How much 5.80M NaOH must be added to 660.0 mL of a buffer that is 0.0210 M acetic acid and 0.0235 M sodium acetate to raise the pH to 5.75

Answer:

xy (-b+c+q) is the answer to this

Answer:

2.38 g of oxygen (O2).

Explanation:

What is given?

Mass of potassium chlorate (KClO3) = 6.06 g.

Molar mass of KClO3 = 122.4 g/mol.

Molar mass of oxygen (O2) = 32 g/mol.

Step-by-step solution:

First, let's state the balanced chemical equation. Remember that the decomposition of a compound produces two or more products:

Now, let's convert 6.06 g of KClO3 to moles using its molar mass:

You can see in the chemical equation that 2 moles of KClO3 produce 3 moles of O2. By doing a rule of three with this data, we obtain that:

The final step is to convert from 0.0743 moles of O2 to grams using its molar mass, like this:

The answer is that we will produce 2.38 g of oxygen (O2) from the decomposition of 6.06 g of potassium chlorate (KClO3).

When the radial wavefunction for an atomic orbital equals zero or reverses sign, angular nodes, which are flat planes, are created. Radial nodes, on the other hand, are spheres. R(r) = 0 designates a radial node.

For a given atom, the only factor affecting radial wave functions is the nucleus's distance, r. An orbital's shape can be effectively described by angular wave functions, which only depend on direction. As stated in the definition, probability density at a location is "probability per unit volume in limit that volume is infinitesimally." A given radius's radial probability distribution, which varies with radial distance from the nucleus, is the probability density of an electron in an infinitesimally thin spherical shell at that radius.

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Answer:

Its D :)

Or not i haven't done this in a while-

Answer:

IIron is the 26th element on the periodic table. It is located in period 4 and group 8. And for the properties, iron, like other metals, conducts heat and electricity, has a luster, and forms positive ions in its chemical reactions. Pure iron is fairly soft and can easily be shaped and formed when hot. Its color is silvery white. Iron is easily magnetized.

Explanation:

Answer:

45km/hr

Explanation:

270/6=45

The partial pressure of \(SO_2Cl_2\) is 1.76 mm Hg after 15 hours.

The given reaction, \(SO_2Cl_2 (g)\) → \(SO_2\) (g) + \(Cl_2\) (g), is first-order in\(SO_2Cl_2\)with a half-life of 245 minutes at 600 K.

To determine the partial pressure of each reactant and product after 245 minutes, we can use the following equation:

ln (P0/Pt) = kt

Where P0 is the initial pressure, Pt is the pressure after time t, k is the rate constant, and t is the time.

Using the given half-life of 245 minutes, we can calculate the rate constant (k) as follows:

t1/2 = ln2 / k
245 min = ln2 / k
k = ln2 / 245 min
k = 0.00283 min^-1

Now, we can use the above equation to calculate the partial pressures of each reactant and product after 245 minutes:

For\(SO_2Cl_2\):
ln (25/Pt) = 0.00283 \(min^-^1\) * 245 min
Pt = 9.59 mm Hg

For \(SO_2\):
ln (0/Pt) = 0.00283\(min^-^1\) * 245 min
Pt = 0 mm Hg

For \(Cl_2\):
ln (0/Pt) = 0.00283 \(min^-^1\)* 245 min
Pt = 0 mm Hg

Therefore, after 245 minutes, the partial pressure of\(SO_2Cl_2\) is 9.59 mm Hg, and the partial pressures of \(SO_2\) and \(Cl_2\) are both 0 mm Hg.

To determine the partial pressure of each reactant after 15 hours, we can use the same equation with t = 900 minutes (15 hours):

For\(SO_2Cl_2\) :
ln (25/Pt) = 0.00283 min^-1 * 900 min
Pt = 1.76 mm Hg

Therefore, after 15 hours, the partial pressure of \(SO_2Cl_2\) is 1.76 mm Hg.

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Answer:

H - Cl2 +NaBr -> Br2+2NaCl

Answer: If a dark section of pavement absorbs more of the sun's energy than it reflects, then that section will feel warmer over the course of a sunny day.

Electron changes their spin to match the spin of proton in the nucleus. Hence, option C is correct.

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.

21-centimetre radiation, electromagnetic radiation of radio wavelength emitted by cold, neutral, interstellar hydrogen atoms. The hydrogen atom is composed of a positively charged particle, the proton, and a negatively charged particle, the electron. These particles have some intrinsic angular momentum called spin.

Hence, option C is correct.

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Well, the answer is the 4rth one "

50°C"

The mass of potassium hydroxide required to neutralize 0.955 moles of sulfuric acid is 107.08 grams.

