how might the atoms that make up bones be different from the atoms that make up soft tissue?

6.07 grams is the theoretical yield of calcium phosphate (Ca₃(PO₄)₂).

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M= molar mass

Given chemical reaction is:

3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂

From the stoichiometry it is clear that:

3 moles of Ca(NO₃)₂ = produce 1 mole of Ca₃(PO₄)₂

Given mass of Ca(NO₃)₂ = 96.1g

Mole of Ca(NO₃)₂ = 96.1g/164g/mol = 0.5859moles

So, 0.5859 moles of Ca(NO₃)₂ = produce 0.5859×1/3 = 0.0196 moles of Ca₃(PO₄)₂

Required mass of Ca₃(PO₄)₂ will be calculated by using moles as:

W = 0.0196mole × 310g/mole = 6.07 grams

Hence, 6.07 grams is the theoretical yield of calcium phosphate.

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Answer:

qns-4

1-multicellular organism

2-unicellular organism

3-unicellular organism

4-multicellular organism

5-unicellular organism

6-multicellular organism

7-unicellular organism

1. Hours

2. 2 hours

3. 1 hour and 50 minutes

4. Hours

5. 300 minutes

6. 7 hours

7. 240 minutes is the same as 4 hours

There are 1.2186 × 10⁴ grams of platinum (Pt) in 62.51 moles of Pt.

To find the number of grams of platinum (Pt) in 62.51 moles of Pt, we need to use the molar mass of Pt. The molar mass of Pt is 195.08 g/mol. We can use this to convert moles of Pt to grams of Pt using the following equation:

grams of Pt = moles of Pt × molar mass of Pt

Plugging in the given values, we get:

grams of Pt = 62.51 moles of Pt × 195.08 g/mol

grams of Pt = 12,186.17 grams of Pt

To express this answer in scientific notation, we need to move the decimal point to the left until we have a number between 1 and 10, and then multiply by 10 to the power of the number of places we moved the decimal point. In this case, we need to move the decimal point 4 places to the left, so our answer in scientific notation is:

grams of Pt = 1.2186 × 10⁴ grams of Pt

So the answer is  1.2186 × 10⁴ grams.

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Answer:

Yes

Beryllium is a chemical element with the symbol Be and atomic number 4. It is a steel-gray, strong, lightweight and brittle alkaline earth metal. ... Notable gemstones high in beryllium include beryl (aquamarine, emerald) and chrysoberyl.

Calcium is a mineral that is necessary for life. In addition to building bones and keeping them healthy, calcium enables our blood to clot, our muscles to contract, and our heart to beat. About 99% of the calcium in our bodies is in our bones and teeth.

The best types of drinks for someone having a stomach ulcer are basic drinks.

If someone is having stomach ulcer they should avoid acidic drinks as they can cause further irritation in the stomach lining and can cause more pain to the person. Instead of acidic drinks one can prefer basic drinks as they are more helpful and consuming them can help in neutralizing the excess acid in the stomach.

Based on the class notes we know that on the PH scale, basic drinks have a ph value greater than 7 and acidic drinks have a ph value less than 7. For someone having a stomach ulcer he or she needs to consume basic drinks more or drinks whose ph value is greater than 7 because it helps them to reduce the acids in the stomach.

Examples of basic drinks are milk, soy milk, almond milk, and herbal tea. On the other hand examples of acidic drinks are: citrus juices, soda, and energy drinks.

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The volume of the container that the gas is in is 21.13 liters.

To find the volume of the gas, use the ideal gas law formula:

PV = nRT

In which:

P = Pressure of the gas

V = Volume of the gas

R = Ideal gas constant

n = Number of moles of the gas

T = Temperature of the gas

Firstly, change the given values to the correct units:

Pressure = 933.8 torr

Temperature = 41.6 °C

To change the temperature to Kelvin:

T(K) = 41.6 °C + 273.15

T = 314.75 K

To change the pressure to atm:

Pressure = Pressure(torr) ÷ 760

Pressure = 933.8 torr ÷ 760

Pressure  = 1.2289 atm

Now put the values into the ideal gas law formula and solve for V:

V = (nRT) ÷ P

V = (0.9 mol × 0.0821 L·atm/(mol·K) × 314.75 K) ÷ 1.2289 atm

V = 21.13 liters

The gas's container has a capacity of roughly 21.13 litres.

