how much is the pressure change in kpa as the pipe expands? the density of water is 1000 kg/m3. enter a positive value for an increase in pressure, a negative value for a decrease. kpa

Answer:

The water will be boiling

Explanation:

When water reaches 100⁰C the water will be boiling.

The glucose with the molecular formula of C₆H₁₂O₆ does not dissociates into the ions it will remain same as the molecule.

The glucose that is the C₆H₁₂O₆ is the covalent compound. The covalent compound is the compound which is formed in between the atoms or the molecules with the mutual sharing of the electrons. This compound contains the three non metallic  elements. When the non metal bond they will share the electron pairs and form the covalent compound. It is typical example of the nonelectrolyte. The Glucose is also known as the which sugar dissolves readily in water.

Thus, the glucose does not dissociates in to the ions it stays same as the molecule.

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The heat absorbed when 15.0 g of water freezes is 5.01 kJ.

Chemical reaction or physical change is endothermic if heat is absorbed by the system from the surroundings.

The heat absorbed or released during a phase change can be calculated using the equation q = mL,

where

For the case of 15.0 g of water freezing, the heat absorbed can be calculated as follows:

q = mL

q = (15.0 g) * (6.01 kJ/mol) / (18.015 g/mol)

q = 5.01 kJ

Therefore, the heat absorbed when 15.0 g of water freezes is 5.01 kJ.

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Answer:

Relative atomic mass = 35.5

Explanation:

Given data:

Abundance of Cl -35 = 75%

Abundance of Cl -25 = 25%

Average atomic mass = ?

Solution:  

Relative atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Relative atomic mass = (75×35)+(25×37) /100

Relative atomic mass =  2625 + 925 / 100

Relative atomic mass = 3550 / 100

Relative atomic mass = 35.5

P₂O₅ is an empirical formula

Given

compounds

Required

an empirical formula

Solution

The empirical formula is the smallest comparison of the atoms forming the compound.

Molecular formulas are formulas that show the number of atomic elements that make up a compound.

(empirical formula) n = molecular formula

1. P₂O₅ : the ratio of compounds cannot be further reduced to whole numbers⇒empirical formula

2. P₄O₆ : molecular formula

(P₂O₃)₂=P₄O₆

P₂O₃ : empirical formula

3.C₂H₄ : molecular formula

(CH₂)₂=C₂H₄

CH₂ : empirical formula

4. C₃H₆ : molecular formula

(CH₂)₃=C₃H₆

CH₂ : empirical formula

Answer:

P₂O₅

Explanation:

Answer:

Reflection: reflection is the process of returning of light into the same medium after striking a surface.

Answer:

BRO IM IN ONLY 7TH GRADE

Explanation:

The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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The freezing point of a solution of 60.0 g of glucose, dissolved in 80.0 g of water is  -7.67 ⁰C

Freezing point is the temperature at which a liquid turns into a solid. In theory, the melting point of a solid should be the same as the freezing point of the liquid.

At freezing point, these two phases viz. liquid and solid exist in equilibrium i.e. at this point both solid state and liquid state exist simultaneously. The freezing point of a substance depends upon atmospheric pressure.

Given,

Mass of Glucose = 60g

Mass of water = 80g

Moles of glucose = 60/ 180 = 0.33 moles

Molality = number of moles of glucose / mass of water in kg

= 0.33 / 0.08

= 4.12 molal

Depression in freezing point = Kf × molality

= 1.86 × 4.12

= 7.67 K

Freezing point of pure water = O⁰C

Freezing point of glucose = 0 - 7.67

= -7.67 ⁰C

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Answer:

Bohr's model of hydrogen is based on the nonclassical assumption that electrons travel in specific shells, or orbits, around the nucleus.

Explanation:

hope this helps and have a great day

A ligand is an atom or molecule that binds to a central atom or ion. The porphyrin ring Fe(II) ion in oxymyoglobin is coordinated by four nitrogen atoms from the porphyrin ring,

two oxygen atoms, and two histidine residues (distal and proximal). Therefore, all of the listed options are ligands.

