Given that the initial speed, u = 3.68 m/s^2 anf the final speed is v=0.
and the mass of the player, m = 82.5 kg, and the coefficient of friction is
\(\mu=\text{ 0.6 }\)(a) The change in internal energy is given by the formula
\(\begin{gathered} \Delta U=\text{decrease in kinetic energy} \\ =\frac{1}{2}m(v)^2-\frac{1}{2}m(u)^2 \end{gathered}\)Substituting the values, the internal energy will be
\(\begin{gathered} \Delta U=\frac{1}{2}\times82.5\times0-\frac{1}{2}\times82.5\times(3.68)^2 \\ =-\text{ 558.62 J} \end{gathered}\)(b) The distance is given by the formula
\(d=\frac{u^2}{2\mu g}\)Here, the acceleration due to gravity, g= 9.8 m/s^2.
Substituting the values, the distance will be
\(\begin{gathered} d=\frac{(3.68)^2}{2\times0.6\times9.8} \\ =1.51\text{ m} \end{gathered}\)Thus the distance is 1.51 m.
The net force on a 13 kg cart is 4.6 N backward.
Ignoring friction, what is the acceleration of the
cart?
a. 0.27 m/s2 backward
b. 3.8 m/s2 backward
c. 35 m/s2 backward
d. 38 m/s2 backward
Divide the net force by the mass:
a = (4.6 N) / (13 kg) ≈ 0.35 m/s²
also pointing backward, which looks like option B, but hard to say for sure since it's missing a decimal point.
what is time taken by radio wave to go and return back from communication satellite to earth??
Answer:
Radio waves are used to carry satellite signals. These waves travel at 300,000 km/s (the speed of light). This means that a signal sent to a satellite 38,000 km away takes 0.13 s to reach the satellite and another 0.13 s for the return signal to be received back on Earth.
Explanation:
hope it help
A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror, when the person is 5.80 ft from the mirror on the left wall and 13.7 ft from the mirror on the right wall.
Answer:
Explanation:
When the person stands 5.80 ft from the mirror of the wall.
a) The first image is found by multiplying the distance of the left mirror to the person.
i.e.
2 × 5.80 = 11.6 ft
b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.
i.e.
(2 × 13.7 ) + 11.6
= 39 ft
c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.
(2 × 5.80) + 39
= 50.6 ft
HONI A ball is rolling steady on the floor. (a) Draw and label all the forces acting on the ball. (b) Describe the relationships between all the forces acting on the ball
a) The image is attached to this answer
b) The kinetic friction force affects the forward force of the ball.
What is the relationship between the forces that act on a rolling ball?
The force that opposes a rolling ball's motion is called rolling friction. It slows the ball down by acting in the opposite direction to that of the ball's motion. The weight of the ball and the type of the surface are two variables that affect rolling friction.
The force that a surface uses to maintain the weight of an object that is resting on it is known as the normal force. When a ball is rolling, the normal force exerts itself perpendicular to the surface the ball is moving on. It maintains the ball's weight balance and offers the required reaction force for rolling motion.
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when light enters albite, also called "moonstone", it has a luminous albedo- like a full moon. When light in air enters albite, it travels at a velocity of 1.95x108 m/s.
What is albite's index of refraction?
Answer:
yes
Explanation:
elocity of 1.95x108 m/s.
Classify the following situations into contact and non-contact forces.
(a) Applying brakes in a vehicle
(b) a coconut falling from a coconut tree
(c ) the planets revolving around the sun
(d) a ball is rolling on ground.
Answer: Contact force
a. Applying break in a vehicle.
d. The speed of ball rolling on ground is reduced
Non contact force
b. A coconut falling from a coconut tree.
c. The planets revolving around the sun.
Explanation:
The contact force is the force which exerts when one object or entity comes in contact with other object or entity. For example, on application of break the vehicle stops, the force is applied on the breaks to stop the vehicle. The ball rolling on the ground the speed reduces so the application of force on the ground also reduces.
The non contact force is the force one object exerts on the other without coming in direct contact with the other object. The force exerted by one object on other due to gravity is a non contact force. The coconut falling on the ground and planets revolving around the sun are examples of non contact force due to gravity.
A student makes the following claim, "Acceleration is when an object changes speed, so it can be discussed as a scalar quantity." Explain the error in the student's claim. Provide an example of each quantity to support your answer.
