however asked this gets one hundreed points

Answer:

xxxxx

Explanation:

Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a Volume (the same volume as 1 milliliter).

Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Answer:

Explanation:

We can use Hooke's law to solve this problem. Hooke's law states that the force required to extend or compress a spring by some distance x is proportional to that distance. Mathematically, this can be written as:

F = kx

where F is the force applied to the spring, x is the distance the spring is stretched or compressed, and k is the spring constant, a measure of the stiffness of the spring.

To find the spring constant, we can use the given information that a 20g weight causes an extension of 0.72cm in the spring. We can convert the weight to force using the acceleration due to gravity, g:

F = mg = (0.02 kg)(9.8 m/s^2) = 0.196 N

Now we can solve for the spring constant:

k = F/x = 0.196 N / 0.0072 m = 27.2 N/m

Finally, we can use this spring constant to find the extension caused by an 80g weight:

F = mg = (0.08 kg)(9.8 m/s^2) = 0.784 N

x = F/k = 0.784 N / 27.2 N/m = 0.0288 m

So the extension caused by an 80g weight is 0.0288 m or 2.88 cm.

The angle in radians through which the wheel rotates is \(14207.511^{\circ}\).

What is angular velocity?

In physics, angular velocity or rotational velocity, also known as angular frequency vector, is a pseudovector representation of how fast the angular position or orientation of an object changes with time.

Given

initial angular velocity \($\omega_1=25 \mathrm{rad} / \mathrm{s}$\)

Final Angular velocity \($\omega_2=36 \mathrm{rad} / \mathrm{s}$\)

time interval \($t=3 \mathrm{~s}$\)

using

\($$\begin{aligned}& \omega_2=\omega_1+\alpha t \\& 36=25+2 \\& \alpha=1.5 \mathrm{rad} / \mathrm{s}^2\end{aligned}$$\)

(b)Average angular speed \($\frac{\Delta \theta}{\Delta t}$\)

\($$\begin{aligned}& \theta=\omega_1 t+\frac{1}{2} \alpha t^2 \\& \theta=25 \times 8+\frac{1}{2} \times 1.5 \times 8^2 \\& \theta=200+48=248 \mathrm{rad}\end{aligned}$$\)

average angular speed \($=\frac{\Delta \theta}{\Delta t}$\)

\(=\frac{248}{8}=31 \mathrm{rad} / \mathrm{s}$$\)

(c)Angle rotated =248 radians

(d)angles in degree \($=14207.511^{\circ}$\)

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Answer:

(a) 9.28 m/s2

(b) 9.03 m/s2

(c) 9.8 m/s2

(d) 450 N, 670 N

Explanation:

mass of elevator + student, m = 870 kg

Reading of scale, R = 450 N

(a) When the elevator goes down, the weight decreases.

Let the acceleration is a.

By the Newton's second law

m g - R = m a

870 x 9.8 - 450 = 870 a

a = 9.28 m/s2

(b) R = 670 N

Let the acceleration is a.

870 x 9.8 - 670 = 870 a

a = 9.03 m/s2

(c) If the scale reads zero, it mean the elevator is falling freely. The acceleration is downwards and its value is 9.8 m/s2.

(d) Tension in cable is 450 N and 670 N.

Answer:

Increases

Explanation:

Due to an increase in temperature, molecules within the medium will vibrate more vigorously, meaning that the rate of chemical reactions generally increases with temperature due to an increase in kinetic energy. Because sound is a form of kinetic energy, it is safe to assume that the speed of sound waves increases with temperature.

Answer:

A- increases because The particles bump into each other more often.