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In 12 minutes, approximately 50 grams of chemical C is formed.

The rate of the reaction is proportional to the product of the instantaneous amounts of chemicals A and B not converted to chemical C. Initially, there are 40 grams of A and 50 grams of B. For each gram of B, 2 grams of A is used. In 6 minutes, 25 grams of C is formed.

To find the amount of C formed in 12 minutes, we can use the concept of proportionality. Since the rate is proportional to the product of the amounts of A and B, and we know the rate of C formation in 6 minutes, we can set up the following proportion:

(25 grams of C) / (6 minutes) = (x grams of C) / (12 minutes)

By cross-multiplying and solving for x, we can determine that approximately 50 grams of C is formed in 12 minutes.

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The formation of adipic acid from cyclohexanol involves a chemical reaction known as oxidation. Specifically, it undergoes a two-step oxidation process.

The first step involves the oxidation of cyclohexanol to form cyclohexanone. This oxidation is typically carried out using an oxidizing agent such as sodium or potassium dichromate in the presence of sulfuric acid or a catalyst such as pyridinium chlorochromate. In this reaction, the hydroxyl group (-OH) of cyclohexanol is converted into a carbonyl group (C=O) in cyclohexanone.

The second step is the further oxidation of cyclohexanone to adipic acid. This step usually involves the use of nitric acid or nitric acid in the presence of a catalyst. In this reaction, the carbonyl group of cyclohexanone is oxidized to form two carboxyl groups (-COOH) in adipic acid.

Overall, the formation of adipic acid from cyclohexanol involves an oxidation reaction where the hydroxyl group of cyclohexanol is first converted to a carbonyl group, and then the carbonyl group is further oxidized to carboxyl groups, resulting in the formation of adipic acid.

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The mass of iron sample will be 585 grams.

According to the question,

Density of iron sample = 7.80 g/cm³

Volume of water displaced = 75.0 ml

1 ml = 1 cm³

Therefore, 75 ml = 75 cm³

Density is defined as the mass (m) of a substance per unit volume (V). It can be generally denoted by ρ. Therefore, ρ = m/V.

Mass is the amount of matter present in a substance. Volume is the 3-D space occupied by a substance.

In the given question density and volume are provided and to find the value of mass, the formula can be rewritten as: m = ρ × V.

Hence, m = 7.80 g/cm³ × 75 cm³

            m = 585 grams.

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25.8 g of NH₄NO₃ decomposed to produce 32.3 L of water vapor.  71.4 g of NH₄NO₃ are needed to produce 10.0 L of O₂.

a) To determine the number of liters of water vapor produced, we first need to calculate the moles of NH₄NO₃ that decompose:

The molar mass of NH₄NO₃ is:

M(NH₄NO₃) = 14.01 g/mol (N) + 4(1.01 g/mol) (H) + 3(16.00 g/mol) (O) = 80.05 g/mol

The moles of NH₄NO₃ can be calculated as:

moles NH₄NO₃  = mass/molar mass = 25.8 g / 80.05 g/mol = 0.322 moles  NH₄NO₃

From the balanced equation, we see that 4 moles of H₂O are produced for every 2 moles of  NH₄NO₃  that decompose, so we can calculate the moles of H₂O produced as:

moles H₂O = 4/2 x moles NH₄NO₃ = 4/2 x 0.322 = 0.644 moles H₂O

Finally, we can use the ideal gas law to calculate the volume of water vapor produced at 350 degrees C and 0.950 atm:

PV = nRT

V = nRT/P

V = (0.644 mol) (0.0821 L·atm/mol·K) (623 K) / (0.950 atm) = 32.3 L

Therefore, 25.8 g of NH₄NO₃ decomposed to produce 32.3 L of water vapor.

b) To determine the grams of NH₄NO₃ needed to produce 10.0 L of O2, we can use the same approach, starting with the ideal gas law:

The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol.

