How much better is a 10-meter diameter mirror than a 5-meter diameter mirror, in a space telescope for visible/optical light?.

A battery rating given in ampere-hours measures the total amount of charge the battery can deliver over time.

A battery rating given in ampere-hours (Ah) quantifies the total amount of charge a battery can deliver over a specific period of time. It represents the product of the battery's current (in amperes) and the duration of discharge (in hours) until the battery is depleted.

For example, a 5 Ah battery can supply a current of 1 ampere for 5 hours or 0.5 amperes for 10 hours before it is fully discharged. Ampere-hours provide a measure of a battery's capacity or energy storage capability.

This rating is commonly used for rechargeable batteries in various applications, such as automotive batteries, portable electronics, and renewable energy systems, allowing users to estimate the battery's performance and plan their usage accordingly.

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Answer:

females

Explanation:

The ova(egg) starts meiosis as a foetus but doesn't complete it until puberty. This is when the menstrual cycle will start to occur indicating the gametes( egg) is maturing and if not fertilized will be removed.

Answer:

Período del tambor: \(T = 0.25\,s\), fuerza sobre la prenda: \(F \approx 80.852\,N\), velocidad lineal del tambor: \(v \approx 10.053\,\frac{m}{s}\), velocidad angular del tambor: \(\omega \approx 25.133\,\frac{rad}{s}\).

Explanation:

La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:

"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."

El tambor gira a velocidad angular constante (\(\omega\)), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga (\(a\)), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor (\(T\)), en segundos:

\(T = \frac{1}{f}\) (1)

Donde \(f\) es la frecuencia, en hertz.

(\(f = 4\,hz\))

\(T = \frac{1}{4\,hz}\)

\(T = 0.25\,s\)

Ahora determinamos la fuerza aplicada sobre la prenda (\(F\)), en newtons:

\(F = m\cdot a\) (2)

\(F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}\) (2b)

Donde:

\(m\) - Masa de la prenda, en kilogramos.

\(r\) - Radio interior del tambor, en metros.

(\(m = 0.32\,kg\), \(r = 0.4\,m\), \(T = 0.25\,s\))

\(F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}\)

\(F \approx 80.852\,N\)

La velocidad lineal de la lavadora es:

\(v = \frac{2\pi\cdot r}{T}\) (3)

(\(r = 0.4\,m\), \(T = 0.25\,s\))

\(v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}\)

\(v \approx 10.053\,\frac{m}{s}\)

Y la velocidad angular del tambor de la lavadora:

\(\omega = \frac{2\pi}{T}\)

(\(T = 0.25\,s\))

\(\omega = \frac{2\pi}{0.25\,s}\)

\(\omega \approx 25.133\,\frac{rad}{s}\)

Answer:

False.

Explanation:

Mass is the amount of matter in a given object. Weight is the force acting on an object due to gravity.

Answer:

False

Explanation:

Weight is the act of pulling an object towards the earth surface so weight is a force to amount

Answer:

what is the answers? so i can't answer.

Explanation:

The statement that is true as regards movement of the box when pushed horizontally with constant velocity is given by;

Option D; The friction is equal to the applied force

The missing options are;

a) The friction is less than the applied force

b) There is no friction acting on the box

c) The friction is greater than the applied force

d) The friction is equal to the applied force

Now, if the frictional force was less than the applied force, it means the velocity of the box will gradually be increasing but we are told the velocity is constant.

Finally, if the frictional force is equal to the applied force, then the box will move with a constant motion.

Thus, in conclusion the friction is equal to the applied force.

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One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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Answer:

\(\huge\boxed{\sf Option \ A}\)

Explanation:

When we stir the solution such that it forms a mixture and the sugar is completely dissolved, we still find some ice cubes floating in the tea which shows that it is a heterogeneous mixture.

A Heterogeneous Mixture:

It is a mixture which has two or more phases that can be separated by physical means.

\(\rule[225]{225}{2}\)

Hope this helped!

Answer: Some ice cubes are floating in the tea.

