how many places are within an ohio county with more than 50,000 persons and also within 0.25 miles of a major road?

Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

velocity of the bullet, v₀ = 250 m/s

mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

5 + 0 = v(2.02)

5 = 2.02v

v = 5/2.02

v = 2.48 m/s

Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

Part A: the x and y components of the total force exerted on the charge of 5.00 nC by the other two charges are: 1.00 N

The x and y components of the total force exerted on the charge of 5.00 nC by the other two charges can be calculated using Coulomb's Law as follows:

Fx = F1x + F2xFy = F1y + F2ywhere F1x and F1y are the components of the force exerted on the charge of 5.00 nC by the charge of -2.70 nC, and F2x and F2y are the components of the force exerted on the charge of 5.00 nC by the charge of 2.25 nC.

We can find these forces as follows:F1 = (k * q1 * q3) / r1²F2 = (k * q2 * q3) / r2²

where:k = 8.99 × 10^9 N·m²/C² is Co ulomb's constantq1 = -2.70 nC = -2.70 × 10^-9 C is the charge at the originq2 = 2.25 nC = 2.25 × 10^-9 C is the charge on the y-axisq3 = 5.00 nC = 5.00 × 10^-9 C is the charge at the point (3.25 cm, 3.75 cm)r1 = √(x1² + y1²) = √(0² + 3.75²) = 3.75 cm is the distance from the origin to (0, 3.75 cm)r2 = √(x2² + y2²) = √(3.25² + 0² + 3.75²) = 5.06 cm is the distance from (3.25 cm, 3.75 cm) to the origin.

Using Coulomb's Law, we can find the forces as follows:F1x = (k * q1 * q3 * x1) / r1³F1y = (k * q1 * q3 * y1) / r1³F2x = (k * q2 * q3 * x2) / r2³F2y = (k * q2 * q3 * y2) / r2³

Substituting the given values, we get:F1x = (-8.99 × 10^9 N·m²/C²) * (-2.70 × 10^-9 C) * (3.25 cm - 0 cm) / (3.75 cm)³ = 0.833 N F1y = (-8.99 × 10^9 N·m²/C²) * (-2.70 × 10^-9 C) * (3.75 cm - 0 cm) / (3.75 cm)³ = 1.000 N F2x = (8.99 × 10^9 N·m²/C²) * (2.25 × 10^-9 C) * (3.25 cm - 0 cm) / (5.06 cm)³ = 0.307 N F2y = (8.99 × 10^9 N·m²/C²) * (2.25 × 10^-9 C) * (3.75 cm - 3.75 cm) / (5.06 cm)³ = 0 N.

Therefore, the x and y components of the total Force Exerted on the charge of 5.00 nC by the other two charges are:Fx = F1x + F2x = 0.833 N + 0.307 N = 1.14 N (to two decimal places)Fy = F1y + F2y = 1.000 N + 0 N = 1.00 N (to two decimal places)

Part B: the magnitude of this force is 1.50 N.

The magnitude of this force can be found using the Pythagorean theorem as follows:F = √(Fx² + Fy²) = √((1.14 N)² + (1.00 N)²) = 1.50 N (to two decimal places)

Therefore, the magnitude of this force is 1.50 N.

Part C: the direction of this force is 41.2° clockwise from the +x axis.

The direction of this force can be found using the inverse tangent function as follows:θ = tan⁻¹(Fy / Fx) = tan⁻¹(1.00 N / 1.14 N) = 41.2° (to one decimal place)Therefore, the direction of this force is 41.2° clockwise from the +x axis.  

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Answer:

I am pretty sure that it is one

Answer:

Explanation: is 1

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Explanation:

Answer:

4.44m/s

Explanation:

Average speed is the total distance covered within a given period of time.

From the quantities given;

Number of laps  = 4 laps

Length of each lap  = 400m

Time taken to complete race  = 6minutes

Unknown:

Average speed  = ?

