Use the equation a = F/m, where an is the acceleration, F is the force being applied, and m is the mass of the object, to calculate acceleration using mass and force. Calculating the acceleration is as simple as dividing the force by the mass.
What is Newton's second law of motion?Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the force applied on it, and inversely proportional to its mass. The mathematical representation of this law is:
F = ma
where F is the force applied on an object, m is the mass of the object, and a is its acceleration. This law implies that the greater the force applied on an object, the greater its acceleration will be, and that the acceleration of an object will decrease as its mass increases, given a constant force.
This law helps to explain the behavior of objects under the influence of external forces. It is used in many areas of science and engineering, including mechanics, physics, and aerospace. Understanding the relationship between force, mass, and acceleration is fundamental to the study of mechanics and the design of machines and structures.
Here in the Question,
To find acceleration using mass and force, you can use the following steps:
1. Determine the force acting on the object. This can be done using a force meter, a scale, or by calculating the force using the formula F = ma, where F is the force in newtons (N), m is the mass of the object in kilograms (kg), and a is the acceleration in meters per second squared (m/s²).
2. Measure the mass of the object in kilograms. This can be done using a scale.
3. Use the formula a = F/m to calculate the acceleration of the object. Rearrange the formula to solve for a: a = F/m.
5. Plug in the values for force and mass and solve for acceleration. For example, if the force acting on an object is 20 N and the mass of the object is 5 kg, the acceleration can be calculated as follows:
a = F/m
a = 20 N / 5 kg
a = 4 m/s²
So, the acceleration of the object is 4 meters per second squared.
It's important to note that the units of force and mass should be in the correct SI units (newtons and kilograms, respectively) to ensure the correct unit for acceleration (meters per second squared).
Therefore, To find acceleration using mass and force, use the formula a = F/m, where a is the acceleration, F is the force applied, and m is the mass of the object. Simply divide the force by the mass to calculate the acceleration.
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Part A
Which yoga poses did you perform best? Which poses do you still need to improve on?
Answer:
Knees to Chest
Be consistent. Setting and committing to a regular practice of yoga is absolutely essential if you want to make improvements. ..
Answer: Dog pose was really easy, but tree pose was really difficult because it was hard to balance.
Complete the following table. Be sure to include units in your answer.
Net Force (N)
Mass (kg)
Acceleration
5.0
2.32
18.2
0.87
180
2.5
12
1.967
21.2
1.793
The acceleration of the object is equal to the net force exerted on it divide by its masses, or a = F m, in accordance with Newton's second rule of motion.
What is the net force equation?Whenever a forces is applied to a body, numerous other forces, such as gravitational force Field goal, frictional force Ff, and the normal force, also work to balance the imposed force. Therefore, FNet Equals Fa Plus Fg Plus Ff + FN is the formula for net force.
What does net force mean when accelerating?The effects (the total) of all push and pull forces that are really operating on a thing is known as the net force. An object will accelerates in the net force if the pushing and pulling forces acting on it are not equal (a net force acts).
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exaggerated feelings of self-importance are most closely linked with
Exaggerated feelings of self-importance are most closely linked with narcissism. Narcissism is a personality trait characterized by an inflated sense of self-worth, an excessive need for admiration, and a lack of empathy towards others.
Individuals with narcissistic traits often believe they are superior to others, crave attention and validation, and have a grandiose self-image.
They may engage in self-promotion, seek constant admiration, and exploit others for personal gain. Narcissism is associated with a sense of entitlement, a tendency to manipulate and exploit others, and a lack of empathy or concern for the well-being of others.
While a certain level of self-confidence and self-esteem is healthy, excessive narcissism can negatively impact relationships, lead to interpersonal conflicts, and hinder personal growth and development.
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An astronaut holds a rock 100m above the surface of Planet X. The rock is then thrown upward with a speed of 15m/s, as shown in the figure. The rock reaches the ground 10s after it is thrown. The atmosphere of Planet X has a negligible effect on the rock when it is in free fall. Determine the acceleration due to gravity on Planet X.
The acceleration due to gravity of the planet X is 1 m/s².
The given parameters;
height above the ground, h = 100 minitial velocity of the rock, u = 15 m/stime of motion of the rock, t = 10 sThe acceleration due to gravity is calculated as follows;
\(h = ut - \frac{1}{2} gt^2\\\\100 = 15(10) - (0.5\times 10^2)g\\\\100 = 150 - 50g\\\\50g = 150-100\\\\50g = 50\\\\g = 1 \ m/s^2\)
Thus, the acceleration due to gravity of the planet X is 1 m/s²
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the voltage across a 1-μf capacitor is given by v(t)=100exp(−100t) v.
Find the expression for the current. Express your answer in terms of t.
i(t)= -0.01e-100t
The expression for the current flowing through the capacitor is i(t) = -0.01exp(-100t), where t is the time in seconds.
The current flowing through a capacitor is given by the derivative of the voltage with respect to time, multiplied by the capacitance:
i(t) = C * d/dt[v(t)]
Substituting the given voltage expression, we get:
i(t) = 1μF * d/dt[100exp(-100t)]
Taking the derivative of the exponential function, we get:
i(t) = 1μF * (-100) * exp(-100t)
Simplifying, we get:
i(t) = -0.01exp(-100t)
Therefore, the expression for the current flowing through the capacitor is i(t) = -0.01exp(-100t), where t is the time in seconds.
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How does the mass of an object affect its acceleration?
Answer:
as the mass of an object is increased, the acceleration of the object is decreased & vice-versa.
Explanation:
hope this helps!
why must the specimen in an electron microscope be placed in a vacuum within a sealed chamber?
The reason why the specimen in an electron microscope must be placed in a vacuum within a sealed chamber is to prevent any interference from air molecules or other contaminants. This is essential because electron microscopes use a beam of electrons to illuminate the specimen, and the presence of air molecules could scatter the electrons, leading to a reduction in image quality and resolution.
By creating a vacuum within a sealed chamber, the electron microscope ensures an unobstructed pathway for the electron beam, resulting in a clearer and more detailed image of the specimen. In a vacuum chamber, the vacuum bag is placed inside a sealed chamber with the mouth of the vacuum bag placed between two sealing bars. Air is pumped out of the entire chamber, effectively squeezing the air out of the vacuum bag before it is automatically heat-sealed when a desired pressure is reached. So, the reason why the specimen in an electron microscope must be placed in a vacuum within a sealed chamber is to prevent any interference from air molecules or other contaminants.
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do batteries in a circuit always supply power to a circuit, or can they absorb power in a circuit?
Batteries in a circuit typically supply power to the circuit by converting chemical energy into electrical energy.
However, under certain circumstances, such as during charging or when connected in reverse, batteries can absorb power from the circuit and store it as chemical energy for later use. This is commonly observed in rechargeable batteries, where they can be recharged by applying a higher voltage to reverse the chemical reactions that occurred during discharge. So while batteries primarily serve as power sources, they can also absorb power under specific conditions to facilitate their recharging process. Batteries in a circuit typically supply power to the circuit by converting chemical energy into electrical energy.
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A biker is going uphill, in one hour he traveled just 20km. What is his speed?
Explanation:
Speed = distance / time
= 20 km / 1 hr
= 20 km/hr
≈ 5.56 m/s
PLS HELP 15 PNTS AND BRAINLSIT FOR CORRECT ASNWER PLSSSS HELP MEEE
Which part of an object's rate of change best defines acceleration?
A.position
B.speed
C.velocity
D.force
Answer:
Velocity
Explanation: If you are going down hill, (Which is one direction) you will gain more speed by, gravity, friction, and most importantly velocity.
Calculate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2.
After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.
To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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the thumb is what to the phalanges?
Answer:
A thumb only has one joint and two phalanges. The thumb is referred to as “the big finger".
Brainlist pls!
Present a brief history of how Johannes Kepler's and Galileo
Galilei's research led to Isaac Newton's theory of gravity and the
confirmation of this theory by Edmund Halley.
Johannes Kepler's and Galileo Galilei's research on celestial motion laid the groundwork for Isaac Newton's theory of gravity, which was later confirmed by Edmund Halley's calculations and observations of Halley's Comet.
Johannes Kepler's laws of planetary motion, based on precise observations, and Galileo Galilei's discoveries in physics and astronomy paved the way for Isaac Newton's theory of gravity. Newton's law of universal gravitation, stating that all objects attract each other with a force proportional to their masses and inversely proportional to the square of the distance between them, unified celestial and terrestrial motion. Edmund Halley confirmed Newton's theory by accurately calculating and predicting the orbit of Halley's Comet, providing empirical evidence for the validity of Newton's laws. Together, these contributions revolutionized our understanding of gravity and shaped the foundation of modern physics.
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Johannes Kepler's and Galileo Galilei's research has contributed significantly to Isaac Newton's theory of gravity and Edmund Halley's confirmation of this theory. He was an astronomer and mathematician who played a significant role in the scientific revolution of the 17th century.
Kepler's first law states that the planets move in ellipses around the sun, with the sun located at one of the foci of the ellipse. Kepler's second law states that the speed of a planet varies as it moves around the sun, with the planet moving faster when it is closer to the sun. Kepler's third law relates the period of a planet's orbit to its distance from the sun. These laws were crucial in later developments in the study of gravity and planetary motion.
Galileo Galilei was a mathematician, astronomer, and physicist who made several important contributions to the study of motion and gravity. Galileo was the first person to use a telescope to observe the heavens, and he made many important discoveries, such as the phases of Venus, the moons of Jupiter, and the sunspots.
Isaac Newton was a mathematician, physicist, and astronomer who is widely regarded as one of the most influential scientists in history.
Newton's laws of motion state that objects will remain at rest or move at a constant velocity in a straight line unless acted upon by an external force. Newton's law of universal gravitation states that every object in the universe is attracted to every other object with a force that is proportional to the product of their masses and inversely proportional to the square of their distance apart.
Edmund Halley was an astronomer and mathematician who is best known for his work on comets. Halley also made several important discoveries of his own, including the orbit of Halley's Comet. Halley used Newton's laws of motion and law of universal gravitation to calculate the orbit of the comet.
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Question 23 of 32
Two pistons are in an enclosed volume with fluid in between them, such that
movement in one piston affects the location of the other piston, as shown in
the image below. If an explosion occurs in the piston on the left such that it
moves 0.2 m, what is the distance that the piston on the right will move
(assuming that friction can be neglected)? (Recall that work on an object is
equal to the force on the object times the distance it is moved, and that work
is conserved.)
Cross-sectional area = 0.25 m²
Cross-sectional area = 0.5 m²
OA. 0.1 m
OB. 0.2 m
OC. 0.8 m
D. 0.4 m
The correct answer for the given question for the distance that the piston on the right will move is 0.1 m option (A).
When an explosion occurs in the left piston, it exerts a force on the fluid, which in turn exerts an equal and opposite force on the right piston due to the enclosed volume.
The cross-sectional area of the left piston is 0.25 m², and assuming the force is uniformly distributed over the entire area, the force exerted by the left piston is given by F = P × A, where P is the pressure and A is the area.
Using the work-energy principle, the work done by the left piston is equal to the work done on the right piston. Therefore, the work done on the right piston is equal to the force exerted on it multiplied by the distance it moves.
The force exerted on the right piston can be calculated using the same formula as before (F = P × A), where the cross-sectional area A is 0.5 m².
Since the force exerted on the right piston is equal to the force exerted by the left piston, we can equate the two expressions for force and solve for the distance moved by the right piston.
Using the equation F_left = F_right, we have P_left × A_left = P_right × A_right.
Plugging in the given values, we get (P_left × 0.25) = (P_right × 0.5).
Since the pressure is the same throughout the fluid, P_left = P_right.
Simplifying the equation, we have 0.25 = (0.5 × A_right).
Solving for A_right, we get A_right = 0.25 / 0.5 = 0.5 m².
The distance moved by the right piston can be calculated using the work formula:
Work_right = Force_right × Distance_right.
Plugging in the values, we have (P_right × A_right) × Distance_right = (P_left × A_left) × Distance_left.
Since P_left = P_right, we can further simplify the equation:
A_right × Distance_right = A_left × Distance_left.
Plugging in the given values, we get (0.5 × Distance_right) = (0.25 × 0.2).
Solving for Distance_right, we have Distance_right = (0.25 × 0.2) / 0.5 = 0.1 m.
Hence, the correct answer is option A: 0.1 m.
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In a river of bed width of 600 m and bed slope of 7.5 cm/km, it is found that the bed material just begin to move when the discharge is 120 million m³/day. Assuming the mean velocity to vary with the water depth and slope according to the relation: v = 120 y $2/³, find the bed slope at which the same tractive force on the bed would be produced with a discharge of 365 million m³/day.
The bed slope required to produce the same tractive force on the bed with a discharge of 365 million m³/day can be determined using the given equation for mean velocity variation.
Bed width (B) = 600 m
Initial discharge (Q1) = 120 million m³/day
Initial bed slope (S1) = 7.5 cm/km
The equation for mean velocity (v) = 120 y^(2/3), where y is the water depth.
To find the bed slope (S2) for a new discharge (Q2) of 365 million m³/day, we need to equate the tractive force on the bed for both scenarios.
The tractive force on the bed can be represented as:
Tractive force =\((Rho * g * S * B * v^2) / (R * D50)\)
where:
Rho is the density of water,
g is the acceleration due to gravity,
S is the bed slope,
B is the bed width,
v is the mean velocity, and
R and D50 are constants.
Since we are comparing two scenarios with the same tractive force, the following equation can be formed:
\((Rho * g * S1 * B * v1^2) / (R * D50) = (Rho * g * S2 * B * v2^2) / (R * D50)\)
Simplifying the equation:
\(S1 * v1^2 = S2 * v2^2\)
Substituting the given values:
\(S_1 * (120 y_1^{(2/3))^2 = S_2 * (120 y_2^{(2/3))^2\)
Rearranging the equation:
\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)
We know that Q = B * v * y, where Q is the discharge. Rearranging this equation gives:
\(v = Q / (B * y)\)
Substituting the values for Q1 and Q2, we have:
\(v1 = 120 million / (B * y1)\)
\(v2 = 365 million / (B * y2)\)
Substituting the expressions for v1 and v2 in the equation from step 7:
\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)
\(= S_1 * (120^2 * y_1^{(4/3)}) / (120^2 * y_2^{(4/3)})\)
\(= S_1 * (y_1^{(4/3)} / y2^{(4/3)})\)
Since the bed material just begins to move when Q = 120 million m³/day, the velocity can be expressed as \(v = v_1 = 120 y1^{(2/3)}.\)
Therefore, the equation for S2 becomes:
\(S_2 = S_1 * (y_1^{(4/3)} / y_2^{(4/3)})\)
=\(S_1 * (120^{(4/3)} * y_1^{(4/3) }/ (120 y_2^{(2/3)})^{(4/3))\)
\(= S_1 * (120^{(4/3)} * y1^{(4/3)} / (120^{(4/3)} * y2^{(4/3)}))\)
\(= S_{1 * (y_1^{(4/3)} / y_2^{(4/3)})\)
Finally, substituting the values for y1 and y2:
\(S_2 = S_1 * (y_1^{(4/3) }/ y_2^{(4/3)})\)
= \(S_1 * (y_1^{(4/3)} / (365 / 120)^{(4/3)})\)
Now, you can substitute the values for y1, and S1, and calculate S2 accordingly.
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What is the wavelength (in feet) of a 600 hz sound wave (assume speed of sound in air is 1125 ft/s; round to the nearest second decimal place e.g. 1.255 = 1.26)?
The wavelength (in feet) of the sound wave with a velocity of 1125 ft/s and a frequency of 600 Hz is 1.88 ft
Relation of velocity, frequency and wavelength of a waveThe velocity of a wave is related to its frequency and wavelength according to the following equation:
Velocity (v) = wavelength (λ) × frequency (f)
v = λf
How to determine the wavelength of the waveFrom the question given, the following data were obtained:
Frequency (f) = 600 HzVelocity (v) = 1125 ft/s Wavelength (λ) =?The wavelength of the wave can be obtained as follow:
v = λf
Divide both sides by f
λ = v / f
λ = 1125 / 600
λ = 1.88 ft
Thus, the wavelegth of the wave is 1.88 ft
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Which of these is formed by a hot spot in Earth's crust?
Answer:
we need to know what the choices are?
Explanation:
Answer:
A hot spot is a region deep within the Earth's mantle from which heat rises through the process of convection. This heat facilitates the melting of rock. The melted rock, known as magma, often pushes through cracks in the crust to form volcanoes.
you attempt to use your multimeter to measure the electric potential difference, but the value stays at 0.00 v no matter what you do and there is an h on the screen. what's going on?
The multimeter is probably broken and you should give it to your instructor/TA is used to measure the electric potential difference, but the value stays at 0.00 v no matter what you do and there is an h on the screen.
What is a multimeter?
A multimeter is an electronic instrument used to measure electrical properties such as voltage, current, and resistance. It is also known as a multi-tester, VOM (volt-ohm-milliammeter), or DMM (digital multimeter). Multimeters are an essential tool for electricians and other technicians, as they allow for accurate and precise measurements of various electrical values. Multimeters are available in a range of styles and designs, from basic models to more advanced versions with additional features.This means that the multimeter is not taking any readings and is displaying the last measured value. You may need to press the "hold" button on the multimeter to turn it off and allow it to take new readings.To learn more about multimeters here
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3. You attempt to use your multimeter to measure the electric potential difference, but the value stays at 0.00 V no matter what you do and there is an H on the screen. What's going on?
The multimeter is probably broken and you should give it to your instructor/TA.You probably plugged in the wires incorrectly. Try using the 10A and V ports.Someone pressed the "Hold" button. If you press it again, the multimeter should work correctly.Someone pressed the "Handheld" button. The multimeter will only work if you hold it in your hand while using it.A 2141.00 lb car is moving at 49.00 miles per hour. Calculate the magnitude of its momentum p in SI units.
The magnitude of the car's momentum (p) in SI units is 965.88 kg·m/s.
To calculate the momentum, we need to convert the mass of the car from pounds (lb) to kilograms (kg) and the velocity from miles per hour (mph) to meters per second (m/s).
Converting the mass of the car, 2141.00 lb, to kilograms, we use the conversion factor 1 lb = 0.453592 kg. Thus, the mass of the car is 2141.00 lb * 0.453592 kg/lb = 971.34 kg.
Converting the velocity, 49.00 mph, to meters per second, we use the conversion factor 1 mph = 0.44704 m/s. Therefore, the velocity of the car is 49.00 mph * 0.44704 m/s/mph = 21.89 m/s.
The momentum is calculated by multiplying the mass and velocity: p = mass * velocity = 971.34 kg * 21.89 m/s = 21277.9826 kg·m/s. Rounding to the appropriate number of significant figures, the magnitude of the car's momentum is 965.88 kg·m/s.
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saturn orbits the sun at more than 50% of the speed of Mars 
true or false????
Answer:
(TRUE) Mars seems to pass the fastest, Jupiter next, and Saturn the slowest. But all exhibit that puzzling quirk--near the point of their celestial course precisely opposite the Sun ("opposition"), their action amongst the stars briefly turns around.
Explanation:
Mars: 24.077 km/s (53,853 miles per
hour), or a period of about 686.93 days.
Answer:is true
Explanation:
You are sitting on the beach and wondering about the properties of mechanical waves. Describe them in terms of ocean waves.
Answer:
The ocean waves is a mechanical wave that transmits mechanical energy in the wave by the synchronized and repeated oscillation of the waters about an equilibrium level such that as the wave approaches the shoreline, and the water depth decreases, the height of the wave also increases reflecting the effective transmission of energy while the medium which is the water through which the wave propagates, move back and forth within a small region
Explanation:
A mechanical wave like other waves is the oscillation of a field about an equilibrium level. In mechanical waves, the field consists of the oscillating matter such that the wave transmits energy through a medium. The displacement of the medium through which the wave energy is limited such that the wave energy is conserved to travel far.
if the car rolls down the hill ( with engine off) with negligible friction and air resistance what will its kinetic energy be
Answer:
falling iirc
Explanation:
Dos masas con valores de 8kg y 12kg cada una se encuentran separadas por una distancia de 1m. Determinar la fuerza de atraccion gravitacional entre ellas si se compara con el valor de sus pesos Como es este valor?
The question is: Two masses with values of 8kg and 12kg each are separated by a distance of 1m. Determine the force of gravitational attraction between them if compared with the value of their weights. What is this value?
Answer: The force of gravitational attraction between them if compared with the value of their weights is \(640.704 \times 10^{-11} N\).
Explanation:
Given: \(m_{1}\) = 8 kg, \(m_{2}\) = 12 kg
Distance = 1 m
Formula used is as follows.
\(F = \frac{G \times m_{1} \times m_{2}}{r^{2}}\)
where,
F = force of gravitational attraction
G = gravitational constant = \(6.674 \times 10^{-11} N m^{2}/kg^{2}\)
\(m_{1}\) = mass of object 1
\(m_{2}\) = mass of object 2
r = distance between the centers of these two objects
Substitute the values into above formula as follows.
\(F = \frac{G \times m_{1} \times m_{2}}{r^{2}}\\= \frac{6.674 \times 10^{-11} Nm^{2}/kg^{2} \times 8 kg \times 12 kg}{(1 m)^{2}}\\= 640.704 \times 10^{-11} N\)
Thus, we can conclude that the force of gravitational attraction between them if compared with the value of their weights is \(640.704 \times 10^{-11} N\).
An object's movement around an internal axis is _____.
Answer:
brooo it is rotation .............
Why are you more likely to have something "go down the wrong pipe" when you are trying to eat and talk at the same time?
It's also a good idea to pause between bites and finish chewing and swallowing before speaking.
You are more likely to have something "go down the wrong pipe" when you are trying to eat and talk at the same time because speaking requires you to coordinate the movements of your tongue, lips, and other parts of your mouth in a precise way. This coordination can sometimes interfere with the normal reflexes that protect your airway when you swallow.
When you swallow, a complex series of actions occur to ensure that the food or liquid you are ingesting goes down the esophagus and into the stomach, rather than into the trachea and lungs. This process involves the closing of the glottis (the opening between the vocal cords in the larynx) and the raising of the larynx to help guide the food or liquid down the esophagus.
When you are talking while eating, your mouth and throat may be in a different position than they would be if you were just eating, and this can affect the timing and coordination of the swallowing reflexes. For example, if you take a breath in the middle of a sentence, the larynx may be in a different position than it would be during a normal swallow, which can increase the likelihood of food or liquid entering the trachea and lungs.
In addition, when you talk while eating, you may be more likely to inhale small particles of food or liquid into your airway because your mouth is open more often than it would be if you were just eating. This can increase the risk of choking or aspiration pneumonia.
To reduce the risk of choking or aspiration, it's best to take small bites of food and chew thoroughly before speaking. It's also a good idea to pause between bites and finish chewing and swallowing before speaking.
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Could someone help me with this
Assuming a flat ground, and football thrown or dropped from the same height, the horizontally-thrown ball will hit the ground with the same vertical velocity as the dropped ball, but it will have most of its initial horizontal velocity, too. A simple vector addition, guarantees that that the horizontally-thrown ball will have a larger total velocity than the dropped ball.
What is Velocity.
Velocity is the directional velocity of a moving object as an indicator of the rate of change of position observed from a particular frame of reference and measured at a particular time standard.
Therefore, A simple vector addition, guarantees that that the horizontally-thrown ball will have a larger total velocity than the dropped ball.
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A bullet is fired upward with an initial velocity of 100 m/s. What will be it’s velocity when it hit the ground?
A bullet is fired upward with an initial velocity of 100 m/s. What will be it’s velocity when it hit the ground?
Zero. It is sitting on the ground. This would almost always “assume” a friction-less environment where the only force acting on the bullet is gravity. In this case, it would be 100 m/s immediately before hitting the ground. (zero once it comes to rest)
How do we know how much gravitational force objects have?
Answer:
understand Newton's second law of motion,F is equal to ma where F is the force ,m is the mass of the object,a is acceleration
An uncharged spherical conductor hangs by an insulating thread. You bring a negatively charged rod near
from the left side. The net charge on the hanging conductor’s left side is (choose one):
a. Positive
b. Negative
c. Neutral
Answer:
Positive
This type of charging is called charging by induction In this the uncharged body gets the opposite type of charge.when a negatively charged rod is bring near uncharged spherical conductor it attracts positive charge and repels negative charges
so In left side all positive charges appears and in right side all negetive
Types of methods of charging
Charging by contact charging by rubbing charging by induction.