How many (whole) dark fringes will be produced on an infinitely large screen if green light (λ = 545 nm) is incident on two slits that are 15.0 μm apart? (The 3% margin of error does not apply for this question.)

Answer:

Force exerted on the car is 7030 N.

Explanation:

It is given that,

Mass of the car, m = 740 kg

Initial speed of the car, u = 19 m/s

Final speed of the car, v = 0

Time taken, t = 2 s

Let F is the force exerted on the car during this stop. We know that it is equal to the product of force and acceleration. Mathematically, it is given as :

F=m\times \dfrac{v-u}{t}F=m×tv−u

F=740\times \dfrac{0-19}{2}F=740×20−19

F = -7030 N

So, the force exerted on the car during this stop is 7030 N. Hence, this is the required solution.

Answer:

D

Explanation:

As the wavelength of a wave gets shorter, its frequency increases, while its energy increases. This relationship is described by the equation E = hf, where E is the energy, h is Planck's constant and f is the frequency of the wave.

The total cut time for drilling 30 bolt holes is 76.2 seconds.

To calculate the total cut time to drill a bolt-hole pattern with 30 holes into 6061-T6 aluminum, we need to consider the depth of the hole, the speed, and the feed. Here's the step-by-step explanation:

1. Depth of hole: 25.4 mm
2. Speed: 2000 rpm (revolutions per minute)
3. Feed: 0.30 mm/rev (millimeters per revolution)

Now, to calculate the cut time for a single hole:

Cut Time (per hole) = Depth of hole / (Speed × Feed)

Cut Time (per hole) = 25.4 mm / (2000 rpm × 0.30 mm/rev)

Next, we need to convert the units to have a consistent measure:

1 minute = 60 seconds, so 2000 rpm = 2000/60 rev/sec

Now, substitute the values:

Cut Time (per hole) = 25.4 mm / ((2000/60) rev/sec × 0.30 mm/rev)

Simplify the expression:

Cut Time (per hole) = 25.4 mm / (33.33 rev/sec × 0.30 mm/rev)

Cut Time (per hole) = 25.4 mm / 10 mm/sec

Cut Time (per hole) = 2.54 seconds

Now, to calculate the total cut time for 30 holes:

Total Cut Time = Cut Time (per hole) × Number of holes
Total Cut Time = 2.54 seconds/hole × 30 holes

Total Cut Time = 76.2 seconds
So, the total cut time to drill a bolt-hole pattern with 30 holes into 6061-T6 aluminum is 76.2 seconds.

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Answer:

Grandma will arive \(\frac{1}{2}\)hr later

Explanation:

\(s=20\\d=210 mi|\\ s=70 mi|h \\ \\ \frac{60}{1} =\frac{210}{+} = 3.5 hrs\)

Explanation:

Solubility is the ability to dissolve within a solvent to form a mixture called a solution

If a substance is soluble, it dissolves in water
If a substance is insoluble in water -  it does not dissolve
Boling point - the temperature at which a substance in its liquid state
converts into the same substance in its gas state.
Water boils at 100 degree centigrade.
Melting point - the temperature at which a substance in its solid state
converts into the same substance in a liquid state.
Ice melts at 0 degree centigrade.
Water freezes at 0 degree centigrade.
How much matter (mass) is packed into a specific space (volume).

Answer:La verdad no tengo conocimiento alguno pero solo te puedo decir que las opciones que te dan en la hoja te pueden ayudar

Explanation:

Answer:1.  verbal communication, which you listen to a person to understand what they are saying 2. written communication, you read what a person is trying to say 3. nonverbal communication, which you observe what someone is trying to say, like sign language.

Explanation:

Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

Contact improvisation stems from the idea that each body is unique.

Body contact improvisation is a form of dance which incorporates elements from sporting movement and gymnastics, martial arts, and modern theatre practices.

Contact Improvisation liberate the dancer from the concern of the outward appearance of movement. Instead of giving importance to it’s outside visual aspect, this practice focuses in sensing a partner while having a body dialogue with her/him.

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Each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.

The three solutions tested to remove oil from water are scooping the oil with a spoon, absorbing the oil with a paper towel, and using soap to break up the oil. Each solution has its advantages and disadvantages. Scooping the oil with a spoon is an effective solution to remove a significant amount of oil quickly. However, it is not a practical solution for removing a large amount of oil. The disadvantage is that it spreads the oil around the surface of the water and leaves some oil in the water. Absorbing the oil with a paper towel can effectively remove a lot of oil. The advantage is that it removes some oil from the water, leaving it relatively clean. However, it also picks up a lot of water and can't get all of the oil. Using soap to break up the oil is a good solution that removes all of the oil from the water. The advantage is that it removes all of the oil from the water, leaving it clean. However, the disadvantage is that it disperses the oil on the surface of the water, making it harder to remove from the sides of the bowl. In conclusion, each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.

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Answer:

F=m[vf-vi]/t

t=m[vf-vi]/F

t=[1200][2]/[550]

t=4.36s

Explanation:

A tow truck will take 4.36 s.

