How many total atoms are in the formula 2H2SO4

answer:

as per the formula of given carbohydrate the answer is 15 moles

explanation:

Answer:

1) There are Four Elements

Li , H , P , O

2) Li have 3 atoms.

3) H have 3 atoms.

4) P have 3 atoms.

5) O have 3 atoms.

If the flask has a volume of 0.28 L ,  the minimum mass of PH₃BCl₃ that must be added to the flask to achieve equilibrium is 1.81 g.

The reaction is as follows :

           PH₃BCl₃(s) ⇄ PH₃(g)  +  BCl₃(g)

initial                       0          0

change    -x             +x      +x

eq.                            +x       +x

The equilibrium constant, Kc for the equation is 1.87 × 10⁻³

Kc = [PH₃] [BCl₃]

1.87 × 10⁻³ = x²

x = 4.32 × 10⁻² mol/L

If we have a flask of 0.28 L, then :

Moles =  4.32 × 10⁻² × 0.28

            = 1.20  × 10⁻²  mol of PH₃ and   BCl₃

The mass of PH₃BCl₃ = moles × molar mass

The mass of PH₃BCl₃  = 1.20  × 10⁻²  mol × 151.13 g/mol

The mass of PH₃BCl₃   = 181.35 × 10⁻² g

                                      = 1.81 g

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Answer:

=> The formulas are written above .

Explanation:

hope it's helpful

Answer:

vanadium

Explanation:

The minimum number of polarizing filters required to achieve a configuration such that the detector only detects 6% of the initial photons would be two.

Polarizing filters are used to transmit light waves that are polarized in a specific direction and block light waves that are polarized in a perpendicular direction. When two polarizing filters are placed in series, the intensity of the light that passes through both filters is proportional to the product of the transmissions of each filter.

Let's assume that the transmission of each polarizing filter is represented by T. If we want the detector to only detect 6% of the initial photons, we can write the equation as follows:

0.06 = T₁ × T₂

Since T represents the transmission of each polarizing filter, it must be a value between 0 and 1. To minimize the number of polarizing filters required, we want T₁ and T₂ to be as close to 1 as possible. So, we can choose T₁ and T₂ to be equal to 0.2:

0.06 = 0.2 × 0.2

Therefore, the minimum number of polarizing filters required to achieve a configuration such that the detector only detects 6% of the initial photons is two.

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--The given question is incomplete, the complete question is

"Using only polarizing filters (the second element under the polarization section) create a configuration such that the detector only detects 6% of the initial photons. what is the minimum number of polarizing filters required to achieve this?"--

Answer:

Hi! Think of it like this:

You and your family are going to go on a vaction for the holidays, to south america or somewhere else. You´re near the equator so it will be warm. If you were to move there, you might pull out the swimsiutes because most of the time, its useally warm and sunny. They dont really get cold weather. They will have a nice and warm christmas.

Answer:

k-39

Explanation:

also pls mark brainliest <3 :)))

Answer- k-39

Explanation:

it is the closest to the actual amu

In the box on a periodic table  we can find its atomic number, symbol, average atomic mass, and (sometimes) name of the element.

By the 20th century, it was clear that atomic numbers, not atomic masses, were involved in the periodic relationship. The periodic law, a more recent formulation of this relationship, states that an element's properties are a periodic function of its atomic number.

The elements are arranged in a modern periodic table in increasing order of their atomic numbers, and atoms with comparable properties are grouped in the same vertical column (Figure below). With its atomic number, symbol, average atomic mass, and (sometimes) name, each box represents an element. The elements are grouped in 18 vertical columns called groups and seven horizontal rows known as periods or series.

Each column's header lists the names of its groups. Roman numerals and capital letters have traditionally been used on labels in the United States. The IUPAC advises using the digits 1 through 18, and these labels are more widely used. Parts of two of the rows, totaling 14 columns, are typically written below the table's main body in order for it to fit on a single page.

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Answer: A.  The compound CuCl is 500 times less soluble in sea water than it is in pure water.

pure water.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in a equilibrium reaction, the equilibrium will shift in a direction so as to minimize the effect.

Thus when a common ion is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing.

\(CuCl\rightleftharpoons Cu^++Cl^-\)

\(NaCl\rightarrow Na^++Cl^-\)

When common ion such as \(Cl^-\) from NaCl in sea water is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing i.e. in the left side and thus solubility of CuCl further decreases.

Different rock and mineral ,soil profile

Answer:

I think its b be ause it looks like a better answer and it has some detail to it

a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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There are 6 hydrogen (H) atoms in total on both sides of the above equation, 3H2+N2 -> 2NH3.

Using 3H2+N2, we get 2NH3.