Explanation:

Just took the test

Answer:

The acceleration in the block is 2.1 m/s²

Explanation:

Given that,

Mass = 50 kg

Angle = 54°

Force = 40 N

Coefficient of friction = 0.33

We need to calculate the acceleration in the block

Using balance equation

\(F_{net}=F_{f}-F\cos\theta\)

\(ma=\mu mg\sin\theta-F\cos\theta\)

\(a=\dfrac{\mu mg\sin\theta-F\cos\theta}{m}\)

Put the value into the formula

\(a=\dfrac{0.33\times50\times9.8\sin54-40\cos54}{50}\)

\(a=2.1\ m/s^2\)

Hence, The acceleration in the block is 2.1 m/s²

Answer:

Most auroras occur in the E-layer of the ionosphere

Explanation:

The E-layer of the ionosphere is located 90 km to 150 km (60 mi to 90 mi) above the earth’s surface. However, auroras also occur in the F-layer of the ionosphere, which is located above the E-layer that is located between 150 km and 500 km (90 mi to 300 mi) altitude

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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The velocity of the autographed baseball before it fell off the table is 1.89 m/s

We'll begin by obtainig the time taken for the autographed baseball to strike the floor. This can be obtained as follow:

h = ½gt²

1.4 = ½ × 9.8 × t²

1.4 = 4.9 × t²

Divide both side by 4.9

t² = 1.4 / 4.9

Take the square root of both side

t = √(1.4 / 4.9)

t = 0.53 s

The initial velocity of the ball can be obatined as illustrated below:

s = ut

1 = u × 0.53

Divide both sides by 0.53

u = 1 / 0.53

u = 1.89 m/s

Thus, we can conclude that the velocity of the ball before it fell off the table is 1.89 m/s

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Answer:

F = 0

Explanation:

Given that,

Force acting to push a bin = 45 N

Mass of the plastic bin, m = 3 kg

The plastic bin is moving with a constant velocity.

We need to find the net force acting on the box. Constant velocity means the change in velocity is equal to 0. It means acceleration will be 0.

As a result, the force acting on the box is equal to 0.

Answer:

THE RUBBER BALL

Explanation:

From the question we are told that

      The mass of the rubber ball is \(m_r = 2 \ kg\)

      The  initial  speed of the rubber ball is  \(u = 3 \ m/s\)

      The final speed at which it bounces bank \(v - 3 \ m/s\)

      The mass of the clay ball  is  \(m_c = 2 \ kg\)

       The  initial  speed of the clay  ball is \(u = 3 \ m/s\)

       The final speed of the clay ball is  \(v = 0 \ m/s\)

Generally Impulse is mathematically represented as

       \(I = \Delta p\)

where \(\Delta p\) is the change in the linear momentum so  

       \(I = m(v-u)\)

For the rubber  is  

        \(I_r = 2(-3 -3)\)

       \(I_r = -12\ kg \cdot m/s\)

=>     \(|I_r| = 12\ kg \cdot m/s\)

For the clay ball

       \(I_c = 2(0-3)\)

        \(I_c = -6 \ kg\cdot \ m/s\)

=>    \(| I_c| = 6 \ kg\cdot \ m/s\)

So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball

Answer:

The water cycle shows the continuous movement of water within the Earth and atmosphere. ... Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow. Water in different phases moves through the atmosphere (transportation).

Explanation:

It's the water cycle.

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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A ten kilo gram satellite completes- are revolution round the earth ata' height one hundred Kilometer in one hundred eight minutes the work done by gravitational force of earth will be​ zero.

Work is defined as the amount of energy required to move an object in a particular direction.

When a force moves an object in the same direction, it performs positive work.

Negative work is performed when an object is moved in the opposite direction of a force, or when the force and motion are perpendicular.

No work is performed when the applied force and motion are perpendicular.

W = Fd cos theta is the formula for work.

Where F is force, d is distance, and theta is the angle between the force and distance.

What is the work done by gravitational force on the satellite?

According to Newton's Law of Gravitation, the gravitational force acting on a body is given by F = (GMm)/r^2, where G is the gravitational constant, M and m are the masses of the two objects, and r is the distance between them.

The work done by a gravitational force on a satellite moving around the Earth is negative.

The gravitational force acts towards the center of the Earth, while the displacement of the satellite is perpendicular to it.

As a result, the work done by gravity on the satellite is zero.

Why is the work done by gravity zero?

Because work is done when a force acts on an object and causes it to move.

If the force is perpendicular to the motion, it does no work.

In the case of the satellite, the force of gravity is acting towards the center of the Earth, while the satellite's motion is perpendicular to it.

As a result, the work done by gravity on the satellite is zero.

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The volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

To calculate the change in volume of a gas from an initial pressure to a final pressure, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's law can be expressed as:

P1 * V1 = P2 * V2

Where:

P1 = Initial pressure (80.8 kPa)

V1 = Initial volume (817 cm³)

P2 = Final pressure (101.3 kPa)

V2 = Final volume (to be calculated)

Let's plug in the values into the equation and solve for V2:

80.8 kPa * 817 cm³ = 101.3 kPa * V2

V2 = (80.8 kPa * 817 cm³) / 101.3 kPa

V2 ≈ 651.25 cm³

Therefore, the volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

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The magnitude of the electric field along the positive z axis is kqz/√(z^2+a^2)^3/2 , the angular frequency of these oscillations is √(kqq0/ma^3)

1. Given that a uniformly charged ring in the xy plane, centered at the origin.

Radius of the ring(r) = a

positive charge distributed evenly along its circumference = q

k= 1/4piepsion

The electric field can be described as, E = kq/r^2

The force exerted on an electric charge by a charge is F = q0E

Any vector can be projected along the z = A(z)=Acosθ

We know that ∑F =ma

Acceleration along z axis = a =d^2z/dt^2

The equation of motion for a simple harmonic oscillation along z is d^2z/dt^2 = -ω^2z

Here,  ω is the cosine function in a right-angled triangle is cosθ = z/√(z^2+a^2)

dE(z)=dEcosθ we know that E = kq/z^2+a^2

To calculate the magnitude of the electric field caused by complete rings, integrate dE(z)=dEcosθ

E(z) = Ecosθ = kq/(z^2+a^2) x  z/√(z^2+a^2)

E(z) = kqz/(z^2+a^2)^3/2

2. We know that F= q0E = kqq0z/(z^2+a^2)^3/2

Given The ball will oscillate along the z axis between z=d and z=-d in simple harmonic motion. Let z =d

F = kqq0d/(d^2+a^2)^3/2 = kqq0d/a^3

Force at any point along z = - kqq0z/a^3

We know F = ma =  

- kqq0z/a^3 = md^2z/dt^2

d^2z/dt^2= - kqq0z/ma^3

This equation of motion can be compared with the equation of motion for simple harmonic motions to find the angular frequency.

ω =√(kqq0/ma^3)

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The diagram that shows the greatest magnitude net torque with a zero net force is the diagram in second option.

option B is the correct answer.

The net torque is the sum of the individual torques. The torque itself is obtained from the product of applied force and the perpendicular distance of the force.

In rotational equilibrium, there is no net torque on the object. There may be individual torques, but they add up to zero and cancel each other out.

Mathematically, the formula for torque is given as;

τ = Fr

where;

The torque applied to an object increases with increase in the perpendicular distance.

To obtain a zero net force, sum of all the opposite forces applied to an object must be equal to zero.

The forces must be equal in magnitude but opposite in direction, and the diagram that meets this specification is the last graph.

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The distance traveled by the object during the time interval from t = 2 s to t = 3s is 3m. Option C.

From the formula d = ½ at2 the displacement is proportional to the square of time. If you run twice as far from the rest, the displacement will quadruple (or 4m). Since the object has already moved 1 m in the first second, the remaining 3 m have moved in time intervals from 1 to 2 seconds.

This means that the velocity and net force in the direction normal to the plane must be zero. Assuming the plane is frictionless means that the plane exerts no force on the block parallel to the surface. For angular frictionless tilt, the acceleration is the result of the gravitational acceleration multiplied by the sine of the angle.

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Answer: 25%

Explanation:

From the question, we are informed that the temperature of source and sink of cannot engine are 400K

and 300K respectively.

The efficiency will be calculated as:

= 1 - t/T

= 1 - 300/400

= 1 - 3/4

= 1/4

= 25%

02222222222222222222222222222222

Answer:

The frecuency is 1.2*10¹¹ Hz.

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).

The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f * λ.

In this case:

Replacing:

300,000,000 m/s= f* 0.0025 m

Solving:

f= 300,000,000 m/s ÷0.0025 m

f= 1.2*10¹¹ \(\frac{1}{s}\) =  1.2*10¹¹ Hz

The frecuency is 1.2*10¹¹ Hz.

Answer:

The cost per week of electricity is Rm 46.8

Explanation:

Electrical Power and Energy

The electrical power consumed by an appliance connected to a voltage V and carrying a current I is given by:

P = V.I

The energy consumed by an electrical appliance of power P during a time t is:

E = P.t

The electrical equipment in an office takes I=13 A when connected to a V=240 V supply.

The power consumed is:

P = 240 V * 13 A

P = 3,120 Watt

Converting to Kilowatt:

P = 3,120/1,000 KW

P = 3,12 KW

If the equipment is used t=30 hours each week, the energy is:

E = 3.12 KW * 30 h

E = 93.6 KWh

Since the cost of each KWh is Rm 0.50, the weekly cost of electricity is:

C = 93.6 * 0.50 = 46.8

The cost per week of electricity is Rm 46.8

The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

2.78 cm³/s

Explanation:

From the question,

Q = v/A'.................... Equation 1

Where Q = Average flow rate, A' = inverse of Area, v = velocity of the car.

Given: v = 100 km/h, A' = 10 km/L

Substitute this value into equation 1

Q = 100/10

Q = 10 L/h.

Now, we convert L/h to cm³/s.

Since,

1 L = 1000 cm³, and

1 h = 3600 s

Therefore,

Q = 10(1000/3600) cm³/s

Q = 2.78 cm³/s

Answer:

a) As the chicken is still, the displacement is zero, which implies that the work is zero.

b) as the person is still there is no displacement therefore the work is zero

c) Lagraua applies a vertical force and the displacement is vertical, therefore the Work is positive

d) the force of gravity is directed downwards and the displacement is upwards, therefore the angle between it is 180º and the 180º fly is -1. Consequently the lock is negative

e) when the person meticulously feels the upward force and the displacement is downward, therefore the work is negative

Explanation:

Work is defined by the expression

        W = F. r

bold letters indicate vectors, we can write this expression as a module

        W= F r cos θ

where is at the angle between force and displacement.

Let's apply this expression to the different cases

a) As the chicken is still, the displacement is zero, which implies that the work is zero.

b) as the person is still there is no displacement therefore the work is zero

c) Lagraua applies a vertical force and the displacement is vertical, therefore the Work is positive

d) the force of gravity is directed downwards and the displacement is upwards, therefore the angle between it is 180º and the 180º fly is -1. Consequently the lock is negative

e) when the person meticulously feels the upward force and the displacement is downward, therefore the work is negative

Answer:(a)

Explanation:all they do is work work work work

Copper, an essential mineral, is naturally present in some foods and is available as a dietary supplement. It is a cofactor for several enzymes (known as "cuproenzymes") involved in energy production, iron metabolism, neuropeptide activation, connective tissue synthesis, and neurotransmitter synthesis. It’s classified as a native element. Copper's metallic luster attracted people's attention. Today most copper is produced from sulfide ores. Copper is an excellent conductor of electricity. Most copper mined today is used to conduct electricity - mostly as wiring.

You must concentrate on the catch to win a water balloon contest without breaking the balloon. Momentum, impulse, force, and impact time are all important factors in the catch's success. The key to catching a water balloon without breaking it is to reduce the balloon's impact force. The momentum of the balloon, the impulse applied to the balloon, and the impact time all contribute to the impact force.

The product of an object's mass and velocity is its momentum. As it is thrown towards you, the water balloon has a certain mass and velocity. The greater the balloon's momentum, the more difficult it will be to catch it without breaking it.

In order to catch a water balloon, you must apply an impulse to the balloon. The higher the impulse, the more effectively you can stop the balloon. To catch a water balloon without breaking it, apply a large impulse to the balloon in a short period of time. This reduces the impact force on the balloon and keeps it from breaking.

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