Explanation:

A. Some ice cubes are floating in the tea.

B. Some water droplets form on the outside of the glass.

C. The mixture looks the same throughout.

D. The sugar crystals are no longer visible in the tea.

The correct realistic problem for the given equation is problem 1 in which the electric field strength of the disc is half its value at the center of the disk.

We know that,

Electric field of a charged disc at a distance along its axis is given by,

E = σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) )

Electric field at the centre of a charged disc is given by,

\(E_{c}\) = σ / 2 ε ( Since at centre, x = 0 )

Distance along the axis of a charged disk, where electric field strength's value is half its value at the center of the disk.

\(E_{x}\) = \(E_{c}\) / 2

σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) =  ( σ / 2 ε ) / 2

x / √ ( \(x^{2}\) + \(r^{2}\) ) = 1 / 2

4 \(x^{2}\) = \(x^{2}\) + \(r^{2}\)

3 \(x^{2}\) = \(r^{2}\)

x = r / √ 3 ,which is the correct distance, when magnitude is half its value from centre.

Electric field is a field that surrounds electrically charged particles that exerts force on other charged particles in the field.

Therefore, the given equation is suitable for Electric field of a charged disc at a distance along its axis where electric field strength's value is half its value at the center of the disk.

The given question is incomplete. The completed question is

You are given the following equation to solve a problem:

σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) = \(E_{c}\) = σ / 2 ε

Choose the most realistic problem for which this could be the correct equation.

1 ) At what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? Give your answer in terms of the disk's radius R.

2 ) At what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? Give your answer in terms of the disk's radius R.

3 ) At what distance along the axis of a charged square is the electric field strength double its value at the center of the square? Give your answer in terms of the square's side R.

4 ) At what distance along the axis of a charged square is the electric field strength half its value at the center of the square? Give your answer in terms of the square's side R.

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The maximum height reached by the roller coaster is  16.53 m.

The maximum height reached by the roller coaster is calculated by applying the principle of conservation of energy.

potential energy of the roller coaster at maximum height = kinetic energy at the lowest point

P.E = K.E

mgh = ¹/₂mv²

h = ( v² ) / ( 2g )

where;

h = ( 18² ) / ( 2 x 9.8 )

h = 16.53 m

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Answer:

160 years.

Explanation:

From the question given above, the following data were obtained:

Initial count rate (Cᵢ) = 400 count/min

Half-life (t½) = 40 years

Final count rate (Cբ) = 25 count/min

Time (t) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Initial count rate (Cᵢ) = 400 count/min

Final count rate (Cբ) = 25 count/min

Number of half-lives (n) =?

Cբ = 1/2ⁿ × Cᵢ

25 = 1/2ⁿ × 400

Cross multiply

25 × 2ⁿ = 400

Divide both side by 25

2ⁿ = 400/25

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time taken for the radioactive material to decay to the rate of 25 counts per minute. This can be obtained as follow:

Half-life (t½) = 40 years

Number of half-lives (n) = 4

Time (t) =?

n = t / t½

4 = t / 40

Cross multiply

t = 4 × 40

t = 160 years.

Thus, it will take 160 years for the radioactive material to decay to the rate of 25 counts per minute.

Answer:

cola forms so slowly that we could use up the supply that exists now

Answer: c and d

Explanation:

This requires sophisticated technology and a thorough understanding of the target solar system. Overall, detecting Planets in our solar system is a difficult task compared to detecting the light from the Sun itself.

Detecting the light from planets in our solar system for an alien astronomer would be considerably more difficult compared to detecting the light from the Sun itself. The main reasons for this challenge are the brightness, proximity, and reflected light.

1. Brightness: The Sun is a massive source of light, emitting a tremendous amount of energy as a result of nuclear fusion. In contrast, planets only reflect a small portion of the Sun's light, making them much dimmer and harder to detect.

2. Proximity: Planets in our solar system are relatively close to the Sun. As a result, their light can be easily overwhelmed by the Sun's light, making it challenging for an alien astronomer to distinguish between the two sources.

3. Reflected light: Planets don't emit their own light; they only reflect sunlight. This makes it harder to detect their presence since the reflected light can be easily overshadowed by the Sun's intense brightness.