The moles of O2 needed to produce 10.0 L can be calculated as:

moles O2 = V/STP = 10.0 L / 22.4 L/mol = 0.446 moles O2

From the balanced equation, we see that 2 moles of  NH₄NO₃ decompose to produce 1 mole of O2, so we can calculate the moles of NH₄NO₃ needed as:

moles NH₄NO₃= 2/1 x moles O2 = 2/1 x 0.446 = 0.892 moles NH4NO3

Finally, we can use the molar mass of NH4NO3 to calculate the grams needed:

mass NH₄NO₃ = moles NH₄NO₃ x molar mass = 0.892 mol x 80.05 g/mol = 71.4 g

Therefore, 71.4 g of NH₄NO₃ are needed to produce 10.0 L of O₂.

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The answer is (e) 0.1 because the fraction of solute remaining in the aqueous phase = 1/10 = 0.1.

The equation for the partition coefficient (K) is:

K = [organic]/[aqueous]

where [organic] and [aqueous] are the concentrations of the compound within the organic and aqueous phases, respectively. In this situation, the partition coefficient (K) is 9 in favor of the organic segment over the aqueous phase.

This means for each 1 unit of solute within the aqueous segment, there are 9 units of solute within the natural segment. Let's assume that we begin with 1 unit of solute within the aqueous section. After one extraction, we switch this 1 unit of solute to the natural section.

In keeping with the partition coefficient, this means that there at the moment are nine units of solute within the organic phase. If we use an identical quantity of solvent for every segment, we are able to have a 1:1 ratio of the natural segment to the aqueous segment after the extraction.

Consequently, the entire quantity of solute gift after the extraction might be 1 + 9 = 10 units. To determine the fraction of solute that remains inside the aqueous section, we divide the quantity of solute within the aqueous segment by the total quantity of solute:

Fraction of solute ultimate within the aqueous section = 1/10 = 0. 1

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ANSWER: We know, by law of constant proportion :

Chemical compounds always contains its component in constant fixed ratio or in fixed percentage without depend on its source, method of preparation and mass of compound.

Therefore, percentage of oxygen is same for any mass.

Hence, this is the required solution.

Explanation:

Answer:

A reversible reaction.

Global Warming

Explanation:

The melting of the polar ice caps due to mostly negative human interactions with the environment.

Answer:

3

Explanation:

3 because it's the most scientific and specific, and it shows the independent and dependant variables

Answer:

I believe your answer is C.

Explanation:

First of all, if you pay attention to the details of the question it states that scientific hypothesis should be specific and demonstrate the relationship between the independent and dependant variable.

Answer A - Does demonstrate the relationship between the independent and dependant variable. but it's not very specific. Thus it is Not the answer.

Answer B - is not specific or demonstrates the relationship between the independent and dependant variable. Thus it is Not the right answer.

Answer C - Fits the criteria as it is specific, and demonstrates the relationship between the independent and dependant variable. Thus it is the Right answer

Answer D - is in the same category as B so again is Not the right answer.

Therefore your only option is C. Your welcome, and have a wonderful day

Answer: I dont think so cause muslims that wear a hijab cant show they're

Shlouders

i can't see the question but if u tryna ask if u can show ur shoulders if ur a hijabi then no?

0.0758 L is the volume of a 133 ppm NH3 solution with a density of 0.988 g/ml is required to provide 0.0175 grams of NH3.

To find the volume of a 133 ppm NH3 solution required to provide 0.0175 grams of NH3, we'll first convert the concentration of the solution from parts per million (ppm) to grams per liter (g/L).