The balanced equation you provided is for the reaction of potassium hydroxide with sulfur dioxide, not sulfuric acid. The correct equation is:

2KOH(aq) + H2SO4(aq) → K2SO4(aq) + 2H2O(l)

To find the mass of potassium hydroxide required to neutralize 0.955 moles of sulfuric acid, you can use the mole ratio between potassium hydroxide and sulfuric acid in the balanced equation, which is 2:1. That means you need twice as many moles of potassium hydroxide as sulfuric acid to completely neutralize it.

So, the number of moles of potassium hydroxide required is 2 x 0.955 = 1.91 moles.

To calculate the mass of potassium hydroxide required, you can use its molar mass, which is 56.11 g/mol:

mass = number of moles x molar mass

mass = 1.91 moles x 56.11 g/mol

mass = 107.08 g

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a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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It is true that most metals,semiconductors , and ceramics have a crystalline structure in which the atoms or ions display short-range order.

This means that the atoms or ions in these materials are arranged in a specific pattern that repeats itself over and over again, giving the material its characteristic structure. This short-range order is what gives these materials their unique properties, such as their strength, semiconductorsconductivity, and thermal stability. So, the statement that most metals, semiconductors, and ceramics have a crystalline structure in which the atoms or ions display short-range order is true.It is true that most metals, semiconductors, and ceramics have a crystalline structure in which the atoms or ions display short-range order. This means that the atoms or ions in these materials are arranged in a specific pattern that repeats itself over and over again, giving the material its characteristic structure. This short-range order is what gives these materials their unique properties, such as their strength, conductivity, and thermal stability. So, the statement that most metals, semiconductors, and ceramics have a crystalline structure in which the atoms or ions display short-range order is true.

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The volume of CO₂ gas produced is 34.8 liters.

The chemical reaction stating decomposition of CaCO₃ is -

CaCO₃ → CaO + CO₂

In the above reaction, CaCO₃ is calclium carbonate, CaO represents calcium oxide and CO₂ is the chemical formula of carbon dioxide.

In the reaction, 1 mole of CaCO₃ forms 1 mole of CO₂. So, number of moles of CaCO₃ consumed will be equal to number of moles of CO₂ produced.

Molar mass of CaCO₃ = 100.1 grams/mole

Number of moles = \(\frac{45}{100.1}\)

Number of moles = 0.44955 moles

Now, using ideal gas equation to find the volume of CO₂ produced at STP.

PV = nRT, where P is pressure in atm, V is volume in liters, n is number of moles, R is gas constant and T is temperature in Kelvin.

Taking R =  0.0821 L-atm per mol-K

Also, 1 torr = 0.00132 atm

So, 645 torr = 0.00132*645

645 torr = 0.8487 atm

Keep the values in formula to find Volume.

\(V = \frac{0.44955*0.0821*800}{0.8487}\)

V = 34.8 liters

Hence, the volume of CO₂ gas produced is 34.8 liters

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Rutherford conclusion was: Inside of the gold atom consists of empty spaces.

Rutherford theorized that atoms have their charge concentrated in a very small nucleus.

This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).

Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.

That is different from Plum Pudding model, because it shows that most of the atom is empty space.

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Answer:

There are approximately 5.55 moles

Explanation:

Anti-glycolytic training avoids metabolic fatigue to ensure the primary source of energy is: fat. Anti-glycolytic training typically involves longer, low-intensity exercises that rely on aerobic metabolism.

The primary source of energy in anti-glycolytic training is fat. This type of training aims to minimize the production of lactic acid, which is a byproduct of the breakdown of glucose. By doing so, it helps to improve fat oxidation and enhance endurance performance. Anti-glycolytic training typically involves longer, low-intensity exercises that rely on aerobic metabolism.

This approach allows the body to use fat as the primary fuel source, sparing glycogen and reducing metabolic fatigue. Overall, the goal of anti-glycolytic training is to enhance the body's ability to utilize fat for energy and improve endurance capacity.

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Answer:

B.

Explanation:

Rust is a chemical change because you can not undo it. Rusting of iron is a chemical change because a new substance iron oxide is formed. The presence of oxygen and water or water vapour is essential for rusting.

No, the amount given to the policeman at the end of his 10-hour shift, which is 0.4 kg, is not the correct amount based on the payment rate of 1 mole per hour.

To determine if the amount is correct, we need to convert the given mass of 0.4 kg to moles using the molar mass of calcium [40 Ca].

The molar mass of calcium is approximately 40.08 g/mol. Since the atomic mass of calcium is close to 40 g/mol, we can assume that the given molar mass refers to calcium-40, denoted as [40 Ca].

