How much kinetic energy does a 0.104 kg hamster have if it is moving at 24.0 m/s?

When the temperature of the ocean is 80°F what is likely to develop is Hurricane. That is option D.

Hurricane is a natural disaster that occurs over the tropical large water bodie such as the oceans which is characterized by low-pressure storm.

The factors that can cause the occurrence of hurricane include the following;

Therefore, when the temperature of the ocean is 80°F what is likely to develop is Hurricane.

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Answer: thunderstorm

Explanation:

When the sea surface is at least 80° Fahrenheit (27° Celsius), it can supercharge a thunderstorm. The storm sucks up that heat and water, which make the storm bigger. As it grows, air pressure at the center of the storm continues to drop, which causes the vacuum in the middle to grow stronger.

Answer:

the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

Explanation:

 Given the data in the question;

first we determine the rotational latency

Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms

To get the longest time, lets assume the sector will be found at the last track.

hence we will access all the track, meaning that 127 transitions will be done;

so the track changing time = 127 × 15 = 1905 ms

also, we will look for the sectors, for every track rotations that will be done;

128 × 8.33 = 1066.24 ms

∴The Total Time = 1066.24 ms + 1905 ms

Total Time = 2971.24 ms

Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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Answer:

no it's not

Explanation:

it's closer to 1.30 than 1.04

The time taken to get up and out of the way before you and the child collide is 2.82 s.

The time taken to get up and out of the way before you and the child collide is calculated as follows;

s = v + ¹/₂at²

s = v + ¹/₂(g sin (31)t²

where;

The time taken to get up is calculated as;

20 = 0 +  ¹/₂(9.8 sin (31)t²

20 = 2.524t²

t² = 20/2.524

t² = 7.925

t = 2.82 s

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The tension in the rope being pulled by you and your friend is; E : None of the above

To solve this question, we need to first quote newton's third law of motion which states that;

To every action, there is an equal and opposite reaction.

Now, we are told that you pulled a rope with a force F. This means there will be an equal and opposite force being used by your friend also pulling the rope which will be -F.

Now, the tension on the rope will be the net force on the rope.

Thus;

Net force = Tension in rope = F + (-F)

Tension in rope = 0 N

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Answer:

I think its B

Explanation:

Hope this helps

Answer:

The diameter is \(d = 8.18*10^{-19} \ m\)

Explanation:

From the question we are told that

   The value of one atomic mass unit is \(u = 1.66 *10^{-27} \ kg\)

    The density of the proton is  \(\rho = 5.8 *10^{27} \ kg/m^3\)

Generally the volume of the proton (sphere)is mathematically represented as

     \(V = \frac{4}{3} * \pi * r^3\)

Generally this volume can also be evaluated as

      \(V = \frac{u}{\rho}\)

=>   \(V = \frac{1.66 *10^{-27}}{5.8*10^{27}}\)  

=>   \(V = 2.862 *10^{-55} \ m^3\)

So

\(2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3\)

=>   \(r^3 = 6.832 *10^{-56}\)

=>  \(r = 4.088 *10^{-19} \ m\)

Now the diameter is mathematically represented as

    \(d = 2 * r\)

=> \(d = 2 * 4.088 *10^{-19}\)

=> \(d = 8.18*10^{-19} \ m\)

When the masses of the blocks are doubled and the force applied is constant, the tension in the string will be the same.

The given parameters:

The acceleration of the blocks is calculated as follows;

\(a = \frac{F}{m + 2m} \\\\a = \frac{F}{3m}\)

The tension in the string is calculated as follows;

\(T = ma\\\\T = m(\frac{F}{3m)}\\\\T= \frac{F}{3}\)

When the masses of the blocks are doubled and the force applied is constant;

\(a = \frac{F}{2m + 4m} \\\\a = \frac{F}{6m}\)

The new tension in the string is calculated as follows;

\(T_2 = ma\\\\T_2 = (2m) (\frac{F}{6m} )\\\\T_2 = \frac{F}{3} = T\)

Thus, when the masses of the blocks are doubled and the force applied is constant, the tension in the string will be the same.

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Answer: B. A light in a swimming pool comes on after dark to prevent

accidents in the water.

If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.

Option A is correct.

impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.

If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.

Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.

As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.

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We have that for the Question "Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw"

It can be said that

From the question we are told

weights are = 300 N and 500 N

length l = 6 m

take x distance from the 300 N

total torque is zero

\(300*3 = 500x\\\\x = 1.8 m\)

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The total drag force acting on a sphere with a diameter of 12 cm and exposed to airflow at 1 atm and 5°C is therefore measured to be 5.2 N. Therefore, the friction drag coefficient is 0.0115.

When determining whether a flow pattern is laminar or turbulent while passing through a pipe, Reynolds number, a dimensionless quantity, is used. The relationship between inertial and viscous forces is what determines the Reynolds number. Friction is caused by surface irregularity, according to observations made at the microscopic level. Variety of Friction Friction can be divided into two categories, which are as follows: internal rubbing

Cdf = 0.2*0.3/5.2

Cdf = 0.06/5.2

Cdf = 0.0115

when 5.2/0.3 = 0.2

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Answer:

A

Explanation:

Myra is struggling to be a great wife, attentive mother, and an innovative designer all at the same time.

Myra's scenario is most accurately represented by role conflict because she  is struggling to be a great wife, attentive mother, and an innovative designer all at the same time.

When there are expectations put on an individual that are not compatible with one another in relation to their profession or position, this may lead to role conflict. When a someone feels as if they are being tugged in several ways while attempting to react to the multiple statuses they hold, they are experiencing role conflict.

The work-family conflict, also known as the struggle one has when torn between the demands of personal and professional responsibilities, is perhaps the clearest illustration of role conflict.

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(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

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The energy lost to friction and air resistance is 186 J.

option B.

The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.

The initial potential energy of the pendulum at the initial position is calculated as;

PEi = mghi

where;

P.Ei = 12 kg x 9.8 m/s² x 20 m

P.Ei = 2,352 J

The final kinetic energy of the pendulum is calculated as follows;

K.Ef = 0.5 x 12 kg x (19 m/s)²

K.Ef = 2,166 J

ΔE = 2,166 J - 2,352 J

ΔE = -186 J

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Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer:

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Explanation:

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At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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The brightness of a source with luminosity L is given by:

Suppose that expression represents the original brightness if we increase the distance four times, then the new brightness is given by:

This means that the brightness will decrease by 16 times. Therefore, the answer is D.

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.

Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.

The weight of the 100 kg object on the surface of the planet is approximately 8.9 × 10¹² Newtons.

To calculate the weight of a 100 kg object on the surface of a planet, we need to use the formula for gravitational force:

F = (G * M * m) / r²

Where:

F is the gravitational force (weight)

G is the gravitational constant (approximately 6.67430 × 10⁻¹¹ N m²/kg²)

M is the mass of the planet (4.8 × 10²⁴ kg)

m is the mass of the object (100 kg)

r is the radius of the planet (diameter / 2)

Given that the diameter of the planet is 12,000 km, we can find the radius by dividing it by 2:

r = 12,000 km / 2 = 6,000 km = 6,000,000 m

Now, we can substitute the values into the formula:

F = (6.67430 × 10⁻¹¹ N m²/kg² * 4.8 × 10²⁴ kg * 100 kg) / (6,000,000 m)²

Simplifying the expression:

F = (6.67430 × 10⁻¹¹ N m²/kg² * 4.8 × 10²⁶ kg) / 36,000,000,000 m²

F ≈ 8.9 × 10¹² N

Therefore, the weight of the 100 kg object on the surface of the planet is approximately 8.9 × 10¹² Newtons.

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Acceleration of the skydiver during the free fall is 4.13 m/s².

1) Mass of the skydiver, m = 83 kg

Weight, W = mg = 83 x 9.8

W = 813.4 N

Free fall acceleration is the acceleration that a body travelling in free fall experiences due to only the gravitational pull of the earth. This is the acceleration brought on by gravity.

Since there is no air resistance, the acceleration of the skydiver during the free fall is the acceleration due to gravity, g.

Freebody diagram is given in Fig.1.

2) Mass of the skydiver, m = 78 kg

Air resistance acting on him, F' = 470 N

mg - 470 = ma

813.4 - 470 = ma

a = 343.4/83

a = 4.13 m/s²

Freebody diagram is given in fig.2.

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Answer:

well its about our thinking but i do believe in ghost a little

Explanation:

Inertia refers to the tendency of an object to resist changes in its motion. In baseball terms, a baseball that is at rest on the ground has a high level of inertia because it is resistant to moving until an external force, such as a player's bat, acts on it.

Momentum, on the other hand, is the product of an object's mass and velocity and refers to the quantity of motion that an object possesses. In baseball terms, a baseball that is moving at a high velocity, such as when it is hit by a bat, has a high level of momentum.

To illustrate the difference between inertia and momentum in baseball, consider the scenario of a baseball that is hit by a bat. Before the bat hits the ball, the ball is at rest and has a high level of inertia. However, once the bat hits the ball, the ball gains momentum and begins to move. As the ball moves, it continues to possess momentum, but its inertia gradually decreases as it encounters external forces, such as air resistance and friction from the ground, which act to slow it down.

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Using Newton's second law and the universal gravitation law we find that the maximum acceleration response is

The universal law of Gravitation states that the force between two bodies is proportional to their masses and inversely proportional to the square of their distance

           F = \(G \frac{M m}{r^2}\)  

Where G is the universal gravitation constant (G = 6.67 10-11 N m²/kg²), M and m the mass of the bodies and r the distance between them

Newton's second law indicates that the force is proportional to the masses and the acceleration of the bodies

        F = m a

Where F is the force, m and a the mass and acceleration of the body     

let's substitute

         \(G \frac{Mm}{r^2}\)  = m a

         a = \(G \frac{M}{r^2}\)

In this case the acceleration is called centripetal since it corresponds to a circular motion of the Moon and the Earth.

In tables we can find the values:

Let's calculate the acceleration of the Moon around the Earth

      a₁ = 6.67 10⁻¹¹ \(\frac{5.98 \ 10^{24}}{ (3.84 \ 10^8 )^2 }\)

      a₁ = 2.71 10⁻³ m / s²

The acceleration of the Earth around the Sun  

      a₂ = 6.67 10⁻¹¹  \(\frac{1.991 \ 10^{30} }{(1.496 \ 10^{11})^2 }\)  

      a₂ = 5.93 10⁻³ m / s²

We can see that the acceleration around the Sun is twice the acceleration of the moon around the Earth

In conclusion they use Newton's second law and the universal gravitation law, we find that the maximum acceleration response is

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