I am taking a trip to San Antonio. It takes me 7 hours to travel a distance of 650 miles. What was my speed that I was traveling at?

Answer: A.0,0097s

Mas a unidade aí deveria ser Hertz (Hz)

Explanation:

Answer:

103 hz

Explanation:

The accuracy of measurements of the speed of sound in a laboratory experiment can depend on various factors. To ensure accuracy, it is important to use precise equipment and techniques. One method commonly used is the resonance method, where a tube with a known length is filled with a gas and a tuning fork is used to produce a sound. The length of the tube is adjusted until resonance occurs, and the speed of sound is calculated using the known length and the frequency of the tuning fork.

To improve accuracy, multiple measurements should be taken and an average should be calculated. This helps to minimize errors and provides a more reliable value. Additionally, the accuracy can be influenced by external factors such as temperature, humidity, and pressure. These should be controlled and monitored to reduce any potential errors.

It is important to note that the accuracy of the measurements can also be affected by the precision and calibration of the instruments used. Regular maintenance and calibration of equipment can help ensure accurate measurements. Overall, by following proper techniques, using precise equipment, and controlling external factors, the accuracy of measurements of the speed of sound can be maximized in a laboratory experiment.

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A

Explanation:

When a liquid occupies a smaller volume, it exerts a higher pressure; when it occupies a larger volume, it exerts a lower pressure.

volume= mass÷density

A- 10÷2= 5cm³

B- 20÷1.6= 12.5cm³

C- 30÷1.2= 25cm³

D- 40÷0.7= 57.1cm³

Answer:

I think the answer 1

Explanation:

im probably wrong too i dont know

The aggregate bulk dry specific gravity, the aggregate apparent specific gravity, the moisture content of stockpile aggregate and absorption are respectively,

A. 2.7

B. 2.72

C. 1.6%

D. 0.21%

A) The formula for the aggregate bulk dry specific gravity is:

Aggregate bulk dry specific gravity = Mass of oven dried aggregate /( Mass of saturated surface dry aggregates - Submerged mass of aggregate)

Placing the values from the data we have,

Aggregate bulk dry specific gravity = 5216/ (5227 - 3295) = 2.7

B) Formula for aggregate apparent specific gravity is

Mass of oven dried aggregate/ ( Mass of oven dried aggregate - Submerged mass of aggregate) = 5216/ (5216 - 3295) = 2.7

C) The moisture content of the stockpile aggregate is

m = (weight of moist aggregate - mass of oven dried aggregate) / (mass of oven dried aggregate* 100%)

m = (5298 - 5216)/ (5216* 100%) = 1.6 %

D) Absorption is calculated as A = (5227 - 5216) / (5216) * 100% = 0.21 %

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A high amplitude sound wave can best be compared to a tightly coiled spring.

The amplitude of a wave is the maximum displacement of the wave.  It is the vertical distance measured from the equilibrium position of the wave.

A tightly coiled spring will have maximum displacement or high amplitude.

A stretched - out spring will have low amplitude

Thus, a high amplitude sound wave can best be compared to a tightly coiled spring.

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Option C is correct. A high amplitude sound wave can best be compared to a tightly coiled spring.

The largest displacement of a wave is known as its amplitude. It's the vertical distance between the wave's equilibrium point and the ground.

A spring that is tightly coiled. A tightly coiled spring will have a large amplitude or maximum displacement.

A spring that has been stretched out will have a low amplitude. A tightly coiled spring is the greatest analogy for a high amplitude sound wave.

Hence high amplitude sound wave can best be compared to a tightly coiled spring.

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During the passage of a longitudinal wave, a particle of the medium moves back and forth along the direction of the wave's propagation. This type of wave is characterized by its compression and rarefaction phases, which are responsible for transmitting energy through the medium.

Longitudinal waves can be observed in various scenarios, such as sound waves traveling through the air or seismic P-waves moving through the Earth's interior. In a compression phase, the particles of the medium are pushed closer together, increasing the density and pressure in that region.

Conversely, during the rarefaction phase, particles move farther apart, causing a decrease in density and pressure. This alternating pattern of compressions and rarefactions creates a continuous transfer of energy through the medium.

The motion of the medium's particles is parallel to the wave's direction, which distinguishes longitudinal waves from transverse waves, where particle movement is perpendicular to the wave's propagation. The speed of a longitudinal wave depends on the medium's properties, such as its elasticity and density. A more elastic and less dense medium allows for faster wave propagation.

