How much energy is required to heat 40. 7 g of water (H2O) from −10∘C to 70∘C? Your answer should have three significant figures. Where: cice=2. 06 J/g∘C cwater=4. 18 J/g∘C ΔHfus=334 J/g

Answer:

The layers of a star's atmosphere can include the photosphere, the chromosphere, and the corona. The photosphere is the layer of the star's atmosphere that is visible to us and is the source of the star's light. The chromosphere is the layer above the photosphere and is characterized by its reddish color. The corona is the outermost layer of the star's atmosphere and is characterized by its high temperatures.

Explanation:

Given:

• Length of beam = 7 m

• Mass of beam = 50 kg

• Mass of person = 60 kg

• Distance of the person from the left = 3.6 m

Let's find the tensions, T1 and T2.

First make a free body sketch:

Here, the net torque = 0.

To find the tension, T1, we have:

Where:

l = 7 m

mp = 60 kg

g is acceleration due to gravity = 9.8 m/s²

l1 = 3.6 m

mb = 50 kg

Thus, we have:

Therefore, the tension T1 = 530.6 N.

To find the tension T2, we have:

Thererfore the tension T2 = 547.5 N

• ANSWER:

T1 = 530.6 N

T2 = 547.4 N

Given values are:

Force,

Time,

Now,

→ \(Work \ done= f\times d\)

                     \(= 100\times 50\)

                     \(= 500\)

hence,

The power will be:

= \(\frac{Work}{time}\)

= \(\frac{500}{4}\)

= \(125 \ watt\)

Thus the response above is right.

Learn more about power here:

https://brainly.com/question/13534333

Answer:

D Elastic collision because momentum is conserved

Explanation:

this is the answer may i be marked brainliest?

A star is considered circumpolar if it remains above the horizon throughout the entire night. The greatest distance that a star can be from Polaris, the North Star, and still be circumpolar is 50°.

Circumpolar stars are those that do not set below the horizon but instead appear to revolve around the celestial pole. In the northern hemisphere, Polaris serves as the North Star, located very close to the celestial north pole.

For a star to be circumpolar as seen from Philadelphia (latitude 40.0°), it must remain above the horizon at all times during the night.

The distance between Polaris and the celestial pole is equivalent to the observer's latitude. In this case, since the latitude of Philadelphia is 40.0°, any star within 40.0° of Polaris will be circumpolar.

Therefore, the greatest distance a star can be from Polaris and still be circumpolar is 40.0° + 10.0° (as the North Star is approximately 10.0° away from the celestial pole), giving a total of 50.0°.

Any star within this range, up to 50.0° from Polaris, will never dip below the horizon and will remain visible throughout the entire night as a circumpolar star.

Learn more about celestial here:

https://brainly.com/question/28876984

#SPJ11

Answer:

encyclopedia most reliable I think

Answer:

organic material

Explanation:

The cosine rule is used to determine the values of unknown aides and angles in a triangle

The measure of θ is approximately 117.2°

Reason:

Given parameters are;

The distance between the two windmills, a = 456 feet

The distance between the cow and one of the windmills, b = 320 feet

Distance between the cow and the other windmills, c = 210 feet

Required, the angle θ between b, and c direction

Solution;

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(θ)

Which gives;

\(cos (\theta) = \dfrac{320^2 + 210^2 - 456^2}{2 \times 320 \times 210 }\)

The measure of θ ≈ 117.2°

Learn more about the cosine rule here:

Answer:

3.8 in

Explanation:

A wheel and axle machine is a machine in which the wheel rotates around the rod (axle). They rotate together thereby transferring force among each other.

The formula for a wheel and axle is:

Fr * Rr = Fe * Re

Where Fr is the resistance force, Rr is the radius of the resistance force, Fe is the effort force and Re is the radius of the resistance force.