In oxymyoglobin, the four nitrogen atoms of the porphyrin ring (tetrapyrole) are coordinated to the Fe(II) ion. These nitrogen atoms can be considered as donor atoms, donating electrons to the metal ion. The two oxygen atoms of the heme group and the two histidine residues (distal and proximal) are also donating electrons and thus considered as ligands. All of these atoms and molecules are involved in the coordination of the Fe(II) ion in oxymyoglobin and can be considered as ligands.

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Hydrochloric acid is a different kind of acid than chloric acid.

Ternary Acids (Oxy-acids) Ternary acids are also referred to as “Oxy-acids. Include hydrogen and oxygen and yet another (normally) nonmetallic detail. Those acids comprise each hydrogen and oxygen but their names make no reference to either hydrogen or oxygen.

A ternary acid is an acid that has the elements hydrogen and oxygen together with every other element, frequently a nonmetal. Or, they comprise hydrogen in addition to a polyatomic ion. An -ate complicated ion is named an -ic acid. as an example, HClO3(aq) consists of the chlorate ion and is known as chloric acid.

A binary acid is an acidic compound that always has hydrogen boned to every other chemical element, most of the time a nonmetal. Ternary acids are acidic compounds that comprise hydrogen and oxygen blended with some other detail. Binary acid has one style of a chemical element (hydrogen bonded to a nonmetal) .

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Answer:

The first one is Propane

The second one is HEPTANE

The third one is octane

The 4th is butane

the 5th is decane

The structures have been named according to IUPAC as \(\rm C_3H_8\) Propane, \(\rm C_7H_{16}\) Heptane, \(\rm C_8H_{18}\) Octane, \(\rm C_4H_{10}\) Butane, and \(\rm C_{10}H_{22}\) Decane.

The images has been the representation of the ball and stick structure of the compounds. The central balls have been the representation of the carbon atom , with small balls attached to the sticks have been the representation of the hydrogen attached.

The following structures has been given as:

The structures have been named according to IUPAC as \(\rm C_3H_8\) Propane, \(\rm C_7H_{16}\) Heptane, \(\rm C_8H_{18}\) Octane, \(\rm C_4H_{10}\) Butane, and \(\rm C_{10}H_{22}\) Decane.

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If compound X3P2 has a molar mass of 135 g/mol, the atomic weight of the unknown element would be 25, because,

The molar mass of a compound is determined by adding the atomic weights of the individual elements, keeping in mind that the atomic weight must also be multiplied the subscripts of each element. In the compound there are two elements, unknown element X and P, which is phosphorus. The total compound weight is 135 g/mol. Therefore this was calculated using the following steps:

⇒ 3 (atomic weight of X) + 2 (atomic weight of P) = 135 g/mol.

⇒ 3X + 2P = 135, so to solve for the atomic weight of unknown element X, the equation must be solved algebraically.

Subtract 2P from both sides: 3X = 135 - 2P,

Then divide by 3X, giving you the atomic weight of element X,

⇒ X = (135 - 2P) / 3

but, we know the atomic weight of P (phosphorous), which is 30.

Hence, X = (135 - 2 × 30) / 3

⇒ X = 75 / 3 ⇒ 25.

Therefore, the atomic weight of X is 25.

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Answer:

2.7*10^23

Explanation:

first work out the moles

So do 36g / 80 (80 is bromine's relative Atomic Mass number)

You have 0.45 M

Then, do 0.45 * 6.02*10^23

You get 2.7*10^23, which is your answer

The amount of CO that would be required to generate 635 g of CO2 will be 404.14 g

First, let us get the equation of the reaction:

\(2CO + O_2 -- > 2CO_2\)

From the equation, we can see that the mole ratio of CO to that of CO2 is 1:1.

635 g of CO2 is to be generated.

Mole of 635 g CO2 = mass/molar mass = 635/44.01 = 14.43 moles

Thus, the equivalent mole of CO required will also be 14.43 moles.

Mass of 14.43 moles CO = moles x molar mass = 14.43 x 28.01 = 404.14 g

Hence, 404.14 g of CO will be required to produce 635 g of CO2

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Answer:

6,461.44 sana po maka tulong

Answer:

Microwatts.

Explanation:

RF + EMF Unit Conversion Charts: Interpreting exposure levels. When measuring Radio Frequencies, the most common units of measurement are microwatts per square meter (µW/m2), microwatts per square centimeter (µW/cm2) and volts per meter (V/m).