There are two nitrogen (N) atoms and three hydrogen (H) atoms on the reactant side and two N atoms and six hydrogen atoms on the product side. Because there are an equal number of hydrogen atoms on each sides, the equation is balanced. Hydrogen has a coefficient of 3, while nitrogen has none, making it a 1. Nitrogen to hydrogen consequently has a 3 to 1 ratio.

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When it comes to embalming, the primary objective is to preserve the body by inhibiting the growth of bacteria and other microorganisms. Aldehydes are effective embalming chemicals because they are good fixatives.

When it comes to embalming, the primary objective is to preserve the body by inhibiting the growth of bacteria and other microorganisms. Aldehydes, such as formaldehyde, are commonly used in embalming fluids due to their excellent fixative properties.

Fixation is the process of cross-linking and stabilizing the proteins in the tissues, preventing their degradation and decomposition. Aldehydes have the ability to react with amino acids and proteins, forming strong chemical bonds that help preserve the cellular structure. This cross-linking process immobilizes the proteins, making them resistant to enzymatic degradation and microbial activity.

Formaldehyde, in particular, is highly effective as an embalming chemical because it can penetrate tissues rapidly, react with proteins, and form stable bonds. This helps to maintain the structural integrity of the body and slow down the decomposition process. Additionally, aldehydes also have antimicrobial properties, further aiding in the preservation of the body by inhibiting the growth of bacteria and other microorganisms.

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Answer:

It must be large

Random

Explanation:

For a sample to represent a population accurately, it must be large and contain random sample spaces.

A population is a group of organism of the same species living in a particular place where they can reproduce.

Answer:

Nucleas is a cell organelle

The option that is a type of cell organelle would be D.Nucleus

A nucleus is a membrane-bound organelle that contains the cell's DNA. It is the control center of the cell, and it is responsible for storing genetic information and directing the cell's activities.

The other options are not cell organelles. Membrane is a  phospholipid bilayer that surrounds the cell and separates the cell's interior from the environment. Cytoplasm is the jelly-like substance that fills the cell and contains the cell's organelles. DNA is the genetic material of the cell, but it is not an organelle.

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Step 1

The reaction must be completed and balanced as follows:

C3H8 + 5 O2 => 3 CO2 + 4 H2O

-------------

Step 2

Information provided:

20.0 g of C3H8

10.0 g of O2

----

Information needed:

1 mole of C3H8 = 44.1 g

1 mole of O2 = 32.0 g

(use your periodic table please)

-------------

Step 3

By stoichiometry,

C3H8 + 5 O2 => 3 CO2 + 4 H2O

44.1 g C3H8 ---------- 5 x 32.0 g O2

20.0 g C3H8 ---------- X

X = 20.0 g C3H8 x 5 x 32.0 g O2/44.1 g C3H8

X = 72.6 g O2

For 20.0 g of C3H8, 72.6 g of O2 is needed, but there is only 10.0 g of O2.

Therefore,

Answer:

The limiting reactant = O2

The excess = C3H8

Answer:

the escape velocity

Explanation:

To do this, your rock has to go very fast – more than 11 kilometers per second. This velocity is called the escape velocity, the speed an object must achieve in order to overcome the gravitational attraction of a celestial body (be it a planet, a star, or a galaxy) and escape into space

found it online, lol better then nothing

Answer:

?

Explanation:

Answer:

20%

Explanation:

a) The purpose of the experiment was likely to investigate the reaction between the heated copper and air within the combustion tube.

b) The volume of air decreased due to a chemical reaction taking place between the copper and the oxygen in the air. This reaction consumed some of the oxygen, resulting in a reduction in volume.

c) The observations in the combustion tube during the experiment would depend on the specific reaction that took place. Generally, one would expect to observe changes in color, temperature, and possibly the formation of new compounds or substances. Without further information, it is difficult to provide specific details.

d) The equation for the reaction that took place would depend on the specific reaction between the copper and oxygen. However, a general equation for the reaction between copper and oxygen can be represented as:

2Cu + O2 -> 2CuO

This equation represents the formation of copper(II) oxide (CuO) when copper (Cu) reacts with oxygen (O2).

e) To calculate the percentage of gas used during the experiment, we can use the initial and final volumes of air passed through the combustion tube.

Initial volume = 80 cm³

Final volume = 64 cm³

The difference in volume represents the gas used during the experiment:

Gas used = Initial volume - Final volume

= 80 cm³ - 64 cm³

= 16 cm³

To calculate the percentage of gas used, we need to find the ratio of gas used to the initial volume, and then multiply by 100:

Percentage of gas used = (Gas used / Initial volume) * 100

= (16 cm³ / 80 cm³) * 100

= 20%

Therefore, the percentage of gas used during the experiment is 20%.

