Answer:
c
Explanation:
In a physics lab, you apply a 34.5 N rightward
force to a 4.52 kg cart to accelerate it across a
horizontal surface at a rate of 1.28 m/s/s.
Determine the friction force acting upon the cart
and coefficient of friction.
Answer:
Explanation:
The frictional force is
=
28.71
N
Explanation:
Let
F
r
=
frictional force
and
F
=
the force applied
The net force acting on the object is
(
F
−
F
r
)
By Newton's second Law
(
F
−
F
r
)
=
m
a
where,
a
=
the acceleration
and
m
=
mass of the cart
So,
F
−
F
r
=
m
a
F
r
=
F
−
m
a
=
34.5
−
4.52
⋅
1.28
=
28.71
N
An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2. What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2 . What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
–1.6 × 103 N
–1.63 × 103 N
–2.4 × 103 N
–5.27 × 104 N
The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N
How do I determine the gravitational force?The gravitaional force between two objects can be obtained by using the following formula:
F = GM₁M₂ / r²
Where
F is the gravitaional force G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from he question:
Mass of satellite (M₁) = 5400 = 5.4×10³ KgHeight (h) = 30000 km = 30000 × 1000 = 30000000 mMass of Earth (M₂) = 6.0×10²⁴ KgRadius of Earth (R) = 6400 km = 6400 × 1000 = 6400000 mDistance apart (r) = R + h = 6400000 + 30000000 = 36400000 mGravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²Gravitational force (F) =?The gravitaional force can be obtained as shown below:
F = GM₁M₂ / r²
F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²
F = 1.63×10³ N
Thus, the gravitational force is 1.63×10³ N
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A 1.5 kg 8-Ball is traveling at 2.3 m/s to the right when it strikes and bounces off a 5.2 kg bowling ball which is at rest. After the collision, the 8-Ball moves to the left with a velocity of 1.1 m/s. What is the final velocity of the bowling ball?
_______________m/s (nearest hundredth)
Answer:
-0.34m/s
Explanation
According to the law of conservation of momentum
m1u1 +m2 u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v s the common velocity
Given
m1 = 1.5kg
m2 = 5.2kg
u1 = 2.3m/s
u2 = -1.1m/s (left direction)
Required
Final velocity v of the ball
Substitute into the formula
1.5(2.3)-5.2(1.1) = (1.5+5.2)v
3.46-5.72 = 6.7v
-2.26 = 6.7v
v = -2.26/6.7
v = -0.34m/s
Hence the final velocity of the bowling ball is 0.34m/s towards the left
A real image can be obtained with:
A convex lens and a convex mirror
A concave lens and a concave mirror
A convex lens and a concave mirror
A concave lens and a convex mirror
Answer:
convex lens and a concave mirror
Answer:
c on edge
Explanation:
To tighten a spark plug, it is recommended that a torque of 20 be applied. If a mechanic tightens the spark plug with a wrench that is 35 long, what is the minimum force necessary to create the desired torque?
the minimum force necessary to create the desired torque is approximately 57.14 Newtons.
To calculate the minimum force necessary to create the desired torque, we can use the formula:
Torque = Force * Distance
Given:
Desired torque = 20 N·m
Length of the wrench = 35 cm = 0.35 m
Force = ?
Rearranging the formula, we can solve for the force:
Force = Torque / Distance
Substituting the given values:
Force = 20 N·m / 0.35 m
Force ≈ 57.14 N
Therefore, the minimum force necessary to create the desired torque is approximately 57.14 Newtons.
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Hey everyone,
right now
I want you to stop
stop whatever you are doing
walk to a mirror
look in it
look at your face
your gorgeous face
look at your eyes
how they shine
look at your hair
it's perfect
you are beautiful
I hope you realize
you are pretty freakin amazing <3
Answer:
oooh thanks
Explanation:
..................
Answer:
awwww thx you are to :)
Explanation:
what is the minimum serving temperature for grilled chicken fillets?
The minimum serving temperature for grilled chicken fillets, as recommended for food safety, is 165°F or 74°C.
Chicken, including fillets, should be cooked thoroughly to ensure that harmful bacteria, such as Salmonella and Campylobacter, are destroyed. Cooking chicken to an internal temperature of 165°F (74°C) ensures that it is safe to consume and reduces the risk of foodborne illnesses.
Using a food thermometer is the most accurate way to determine the internal temperature of grilled chicken fillets. Insert the thermometer probe into the thickest part of the fillet without touching the bone, and make sure it reads at least 165°F (74°C) before considering the chicken fully cooked and safe to eat.
It is crucial to maintain proper cooking temperatures to ensure food safety and prevent the transmission of foodborne pathogens.
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the question is confusing
Alpha particles have highest mass.
Alpha particles are most ionising.
Gamma particles are the most penetrating.
Beta particles are negatively charged.
Gamma particles have the highest speed.
Comparing the three types of ionizing radiation-alpha particles have the greatest mass. Alpha particles have approx 4 times the mass of a proton or neutron and 8,000 times the mass of a beta particle. Ionising power of alpha particle is very high due to double positive charge, large mass as compared to a beta particle. Alpha particles can cause multiple ionisations within a very small distance. Beta radiation is more penetrating than alpha radiation. beta radiation can pass through the skin, but it is absorbed by a few cm of tissue of the body or a few mm of aluminum. Gamma radiation is the most penetrating of the three radiations. Alpha particles are positively charged, while beta particles are negatively charged, and gamma radiation is electrically neutral. Gamma rays are similar to visible light but they have higher energy. Gamma rays are emitted along with alpha or beta particles during radioactive decay.learn more about gamma rays here:
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If a wave has a speed of 362 m/s and a period of 4.17 ms, its wavelength is closest to
O A. 1.51 m
B.0.0115 m
OC. 86.8 m
OD. 1510 m
Answer:
Option A (1.51 m) is the appropriate option.
Explanation:
The given values are:
Speed of wave,
= 362 m/s
Period,
= 4.17
Now,
⇒ \(v=\frac{\lambda}{T}\)
then,
⇒ \(\lambda=vT\)
⇒ \(= 362\times 4.17\times 10^{-3}\)
⇒ \(=1.51 \ m\)
a 3.89 ωω resistor, a 7.75 ωω resistor, and a 9.05 ωω resistor are connected in series with a 12.0 v battery. what is the equivalent resistance?
The equivalent resistance of the 3.89 Ω, 7.75 Ω, and 9.05 Ω resistors connected in series with a 12.0 V battery is 20.69 Ω.
The equivalent resistance of resistors connected in series is equal to the sum of the resistance of each resistor. Therefore, the equivalent resistance is: R = 3.89 Ω + 7.75 Ω + 9.05 Ω = 20.69 Ω
So, the equivalent resistance of the 3.89 Ω, 7.75 Ω, and 9.05 Ω resistors connected in series with a 12.0 V battery is 20.69 Ω.
The equivalent resistance of an electrical circuit refers to the single resistance that would have the same effect as the combination of multiple resistors in the circuit. It is a measure of the total opposition to current flow in the circuit. The equivalent resistance can be found by using various methods such as series, parallel, and combination circuits. The equivalent resistance of a circuit depends on the individual resistances, the connections between them, and the voltage and current in the circuit.
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subtract 14/3 from 5
\(subtact14 \3 from5\)
What is the disadvantage of the circuit pictured below
A._ The addition of more light bulbs decreases the flow of electricity through the circuit.
B._ The addition of more light bulbs decreases the voltage to each bulb.
C._ The addition of more light bulbs decreases the resistance in the circuit.
D._ The circuit only works when alternating current is used.
The circuit shown has the drawback that it can only operate with alternating current.
The correct answer is D
What exactly do you mean by "alternating current"?A type of electrical current known as alternating current (AC) alternates the flow of electrons periodically or in cycles between two directions. Alternating current (AC) is the kind of current that circulates through electrical outlets used in everyday homes and power lines.
How do AC & DC current differ from one another?Both alternating current (AC) and direct current (DC) are types of electric current (DC). The way that electrons move determines how AC and DC are different from one another. While the flow of electrons in AC is constantly changing, moving first ahead and then backward, as opposed to DC's steady movement in one direction
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The Sex Equity in Education Act requires educational institutions to distribute a sexual harassment policy to:
A._ faculty and parents.
B._parents and administrators. C._students and administrators.
D._faculty and students.
A charge of 6.5 x 10-5 C is attracted by another charge with a force of 250 N when
they are separated by 0.15 m. Find the magnitude of the other charge.
8.65 X 105 C
9.62 × 10-2 C
6.15 x 10-6 C
O 9.62 x 10 c
Answer:
We can use Coulomb's law to solve this problem:
F = k * q1 * q2 / r^2
where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.
We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:
q2 = F * r^2 / (k * q1)
Substituting the values we have:
q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)
Simplifying:
q2 = 8.65 x 10^5 C
Therefore, the magnitude of the other charge is 8.65 x 10^5 C.
What is the equation that shows the inverse relationship between wavelength and frequency?
Answer:
V = f * λ velocity equals frequency * wavelength
If f is increased then λ must decrease for the velocity to remain constant.
What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes through a diffraction grating that has 500.0 lines per mm?
236 nm
353 nm
943 nm
1414 nm
Answer:
D) 1414 nm
Explanation:
This is correct on Edge.
Using the equation dsin(angle)=n(wavelength), we can solve for wavelength.
First we must convert the 500 lines per mm to nm. We do this by 1/500, giving you 0.002. Then move the decimal over six places to the right, resulting in 2000.
Then by plugging in the other values, we have 2000sin(45)=1(wavelength).
N is one because we are just solving for a first-order band.
So 2000sin(45)=wavelength
By using a calculator, we can see that the wavelength equals approximately 1414nm.
I hope this helped. If it did, I would really appreciate a Brainliest!!
Have a great day:)
Answer:
1414
Explanation:
took the test :)
Unbalanced forces acting on an object produce a change in the object's __________
An unbalanced force acting on an object results in the object's motion changing. The object may change its speed (speed up or slow down), or it may change its direction. Friction is a force that resists the motion or the tendency toward motion between two objects in contact with each other.
motion
Answer:
motion. FILLER FILLER FILLER
Why is an object’s mass, rather than its weight, used to indicate the amount of matter it contains?.
An object's mass, rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force due to an existing field (In most cases, gravitational field) that is experienced by the body. The weight of the same body can be different in different environments it's observed.
However, the mass of the body is the exact measure of the amount of matter contained in a body. Which is constant, regardless of the environment, or conditions the body is observed.
Hence, for real-world calculations and experimentation, the mass of the body is considered to represent the amount of matter it contains rather than its weight.
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calculate the effective value of g , the acceleration of gravity, at 3500 m above the earth's surface. express your answer to three significant figures and include the appropriate units
Therefore, the effective value of g at 3,500 m above the Earth's surface is approximately 9.40 m/s^2
The acceleration due to gravity (g) decreases with increasing altitude above the Earth's surface. The formula to calculate the effective value of g at a height h above the Earth's surface is:
g_eff = g * (R / (R + h))^2
where g is the acceleration due to gravity at the Earth's surface, R is the radius of the Earth, and h is the height above the Earth's surface.
The acceleration due to gravity at the Earth's surface is approximately 9.81 m/\(s^2\). The radius of the Earth is approximately 6,371 km or 6,371,000 m.
At a height of 3,500 m above the Earth's surface:
g_eff = 9.81 m/\(s^2\) * (6,371,000 m / (6,371,000 m + 3,500 m))\(^2\)
g_eff = 9.40 m/\(s^2\)
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A body is thrown vertically upward with velocity 20m/s .How long time it remains in air? (g=10m/s2)
Answer:
\(\boxed{\sf Time \ being \ in \ which \ body \ remains \ in \ air = 4 \ s}\)
Given:
Velocity (u) = 20 m/s
Acceleration due to gravity (g) = 10 \(\sf m/s^2\)
To Find:
Time (t) being in which body remains in air.