A student makes the following claim, "Acceleration is when an object changes speed, so it can be discussed as a scalar quantity." The error here is that acceleration is said to be done when either speed of that object changes or direction of that object changes. Hence , acceleration is not a scaler quantity.
Scalar quantities are quantities that only have a magnitude and do not have any direction
A vector quantity is defined as the physical quantity that has magnitude as well as directions associated to it.
Acceleration is said to be occurred in two cases :
when the object changes its speed
or when the object changes its direction
since , acceleration depends upon both direction as well as magnitude ,hence it is a vector quantity not a scaler quantity.
for example : a stone attached to a string moving in a circular motion at a constant speed will be considered in accelerated motion because it is constantly changing its direction. Here we can see speed is constant hence magnitude (value of speed) is not changing but direction of the stone is changing . since , direction is changing the object is said to be in accelerated motion.
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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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Could anyone help me on this question?
You really don't need any help on the question. It's all right there in the picture. What you need help with is the answer.
The number of times the same thing happens each second is called its "frequency". The frequency of the dragonfly's flaps is 477 Hz. (If you're close enough to the dragonfly, you can hear the wings flapping. It sounds like a raspy tone with a frequency of 477 Hz.)
The "period" is just the length of time it takes to happen once. That length of time is just (1 / frequency) .
The dragonfly flaps its wings once every (1 / 477 Hz) = 0.0021 second (C)
A car drives around a racetrack for 30 seconds. What do you need to know to
calculate the instantaneous speed of the car at a given point?
A. The total displacement of the car
B. The time needed to drive 1 lap
C. The slope of the car's position-time graph
D. The average speed of the car
Answer: the slope of the cars position-time graph
Explanation:
Just took the test
Many of the important discoveries of genetics and inheritance came from these:
fruit flies
zebras
enzymes
Answer:
fruit flies
Explanation:
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50 POINTS‼️‼️‼️‼️‼️
A 4.88 x 10-6 C charge moves 265 m/s
perpendicular (at 90°) to a magnetic
field of 0.0579 T. What is the magnetic
force on the charge?
Answer: 0
Explanation: Trust
The magnetic force on the charge is approximately 6.47 x 10^(-4) Newtons.
The magnetic force on a charged particle moving through a magnetic field can be calculated using the formula:
F = q * v * B * sin(θ)
Where:
F is the magnetic force,
q is the charge of the particle (in this case, 4.88 x 10^(-6) C),
v is the velocity of the particle (in this case, 265 m/s),
B is the magnetic field strength (in this case, 0.0579 T),
θ is the angle between the velocity vector and the magnetic field vector (in this case, 90 degrees).
Plugging in the values:
F = (4.88 x 10^(-6) C) * (265 m/s) * (0.0579 T) * sin(90°)
Since sin(90°) is equal to 1, the equation simplifies to:
F = (4.88 x 10^(-6) C) * (265 m/s) * (0.0579 T) * 1
Calculating the value:
F = 6.47 x 10^(-4) N
Therefore, the magnetic force on the charge is approximately 6.47 x 10^(-4) Newtons.
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The surface temperature of our sun is about 5800 K, and the peak of its intensity curve is in the middle of the visible spectrum. Mammals have a body temperature of about 310 K. A star that appears reddish could have a surface temperature of:
Explanation:
i expected to use Stefan's law of heat exchange but the value you gave aren't conclusive.
I should say that the temperature of the star should be close to that of the sun because of the similarity in the intensity curves
1. At t=0s, a particle moving in the x-y plane with constant acceleration has a velocity ofv; = (3î-2)) m/s, and is at the origin. At t=3s, the particle's velocity is f = (91+7j) m/s. Find (a)the acceleration of the particle (b) Its coordinates at t=3s
Answer:
the particle is at coordinates (18,15/2)
Explanation:
To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:
a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j
So the acceleration of the particle is a = 2i + 3j m/s².
To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:
r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j
We can use the kinematic equations of motion to solve this problem.
Let the acceleration of the particle be a = axî + ayj.
(a) Using the equation of motion v = u + at, where u is the initial velocity:
f = v = u + at
Substituting the given values, we get:
(91+7j) = (3î-2j) + a(3î + 3j)
Equating the real and imaginary parts, we get:
91 = 3a + 3a (coefficients of î are equated)
7 = -2a + 3a (coefficients of j are equated)
Solving these equations simultaneously, we get:
a = î(23/6) + j(1/2)
So the acceleration of the particle is a = (23/6)î + (1/2)j.