Solution:

 Her average speed is given as:

      Average speed  = \(\frac{number of laps x length of lap}{time}\)

We need to convert time to seconds;

         60s  = 1 min;

        6 minute = 60 x 6  = 360s

  Average speed  = \(\frac{4 x 400}{360}\)   = 4.44m/s

Explanation:

since oil needs more boiling time and a higher boiling temperature the oil would have to be in the pot longer than the water if it needs to be boiled longer that is why the blue line for oil temp. is significantly higher than that of the water temp.

Answer:

an apple that fell down from a tree

Explanation:

he wondered what force was acting as the apple fell , he later termed it as a downward force acting on the earth called gravity.

A roller coaster accelerates at 8.75 m/s² from rest to a final velocity of 70 m/s it takes 8 sec to speed up.

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Answer:

Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that is perceived by the human eye. Visible light is usually defined as having wavelengths in the range of 400–700 nanometres, between the infrared and the ultraviolet.

Here are the 7 from shortest to longest wavelength.

Violet - shortest wavelength, around 400-420 nanometers with highest frequency.  

Indigo - 420 - 440 nm.

Blue - 440 - 490 nm.

Green - 490 - 570 nm.

Yellow - 570 - 585 nm.

Orange - 585 - 620 nm.

Red - longest wavelength, at around 620 - 780 nanometers with lowest frequency.

Explanation:

Answer:

The Answer To This Question Is B

Explanation: Please Mark Brainliest!

(a) The camel should walk 25.45 km

(b) The camel should walk -159.9 degrees relative to the positive x-axis in the range of (-180,180).

To solve this problem, use the Pythagorean Theorem and the Law of Sines.

Pythagorean Theorem: The square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

a² + b² = c²

Law of Sines: The ratio of the length of a side of a triangle to the sine of the opposite angle is equal for all sides and angles of the triangle.

a/sin A = b/sin B = c/sin C

To solve this problem, use these equations to calculate the distance the camel should walk (a) and the angle relative to the positive x-axis (b).

Start by calculating the hypotenuse of the triangle (c) using the Pythagorean Theorem:

8² + 32² = c²

64 + 1024 = 1088

c = 33

Next, calculate the angle (B) using the Law of Sines:

20/sin 15 = 33/sin B

sin B = 20/33

B = 8.4

Now, calculate the distance (a) using the Law of Sines:

20/sin 15 = a/sin 8.4

a = 27.06

Finally, calculate the angle relative to the positive x-axis (b) using the inverse of the Law of Sines:

b = sin-1 (27.06/33)

b = -159.9

Therefore, the camel should walk 25.45 km and -159.9 degrees relative to the positive x-axis in the range of (-180,180).

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Answer:

Therefore letter C is the correct answer.

Explanation:

In a projectile motion the total time in the air can be calculated using the following equation:

We analyze the y-component motion.

\(v_{fy}=v_{iy}-gt\)

When the final velocity (v(f)) is equal to zero we calculate the upward time and multiplying it by 2 we find the total time in the air. So we will have:

\(t_{tot}=2\frac{v_{iy}}{g}\)

\(t_{tot}=2\frac{v_{i}sin(\theta)}{g}\)

We can see that the total time is directly proportional to the angle, then when θ increase t increase.

Therefore letter C is the correct answer.

I hope it helps you!  

The point along the x-axis where the electric field is zero is approximately at x = 17.833 cm.

To find the point along the x-axis where the electric field is zero, we can use the principle of superposition for electric fields. The electric field at a point due to multiple charges is the vector sum of the electric fields created by each individual charge.

In this case, we have two point charges: +3.3 µC at x = 0 cm and -7.6 µC at x = 40 cm.

Let's assume the point where the electric field is zero is at x = d cm. The electric field at this point due to the +3.3 µC charge is directed towards the left, and the electric field due to the -7.6 µC charge is directed towards the right.

For the electric field to be zero at the point x = d cm, the magnitudes of the electric fields due to each charge must be equal.

Using the formula for the electric field of a point charge:

E = k × (Q / r²)

where E is the electric field, k is the Coulomb's constant, Q is the charge, and r is the distance.

For the +3.3 µC charge, the distance is d cm, and for the -7.6 µC charge, the distance is (40 - d) cm.

Setting the magnitudes of the electric fields equal, we have:

k × (3.3 µC / d²) = k × (7.6 µC / (40 - d)²)

Simplifying and solving for d, we get:

3.3 / d² = 7.6 / (40 - d)²

Cross-multiplying:

3.3 × (40 - d)² = 7.6 × d²

Expanding and rearranging terms:

132 - 66d + d² = 7.6 × d²

6.6 × d² + 66d - 132 = 0

Solving this quadratic equation, we find two possible solutions for d: d ≈ -0.464 cm and d ≈ 17.833 cm.

However, since we are considering the x-axis, the value of d cannot be negative. Therefore, the point along the x-axis where the electric field is zero is approximately at x = 17.833 cm.

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answer:

Explanation:

the impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it. The impulse-momentum theorem is logically equivalent to Newton's second law of motion (the force law).

According to the impulse-momentum theorem, the amount of change in an object's momentum equal to the amount of force applied to the object over a certain amount of time. So, option B.

According to the impulse-momentum theorem, the impulse that is applied to an item is equal to the change in momentum.

It shows how an object's change in momentum depends on both the strength and duration of the applied forces.

Impulse is defined as the force acting for a short interval of time.

Impulse = F x t

The momentum of the object,

P = mv

So, the rate of change of momentum,

dP/dt = d(mv)/dt

dP/dt = mdv/t

dP/dt = ma = Force

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NASA estimates that a white dwarf's surface has 350,000 times as much gravity as Earth has.

If the mass is too enormous (more than 1.4 solar masses, known as the Chandrasekhar limit), a white dwarf star will no longer be in equilibrium between gravity and degeneracy pressure.

Sirius B is smaller than Earth at 7,500 miles (12,000 kilometers) in diameter, but it is more denser. A 150-pound individual would weigh 50 million pounds standing on its surface due to the star's strong gravitational field, which is 350,000 times stronger than Earth's.

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Answer: hair

Explanation: Since a persons hair can be tracked back to their DNA this was often used because most of the criminals were female and all female have extremely long hair. Hair is also easy to find at a crime scene because the k9 dogs can easily smell it.

Answer:

The answer to this question would be fingerprints.

Explanation:

In the late 1800's Chinese organized a fingerprinting system and started using it to track down criminals

Answer:

99 meters

Explanation:

Apply the distance formula:

\( \displaystyle{s = ut + \dfrac{1}{2} g{t}^{2} }\)

where u is initial velocity which is 0 m/s since there is no initial velocity by dropping an object.

t is time which we know is 4.5 seconds. Finally, g is a constant of acceleration due to gravity which on Earth equals to 9.8 m/s². Therefore:

\( \displaystyle{s = 0 \cdot 4.5 + \dfrac{1}{2}(9.8) {(4.5)}^{2} } \\ \\ \displaystyle{s = \dfrac{1}{2}(9.8) {(4.5)}^{2} } \\ \\ \displaystyle{s \approx 99 \: \text{m}}\)

Therefore, the bridge is around 99 meters height.

Explanation:

thx bro......... ...........

Answer:

Friedrich Miescher was the scientist who first discovered DNA.

Answer:

b

Explanation:

Answer:

I dont know

Explanation:

Answer:

I think B but im not sure

Explanation:

Answer: i think both mirrors are used to reflect the beam of light.

Explanation:

gr 10 science right? im almost done the semester and i learnt this already so i think the best answer is the last one

The altitude of the synchronous satellite is \(3.59*10^7\) meters which always remains above the same point on Earth’s equator.

The altitude of a synchronous satellite, which remains above the same point on Earth's equator, can be determined using the formula for the orbital period of a satellite and the rotational period of the Earth. Since the satellite is in a circular orbit, its orbital period will be equal to the rotational period of the Earth, which is 24 hours.
The formula for the orbital period of a satellite is \(T=2\pi \sqrt{(a^3/GM)}\), where T is the orbital period, a is the semi-major axis of the orbit, G is the gravitational constant, and M is the mass of the Earth.
Since we know the orbital period is 24 hours, we can rearrange the formula to solve for a, which represents the altitude of the satellite.
\(a=\sqrt[3]{[(GMT^2)/4\pi ^2]} =\sqrt[3]{[(6.67*10^{-11} * 5.97*10^{24} * (24*60*60)^2)/4\pi ^2]} = 3.59*10^7\) m

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The work done by the applied force on block b ( wb ) positive, negative, or zero is wb is positive both works are positive.

For calculation of work, angle between force and displacement vector is of importance.

a)

Here, F = Fi

s = si

W= F.S= (Fî). (sî )·

= FS >0

b) Here, F= -Fi

s=-si

w= F.s=(-Fi).(-si)

W= FS >0

Work done is a measure of the energy transferred when a force is applied over a distance. In physics, work is defined as the product of the force and the displacement of an object in the direction of the force.

Work done is an important concept in physics and is used to describe a wide range of phenomena, from the work done by the heart to pump blood to the work done by a machine to lift a heavy object. Work done can be positive, negative or zero. When the force and displacement vectors are in opposite directions, the work done is negative. When the force and displacement vectors are perpendicular to each other, the work done is zero.

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Complete Question: -

Two identical blocks are pushed across a smooth floor. is the work done by the applied force on block a ( wa ) positive, negative, or zero? is the work done by the applied force on block b ( wb ) positive, negative, or zero?

a. wa is positive,

b. wb is negative wa is negative,

c. wb is positive both works are positive.

d. both works are negative.

Answer:

Explanation: F = m * a F = 20 kg * 3 m/s 2 F = 60 N Newtons are a derived unit, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second

The time constant of the circuit can be determined from the formula τ = RC. The values given in the question are R = 4.00 MΩ and C = 3.00 µF. Thus, the time constant is given as:τ = RC = (4.00 × 10^6 Ω) × (3.00 × 10^-6 F) = 12 secondsb. The current in the circuit can be found by using Ohm’s law, which states that I = V/R, where V is the voltage across the circuit.

The voltage across the circuit is 12.0 V, so the current is given as:I = V/R = (12.0 V)/(4.00 MΩ) = 3.00 µAThe charge on the capacitor as a function of time can be found using the formula Q = Qmax (1 - e^(-t/τ)), where Qmax is the maximum charge that can be stored by the capacitor. The maximum charge can be found using the formula Qmax = CV, where V is the voltage across the capacitor.

The voltage across the capacitor is the same as the voltage across the circuit, which is 12.0 V. Thus, the maximum charge that can be stored by the capacitor is:Qmax = CV = (3.00 × 10^-6 F) × (12.0 V) = 36 µCThe charge on the capacitor as a function of time is given as:Q = Qmax (1 - e^(-t/τ)) = (36 µC) (1 - e^(-t/12)).

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The variables that can be plotted to create a straight line with a slope approximately equal to the acceleration of the ball are h as a function of t^2 and v as a function of t.

The acceleration of the ball can be obtained by analyzing the slope of the velocity-time graph. Since the acceleration is constant in this scenario, a straight line on the graph will indicate a constant acceleration.

To determine the variables that produce a straight line with a slope approximately equal to the acceleration, we need to consider the relationships between different kinematic quantities.

The equation for the vertical displacement of the ball can be expressed as h = h0 + v0t + (1/2)at^2, where h is the height, h0 is the initial height, v0 is the initial velocity, t is time, and a is acceleration. If we plot h as a function of t^2, the resulting graph will be a straight line with a slope equal to (1/2)a, which represents the acceleration.

Additionally, the velocity of the ball can be related to the displacement and time using the equation v = v0 + at. If we plot v as a function of t, we will obtain a straight line with a slope equal to the acceleration.

Therefore, h as a function of t^2 and v as a function of t are the variables that can be plotted to create a straight line with a slope approximately equal to the acceleration of the ball.

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The speed of a train that moves from a train station at 30 meters per second after 5 seconds and covers a distance of 100 m with an acceleration of ten meters per second square would be 80 m/s.

We can use the equation of motion to solve for the final velocity of the train:

v = u + at

where:

Substituting the values, we get:

v = 30 + 10(5)

v = 80 m/s

Therefore, the speed of the train after 5 seconds is 80 m/s.

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Answer: 1700

Explanation: