By comparing the measured value of γ to the known values for monoatomic and diatomic gases, we can determine the nature of the gas and whether it is monoatomic or diatomic.
To determine if a gas is monoatomic or diatomic based on the ratio of specific heat at constant pressure (Cp) to specific heat at constant volume (Cv), we can use the following relationship:
γ = Cp / Cv
Where:
γ is the ratio of specific heat, also known as the adiabatic index or heat capacity ratio.
For monoatomic gases, such as noble gases like helium (He) and argon (Ar), the ratio of specific heats is γ = 5/3 ≈ 1.67.
For diatomic gases, such as nitrogen (N₂), oxygen (O₂), and hydrogen (H₂), the ratio of specific heats is γ = 7/5 = 1.4.
By measuring the ratio γ experimentally, we can determine whether the gas is monoatomic or diatomic.
If the measured value of γ is approximately 1.67, it suggests that the gas is monoatomic.
If the measured value of γ is approximately 1.4, it suggests that the gas is diatomic.
This difference in the ratio of specific heat arises from the degrees of freedom in the molecular structure of the gas. Monoatomic gases have three degrees of freedom, while diatomic gases have five degrees of freedom.
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which is the correct name for the compound n2o4? a. nitrogen oxide b. tetranitrogen dioxide c. dinitrogen quadoxide d. dinitrogen tetroxide
The correct name for the compound N₂O₄ is dinitrogen tetroxide. The formula N₂O₄ represents the molecule dinitrogen tetroxide.
Hence, option D (dinitrogen tetroxide) is the correct answer.
The formula for nitrogen monoxide is NO, nitrogen dioxide is NO₂, and nitrogen trioxide is N₂O₃. The term "tetranitrogen dioxide" (Option B) is incorrect as it contains the prefix "tetra-," which refers to four. There are only two nitrogen atoms present in the molecule.
The term "dinitrogen quadoxide" (Option C) is also incorrect because it does not exist. The term quadoxide does not apply to any known compound.
Hence, the correct name of the compound N₂O₄ is dinitrogen tetroxide (Option D).
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List some of the methods used to prevent or slow corrosion with detailed explanation
Answer:
There are several methods that can be used to prevent or slow corrosion:
Coatings: Applying a protective coating to a metal surface can prevent corrosion by creating a barrier between the metal and the environment. Common types of coatings include paint, galvanizing, and electroplating.
Cathodic protection: Cathodic protection involves applying a current to a metal surface in order to reduce the potential difference between the metal and its environment. This can help to prevent corrosion by reducing the electron flow that drives the corrosion reaction.
Inhibitors: Corrosion inhibitors are chemical substances that can be applied to a metal surface to slow or prevent corrosion. These substances work by reacting with the metal surface or the environment to form a protective film or layer.
Passivation: Passivation is a process that involves removing surface contaminants and oxide layers from a metal surface in order to improve its corrosion resistance. This can be achieved through chemical or mechanical means.
Materials selection: Choosing corrosion-resistant materials for specific applications can help to prevent or slow corrosion. For example, stainless steel is a commonly used material for corrosive environments because of its high resistance to corrosion.
Environmental control: Controlling the environment in which a metal object is used can also help to prevent or slow corrosion. For example, reducing humidity or keeping a metal object dry can help to prevent corrosion.
Maintenance: Regular maintenance, such as cleaning and inspection, can help to identify and address corrosion issues before they become severe. This can include removing corrosion products, repairing damage, and applying protective coatings as needed.
A sample of crushed rock is found to have 4. 81 x 10^21 atoms of gold, how many moles of gold are present in this sample?
A. 7. 99 x 10^-3 moles
B. 1. 57 x 10^-1 moles
C. 1. 25 x 10^3 moles
D. 2. 47 x 10^5 moles
Answer:
A
Explanation:
Recall that a mole of any substance contains 6.02 × 10²³ amounts of that substance.
In other words, a mole of gold atoms contains 6.02 × 10²³ gold atoms.
Hence, by dimensional analysis, we have that:
\(\displaystyle 4.81\times 10^{21} \text{ Au} \cdot \frac{1\text{ mol Au}}{6.02\times 10^{23} \text{ Au}} = 7.99\times 10^{-3} \text{ mol Au}\)
Therefore, there is about 7.99 × 10⁻³ moles of gold present in the sample.
In conclusion, the answer is A.
an atom of which of the following elements can form the most bonds?
a. phosphorus
b. sodium
c. oxygen
d.oxygen
Calculate the pH during the titration of 20. 00 mL of 0. 1000 M C3H7COOH(aq) with 0. 1000 M NaOH(aq) after 19. 68 mL of the base have been added. Ka of butanoic acid
The pH of the solution after adding 19.68 mL of 0.1000 M NaOH(aq) is 3.7525.
Volume of C₃H₇COOH(aq) = 20.00 mL
Concentration of C₃H₇COOH(aq) = 0.1000 M
Volume of NaOH(aq) added = 19.68 mL
Concentration of NaOH(aq) = 0.1000 M
Ka of butanoic acid = 1.52 × 10⁻⁵
To find the pH during the titration, we need to determine the concentration of H₃O⁺ ions in the solution.
First, calculate the initial moles of butanoic acid:
Moles of C₃H₇COOH = Volume × Concentration = (20.00 mL × 0.1000 M) / 1000 = 0.00200 moles
According to the balanced chemical equation, 1 mole of NaOH reacts with 1 mole of C₃H₇COOH. Therefore, the moles of NaOH added are:
Moles of NaOH = Volume × Concentration = (19.68 mL × 0.1000 M) / 1000 = 0.001968 moles
The moles of butanoic acid left after reacting with NaOH can be calculated as:
Moles of C₃H₇COOH left = Initial moles of C₃H₇COOH - Moles of NaOH = 0.00200 moles - 0.001968 moles = 0.000032 moles
The total volume of the solution after the addition of NaOH is (20.00 mL + 19.68 mL) = 39.68 mL or 0.03968 L.
Now, calculate the new concentration of butanoic acid:
Concentration of C₃H₇COOH = Moles of C₃H₇COOH left / Volume = 0.000032 moles / 0.03968 L = 0.0008065 M
The concentration of sodium butanoate (NaC₃H₇COO) formed is also 0.0008065 M, as the balanced equation shows a 1:1 mole ratio between C₃H₇COOH and NaC₃H₇COO.
Next, use the expression for the ionization of butanoic acid to calculate the pH:
C₃H₇COOH(aq) + H₂O(l) ⇌ C₃H₇COO⁻(aq) + H₃O⁺(aq)
Ka = [C₃H₇COO⁻][H₃O⁺] / [C₃H₇COOH]
Let [C₃H₇COO⁻] = [H₃O⁺] = x
[C₃H₇COOH] = 0.0008065 M - x
Substituting these values into the Ka expression, we get:
Ka = [x * x] / [0.0008065 - x]
Solving for x, the concentration of H₃O⁺ ions, using the given Ka value:
1.52 × 10⁻⁵ = [x * x] / [0.0008065 - x]
Solving the equation, we find:
[H₃O⁺] = x = 1.77 × 10⁻⁴ M
Finally, calculate the pH:
pH = -log[H₃O⁺]
pH = -log(1.77 × 10⁻⁴)
pH = 3.7525
Therefore, the pH of the solution after adding 19.68 mL of 0.1000 M NaOH(aq) is 3.7525.
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help me pls. the answer i got is 42.78 but it keeps saying it’s wrong
Answer: try 42.8
Explanation: you might have to round to 42.8 because of the significant figures
How does inclusions represent the principles
Will give 15 points
Two liquids are in a graduated cylinder - liquid a has a density of 1.004 g/cm3 and liquid b has a density of 0.6223 g/cm3 . assuming that they do not mix, which liquid is on top and which liquid is on bottom? where would you expect to find the plastic cube from question #2 if it is dropped into the graduated cylinder with these two liquids?
Liquid B is expected to be at the top while liquid A is found at the bottom.
What is density?The term density has to do with the ratio of the mass of a substance to its volume. Now given that the density of a substance actually shows how much heavy the substance is, it is not difficult to understand that a material that has a low density will flat at the top of a material that has a lower density.
Here we are told that the two liquids do not mix. If they do not mix then it follows that they must have formed a two phase system in which one is at the top of the other. The one that is at the top must have the lower density.
Thus, liquid B is expected to be at the top while liquid A is found at the bottom. From the density of the plastic cue, the cube will be at the top.
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four drops of a 0.25 m imidazole solution were added to a solution in a cuvette containing ferrihemoglobin. the mass of the ferrihemoglobin solution in the cuvette was measured to be 2.655 g initially and 2.739 g after the addition of the stock imidazole solution. what is the molar concentration of imidazole in the final solution?
The molar concentration of imidazole in the final solution is approximately 0.595 M.
What is the molar concentration?
First, we need to calculate the mass of the imidazole added to the solution. Since we added four drops of 0.25 M imidazole solution, we can assume that the volume of each drop is approximately 0.05 mL (this value can vary depending on the size of the dropper).
Therefore, the total volume of imidazole solution added is:
4 drops x 0.05 mL/drop = 0.2 mL
To convert this volume to liters, we need to divide by 1000:
0.2 mL / 1000 = 0.0002 L
The moles of imidazole added to the solution can be calculated using the formula:
moles = M x V
where;
M is the molar concentration of the imidazole solution and V is the volume of solution added. Substituting the values we have:moles = 0.25 M x 0.0002 L = 0.00005 moles
Next, we can calculate the mass of ferrihemoglobin in the final solution:
mass = 2.739 g - 2.655 g = 0.084 g
To calculate the molar concentration of imidazole in the final solution, we can use the formula:
Molarity = moles of solute / volume of solution (in liters)
density of ferrihemoglobin = 1.0 g/mL (approximate value)
volume of ferrihemoglobin solution = mass / density = 0.084 g / 1.0 g/mL = 0.084 mL
If we assume that the volume of the imidazole solution is negligible compared to the volume of the ferrihemoglobin solution, we can use the total volume as:
volume of solution = 0.084 mL = 0.000084 L
Now we can calculate the molar concentration of imidazole in the final solution:
Molarity = 0.00005 moles / 0.000084 L = 0.595 M
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What is the heat of combustion of ethane, c2h6, in kilojoules per mole of ethane?.
Combustion is the process in which CO₂ is react with reactant. Heat of combustion of ethane is 1560 kilo joule per mole.
What is combustion ?Combustion is the process in which oxygen is react to form heat or energy. There are three types of combustion as follows
spontaneous combustion
rapid combustion
explosive combustion
Combustion is a chemical reaction between substances, mostly including oxygen and usually followed by the generation of heat and light in the form of flame.
Combustion is the other word for burning. In a combustion reaction, a fuel is heated and it reacts with oxygen and their is energy released.. The fire triangle require the three things for combustion - a fuel, heat and oxygen.
Thus, combustion of ethane gives 1560 kilo per joule energy.
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A local hamburger shop sold a combined total of 620 hamburgers and cheeseburgers on Wednesday. There were 70 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Wednesday?
The number of hamburgers sold on Wednesday is 275.
Let's assume the number of hamburgers sold is x.
According to the given information, the number of cheeseburgers sold is 70 more than the number of hamburgers. So, the number of cheeseburgers sold can be expressed as x + 70.
The total number of hamburgers and cheeseburgers sold is given as 620, so we can set up the following equation:
x + (x + 70) = 620
Combining like terms, we get:
2x + 70 = 620
Subtracting 70 from both sides of the equation:
2x = 550
Dividing both sides by 2:
x = 275
Therefore, the number of hamburgers sold on Wednesday is 275.
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why the density of the borosilicate glass is different from the weighted average of the densities of its components
The density of borosilicate glass is different from the weighted average of the densities of its components because the density of a glass is influenced by its molecular structure and the way its atoms are arranged, rather than a simple weighted average of its components.
Borosilicate glass is a type of glass that contains boron trioxide, which makes it more resistant to thermal expansion and chemical corrosion. When the glass is formed, the components (such as silicon dioxide, boron trioxide, and other metal oxides) are combined at high temperatures, causing them to form a new amorphous material with a unique atomic structure.
The arrangement of atoms and bonding in borosilicate glass is not linear or consistent, and it can differ from the atomic arrangements found in the individual components. This irregular structure results in the overall density of the glass being different from a simple weighted average of the densities of its individual components.
In summary, the density of borosilicate glass is different from the weighted average of the densities of its components due to the unique molecular structure and atomic arrangements that occur when the glass is formed.
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The substances that start a chemical reaction are called?
Answer: The reactants
Explanation: These are the substances that go into a chemical reaction and start it.
What are 4 examples of amorphous solids?
Four examples of amorphous solids are: Glass, Rubber, Asphalt, and Amorphous metals.
Amorphous solids are solids that lack a long-range ordered structure and have a disordered arrangement of atoms or molecules.
Glass: Glass is a non-crystalline solid that is made by cooling a melt or solution so rapidly that the atoms or molecules do not have time to arrange themselves into a crystalline structure.
Rubber: Natural rubber and synthetic rubber are both examples of amorphous solids. Rubber is made up of long polymer chains that are tangled and disordered, giving it its characteristic elasticity and flexibility.
Asphalt: Asphalt is a mixture of bitumen and mineral aggregates that is used as a paving material for roads, parking lots, and other surfaces. Asphalt is an amorphous solid because the bitumen molecules have a disordered arrangement.
Amorphous metals: Amorphous metals, also known as metallic glasses, are a class of metals that have a disordered atomic structure. Amorphous metals are made by cooling a liquid metal at a rate of millions of degrees per second, which prevents the atoms from arranging themselves into a crystalline structure.
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How are organisms classified as Eukarya different from organisms classified as Archaea and Bacteria?
A)They are all multicellular.
B)They all produce their own food.
C) They all reproduce sexually.
D) They all have membrane-bound nuclei
Answer: D
Explanation: The Eukarya differ from the Archea and Bacteria in that their cells are eukaryotic, meaning they contain a membrane enclosed nucleus and other membrane enclosed organelles.
Eukarya is different from organisms classified as Archaea and Bacteria because Eukarya have membrane-bound nuclei. Therefore, option (D) is correct.
How does the classification of Eukarya differ from Archaea?The type of cell of the organism can be classified into three domains. First is the bacteria which have no nucleus present in cells. Then Archaea have no nucleus in the cells but they have a different cell wall than bacteria. Then Eukarya have a nucleus in them.
The domains of Archaea and Bacteria are both composed entirely of small, single-celled organisms but they also have differences. All are composed of prokaryotic cells, which are nucleus-less cells. T
All the cells in the Eukarya domain contain their genetic material or DNA within the nucleus. Four classes make up the Eukarya domain: Plantae, Fungi, Animalia, and Protista.
Therefore, the domain of the Eukarya is different from organisms classified as Archaea and Bacteria as Eukarya have membrane-bound nuclei.
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Which type of molecule speeds up chemical reactions in living things?
Protein molecule acting as enzymes speeds up chemical reactions in living things.
Enzymes are proteins that help speed up metabolism, or the chemical reactions in our bodies. They build some substances and break others down. All living things have enzymes. The enzyme is not destroyed during the reaction and is used over and over.
Our bodies naturally produce enzymes. But enzymes are also in manufactured products and food.
Without enzymes, many of these reactions would not take place at a perceptible rate. Enzymes catalyze all aspects of cell metabolism.
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What do all things that are made of matter have in common?
Answer:
The common things among the three states of matter are: They are made up of small tiny particles. They have a particular mass and can occupy space. These three states have volume in it.
Answer:
Matter is any substance that has mass and takes up space. Everything is made of matter, so any object you can name consists of matter. Basically, if it takes up space and has mass, it's matter.
Explanation:
I really hope this helps have a wonderful day
Fusion of hydrogen releases energy because O Fusion breaks the electromagnetic bonds between hydrogen atoms, releasing energetic photons. The mass of a helium nucleus is smaller than the mass of four protons The mass of a helium nucleus is larger than the mass of four protons The size of a proton is larger than the size of a helium nucleus None of the above is true. 20 Fusion in the core of a stable massive star cannot proceed beyond iron because It would require temperatures that even stars cannot generatel The fusion of iron nuclei is impossible under any circumstances. Iron nuclei are on top of the binding energy curve so iron fusion does not release energy. It is so massive that a black hole must result 000
Question 19: The fusion of hydrogen releases energy because the mass of a helium nucleus is smaller than the mass of four protons.Question 20: Fusion in the core of a stable massive star cannot proceed beyond iron because it would require temperatures that even stars cannot generate.
Question 19 addresses the reason why the fusion of hydrogen releases energy. The correct statement is that the mass of a helium nucleus is smaller than the mass of four protons. This mass difference results in the release of energy during fusion reactions. In fusion, hydrogen nuclei (protons) combine to form helium nuclei, and in the process, some mass is converted into energy according to Einstein's famous equation, E=mc^2. This energy is released in the form of photons, which can be observed as light and heat.
Question 20 explains why fusion in the core of a stable massive star cannot proceed beyond iron. The correct statement is that it would require temperatures that even stars cannot generate. Fusion reactions in stars involve the fusion of lighter elements to form heavier elements, releasing energy in the process.
However, fusion reactions that produce elements heavier than iron require extremely high temperatures and pressures, which are not achievable in the core of a stable massive star. Iron has the highest binding energy per nucleon, meaning that fusion of iron nuclei would require an input of energy rather than releasing energy. As a result, fusion reactions cease beyond the formation of iron in the core of a star.
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A 80°C la presion de vapor del benceno (C6H6) es de 1 atm. Calcula la cantidad de hexano (C6H14) que debemos añadir a 200g de benceno para que su presion de vapor sea de 700mm de Hg
Answer:
18,9g de hexano son necesarios
Explanation:
Basados en la ley de Raoult, la presión de vapor ejercida por una solución es:
P = P°*Xsolvente
Donde P es la presión de la solución deseada = 700mmHg, P° la presión de vapor de vapor del benceno = 1atm = 760mmHg y X es la fracción molar del solvente (Benceno).
Reemplazando:
700mm Hg = 760mmHg * X(Benceno)
0.9211 = X(Benceno)
La fracción molar de benceno se define como:
X = Moles benceno / Moles benceno + Moles hexano
Moles benceno -Masa molar: 78g/mol-
200g * (1mol/78g) = 2.5641 moles benceno
X = Moles benceno / Moles benceno + Moles hexano
0.9211 = 2.5641 moles benceno / 2.5641 moles benceno + Moles hexano
0.9211moles Hexano + 2.3618 = 2.5641
0.9211*Moles Hexano = 0.2023
Moles hexano = 0.2023/0.9211 = 0.2196 moles hexano.
Masa Hexano -Masa molar: 86g/mol-
0.2196 moles hexano * (86g/mol) =
18,9g de hexano son necesariosLa cantidad de hexano (C6H14) que se debe agregar a 200 g de benceno para permitir que la presión de vapor se convierta en 700 mm de Hg sería:
18.9 g
Usando la ley de Raoult, la presión de vapor que libera una solución se encuentra por:
P = P ° × X disolvente
Donde (P) denota la presión de la solución deseada
P ° denota la presión de vapor del benceno y
X denota la fracción molar del disolvente (benceno).
En el caso dado,
(P) = 700 mmHg,
P° = 1atm = 760mmHg
Fracción molar de benceno = 0,9211 (∵ 700/760)
La fracción molar de benceno (X) = Moles de benceno/Moles de benceno + Moles de hexano
Moles de benceno - Masa molar: 78g / mol - 200 g × (1 mol / 78 g)
= 2.5641 moles de benceno
X = Moles de benceno/Moles de benceno + Moles de hexano
0.9211 = 2.5641 moles Benceno/2.5641 moles Benceno + Moles de Hexano
⇒ 0,9211 × moles de Hexano + 2,3618 = 2,5641
⇒ 0.9211 × moles de Hexano = 0.2023
∵ Moles de Hexano = 0.2023/0.9211
\(= 0.2196 moles\)
\(Hexane mass - Molar mass = 86g/mol - 0.2196 mole hexane\) × \((86g/mole)\)
\(= 18.9g\)
Por tanto, 18,9 g es la respuesta correcta.
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Where do most fungi thrive?
Question :
Where do most fungi thrive ?
Answer :
Fungi are found all around the world and grow in a wide range of habitats, including deserts. Most grow on land (terrestrial) environments, but several species live only in aquatic habitats. Most fungi live in either soil or dead matter, and many are symbionts of plants, animals, or other fungi.
Source :
CK-12 , Edgenuity2020
Which Hazardous Material class includes compressed gases, dissolved gases, and gases liquefied by compression or refrigeration?
The Hazardous Material class that includes compressed gases, dissolved gases, and gases liquefied by compression or refrigeration is Class 2: Gases. This class is further divided into three divisions:
1. Division 2.1 - Flammable Gases: These are gases that can burn in the presence of an ignition source. Examples include propane, butane, and hydrogen.
2. Division 2.2 - Non-Flammable, Non-Toxic Gases: These are gases that do not burn and are not toxic, but may still pose risks due to their physical properties, such as high pressure or low temperature. Examples include nitrogen, helium, and carbon dioxide.
3. Division 2.3 - Toxic Gases: These are gases that are harmful or even fatal when inhaled. Examples include chlorine, ammonia, and phosgene.
The proper handling, storage, and transportation of these gases are essential to minimize the risks associated with their hazardous properties. Regulations and guidelines are in place to ensure the safety of those working with and around these materials.
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calculate the mass of 0.5 moles of caco3 in grams with procedure
Answer:
50g
Explanation:
moalr mass of CaCO3= 40g/mol+ 12g/mol+(16g/mol*3)
=52g/mol+48g/mol
=100g/mol
1 mol= 100g
0.5mol=x
by cross multiplication,
0.5*100gmol=x mol
x=50g
what is El Nino and La Nina, and how are they different?
Answer:
El Niño refers to the above-average sea-surface temperatures that periodically develop across the east-central equatorial Pacific. It represents the warm phase of the ENSO cycle. La Niña refers to the periodic cooling of sea-surface temperatures across the east-central equatorial Pacific.
If 0.0025 mol of NaNO3 forms during the reaction, what is the concentration of NaNO3 in the final solution?
Answer:Hi! I hope this will help you with your question, whether this is an assignment or not. The answer that I get is 0.033 concentration.
If 0.0025 mol NaNo3 forms during the reaction, the concentration of NaNO3 in the final solution should be 0.033.
Explanation:
Some athletes like runners or sprinters may train by attaching a small parachute to their upper body. The parachute opens behind them as they run, resulting in a drag force acting on the athlete. Such athletes would never use this in actual competition, though. Explain how using a parachute like this might make an athlete stronger and why they wouldn’t actually use the parachute during a competition even though they trained with it.
Answer:
when using would make an athlete stronger when they keep on training with it.
they don't actually use it during a competition because it slows them down and they won't be able to perform well during Competition even though they trained with it
If you require 15. 1 ml of 0. 0368 m k m n o 4 solution to titrate the n a 2 c 2 o 4 solution, what is the mass of n a 2 c 2 o 4 present in the solution? g\
To calculate the mass of Na2C2O4 present in the solution, we need to use the volume and concentration of KMnO4 solution and the stoichiometry of the balanced equation between KMnO4 and Na2C2O4.