(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:
At t = 3s, the displacement of the particle is:
s = ut + (1/2)at^2
Substituting the given values, we get:
s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2
Simplifying, we get:
s = 9î + (17/2)j
So the coordinates of the particle at t=3s are (9, 17/2).
A piston-cylinder device initially contains 50 L of liquid water at 40°C and 200 kPa. Heat is transferred to the water at constant pressure until the entire liquid is vaporized. (a) What is the mass of the water? (b) What is the final temperature? (c) Determine the total enthalpy change. (d) Show the process on a T-v diagram with respect to saturation lines.
(a) The mass of water is approximately 49.65 kg. (b) The final temperature of the water vapor will be 120°C. (c) The total enthalpy change is approximately 277,956 kJ. (d) Diagram shown below.
(a) To determine the mass of the water, we need to know its density at the given conditions. The density of water changes with temperature and pressure. At 40°C and 200 kPa, the density of water is approximately 993 kg/m³.
Since we have 50 L of water, we need to convert it to cubic meters:
50 L = 0.05 m³
Now we can calculate the mass of water:
Mass = Density * Volume
Mass = 993 kg/m³ * 0.05 m³
Mass ≈ 49.65 kg
Therefore, the mass of water is approximately 49.65 kg.
(b) To find the final temperature, we need to consider the phase change from liquid to vapor. At constant pressure, the temperature will remain constant until all the liquid water has vaporized. This temperature is called the saturation temperature.
We can determine the saturation temperature at 200 kPa using a steam table or other relevant data sources. Let's assume that the saturation temperature is 120°C.
Therefore, the final temperature of the water vapor will be 120°C.
(c) To calculate the total enthalpy change, we need to consider the energy required to heat the water from its initial temperature to the saturation temperature, as well as the energy required for the phase change from liquid to vapor.
The enthalpy change during heating can be calculated using the formula:
ΔH1 = Mass * Specific Heat Capacity * ΔT1
Where:
Mass = 49.65 kg (from part a)
Specific Heat Capacity = specific heat capacity of water at constant pressure = 4.18 kJ/(kg·°C)
ΔT1 = final temperature - initial temperature = 120°C - 40°C = 80°C
ΔH1 = 49.65 kg * 4.18 kJ/(kg·°C) * 80°C
ΔH1 ≈ 165,938 kJ
The enthalpy change during phase change can be calculated using the formula:
ΔH2 = Mass * Latent Heat of Vaporization
Where:
Mass = 49.65 kg (from part a)
Latent Heat of Vaporization = energy required to vaporize 1 kg of water = 2257 kJ/kg
ΔH2 = 49.65 kg * 2257 kJ/kg
ΔH2 ≈ 112,018 kJ
The total enthalpy change is the sum of ΔH1 and ΔH2:
Total Enthalpy Change = ΔH1 + ΔH2
Total Enthalpy Change ≈ 165,938 kJ + 112,018 kJ
Total Enthalpy Change ≈ 277,956 kJ
Therefore, the total enthalpy change is approximately 277,956 kJ.
(d) The process can be shown on a T-v (temperature-volume) diagram with respect to saturation lines. In this case, the process starts at the initial temperature and pressure (40°C, 200 kPa), and moves along the constant pressure line until reaching the saturation temperature (120°C). Then, the process follows the saturation line until the entire liquid is vaporized.
Here is a simplified representation of the process on a T-v diagram:
|
Saturation | |
Line | |
| |
| |
| |
| |
| |
| |
Initial |-----------------------------| Final
| |
| |
| |
| |
| |
|
This diagram is a rough representation and does not accurately reflect specific volume values or scale. It simply illustrates the general process from initial conditions to the final state along the constant pressure and saturation lines.
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What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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dose contact or noncontact force weaken with distance
Answer:
The more massive an object is, the greater the gravitational force. Since gravitational force is inversely proportional to the distance between two interacting objects, more separation distance will result in weaker gravitational forces.
Explanation:
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A gene can be best described as a unit of –
The Bernoulli effect can have important consequences for the design of buildings. For example, wind can blow around a skyscraper at remarkably high speed, creating low pressure. The higher atmospheric pressure in the still air inside the building can cause windows to pop out. This happened with the original design of the John Hancock Building in Boston.