Overall, a particle of the medium involved in a longitudinal wave oscillates in a back-and-forth motion along the direction of the wave, contributing to the transfer of energy as the wave travels through the medium. This dynamic process of compression and rarefaction enables longitudinal waves to carry information and energy across vast distances.

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The appropriate SI base unit for measuring each of the following

1. the diameter of a large pizza ⇒ Meter

2. the mass of a pencil ⇒ Kilogram

3. the length of the soccer field⇒ Meter

4. the distance from your home to school ⇒Meter

5. the mass of the bicycle⇒Kilogram

6. the time to play a song⇒second

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation. Any additional quantity of that type can be stated as a multiple of the measurement unit.

Thus, we can represent the appropriate SI base unit for measuring each

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Answer:

1) The Mechanical Advantage of the lever is 3

2) The velocity ratio of the lever is 4

3) The efficiency of the lever is 75%

Explanation:

A lever is a simple machine that is used to lift a heavy load with a little effort or force

The mechanical advantage is the ratio of the force output to the force input

The given parameters of the lever are;

The length of the lever = 1 m

The weight of the load (force output), \(F_r\) = 600 N

The effort applied (force input), \(F_e\) = 200 N

1) The Mechanical Advantage, MA of the lever is given as follows;

\(MA = \dfrac{F_r}{F_e} = \dfrac{600 \ N}{200 \ N} = 3\)

The Mechanical Advantage, MA of the lever = 3

2) The velocity ratio, V.R., is the ratio of the distance moved by the effort, \(L_e\), to the distance moved by the load, \(L_r\)

For the lever, we have;

The distance of the load from the fulcrum, \(L_r\) = 20 cm = 0.2 m

Therefore, we have;

The distance of the effort from the fulcrum, \(L_e\) = 1 m - 0.2 m = 0.8 m

From which we have;

\(V.R.= \dfrac{L_e}{L_r} = \dfrac{0.8 \ m}{0.2 \ m} = 4\)

The velocity ratio of the lever = 4

3) The efficiency, η, is given as follow;

\(\%Efficiency, \, \eta = \dfrac{M.A.}{V.R.} \times 100 = \dfrac{3}{4} \times 100 = 75\%\)

The efficiency of the lever is 0.75 or 75%.

Explanation:

The length of the lever = 1 m

The weight of the load (force output), F_rF

r

= 600 N

The effort applied (force input), F_eF

e

= 200 N

1) The Mechanical Advantage, MA of the lever is given as follows;

MA = \dfrac{F_r}{F_e} = \dfrac{600 \ N}{200 \ N} = 3MA=

F

e

F

r

The length of the lever = 1 m

The weight of the load (force output), F_rF

r

= 600 N

The effort applied (force input), F_eF

e

= 200 N

1) The Mechanical Advantage, MA of the lever is given as follows;

MA = \dfrac{F_r}{F_e} = \dfra

=

200 N

600 N

=3

The Mechanical Advantage, MA of the lever = 3

2) The velocity ratio, V.R., is the ratio of the distance moved by the effort, L_eL

e

, to the distance moved by the load, L_rL

r

For the lever, we have;

The distance of the load from the fulcrum, L_rL

r

= 20 cm = 0.2 m

Therefore, we have;

The distance of the effort from the fulcrum, L_eL

e

= 1 m - 0.2 m = 0.8 m

From which we have;

V.R.= \dfrac{L_e}{L_r} = \dfra

The distance of the load from the fulcrum, L_rL

r

= 20 cm = 0.2 m

Therefore, we have;

The distance of the effort from t

V.R.= \dfrac{L_e}{L_r} = \dfrac{0.8

L

e

=

0.2 m

0.8 m

=4

The velocity ratio of the lever = 4

3) The efficiency, η, is given as follow;

\%Efficiency, \, \eta = \dfrac{M.A.}{V.R.} \times 100 = \dfrac{3}{4} \times 100 = 75\%%Efficiency,η=

V.R.

M.A.

×100=

4

3

×100=75%

The efficiency of the lever is 0.75 or 75

The new angular speed when the man walks to a point 0m from the center is ω = 0.369 rev/s.

The definition of angular speed is the rate at which angular displacement changes, and it is expressed as,

ω=θ/t

where t is the period of time, is the angular speed, and ω is the angular displacement.

Radian per second is used to measure angular speed. Both angular velocity and angular speed are represented using the same formula.

Now for the given question,

Since there is no external torque, angular momentum of the system is conserved. Then, the angular momentum when the man is at x = 1.6 m, it is equal to that of x = 0 m.

