How much excess reactant is left over when 17.0 g of potassium hydroxide (KOH) reacts with 20.0 g of iron (III) nitrate (Fe(NO3)3)?

Answer:

the correct answer is 2

Explanation:

i just did this assignment :)

There will be 2 unpaired electrons in p orbital of unpaired electrons present in the ground state of the atoms in Group 4A(14).

The unpaired electrons are those which do not have any pair due to absence of no more electrons and they are highly unstable elements if the electrons are not paired in the orbitals.

There are 4 types of orbitals s, p, d, and f s-orbital consist of one pair of electrons to fill and the p-orbital have 3 blocks which can be filled with 3 pair that is 6 electrons after filling, and two unpaired electrons left in p-orbital.

Therefore, in the ground state of the atoms in Group 4A(14)  2 unpaired electrons in the p orbital of unpaired electrons are present.

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A. Balanced net ionic equation: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
B. Balanced net ionic equation: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)
C. Balanced net ionic equation: AgCl(s) + 2NH₂(aq) → Ag(NH₃)₂+(aq) + Cl⁻(aq)                                                          

D.Balanced net ionic equation: Ag(NH₃)₂+(aq) + Cl⁻(aq) → AgCl(s) + 2NH₃(aq)

A. The initial precipitation of the chloride of Ag⁺:
Ag⁺(aq) + Cl-(aq) → AgCl(s)
Balanced net ionic equation: Ag+(aq) + Cl^-(aq) → AgCl(s)
B. The conformity test for Pb²⁺:
Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)
Balanced net ionic equation: Pb₂+(aq) + 2I^-(aq) → PbI₂(s)
C. The dissolving of AgCl in aqueous ammonia:
AgCl(s) + 2NH₃(aq) → Ag(NH₃)₂+(aq) + Cl⁻aq)
Balanced net ionic equation: AgCl(s) + 2NH3(aq) → Ag(NH3)2+(aq) + Cl^-(aq)
D. The precipitation of AgCl from the solution of Ag(NH3)2+:
Ag(NH₃)₂ +(aq) + Cl⁻(aq) → AgCl(s) + 2NH₃(aq)
Balanced net ionic equation: Ag(NH₃)₂+(aq) + Cl⁻(aq) → AgCl(s) + 2NH₃(aq)

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Water 3.0 deals mainly with sewage treatment. The primary aim of this project is to reduce the harmful impacts of chemical pollutants from industrial and agricultural activities on natural water resources.

Currently, used wastewater treatment technologies can break down some of the chemicals in wastewater but not all of them. Chemicals that are not broken down are referred to as persistent organic pollutants. These chemicals persist in the environment for long periods, and they can cause severe damage to aquatic life and human health.
Currently, the primary challenge facing water treatment technologies is the removal of persistent organic pollutants such as pesticides, pharmaceuticals, and endocrine-disrupting chemicals from wastewater.

These pollutants are generally water-soluble and resist microbial degradation, making them hard to remove from wastewater using current water treatment technologies. For example, conventional activated sludge treatment used in wastewater treatment plants does not remove some persistent organic pollutants from wastewater.
Failure to remove these pollutants from wastewater can have significant environmental and health impacts.

For example, pharmaceutical chemicals can cause antibiotic resistance, while endocrine-disrupting chemicals can cause birth defects, cancer, and other health problems.

Therefore, there is a need to improve wastewater treatment technologies to remove persistent organic pollutants from wastewater.
In conclusion, wastewater treatment technologies can break down some chemicals but not all. Chemicals that are not broken down are persistent organic pollutants and pose a significant risk to the environment and human health. Therefore, it is important to develop wastewater treatment technologies that can remove these pollutants from wastewater.

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Answer:

Electrons

Explanation:

Cathode rays carry electronic currents through the tube. Electrons were first discovered as the constituents of cathode rays. J.J. Thomson used the cathode ray tube to determine that atoms had small negatively charged particles inside of them, which he called “electrons.”

The rays produced in a cathode tube are electrons which are present in the shells surrounding the nucleus of an atom.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer:

C6H12O6 + 6O2 - 6CO2 + 6H2O + ENERGY

Explanation:

Let me know if I'm right

When a precipitation reaction occurs the resulting mixture of liquid solution and solid precipitate would be considered a heterogeneous Mixture.

Chemical reactions known as precipitation reactions take place in aqueous solutions to produce precipitates. Moreover, chemical changes that occur inside the substances are a part of chemical processes.

Moreover, chemical reactions take place between two or even more chemical substances, known as reactants. As a result, the reactants might be solid, gaseous, or liquid in nature. When a precipitation reaction occurs the resulting mixture of liquid solution and solid precipitate would be considered a heterogeneous Mixture.

Therefore, when a precipitation reaction occurs the resulting mixture of liquid solution and solid precipitate would be considered a heterogeneous Mixture.

