How to find average speed

The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Answer:

 a = 7.6 m / s²

Explanation:

In this exercise we must use Newton's second law .  In general, it is asked to know if the system is in equilibrium or accelerated, suppose that the system is in equilibrium

Person on top of the cliff m = 85 kg

Y axis

          N - W = 0

          N = w₁

          N = m g

X axis

          T’ -fr = 0

          T’ = fr

the friction force has the formula

         fr = μ N

we subtitle

         T’ = μ m g

we calculate

        T ’= 0.5 85 9.8

        T’ = 416.5 N

This is the maximum value that the tension of the rope can have by remaining in static equilibrium.

Person on the cliff   M = 100 kg

        T -W = 0

        T = W = M g

        T = 100 9.8

        T = 980 N

we see that

         T> T ’

as the tension exceeds the maximum static friction force, in the system it is accelerated, so the friction coefficient decreases to   μ= 0.4

We medo the problem, but  with acceleration

Person on the cliff

          T ’-fr = m a

          a = (T '-  μ mg) / m

in this case, how the rope should maintain the tension of the diagram of the person hanging

         T ’= T = Mg

we substitute

         a = Mg / m - very g

         a = g (M / m - my)

let's calculate

        a = 9.8 (100/85 - 0.4)

        a = 7.6 m / s²

The statement "the speed of light is always the same no matter how fast you are moving" is true. This phenomenon is known as the constancy of the speed of light.

According to the theory of relativity, the speed of light in a vacuum is a constant value that is independent of the motion of the observer. This means that no matter how fast you are moving, you will always measure the speed of light to be the same value.

This idea may seem strange and counterintuitive, but it has been experimentally verified and is now a fundamental principle of modern physics. It has important consequences for our understanding of the nature of space and time, and it has played a key role in the development of many important scientific theories, including the theory of relativity.

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Answer:

the particle is at coordinates (18,15/2)

Explanation:

To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:

a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j

So the acceleration of the particle is a = 2i + 3j m/s².

To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:

r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j

We can use the kinematic equations of motion to solve this problem.

Let the acceleration of the particle be a = axî + ayj.

(a) Using the equation of motion v = u + at, where u is the initial velocity:

f = v = u + at

Substituting the given values, we get:

(91+7j) = (3î-2j) + a(3î + 3j)

Equating the real and imaginary parts, we get:

91 = 3a + 3a (coefficients of î are equated)

7 = -2a + 3a (coefficients of j are equated)

Solving these equations simultaneously, we get:

a = î(23/6) + j(1/2)

So the acceleration of the particle is a = (23/6)î + (1/2)j.

(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:

At t = 3s, the displacement of the particle is:

s = ut + (1/2)at^2

Substituting the given values, we get:

s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2

Simplifying, we get:

s = 9î + (17/2)j

So the coordinates of the particle at t=3s are (9, 17/2).

Answer:

Direction & accelerate

Answer:

unbalanced forces cause an object to accelerate

Answer:

E = 1.29*10^6N/C

Explanation:

You take the cell membrane as a parallel plate capacitor. In order to calculate the magnitude of the electric field in between the membranes you use the following formula:

\(E=\frac{\sigma}{\epsilon_o}\)           (1)

σ:  surface charge density = 10^-5 C/m^2

εo: dielectric permittivity of vacuum = 8.85*10^-12C^2/Nm^2

You replace the values of the parameters in the equation (1):

\(E=\frac{10^{-5}C/Nm^2}{8.85*10^{-12}C^2/Nm^2}=1.29*10^6\frac{N}{C}\)

The magnitude of the electric field between the membrane cell is 1.29*10^6N/C

Answer:

1 astronomical unit, or AU, is the average distance from the Earth to the Sun; that's about 150 million km. So, Neptune's average distance from the Sun is 30.1 AU. Its perihelion is 29.8 AU, and it's aphelion is 30.4 AU.

Short Answer: it is 29

Explanation:

sorry if its wrong

Answer:

29

Explanation:

I just took a test! not only that but the other person who answered this question had the corrected answer.

Answer:

Study

Explanation:

From the given analogy, we understand that.

Teachers educates

If this is true,

The students are expected to learn from what the teacher teaches.

This can also be said that, the students studies what the teachers teach

Hence, to complete the analogy.

We have;

(1) Students, Study.

We can also make use of

(2) Students, learn.

(1) & (2) answer the question completely.

Answer:

STUDENT:STUDY OR LEARN

Explanation:

Answer:

The net torque will be "1366.33 Nm".

Explanation:

The given values are:

Length of ladder,

\(\tau_{242N} = 9.83 \ m\)

then,

\(\tau=4.92\)

Mass,

= 20.3 kg

Now,

The net torque will be:

⇒  \(\tau_{net}=\tau_{mg}+\tau_{242}\)

On putting the given values, we get

⇒         \(=4.92\times (-mg)+9.83\times (+242)\)

⇒         \(=4.92\times (-21\times 9.8)+9.83\times 242\)

⇒         \(=-1012.53+2378.86\)

⇒         \(=1366.33 \ Nm\)

At a divergent boundary, heat and pressure can cause metamorphism, magma can solidify to form igneous rocks, and sediments can accumulate and lithify to form sedimentary rocks. These three processes contribute to the formation of various types of rocks.

At a divergent boundary, three main processes occur that can lead to the formation of metamorphic, igneous, and sedimentary rocks:

1. Metamorphic rocks: Heat and pressure from the divergent boundary can cause existing rocks to be metamorphosed, or transformed, into new rocks with different textures and mineral compositions. This process is called metamorphism.

2. Igneous rocks: Magma, which is molten rock, can rise to the surface at a divergent boundary and cool and solidify to form igneous rocks. This process is called solidification or crystallization.

3. Sedimentary rocks: Sediments, such as sand and mud, can accumulate in the low-lying areas near a divergent boundary, such as in rift valleys or on the continental shelf. Over time, these sediments can be compacted and cemented together to form sedimentary rocks. This process is called lithification.

Hence, Heat and pressure at a divergent boundary can produce metamorphism, solidify magma to create igneous rocks, and accumulate and lithify sediment to create sedimentary rocks. Different sorts of rocks are formed as a result of these three processes.

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According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Therefore, the street applies an equal and opposite force on the car, which is 20,000 N upward. So the answer is O exactly 20,000 N.

In this scenario, the car is applying a force of 20,000 N downward towards the street.

Therefore, the street must be applying an equal and opposite force on the car, which would be 20,000 N upward.

This is because the force of the car pushing down on the street is balanced by an equal and opposite force from the street pushing up on the car.

To summarize, the force applied by the street on the car is equal in magnitude but opposite in direction to the force applied by the car on the street, according to Newton's third law.

So the answer is O exactly 20,000 N.

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The intensity of the light due to both sources at point P will be four times that of a single source.

According to the superposition principle, the total intensity of light at a point is equal to the sum of the intensities due to each individual source. Since the two sources are of equal strength, the intensity of the combined light at point P will be twice that of a single source.

However, the light from each source will interfere with each other, resulting in constructive and destructive interference. As two beams are coherent, meaning they have the same frequency and phase, the light waves will add together constructively at certain points, increasing the intensity. So, at point P, the intensity of the light due to both sources will be four times that of a single source.

Hence option 1 is correct.

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Young people

Explanation:

cuz old people can't do sports

As positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.

At the beginning of an action potential of cell membrane, the sodium ion gates open and sodium ions flows into the cell.  This process is called depolarization. Due to rapid influx of sodium ion, the channel is eventually closed.

The potassium channels are then activated in a process called repolarization. This process occurs when the potassium channels open and allow potassium ions to flow out of the cell.

To maintain the cell membrane potential, cells are kept at low concentration of sodium ions and high concentration of potassium ions.

Thus, as positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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Answer:

\(-180.38\ \text{N}\)

Explanation:

\(q_1=-53\ \mu\text{C}\)

\(q_2=105\ \mu\text{C}\)

\(q_3=-88\ \mu\text{C}\)

r = Distance between the charges

\(r_{12}=0.5\ \text{m}\)

\(r_{23}=0.95\ \text{m}\)

\(r_{13}=1.45\ \text{m}\)

k = Coulomb constant = \(9\times 10^9\ \text{Nm}^2/\text{C}^2\)

Net force is given by

\(F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}\)

The force on the particle \(q_1\) is \(-180.38\ \text{N}\).

Answer:

The answer sir would be 180.38

Explanation:

Put in 180.38 trust

Regarding a spring-mass system's duration, the square root of the mass and the spring constant have opposing correlations. The length of spring will be longer and vice versa as the mass grows. Therefore, the mass influences spring.

They swing back and forth around a stationary point. Classic examples of this type of vibrating motion are a simple pendulum and a mass on a spring.

Therefore, The use of motion detectors demonstrates that the vibrations of these objects have a sinusoidal nature, even if this is not obvious from plain viewing.

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The force in member KD is 19.04 kN in tension.

Determine the reactions at the support points. Since the truss is statically determinate, we can easily solve for these reactions. Assuming the supports are pinned, we can determine the vertical reaction at support A to be 54 kN and the horizontal reaction at support D to be 33 kN.

Analyze the forces at each joint of the truss. Starting at joint A, we can solve for the forces in members AB and AC using the equations of equilibrium:

ΣFy = 0: 54 - P1 - 10sin(60) - ABsin(60) = 0

ΣFx = 0: AC - 10cos(60) - ABcos(60) = 0

Solving these equations simultaneously, we get AB = 16.21 kN (compression) and AC = 5.00 kN (tension).

Move on to joint B and solve for the forces in members BD and BE:

ΣFy = 0: ABsin(60) - BDsin(45) - 10sin(60) = 0

ΣFx = 0: -BE - ABcos(60) + BDcos(45) = 0

Solving these equations, we get BD = 15.17 kN (compression) and BE = 8.21 kN (tension).

Continue analyzing the forces at each joint until we reach joint D. Solving for the forces in members CD and KD:

ΣFy = 0: -P3 - CDsin(30) - BE - BDsin(45) = 0

ΣFx = 0: CDcos(30) + BDcos(45) - KD = 33

Solving these equations, we get CD = 18.41 kN (compression) and KD = -19.04 kN (tension).

Therefore, the force in member KD would be 19.04 kN in tension.

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The vertical speed at this moment is option A which is V₂.

Since the ball is rolling across a flat, horizontal table, there is no vertical acceleration acting on it. Therefore, the ball's initial vertical velocity is equal to its final vertical velocity just before it hits the ground.

Let the ball's initial velocity in the horizontal direction be v₁, and let the horizontal velocity remain constant as it falls. Then, just before hitting the ground, the ball's velocity in the horizontal direction is also V₂.

Using the principle of conservation of energy, we know that the ball's initial kinetic energy is equal to its final kinetic energy just before hitting the ground. The ball's initial kinetic energy is given by 1/2 mv₁², and its final kinetic energy is given by 1/2 mv₂², where m is the mass of the ball.

Therefore, we can set these two expressions equal to each other and solve for the final velocity in terms of the initial velocity and v₂:

1/2 mv₁² = 1/2 mv₂²

v₂ = √(v₁²)

Since the vertical velocity of the ball remains constant throughout its motion, the vertical component of the velocity just before hitting the ground is also √(v₁²). Therefore, the answer is:

Vertical speed at the moment of hitting the ground = √(v₁²) = |v₁|, which is option A.

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The frequency that the person on the train hears is calculated as 767 Hz.

Frequency is the number of waves that passes a fixed point in unit time.

The formula for the observed frequency (f') of a wave with a known frequency (f) due to the Doppler Effect is:

f' = f (v + vo) / (v + vs)

v : speed of the wave in the medium (in this case, the speed of sound)

vo : speed of the observer (in this case, the speed of the train)

vs is the speed of the source (in this case, assumed to be zero)

vo = 85.0 km/h * 1000 m/km / 3600 s/h = 23.6 m/s

f' = 725 Hz * (343 m/s + 23.6 m/s) / (343 m/s + 0 m/s) = 767 Hz

Therefore, the frequency that the person on the train hears is 767 Hz.

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The ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

An emf is induced in a coil placed in a magnetic field when a current carrying conductor moves in the field.

emf = NdФ/dt

where;

Thus, the ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

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The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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We will have the following:

So, the distance is approximately 0.874 m.

Answer:

C !! i needed to make this answer  longer lol so hi

Answer:

Explanation:

For discharge of capacitor in RC circuit , the relation is as follows

\(V=V_0e^\frac{-t}{\lambda}\)

V is voltage across the capacitor , V₀ is maximum  voltage across capacitor  , λ is time constant and t is the time after which the voltage is recorded. During discharge this will also be voltage across resistance .

Taking log on both sides

lnV = lnV₀   -  \(\frac{t}{\lambda}\)

Given equation

[lnV] = - .027 t + 2.5

Comparing these equation

\(\frac{1}{\lambda} = .027\)

λ = 37 s

time constant = 37 sec.

ANSWER:

D. The rubbed balloon gets a greater charge

STEP-BY-STEP EXPLANATION:

If we rub the two bodies against each other, we increase the contact between them, and then the passage of electrons from one body to another is greater, that is to say, in the case of rubbing some of the electrons are released, and remain attached to the balloon. Whereas when it is only touched this does not happen.

So the correct answer is D. The rubbed balloon gets a greater charge