= (ppm) x (density of solution in g/mL) x (molecular weight of solute in g/mol) / (10^6)

= (g/L)

For a 133 ppm NH3 solution at 0.998 g/mL density:-

= (133 ppm) x (0.998 g/mL) x (17.03 g/mol) / (10^6)

= 0.2309 g/L

Next, we'll use the mass of NH3 (0.0175 g) and the concentration of the solution (0.2309 g/L) to find the volume of the solution required:

= (mass of NH3 in g) / (concentration of solution in g/L)

= (volume of solution in L)

= (0.0175 g) / (0.2309 g/L)

= 0.0758 L

So, 0.0758 liters of the 133 ppm NH3 solution with a density of 0.998 g/mL is required to provide 0.0175 grams of NH3.

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The pH of the solution will be 10.47.

The pH of a solution is mathematically given as:

 pH = - log [\(H^+\)] of -log [\(H_3O^+\)]

Thus, in this case, with  [\(H_3O^+\)]  of 3.4 x 10-¹¹ M:

pH = -log 3.4 x \(10^-^1^1\) = 10.47

Thus, the pH of the solution will be 10.47.

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Answer:

D. Pimmada's candle burning.

Explanation:

Answer: C. Conducts electricity in the solid state

Explanation:

They are. solids liquids gases and plasma. and fift one in man made.

Answer:

gas vibrate and move freely at high speeds. liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place.

Answer:

The soilds vibrate in a fixed position and are very packed together whilst in liquids they are close together but they can move around and gases are widely spaced and move around randomly

Explanation:

Answer:

The answer is Inference.

The type of bond that connects adjacent nucleotides in a single strand of nucleic acid is a phosphodiester bond.

It forms between the 3' carbon of one nucleotide and the 5' carbon of the next nucleotide in the chain, linking the two nucleotides together.

The resulting sugar-phosphate backbone provides structural stability to the nucleic acid molecule and allows it to persist as a long polymer.

This backbone is essential for the function of both DNA and RNA as genetic and functional molecules, respectively.

The bond between the nucleotides in a nucleic acid can be broken by hydrolysis, releasing individual nucleotides and allowing for the molecule to be degraded or modified as needed for cellular processes.

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Option g. formic propanoic anhydride.

Propionic anhydride is an organic compound with the system CH₃CH₂CO₂O. This easy acid anhydride is a colorless liquid. it is a broadly used reagent in natural synthesis in addition to producing distinctive derivatives of cellulose.

Propionic Anhydride is a colorless liquid with a very sturdy, unpleasant smell. it's far used in the manufacture of perfumes, oils, resins, dyestuffs, drugs, and cellulose esters.

Anhydrides react with alcohols to form esters as the main product and carboxylate as a facet product. The response is generally run with a base, such as NaOH or pyridine, to take away any acid produced.

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2.497 grams of CuSO4⋅5H2O are needed to prepare 100 mL of a 0.10 M solution.

The term molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.

We need your target solution to have a molarity of 0.10 M and a volume of 100. mL. Therefore,molarity is defined as moles of solute per liter of solution, you can say that the target solution must contain.

Now, calculate the hydrate's percent composition by using its molar mass and the molar mass of anhydrous copper(II) sulfate.

= 159.61g mol−1(159.61+5×18.015)g mol−1×100

= 63.92% CuSO4

This tells you that for every 100 g of copper(II) sulfate pentahydrate, you get 63.92 g of anhydrous copper(II) sulfate. Use this as a conversion factor to get

= 1.596g CuSO4⋅100 g × CuSO4⋅5H2O / 63.92g CuSO4

= 2.497 g CuSO4⋅5H2O

Thus, 2.497 grams of CuSO4⋅5H2O are needed to prepare 100 mL of a 0.10 M solution.

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The molarity of the diluted standard solution is obtained by calculation to be 0.015 M.

Recall the dilution formula;

C1V1 = C2V2

C1 = Initial concentration = 0.1140 M

V1 = initial volume =  6.50mL

C2 = Final concentration = ?

V2 = Final volume = 50.0mL

Making C2 the subject of the formula and substituting values;

C2 = C1V1/V2

C2 = 0.1140 M ×  6.50mL/50.0mL

C2 = 0.015 M

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