Answer:
i think it's d
Explanation:
Newtons laws of motion
Answer:
Law 1. A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.
Law 2. A body acted upon by a force moves in such a manner that the time rate of change of momentum equals the force.
Law 3. If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction.
Which best describes a radio wave?
A. an electromagnetic wave at very long wavelength (low
frequency)
B. a pressure wave at very long wavelength (low frequency)
C. a pressure wave at very short wavele
Option A. An electromagnetic wave at very long wavelength (low frequency) best describes a radio wave.
A radio wave is best described as an electromagnetic wave at a very long wavelength or low frequency. It is not a pressure wave. Radio waves are a type of electromagnetic radiation, which also includes other forms such as visible light, infrared, and X-rays. The term "wavelength" refers to the distance between two consecutive points in a wave, such as from one crest to the next. In the case of radio waves, the wavelength is quite long, ranging from several millimeters to hundreds of meters. This long wavelength allows radio waves to travel long distances and pass through obstacles such as buildings and trees. Radio waves are used for various purposes, including communication, broadcasting, and radar systems. For example, when you listen to the radio, the sound is encoded onto a carrier wave, which is a specific radio wave frequency. The receiver then extracts the sound from the carrier wave, allowing you to hear it. Similarly, radar systems use radio waves to detect and track objects like airplanes or weather patterns. To summarize, a radio wave is an electromagnetic wave at a very long wavelength or low frequency. It is not a pressure wave. Radio waves are used for communication, broadcasting, and radar systems due to their ability to travel long distances and pass through obstacles. They play a crucial role in everyday life, allowing us to enjoy wireless communication and entertainment.
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A cup of tea with a temp. of 80°C is put on a table in a 20°C room. What happens to thermal energy and molecular motion of the tea when it is left on the table? *
Answer:
The thermal energy increases and the molecules move faster.
What are other ways you could try to build an arch?
10 POINTS HELP ME
Answer:
Apply glue to one side of a layer of arch (segments) and place the next player on top. Screw them together while the glue dries. Add glue the top of these two laminated arch layers and then add one more layer, screwing it afterwards. Repeat this to make as many arches as you need (or have wood for).
Explanation:
you are using a 50-mm-focal-length lens to photograph a tree. if you change to a 100-mm-focal-length lens and refocus, the image height on the detector changes by a factor of
The image height on the detector will change by a factor of 2 if you change from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocus.
The magnification of a lens is given by the ratio of the image height to the object height. Since the object height remains the same, the change in magnification is solely determined by the change in focal length.
The magnification of a lens is given by the formula:
Magnification = - (image distance / object distance).
Since we are only interested in the ratio of image heights, we can ignore the negative sign.
For the 50-mm lens, the magnification is:
Magnification1 = 50 mm / object distance.
For the 100-mm lens, the magnification is:
Magnification2 = 100 mm / object distance.
Taking the ratio of the two magnifications:
Magnification2 / Magnification1 = (100 mm / object distance) / (50 mm / object distance) = 100 mm / 50 mm = 2.
Therefore, the image height on the detector changes by a factor of 2 when switching from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocusing.
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in the photoelectric effect, photons with less than the threshold energy strike an emitter, and no electrons are emitted. what change or changes will cause electrons to be emitted?
The most likely causes of electrons being emitted in the photoelectric effect is an increase in the intensity of the light, a decrease in the threshold energy of the photons, or a change in the material of the emitter to one with a higher work function.
What is photoelectric effect?The photoelectric effect is a phenomenon in which electrons are emitted from a material when it is exposed to light. This is a result of the absorption of energy from photons, the particles that make up light. The photoelectric effect was first discovered in 1887 by Heinrich Hertz and was later explained by Albert Einstein in 1905. The effect has since been used in a variety of devices, such as photomultipliers and photodiodes, which are widely used in scientific experiments and everyday applications.
Intensity is a measure of the amount of energy present in the light, and increasing the intensity can result in a higher number of photons with enough energy to be emitted from the emitter. Decreasing the threshold energy of the photons means that photons with less energy can be emitted, which would result in electrons being emitted. Changing the material of the emitter to one with a higher work function means that photons with lower energy can be emitted, again resulting in electrons being emitted.
Overall, the changes that would cause electrons to be emitted in the photoelectric effect are increasing the intensity of the light, decreasing the threshold energy of the photons, or changing the material of the emitter to one with a higher work function.
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two ways that friction can be reduced
Answer:
One way is to polish the surface and the other way is to use oil or grease between the surfaces.
Explanation:
Hope this is right lol :)
The quantity of matter in an object. More specifically, it is the measure of the inertia that an object exhibits in response to any effort made to start it, stop it, or change in any way its state of motion
Answer:
Mass
Explanation:
The mass of an object expresses the amount of matter it comprises. Which implies that objects with higher mass contains higher matter compared to objects with lesser masses. Thereby it determines the measure of inertia experienced by an object when a force is applied to change its direction of motion, or to set it in motion when at rest, or bring it to rest when in motion.
The mass of an object the same no matter its location, and it is measured in kilograms.
Please help me on these questions. I’m very stuck.
Answer:
I can't see the pic so I cannot ans
What is the wavelength of the microwave?
The wavelength of the microwave, given that it is moving at a speed of 3.6×10⁸ m/s is 3 m (last option)
How do i determine the wavelength of the microwave?From the question given above, the following data were obtained:
Speed of microwave (v) = 3.6×10⁸ m/sFrequency of microwave (f) = 1.2×10⁸ HzWavelength of microwave (λ) = ?The wavelength of the microwave can be obtained as shown below:
Velocity (v) = wavelength (λ) × frequency (f)
3.6×10⁸ = wavelength × 1.2×10⁸
Divide both sides by 1.2×10⁸
Wavelength = 3.6×10⁸ / 1.2×10⁸
Wavelength = 3 m
Thus, from the above calculation, we can conclude that the wavelength of the microwave is 3 m (last option)
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An object has a kinetic energy of 90 J and a mass of 30 kg how fast is the object moving?
Answer:
The speed of the object will be "2.4 m/s".
Explanation:
The given values are:
Kinetic energy,
K.E = 90 J
Mass,
m = 30 kg
Speed,
v = ?
As we know,
⇒ \(K.E=\frac{1}{2} (mass\times speed^2)\)
On substituting the values, we get
⇒ \(90=\frac{1}{2} (30\times v^2)\)
⇒ \(90=15\times v^2\)
⇒ \(v^2=\frac{90}{15}\)
⇒ \(v^2=6\)
⇒ \(v=\sqrt{6}\)
⇒ \(v=2.44 \ m/s\)
An acetate rod is rubbed with a cloth.
Explain why the rod becomes positively charged
what would you do to increase resistance
Answer:
If this is electrical currents , make the wire longer, smaller diameter wires, heat it up
Why doesn’t an orbiting satellite fall back to earth?
A = (1 point) A particle is moving with acceleration a(t) = 6t + 8. its position at time t = O is s(0) = 6 and its velocity at time t = 0 is v(O) = 2. What is its position at time t = 7? =
Answer:
\(559\).
Explanation:
Integrate \(a(t)\) with respect to time \(t\) to find an expression for velocity:
\(\begin{aligned} v(t) &= \int a(t)\, d t \\ &= \int (6\, t + 8)\, d t && (\text{power rule}) \\ &= 3\, t^{2} + 8\, t + C_{v} \end{aligned}\).
Note that since this integral is indefinite, the expression for \(v(t)\) includes a constant \(C_{v}\).
Find the value of \(C_{v}\) using the fact that \(v(0) = 2\). Specifically, substitute \(t = 0\) into the expression \(v(t) = 3\, t^{2} + 8\, t + C_{v}\) and solve for \(C_{v}\!\):
\(v(0) = 3\, (0)^{2} + 8\, (0) + C_{v} = C_{v}\).
\(v(0) = 2\).
\(C_{v} = 2\).
In other words, \(v(t) = 3\, t^{2} + 8\, t + 2\).
Similarly, integrate \(v(t)\) with respect to \(t\) to find an expression for position:
\(\begin{aligned} s(t) &= \int v(t)\, d t \\ &= \int (3\, t^{2} + 8\, t + 2)\, d t\\ &= t^{3} + 4\, t^{2} + 2\, t + C_{s} \end{aligned}\).
Similarly, find the value of constant \(C_{s}\) using the fact that \(s(0) = 6\):
\(s(0) = (0)^{3} + 4\, (0)^{2} + 2\, (0) + C_{s} = C_{s}\).
\(s(0) = 6\).
\(C_{s} = 6\).