Given:

Force, F= 550N

Mass, m= 1200kg

Final Velocity vf= 2 m/s

Initial Velocity vi= 0 m/s

A force can cause an object with mass to change its velocity (e.g. moving from a state of rest), i.e., to accelerate.

\(F= m*a\)...............(i)

and \(a=\frac{[v_f-v_i]}{t}\)...............(ii)

So, on substituting (ii) in (i)

\(F=\frac{m[v_f-v_i]}{t} \\\\t= \frac{m[v_f-v_i]}{F}\\\\t= \frac{[1200][2-0]}{[550]} \\\\t=4.36s\)

Thus, time taken is 4.36 s.

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Answer:

Explanation:

His top speed is a blip that occurs for less than the full time he was out. Below is a graph showing what he did from 1 o'clock to 9. He was walking from 1 to the point where starts walking faster and then back down again to 2. The line at 2 is longer than the triangular shape that shows where he speeded up. Then he went back down to 2 and continued at that speed until 9.

Obviously he spent more time at 2 than he did at 4 and therefore his average speed will less than the 4 speed.

Remember that average speed = total distance / total time.

The g - string will stretch by 0.0016 mm.

We have a g - string of a guitar with given specifications.

We have to determine how many mm does a 75-cm-long g - string stretch when it’s first tuned.

According to the question -

The force of tension in the string -

\($v = \sqrt{\frac{T}{\mu} }\)

T = \($v^{2} \mu\) = 250 x 250 x 0.0011 = 68.75 N

The Yung modulus of steel = 2 x \(10^{11}\) N/\(m^{2}\)

the amount by which the g - string will be stretched is given by -

\($\delta L = \frac{LT}{Y(\pi r^{2})}\)

Substituting the values -

\($\delta L = \frac{0.75\times 68.75 }{(2\times 10^{11} )\times (\pi (2.2 \times 10^{-4}\times 2.2\times 10^{-4}) )}\)

\(\delta L=\) 0.0016mm

Hence, the g - string will stretch by 0.0016 mm.

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[ The given question is incomplete. The complete question is

" The G string on a guitar is a 0.46-mm-diameter steel string

with a linear density of 1.1 g/m. When the string is properly

tuned to 196 Hz, the wave speed on the string is 250 m/s. Tuning

is done by turning the tuning screw, which slowly tightens—and

stretches—the string. By how many mm does a 75-cm-long G

string stretch when it’s first tuned? "]

The sparks that could jump from an electrical circuit depend on the direction of the current. If the current is directed from left to right, then the sparks would first be seen on the left side.

This is because the electrons in the current flow from the negative terminal of the power source to the positive terminal. As the electrons flow along the circuit, they create a spark at the point where the electrons encounter a break in the circuit.

The sparks would continue to jump from the left side as long as the current is flowing in that direction. On the other hand, if the current is flowing right to left, then the sparks would first be seen on the right side. This is because the electrons are flowing from the positive terminal of the power source to the negative terminal. The sparks would then continue to jump from the right side until the current is turned off.

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The symbolic expression for the moment of inertia of the pulley in terms of the tensions t₁ and t₂, the pulley radius r, and the acceleration a is:

I = (1/2)(t₁ + t₂)r² / a

The moment of inertia (I) of a pulley is a measure of its resistance to rotational motion. It depends on various factors, including the tensions (t₁ and t₂) in the ropes or cables wrapped around the pulley, the radius (r) of the pulley, and the acceleration (a) of the system.

In this expression, the moment of inertia (I) is calculated as half of the sum of tensions (t₁ + t₂) multiplied by the square of the pulley radius (r²), divided by the acceleration (a). This is based on the assumption that the pulley is rotating about its central axis, and the tensions in the ropes are causing the pulley to accelerate.

The factor of 1/2 arises from the geometry of a pulley, as it distributes tension on both sides of the pulley. Note that this expression assumes idealized conditions, such as a massless and frictionless pulley, and neglects other factors such as the mass of the pulley itself.

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Answer:

See below

Explanation:

Filling in the definitions:

acceleration

vector quantity

deceleration

time

slope

zero

positive

Answer:

getting shocked

Explanation:

i didnt really get the answer really much but i hope this helps

Answer:

Hair standing up

Explanation:

When there is a lot of static electricity, your hair stands up.

Answer: Thunderstorm.

Explanation: When a cold, dry air mass collides with a warm, humid air mass over the land, that's a tornado, but on top of that the air rises and it cools and condenses that's a thunderstorm

When a cold, dry air mass collides with a warm, humid air mass over the land, that's a tornado, but on top of that the air rises and it cools and condenses that's a thunderstorm.

A thunderstorm, sometimes referred to as an electrical storm or a lightning storm, is a type of storm that is distinguished by the presence of lightning and the thunder that results from the lightning's acoustic effect on the Earth's atmosphere.  

Thundershowers are the name for relatively weak thunderstorms. A cumulonimbus is a form of cloud where thunderstorms develop.  They frequently produce heavy rain.  and occasionally snow, sleet, or hail and they are typically accompanied by strong wind.

However, some thunderstorms result in little or no precipitation. A squall line, often known as a succession of thunderstorms, can form or become a rainband.

