I dont really understand this question

Answer:

11 ft

Step-by-step explanation: A square has side lengths that are equal in length. Given that a side length of a square is x, the area would be x^2 because x*x = x^2. Now we have to reverse for the problem. If the area is 121 then what is x. 121=x^2. So we have to square root 121, resulting in 11. So each side of the garden is 11 feet each.

Answer: 7,320.5

Step-by-step explanation:

121 squared

= 1212

= 121 x 121

= 14,641  (Area)1/2=s, where s = side.

So 14,641÷2= 7,320.5

Answer:

Step-by-step explanation:

Not true: Right angle is not 90 degrees  because all right angles must be 90 degrees

Answer:

cups

0.14 and 0.098

plates

0.1375 and 0.144

silverware

0.047 and 0.129

Total:

30.25

Step-by-step explanation:

5.60/40 and 4.90/50

40 count and 50 count

cups

0.14 and 0.098

2.75/20 and 3.60/25

plates

0.1375 and 0.144

9.85/210 and 12.90/100

silverware

0.047 and 0.129

Total:

(5.60+4.90)*(0.85)+(2.75+3.60)*(0.85)+(9.85+12.90)*(0.70)

=30.2475

round

30.25

Answer:

The answer to your question is 30.25

Step-by-step explanation:

Hope I helped! Sorry if not. Have a wonderful day and an even better Christmas break! Happy Holidays! Remember to focus on the positive and follow me please! Thanks, Bye! ;D

Answer:

y = x² - 6x + 9

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (3, 0 ) , then

y = a(x - 3)² + 0

To find a substitute (1, 4) into the equation

4 = a(1 - 3)² = a(- 2)² = 4a ( divide both sides by 4 )

1 = a

y = (x - 3)² = x² - 6x + 9

Answer:

B) 131°

Step-by-step explanation:

-4a + 139 = 4a + 123 because they are vertical angles

-4a + 139 = 4a + 123

reduce:

8a = 16

a = 2

4(2) + 123 = 131°

The measure of the missing length "u" is 45 miles.

To find the measure of the missing length "u" in the similar shapes, we can set up a proportion based on the corresponding sides of the shapes. Let's denote the given lengths as follows:

20 mi corresponds to 25 mi,

36 mi corresponds to u.

The proportion can be set up as:

20 mi / 25 mi = 36 mi / u

To find the value of "u," we can cross-multiply and solve for "u":

20 mi * u = 25 mi * 36 mi

u = (25 mi * 36 mi) / 20 mi

Simplifying:

u = (25 * 36) / 20 mi

u = 900 / 20 mi

u = 45 mi

Therefore, the measure of the missing length "u" is 45 miles.

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Answer:

Step-by-step explanation:

x‒axis: minutes in increments of 5; y-axis: temperature in increments of 1

In the graph the x axis is used to represent the independent variable and y axis is used to represent the dependent variable.

Data should be represented as,

Axis line of the graph is the reference line which is used to represents the variables, and measure the coordinate on the graph and grid.

In the graph the x axis is used to represent the independent variable and y axis is used to represent the dependent variable.

Given information-

The table given in the problem between the minutes and temperature is,

Minutes         Temperature (°C)

5                         −20

10                           5

15                          10

20                          6

25                        25

30                         21

35                         14

40                        −6

From the given table it can be seen that the minute is increasing as 5 minutes with each value.

With increasing 5 minutes the value of temperature is changing.

As the value of temperature is changing with change in the time. Thus the temperature is dependent variable here, and minute is independent variable.

As in the graph the x axis is used to represent the independent variable and y axis is used to represent the dependent variable.

Thus x-axis represent the minute and y-axis represent the temperature.

As the minute is increasing as 5 minutes, so the increment on the x axis is with 5 units. The value of temperature is also increasing with some amount thus the increments of 1 in y-axis also occurred.

Thus,

The data should be represented as,

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Answer: why is it wrong

Step-by-step explanation:i said so

 The random sample proportion.

Probability distribution is a statistical function that describes all the possible values and likelihoods that a random variable can take within a given range.

at 90% confidence interval: The Central 90% of any normal   distribution is: Z_(α/2) = 1.960

 Error = E = ±5% = ±0.05

Applying the normal  Probability distribution

= 0.70 ≤ P≤  0.77(this means that we are 90% confident that the true proportion of jet with wiring problem fall with 0.70 and 0.77, hence there is no need for the airline to conduct further sampling, rather, they should just inspect all the planes)

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Answer: the gcf is 2

Step-by-step explanation:

There boom your anwser

Answer:

k\

Step-by-step explanation:

j

(i) gcd(a,bc) = 1, since a has no factors in common with bc. Hence proved. (ii) gcd(a,b^2) = 1, since a has no factors in common with b^2. Hence proved. (iii) GCD(a2, b2) = 1, since (a+b)(a-b) and b2 share no common factors other than 1. Hence proved.

(i) Given that gcd(a,b)=1 and gcd(a,c)=1.

Theorem 1.4 states that if x, y, and z are integers such that x | yz and gcd(x, y) = 1, then x | z.

So, we have gcd(a,b) = 1, which means a and b have no common factors other than 1.

Similarly, gcd(a,c) = 1, which means a and c have no common factors other than 1.

Therefore, a has no factors in common with b or c.

Thus gcd(a,bc) = 1, since a has no factors in common with bc.

Hence proved.

(ii) Given that gcd(a,b)=1.

So, a and b have no common factors other than 1.

Therefore, a has no factors in common with b^2.

Thus gcd(a,b^2) = 1, since a has no factors in common with b^2.

Hence proved.

(iii) Given that gcd(a,b)=1.

Using Euclid's algorithm to calculate the GCD of two integers a and b:

GCD(a, b) = GCD(a, a-b)

Therefore, GCD(a2, b2) = GCD(a2 - b2, b2) = GCD((a+b)(a-b), b2)

Now, (a+b) and (a-b) are both even or odd.

Hence (a+b) and (a-b) have a factor of 2.

Therefore, (a+b)(a-b) has at least two factors of 2.

However, b2 is odd since gcd(a,b)=1 and b has no factors of 2.

Therefore, (a+b)(a-b) and b2 share no common factors other than 1.

Therefore, GCD(a2, b2) = 1, since (a+b)(a-b) and b2 share no common factors other than 1.

Hence proved.

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Answer: m∠6 = 115 , m∠7 = 65

Step-by-step explanation: Its pretty straight forward ig :) Hope this helps

Answer:

Step-by-step explanation:

m∠4 = m∠2 = 115° (vertically opposite angles)

m∠2 = m∠6 = 115° (corresponding angles)

m∠6 + m∠7 = 180° (linear pair)

115 + m∠7 = 180°

m∠7 = 180 - 115°

m∠7 = 65°

So, m∠6 = 115° and m∠7 = 65°

Hope you understood!!

In order to calculate the z-scores for the given Confidence Interval (CI) levels, we need to use the Z-table. It is also known as the standard normal distribution table. Here are the z-scores for the given Confidence Interval levels:1. 68% CI: The confidence interval corresponds to 1 standard deviation on each side of the mean.

Thus, the z-score for the 68% \(CI is ±1.00.2. 85% CI\): The confidence interval corresponds to 1.44 standard deviations on each side of the mean.

We can calculate the z-score using the following formula:\(z = invNorm((1 + 0.85)/2)z = invNorm(0.925)z ≈ ±1.44\)Note that invNorm is the inverse normal cumulative distribution function (CDF) which tells us the z-score given a certain area under the curve.3. 99% CI: The confidence interval corresponds to 2.58 standard deviations on each side of the mean. We can calculate the z-score using the following formula:\(z = invNorm((1 + 0.99)/2)z = invNorm(0.995)z ≈ ±2.58\)

Note that in general, to calculate the z-score for a CI level of (100 - α)% where α is the level of significance, we can use the following formula:\(z = invNorm((1 + α/100)/2)\) Hope this helps!

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Answer:

D) 2 1/2

Step-by-step explanation:

Answer:

D) 2 1/2

Step-by-step explanation:

Hope this helps! I for sure this is the answer haha

To find the probability of selecting a blue ball first and a yellow ball second (with replacement) from a box containing 3 red balls, 5 yellow balls, and 2 blue balls.

The probability of selecting a blue ball on the first draw is 2/10, as there are 2 blue balls out of a total of 10 balls in the box.

Since we are replacing the ball after each draw, the probability of selecting a yellow ball on the second draw is also 5/10, as there are still 5 yellow balls remaining in the box.

To find the probability of both events occurring, we multiply the probabilities together:

Probability of selecting a blue ball first = 2/10

Probability of selecting a yellow ball second = 5/10

Probability of both events occurring = (2/10) * (5/10) = 1/10

Therefore, the probability of selecting a blue ball first and a yellow ball second (with replacement) from the given box is 1/10.

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The value of the double integral ∬R (6x/(1 + xy)) dA over the region

R = [0, 6] × [0, 1] is 6 ln(7).

To calculate the double integral ∬R (6x/(1 + xy)) dA over the region

R = [0, 6] × [0, 1], we can integrate with respect to x and y using the limits of the region.

The integral can be written as:

∬R (6x/(1 + xy)) dA = \(\int\limits^1_0\int\limits^6_0\) (6x/(1 + xy)) dx dy

Let's start by integrating with respect to x:

\(\int\limits^6_0\)(6x/(1 + xy)) dx

To evaluate this integral, we can use a substitution.

Let u = 1 + xy,

     du/dx = y.

When x = 0,

u = 1 + 0y = 1.

When x = 6,

u = 1 + 6y

  = 1 + 6

   = 7.

Using this substitution, the integral becomes:

\(\int\limits^7_1\) (6x/(1 + xy)) dx = \(\int\limits^7_1\)(6/u) du

Integrating, we have:

= 6 ln|7| - 6 ln|1|

= 6 ln(7)

Now, we can integrate with respect to y:

= \(\int\limits^1_0\) (6 ln(7)) dy

= 6 ln(7) - 0

= 6 ln(7)

Therefore, the value of the double integral ∬R (6x/(1 + xy)) dA over the region R = [0, 6] × [0, 1] is 6 ln(7).

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The value of the double integral   \(\int\limits^1_0\int\limits^6_0 \frac{6x}{(1 + xy)} dA\), over the given region [0, 6] x [0, 1] is (343/3)ln(7).

Now, for the double integral  \(\int\limits^1_0\int\limits^6_0 \frac{6x}{(1 + xy)} dA\), use the standard method of integration.

First, find the antiderivative of the function 6x/(1 + xy) with respect to x.

By integrating with respect to x, we get:

∫(6x/(1 + xy)) dx = 3ln(1 + xy) + C₁

where C₁ is the constant of integration.

Now, we apply the definite integral over x, considering the limits of integration [0, 6]:

\(\int\limits^6_0 (3 ln (1 + xy) + C_{1} ) dx\)

To proceed further, substitute the limits of integration into the equation:

[3ln(1 + 6y) + C₁] - [3ln(1 + 0y) + C₁]

Since ln(1 + 0y) is equal to ln(1), which is 0, simplify the expression to:

3ln(1 + 6y) + C₁

Now, integrate this expression with respect to y, considering the limits of integration [0, 1]:

\(\int\limits^1_0 (3 ln (1 + 6y) + C_{1} ) dy\)

To integrate the function, we use the property of logarithms:

\(\int\limits^1_0 ( ln (1 + 6y))^3 + C_{1} ) dy\)

Applying the power rule of integration, this becomes:

[(1/3)(1 + 6y)³ln(1 + 6y) + C₂] evaluated from 0 to 1,

where C₂ is the constant of integration.

Now, we substitute the limits of integration into the equation:

(1/3)(1 + 6(1))³ln(1 + 6(1)) + C₂ - (1/3)(1 + 6(0))³ln(1 + 6(0)) - C₂

Simplifying further:

(343/3)ln(7) + C₂ - C₂

(343/3)ln(7)

So, the value of the double integral  \(\int\limits^1_0\int\limits^6_0 \frac{6x}{(1 + xy)} dA\), over the given region [0, 6] x [0, 1] is (343/3)ln(7).

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The maximum value of f(x, y)=x2-x-y on the region where 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1 is 1.

To find the maximum value, we can set up a system of inequalities and solve it:

0 ≤ x ≤ 1
0 ≤ y ≤ 1
f(x, y)=x2-x-y

Since both x and y are greater than or equal to 0, their product will also be greater than or equal to 0. Therefore, the maximum value of the equation is when x = 1 and y = 0, since it maximizes the positive value of x2 while minimizing the negative value of -x-y. This means that the maximum value of f(x, y) is 1.

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The maximum value of f(x,y)=x^{2}-x-yf(x,y)=x 2 −x−y on the region where \{(x, y): 0 \leq x \leq 1,0 \leq y \leq 1\} is 0.

To find the maximum value, we need to find the critical points of the function and test them within the given region. The critical points are where the partial derivatives of the function are equal to 0.