Explanation:
Formula:
\(\boxed{\bold{\sf t=\frac{2u}{g}}}\)
Substituting values of u & g in the equation:
\(\sf \implies t = \frac{2 \times 20}{10}\)
\(\sf \implies t =\frac{40}{10}\)
\(\sf \implies t =\frac{4 \times \cancel{10}}{ \cancel{10}}\)
\(\sf \implies t = 4 \ s\)
\(\therefore\)
Time (t) being in which body remains in air = 4 seconds
A monoatomic ideal gas at initial state A occupies 7,0 dm³ at a temperature of 300 K and a pressure of 200 kPa. The gas is compressed to 1/7 of its original volume to state B, then cooled at constant volume at 300 K to state C, and finally allowed to expand isothermally to its initial state A, such that the cycle is A-B-C-A. On the pV diagram, B is represented by a horizontal line. the process A 1 Question: Calculate the work WAB done by or on the gas during the process A - B
The gas is compressed to 1/7 of its original volume, but since the process is horizontal, there is no change in volume. Hence, no work is done during the process A to B.
Therefore, the work done (WAB) during the process A to B is zero.
The work done by or on the gas during the process A - B can be calculated using the following formula: WAB = -∫PdV where P = pressure, and V = volume. To calculate WAB, we need to calculate the integral of PdV. Since B is represented by a horizontal line, the pressure P is constant. Therefore, WAB = -P∫dVWhere, ∫dV is the integral of dV from the initial volume Vi to the final volume Vf.
The gas is compressed from state A to state B. Therefore, the initial volume Vi = 7.0 dm³ and the final volume Vf = 1/7 * 7.0 dm³ = 1.0 dm³.WAB = -P ∫dV = -P(Vf - Vi)WAB = -200 kPa (1.0 dm³ - 7.0 dm³) = 1200 JThe work done by the gas during the process A - B is -1200 J.
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on an icy day your worry about parking your car in a driveway
(a) By solving the diffusion equation for a planar source the diffusion kernel for an infinite slab of thickness a is given by located at x, show that - x sinh
(b) Using this kernel calculate the flux in a slab containing uniformly distributed sources emitting S neutrons/cm3-sec.
The one-dimensional diffusion equation or Fick's second law is the name of this equation. For the geographically and temporally variable concentration, it is solvable.
A diffusion explanation is what?
The movement of molecules along a concentration gradient is known as diffusion. It is a significant process that all living things go through. Diffusion facilitates the flow of materials into and out of cells.
Which definition of diffusion is the best?
Diffusion is the movement of molecules from a region where they are more concentrated to one where they are less concentrated. Therefore, "Movement of molecules from a region of their greater concentration to a region of their lower concentration" is the right response.
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1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"
Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.
To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.
The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).
Using the equation:
v = v₀ + at
where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:
v = 0 + (0.75 m/s²) * t
v = 0.75t m/s
The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:
v = ωr
Substituting the values:
0.75t = ω * 300
Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:
ω = ω₀ + αt
ω = 0 + (0.75 m/s²) * t
ω = 0.75t rad/s
We can now substitute the value of ω into the equation:
0.75t = (0.75t) * 300
Simplifying the equation gives:
0.75t = 225t
t = 0.75 seconds
The time elapsed is 0.75 seconds.
To calculate the distance traveled (s), we can use the equation:
s = v₀t + (1/2)at²
Since the initial velocity (v₀) is zero, the equation becomes:
s = (1/2)at²
s = (1/2)(0.75 m/s²)(0.75 s)²
s = (1/2)(0.75 m/s²)(0.5625 s²)
s = 0.2119 meters or approximately 21.19 centimeters
Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.
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Please the answer with steps
Answer:
Is safe to use the bag.
Explanation:
To solve this problem we must use Newton's second law which tells us that the resulting force is equal to the product of mass by acceleration.