Answer:

No units

Explanation:

In Thin Layer Chromatography (TLC), retention factor (Rf value) is found by taking the distance travelled by the spot divided by the distance of the solvent front. Rf value is a ratio of distances hence they have no units.

Mathematical derivation

The distance travelled by the spot is in cm, and that of the solvent front is also in cm. Thus, dividing the two units would give us no units for the Rf value.

What is TLC?

TLC is a technique used for separation and identification. The stationary phase is polar while the solvent is relatively nonpolar. Thus, the less polar substance is more attracted to the solvent (according to the principle of 'like attracts like') and travels further and thus have a higher Rf value.

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Increasing LED brightness with a lampshade or reflection and choosing LED lights with high luminous efficiency can be useful  to obtain a brighter lamp.

Lamp, lighting device, initially a jar housing a flame soaked in flammable substance, and later such light-producing devices as gas and electrical lamps.

The light was developed at least 70,000 years ago. Originally, it was a sunken rock filled in moss or other absorbent substance, saturated in animal fat, and burned. The ways to obtain a brighter lamp are

Increasing LED brightness with a lampshade or reflection.

To boost brightness, use greater color temperature LED lights.

Choosing LED lights with high luminous efficiency.

With increased voltage, LED lights get brighter.

Therefore, in above ways we can get brighter lamp.

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A) The number of H₂O molecules in 0.23 moles is equal to 1.5 × 10²³.

B) The single displacement reaction is,

Ca + 2HCl →  CaCl₂ + H₂

C)  The double displacement reaction is,

Na₂SO₄ + 2NH₄Cl → 2NaCl  + (NH₄)₂SO₄

A displacement reaction is one in which a set of atoms in a molecule are replaced by another set of atoms.

When an element leaves its compound or when one element is replaced by another from its own compound, a single displacement reaction can be demonstrated as a type of redox reaction.

In aqueous solutions, double displacement reactions take place where ions precipitate and exchange ions.

Hydrogen gas and calcium chloride are produced in a single displacement reaction between calcium and HCl acid.

Ca + 2HCl →  CaCl₂ + H₂

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Answer:

53.8g

Explanation:

plz let me know if the answer is right than I can explain it to u :)

Answer:

a. The gluing together of any two atoms that don't have full outer shells.

b. The separation of electrons from the main atom.

c. The joining of atoms by a shared interested of valence electrons which ends up

creating new substances.

d. The melting of substances to form new solids.

Explanation:

a. The gluing together of any two atoms that don't have full outer shells refers to chemical bonding, which can occur through different mechanisms such as covalent bonding, ionic bonding, and metallic bonding.

b. The separation of electrons from the main atom refers to ionization, where an atom or molecule loses or gains one or more electrons and becomes charged.

c. The joining of atoms by a shared interest of valence electrons which ends up creating new substances refers to covalent bonding, where atoms share electrons to form a stable molecule.

d. The melting of substances to form new solids does not necessarily create new substances; it is a physical change where a solid is transformed into a liquid due to an increase in temperature. Upon cooling, the liquid may solidify again, either forming the original substance or a different solid phase.

To determine the amount of water and methane needed, we can set up a system of equations based on the desired composition of the mixture. you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.

Let's assume x represents the number of gallons of water and y represents the number of gallons of methane. We have the following information: The total volume of the mixture is 90 gallons: x + y = 90. The mixture should be 60% methane: (y / (x + y)) * 100 = 60. Simplifying the second equation: y / (x + y) = 0.6. Now we can solve the system of equations: From equation 1, we can express x in terms of y: x = 90 - y. Substituting this into equation 2: y / ((90 - y) + y) = 0.6. Simplifying further: y / 90 = 0.6. Solving for y: y = 0.6 * 90. y = 54. Now we can find x using equation 1: x = 90 - y. x = 90 - 54. x = 36. Therefore, you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.

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Answer:

5

Explanation:

First find the balanced equation for this rxn

C3H8    +  5O2    ====>     3 CO2    + 4  H2O

To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. The correct option is option A.

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.

Propane gas, C\(_3\)H\(_8\), burns in excess oxygen gas. When the equation for this reaction is correctly balanced and all coefficients are reduced to their lowest whole-number terms, the coefficient for O\(_2\) is 5.