Given:
Volume of KMnO4 solution = 15.1 mL
Concentration of KMnO4 solution = 0.0368 M (moles per liter)
We can use the equation:
Moles of Na2C2O4 = Moles of KMnO4
The balanced equation between KMnO4 and Na2C2O4 is:
2 KMnO4 + 5 Na2C2O4 + 8 H2SO4 -> 2 MnSO4 + 10 CO2 + 5 Na2SO4 + 8 H2O
According to the equation, the stoichiometric ratio is 2 moles of KMnO4 to 5 moles of Na2C2O4.
Now, let's calculate the moles of Na2C2O4 using the volume and concentration of KMnO4:
Moles of KMnO4 = Volume of KMnO4 solution (L) x Concentration of KMnO4 solution (mol/L)
Moles of KMnO4 = 15.1 mL / 1000 mL/L x 0.0368 mol/L
Next, we can use the stoichiometric ratio to find the moles of Na2C2O4:
Moles of Na2C2O4 = (Moles of KMnO4) x (5 moles of Na2C2O4 / 2 moles of KMnO4)
Now, we can calculate the mass of Na2C2O4 using its molar mass:
Mass of Na2C2O4 = Moles of Na2C2O4 x Molar mass of Na2C2O4
Given that the molar mass of Na2C2O4 is 134.00 g/mol, we can substitute the values and calculate the mass:
Moles of Na2C2O4 = (15.1 mL / 1000 mL/L x 0.0368 mol/L) x (5 mol Na2C2O4 / 2 mol KMnO4)
Mass of Na2C2O4 = Moles of Na2C2O4 x Molar mass of Na2C2O4
Please perform the calculations to find the mass of Na2C2O4.
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The solute is designated as the dispersed phase in a colloidal suspension.
A. true
B. false
Answer: Im not, sure if this is right, but I personally think that the Answer, to your question is TRUE!
Explanation: But Dont just take my word for it as I am not sure, Myself. I only made a guess.
When 0.50 M CS2 and 1.50 M Cl2 are placed in a container and allowed to come to equilibrium, the mixture is found to contain 0.125 M CCl4. What is the concentration of Cl2 at equilibrium
The concentration of Cl2 at equilibrium is 1.50 M.
To determine the concentration of Cl2 at equilibrium, we can use the stoichiometry of the reaction between CS2 and Cl2 to form CCl4. The balanced chemical equation for the reaction is:
CS2 + 3Cl2 → CCl4 + S2Cl2
From the balanced equation, we can see that 1 mole of CS2 reacts with 3 moles of Cl2 to produce 1 mole of CCl4. Therefore, the ratio of moles of CS2 to Cl2 is 1:3.
Given the initial concentrations of 0.50 M CS2 and 1.50 M Cl2, we can calculate the initial moles of CS2 and Cl2 in the container.
Moles of CS2 = concentration × volume
= 0.50 M × volume (assuming the volume is 1 L for simplicity)
Moles of Cl2 = 1.50 M × volume
Since the ratio of moles of CS2 to Cl2 is 1:3, we have:
Moles of CS2 / Moles of Cl2 = 1 / 3
(0.50 M × volume) / (1.50 M × volume) = 1 / 3
Simplifying the equation, we find:
0.50 M / 1.50 M = 1 / 3
1/3 = 1/3
This means that the initial ratio of moles of CS2 to Cl2 is already 1:3, which is the stoichiometric ratio in the balanced equation. Therefore, at equilibrium, all the CS2 will be consumed to form CCl4, and the concentration of Cl2 will remain unchanged.
Hence, the concentration of Cl2 at equilibrium is 1.50 M.
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1. How many moles of potassium are present in 4.23 x 10^25 potassium atoms? (show solution)
Answer:
70.27 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
\(n = \frac{N}{L} \\ \)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
\(n = \frac{4.23 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 70.265780...\)
We have the final answer as
70.27 molesHope this helps you
is plasma a matter or no
Answer:
yes
Explanation:
it is very hot matter and solid, liquid and gas and plasma is the states of matter
Answer: Plasma is a state of matter that is often thought of as a subset of gases, but the two states behave very differently. ... But unlike ordinary gases, plasmas are made up of atoms in which some or all of the electrons have been stripped away and positively charged nuclei, called ions, roam freely. so True.
Explanation: hope this helps!