To successfully detect the light from planets, an alien astronomer would need to use advanced observational techniques, such as analyzing the transit of planets across the Sun's face or the gravitational wobble caused by orbiting planets.

This requires sophisticated technology and a thorough understanding of the target solar system. Overall, detecting planets in our solar system is a difficult task compared to detecting the light from the Sun itself.

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The tank to drain completely in 75.8 minutes.

The definition of density It is possible to measure a material's density by how closely it is packed. The mass per unit volume is how it is formally defined. Density Symbol: D or The density is expressed as follows: = m/V, where m is the object's mass and V is its volume.

When half full, 100 liters must be drained.

Net rate of water draining out is = 32 - 10 = 22 g/s  or 22 ml/s = 0.022 L/s

Time taken to drain tank completely = 100 L / 0.022 L / s  

Time taken to drain tank completely = 4545.45 seconds  

Divide by 60 to find minutes

The tank to drain completely in minutes = 4545.45/60

The tank to drain completely in minutes = 75.8 minutes.

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Answer:

the ebergy

Explanation:

energy does it have if a miving object

Answer:

Explanation:

First of all we shall calculate the velocity of composite mass . Let it be v . Applying law of conservation of momentum

mu - MU = ( m + M ) v

v = mu - MU /  ( m + M )

loss of kinetic energy

= 1/ 2 mu² + 1/2 MU² - 1/2 ( M +m ) v²

= 1/ 2 mu² + 1/2 MU² - 1/2 ( M +m ) (mu - MU)² / ( m + M )²

= 1/ 2 mu² + 1/2 MU² - 1/2  (mu - MU)² / ( m + M )

= 1/2 [ m²u² + mMu² +mMU² + m²U² - m²u² - M²U² - 2 muMU ] /  ( m + M )

=  1 / 2 [ mMu² + mMU² - 2 muMU ] /  ( m + M )

= 1 / 2mM  [ (u² + U² - 2 uU)  /  ( m + M )]

= 1/2 mM  x k

where

k =  [ (u² + U² - 2 uU)  /  ( m + M )]

Given

m = .004 kg

M = 4 kg

u = 890 ms⁻¹

U = 7 ms⁻¹

k = ( 890² + 7² - 2 x 890 x 7 ) / 4.004

= ( 792100 + 49 - 12460 ) / 4.004

= 194727.52

loss of kinetic energy

= 1/2 mM  x k

= .5 x .004 x 4 x 194727.52

= 1557.82 J .

U = mgh, Ek = 1/2*m*v^2

U = Ek (conservation of mechanical energy)

⇒ mgh = 1/2*m*v^2

∵g = 10, v = 20

⇒ 10h = 1/2*400

⇒ h = 20 (m)

A ball is dropped from the cliff and the ball is travelling at the speed of 20 m/s, then the height at which the ball is dropped will be equal to 20 meters.

The work per unit mass required to transport an object from a fixed reference position to a given location is the gravitational potential at a certain location. With mass taking the function of charge, it is comparable to the electric potential. As per convention, any mass is infinitely far from the reference line, where the potential is 0, causing a negative potential at any particular distance.

The gravitational potential, also referred to as the Newtonian potential in mathematics, is essential for the understanding of potential theory.

From the equation of energy conservation,

Total mechanical energy = PE + KE

U = mgh and,

KE = 1/2 mv²

mgh = 1/2mv²

Speed, v = 20 m/s and,

acceleration due to gravity. g = 9.8 m/s²

10h = 1/2  × 400

h = 20 meters.

Therefore, the height from where the ball is dropped is 20 meters.

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Answer:

Speed and velocity are related in much the same way that distance and displacement are related. Speed is a scalar and velocity is a vector.

Answer:

294km

Explanation:

The equation to calculate distance given the speed and time is:

d = s * t

Now, we just need to plug in the given information:

The speed: 98km/h

The time: 3h

so:

d = 98 * 3

d = 294 km

Hope this helps, have a great day!

When the area of each plate is doubled while keeping the charge and separation constant, the electric field decreases, the potential difference remains the same, and the stored energy in the capacitor increases four times.

