Answer:
-5 because of I'm right I am always right
[3 x (8-2)] + 5 PEMDAS
Answer:
23
Step-by-step explanation:
8-2=6
6×3=18
18+5=23
Answer: 23
Step-by-step explanation:
Points R, S, and T are collinear, and S is between R and T. Find ST if RS = 6.4in and RT = 9.3 in.
Answer:
Step-by-step explanation:
The layout looks like this.
r-----------s-----------------t
6.4
----------------9.3-----------
Now you want st so the formula is
rt = rs + st
9.3 = 6.4 + st Subtract 6.4 from both sides
9.3 - 6.4 = st Combine
st = 2.9
recently, the top web browser had 51.04% of the market. in a random sample of 300 people, what is the probability that fewer than 135 did not use the top web browser? round the final answer to at least 4 decimal places and intermediate z-value calculations to 2 decimal places.
The probability that fewer than 135 did not use the top web browser is 0.0885 (rounded to four decimal places).
Given that the top web browser had 51.04% of the market.
Representing the probability of using top web browser P(T) = 0.5104
Probability of not using the top web browser is P(N) = 1 - 0.5104 = 0.4896
The sample size is n = 300 people.
We need to find the probability that fewer than 135 people did not use the top web browser.
Therefore, the required probability is given by;
P(X < 135)
Where X is the number of people who did not use the top web browser.
The number of people who did not use the top web browser follows a binomial distribution with parameters n = 300 and p = 0.4896.
The mean of the distribution is given by;
Mean = np= 300 × 0.4896 = 146.88
The variance of the distribution is given by;
Variance = np(1 - p)= 300 × 0.4896 × 0.5104 = 74.8473
The standard deviation of the distribution is;
Standard deviation = √variance= √74.8473= 8.6485z = (X - μ) / σ
Where μ is the mean and σ is the standard deviation of the distribution
Substitute the mean and standard deviation of the distribution; z = (X - μ) / σ = (135 - 146.88) / 8.6485= -1.3542
Using a standard normal distribution table, find the probability that Z < -1.3542P(Z < -1.3542) = 0.0885
The probability that fewer than 135 did not use the top web browser is 0.0885 (rounded to four decimal places).
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HELP ASAP!!!20pts
1/3x=−20
WHAT IS X?
Answer:
x = -60
Step-by-step explanation:
1/3x=−20
X is 1/3
X times 3 = a full X
Fill it in
X times -20 = -60
Hope this helps :)
Question 7 of 25
URGENT! PLEASE ANSWER
Which of these changes
produces a chemical change?
A. A large rock is crushed into gravel.
B. Lava cools and changes from a thick fluid to solid rock.
C. A stone fizzes and forms a gas when acid is dropped on it.
D. Limestone slowly dissolves in water and forms a cave.
Answer:
Answer is C.
Step-by-step explanation:
it changes the CHEMICAL composition of it
The coordinates of the vertices of a triangle are A(-6,-3), B(-5,2), C(-2,-2). If the coordinates are changed to A' (6,-3), B(5,2). C'(2,-2), what transformation was
Performed?
Answer:
a
Step-by-step explanation:
jefioweodke = f0eoddjeoe -2fkoforkg f = A
discouraging consumers from purchasing products from an insurer is called
Discouraging consumers from purchasing products from an insurer is referred to as "consumer dissuasion." It involves implementing strategies or tactics to dissuade potential customers from choosing a particular insurance company or its products.
Consumer dissuasion is a practice employed by insurers to discourage consumers from selecting their products or services. This strategy is often used to manage risk by discouraging individuals or groups that insurers perceive as having a higher likelihood of filing claims or incurring higher costs. Insurers may employ various techniques to dissuade potential customers, such as setting higher premiums, imposing strict eligibility criteria, or offering limited coverage options. The purpose of consumer dissuasion is to selectively attract customers who are deemed less risky or more profitable for the insurer, thereby ensuring a healthier portfolio and reducing potential losses. By implementing strategies that discourage certain segments of the market, insurers can manage their risk exposure and maintain profitability. It is important to note that consumer dissuasion practices should adhere to applicable laws and regulations governing the insurance industry, including fair and transparent practices. Insurers are expected to provide clear and accurate information to consumers, enabling them to make informed decisions about insurance coverage and products.
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if b = 0.54, My = 3.35, and Mx = 5.85, then what is the value of the y-intercept for the best fitting regression line?
O 0.19
4.07
10.27
-18.47
The value of the y-intercept for the best fitting regression line is approximately 2.9236. Based on the available options, none of them match the calculated value.
To determine the y-intercept of the best fitting regression line, we need to use the formula for the equation of a straight line, which is given by:
y = mx + b
where y represents the dependent variable, x represents the independent variable, m represents the slope of the line, and b represents the y-intercept.
In this case, we are given that b = 0.54, My = 3.35, and Mx = 5.85. The values My and Mx represent the means of the dependent and independent variables, respectively.
The slope of the best fitting regression line (m) can be calculated using the formula:
m = (My - b * Mx) / (Mx - b * Mx)
Substituting the given values, we have:
m = (3.35 - 0.54 * 5.85) / (5.85 - 0.54 * 5.85)
= (3.35 - 3.159) / (5.85 - 3.1719)
= 0.191 / 2.6781
≈ 0.0713
Now that we have the value of the slope (m), we can substitute it back into the equation of a straight line to find the y-intercept (b).
y = mx + b
Using the given values, we have:
3.35 = 0.0713 * 5.85 + b
Simplifying the equation:
3.35 = 0.4264 + b
Subtracting 0.4264 from both sides:
b = 3.35 - 0.4264
≈ 2.9236
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When a number is subtracted from x the result is 6. What is that number?
a.)6 - x
b.)x - 6
c.)6 + x
d.)6 - ( x - 6)
Matt's saving account balance went from $325 at the beginning of the month to $195 at the end of the month. What was the percent of decrease?
Answer:
60%
Step-by-step explanation:
yes
suppose albers elementary school has 39 teachers and bothel elementary school has 84 teachers. if the total number of teachers at albers and bothel combined is 104, how many teachers teach at both schools?
The number of teachers who teach at both Albers Elementary School and Bothel Elementary School is 19.
Let's assume the number of teachers who teach at both schools is 'x'. According to the given information, Albers Elementary School has 39 teachers and Bothel Elementary School has 84 teachers. The total number of teachers at both schools combined is 104.
We can set up an equation to solve for 'x'. The sum of the number of teachers at Albers and Bothel should be equal to the total number of teachers: 39 + 84 - x = 104. Simplifying the equation, we get 123 - x = 104. By subtracting 123 from both sides, we find -x = -19. Multiplying both sides by -1 gives us x = 19.
Therefore, the number of teachers who teach at both Albers Elementary School and Bothel Elementary School is 19.
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11 points Please answer quick.
Divide (x^5 - x^4 + x^3 - x^2 + x -1) by (x-1)
show your calculation
If you don't know don't answer.
If you do it I will report the answer.
Answer:
\(\boxed{x^4 + x^2 + x}\)
Step-by-step explanation:
\(\frac{x^5 - x^4 + x^3 -x^2 + x - 1}{x - 1}\)
\(= \frac{(x - 1)(x^4 + x^2 + x)}{x - 1}\)
\(= x^4 + x^2 + x\)
.
Happy to help :)
Find the area of a garden with a length of 3 1/2 yards and a width of 2 2/3 yards
Answer:
2.33 yards
Step-by-step explanation:
3 1/2-3.5
2/3-0.66
0.66 x 3.5 = n
PLS HELP WILL MARK BRAINLIEST, PLS HURRY
Answer:
b) I think. sorry if its wrong.
Step-by-step explanation:
Solve the following maximisation problem by applying the Kuhn-Tucker theorem: Max xy subject to –4x^2 – 2xy – 4y^2 x + 2y ≤ 2 2x - y ≤ -1
By applying the Kuhn-Tucker theorem, the maximum value of xy is: 18/25
The constraints are:-4x² - 2xy - 4y²x + 2y ≤ 22x - y ≤ -1
Let us solve this problem by applying the Kuhn-Tucker theorem.
Let us first write down the Lagrangian function:
L = xy + λ₁(-4x² - 2xy - 4y²x + 2y - 2) + λ₂(2x - y + 1)
Then, we find the first order conditions for a maximum:
Lx = y - 8λ₁x - 2λ₁y + 2λ₂ = 0
Ly = x - 8λ₁y - 2λ₁x = 0
Lλ₁ = -4x² - 2xy - 4y²x + 2y - 2 = 0
Lλ₂ = 2x - y + 1 = 0
The complementary slackness conditions are:
λ₁(-4x² - 2xy - 4y²x + 2y - 2) = 0
λ₂(2x - y + 1) = 0
Now, we solve for the above equations one by one:
From equation (3), we can write 2x - y + 1 = 0, which implies:y = 2x + 1
Substitute this in equation (1), we get:
8λ₁x + 2λ₁(2x + 1) - 2λ₂ - x = 0
Simplifying, we get:
10λ₁x + 2λ₁ - 2λ₂ = 0 ... (4)
From equation (2), we can write x = 8λ₁y + 2λ₁x
Substitute this in equation (1), we get:
8λ₁(8λ₁y + 2λ₁x)y + 2λ₁y - 2λ₂ - 8λ₁y - 2λ₁x = 0
Simplifying, we get:
-64λ₁²y² + (16λ₁² - 10λ₁)y - 2λ₂ = 0 ... (5)
Solving equations (4) and (5) for λ₁ and λ₂, we get:
λ₁ = 1/20 and λ₂ = 9/100
Then, substituting these values in the first order conditions, we get:
x = 2/5 and y = 9/5
Therefore, the maximum value of xy is:
2/5 x 9/5 = 18/25
Hence, the required answer is 18/25.
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1. If f(x) = (3x-2)/(2x+3), then f'(x) =
Answer:
\(f'(x)= \frac{13}{(2x+3)^2}\\\)
Step-by-step explanation:
\(f(x)= \frac{3x-2}{2x+3} \\\)
\(f'(x)=\frac{dy}{dx} = \frac{d}{dx}(\frac{3x-2}{2x+3})\\ f'(x)= \frac{(2x+3)\frac{d}{dx}(3x-2)-(3x-2)\frac{d}{dx}(2x+3) }{(2x+3)^{2} } \\f'(x)= \frac{(2x+3)(3)-(3x-2)(2)}{(2x+3)^{2} } \\\)
\(f'(x)= \frac{6x+9-6x+4}{(2x+3)^{2} }\\ f'(x)= \frac{13}{(2x+3)^2}\\\)
Remote Assignment 1-5 Score: 37/100 3/8 answered Progress saved Done Question 4 < > B0/13 pts 10 A BX bisects ZABC. If m ZABC = 9 x + 18 and mZCBX = 5 x + 7, find the value of mZABX. Submit Question
When a ray bisects an angle, it divides said angle in half. This means that the two new created angles will have the same measurement and when added they should be equal to the larger one. With this in mind we can find mABX as shown below:
\(\begin{gathered} \measuredangle ABC=\measuredangle ABX+\measuredangle CBX \\ \measuredangle ABX=\measuredangle ABC-\measuredangle CBX \end{gathered}\)We were given the values for mABC and mCBX, so we use those in the expression above and solve for the value of mABX. We have:
\(\begin{gathered} \measuredangle ABX=9x+18-(5x+7) \\ \measuredangle ABX=9x-5x+18-7 \\ \measuredangle ABX=4x+11 \end{gathered}\)The value of mABX is "4x + 11".
Are lines L1 and L2 perpendicular??
How do I explain and justify it ?
Please help me
Answer:
No.
Step-by-step explanation:
Perpendicular in the dictionary means: at an angle of 90° to a given line, plane, or surface. Those lines do not create a square angle, as the points of the lines do not match up, so it will not create a right angle. (90°)
Hall is making fasnachts to sell on Tuesday before Ash wednesday, his bakery's biggest fasnachts day of the calendar year. He has 9 pounds of butter and the recipe calls for 3/4 cups of butter per 1.5 frozen fasnachts. If 1 pound of butter is two cups, then how many individual fasnachts will Hall be able to make?
Based on the number of pounds of butter that Hall has and the number of cups needed per fasnachts, the number of fasnachts Hall will be able to make is 36 fasnachts
How to find out the number to be made?First, find out the number of cups of butter than Hall has:
= 9 pounds x 2 cups per pound
= 18 cups
Then, find out the number of 3/4 cups in this amount of butter:
= 18 cups / 3/4
= 18 x 4/3
= 24 cups
The number of fasnachts that Hall can make are:
= 24 x 1.5 frozen fasnachts per cup
= 36 fasnachts
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PLZZZZZZZZZZZZZ HELP IM TIMED!!!!!!!!!!!!!!
which scatter plot is incorrect and what is wrong with it
ill give 50 points
Answer:
is there any more information
A wildlife manager determines that there are approximately 800 deer in a state park. The population is decreasing at a rate of 5% each year. How many deer would you expect to live in the park after 5 years? Round to the nearest whole
Step-by-step explanation:
5 % decrease means 95 % (.95) remain
Year 1
800 * .95
year 2 800 * .95 * .95
.
.
year 5 = 800(.95)^5 = 619 deer after year 5
List the first four perfect squares. Next, list the first four perfect cubes. Following that same pattern find a number that is a perfect square and also a perfect cube other than the number 1. Explain how you found your answer.
We can list the first four perfect squares:
\(1^2=1,2^2=4,3^2=9,4^2=16\)We can following the same pattern to find the rest of the square and compare them to those that are a perfect cube:
\(5^2=25,6^2=36,7^2=49,8^2=64,9^2=81,10^2=100\)Then, we have
\(1^3=1,2^3=8,3^3=27,4^3=64,5^3=125^{}\)We can see from the two lists:
Perfect squares: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100....
Perfect cubes: 1, 8, 27, 64, 125....
Comparing these two lists, we have that the number 64 is, at the same time, a perfect square and a perfect cube.
Then, to find the answer, we need to make two lists, first, raising the natural numbers to the second power, and then, to the third power, and compare when we get a number is a perfect square and a perfect cube (the other apart from 1).
Please help, I’ll mark as brainliest
Perimeter:
2L + 2W = 380
2L = 380 - 2W
C(W) = (2W x 9) + ((380-2W) x 8)
\(\tt C(W)=18W-16W+3040=2W+3040\)
Given f(x)=3x-1, solve for x when f(x)=-7.
Answer:
x = -2
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Algebra I
Function NotationStep-by-step explanation:
Step 1: Define
f(x) = 3x - 1
f(x) = -7
Step 2: Solve for x
Substitute: -7 = 3x - 1Isolate x term: -6 = 3xIsolate x: -2 = xRewrite: x = -2planned expenditures in the most basic model are equal to
The planned expenditures in the most basic model are equal to the total expenses projected for a specific period of time, typically calculated on a monthly or annual basis.
To determine the planned expenditures in the most basic model, you need to consider all the expenses that will be incurred during the designated period. This includes both fixed and variable costs. Fixed costs are expenses that remain constant regardless of production or sales volume, such as rent, insurance, and salaries. Variable costs, on the other hand, fluctuate based on production or sales levels, such as raw materials, utilities, and commissions.
To calculate the planned expenditures, you should list all the expenses and their corresponding amounts. Add up the fixed costs for the period and estimate the variable costs based on expected production or sales levels. Summing these figures will give you the total planned expenditures.
The planned expenditures represent the estimated total expenses for a specific period. By accurately forecasting and tracking these expenditures, individuals and businesses can effectively manage their finances and make informed decisions regarding budgeting, investments, and cost control.
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explain how and solve please asap !
Answer:
x=14
y=41
x+y= 55
Step-by-step explanation:
Since a and b are parallel you know that 123° and 3y are the same degree, so 123 divided by 3 because its 3×y= 41 so y=41
the line123° and 4x+1 are on has to equal 180 because its a straight line, 180-123= 57. 57- 1 because its not with the x= 56. 56÷4 because its 4×x/its with the x= 14. Hope thsi helps :)
IVIIxed N
Douglas was planting grape vines. He completed 2-
rows of
grapes
each hour he worked. After completing 140 rows of grapes, how many
hours had he worked?
0000
48 hours
50 hours
52 hours
60 hours
Answer: He completes 2 4/5 rows per hour
if he completed 140 rows, how many hours did it take?
We should divide the work completed by the amount of work done per hour.
So, 140/(2 4/5) =
2 4/5 is equivalent to 2.8
so 140/2.8 = 50 hours
Step-by-step explanation:
I buy
packet of bread rolls costing £1.50 for each packet
2 bottle of ketchup costing £1.60 for each bottle
3 packets of sausages
I pay with a £10 note.
I get 50p change.
How much does 1 packet of sausages cost?
Step-by-step explanation:
are you having problems with something if so message
find a matrix p such that ptap orthogonally diagonalizes a. verify that ptap gives the proper diagonal form. (enter each matrix in the form [[row 1], [row 2], ...], where each row is a comma-separated list.)
To orthogonally diagonalize a matrix A, we need to find a matrix P such that P^T * A * P is a diagonal matrix. Here's how you can find such a matrix P:
1. Find the eigenvalues of A.
2. For each eigenvalue, find its corresponding eigenvector.
3. Form a matrix P by arranging the eigenvectors as columns.
4. Verify that P^T * A * P is a diagonal matrix.
Let's go through the steps to find the matrix P for a given matrix A.
1. Find the eigenvalues of A:
Let's assume A is the matrix provided.
A = [[a, b],
[c, d]]
To find the eigenvalues, we solve the characteristic equation:
|A - λI| = 0, where λ is the eigenvalue and I is the identity matrix.
|A - λI| = |[[a, b],
[c, d]] - [[λ, 0],
[0, λ]]|
= |[[a - λ, b],
[c, d - λ]]|
Determinant of A - λI must be equal to 0:
(a - λ)(d - λ) - bc = 0
λ^2 - (a + d)λ + (ad - bc) = 0
Solve this quadratic equation to find the eigenvalues λ1 and λ2.
2. Find the corresponding eigenvectors:
For each eigenvalue, substitute it back into (A - λI) * v = 0 and solve for v. Normalize the eigenvectors if necessary.
3. Form matrix P:
Arrange the eigenvectors as columns to form matrix P.
4. Verify diagonalization:
Calculate P^T * A * P. If the result is a diagonal matrix, then P orthogonally diagonalizes A.
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The mean and standard deviation of a random sample of n measurements are equal to 34.5 and 3.6 , respectively. a. Find a 90 % confidence interval for mu if nequals 144 . b. Find a 90 % confidence interval for mu if nequals 576 . c. Find the widths of the confidence intervals found in parts a and b. What is the effect on the width of a confidence interval of quadrupling the sample size while holding the confidence coefficient fixed
a) The 90% confidence interval for μ when n = 144 is (34.006, 34.994).
b) The 90% confidence interval for μ when n = 576 is (34.251, 34.749).
c) The widths of the confidence intervals found in parts a is 0.494 and b is 0.249.
a) For n = 144 and a 90% confidence interval:
The critical value for a 90% confidence level with (n - 1) degrees of freedom is approximately 1.660. Using this value:
Confidence Interval = 34.5 ± 1.660 × (3.6 / sqrt(144))
Calculating the confidence interval:
Confidence Interval = 34.5 ± 1.660 × (3.6 / 12)
Confidence Interval = 34.5 ± 0.494
Therefore, the 90% confidence interval for μ when n = 144 is (34.006, 34.994).
b) For n = 576 and a 90% confidence interval:
The critical value remains the same: 1.660.
Confidence Interval = 34.5 ± 1.660 × (3.6 / sqrt(576))
Calculating the confidence interval:
Confidence Interval = 34.5 ± 1.660 × (3.6 / 24)
Confidence Interval = 34.5 ± 0.249
Therefore, the 90% confidence interval for μ when n = 576 is (34.251, 34.749).
c) The width of a confidence interval is given by:
Width of confidence interval = 2 × (critical value) × (standard deviation / sqrt(n))
For part a:
Width of confidence interval = 2 × 1.660 × (3.6 / sqrt(144))
Width of confidence interval = 0.494
For part b:
Width of confidence interval = 2 × 1.660 × (3.6 / sqrt(576))
Width of confidence interval = 0.249
Therefore, the widths of the confidence intervals in parts a and b are 0.494 and 0.249, respectively.
To compare the effect of quadrupling the sample size while holding the confidence coefficient fixed, we can calculate the ratio of the widths:
Ratio of widths = W2 / W1 = 0.249 / 0.494 = 0.504
So, quadrupling the sample size while holding the confidence coefficient fixed reduces the width of the confidence interval by approximately 50.4%.
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