To convert the mass to moles, we can use the formula:

moles = mass (in grams) / molar mass

moles = 0.4 kg * 1000 g/kg / 40.08 g/mol

moles ≈ 9.98 mol

Therefore, the amount of calcium [40 Ca] the policeman received after his 10-hour shift is approximately 9.98 moles, not 1 mole per hour as stated in the payment rate.

Thus, the amount given to him is significantly higher than the correct amount. It appears there may have been an error in the payment calculation or a misunderstanding regarding the payment rate.

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Answer:

Assuming both players are on the same surface and are wearing the same kind of shoes, who will win the game and why?

Mason will win because although he is applying less force than William, he is smaller and can move faster than William.

The diene that reacts with one equivalent of HBr to form the two bromoalkene products described in the question can be drawn as follows:

    H          H

    |          |

H3C-C=C-CH2-CH=CH2

    |          |

    H          H

In this diene, there are two double bonds, one between carbons 2 and 3 and another between carbons 4 and 5. When one equivalent of HBr is added to this diene, an electrophilic addition reaction occurs in which the H and Br add to the two double bonds to form two different products, as described in the question.

The effect of increasing temperature on the relative amount of each product can be explained by considering the mechanism of the reaction. The reaction proceeds through a carbocation intermediate, which is formed by protonation of the diene with HBr. The carbocation intermediate can then react with Br- to form the bromoalkene products.

Product 1 is formed by the addition of HBr to the double bond between carbons 2 and 3, which results in the formation of a more stable tertiary carbocation intermediate. As the temperature increases, the reaction rate increases, which can lead to a higher proportion of product 1 being formed. However, at very high temperatures, the reaction rate can become too fast, leading to increased side reactions such as rearrangements, which can decrease the relative amount of product 1.

Product 2 is formed by the addition of HBr to the double bond between carbons 4 and 5, which results in the formation of a less stable secondary carbocation intermediate. As the temperature increases, the reaction rate also increases, which can lead to a higher proportion of product 2 being formed. However, at very high temperatures, the reaction rate can become too fast, leading to increased side reactions such as elimination, which can decrease the relative amount of product 2.  Therefore, the answer to the question is that as the temperature increases, the relative amount of product 1 is expected to increase, while the relative amount of product 2 is expected to decrease due to side reactions. However, at very high temperatures, both products can be affected by side reactions, and the relative amounts may not change significantly.

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Answer:

B.) SnO and SnO₂

Explanation:

Tin can either exist as Sn²⁺ or Sn⁴⁺ when ionized. Oxygen always exists as O²⁻ when ionized.

When ions combine, sometimes there needs to be different amounts of each ion in order to create an overall charge of 0. In one combination of the ions (Sn²⁺ and O²⁻), there only needs to be one atom of each ion. In another combination (Sn⁴⁺ and O²⁻), you need to have more anions to balance the high positive charge of the cation.

SnO
-----> Sn²⁺ and O²⁻

-----> +2 + (-2) = 0

SnO₂

-----> Sn⁴⁺ and O²⁻

-----> +4 + (-2) + (-2) = 0

The grams of sodium chloride  are needed to make 0.5 l of a 0.15 M solution is 4.38 g.

The molarity of the sodium chloride solution = 0.15 M

The volume of the sodium chloride solution = 0.5 L

The number of the moles of the sodium chloride = molarity × volume

The number of the moles of the sodium chloride = 0.15 × 0.5

The number of the moles of the sodium chloride = 0.075 mol

The molar mass of the sodium chloride = 58.4 g/mol

The mass of the sodium chloride = moles × molar mass

The mass of the sodium chloride = 0.075 × 58.4

The mass of the sodium chloride = 4.38 g

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Explanation:

Hydrogen bonding, present in alcohols but not hydrocarbons, leads to strong intermolecular forces and increases the boiling point significantly.

For example:

Glycerol has 3 OH groups, which lead to a much more extensive hydrogen-bonding network and a higher boiling point compared to the 1 OH or 2 OH in other chains.

The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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Answer:

Man-made radiation is generated in range of medical, commercial and industrial activities and natural occuring radiation occurs due to minerals.

Carbon is a non metal and also has four valence electrons.

Answer:

Explanation:

The speed of an object can be found by using the formula

\(v = \frac{d}{t} \\ \)

where

d is the distance

t is the time taken

From the question we have

\(v = \frac{100}{30} = \frac{10}{3} \\ = 3.333333...\)

We have the final answer as

Hope this helps you

Answer:

The law of conservation of matter says that matter cannot be created or destroyed.

Explanation:

Answer:

Atoms don’t appear or disappear during the reaction. Instead, they get rearranged.

Explanation:

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