\(L_1=L_2\\I_1ω_1=I_1ω_2\)

where I is the moment of inertia of the system. Here we consider the merry-go-round which is a solid cylinder and the man which can be regarded as a point object.

Total moment of inertia in first case is

\(I_1=I_{cylinder}+ I_{man}= 1/2 m_{cylinder}R^2_{cylinder}+m_{man}d^2\\ = 1/2 (72)(1.6)^2+(97)(1.6)^2=340.48\)

moment of inertia in second case is

\(I_2=1/2 m_{cylinder}R^2_{cylinder}+ m_{man}(0)\\=1/2(72)(1.6)^2=92.16\)

In the second case, the man shows no contribution to the moment of inertia of the system, since he stands on the center.

Finally,

\(I_1ω_1=I_2ω_2\\(340.48)(0.1)=(92.16)ω_2\\ω_2=0.369 rev/sec.\)

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The other string could have a frequency of either 288.3 Hz or 291.7 Hz.

If the middle-c hammer of a piano hits two strings and produces beats of 1.70 Hz, it means that the frequencies of the two strings are very close to each other, but not exactly the same. One of the strings is turned to 290.00 Hz, so we can calculate the possible frequencies of the other string by adding or subtracting the beat frequency from the tuned frequency.

So, the possible frequencies of the other string could be 288.3 Hz or 291.7 Hz.

To get these values, we can use the formula:

f(other string) = tuned frequency ± beat frequency

f(other string) = 290.00 ± 1.70

f(other string) = 288.3 Hz or 291.7 Hz

Therefore, the other string could have a frequency of either 288.3 Hz or 291.7 Hz.

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Answer:

330m/s

Explanation:

v= total distance/ time

=3300/10

An observer on sub B would detect a sonar wave at a frequency of 1389.2 Hz as the two submarines approach each other.

When two objects are moving toward each other, the relative motion of the objects causes a change in the frequency of sound waves between them. This phenomenon is known as the Doppler effect, and it can be used to calculate the frequency of sound waves received by an observer on a moving object.

In this scenario, the first submarine (sub A) is emitting a sonar wave at a frequency of 1400 Hz while moving through the water at a speed of 17.89 mi/h. The second submarine (sub B) is moving towards sub A at a speed of 20.13 mi/h. The speed of sound in water is 1533 m/s.

To determine the frequency of the sonar wave received by an observer on sub B, we need to first calculate the relative velocity between the two submarines. We can use the formula:

Relative velocity = velocity of sub A + velocity of sub B

Since the two submarines are moving towards each other, the velocity of sub B is negative. Therefore, the relative velocity is:

Relative velocity = 17.89 mi/h - 20.13 mi/h = -2.24 mi/h

Next, we need to convert the relative velocity into meters per second to use the formula for the Doppler effect:

Relative velocity = -2.24 mi/h = -1.0016 m/s

Now we can use the formula for the Doppler effect:

\(f' = \frac{f((v + v_{obs})}{(v + v_{sound}))}\)

Where f is the original frequency of the sonar wave emitted by sub A, v is the velocity of sub A, v_obs is the velocity of sub B, v_sound is the speed of sound in water, and f' is the frequency of the sonar wave received by an observer on sub B.

Plugging in the values we have:

f' = 1400 Hz ((17.89 mi/h - 20.13 mi/h) / (17.89 mi/h + 1533 m/s))

Converting the velocities to meters per second:

f' = 1400 Hz ((-1.0016 m/s) / (7.9948 m/s))

Simplifying:

f' = 1389.2 Hz

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Answer:

What is the figure? please provide

The potential energy (PE) represented by mgh (mass, gravitational acceleration, and height) is called gravitational potential energy (GPE).

The term GPE refers to the potential energy possessed by an object due to its height in the Earth's gravitational field. This energy is stored in the object, and it has the potential to do work because of its position.

Gravitational potential energy is a type of potential energy that is calculated using the equation mgh. Gravitational potential energy is the energy stored in an object due to its position in a gravitational field. This type of energy is based on the distance between two objects and the gravitational force between them. Gravitational potential energy is related to the object's mass and the height it is located above the ground. The formula mgh is used to determine the potential energy stored in the object. In this equation, m is the mass of the object, g is the acceleration due to gravity, and h is the height above the reference point. The unit of gravitational potential energy is Joules (J).

Gravitational potential energy is a type of potential energy that is used to describe the energy stored in an object due to its position in a gravitational field. Gravitational potential energy is equal to the mass of the object times the acceleration due to gravity times the height above the reference point. Gravitational potential energy is measured in Joules (J).

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Answer:

The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m

Explanation:

Given that,

First charge = 40 μC

Second charge = 80 μC

Distance between the two particles = 2.0 m

Kinetic energy = 16 J

We need to calculate the distance separating the two particles when the moving particle is momentarily stopped

Using conservation of energy

\(K.E+\dfrac{kq_{1}q_{2}}{d}=\dfrac{kq_{1}q_{2}}{x}+K.E\)

Put the value into the formula

\(16+\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{2}=\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{x}+0\)

\(16+14.4=\dfrac{28.8}{x}\)

\(30.4x=28.8\)

\(x=\dfrac{28.8}{30.4}\)

\(x=0.947\ m\)

Hence, The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m

The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m.

The given parameters;

The kinetic energy is zero at the instant the moving particle is momentarily stopped.

The distance separating the two particles when the moving particle is momentarily stopped is calculated as follows;

\(K.E_1 \ + W_1 = K.E_2 + W_2\\\\K.E_1 + \frac{kq_1q_2}{x_1} = K.E_2 + \frac{kq_1q_2}{x_2} \\\\16 \ + \ \frac{(9\times 10^9)\times (40\times 10^{-6})\times (80\times 10^{-6})}{2} = 0 \ + \ \frac{(9\times 10^9)\times (40\times 10^{-6})\times (80\times 10^{-6})}{x_2} \\\\30.4= \frac{28.8}{x_2} \\\\x_2 = \frac{28.8}{30.4} \\\\x_2 = 0.947 \ m\)

Thus, the distance separating the two particles when the moving particle is momentarily stopped is 0.947 m.

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Answer:

10m/s

Explanation:

Answer: 10

Explanation: Because, 10*10= 100 or 100/10=10

Explanation:

Tony's claim that solids do not have a lot of thermal expansion is partially true, but it is not entirely accurate. All materials, including solids, do undergo some degree of thermal expansion or contraction when their temperature changes. However, the amount of expansion or contraction varies depending on the material's coefficient of thermal expansion (CTE), which measures the material's response to temperature changes.

Some materials, like metals, have a high CTE and undergo significant expansion or contraction when their temperature changes. On the other hand, materials like ceramics and glasses have a low CTE and undergo relatively little expansion or contraction. Wood, which is the material used to make the door in Valdez's house, has a moderate CTE, meaning it undergoes some degree of expansion or contraction with changes in temperature.

Therefore, Valdez's argument is valid. The wooden door in his house experiences thermal expansion in the summer due to the higher temperatures. As the temperature increases, the particles in the wood gain kinetic energy, move faster, and create more space between each other, which results in the door expanding. Conversely, in the winter, the lower temperatures cause the particles in the wood to lose energy, move slower, and become closer to each other, which results in the door contracting.

In conclusion, while Tony's statement is correct in that solids do not have a lot of thermal expansion compared to liquids or gases, all solids, including wood, do experience some degree of thermal expansion or contraction due to changes in temperature.

The comet that is beyond neptune belongs to the oort cloud

The Oort Cloud is an icy celestial mass predicted to be more distant than any other cloud in the solar system. This is consistent with observations of comets in the planetary regions of the solar system, but scientists have yet to observe an object in the Oort Cloud itself. The Oort Cloud is about two light years away from Earth. This means that light travels 300,000 kilometers per second and takes two years to travel from the Oort Cloud to Earth. The Oort Cloud is sometimes used to mark the edge of the solar system. 

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Answer:

Both momentum and kinetic energy are conserved quantities in elastic collisions.

Explanation:

An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.

Answer:

b. 1.1 m/s c. -1.1 m/s

Explanation:

b.

m x v=f x t

The mass is 10 kg

10 x v (equation for momentum) = f x t (impulse)

you would find the impulse by finding the area under the graph, and then dividing by the mass

So in this case:

10 x v = 11

then divide by the mass

v = 11/10

v= 1.1 m/s

c.

F x t = impulse

we are trying to find force (magnitude)

impulse/t = F

we said that in order for it to stop the impulse for b would be 11, so if thats the case it would be 11 but it would be negative because when going in a positive direction and suddenly stopping the direction changes.

-11/t = F

to find t all we need to do is find the amount of seconds between 10 and 20, that would be 10.

-11/10 = F

F= -1.1 m/s

Answer B:

The velocity of the box at 10 seconds is :

              m x v=f x t

Given Information :

Mass(m)=10kg

Therefore, the velocity of the box at 10 seconds is 1.1m/s.

Answer C:

The magnitude and direction of that force be :

F x t = impulse

To find t all we need to do is find the amount of seconds between 10 and 20, that would be 10.

The magnitude and direction of that force will be -1.1m/s.

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A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. The minimum angle of elevation necessary to hit the target is approximately 15.2 degrees.

To find the minimum angle of elevation, we can use the equation for the horizontal range of a projectile. The horizontal range is the distance traveled by the bullet in the horizontal direction, which in this case is 4750 feet. The equation for the horizontal range is: R = (v^2 * sin(2θ)) / g

where R is the range, v is the muzzle velocity, θ is the angle of elevation, and g is the acceleration due to gravity.

Rearranging the equation to solve for θ, we have: θ = 0.5 * arcsin((R * g) / v^2). Plugging in the given values, we have: θ = 0.5 * arcsin((4750 * 32.2) / (1099^2))

Evaluating this expression, we find that the minimum angle of elevation necessary to hit the target is approximately 15.2 degrees. This means that the gun should be elevated at an angle of approximately 15.2 degrees above the horizontal in order to hit the target 4750 feet away.

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Answer:

I think A because inertia is the amount of potential energy right? hope this helps :)

Explanation:

Answer:

5 Stars

Explanation:

Because every Star from 1 to 5 vary energy consumption of the electrical device...So 5 star product uses a very less energy compared to 1 star product...

Hope it is helpful

There are 0 to 5 star are used in the star rating label of electrical appliance.

The appliance is more energy efficient if it has more stars on the Energy Rating Label. To perform at the same level as comparable models of the same size or capacity, efficient appliances require less electricity. A model will use less energy and cost you less to run if it is more energy efficient.

Example a 3-star refrigerator saves a lot more energy compared to a 2 star.

Number of stars in the star rating label of an electrical appliance should be used is five for most efficient electrical device.

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The work function of potassium is approximately 3.564 x 10^-19 J.  The threshold (cutoff) wavelength for potassium is 5.33 x 10^-7 m. The frequency corresponding to the cutoff wavelength is 5.63 x 10^14 Hz.

(a) To find the work function of potassium, we need to calculate the energy of a photon with the given wavelength and equate it to the maximum kinetic energy of the emitted electrons. The energy of a photon (E) is given by the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength. E = hc/λ = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (350 x 10^-9 m) = 5.66 x 10^-19 J
Since the maximum kinetic energy is given as 1.31 eV, we convert it to joules:
1.31 eV = 1.31 x 1.6 x 10^-19 J = 2.096 x 10^-19 J
Now, we can determine the work function:
Work function = Energy of a photon - Maximum kinetic energy = 5.66 x 10^-19 J - 2.096 x 10^-19 J = 3.564 x 10^-19 J
Therefore, the work function of potassium is approximately 3.564 x 10^-19 J.
(b) The threshold (cutoff) wavelength corresponds to the minimum wavelength of light required to emit electrons from the potassium surface. At this wavelength, the energy of the photon matches the work function.
E = hc/λ_cutoff = Work function
λ_cutoff = hc/Work function = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (3.564 x 10^-19 J) = 5.33 x 10^-7 m
Therefore, the threshold (cutoff) wavelength for potassium is approximately 5.33 x 10^-7 m.
(c) To find the frequency corresponding to the cutoff wavelength, we can use the equation:
f = c/λ_cutoff = (3 x 10^8 m/s) / (5.33 x 10^-7 m) = 5.63 x 10^14 Hz
Therefore, the frequency corresponding to the cutoff wavelength is approximately 5.63 x 10^14 Hz.

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Answer:

sequence

Explanation:

sequences are the way in which things are ordered, for example: 1, 2, 3, 4 is a sequence:)

Because of Kinetic Theory Postulate, the gas molecule's collision will affect.

Gases can be compressed because most of the volume of gas is an empty space according to Kinetic Molecular theory. If we compress a gas without changing its temperature, the average K.E of the gas particles remains the same. There is no change in the speed of the gas molecules with which the particles move in a container, but the container is smaller. So particles travel from one side of the container to the other in a very small period of time. So it means that they strike the walls mostly. Any increase in the frequency of collisions with the walls must increase the pressure of the gas. from Boyle's law, the pressure of gas becomes more significant as the volume of the gas becomes smaller have opposite relation.

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