Given that: Fr = 235 lb, Fe = 45 lb, Re = 20 in / 2 = 10 in. Hence:

235 * Rr = 45 * 10

Rr = 45 * 10 / 235

Rr= 1.9 in

Diameter of axle = 2 * 1.9 = 3.8 in

This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2 Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

Here's the solution to the given problem: Let the origin of our coordinate system be located at the center of the platform. We can assume that there is no friction between the platform and the ground. If v  Rw, the woman will collide with the center of the platform after the platform stops moving because it is not able to move with the required speed to reach the center of the platform before it stops. The net torque about the origin, assuming that the angular momentum is conserved, is Iα = τ, or, assuming that the angular momentum is conserved,T2−T1=IwoR2wR2+mr2αT2 = Mg/2 + Mv/RT1 = (M + m)g/2Let a be the speed of the platform just after the woman reaches the center, which is given by a = v + αr. This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

learn more about velocity

https://brainly.com/question/30559316

#SPJ11

Answer:

vote me brainliest

Explanation:

The magnitude B of the magnetic field at the center of the semicircles is given by these expression B = (μ₀(I(outer) - I(inner)))/(π(a + b)). The B in terms of the asked variable.

In this case, we have two concentric semicircles, each carrying current in opposite directions. Let's consider a circular loop with radius r, where a < r < b. The magnetic field at the center of this loop will be the sum of the magnetic fields produced by the two semicircles.

For the outer semicircle (radius b), the magnetic field at the center can be calculated as follows:

∮ B · dl = μ₀I(outer)

For the inner semicircle (radius a), the magnetic field at the center has the opposite direction, so the equation becomes:

∮ B · dl = -μ₀I(inner)

Since the circular loop with radius r contains both the inner and outer semicircles, we can add these equations together:

∮ B · dl = μ₀(I(outer) - I(inner))

The line integral ∮ dl represents the circumference of the circular loop, which is 2πr:

B(2πr) = μ₀(I(outer) - I(inner))

B = (μ₀(I(outer) - I(inner)))/(2πr)

In this case, as we are interested in the magnetic field at the center of the semicircles, the radius r would be the average radius between a and b, given by:

r = (a + b)/2

Substituting this value into the equation, we get the final expression for the magnitude B of the magnetic field at the center of the semicircles:

B = (μ₀(I(outer) - I(inner)))/(2π((a + b)/2))

B = (μ₀(I(outer) - I(inner)))/(π(a + b))

Therefore, the magnitude B of the magnetic field at the center of the semicircles is given by B = (μ₀(I(outer) - I(inner)))/(π(a + b)).

To know more about the magnetic field:

https://brainly.com/question/14848188

#SPJ4

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

To know more about damping ratios, refer here:

https://brainly.com/question/31463018#

#SPJ11

The energy conservation that occurred in the circuit when a 12 V battery is connected to a resistor, a light bulb, and a buzzer is light energy (light bulb) and to sound energy (buzzer).

The principle of energy conservation states that energy can neither be created nor destroyed but can be transferred from one form to another.

When a 12 V battery is connected to a resistor, a light bulb, and a buzzer, the energy conservation that occur in the circuit is light energy (light bulb) and to sound energy (buzzer).

Thus, the energy conservation that occurred in the circuit when a 12 V battery is connected to a resistor, a light bulb, and a buzzer is light energy (light bulb) and to sound energy (buzzer).

Learn more about energy conservation here: https://brainly.com/question/166559

#SPJ1

This is a multi-part question involving a three-dimensional harmonic oscillator and its angular momentum.

a. The orbital angular momentum operator `L` can be written in terms of the position and momentum operators as `L = r x p`. The squared magnitude of the angular momentum is given by `L^2 = Lx^2 + Ly^2 + Lz^2`. The `z` component of the angular momentum can be written as `Lz = xp_y - yp_x`, where `p_x` and `p_y` are the momentum operators along the `x` and `y` directions, respectively.

Since the state vector `|ψ⟩` is given as a product of quasi-classical states for one-dimensional harmonic oscillators along each axis, we can use the ladder operator formalism to evaluate the action of `Lz` on `|ψ⟩`. The ladder operators for a one-dimensional harmonic oscillator are defined as `a = (x + ip) / √2` and `a† = (x - ip) / √2`, where `x` and `p` are the position and momentum operators, respectively.

Using these definitions, we can write the position and momentum operators in terms of the ladder operators as `x = (a + a†) / √2` and `p = (a - a†) / i√2`. Substituting these expressions into the definition of `Lz`, we get:

`Lz = (xp_y - yp_x) = ((a_x + a_x†) / √2)((a_y - a_y†) / i√2) - ((a_y + a_y†) / √2)((a_x - a_x†) / i√2)`
  `  = (1/2i)(a_xa_y† - a_x†a_y - a_ya_x† + a_y†a_x)`
  `  = iħ(a_xa_y† - a_x†a_y)`

where we have used the commutation relation `[a, a†] = 1`.

The action of this operator on the state vector `|ψ⟩` is given by:

`(Lz)|ψ⟩ = iħ(a_xa_y† - a_x†a_y)|αx⟩|αy⟩|αz⟩`
        `= iħ(αxa_y† - αya_x†)|αx⟩|αy⟩|αz⟩`
        `= iħ(αx - αy)Lz|αx⟩|αy⟩|αz⟩`

where we have used the fact that the ladder operators act on quasi-classical states as `a|α⟩ = α|α⟩` and `a†|α⟩ = d/dα|α⟩`.

Since `(Lz)|ψ⟩ = iħ(αx - αy)Lz|ψ⟩`, it follows that `(Lz)^2|ψ⟩ = ħ^2(αx - αy)^2(Lz)^2|ψ⟩`. Therefore, we have:

`(L^2)|ψ⟩ = (Lx^2 + Ly^2 + Lz^2)|ψ⟩`
        `= ħ^2(αx^2 + αy^2 + (αx - αy)^2)(L^2)|ψ⟩`
        `= ħ^2(αx^2 + αy^2 + αx^2 - 2αxαy + αy^2)(L^2)|ψ⟩`
        `= ħ^2(3αx^2 + 3αy^2 - 4αxαy)(L^2)|ψ⟩`

This shows that `(L^2)|ψ⟩` is proportional to `(L^2)|ψ⟩`, which means that `(L^2)` is an eigenvalue of the operator `(L^2)` with eigenstate `|ψ⟩`. The eigenvalue is given by `(L^2) = ħ^2(3αx^2 + 3αy^2 - 4αxαy)`.

b. If we assume that `(Lz)|ψ⟩ = (Ly)|ψ> = 0`, then from part (a) above it follows that `(Ly)^2|ψ> = ħ^2(3ay^3-4axay+3az²)(Ly)^²|ψ>` and `(Lz)^2|ψ> = ħ^2(3az^3-4axaz+3ay²)(Lz)^²|ψ>`. Since `(Ly)^2|ψ> = (Lz)^2|ψ> = 0`, it follows that `3ay^3-4axay+3az² = 0` and `3az^3-4axaz+3ay² = 0`. Solving these equations simultaneously, we find that `ax = ay = az = 0`.

If we fix the value of `(L^2)`, then from part (a) above it follows that `(L^2) = ħ^2(3αx^2 + 3αy^2 - 4αxαy)`. Since `ax = ay = az = 0`, this equation reduces to `(L^2) = 0`.

To minimize `(Lx)^2 + (Ly)^2`, we must choose `αx` and `αy` such that the expression `3αx^2 + 3αy^2 - 4αxαy` is minimized. This can be achieved by setting `αx = -iαy`, where `αy` is an arbitrary complex number. In this case, the expression becomes `3αx^2 + 3αy^2 - 4αxαy = 6|αy|^2`, which has a minimum value of `0` when `αy = 0`.

c. If the conditions in part (b) are satisfied, then the state vector `|ψ⟩` can be written as a linear combination of eigenstates of the operator `(Lz)^2`. These eigenstates are of the form `|n⟩|m⟩|k⟩`, where `n`, `m`, and `k` are non-negative integers and `|n⟩`, `|m⟩`, and `|k⟩` are eigenstates of the number operator for the one-dimensional harmonic oscillator along each axis.

The action of the ladder operators on these states is given by:

`a_x|n⟩|m⟩|k⟩ = √n|n-1⟩|m⟩|k⟩`
`a_x†|n⟩|m⟩|k⟩ = √(n+1)|n+1⟩|m⟩|k⟩`
`a_y|n⟩|m⟩|k⟩ = √m|n⟩|m-1⟩|k⟩`
`a_y†|n⟩|m⟩|k⟩ = √(m+1)|n⟩|m+1⟩|k⟩`
`a_z|n⟩|m⟩|k⟩ = √k|n⟩|m⟩|k-1⟩`
`a_z†|n⟩|m⟩|k⟩ = √(k+1)|n⟩|m⟩|k+1⟩`

Since we have assumed that `(Lz)|ψ> = (Ly)|ψ> = 0`, it follows that:

`(Lz)|ψ> = iħ(a_xa_y† - a_x†a_y)|ψ> = iħ(∑_n,m,k c_nmk(a_xa_y† - a_x†a_y)|n>|m>|k>)`
        `= iħ(∑_n,m,k c_nmk(√n√(m+1)|n-1>|m+1>|k> - √(n+1)√m |n+1>|m-1>|k>))`
        `= iħ(∑_n,m,k (c_(n+1)(m+1)k√(n+1)√(m+1) - c_n(m-1)k√n√m)|n>|m>|k>)`
        `= 0`

This implies that for all values of `n`, `m`, and `k`, we must have:

`c_(n+1)(m+1)k√(n+1)√(m+1) - c_n(m-1)k√n√m = 0`

Similarly, since `(Ly)|ψ> = 0`, it follows that:

`(Ly)|ψ> = iħ(a_xa_z† - a_x†a_z)|ψ> = iħ(∑_n,m,k c_nmk(a_xa_z† - a_x†a_z)|n>|m>|k>)`
        `= iħ(∑_n,m,k c_nmk(√n√(k+1)|n-1>|m>|k+1> - √(n+1)

learn more about angular momentum

https://brainly.com/question/30656024

#SPJ11

The total number of significant digits in the given number is five. If the books are measured in packets of 10, the number of significant digits reduces to two.

The given data is: Total number of books in the library = 57,000. We are to determine how many significant digits are there in the result? For this, let us define what are significant digits: Digits that are used to communicate meaning or accuracy of measurements are known as significant digits. In other words, the digits that carry meaning contributing to its measurement uncertainty are called significant digits. It is used to determine the accuracy of the results. In this question, the total number of books in the library is given as 57,000. As there are five non-zero digits in the given number, there are five significant digits in the result. Will the result change if the books are measured in the packet of 10? If the number of books is measured in the packet of 10, then there will be a change in the number of significant digits. When we express 57,000 in the packet of 10, we get: 57,000 = 5.7 × 10^4. Now, there are only two significant digits in the result (5 and 7), and hence the result changes.

Learn more about significant digits here :-

https://brainly.com/question/28993414

#SPJ11

If the thickness of an absorber is 1.5 cm and 36.45% of a beam is attenuated by the absorber, The half-value layer is 0.51 cm.

The half-value layer (HVL) is a measure of the thickness of an absorber required to reduce the intensity of a beam to half its initial value. In this case, we are given that the absorber attenuates 36.45% of the beam.

To find the HVL, we can use the relationship between the percent attenuation and the thickness of the absorber. The HVL is the thickness at which the beam is attenuated to 50% or 0.5 of its initial intensity.

Since 36.45% of the beam is attenuated by the absorber, the remaining intensity is 100% - 36.45% = 63.55% or 0.6355 of the initial intensity.

We can set up the following equation:

0.5 = 0.6355^x

Solving for x, we find x ≈ 0.51.

Therefore, the half-value layer is approximately 0.51 cm, indicating that a thickness of 0.51 cm of the absorber is required to reduce the beam intensity to half its initial value.

To know more about half-value layer refer here:

https://brainly.com/question/32350702#

#SPJ11

The size of the planets from smallest to largest is: Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter.

The planets in our solar system range in size from the small, rocky Mercury, which has a diameter of 4,879 km, to the giant gas giant Jupiter, which has a diameter of 139,822 km. The order of the planets based on size is determined by their relative diameters, with the smallest planet, Mercury, being the first in the list and the largest planet, Jupiter, being the last.

The rocky planets, Mercury, Mars, Venus, and Earth, are all relatively close in size, with diameters ranging from 4,879 km to 12,742 km. The gas giants, Jupiter, Saturn, Uranus, and Neptune, are much larger, with diameters ranging from 49,244 km to 139,822 km.

To know more about the planets, here

brainly.com/question/14581221

#SPJ4

The position when velocity is 4.5cm/s is ±3.05cm and the velocity when the position is 1.6cm/s is 12.99cm.

The maximum velocity of the particle is 15cm/s and the amplitude is 3.2cm.

The velocity of a particle in simple harmonic motion is given by

V = W√(A²-X²)

Where,

V is the velocity,

A is the amplitude,

X is the position,

W is the angular frequency.

So, for maximum velocity,

V = WA

Putting values,

15 = W(3.2)

W = 4.6875 rad/s

(a) For position when speed is 4.5cm/s.

Putting values,

(4.5) = 4.6875√((3.2)²-(X²))

X = ±3.05cm

So, at ±3.05cm, the velocity will be 4.5cm/s.

(b) For velocity at position of 1.6cm,

Putting values,

V = 4.6875√((3.2)+(1.6))

V = 12.99cm/s

So, the velocity is 12.99cm/s at 1.6cm

To know more about Simple harmonic motion, visit,

https://brainly.com/question/24646514

#SPJ4

The g - string will stretch by 0.0016 mm.

We have a g - string of a guitar with given specifications.

We have to determine how many mm does a 75-cm-long g - string stretch when it’s first tuned.

According to the question -

The force of tension in the string -

\($v = \sqrt{\frac{T}{\mu} }\)

T = \($v^{2} \mu\) = 250 x 250 x 0.0011 = 68.75 N

The Yung modulus of steel = 2 x \(10^{11}\) N/\(m^{2}\)

the amount by which the g - string will be stretched is given by -

\($\delta L = \frac{LT}{Y(\pi r^{2})}\)

Substituting the values -

\($\delta L = \frac{0.75\times 68.75 }{(2\times 10^{11} )\times (\pi (2.2 \times 10^{-4}\times 2.2\times 10^{-4}) )}\)

\(\delta L=\) 0.0016mm

Hence, the g - string will stretch by 0.0016 mm.

To solve more questions on Oscillations, visit the link below-

https://brainly.com/question/15872783

#SPJ4

[ The given question is incomplete. The complete question is

" The G string on a guitar is a 0.46-mm-diameter steel string

with a linear density of 1.1 g/m. When the string is properly

tuned to 196 Hz, the wave speed on the string is 250 m/s. Tuning

is done by turning the tuning screw, which slowly tightens—and

stretches—the string. By how many mm does a 75-cm-long G

string stretch when it’s first tuned? "]

Answer:c. 2.1°C

Explanation:

I just did it

The life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

The life expectancy of a star is determined by its mass and luminosity. The more massive and luminous the star is, the shorter its life expectancy is. Hence, using this information, we can estimate the life expectancy of the following stars:a) 0.2-solar mass, 0.01-solar luminosity red dwarfRed dwarfs are known to have the longest life expectancies among all types of stars. They can live for trillions of years.

Hence, a 0.2-solar mass, 0.01-solar luminosity red dwarf is expected to have a much longer life expectancy than the Sun. It could live for up to 10 trillion years or more.b) 3-solar mass, 30-solar luminosity starA 3-solar mass, 30-solar luminosity star is much more massive and luminous than the Sun. As a result, it will have a much shorter life expectancy than the Sun.

Based on its mass and luminosity, it is estimated to have a lifetime of around 10 million years.c) 10-solar mass, 1000-solar luminosity starA 10-solar mass, 1000-solar luminosity star is extremely massive and luminous. It will burn through its fuel much faster than the Sun, resulting in a much shorter life expectancy. Based on its mass and luminosity, it is estimated to have a lifetime of only around 10 million years as well.

Therefore, the life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

Learn more about luminosity here,

https://brainly.com/question/20308478

#SPJ11

The mass of the given will be 20kg.

By using formula,

force = mass x acceleration

mass = force / acceleration

mass = 400 N / 20m/s²

mass = 20 Kg

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

Any process where the velocity changes is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because the velocity is both a speed and a direction.

To know more about vector quantities :

https://brainly.com/question/774036

#SPJ9

The axial resistance of an axon is calculated using the formula R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. In this case, the axial resistance is 11.28 MΩ.

The resistance along the axon is calculated using the following formula:

R = ρL/A

where:

R is the resistance in ohms

ρ is the resistivity in ohms per meter

L is the length in meters

A is the cross-sectional area in meters squared

In this case, we have:

ρ = 1.6 x 107 Ω.m

L = 0.5 mm = 0.0005 m

A = πr² = π(5 x 10-6)² = 7.854 x 10-13 m²

Therefore, the resistance is:

R = ρL/A = (1.6 x 107 Ω.m)(0.0005 m) / (7.854 x 10-13 m²) = 11.28 MΩ

Therefore, the axial resistance of the axon is 11.28 MΩ.

To know more about the axial resistance refer here,

https://brainly.com/question/30354467#

#SPJ11

The maximum allowable deflection permitted for 7:12-sloped rafters with no finished ceiling attached to the rafters is L/180.

1. Understand the terms: Rafters are structural components of a roof, supporting the sheathing and transferring loads to the walls. Deflection refers to the displacement or deformation of a structural element under load.
2. Determine the deflection limit: In this case, you need to find the maximum allowable deflection for rafters with a 7:12 slope and no finished ceiling attached. The common deflection limit for this scenario is L/180, where L represents the rafter's span length.

In summary, the maximum deflection for 7:12-sloped rafters without a finished ceiling is L/180, ensuring that the rafters maintain structural integrity and minimize excessive bending under load.

To know more about rafters visit

https://brainly.com/question/21371420

#SPJ11

Answer:

The Convex Mirror is used.

Explanation:

1074022.08 tonnes/year is equivalent to 340 kmol/second assuming an average molar mass of 100 g/mol.

To convert 1074022.08 tonnes/year to kmol/second, we need to consider the molar mass of the substance involved. Since the question does not specify the substance, let's assume we are converting a substance with an average molar mass of 100 g/mol.

First, convert tonnes/year to kilograms/second by dividing by 31,536,000 (the number of seconds in a year). Thus, 1074022.08 tonnes/year is equivalent to 34 kg/s.

Next, convert kilograms to moles by dividing by the molar mass. In this case, dividing 34 kg/s by 0.1 kg/mol (since 100 g/mol is equivalent to 0.1 kg/mol) gives us 340 kmol/s.

1074022.08 tonnes/year is equivalent to 340 kmol/second when assuming an average molar mass of 100 g/mol.

To know more about molar mass  refer here

brainly.com/question/31545539#

#SPJ11