(a) Suppose a horizontal wind blows with a speed of 11.2 m/s outside a large pane of plate glass with dimensions 4.00 m X 1.50 m. Assume the density of air to be constant at 1.20 kg/m3. The air inside the building is at atmospheric pressure. What is the total force exerted by air on the window pane?
(b) What force is experienced by the window pane from air if the airspeed outside is now 22.4m/s The Bernoulli effect can have important consequences for the design of buildings. For example, wind can blow around a skyscraper at remarkably high speed, creating low pressure. The higher atmospheric pressure in the still air inside the building can cause windows to pop out. This happened with the original design of the John Hancock Building in Boston.
Answer:
a. 451.58 N b. 1806.34 N
Explanation:
(a) Suppose a horizontal wind blows with a speed of 11.2 m/s outside a large pane of plate glass with dimensions 4.00 m X 1.50 m. Assume the density of air to be constant at 1.20 kg/m3. The air inside the building is at atmospheric pressure. What is the total force exerted by air on the window pane?
Using Bernoulli's equation
P₁ + 1/2ρv₁² + ρgh₁ = P₂ + 1/2ρv₂² + ρgh₂ where P₁ = pressure of air in building = atmospheric pressure = 1.013 × 10⁵ N/m², ρ = density of air = 1.20 kg/m³, v₁ = speed of air in building = 0 m/s(since it is still), h₁ = h₂ = h = height of building, P₂ = pressure on the outside of window pane, v₂ = speed of air outside window pane = 11.2m/s and g = acceleration due to gravity
So, since h₁ = h₂ = h
P₁ + 1/2ρv₁² + ρgh = P₂ + 1/2ρv₂² + ρgh
P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²
Also, v₁ = 0m/s
So, P₁ + 1/2ρ(0 m/s)² = P₂ + 1/2ρv₂²
P₁ + 0 = P₂ + 1/2ρv₂²
P₁ = P₂ + 1/2ρv₂²
P₁ - P₂ = 1/2ρv₂²
So the net pressure on the window is ΔP = P₁ - P₂ = FA where F is the total force on the window pane and A is the area of the window pane = 4.00 m × 1.50 m = 6.00 m²
So, P₁ - P₂ = 1/2ρv₂²
ΔP = 1/2ρv₂²
F/A = 1/2ρv₂²
F = 1/2ρAv₂²
Substituting the values of the variables into the equation, we have
F = 1/2ρAv₂²
F = 1/2 × 1.20 kg/m³× 6.00 m² × (11.2 m/s)²
F = 1/2 × 1.20 kg/m³ × 6.00 m² × 125.44 m²/s²
F = 451.584 N
F ≅ 451.58 N
(b) What force is experienced by the window pane from air if the airspeed outside is now 22.4m/s
When v₂ = 22.4 m/s, F is
F = 1/2ρAv₂²
F = 1/2 × 1.20 kg/m³× 6.00 m² × (22.4 m/s)²
F = 1/2 × 1.20 kg/m³ × 6.00 m² × 501.76 m²/s²
F = 1806.336 N
F ≅ 1806.34 N
You are moving your desk across the room. What force do you have to overcome in order to start the moving?possible answers1. Dynamic Friction2. Static Friction3. If it's not moving, there are no forces to overcome.4.Gravity
In order to start moving the desk, we need to overcome the force of static friction
ANSWER
2. Static Friction
when the moving sidewalk at the airport is broken, as it oftenseems to be , it takes you 50sec to walk from your gate to baggageclaim. when it is working and you stand on the moving sidewalk theentire way, without walking, it takes you 75sec to travel thesame distance.
Q : how long will it take you to travel from the gate tobaggage claim if you walk while riding on the movingsidewalk?
30 sec time it will take you to travel from the gate to baggage claim if you walk while riding on the moving sidewalk. This can be solved by using the concept of velocity.
What is velocity?The direction of a body or object's movement is defined by its velocity. Speed is fundamentally a scalar number. In essence, velocity is a vector quantity. The pace at which distance changes is what it is. It is the displacement change rate. The definition of velocity is the determination of a moving object's speed and direction (for example, 60 km/h to the north).
Here let us suppose that "d" denotes the distance in meter.