When the area of each plate of a capacitor is doubled while keeping the total charge on each plate and the separation between the plates constant, the following changes occur:

1. Electric Field: The electric field between the plates decreases. The electric field (E) between the plates of a capacitor is inversely proportional to the area (A) of the plates. As the area is doubled, the electric field is halved, assuming the other factors remain constant.

2. Potential Difference: The potential difference (V) across the plates remains the same. The potential difference across the plates of a capacitor depends on the charge (Q) and the capacitance (C), which is determined by the geometric and material properties of the capacitor. Since the total charge and separation between the plates are held constant, the potential difference remains unchanged.

3. Stored Energy: The stored energy in the capacitor increases four times. The energy stored in a capacitor (U) is directly proportional to the area of the plates (A). When the area is doubled, the stored energy is quadrupled (increases by a factor of four).

Therefore, when the area of each plate is doubled while keeping the charge and separation constant, the electric field decreases, the potential difference remains the same, and the stored energy in the capacitor increases four times.

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Answer:

Water can spread germs through bacteria.

Explanation:

Bacteria can live in water and can spread to new locations when water is moved.

1. C. It is one of the richest in natural resources.

2. D. Conflict often occurs over natural resources.

3. C. earthquake

4. B. earthquake

5. C. switching to a more plant-based diet

A seismograph is a device that is used to detect and measure seismic waves caused by earthquakes or other ground vibrations. Therefore, a seismograph helps predict and record earthquakes.

.

The Pacific Ocean and the Ring of Fire are known for having a high frequency of earthquakes and volcanic eruptions, which are some of the biggest hazards in this region.

The most effective way for an individual on their own to reduce climate change is by switching to a more plant-based diet.

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As a star's temperature increases, it becomes hotter. Its color changes from orange, through yellow, to white.

Answer:

Gamma rays

Explanation:

The gain (or attenuation) of the first system is approximately -80.3 dB to -77.3 dB. This system is associated with attenuation. The power change in dB for the second scenario is a decrease of approximately -3.01 dB.

To calculate the gain or attenuation of a system, we can use the formula:

Gain (in dB) = 10 × log10(Power output / Power input)

For the first system, the power input is 15.5 kW (or 15,500 watts), and the power output ranges from 10 watts to 15 watts. Plugging these values into the formula, we get:

Gain = 10 × log10(10 / 15,500) to 10× log10(15 / 15,500)

≈ -80.3 dB to -77.3 dB

Since the gain is negative, it indicates attenuation rather than amplification.

In the second scenario, the power change can be calculated using the formula:

Power change (in dB) = 10 × log10(Power final / Power initial)

The initial power output is 100 W, and the final power output is 50 W. Plugging these values into the formula, we get:

Power change = 10 × log10(50 / 100)

= 10× log10(0.5)

≈ -3.01 dB

Therefore, the power change in dB is a decrease of approximately -3.01 dB.

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Answer:

Mrs Hamilton

Explanation:

The most commonly used scale for predicting the potential threat posed by an asteroid impact is the Torino Scale and the more recently developed Palermo Scale.

An asteroid is a small rocky or metallic object that orbits the Sun. Most asteroids are found in the asteroid belt, a region of the solar system between the orbits of Mars and Jupiter. However, some asteroids can have orbits that bring them closer to Earth.

The Torino Scale, which was first introduced in 1999, is a risk assessment scale that uses a range of values from 0 to 10 to quantify the potential impact hazard of a near-Earth object (NEO) such as an asteroid or comet. The Torino Scale takes into account the size, velocity, and proximity of the NEO, as well as the likelihood of impact and the potential consequences.

The Palermo Scale, which was introduced in 2001, is a more sophisticated version of the Torino Scale that uses a probability-based approach to assess the potential impact hazard of a NEO. The Palermo Scale takes into account a wider range of factors, such as the NEO's orbit and the likelihood of impact, and provides a more accurate estimate of the potential threat.

Hence, The most commonly used scale for predicting the potential threat posed by an asteroid impact is the Torino Scale and the more recently developed Palermo Scale.

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Answer:

Crust

Explanation: