How to get from here to here

there is a change from vapour to liquid

Answer:

perform multiple trials for each release height instead of just one

Explanation:

Number of moles = mass/ molar mass

it implies that n(O2) = 24.0g / 32

= 0.75 mols

Answer:

Chemistry Q&A Library decide which element probably forms a compound with chlorine that has a chemical formula most and least similar to the chemical formula of the compound formed by chlorine and magnesium most and least similar to magnesium:strontium,rubidium,phosphorus, cesium

Explanation:

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Answer:

a. "-ic"

Explanation:

The correct answer is a. "-ic".

For example:

Following the same logic, the name for HBr is Hydrobromic acid; and the name for HI is Hydroiodic acid.

The weight of the book in kilograms is 0.498Kg.

A body's bulk is an innate characteristic. It was widely believed to be related to the volume of matter in a physical body prior to the discovery of the atom and particle physics.

You can work on a level surface provided by the book.

will eventually add more weights. It is distinctive in its own way. The mass must be measured.

the account balance to 0 the scale with the book on it. Weigh the object down to the nearest gram (1 g). 498g In this experiment, all masses will be measured in kilograms. the books weigh 0.498 kg in kilograms.

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False. Potassium-argon dating is a radiometric dating technique used to determine the age of rocks and minerals.

It is based on the decay of the isotope potassium-40 (K-40) into argon-40 (Ar-40) over time. This dating method is particularly useful for dating volcanic rocks and minerals because the K-40 is commonly found in them.

Potassium-argon dating is not limited to organic materials. In fact, it is primarily used for dating inorganic substances like rocks and minerals. The method relies on the measurement of the ratio of K-40 to Ar-40 in a sample. By comparing this ratio to the known decay rate of K-40, scientists can calculate the age of the rock or mineral.

While other dating methods like radiocarbon dating are specifically designed for organic materials, potassium-argon dating is uniquely suited for dating non-organic substances, making it an important tool in geological and archaeological research.

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Answer:

The alkanes comprise a series of compounds that are composed of carbon and hydrogen atoms with single covalent bonds. This group of compounds comprises a homologous series with a general molecular formula of C n H 2 n+2 , where equals any integer.

Explanation:

The general formula for the alkane series is CnH2n+2

In this formula:

"Cn" shows how many carbon atoms are in the alkane molecule.

"H2n+2" shows the amount of hydrogen atoms in the alkane compound, with "n" being the number of carbon atoms.

Alkanes are a group of hydrocarbons that only have single bonds between their carbon atoms. The formula says that each carbon atom is connected to two hydrogen atoms. And the total number of hydrogen atoms in an alkane molecule is two more than double the number of carbon atoms.

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Answer:

I feel like the answer is A) true

Explanation:

you create a model to help your audience understand your complex idea. There have been models made to represent ideas that we cannot see.

Answer:

Increased the concentration

Explanation:

Complete Question

Open the simulation by pushing the play button.  Begin by dragging the concentration tester overto the liquid and add drink mix until the concentration reaches approximately 2.oo mol/L.  This means there are 2.00 moles of the drink mix in 1 Liter of the solution. Add more drink mix until you notice a color change. Have you increased or decreased the concentration? (Higher number means a higher concentration).

Solution

Drink mix is basically the solute which is added to solvent i.e water.

The higher is the amount of drink mix in the solvent, the higher is the concentration of the solute and hence darker is the color of the drink.

Hence, in the case the concentration of the drink has been increased.

Answer:

Pressure inside soda can = 5.56 atm

Explanation:

Given data:

Initial volume = 1250 mL

Initial pressure = 1.00 atm

Final volume = 225  mL

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.00 atm × 1250m L =  P₂ × 225 mL

P₂ =  1250 atm. mL/ 225 mL

P₂ = 5.56 atm

The limiting reagent in the reaction between 43.5 g of nitrogen gas (N₂) and 12.3 g of hydrogen gas (H₂) is hydrogen gas (H₂).

This can be determined by

1. To determine the limiting reagent, we need to compare the amount of each reactant present and their stoichiometric ratios in the balanced chemical equation.

2. The balanced equation for the reaction between nitrogen gas and hydrogen gas is N₂ + 3H₂ → 2NH₃.

3. The molar mass of nitrogen gas (N₂) is 28 g/mol, and the molar mass of hydrogen gas (H₂) is 2 g/mol.

4. To find the number of moles of each gas, we divide their masses by their respective molar masses. For nitrogen gas, we have 43.5 g / 28 g/mol = 1.55 mol. For hydrogen gas, we have 12.3 g / 2 g/mol = 6.15 mol.

5. Based on the stoichiometric ratio in the balanced equation, 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas. Therefore, the nitrogen gas requires 1.55 mol × 3 = 4.65 mol of hydrogen gas.