In other words, \(s(t) = t^{3} + 4\, t^{2} + 2\, t + 6\). Substitute in \(t = 7\) and evaluate to find the position of the particle at that moment:
\(s(7) = 7^{3} + 4\, (7)^{2} + 2\, (7) + 6 = 559\).
The pοsitiοn of the particle at time t = 7 is 559 units.
How tο find the pοsitiοn at time?Tο find the pοsitiοn at time t = 7, we need tο integrate the given acceleratiοn functiοn tο οbtain the velοcity functiοn and then integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn.
Given:
Acceleratiοn functiοn: a(t) = 6t + 8
Initial pοsitiοn: s(0) = 6
Initial velοcity: v(0) = 2
First, let's integrate the acceleratiοn functiοn tο οbtain the velοcity functiοn:
v(t) = ∫(a(t)) dt
= ∫(6t + 8) dt
= 3t^2 + 8t + C
Tο find the cοnstant οf integratiοn (C), we can use the initial velοcity v(0) = 2:
2 = 3(0)² + 8(0) + C
C = 2
Sο, the velοcity functiοn becοmes:
v(t) = 3t² + 8t + 2
Next, let's integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn:
s(t) = ∫(v(t)) dt
= ∫(3t² + 8t + 2) dt
= t³ + 4t² + 2t + C'
Tο find the cοnstant οf integratiοn (C'), we can use the initial pοsitiοn s(0) = 6:
6 = (0)³ + 4(0)² + 2(0) + C'
C' = 6
Sο, the pοsitiοn functiοn becοmes:
s(t) = t³ + 4t² + 2t + 6
Finally, we can find the pοsitiοn at time t = 7:
s(7) = (7)³+ 4(7)² + 2(7) + 6
= 343 + 196 + 14 + 6
= 559
Therefοre, the pοsitiοn at time t = 7 is 559 units.
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the red giants and supergiants are only a tiny fraction of all known stars. why then do the giant stars account for most of the brightest stars we can see in the sky?
The reason for the red giants and supergiant stars being the brightest stars in the sky is their large radius and mass leads to high temperature.
The red giant and supergiant stars, are stars with a relatively large radius relative to their mass and temperature. The brightness of such stars is high since the radiating surface is correspondingly large. A subclass of giant stars are supergiants that have larger radii and luminosities for mass and temperature. A very bright red giant with a low temperature. The subgiant has a slightly reduced radius and brightness.
There are giants that are hundreds of thousands of times brighter than the sun. Their position on the Hertzsprung-Russell diagram is above the main sequence, where most stars fall as opposed to dwarfs. Giants and supergiants can have masses 10 to 30 times that of the Sun, but their volumes are often 1 million to 10 million times that of the Sun. They are, therefore "diffuse" low-density stars.
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a small aircraft has a wing area of 35 m2, a lift coefficient of 0.45 at takeoff settings, and a total mass of 4000 kg. determine (a) the takeoff speed of this aircraft at sea level at standard atmospheric conditions, (b) the wing loading, and (c) the required power to maintain a constant cruising speed of 300 km/h for a cruising drag coefficient of 0.035.
The takeoff speed of the aircraft is approximately 41.6 m/s.
The wing loading of the aircraft is approximately 1128.6 N/m².
The required power to maintain a constant cruising speed of 300 km/h is approximately 173791.5 W.
How to calculate the value1. Lift = Weight
1/2 * density * velocity² * wing area * lift coefficient = mass * gravity
1/2 * 1.225 * velocity² * 35 * 0.45 = 4000 * 9.81
Simplifying and solving for velocity, we get:
velocity = ✓((4000 * 9.81 * 2) / (1.225 * 35 * 0.45)) = 41.6 m/s
(b) Wing loading = Weight / wing area
Wing loading = 4000 * 9.81 / 35 = 1128.6 N/m²
Therefore, the wing loading of the aircraft is approximately 1128.6 N/m²
(c) Drag = 1/2 * density * velocity² × wing area * drag coefficient
Substituting the given values, we get:
Drag = 1/2 * 1.225 * (300/3.6)² * 35 * 0.035 = 2085.5 N
Power = force * velocity
Power = 2085.5 * 83.33 = 173791.5 W
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A kid drives 4 miles to the mall. If the speed limit is 45 miles/hr and the kid makes the trip in .03 hours. Is the kid breaking the speed limit? a. No, he is going 1 mile/hr. b. Yes, he is going 133 miles/hr, C. No, he is going 40 miles/hr. d. Yes, he is going 150 miles/hr.