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Answer: The chemical equation you have listed is nonane. However, I have inculded a screen shot that explains what each aswer option is so you can verify.

Explanation:

The percent of aluminum in the alloy sample when hydrochloric acid only reacts with the aluminum is found to be 21.7%.

This single replacement reaction is described by the following balanced chemical equation: 2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g).

Aluminium interacts with weak hydrochloric acid at room temperature. The dissolution of the metal in hydrochloric acid results in the production of aluminium chloride and colourless hydrogen gas. Because the finished products do not interact, this reaction cannot be stopped.

moles of H2 = PV/RT

             => 1.03atm X 1.53L / 0.0821 x 298K

            => 0.0644 mol H2

Balanced equation => 0.0644 mol H2 x 2 mol Al / 3 mol H2 x 26.98g/        

                                                                                                    1 mol Al

                              => 1.16g Al      

% Al = 1.16/5.34 x 100 = 21.7%

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Density of water is 1g/cc whereas ethanol is 0.79g/cc

So density of ethanol is less than water hence ethanol will float on water

What is density ?

density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density. For instance, while Earth has a density of 5.51 grammes per cubic centimeter, water has a density of 1 grammes per cubic centimeter. Another way to state density is in kilograms per cubic meter (in meter-kilogram-second or SI units)

Density of water is 1g/cc whereas ethanol is 0.79g/cc

So density of ethanol is less than water hence ethanol will float on water

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We must first determine how many moles of Mg(OH)2 are in the solution in order to determine its molarity:

Compute Mg(OH)2's molar mass:

mol Mg = 24.31 g

O = 15.99 g/mol

H = 1.01 g/mol

Mg(OH)2 has a molar mass of 24.31 plus 2(15.99) plus 2(1.01), or 58.33 g/mol.

Determine how many moles of Mg(OH)2 there are:

Mass / molar mass = number of moles

1.925 moles are obtained by multiplying 112.3 g by 58.33 g/mol.

Determine the solution's molarity:

Molarity is equal to the moles of solute per litre of solution.

Molarity = 1.925 moles/1.2 litres = 1.60 M

As a result, the molarity of the solution created by combining 1.2 L of water with 112.3 g of Mg(OH)2 is 1.60 M.

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Answer:

All the matter that is made of atoms that cannot be broken or beaten into thin sheet .2All matters of a given book are in mass and mixture

True. active transport is used to move solutes against the concentration gradient.

Active transport is a cellular process that uses energy to move solutes against their concentration gradient, from an area of lower concentration to an area of higher concentration. This process requires the input of energy in the form of ATP (adenosine triphosphate) to drive the movement of molecules against their concentration gradient.

By utilizing specialized transport proteins embedded in the cell membrane, active transport allows the movement of ions, molecules, or other substances across the membrane against the natural flow dictated by diffusion. This mechanism enables the cell to maintain concentration gradients and perform essential functions such as nutrient uptake, ion transport, and waste removal.

In contrast, passive transport processes, such as simple diffusion or facilitated diffusion, move solutes along their concentration gradient, from higher to lower concentrations, without requiring energy expenditure. Active transport is a vital mechanism for maintaining homeostasis and ensuring the proper functioning of cells and organisms.

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To raise the temperature of a 10.35g sample of carbon tetrachloride from 32.1°c to 56.4°c, 222.92J heat is required.

Heat is a form of energy and it is associated with the motion of particles. The amount of heat required to change the temperature of a substance depends on its mass, the specific heat capacity of the substance and the change in temperature.

The mass of carbon tetrachloride is given as 10.35g. The specific heat capacity of carbon tetrachloride is given as 0.85651 J/g°C and the change in temperature is given as 24.3°C. Putting these values into the formula: q = m × C × ΔTq = 10.35 g × 0.85651 J/g°C × 24.3°Cq = 222.92 J. Therefore, 222.92 Joules of heat are required to raise the temperature of a 10.35g sample of carbon tetrachloride from 32.1°c to 56.4°c.

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The chemical that was given the wrong name "2-propylbutane" should instead be called "2-methylpentane."

We begin by determining the longest carbon chain, which has five carbon atoms, in order to accurately name the molecule. It is known as pentane.

The next step is to locate and name any substitutes that are connected to the main chain. The second carbon atom in this instance has a methyl group (-CH3) linked to it. Since it is named as a substituent, we use the prefix "methyl."

The methyl group is therefore connected to the second carbon atom of the pentane chain, so the correct name for the molecule is "2-methylpentane," signifying this.

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Answer:

light intensity

Explanation:

Answer: \(1.6\times 10^4\)

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as \(5.0\times 10^3\)

In division , the result would contain the same number of significant digits as there in the least precise number , thus the answer would have 2 significant digits.

\(\frac{1.248\times 10^{-2}}{7.8\times 10^{-7}}=1.6\times 10^4\)

In the given scenario, when salt is added to the ice-water mixture, the final equilibrium temperature is less than 0°C. Based on this information, we can predict that there will be a greater amount of ice in the final equilibrium state compared to the initial state before the salt was added.

To understand this prediction, let's analyze the energy-interaction diagram:

Adding salt to the ice-water mixture lowers the temperature of the system, causing more water to freeze and resulting in a greater amount of ice in the final equilibrium state compared to the initial state before the salt was added.

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Chemical similarity (or molecular similarity) is the likeness of chemical elements, molecules, or chemical compounds in terms of either structural or functional features, i.e. the impact that the chemical substance has on reaction partners in inorganic or biological environments.

The empirical formula of a molecular simplification is defined as the lowest ratio of atoms. The empirical formula and the molecular formula are therefore connected. The information about the elements contained in a molecule and their ratios is provided by both the molecular formula and the empirical formula.

While a compound's structural formula provides the same information as its molecular formula, it additionally reveals the atoms' connections inside the molecule.

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Answer:

Boron

Explanation:

Using the periodic table we can see that Period 2 represents the second row. Group 13 indicates the 13th column.

Answer:

Germanium or Ge

Explanation:

It is on the perioidic table. Gallium has an atomic number of 31 and Germanium has an atomic number of 32.

Answer:

Molecularity is the number of ions or molecules that take part in the rate determining step

Order of reaction is the number of molecules of reactant whose concentration changes during the chemical change

Answer:

C

Explanation:

it's always colder at night and close to night especially near water and that's when wind tends to blow the most

Answer: Therefore 4 moles of ammonia can be produced

Explanation: The equation is 3H2 + N2 → 2NH3

If 6 moles of H2 gas react with N2 (assuming all reactants react)

6 * 2/3 moles of ammonia must be produce

Hope I'm right

The structure of the alkene formed in this reaction is  \(CH_{3}CH=CHCOCH_{3}\) .

The structure of the alkene formed in the reaction when \(CH_{3}CH_{2}I\) reacts with triphenyl phosphine, followed by n-butyl lithium, followed by acetone is as follows:

Step 1: \(CH_{3}CH_{2}I\)  reacts with triphenyl phosphine ( \(PPh_{3}\) ) to form a phosphonium ylide through a substitution reaction.
\(CH_{3}CH_{2}I\)  + \(PPh_{3}\) → (\(CH_{3}CH_{2}\)) \(PPh_{3}\) + I-

Step 2: The phosphonium ylide reacts with n-butyl lithium (n-BuLi), which acts as a strong base, to form a carbanion.
(\(CH_{3}CH_{2}\)) \(PPh_{3}\) + I- + n-BuLi → [(\(CH_{2}=CH\)) \(PPh_{3}\) ]+ LiI

Step 3: The carbanion then reacts with acetone through a Wittig reaction, forming an alkene as the product.
[(CH2=CH) \(PPh_{3}\) ]+ LiI +\(CH_{3}COCH_{3}\) → \(CH_{3}CH=CHCOCH_{3}\) + ( \(PPh_{3}\) )LiI

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Answer:

78.894g of NaCl

Explanation:

This requires some dimensional analysis:

Using the molar mass of NaCl we get the answer we are looking for.

1.35 Moles of NaOH * \(\frac{58.44g NaCl}{ 1 mole NaCl}\) = 78.894 g of NaCl

Electrolysis occur when an electric current is passed through a liquid or solution thereby causing the decomposition of chemicals.

For magnesium chloride, it will be heated to be able to conduct electricity. When molten, the MgCl2 will decomposes into Mg2+ and 2Cl- ions. During electrolysis, the elements are separated according to the equations;

According to the half reactions, the Mg2+ is reduced at the cathode (-) and the Cl- is oxidized at the anode (+). Reduction at the cathode shows that magnesium gains two electrons to form a magnesium solid while the chlorine ion looses two electrons at the anode

Answer:

The answer is D, I would type it out but it is to long and I'm kind of lazy, but anyways! Your answer is D

Hope This Helps!

The general process of drawing products and differentiating between higher and lower molecular weight products in a reaction.

To draw the products of a given reaction, follow these steps:

1. Identify the reactants and their molecular structures.
2. Determine the type of reaction occurring (e.g., addition, substitution, elimination).
3. Predict the products based on reaction mechanisms and the specific reactants involved.
4. Draw the molecular structures of the products.

To differentiate between the higher molecular weight product and the lower molecular weight product:

1. Calculate the molecular weight of each product by adding up the atomic weights of the constituent elements.
2. Compare the molecular weights of the products.
3. Identify the product with the higher molecular weight and the product with the lower molecular weight.

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