how much force must you and your friend each apply to the free end of the door on the same side and perpendicular to the plane of the door in order to produce the same torque as that produced by both of you in part (a) above?
Answers
Answer:
(If you find this answer helpful, i would appreciate if u gave brainliest but otherwise, I hope this helped ^^)
Explanation:
To produce the same torque as that produced by both you and your friend in part (a), you would need to apply forces in opposite directions but with the same magnitude. This ensures that the torques created by the two forces cancel each other out, resulting in a net torque of zero.
Since torque is the product of the force and the perpendicular distance from the pivot point, the forces you and your friend apply should be inversely proportional to the distances from the pivot point.
If you and your friend are applying forces at the same distance from the pivot point, then the forces you need to apply should be equal. However, if you and your friend are at different distances from the pivot point, the force required for each person would depend on their respective distances.
In general, to determine the specific force required for each person, you would need to know the distances of both you and your friend from the pivot point. With that information, you can calculate the required force using the equation:
Force = Torque / Distance
By applying forces in opposite directions but with the same magnitude and ensuring that the torques cancel each other out, you and your friend can produce the same torque as in part (a) with your individual forces.
Related Questions
Determine the forces in members abab and cbcb of the truss, and use the correct signs to state if the members are in tension or compression. Set θθ = 30 ∘∘
Answers
The forces in members ab and cb are 4 kN (compression) and 2.3094 kN (tension), respectively.
Given, θ = 30°; Load P = 4 kN
Let's find out the force in member AB:
As the load P is applied at joint B, the horizontal force in member AB will be equal to the force P. Thus,
HAB = P = 4 kN
Now, to find out the force in member CB, let's resolve forces horizontally and vertically at joint B.
Horizontal equilibrium: HCB - P = 0
HCB = P = 4 kN
Vertical equilibrium: VCB - HAB * tanθ = 0
VCB = HAB * tanθ = 4kN * tan30°
VCB = 2.3094 kN
Now, let's resolve forces at joint C.
Vertical equilibrium: VCA - VCB - 2 kN = 0
VCA = VCB + 2 kN
VCA = 2.3094 kN + 2 kN
VCA = 4.3094 kN
The forces in members AB and CB are 4 kN and 2.3094 kN, respectively.
Members AB and CB are in compression and tension, respectively.
Thus, the forces in members ab and cb are 4 kN (compression) and 2.3094 kN (tension), respectively.
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There is an attachment. There is an attachment on here.
Answers
Answer:
5 i think
Explanation:
What is constant in the horizontal direction for a projectile?
Answers
Answer:
initial velocity is the constant in horizontal projectile
In a second order lever system the force ratio is 2.5, the load is at the distance of 0.5m from the fulcrum find distance of effort if it losses are negligible
Answers
Answer:
1.25 m
Explanation:
From the question given above, the following data were obtained:
Force ratio = 2.5
Distance of load from the fulcrum = 0.5 m
Distance of effort =.?
The distance of the effort from the fulcrum can be obtained as illustrated below:
Force ratio = Distance of effort / Distance of load
2.5 = Distance of effort / 0.5
Cross multiply
Distance of effort = 2.5 × 0.5
Distance of effort = 1.25 m
Therefore, the distance of the effort from the fulcrum is 1.25 m
A 1000 kg race car rounds a curve with a radius of 50 m.
Find the magnitude of the centripetal force acting on the car
when it rounds the curve at 15 m/s.
Answers
Answer:
5644556677888777766554433
A ball rolls off the top of the roof of a building that is 13 meters tall. Calculate the amount of time it takes for it to hit the ground.
Answers
Answer:
The ball takes \($t=1 \cdot 917sec$\) to hit the ground.
Explanation:
• The second equation of motion represents the total distances travelled by an object in a time interval of \($\Delta t$\) with an initial speed of \($u$\) and acceleration \($a$\).
• To find the time, ball takes to hit the ground, use the formula: \($$s = ut + \frac{1}{2}a{t^2}$$\)
Where, \($t$\) is time, \($u$\) is initial velocity, \($a$\) is acceleration and\($s$\) is displacement.
• In this case, \($a = g = 9 \cdot 8m/se{c^2}$\).
• Placing the value of the given initial velocity, \($u=0cm/s$\) and displacement,\($s = 13m$\) in the above formula.
\(& \therefore s = ut + \frac{1}{2}g{t^2} \\& \Rightarrow 13 = 0 \cdot t + \frac{1}{2} \times 9 \cdot 8 \times {t^2} \\\)
\(& \Rightarrow 13 = 4 \cdot 9{t^2} \\& \Rightarrow {t^2} = \frac{{13}}{{4.9}} \\& \Rightarrow t = 1 \cdot 917sec \\\end{align}\]\)
• Hence, ball takes \($t=1 \cdot 917sec$\) to hit the ground.
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A 10 kg mass is lifted to a height of 2 meters. What is the potential energy at this position?
Answers
Answer:
m=10kg h=2m Ep=mgh Ep=(10kg)(9.8 m/sec2)(2m)
Ep=196J
Explanation:
The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.
Explanation:
The force of electrostatic repulsion between two small positively charged objects, A and B, is 3.6 x 10⁻⁵ N when AB = 0.12m. What is the force of repulsion if AB is increased to 0.24 m
Answers
Given data:
* The electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=3.6\times10^{-5}\text{ N}\)* The distance between the charged bodies in the initial state is,
\(d=0.12\text{ m}\)* The distance between the charged bodies in the final state is,
\(\begin{gathered} d^{\prime}=0.24\text{ m} \\ d=2\times0.12 \\ d^{\prime}=2d \end{gathered}\)Solution:
According to Coulomb's law, the electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=\frac{kq_1q_2}{d^2}\)where k is the electrostatic force constant, q_1 is the charge on the first charged body and q_2 is the charge on the second charged body,
The electrostatic force of repulsion between the charged bodies in the final state is,
\(\begin{gathered} F^{\prime}=\frac{kq_1q_2}{(2d)^2} \\ F^{\prime}=\frac{kq_1q_2}{4d^2} \\ F^{\prime}=\frac{1}{4}\times\frac{kq_1q_2}{d^2} \\ F^{\prime}=\frac{F}{4} \end{gathered}\)Substituting the known values,
\(\begin{gathered} F^{\prime}=\frac{3.6\times10^{-5}}{4} \\ F^{\prime}=0.9\times10^{-5}\text{ N} \end{gathered}\)Thus, the electrostatic force of repulsion between the charged bodies in the final state is,
\(\text{0}.9\times10^{-5}\text{ N}\)d+x 8. A wire of 2 mm cross-sectional area and 10.3 cm long contains 2x1020 electrons. It has a 10 2 resistance. What is the drift velocity of the charges in the wire when 5 Volts battery is applied a
Answers
The drift velocity v will give us the answer.
\(v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))\)
\(v = (5 V) / (4x10^-14 m³) * (1.6x10^-19 C)?\)To find the drift velocity of charges in the wire, we can use Ohm's Law, which states that the current flowing through a conductor is directly proportional to the applied voltage and inversely proportional to the resistance. The equation for Ohm's Law is:
I = V / R
Where:
I is the current flowing through the wire,
V is the applied voltage (in this case, 5 Volts),
R is the resistance of the wire (given as 10^2 Ohms).
Now, we need to calculate the current flowing through the wire using Ohm's Law. The current is the rate at which charges (electrons) move through the wire. The equation for current is:
I = n * A * v * q
Where:
n is the number of charges per unit volume (given as 2x10^20 electrons),
A is the cross-sectional area of the wire (given as 2 mm² or 2x10^-6 m²),
v is the drift velocity of the charges (what we need to find),
q is the charge of each electron (1.6x10^-19 C).
Rearranging the equation and solving for v, we have:
v = I / (n * A * q)
Substituting the given values:
v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))
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In the first activity, Vehicle 2 has a greater acceleration than Vehicle 1, but has a less forceful engine. How can this be? Explain in terms of your equation.
Answers
Answer:
This can be explained by the equation Force=Mass x Acceleration. Vehicle 2 has a higher acceleration than Vehicle 1, which means it accelerates quicker. However, this increased acceleration is achieved by a less forceful engine. This is possible because Vehicle 2 has a lower mass than Vehicle 1, meaning the same force applied to Vehicle 2 results in greater acceleration. Therefore, Vehicle 2 has a greater acceleration than Vehicle 1 but has a less forceful engine.
g a student actor is wearing a purple costume on the theatrical stage. what color will the costume appear if a green light illuminates the student?
Answers
When a green light illuminates a purple costume on a theatrical stage, the color of the costume will appear as a darker shade of green. This is due to the subtractive color model, which states that colors are created when light is reflected off of an object and absorbed by the object.
In this case, the purple costume is reflecting green light and absorbing all other colors, resulting in a darker shade of green. This effect is even more dramatic when the light is brighter, resulting in a nearly black color.
The color of a costume is also affected by the lighting equipment used, such as the color and power of the light. This means that the costume’s color can be changed based on the lighting used on the stage.
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A stone is dropped from a height of 49m and simultaneously another ball is thrown upward from the ground with a speed of 40m/s. when and where do the two stone meet
Answers
Answer:
S1 = 1/2 g t^2 distance stone falls in time t
S2 = Vy t - 1/2 g t^2 distance thrown stone rises in time t
H = 49 = S1 + S2 = Vy t
t = 49 / 40 sec time when stones meet
Check:
Stone 1 falls: 1/2 g t^2 = 1/2 * 9.8 * (49 / 40)^2 = 7.35 m
Stone 2 rises : 40 * (49 / 40) - 1/2 * 9.8 (49 / 40)^2 = 41.65 m
what is the derived relationship between molar mass and delta t
Answers
The relationship between molar mass and delta t (Δt) is derived from the colligative properties of solutions. Colligative properties are those properties that depend on the number of solute particles in a given volume of solution, regardless of the type of solute particles.
One of the colligative properties is the freezing point depression, which is the difference between the freezing point of a pure solvent and the freezing point of a solution containing a solute. The freezing point depression is directly proportional to the molality (moles of solute per kilogram of solvent) of the solution, and inversely proportional to the molar mass of the solute. This can be mathematically expressed as Δt = Kf * m * (1/M), where Δt is the freezing point depression, Kf is the freezing point depression constant, m is the molality of the solution, and M is the molar mass of the solute. Therefore, as the molar mass of the solute increases, the freezing point depression decreases, and vice versa. This relationship can be useful in determining the molar mass of an unknown solute in a solution.
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An object starts at the 100 m mark and ends up at the -100 m mark, 50
seconds later. What was the velocity? *
Answers
The velocity is -4 m/s (negative because it travelled from 100 to -100 or backwards)
Not sure what i’m doing how do i do this??
Answers
Explanation:
Given:
v₀ = 25 m/s
v = 0 m/s
a = -9.8 m/s²
1a) Find t.
v = at + v₀
0 m/s = (-9.8 m/s²) t + 25 m/s
t = 2.55 s
1b) Find Δy.
v² = v₀² + 2aΔy
(0 m/s)² = (25 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 31.9 m
A police car emitting a siren wail (400 Hz) is driving at v/30 towards a suspect who is fleeing on foot at v/60, where v is the speed of sound. a.) Concept: The distance between the car and suspect Select overall, therefore the frequency observed by the suspect will be --Select- that emitted by the siren. b.) Calculate: What is the frequency the suspect hears? (Make sure your result agrees with part a Hz ---Select--- increases adi /3.5 points decreases a suspect who is fleeing on foot at police car emitting a siren wail ( sound. stays the same ) Concept: he distance between the car and suspect Select -Select- overall, therefore the frequency observed that emitted by the siren. .) Calculate: Vhat is the frequency the suspect hears? (Make sure your result agrees with part al) Hz Submit Answer Save Progress ---Select- higher than lower than the same as en wail (400 Hz) is driving at v/30 toward car and suspect -Select over Select--- that emitted by the siren. b.) Calculate: What is the frequency the suspect hears?
Answers
a) The distance between the car and the suspect decreases overall as the police car is driving towards the suspect. Therefore, the frequency observed by the suspect will be higher than that emitted by the siren.
b) To calculate the frequency the suspect hears, we need to consider the Doppler effect. The formula for the apparent frequency observed due to the Doppler effect is:
f' = (v + vr) / (v + vs) * f
Where:
f' is the apparent frequency observed,
v is the speed of sound,
vr is the velocity of the receiver (suspect),
vs is the velocity of the source (police car),
and f is the emitted frequency.
In this case, the suspect is fleeing on foot at v/60, and the police car is driving towards the suspect at v/30. Therefore, vr = v/60 and vs = -v/30 (negative because it's approaching). Plugging these values into the formula, we get:
f' = (v - v/60) / (v - (-v/30)) * 400 Hz
Simplifying further:
f' = (59v/60) / (31v/30) * 400 Hz
f' = 47.742 Hz
Therefore, the frequency the suspect hears is approximately 47.742 Hz.
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what mechanism causes hair cell depolarization as stereocilia bend in response to sound waves?
Answers
The mechanism that causes hair cell depolarization as stereocilia bend in response to sound waves is the tip links that connect adjacent stereocilia stretch, opening cation channels and allowing potassium ions to enter the cells, causing depolarization.
The auditory system's sensory receptors, hair cells, transform mechanical vibrations into electrical impulses the brain can understand. The hair cell membrane becomes depolarized due to the stereocilia of the hair cells bending in response to sound waves, which starts an action potential.
The basilar membrane's movement in the cochlea causes the stereocilia to bend in response to sound waves. The tallest stereocilia, known as "kinocilia," are positioned at one end of each row where the stereocilia are grouped in rows.
Positively charged ions, including potassium (K+), enter the cell when the channels open, depolarizing the membrane potential.
Nonetheless, it is evident that the mechanical stresses applied to the stereocilia are essential in starting the process. Research is still being done to determine the precise mechanism of ion channel opening and the nature of the channels involved in hair cell depolarization.
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Consider the reaction below:
AgNO3 (aq) + HCl (aq) AgCl (s) + HNO3 (aq)
If the reaction releases 68.0 kJ of energy, how many
kilocalories of energy does it release? (1 cal = 4.184 J) (Round
off decimal to nearest tenths)
Answers
Answer: 16.3 kcal
Explanation:
Given that the reaction releases 68 kJ or 68000 J. One cal is 4.184 J. Thus, 68000 J is 16.25 kilocalories.
What is exothermic reaction?An exothermic reaction is the reaction which evolves heat energy to the surroundings. The given reaction is an exothermic double displacement reaction.
The given reaction involves the displacement of nitrate and Cl groups in between silver metal and hydrogen. This reaction releases a heat of 68kJ or 68000 J
given, 1 cal of energy = 4.184 J
hence, 68000 J = 68000/4.184 = 16252 cal
One kilocalorie = 1000 calories
thus, 16252 calories = 16.25 kilocalories.
Therefore, the given reaction, releases 16.25 kilocalories of energy.
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A 72 kg swimmer jumps into a pool from a diving board 3.25 m above the water. Use energy conservation to find his speed just as he hits the water if he jumps straight up (but just beyond the board!) at 2.5 m/s. A. 10.5 m/s B. 5.7 m/s C. 7.4 m/s D. 8.4 m/s
Answers
Answer:
8.06 m/s
Explanation:
It is given that,
Mass of a swimmer, m = 72 kg
He jumps from a diving board 3.25 m above the water.
We need to find the speed just as he hits the water if he jumps straight up. Using the conservation of energy to fin it as follows :
\(mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 10\times 3.25}\\\\ v=8.06\ m/s\)
So, the required speed is 8.06 m/s.
during which lunar phase does every solar eclipse occur?
Answers
Answer:
It has to be the "New Moon" because that is when the moon is between the sun and the earth.
A lunar eclipse can occur when the earth is between the sun and the moon.
a ball thrown straight upwards moves initially with decreasing upward velocity. what are the directions of the velocity and acceleration vectors during this part of the motion?
Answers
During the initial part of the ball's motion, as it moves upwards, its velocity vector points upwards and its acceleration vector points downwards.
When the ball is thrown straight upwards, the velocity vector points upwards, as the ball has upward velocity. However, the upward velocity is decreasing due to the acceleration vector, which points downward because of gravity. This downward acceleration vector opposes the upward motion, causing the upward velocity to decrease until the ball reaches its peak and begins to fall back down.
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_ 5) The number of electrons that pass a certain point in a conductor in a given amount of time is
defined as
A) electric current
B) potential difference C) charge
D) resistance
Answers
The number of electrons that pass a certain point in a conductor in a given amount of time is defined as electric current.
Electric current is a measure of the flow of electric charge through a material. It is defined as the rate at which electric charge flows through a conductor. The SI unit of electric current is the ampere (A), which is defined as the flow of one coulomb of charge per second. Electric current is an important concept in physics and is used to describe many electrical phenomena, such as the behavior of circuits and the properties of conductors and insulators.