Answer:B
Explanation:
.03 of an hr is 2 mins and if it takes 2 mins to drive 4 miles enter it in pace calulator you are going 120mph so the closest to 120 is 133mph
The kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
Speed is the ratio of distance travelled to time taken. It is given by:
Speed = distance / time
Since the distance to the mall is 4 miles, the time taken is 0.03 hours, hence the speed is:
Speed = distance / time
Speed = 4 miles / 0.03 hours
Speed = 133.3 miles/hr
Hence the kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
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Andrea, whose mass is 48kg, thinks she's sitting at rest in her 5. 0m-long dorm room as she does her physics homework. Within what range is her velocity likely to be?
For Andrea, whose mass is 48kg, thinks she's sitting at rest in her 5. 0m-long, her range is mathematically given as
dv=1.95*10^{-37}ms^{-1}
Within what range is her velocity likely to be?Generally, the equation for the uncertainty principle is mathematically given as
mdxsv=h/2
Therefore
dv=h/(2mdx)
dv=1.054*10^{-39}/2*45*6
dv=1.95*10^{-37}ms^{-1}
In conclusion, range of her velocity
dv=1.95*10^{-37}ms^{-1}
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How can global warming lead to changes to the Earth’s surface?
a.
Global warming can lead to an increased number of earthquakes, which change the Earth’s surface.
b.
Global warming can lead to glaciers melting, causing flooding to areas and the decrease of glacial land masses.
c.
Global warming leads to a decrease in water levels of coastal wetlands.
d.
Global warming cannot lead to changes to the Earth’s surface.
Please select the best answer from the choices provided
A
B
C
D
Answer:
A
Explanation:
But global warming will have additional, far-reaching effects on the planet. Warming modifies rainfall patterns, amplifies coastal erosion, lengthens the growing season in some regions, melts ice caps and glaciers, and alters the ranges of some infectious diseases.
Answer:
I think it is B since Global warming can lead to glaciers melting and cause flooding since the water will get warmer resulting in the ocean rising, which causes flooding
Explanation:
When making a lane change on the Interstate, you should always
Answer: When you change lanes, follow these steps:
Turn on your signal.
Check your mirrors.
Check your blind spot by looking over your shoulder.
If it is safe, change lanes.
Turn off your signal after completing the lane change.
Explanation: urwellcome
Answer:
Turn on your turn signal, and check for cars behind and in front of you.
Explanation:
It is important to check for cars because you may crash and injure/die. So stay safe!
PLEASE HELP!!
Suppose an ostrich runs 1.5 km at a speed of 58 km/h and then runs another 1.5 km at a speed of 29 km/h. What is the ostrich’s average speed during the 3.0 km run? (Hint: find the total time first by finding the time of each 1.5 km segment)
The ostrich's average speed during the 3.0 km run is approximately 38.65 km/h.
The average speed of the ostrich during the entire 3.0 km run, we need to calculate the total time taken for both segments and then divide the total distance by the total time.
Calculate the time for each segment:
Time taken for the first 1.5 km segment at 58 km/h:
Time = Distance / Speed
= 1.5 km / 58 km/h
≈ 0.02586 hours
Time taken for the second 1.5 km segment at 29 km/h:
Time = Distance / Speed
= 1.5 km / 29 km/h
≈ 0.05172 hours
Calculate the total time:
Total Time = Time for the first segment + Time for the second segment
Total Time ≈ 0.02586 hours + 0.05172 hours
≈ 0.07758 hours
Calculate the average speed:
Average Speed = Total Distance / Total Time
Average Speed = 3.0 km / 0.07758 hours
≈ 38.65 km/h
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Newton discovered measurable, mathematical patterns in the phenomenon of color. He found _____ light to be a mixture of infinitely varied colored rays.
Newton discovered measurable, mathematical patterns in the phenomenon of color. Newton found white light to be a mixture of infinitely varied colored rays.
Sir Isaac Newton conducted various experiments with light and discovered that white light is composed of a combination of different colored rays. He used a prism to separate white light into its constituent colors and observed a continuous spectrum of colors, ranging from red to violet.
When white light passes through a prism, it undergoes a process called dispersion. The prism refracts the different wavelengths of light by different amounts, causing them to spread out and form a spectrum. This experiment demonstrated that white light is not a single color but rather a mixture of different colors with varying wavelengths.
Newton's findings led to the development of the concept of the visible spectrum, which represents the range of colors that can be observed by the human eye. This spectrum includes colors such as red, orange, yellow, green, blue, indigo, and violet. Each color corresponds to a specific range of wavelengths within the electromagnetic spectrum.
Therefore, Newton discovered that white light is a combination of infinitely varied colored rays, each with its own specific wavelength and corresponding color.
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To take off from an aircraft carrier, a 21000 kg jet needs to accelerate at 36.9 m/s^2. How much force is required? (unit = N)
The force required for the jet to take off from an aircraft carrier is 773,490 N (Newton).
To calculate the force required for the jet to take off from the aircraft carrier, you can use Newton's second law of motion, which is:
Force (F) = Mass (m) × Acceleration
(a) Given the mass (m) of the jet as 21,000 kg and the acceleration
To calculate the force required for the 21000 kg jet to accelerate at 36.9 m/s^2, we need to use Newton's second law of motion which states that force (F) is equal to mass (m) multiplied by acceleration (a).
So,
F = m x a
F = 21000 kg x 36.9 m/s^2
F = 773,490 N
∴ force required = 773,490 N
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A 1.50-kg mass is acted upon by a force of 16.0 N applied at an angle of 60o above the horizontal. What is the acceleration of the mass? Group of answer choices 4.33 m/s2 5.33 m/s2 6.33 m/s2 7.35 m/s2
If a 1.50-kg mass is acted upon by a force of 16.0 N applied at an angle of 60° above the horizontal. The acceleration of the mass is approximately 5.33 m/s². Therefore, the correct option is (B) 5.33 m/s².
The given force applied at an angle of 60° is 16 N. The mass of the object is 1.50 kg. We need to calculate the acceleration of the mass. The force is resolved into two components. One component is parallel to the surface and another one is perpendicular to the surface.
We can calculate the parallel and perpendicular components as:
F⊥= F sin θ = 16 sin 60° = 13.86 N.
F|| = F cos θ = 16 cos 60° = 8 N.
Here, F⊥ is the perpendicular force and F|| is the parallel force. So, the perpendicular force acting on the mass is 13.86 N and the parallel force acting on the mass is 8 N. Now we can calculate the acceleration of the mass as:
Net force acting on the object, F = F|| = 8 N. Using Newton's second law of motion, we have:
ma = F ⇒ a = F/m.
Using this value of F and m, we get the acceleration as a = 8 N/1.50 kg ≈ 5.33 m/s². Hence, B is the correct option.
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Which of the following actions are minimally necessary to determine if a motion detector should be calibrated before using it to investigate the motion of an object? Note: Even if you did not use a motion detector in to carry out this experiment, consider the information in the reading when responding to this question.
The following actions are minimally necessary to determine if a motion detector should be calibrated before using it to investigate the motion of an object is option C which is both of this action are required.
What is motion detector?Motion detector is a mechanical device that have sensor and it is use to detect the movements of people or objects in a place. It is use by security organizations to detect illegal movements and the sensors send alert to the system if there is any strange thing.
Therefore, The following actions are minimally necessary to determine if a motion detector should be calibrated before using it to investigate the motion of an object is option C which is both of this action are required.
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consider the first image shown in the video, which is the hubble extreme deep field. which of the following statements about this image are true?
The true statements about the Hubble Extreme Deep Field image are:
Careful study of the image shows that the youngest galaxies were mostly irregular in shape.We see the more distant galaxies as they were when they were quite young.The image includes galaxies that are elliptical, spiral, and irregular.The Hubble Extreme Deep Field image is a testament to the immense scale and diversity of our universe. By capturing thousands of galaxies at various stages of development, the XDF allows astronomers to study the intricate processes of galaxy formation and evolution, ultimately enhancing our understanding of the cosmos.
The Hubble Extreme Deep Field (XDF) image is a remarkable snapshot of our universe, showcasing the farthest and most diverse celestial objects. This image contains approximately 5,500 galaxies, with some dating back to just 450 million years after the Big Bang. The XDF is a combination of observations taken by the Hubble Space Telescope over a period of ten years, focusing on a small region of the sky.
The XDF's depth and clarity reveal a wealth of information about the galaxies present in the image. Observing galaxies at different stages of development helps astronomers understand the processes involved in galaxy formation and evolution. The image contains a mix of spiral, elliptical, and irregular galaxies, each with their unique characteristics and histories.
Furthermore, the XDF highlights the vast scale of the universe, as many of the galaxies captured in this image are billions of light-years away from Earth. This vast distance means that the light we see from these galaxies started its journey billions of years ago, providing us with a glimpse into the universe's distant past.
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Complete Question:
Consider the first image shown in the video, which is the Hubble Extreme Deep Field. Which of the following statements about this image are true? Select all the true statements. The galaxies in this image are part of a large galaxy cluster, bound together by gravity. Careful study of the image shows that the youngest galaxies were mostly irregular in shape. We see the more distant galaxies as they were when they were quite young. ООО Careful study of the image shows that all present-day galaxies are spirals. The image includes galaxies that are elliptical, spiral, and irregular.
A loop of wire is in the shape of two concentric semicircles as shown. (Figure 1) The inner circle has radius a; the outer circle has radius b. A current I flows clockwise through the outer wire and counterclockwise through the inner wire. Part A What is the magnitude, B, of the magnetic field at the center of the semicircles? Express B in terms of any or all of the following: I, a, b, and mu_0.
Answer:
vote me brainliest
Explanation:
The magnitude B of the magnetic field at the center of the semicircles is given by these expression B = (μ₀(I(outer) - I(inner)))/(π(a + b)). The B in terms of the asked variable.
In this case, we have two concentric semicircles, each carrying current in opposite directions. Let's consider a circular loop with radius r, where a < r < b. The magnetic field at the center of this loop will be the sum of the magnetic fields produced by the two semicircles.
For the outer semicircle (radius b), the magnetic field at the center can be calculated as follows:
∮ B · dl = μ₀I(outer)
For the inner semicircle (radius a), the magnetic field at the center has the opposite direction, so the equation becomes:
∮ B · dl = -μ₀I(inner)
Since the circular loop with radius r contains both the inner and outer semicircles, we can add these equations together:
∮ B · dl = μ₀(I(outer) - I(inner))
The line integral ∮ dl represents the circumference of the circular loop, which is 2πr:
B(2πr) = μ₀(I(outer) - I(inner))
B = (μ₀(I(outer) - I(inner)))/(2πr)
In this case, as we are interested in the magnetic field at the center of the semicircles, the radius r would be the average radius between a and b, given by:
r = (a + b)/2
Substituting this value into the equation, we get the final expression for the magnitude B of the magnetic field at the center of the semicircles:
B = (μ₀(I(outer) - I(inner)))/(2π((a + b)/2))
B = (μ₀(I(outer) - I(inner)))/(π(a + b))
Therefore, the magnitude B of the magnetic field at the center of the semicircles is given by B = (μ₀(I(outer) - I(inner)))/(π(a + b)).
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Electric room heaters use a concave mirror to reflect infrared (IR) radiation from hot coils. Note that IR follows the same law of reflection as visible light.
A) Find the magnification of the heater element, given that the mirror has a radius of curvature of 54 cm and produces an image of the coils 3.5 m away from the mirror.
The magnification of the heater element is 11.96.
To find the magnification of the heater element, we'll use the mirror formula and the magnification formula.
1. The mirror formula is 1/f = 1/u + 1/v
where f is the focal length, u is the object distance, and v is the image distance.
2. The magnification formula is: M = -v/u
where M is the magnification, v is the image distance, and u is the object distance.
1: Find the focal length (f)
Since the radius of curvature is given (R = 54 cm), we can find the focal length using the formula: f = R/2
f = 54 cm / 2
f = 27 cm
2: Use the mirror formula to find the object distance (u)
Given that the image distance (v) is 3.5 m away, convert it to cm: v = 350 cm
Now, plug the values into the mirror formula:
1/27 = 1/u + 1/350
3: Solve for u
1/u = 1/27 - 1/350
u = 1 / (1/27 - 1/350)
u 29.25 cm
4: Calculate the magnification (M)
Now, we can use the magnification formula with the values of u and v:
M = -v/u
M = -350/29.25
M = -11.96
The magnification of the heater element is approximately -11.96. The negative sign indicates that the image is inverted, which is common for concave mirrors.
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A ball is thrown horizontally from the top of a building at 2 m/s. It takes 3 seconds to reach the ground. How far did the ball travel horizontally (dx)?