The partial derivative with respect to x is:
f_x(x,y)=2x-1

The partial derivative with respect to y is:
f_y(x,y)=-1

Setting these partial derivatives equal to 0, we get:
2x-1=0 --> x=1/2
-1=0 --> no solution for y

So the only critical point within the given region is (1/2, y) for any value of y. However, since the partial derivative with respect to y is always -1, the function is decreasing with respect to y. Therefore, the maximum value will occur when y is at its smallest value, which is 0.

Plugging in x=1/2 and y=0 into the original function, we get:
f(1/2,0)=(1/2)^{2}-(1/2)-0=0

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Answer:

15,600

Step-by-step explanation:

Answer:

15,600

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

The nth term of a geometric progression is

\(a_{n}\) = a₁\(r^{n-1}\)

where a₁  is the first term and r the common ratio

Given a₅ = 162 and a₈ = 4374 , then

a₁\(r^{4}\) = 162 → (1)

a₁\(r^{7}\) = 4374 → (2)

Divide (2) by (1)

\(\frac{a_{1}r^{7} }{a_{1}r^{4} }\) = \(\frac{4374}{162}\)

r³ = 27

r = \(\sqrt[3]{27}\) = 3

Substitute r = 3 into (1) and solve for a₁

a₁\((3)^{4}\) = 162

81a₁ = 162

a₁ = \(\frac{162}{81}\) = 2

Then

a₂ = a₁ × 3 = 2 × 3 = 6

a₃ = a₂ × 3 = 6 × 3 = 18

The first 3 terms are 2, 6, 18

(ii)

The sum to n terms of a geometric progression is

\(S_{n}\) = \(\frac{a_{1}(r^{n}-1) }{r-1}\) , then

\(S_{10}\) = \(\frac{2(3^{10}-1) }{3-1}\)

     = \(\frac{2(59049-1)}{2}\)

     = 59049 - 1

     = 59048

The present value of $100 per year forever (where the first payment is one year from now) at a discount rate of 1% is $10,000.The present value of a perpetuity is the amount of money that would be needed today to produce a stream of equal payments in the future.

The formula for the present value of a perpetuity is:

PV = PMT / r

Where:

PV is the present value

PMT is the periodic payment

r is the discount rate

In this case, the periodic payment is $100 and the discount rate is 1%. Substituting these values into the formula, we get:

PV = $100 / 0.01 = $10,000

This means that $10,000 invested today at a 1% discount rate would produce a stream of $100 payments per year forever.

The present value of a perpetuity is the amount of money that would be needed today to produce a stream of equal payments in the future. The present value of a perpetuity is always equal to the periodic payment divided by the discount rate. In this case, the periodic payment is $100 and the discount rate is 1%. Therefore, the present value of the perpetuity is $10,000.

The present value of perpetuity can be used to calculate the value of an asset that produces a stream of equal payments in the future. For example, a bond that pays $100 per year forever has a present value of $10,000 if the discount rate is 1%.

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Answer:

in a complete turn the wheel will travel the

expressed 2pi x radius or 2 x 3.14 x 28 or 175.84

circumference of the wheel. The circumference is cm x 3 (turns) = 527.52 cm or 572.52cm x 1in/2.54 cm x 1ft/12in or 18.78 ft or if you prefer meters 572.52 cm x 1m/100cm = 5.73 m

you will have 8 hours in each part.

24/3 = 8

0am to 8 am

8am to 4pm

4pm to 0am

Answer:

If we'll divide 3 to get equally in to a day.

We'll get 8hr. in each time

\( \frac{24 \: hr}{3} = 8 \: h\)

We can imagine this as

1am - 9am

9am - 5pm

5pm - 1am

Or as u want !!

The operations on the functions gives:

(f + g) (-2) = 12, f - g)(-3) = 44, (f . g)(1) = -7 and (f /g) (-2) = -19/7

A function is an expression that shows the relationship between the independent variable and the dependent variable.  A function is usually denoted by letters such as f, g, etc.

f(x) = 3x²-x+5; g(x) =2x-3

(f + g) (-2) = [3(-2)²-(-2)+5] + [2(-2)-3]         (addition)

(f + g) (-2) = [19] + [-7] = 12

(f - g)(-3) = [3(-3)²-(-3)+5] - [2(-3)-3]           (subtraction)

(f - g)(-3) = [35] - [-9] = 44

(f . g)(1) = [3(1)²-1+5] * [2(1)-3]                    (multiplication)

(f . g)(1) = [7] * [-1] = -7

(f /g) (-2) = [3(-2)²-(-2)+5] / [2(-2)-3]          (division)

(f /g) (-2) = [19] / [-7] = -19/7

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