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plzzzz urgent
solve this
Answers
Answer:
\( \large{ \tt{☄ \: EXPLANATION}} : \)
Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .\( \large{ \tt{♨ \:LET'S \: START}} : \)
Acceleration is defined as the rate of change of velocity. We know :\( \large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) = \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}} \)
- Plug the values & then simplify !
\( \large{ \bf{↬a = \frac{60 - 0}{300} = \frac{60}{300} = \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}\)
The acceleration of the jeep is 0.2 m/s²\( \large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} : \)
\( \boxed{ \large{ \bf{✾ \: s = \frac{u + v}{2} \times t}}}\)
- Plug the values & then simplify !
\( \large{ \bf{↦s = \frac{0 + 60}{2} \times 300 = \boxed{ \bold{ \bf{9000 \: m}}}}}\)
The distance covered by the jeep is 9000 m .❃ The days that break you are the days that make you ! ♪
♡ Hope I helped! ツ
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Answer:
What she said is right I know it is
A car travels 500 km from home at 35 m/s, then travels back at 43 m/s. Find its average speed.
Answers
The average speed of the car is 35.6m/s
What is average speed?The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction. It is measured in meter per second
Therefore average speed = total distance / total time taken
The total distance here is 500+ 500= 1000km = 1×10⁶m
the time taken for the first journey = 500×1000/35= 14285.71 seconds
the time taken for traveling back = 500000/43= 11627.91 seconds
total time taken = 14285.71 + 11627.91 = 25913.62seconds
therefore average speed = 1000000/25913.62
= 35.6m/s
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What is the speed of an object at rest?
0 m/s
O 1 m/s
O 10 m/s
Answers
Answer:
1 m/s so number 2 is the right one
Explanation:
so when it is at rest it still has some of the left over energy so it would be at 1 m/s
A stone is dropped from the top of a cliff. It hits the ground below after 3.25 s. How high is the cliff
Answers
The height of the cliff above the ground is 51.76 m.
Height of the cliffh = vt + ¹/₂gt²
where;
v is initial vertical velocityt is time of motiong is acceleration due to gravityh = 0 + ¹/₂gt²
h = ¹/₂gt²
h = ¹/₂(9.8)(3.25)²
h = 51.76 m
Thus, the height of the cliff above the ground is 51.76 m.
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A flux of 0.6Wb passes through a motor field pole with an area of 120 cm2. Calculate the flux density
Answers
We will have that the flux density will be:
\(^{}\rho=\frac{0.6Wb}{120cm^2}\Rightarrow\rho=5\cdot10^{-3}Wb/cm^2\)1. Which wave phenomenon is illustrated by this image?
O A. Refraction
O B. Diffraction
O C. Diffusion
O D. Interference
Answers
Answer:
Explanation: O B. Diffraction
hope i’m right
what is convection?
what is radiation ?
what conduction?
Answers
--ⓒᴄᴏɴᴠᴇᴄᴛɪᴏɴ ᴏᴄᴄᴜʀꜱ ᴡʜᴇɴ ᴘᴀʀᴛɪᴄʟᴇꜱ ᴡɪᴛʜ ᴀ ʟᴏᴛ ᴏꜰ ʜᴇᴀᴛ ᴇɴᴇʀɢʏ ɪɴ ᴀ ʟɪQᴜɪᴅ ᴏʀ ɢᴀꜱ ᴍᴏᴠᴇ ᴀɴᴅ ᴛᴀᴋᴇ ᴛʜᴇ ᴘʟᴀᴄᴇ ᴏꜰ ᴘᴀʀᴛɪᴄʟᴇꜱ ᴡɪᴛʜ ʟᴇꜱꜱ ʜᴇᴀᴛ ᴇɴᴇʀɢʏ. ... ʟɪQᴜɪᴅꜱ ᴀɴᴅ ɢᴀꜱᴇꜱ ᴇxᴘᴀɴᴅ ᴡʜᴇɴ ᴛʜᴇʏ ᴀʀᴇ ʜᴇᴀᴛᴇᴅ. ᴛʜɪꜱ ɪꜱ ʙᴇᴄᴀᴜꜱᴇ ᴛʜᴇ ᴘᴀʀᴛɪᴄʟᴇꜱ ɪɴ ʟɪQᴜɪᴅꜱ ᴀɴᴅ ɢᴀꜱᴇꜱ ᴍᴏᴠᴇ ꜰᴀꜱᴛᴇʀ ᴡʜᴇɴ ᴛʜᴇʏ ᴀʀᴇ ʜᴇᴀᴛᴇᴅ ᴛʜᴀɴ ᴛʜᴇʏ ᴅᴏ ᴡʜᴇɴ ᴛʜᴇʏ ᴀʀᴇ ᴄᴏʟᴅ.
--Ⓡʀᴀᴅɪᴀᴛɪᴏɴ ɪꜱ ᴇɴᴇʀɢʏ ᴛʜᴀᴛ ᴄᴏᴍᴇꜱ ꜰʀᴏᴍ ᴀ ꜱᴏᴜʀᴄᴇ ᴀɴᴅ ᴛʀᴀᴠᴇʟꜱ ᴛʜʀᴏᴜɢʜ ꜱᴘᴀᴄᴇ ᴀɴᴅ ᴍᴀʏ ʙᴇ ᴀʙʟᴇ ᴛᴏ ᴘᴇɴᴇᴛʀᴀᴛᴇ ᴠᴀʀɪᴏᴜꜱ ᴍᴀᴛᴇʀɪᴀʟꜱ. ... ᴛʜᴇ ᴋɪɴᴅꜱ ᴏꜰ ʀᴀᴅɪᴀᴛɪᴏɴ ᴀʀᴇ ᴇʟᴇᴄᴛʀᴏᴍᴀɢɴᴇᴛɪᴄ (ʟɪᴋᴇ ʟɪɢʜᴛ) ᴀɴᴅ ᴘᴀʀᴛɪᴄᴜʟᴀᴛᴇ (ɪ.ᴇ., ᴍᴀꜱꜱ ɢɪᴠᴇɴ ᴏꜰꜰ ᴡɪᴛʜ ᴛʜᴇ ᴇɴᴇʀɢʏ ᴏꜰ ᴍᴏᴛɪᴏɴ). ɢᴀᴍᴍᴀ ʀᴀᴅɪᴀᴛɪᴏɴ ᴀɴᴅ x ʀᴀʏꜱ ᴀʀᴇ ᴇxᴀᴍᴘʟᴇꜱ ᴏꜰ ᴇʟᴇᴄᴛʀᴏᴍᴀɢɴᴇᴛɪᴄ ʀᴀᴅɪᴀᴛɪᴏɴ
--Ⓒᴄᴏɴᴅᴜᴄᴛɪᴏɴ ɪꜱ ᴛʜᴇ ᴡᴀʏ ɪɴ ᴡʜɪᴄʜ ᴇɴᴇʀɢʏ ɪꜱ ᴛʀᴀɴꜱꜰᴇʀʀᴇᴅ (ᴛʜʀᴏᴜɢʜ ʜᴇᴀᴛɪɴɢ ʙʏ ᴄᴏɴᴛᴀᴄᴛ) ꜰʀᴏᴍ ᴀ ʜᴏᴛ ʙᴏᴅʏ ᴛᴏ ᴀ ᴄᴏᴏʟᴇʀ ᴏɴᴇ (ᴏʀ ꜰʀᴏᴍ ᴛʜᴇ ʜᴏᴛ ᴘᴀʀᴛ ᴏꜰ ᴀɴ ᴏʙᴊᴇᴄᴛ ᴛᴏ ᴀ ᴄᴏᴏʟᴇʀ ᴘᴀʀᴛ).
It takes a person 42 seconds to swim in a straight line from the west end of a
pool to the east end of the pool, a distance of 45 meters. What is the
swimmer's velocity?
A. 0.9 m/s east
B. 0.9 m/s west
C. 1.1 m/s east
D. 1.1 m/s west
Answers
Hello User!
Answer:
Answer: 1.1 m/s east
It takes a person 42 seconds to swim in a straight line from the west end of a pool to the east end of the pool, a distance of 45 meters, the swimmer's velocity is approximately 1.1 m/s. The correct option is C.
The velocity is the rate of motion in a certain direction and is calculated by dividing 45 metres by 42 seconds. The swimmer in this instance is swimming towards the east side of the pool.
The swimmer's velocity can be calculated using the formula:
Velocity (v) = Distance (d) / Time (t)
Given that the distance is 45 meters and the time is 42 seconds:
Velocity (v) = 45 m / 42 s ≈ 1.0714 m/s
The swimmer's velocity is approximately 1.1 m/s.
Thus, the correct answer is C. 1.1 m/s east.
For more details regarding velocity, visit:
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