C\(_3\)H\(_8\)    +  5O\(_2\)  \(\rightarrow\)   3 CO\(_2\)    + 4  H\(_2\)O

Therefore, the correct option is option B.

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0.499 mol

Explanation: M(CaC2) = 64.1 g/mol, n= m/M = 32.0 g/ 64.1 g/ mol= 0.499 mol

Amount of Calcium hydroxide Is same

The answer C less active (or more noble) than hydrogen. This is because copper has a lower tendency to lose electrons and form cations compared to hydrogen. In other words, copper is a relatively stable element that is not as easily oxidized as hydrogen.

They can be seen in the electrochemical series, which ranks elements according to their tendency to undergo oxidation or reduction reactions. Hydrogen is located higher up on the series, indicating that it is more reactive and has a greater tendency to lose electrons and form cations. On the other hand, copper is located lower down on the series, indicating that it is less reactive and has a lower tendency to undergo oxidation. It is worth noting that copper can still undergo oxidation reactions under certain conditions. For example, when exposed to air and moisture, copper can slowly react to form copper oxide. Additionally, copper can be used as an anode in certain electrochemical cells, indicating that it is more anodic than some other metals. However, in general, copper is considered to be a relatively stable and unreactive element, particularly compared to hydrogen.

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Ascorbic acid is a diprotic acid, which means it can donate two protons (H+ ions) in an acid-base reaction. The student will need to add 12.68 mL of the 0.0700 M NaOH solution to reach the final equivalence point.

Ascorbic acid is a diprotic acid, which means it can donate two protons (H+ ions) in an acid-base reaction. To determine the volume of NaOH solution needed for neutralization, we need to calculate the number of moles of ascorbic acid and then use stoichiometry to find the corresponding moles of NaOH.

Given that the student weighed out 0.209 g of ascorbic acid, we can convert this mass to moles using the molar mass of ascorbic acid. The molar mass of ascorbic acid (C6H8O6) is 176.12 g/mol, so the number of moles of ascorbic acid is:

0.209 g / 176.12 g/mol = 0.001186 mol

Since ascorbic acid is diprotic, it will require twice the amount of NaOH to neutralize both protons. Therefore, the number of moles of NaOH needed is:

2 * 0.001186 mol = 0.002372 mol

To calculate the volume of NaOH solution needed, we can use the molarity (0.0700 M) and the number of moles of NaOH:

Volume of NaOH solution = (0.002372 mol) / (0.0700 mol/L) = 0.03389 L = 33.89 mL

Rounding to the correct number of significant digits, the student will need to add approximately 12.68 mL of the 0.0700 M NaOH solution to reach the final equivalence point.

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Answer:

2 Al + 3 Pb(NO3)2 > 2 Al(NO3)3 + 3 Pb

Explanation:

The intermolecular forces present between two molecules of HI (hydrogen iodide) are dispersion forces (also known as London dispersion forces). Therefore, the correct answer is A) dispersion only.

Dispersion forces are the weakest type of intermolecular forces and occur between all molecules, regardless of their polarity. These forces result from temporary fluctuations in electron distribution, leading to the formation of temporary dipoles. In the case of HI, both hydrogen and iodine atoms have electrons that are constantly in motion, causing temporary imbalances in electron distribution and resulting in the formation of temporary dipoles.

The hydrogen iodide (HI) molecule consists of a hydrogen atom bonded to an iodine atom. Hydrogen has a relatively positive charge due to its low electronegativity, while iodine has a relatively negative charge due to its high electronegativity. This polarity within the molecule gives rise to a dipole-dipole interaction between HI molecules. However, in this case, the dipole-dipole interaction is not strong enough to be considered a significant intermolecular force.

Instead, the dominant intermolecular force between HI molecules is dispersion forces. Dispersion forces occur due to temporary fluctuations in electron distribution. In the case of HI, the movement of electrons creates temporary dipoles, resulting in attractive forces between neighboring molecules. Since dispersion forces are present between all molecules, regardless of their polarity, they are the primary intermolecular force in HI. Other intermolecular forces such as hydrogen bonding or dipole-dipole interactions are not significant in HI molecules.

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