Walking velocity =d/v₁ = 50 sec
Walking velocity = d/50 m/sec
Also,
riding velocity = d/v₂ = 75 sec
V₂ = d / 75 m/sec
∴ combined velocity = d / 50 + d / 75 = 5d / 150
Hence the value of the time taken to travel while walking on a moving sidewalk is given as below.
t = (d / 5) × (d / 150)
t =30 sec
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What's one major difference between the earth's greenhouse effect and an actual greenhouse?
Select one:
a.
Heat escapes from a greenhouse more easily than it does from Earth's atmosphere
b.
The glass in a greenhouse traps heat, while greenhouse gases in the atmosphere absorb and recycle heat
c.
There is no significant difference; both work pretty much the same way
d.
Actual greenhouses are cold in winter, while the greenhouse effect has led to warm winters across the earth
The difference between the earth's greenhouse effect and an actual greenhouse is that the glass in a greenhouse traps heat, while greenhouse gases in the atmosphere absorb and recycle heat. That is option B.
What is a green house gas?The greenhouse gas is the type of gas that is found in the earth's atmosphere that has the ability to absorb heat from the earth's environment.
Examples of greenhouse gases include the following:
carbon dioxide, methane, nitrous oxide, and water vapor.An ordinary greenhouse is used to grow crops such as tomatoes and tropical flowers. Heat is bring trapped inside these houses as the sun shines during the day time.
Therefore, it can be concluded that the major difference between the earth's greenhouse effect and an actual greenhouse is that the glass in a greenhouse traps heat, while greenhouse gases in the atmosphere absorb and recycle heat.
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A 3.0 kg puck slides due east on a horizontal frictionless surface at a constant speed of 4.5 m/s. Then a force of magnitude 6.0 N, directed due north, is applied for 1.5 s. Afterward, a. What is the northward component of the puck’s velocity?
Answer:
3 m/s
The northward component of the puck’s velocity is 3 m/s
Explanation:
Applying the impulse momentum equation;
Impulse = change in momentum
Ft = m(∆v)
∆v = Ft/m
F = force = 6.0 N due north
t = time = 1.5 s
m = mass = 3.0 kg
Substituting the values;
Change in velocity ∆v = (6 × 1.5)/3.0 = 9/3
∆v = 3 m/s due north
And since the initial northward component of the puck’s velocity is zero.
The final northward component of the puck’s velocity is;
v = 0 + 3 m/s
v = 3 m/s
The northward component of the puck’s velocity is 3 m/s
Ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load.
True
False
Answer: False
Explanation:
Took the test.
Hide question 9 feedback
Rationale:
Ideal mechanical advantage is the ratio of input to output distance moved.
(Figure 1) shows a container with a cross-section area of 15 cm^2 in which a layer of water floats on top of a layer of mercury. A 1.0 kg wood block with a cross-section area of 10 cm^2 floats on the water. The water depth, measured from the bottom of the block, is 25 cm. A pressure gauge at the bottom of the container reads 26 kPa.
A container with vertical walls is filled with a layer of mercury of height h at the bottom and a layer of water above it. A rectangular block of 1.0 kilogram floats on the water. The distance from the mercury layer to the bottom side of the block is 25 centimeters. The area of the horizontal cross section of the block is 10 square centimeters. The area of the bottom of the container is 15 square centimeters. A pressure gauge is located at the bottom of the container.
Part A
What is the depth dm of the mercury? Use ρw = 1000 kg/m3 as the density of water and ρm = 13,600 kg/m3 as the density of mercury.
Pressure gauge is located at the bottom of the container thus, the depth of the mercury = 11.05 cm
What is pressure?Pressure refers to the force applied on a unit area of a surface. It works parallel to the pressure-applied surface. Pressure = force multiplied by the area on which it operates. The stronger the power, the smaller the area.
Given that,
pressure exerted by block (\(P_{B}\))= weight / cross-section area of block
\(P_{B}\) = (1 ×9.81) ÷ (10 × 10⁻⁴)
= 9810 Pa
Now, pressure at bottom of container is given as:
\(P_{Bottom}\) = \(P_{B}\) + ρ × g × h + ρ₁ × g × h₁
[ ρ = density of water,
ρ₁ = density of Hg,
h = height of water and
h₁ = height of Hg ]
Thus, 27000 = 9810 + (1000 × 9.81 × 0.25) + (13600 × 9.81 × h₁)
h₁ = 14737.5 ÷ 133416
h₁ = 0.1105 m
h₁ = 11.05 cm
Thus, depth of the mercury = 11.05 cm.