F = m*a
where:
F = force [N] (units of Newtons)
m = mass = 15 [kg]
a = acceleration = 7 [m/s²]
Now replacing these values in the previous equation:
F = 15*7
F = 105 [N]
F < 230 [N]
The force of 105 [N] is lesser than the maximum resistance force, therefore is safe to use the bag.
A graduate student is trying to follow the weather on Jupiter for her PhD thesis. To see the big weather patterns in the upper atmosphere of the planet, she needs to have excellent resolution. What type of telescope would be best for her to use? a. a refractor, with as small an aperture as possible b. a radio telescope c. a large reflector in an observatory located at sea level d. a large reflector located in orbit above the Earth's atmosphere e. you can't fool me, all these telescopes have the same resolution
Answer: large reflector located in orbit above the Earth's atmosphere
Explanation:
Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.
It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.
Using the diagram above, the coefficient of kinetic friction for copper is ____ (Your answer should be given to the nearest thousandths.)
This coefficient _____ applies to all similar copper surfaces.
Answer:
μ= 0.0375, kinetic
Explanation:
For this exercise we set a reference system with the x axis parallel to the chord
Y axis
N - W = 0
N = W
X axis
T - fr = 0
the expression for the friction force is
fr = μ N
we substitute
T - μ W = 0
μ = T / W
we calculate
μ = 1.5 / 40
μ= 0.0375
coefficient of kinetic friction
how much time will pass when it goes from one-half initial voltage to one-fourth its initial voltage
The time taken is twice the time taken to decrease from the initial voltage to one-half initial voltage.
How much time will pass when it goes from one-half initial voltage to one-fourth its initial voltage?The amount of time it takes for a voltage to decrease from one level to another depends on the characteristics of the system generating the voltage.
Assuming that the voltage is decreasing exponentially over time, the time it takes for a voltage to decrease from one level to another can be calculated using the formula:
\(t = -(ln(Vf/Vi))/λ\)
where t is the time taken, Vi is the initial voltage, Vf is the final voltage, and λ is the decay constant of the system generating the voltage.
If the voltage decreases from one-half its initial voltage to one-fourth its initial voltage, then \(Vi = 1, Vf = 1/4\), and the voltage has decreased by a factor of 2.
Assuming that the decay is exponential, the time it takes to decrease by a factor of 2 is:
\(t = -(ln(1/2))/λ\)
We can simplify this expression using the fact that \(ln(1/2) = -ln(2)\), which gives:
\(t = ln(2)/λ\)
Similarly, the time it takes to decrease by a factor of 4 is:
\(t = -(ln(1/4))/λ = ln(4)/λ = 2ln(2)/λ\)
So, the ratio of the time taken to decrease from one-half initial voltage to one-fourth initial voltage is:
\(t(1/4) / t(1/2) = (2ln(2)/λ) / (ln(2)/λ) = 2\)
Therefore, the time taken to decrease from one-half initial voltage to one-fourth initial voltage is twice the time taken to decrease from the initial voltage to one-half initial voltage.
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a 1500-nfnf capacitor with circular parallel plates 2.0 cmcm in diameter is accumulating charge at the rate of 39.0 mc/smc/s at some instant in time. part a what will be the induced magnetic field strength 9.5 cmcm radially outward from the center of the plates?
The induced magnetic field strength 9.5cm radially outward from the center of the plates is 821.052 Tesla.
We know very well that when a charge is moving with some speed in particular direction then, it will induce a magnetic field around its environment. Only moving charge is able to produce magnetic field, stationary charge only produce electric field.
We know that magnetic field is given by=(μ/2πr)×(q/t) where
μ is called as magnetic field constant,
q is the induced charge in the capacitor,
and r is the distance between the two plates
So, we have r=9.5cm=0.095m,(q/t) =39C/sec and μ=4π×10⁻⁷Tesla-m/A.
So, on putting the above values, we get
=>B=(4π×10⁻⁷ × 39)/2π×0.095
=>B=2×39/ 0.095
=>B=78/0.095
=>B=821.052Tesla.
Hence, induced magnetic field is 821.052Tesla.
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