Therefore, When a cold, dry air mass collides with a warm, humid air mass over the land, that's a tornado, but on top of that the air rises and it cools and condenses that's a thunderstorm.

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The spring constant is 2 N/m. The result is obtained by using the Hooke's Law formula.

The Hooke's Law states that the restoring force of a spring equals the spring constant times the change in length. It can be expressed as

F = -kΔx

Where

Note: the minus sign indicates that F is in the opposite direction to the displacement of a free end.

Given the length of a spring is 10 m. When it is stretched by a force of 16 N, the length is increased to 18 m. What is the spring constant?

From that information, we get the change in length.

Δx = 18 m - 10 m

Δx = 8 m

The spring constant is

F = -kΔx

16 = -k . 8

k = - (16/8)

k = 2 N/m

Hence, the spring constant is 2 N/m.

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An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. Power is the measure of how fast work can be done. The unit of power is watts (W), which can be defined as the amount of work done in one second.

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Based on the data provided, the distance travelled is 37.68 m.

First we calculate the angular velocity:

angle turned = 180 degrees = πradians

angular velocity =  πradians/5

angular velocity = 0.628 rad/s

Linear speed = radius * angular velocity

Linear speed = 12 * 0.628

Linear speed = 7.536 m/s

Then:

Distance travelled = 7.536 * 5

Distance travelled = 37.68 m

Therefore, the distance travelled is 37.68 m.

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Answer:

F= 1800N

Explanation:

the equation for force is F= ma

so plug in the numbers: F= (120)(15)

solve this to get F= 1800N

tip: don't forget to add the units when writing your answer :)

Answer:

x_total = 20m

Explanation:

This is an exercise in kinematics, we will look for the distance it travels during the reaction time, where there is no braking, and then the distance during the deceleration.

Distance traveled during response time

           v = x₁ / t

           x₁ = v t

let's calculate

          x₁ = 10 0.75

          x₁ = 7.5 m

Now we calculate the distance during braking, the final speed is zero (v = 0)

         v² = v₀² - 2 a x₂

         x₂ = v₀² / 2 a

let's calculate

         x₂ = 10² / (2 4)

         x₂ = 12.5m

the total stopping distance is

        x_total = x₁ + x₂

        X_total = 7.5 + 12.5

        x_total = 20m

The statement "Electromagnetic waves in free space has frequency 7.24 × 10¹⁴ Hz" is true.

Electric and magnetic fields oscillate while traveling over space to form an electromagnetic wave. The number of oscillations or cycles that take place within a certain period of time is represented by an electromagnetic wave's frequency. In this instance, a frequency of 7.24 × 10¹⁴ Hz indicates that the wave cycles 7.24 × 10¹⁴ times in a second.

Electromagnetic waves can move freely in empty space without interference from other objects or media. Because of this characteristic of free space, electromagnetic waves can move at the same speed as light or about 3 × 10⁸ meters per second.

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Answer:

gas vibrates and moves freely at high speeds.

Explanation:

Hope this helps

Answer:

1) 51 m

2) Some energy was transformed to other forms. (This question)

3) 3.24 J

4) 45 J

5) 1020 J

Explanation:

100%

Answer:

Explanation:

Rubbing objects together generates static charges. There will be two type of charges: positive and negative. So the answer is (a) 2.

Answer:

2

Explanation:

When you rub two objects one gets positively charged and other gets negatively charged

So

there are two charges

a. The final pressure is 1.39 atm.

b. The final temperature is 80.4 °C.

The final pressure can be calculated using the adiabatic expansion equation:

P₂/P₁ = (V₁/V₂)^(γ)

where P₁, V₁, and P₂, V₂ are the initial and final pressures and volumes, respectively, and γ is the adiabatic index, which is 1.4 for diatomic gases like O2.

Substituting the given values, we get:

P₂/2.5 atm = (1/2)^(1.4)

P₂ = 1.39 atm

Therefore, the final pressure is 1.39 atm.

The final temperature can be calculated using the adiabatic expansion equation:

T₂/T₁ = (V₁/V₂)^(γ-1)

Substituting the given values, we get:

T₂/443.15 K = (1/2)^(0.4)

T₂ = 353.4 K

Therefore, the final temperature is 80.4 °C.

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The pressure on the tyres of the automobile of weight 2.6 x104 N with a contact area of 0.026 m2 for each tyre is 250 KPa and the pressure on each tire is 62.5 KPa.

P = F / A

P = Pressure

F = Force

A = Area

F = W = 2.6 * \(10^{4}\) N

Area of one tyre = 0.026 m²

Total area, A = 0.026 * 4

A = 0.104 m²

P = ( 2.6 * \(10^{4}\) ) / 0.104

P = 25 * \(10^{4}\) Pa

P = 250 KPa

Total pressure of the tyres = 25 * \(10^{4}\) Pa

Assuming the pressure is same on all four tyres,

Pressure on each tyre = ( 25 * \(10^{4}\) ) / 4

Pressure on each tyre = 6.25 * \(10^{4}\) Pa

Pressure on each tyre = 62.5 KPa

Therefore,

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