So, the depth of the mercury = 11.05 cm
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What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.
The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.
Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.
Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.
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Need help with this assignment please
Torque is a measure of the turning force applied to an object about a rotational axis. It is calculated as the product of the force applied to the object and the distance from the axis of rotation at which the force is applied.
How to explain the informationUse the equation slope = mod to calculate the unknown mass (mo) for parcels A and C, setting d = 1.0 m, and parcels G and H, setting d = 1.5 m.
Record all data, tables, and four graphs for analysis.
The experiment demonstrates the application of torque in determining unknown masses and provides valuable insights into the concept of torque in physics.
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Which best compares the temperatures of the substances?
O Substance X has the highest temperature because its particles have more kinetic energy.
O Substance X has the highest temperature because it has fewer particles.
O Substance Y has the highest temperature because its particles have more kinetic energy.
O Substance Y has the highest temperature because it has more particles.
The temperature of a substance is determined by the average kinetic energy of its particles, so Substance X and Substance Y have higher temperatures because their particles have more kinetic energy. The number of particles does not affect temperature. The correct options are (A) and (C).
The temperature of a substance is a measure of the average kinetic energy of its particles. When two substances are compared, the substance with the higher temperature has a higher average kinetic energy. The temperature of a substance is affected by the number of particles in it, as well as their kinetic energy. In general, if two substances have the same number of particles but different temperatures, the substance with the higher temperature has more kinetic energy. The options provided include two statements for each substance that describe why it has a higher temperature. Substance X has the highest temperature because its particles have more kinetic energy and Substance X has the highest temperature because it has fewer particles. Substance Y has the highest temperature because its particles have more kinetic energy and Substance Y has the highest temperature because it has more particles.Only one of these statements can be true. The first statement for each substance is correct. This is because the temperature of a substance is determined by the average kinetic energy of its particles. Substance X has a higher temperature because its particles have more kinetic energy. Similarly, Substance Y has a higher temperature because its particles have more kinetic energy. The number of particles in the substance does not affect its temperature.Therefore, option (A) Substance X has the highest temperature because its particles have more kinetic energy, and option (C) Substance Y has the highest temperature because its particles have more kinetic energy are the correct answers.For more questions on temperature
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A digital component defines an output voltage between 0 and 0.8V as a logic-0, and an output voltage between 2V and 5V as a logic. These voltages are its ___________/?
A digital component defines an output voltage between 0 and 0.8V as a logic-0 and an output voltage between 2V and 5V as logic. These voltages are its Logic Level.
For a signal to exist or to be considered a signal it should be at a certain logic level. Mostly used states are ON or OFF. An 'on' refers to a binary 1, and an 'off' refers to a binary 0 when expressed in binary. These signals are referred to as "high" or "low", respectively
Binary logic is used by digital devices to store, analyse, and transmit data and information. In binary logic, a condition is either "on" or "off".
The manufacturers mentions the logic level voltage of each device in the manual provided with it.
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A 2.8 kg block slides along a frictionless surface at 1.1 m/s . A second block, sliding at a faster 4.8 m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.3 m/s.
What was the mass of the second block?
Conservation of momentum is a major law of physics which states that the momentum of a system is constant if no external forces are acting on the system. It is embodied in Newton’s First Law or The Law of Inertia.the mass of the second block is 1.1Kg.
principle of momentum conservation
M1u1 plus M2u2 equals M1v1 and M2V2.
As all collisions were elastic in nature and no energy loss through friction, heat, etc. was taken into account, theoretic calculations alone cannot guarantee that there was a complete transfer of energy.
Consider the scenario where a football with mass M2 is lying on the ground and a bowling ball with mass M1 is hurled at the football at a velocity of
The formula is: (2.8 kg * 1.1 m/s) + (m2 * 4.8 m/s) = (2.3 kg + m2). 2.3 m/s
The formula is 2.8 J + (4.8 m/s m2) = 4.8 J + (2.3 m/s m2).
4.8 m/s m2 = 2.8 J plus (2.3 m/s m2)
4.8 m2 = 2.8 + 2.3 m2
2.3 m2 on each side of the equation
2.5 m = 2.8 m = 2.8 / 2.5\sm = 1.1kg
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