Hyperextension bends a joint in the opposite direction as flexion.

Answer:

C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.

Explanation:

The girl looks quite worried in the poster. Attached is the image:

Answer:

can u send pictures again it's unclear.

The temperature of the gas (in °C) at this pressure is 248.5 °C

Temperature is a bodily quantity that expresses the hotness of count or radiation. There are 3 kinds of temperature scales. Temperature is the degree of hotness or coldness of an item.

Temperature is a degree of the common kinetic energy of the debris in an object. whilst the temperature increases, the motion of those particles also increases. Temperature is measured with a thermometer or calorimeter.

Given;

P₁ = 1.2 x10⁵ Pa = 1.18430792

T₁ = 25.0°C = 298 K

P₂ = 2.1x10 Pa = 0.000207253886

T₂ = ?

using ideal gas equaion:-

PV = nRT

P₁/T₁ = P₂/T₂

T₂ = P₂T₁  /P₁

   = 2.1x10⁵ x  298 / 1.2 x10⁵

   = 521.5 K

   = 248.5 °C

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The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.

To find the electrical force, distance = 2 meters

charge q1 = 2×10⁻⁶ C

charge q2 = 4×10⁻⁶ C

         The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

Formula can be written as,

          F = K ( q1q2 / r² )

F - electric force

k - Coulomb constant

q1, q2 - charges

r - distance of separation

Substituting the values in the formula,

         F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C ×  4×10⁻⁶ C) / (2²))

            = 0.0179751

         F = 1.8 × 10 ⁻² N.

As both the charges q1 and q2 are positive, the charges gets repulsive.

SO, the correct answer is Option A.

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Answer:

potential lines that are perpendicular to the electric field, they must be parallel to the plates

Explanation:

A and C) for this drawing, as the electric field lines go from the positive plate to the negative plate and are horizontal to the potential lines that are perpendicular to the field, they must be parallel to the plates, see attached part a

B) in this case the ground has an energy of zero and the lines are parallel to the ground, see attached part b

ANSWER

C. The total (PE + KE) before an event is equal to the total (PE + KE) after the event.

EXPLANATION

We want to identify the correct option.

The law of conservation of energy is a law that applies only to closed systems and it states that:

In other words, energy cannot be created nor destroyed.

This implies that the total energy (sum of potential and kinetic energy) before an event occurs must be equal to the total energy after the event has occurred.

Therefore, the correct option is option C.

The net force on the balloon is zero, so it has no acceleration. So by Newton's first law, if the balloon has some velocity in a given direction, it will continue moving in that direction at a constant speed. If it's motionless, it stays motionless.

The volume density of atoms in a simple cubic crystal is 2.92 × 1021 atoms per cubic centimeter.

The lattice constant (a) of a simple cubic (SC) crystal is 0.7 nm. One atom is present at each lattice point. We have to compute the volume density of atoms (i.e. the number of atoms per unit volume) in terms of atoms per cubic centimeter.1 nm = 10-7 cm ⇒ 0.7 nm = 0.7 × 10-7 cm = 7 × 10-8 cm.

Volume of the unit cell of a SC crystal is given byV = a3= (0.7 × 10-7 cm)3= 3.43 × 10-22 cm3The unit cell has one atom, so the volume density of atoms is the same as the number of atoms per unit cell, which is1/ V = 1 / (3.43 × 10-22 cm3)= 2.92 × 1021 atoms per cubic centimeter.= 2.92 × 1023 atoms per cubic meter= 2.92 × 10-4 atoms per cubic angstrom.

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The force acting on the particle at t = 1 s is 24.4 N.

Mass of the particle, m = 2 units

Distance of the curve, r(t) = (4t²- t³)i - 5tj + (t⁴- 2)k

The velocity of the particle,

v = d[r(t)]/dt = (8t - 3t²)i - 5j + 4t³k

The acceleration of the particle,

a = d²[r(t)]/dt² = (8 - 6t)i + 12t²k

Let the time for which the force is acting be 1 second.

Therefore, acceleration at t = 1 is,

a₁ = 2i + 12k

Hence, the magnitude of acceleration,

|a₁| = √(2²+ 12²)

|a₁| = √148

|a₁| = 12.2 unit/s²

Therefore, the force acting on the particle at t = 1 s is,

F₁ = m x |a₁|

F₁ = 2 x 12.2

F₁ = 24.4 N

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Answer: gravity

Explanation: the moving and sifting around in the train

Answer:

11948.64 Newtons

Explanation:

Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

  t = 1.81 min ,     the correct answer is c

Explanation:

This is a missile throwing exercise

The object is thrown horizontally, so its vertical speed is zero (voy = 0), let's use the equation

             y = y₀ + \(v_{oy}\) t - ½ g t²

the final height is y = 0 and the initial height is y₀ = 22000 m

            0 = y₀ + 0 - ½ g t²

            t = √y 2y₀ / g

let's calculate

           t = √(2  22000 / 3.72)

           t = 108.76 s

let's reduce to minutes

           t = 108.76 s (1 min / 60 s)

           t = 1.81 min

The correct answer is c

Answer:

equilibrium because its equal force on the ball.

Explanation:

Answer:

good

Explanation:

How ??

Force:-

We know

According to newtons second law

\(\boxed{\sf Force=Mass\times Acceleration}\)

\(\\ \sf\longmapsto Force=kgm/s^2\)

We don't use it

\(\\ \sf\longmapsto Force=Newton(N)\)

Hence its a derived unit.

Pressure:-

\(\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\)

\(\\ \sf\longmapsto Pressure=\dfrac{N}{m^2}\)

\(\\ \sf\longmapsto Pressure=Pascal(Pa)\)

Hence its a derived unit

Given:

v = 30 m/s , t = 45 min=2700 s

V2= 25 m/s , t2=28 min= 1680 s

V3= 38 m/s , t3 = 15 min = 900 s

v4= 0m/s , t4= 20 min= 1200s

Calculate each distance

v= d/t

d= vt

d1 = v1 t1 = 30 x 2700 = 81,000 m

d2= 25 x 1680 = 42,000 m

d3= 38 x 900 = 34200 m

Total distance = d1+d2+d3= 81000+42000+34200 = 157,200 m

Average speed = total distance / time = 157,200 / (2700 +1680 + 900 +1200 ) = 24.26 m/s

Answers:

a . 24.26 m/s

b. 157200 m

Stone travels at the distance of 44.1 meters far did the stone drop before hitting water.

What is the distance ?

Distance is a numerical and sometimes qualitative measure of how far apart an object or point is. In physics or everyday use, distance can refer to estimates based on physical length or other criteria.

How can distance used in real life?

I am using it in my navigation. Airplane pilots use distance formulas to calculate the distance between their plane and other planes. Find the coordinates of the plane and then apply the distance formula to get the distance.

What is the use of distance?

(i) indicate body position at any point in time; (ii) You can see a graph of the distance your body has moved in a certain period of time. (iii) The object's velocity can be determined at any point in time.

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Answer:

An object is in motion if it changes position relative to a reference point.

Explanation:

Answer: Parallel

Explanation: Parallel because you don’t want all the lights to go out because of one light.

The electrical wiring and safety devices applied have to be perfect for non complainable circuit system  in houses. One thing have to ensure that all the electrical components needs to follow the requirements set by national electrical code.

Circuits are way for the passage of electrical current which consists of electrical wires and devices such as bulbs, fan etc. The circuit system have to be properly designed so that no overload or short circuit can be occured.

Proper thermal insulations for cables and wires have to be chosen. Moreover, all the electrical components should follow the standard requirements set by local bodies or national electrical code.

Safety devices such as circuit breaker or switches like fuse of standard quality must be applied to protect the devices. Circuit breakers are more better than fuses because they don't need replacements.

Similarly, the selection of wires of cables have to careful and need to check the quality of plastic sheaths on them.

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#1

The kinetic energy decreases

#2

This is because of law of conservation of linear momentum .

The momentum is conserved

So the velocity of ball decreases than before .

So kinetic energy also decreases

#3 and #4

Kinetic energy of the can increases as after the collision the velocity of the can increases so the kinetic energy also increases

The correct statement that describes a factor that leads to loess deposits is: C. The wind carries fine sediment.

Loess deposits are formed by the accumulation of wind-blown silt and clay-sized particles, which are deposited over large areas, often covering existing landforms. The fine particles are transported by the wind and eventually settle out of the air to form a layer of sediment. The size of the particles is important, as only fine particles can be transported long distances by the wind and deposited as loess. Plant roots may play a role in stabilizing the sediment, but they do not contribute to the formation of loess deposits.

Loess deposits are typically found in areas with a history of intense wind erosion and deposition, such as the Great Plains of North America, the steppes of Russia and Ukraine, and the Loess Plateau of China.

These deposits can be important archives of past environmental conditions, as they can contain a record of changes in climate, vegetation, and land use over long periods of time.

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Given that,

Mass of a water balloon, m = 1 kg

It comes downward an experience a 4.9 N air resistance as it approaches the ground.

To find,

The acceleration of the water balloon when it experiences this air resistance.

Solution,

Let the acceleration be a.

The net force acting on it will be :

\(F_{net}=mg+F_r\\\\=1\times 10+(-4.9)\\\\=5.1\ N\)

The force is also given by :

F  = ma

\(a=\dfrac{F}{m}\\\\a=\dfrac{5.1}{1}\\\\=5.1\ m/s^2\)

So, the acceleration of the water balloon is \(5.1\ m/s^2\).

The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².

Acceleration is the rate of change of velocity.

To calculate the acceleration of the ballon when it experiences the air resistance, we use the formula below.

Formula:

Where:

Make a the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².

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Answer:

459.6J

Explanation:

Given parameters:

Angle of pull  = 40°

Force applied  = 30N

Distance moved = 20m

Unknown:

Work done by Kraig  = ?

Solution:

To solve this problem;

   Work done  = F x dcosФ

d is the distance

F is the force

Ф is the angle given

  Work done  = 30 x 20cos40°   = 459.6J

Answer:

yez

Explanation:

Answer: The rock

Explanation:

Answer:

 ΔV = -2.1 L

Explanation:

To solve this exercise we can use the ideal gas equation for two points

         PV = nRT

          P₁V₁ = P₂ V₂

where point 1 is on the surface and point 2 is at the desired depth,

          V₂ = \(\frac{P_1}{P_2} \ V_1\)

let's calculate

           V₂ = ( \(\frac{1 atm}{2.5 atm}\) ) 3.5 L

            V₂ = 1.4 L

this is the new volume, the change in volume is

          ΔV = V₂ -V₁

          ΔV = 1.4-3.5

          ΔV = -2.1 L

The speed of the truck just before braking is 23.24 m/s.

The speed of the truck before braking is calculated by applying the third kinematic equation as shown below.

v² = u² - 2as

where;

When the truck stops, the final velocity = 0

0 = u² - 2as

u²  = 2as

u = √2as

u = √ ( 2 x 6 x 45 )

u = 23.24 m/s

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Answer:

Explanation:

We can use the kinematic equation v^2 = u^2 + 2as to solve for the length of the driveway. Here, u = 0 (since the car starts from rest), v = 3.8 m/s, a = F/m = 4.0 x 10^3 N / 2.1 x 10^3 kg = 1.9 m/s^2. Solving for s, we get:

s = (v^2 - u^2) / 2a = (3.8^2) / (2 x 1.9) = 3.8 m

So the length of the driveway is 3.8 meters.