The underlined carbon in the molecule c−−h3ccch2cooh is a sp3 hybridized carbon, which means that it has four hybrid orbitals. Therefore, we can predict that the ideal values for the bond angles about the underlined carbon atom would be approximately 109.5 degrees.

The provided molecule (C−H3CCH2COOH), the underlined carbon atom appears to be the second carbon in the sequence (the one bonded to three hydrogen atoms). This carbon is sp3 hybridized, meaning it forms four sigma bonds, in this case, three bonds with hydrogen atoms and one bond with another carbon atom. In an ideal sp3 hybridized carbon atom, the bond angles should be approximately 109.5 degrees. This is due to the tetrahedral arrangement of the four sigma bonds around the carbon atom, which results in the most stable, least repulsive configuration between the electron pairs.
So, the ideal values for the bond angles about the underlined carbon atom would be approximately 109.5 degrees.

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The molecules produced by translation including molecules that are subject to further modification after initial synthesis are-  RNA polymerase and Aminoacyl-tRNA synthetase.

The process of translation converts the information carried by messenger RNA from DNA into a string of amino acids joined by peptide bonds. Translation from one code (nucleotide sequence) to another code is essentially what it is (amino acid sequence). This activity takes place on the ribosome, just as mRNA synthesis took place on the RNA polymerase.

The ribosome pairs tRNA molecules with the three complimentary bases in their anticodon regions with sets of three bases from the mRNA (called codons). The base-pairing rule is crucial in this recognition once more (A binds to U and C binds to G). In order to add the amino acids to the polypeptide chain, the ribosome matches three base pairs at a time as it advances along the mRNA. The polypeptide and mRNA are released by the ribosome when it reaches one of the "stop" codes. When this polypeptide twists into its natural shape, it starts to function as a protein in the metabolism of the cell.

Hence, The molecules produced by translation including molecules that are subject to further modification after initial synthesis are- RNA polymerase and Aminoacyl-tRNA synthetase.

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Answer:

See the answer below

Explanation:

In chemistry, indicators are substances that are capable of changing colors with respect to the pH. Each indicator has its characteristic color in acidic pH and another characteristic color in alkaline pH.

Methyl orange indicator appears red in acidic solution and yellow in basic solutions. Phenolphthalein is usually colorless in acidic solutions and appears pink in basic solutions. A red litmus paper will turn blue in alkaline solutions while a blue litmus paper will turn red in acidic solutions.

Answer:

The final temperature will be "12.37°".

Explanation:

The given values are:

mass,

m = 0.125 kg

Initial temperature,

c = 22.0°C

Time,

Δt = 4.5 min

As we know,

⇒  \(q=mc \Delta t\)

On putting the estimated values, we get

⇒     \(=0.125\times 22.0\times 4.5\)

⇒     \(=12.37^{\circ}\)

Answer:

Explanation:F

The final equilibrium temperature when 0.645 kg of molten silver is added to 0.8 kg of water at 20°C is approximately 39°C.

Let us apply the principle of conservation of energy: Heat gained by the cold body is equal to the heat lost by the hot body. Let’s take the following details into consideration: Heat lost by molten silver = Heat gained by water. Heat lost by molten silver: Q1 = mass × specific heat capacity × change in temperature Q1 = 0.645 kg × 235 J/kg°C × (962°C – T).

Heat gained by water: Q2 = mass × specific heat capacity × change in temperatureQ2 = 0.8 kg × 4,186 J/kg°C × (T – 20°C)At equilibrium, Q1 = Q2. Therefore, we can write:0.645 × 235 × (962 – T) = 0.8 × 4186 × (T – 20)151522.25 – 235T = 3348T – 66960Solving for T, we get: T = 39°C. Therefore, the final equilibrium temperature when 0.645 kg of molten silver is added to 0.8 kg of water at 20°C is approximately 39°C.

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Answer: here, for those of you who can't see it upright

Explanation:

Each element have its own electronic configuration.The first given configuration is with 4 electrons represents beryllium (Be) and the second one with 9 electrons is Fluorine (F) and the last one with 11 electrons is sodium (Na).

An orbital is a circular path with fixed energy through which electrons in an atom revolving around the nucleus. Electrons are filled in these orbitals based on the energy levels.

Lowest energy orbitals are filled first and the higher energy orbitals are filled last. Each orbital has a specific capacity to accommodate electrons. S orbital fill only two electrons, p orbital fill 6 electrons d orbital 10 electrons and f orbital fills 14 electrons.

The first electronic configuration have a total 4 electrons thus the element with atomic number 4 is Beryllium (Be) and the second configuration have 9 electrons thus it is Fluorine (F).

The last configuration represented as slashes have a total of 11 electrons. The element with 11 electrons is sodium (Na).

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