this inequality:

\(k < (-(-8) - \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = -2/5\\ or\\ k > (-(-8)) + \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = 2\)

Therefore, the set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.

b) To find the two values of k for which the line is a tangent to the curve, we need to find the values of k for which the line is parallel to the tangent to the curve at the point of intersection. For m to be the slope of the tangent at the point of intersection, we need to have:

2x - 4 = m

3k = m

Substituting the first equation into the second, we get:

3k = 2x - 4

Solving for x, we get:

x = (3/2)k + (2/3)

Substituting this value of x into the equation of the curve, we get:

y = ((3/2)k + (2/3))^2 - k((3/2)k + (2/3)) + 2

Simplifying, we get:

y = (9/4)k^2 + (8/9) - (5/3)k

For this equation to have a double root, the discriminant must be zero:

(-5/3)^2 - 4(9/4)(8/9) = 0

Simplifying, we get:

25/9 - 8/3 = 0

Therefore, the constant term is 8/3. Solving for k, we get:

(9/4)k^2 - (5/3)k + 8/3 = 0

Using the quadratic formula, we get:

\(k = (-(-5/3) ± \sqrt{((-5/3)^2 - 4(9/4)(8/3)))} / (2(9/4)) = -1/3 \\or \\k= 4/3\)

Therefore, the two values of k for which the line is a tangent to the curve are k = -1/3 and k = 4/3. To show that the two tangents meet on the x-axis, we can find the x-coordinate of the point of intersection:

For k = -1/3, the x-coordinate is x = (3/2)(-1/3) + (2/3) = 1

For k = 4/3, the x-coordinate is x = (3/2)(4/3) + (2/3) = 3

Therefore, the two tangents meet on the x-axis at x = 2.

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Answer:

180*0.1=18

Step-by-step explanation:

Answer:

22 and 14

Step-by-step explanation:

22 divided by 2 is 11

11 plus 3 is 14

22 minus 14 is 8

Answer:

16 boys

Step-by-step explanation:

Lets go with easy example:

20% of 100 students means 20 students: what is done there

\(\frac{20}{100}*100=20\)

Lets do the same with 80 students as well

\(\frac{20}{100}*80=16\)

Answer:

16

Step-by-step explanation:

\(\frac{20}{100} x \frac{x}{80} =16\)

or do

80 x 0.20=16

both works

80%

No

The mean of a data set is the average value.

How to Find Mean

The mean of a data set is the sum of all the values divided by the number of terms. For example, take the set {1, 3, 4, 7, 9, 12}. First, add all the values together: 1+3+4+7+9+12 = 36. Then divide by the number of terms, 6: 36/6 = 6. The mean is 6.

Minimum Score

To find the minimum score needed, we need to work backward from the mean. We want a mean of 80, and we have 5 terms. So, multiply 80 * 5 to find the sum of the scores.

This means when all 5 scores are added together, they must equal 400. Now, we can subtract the scores of the 4 known classes. This will give us the score for math.

This means that Mike needs an 85% in math to reach a mean of 80. Any lower and the mean will be less than 80%.

Mean of 85%

The last question asks if a mean of 85% is possible. To answer this we can solve the same way above but with a desired mean of 85%. Start by multiplying by the number of terms.

Then, subtract the known values.

Assuming there is no extra credit, a score of 110 is not possible. So, Mike cannot reach a mean of 85%.

In this triangle, the product of tan A and tan C is `(BC)^2/(AB)^2`.

The given triangle ABC has angle A measuring 45 degrees, angle B measuring 90 degrees, and angle C measuring 45 degrees , Answer: `(BC)^2/(AB)^2`.

We have to find the product of tan A and tan C.

In triangle ABC, tan A and tan C are equal as the opposite and adjacent sides of angles A and C are the same.

So, we have, tan A = tan C

Therefore, the product of tan A and tan C will be equal to (tan A)^2 or (tan C)^2.

Using the formula of tan: tan A = opposite/adjacent=BC/A Band, tan C = opposite/adjacent=AB/BC.

Thus, tan A = BC/AB tan C = AB/BC Taking the ratio of these two equations, we have: tan A/tan C = BC/AB ÷ AB/BC Tan A * tan C = BC^2/AB^2So, the product of tan A and tan C is equal to `(BC)^2/(AB)^2`.

Answer: `(BC)^2/(AB)^2`.

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Answer: 187.96 cm

Step-by-step explanation: First you need to convert all of the units into centimeters. To do this you need to convert the 6 feet into inches. Since there are 12 inches in a foot, 6 feet is equal to 72 inches. Next add the 2 inches to 72, and now this means Tyson is 74 inches tall. Lastly convert the inches into centimeters by multiplying 74 by 2.54, which equals 187.96.

Answer:

187.96cm

Step-by-step explanation:

Step 1: Convert 6 feet 2 inches to centimeters.

We have 1 inch = 2.54 cm and 1 foot = 12 inches and 1 feet = 30.48 cm

=> 6 feet 2 inches is about 187.96cm

Answer:

125x=1000

=8 bags of sand

Step-by-step explanation:

Alan has to sell 540 boxes to earn less than $2050

A linear model is an equation that describes a relationship between two quantities that show a constant rate of change.

Given is graph that represent the relation between the total sales and number of boxes sold,

The linear model for same is given by =

f(b) = 3.75b + 25

We need to find, how many boxes would Alan have to sell to earn less than $2050,

Here, we have, f(b) = $2050

Therefore,

$2050 = 3.75b + 25

3.75b = 2025

b = 540

Hence, Alan has to sell 540 boxes to earn less than $2050,

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Each box has a mass of 90 grams, which is found by setting up a proportion using the ratio of cans to boxes and the known mass of each can.

To solve this problem, we need to use proportions. We know that 3 cans have the same mass as 9 identical boxes, which means that the ratio of cans to boxes is 3:9 or simplified to 1:3.

We also know that each can has a mass of 30 grams. Therefore, we can set up the proportion:

1 can / 30 grams = 1 box / x grams

where x is the mass, in grams, of each box.

To solve for x, we can cross-multiply:

1 can * x grams = 30 grams * 1 box

x grams = 30 grams / 1 can * 1 box

Since the ratio of cans to boxes is 1:3, we can substitute 3 for the number of boxes:

x grams = 30 grams / 1 can * 3 boxes

x grams = 90 grams

Therefore, the mass of each box is 90 grams.

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