6. Since we have only 6.15 mol of hydrogen gas, which is greater than the required amount for nitrogen gas, hydrogen gas is present in excess, and nitrogen gas is the limiting reagent.

7. Therefore, hydrogen gas is the excess reagent, and nitrogen gas is the limiting reagent in this reaction.

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If we add 25.6 g of an unknown molecular compound to the 0.250 kg of benzene, the molar mass of the unknown compound is 148.8 g/mol.

The Molality of the compound is given as :

ΔT = i Kf m

Where,

ΔT = freezing point depression = 3.54 °C

i =  Van't Hoff factor of the Benzene = 1

Kf =  constant of the freezing = 5.12 °C/m

m = molality = ?

m = ΔT / i Kf

m = 3.54 / 1 × 5.12

m = 0.69 mol

molality = moles / mass of benzene

moles = 0.172

The molar mass = mass / moles

The molar mass = 25.6 / 0.172

The molar mass = 148.8 g/mol

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Answer: 3 methylhexane

Explanation: Attached is a picture of the molecule. Courtesy of the National Institute of Health, United States Government.

Answer: 3-methylhexane

Explanation:

The parent chain is six carbon atoms long, so there is the prefix 'hex'

There is a methyl branch on the third carbon atom, so it is 3-methylhexane.

Answer:

1.346 g/mL

Explanation:

The density is defined as the mass of a substance per unit of volume.

In the problem, you add 10.0mL of glycerine. the mass change from 78.32g to 91.78g. The difference is the mass of the glycerine:

Mass glycerine: 91.78g - 78.32g = 13.46g

As the volume added was 10.0mL, the density, δ, in g/mL is:

δ =13.46g / 10.0mL =

To determine Eo for the given reaction, we can use the equation:  Eo(cell) = Eo(cathode) - Eo(anode)

The reduction potential for the cathode is the reduction potential of Ti²⁺, which is -1.63 V.

The reduction potential for the anode is the reduction potential of Fe³⁺, which is 0.77 V.

Plugging the values into the equation, we have:

Eo(cell) = (-1.63 V) - (0.77 V)

Eo(cell) = -2.40 V

Therefore, the standard cell potential (Eo) for the given reaction is -2.40 V.

This negative value indicates that the reaction is not spontaneous under standard conditions. The electrons flow from the anode (Fe³⁺) to the cathode (Ti²⁺), resulting in a negative cell potential. The reaction would require an external energy source to proceed.

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The density of the solid is  6.724 g/ml.

Density is the number of factors which can be people, animals, vegetation, or objects in a sure place. To calculate density, you divide the number of objects by the dimension of the place. The populace density of a rustic is the wide variety of human beings in that us of a divided by means of the location in square kilometers or miles.

The density of an amount to being counted is its mass divided by means of its quantity. it also includes measured at zero °C and at 1 atmosphere of stress. Density is vital in figuring out the buoyancy of materials in fluids, as well as in evaluating materials and other measurements.

The density of an object is certainly one of its maximum crucial and easily-measured physical properties. Densities are extensively used to perceive natural substances and to represent and estimate the composition of many varieties of combos.

density = mass/ volume

      = 975g/145ml

      = 6.724 g/ml

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It would take approximately 0.00021 minutes (or about 0.013 seconds) to deposit 1.48 g of Cr from a Cr³⁺(aq) solution using a current of 2.50 A.

To calculate the time required to deposit 1.48 g of chromium (Cr) from a Cr³⁺(aq) solution using a current of 2.50 A and a Faraday constant (f) of 96,500 C/mol, we need to use the following formula:
time (in seconds) = (mass of substance / molar mass) * (1 / n * F * I)
where:
- mass of substance = 1.48 g
- molar mass of Cr = 52 g/mol
- n = number of electrons transferred per mole of substance, which is 3 in this case (from Cr³⁺ to Cr⁰)
- F = Faraday constant = 96,500 C/mol
- I = current = 2.50 A
First, we need to convert the mass of substance from grams to moles:
1.48 g / 52 g/mol = 0.02846 mol
Then, we can plug in the values into the formula and solve for time:
time (in seconds) = (0.02846 mol / 3) * (1 / 96,500 C/mol * 2.50 A)
time = 0.0128 seconds
However, the question asks for the time in minutes, so we need to convert the answer from seconds to minutes:
time (in minutes) = 0.0128 seconds / 60 seconds/minute
time = 0.00021 minutes
Therefore, it would take approximately 0.00021 minutes (or about 0.013 seconds) to deposit 1.48 g of Cr from a Cr³⁺(aq) solution using a current of 2.50 A.

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2.50 litres of a 10.0 M solution require the preparation of 25.0 moles of ethylene glycol.

Excellent antifreeze, anti-boil, and anti-corrosive qualities are produced when antifreeze and water are mixed in a 50/50 ratio. The proportion of conventional ethylene glycol to water in severely cold conditions can reach 70% antifreeze, 30% water. The maximum antifreeze to water ratio when using DEX-COOL® is 60/40.

moles = concentration (M) x volume (L)

Given that the desired concentration is 10.0 M and the volume needed is 2.50 L, the setup for calculating the total number of moles of ethylene glycol can be written as:

moles = 10.0 M x 2.50 L

moles = 25.0 mol

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Based on Hess law of constant heat summation, the enthalpy of the combustion of C2H4 can be calculated from the heat of formation values of the products CO2 and H2O.

A combustion reaction is a reaction between a substance and oxygen in which light and large amounts of heat is given off.

The amount of heat evolved when one mole of that substance reacts completely with oxygen is known as the enthalpy of combustion of that substance.

The equation of the combustion of C2H4 is given below:

The enthalpy of the combustion of C2H4 can be calculated from the heat of formation of the products CO2 and H2O based on Hess law.

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Mendeleev noticed that patterns appeared when he arranged the elements in order of increasing atomic mass.

Dmitri Mendeleev noticed that when the elements were arranged in order of their increasing atomic mass, a pattern of chemical and physical properties was repeated every eighth element. Mendeleev noticed that certain similarities in chemical properties appeared at regular intervals among the elements when they were arranged in increasing order of atomic mass.

The elements when they were arranged in increasing order of atomic mass he used the pattern to predict the existence of undiscovered elements and to predict the properties of those elements. You can check out the related link for a better understanding of the topic.

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Answer:

(9,5) and (2,1)

Explanation:

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

We have

\(density = \frac{65.54}{33.21} \\ = 1.973501957...\)

We have the final answer as

Hope this helps you

The molarity of the phosphorous acid solution is approximately 0.00760 M.To determine the molarity of the phosphorous acid solution, we need to use the balanced chemical equation and the stoichiometry of the reaction between ammonia and phosphorous acid.

The balanced chemical equation for the reaction between ammonia (NH3) and phosphorous acid (H3PO3) is:

3NH3 + H3PO3 -> (NH4)3PO3

From the equation, we can see that the ratio of ammonia to phosphorous acid is 3:1.

Given that 11.91 ml of 0.162 M ammonia solution reacts, we can calculate the number of moles of ammonia used:

Moles of ammonia = volume (in L) x molarity

Moles of ammonia = 0.01191 L x 0.162 mol/L = 0.001930 mol

Since the ratio of ammonia to phosphorous acid is 3:1, we know that the number of moles of phosphorous acid used is one-third of the moles of ammonia:

Moles of phosphorous acid = 1/3 x moles of ammonia

Moles of phosphorous acid = 1/3 x 0.001930 mol = 0.000643 mol

Next, we calculate the molarity of the phosphorous acid solution:

Molarity = moles of solute / volume of solution (in L)

Molarity = 0.000643 mol / 0.08459 L = 0.00760 M

Therefore, the molarity of the phosphorous acid solution is approximately 0.00760 M.

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GTA → GTG, AAC → ATC, GTA → TA, and CGG → CTG are different types of point mutations that can occur in the genetic code. A point mutation is a type of genetic mutation that alters only one nucleotide base pair of a DNA molecule. It is also called a single nucleotide polymorphism (SNP).

The types of point mutations are substitution, deletion, and insertion.

GTA → GTG chemical case : This is a substitution mutation, which is a type of point mutation. The nucleotide guanine is replaced by thymine, resulting in a change from a purine to a pyrimidine. This kind of mutation is known as a transversion.

AAC → ATC chemical cause : This is a substitution mutation, which is a type of point mutation. The nucleotide adenine is replaced by thymine, resulting in a change from a purine to a pyrimidine. This kind of mutation is known as a transversion.

GTA → TA chemical cause :  This is a substitution mutation, which is a type of point mutation. The nucleotide guanine is replaced by adenine, resulting in a purine-to-purine transition mutation.

CGG → CTG chemical cause : This is a substitution mutation, which is a type of point mutation. The nucleotide cytosine is replaced by thymine, resulting in a change from a pyrimidine to a purine. This kind of mutation is known as a transition mutation.

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It takes 2.79669 kJ of heat to raise the temperature of 47.8 g of benzene by 57.0 K.

To calculate the amount of heat necessary to raise the temperature of benzene, we can use the formula:

Q = m * c * ΔT

where Q is the amount of heat, m is the mass of benzene, c is the specific heat capacity of benzene, and ΔT is the change in temperature.

Substituting the given values, we get:

Q = 47.8 g * 1.05 J/g°C * 57.0 K

Q = 2796.69 J

To convert J to kJ, we divide by 1000:

Q = 2.79669 kJ

Therefore, it takes 2.79669 kJ of heat to raise the temperature of 47.8 g of benzene by 57.0 K.

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