how many o atoms are in ammonium acetate? how many o atoms are in ammonium acetate? 5 2 1 3 none of the above

A. Ammonia is the limiting reactant.

B. Theoretical yield of urea is 215.3 kg.

C. Percent yield for the reaction is 86.0%

D. The mass of the excess carbon dioxide left is approximately 54.1 kg.

a) To identify the limiting reactant, we should compare the amount of products formed from each reactant. The chemical equation for the formation of urea \((NH_2CONH_2)\) by combining ammonia \((NH_3)\) and carbon dioxide \((CO_2)\) is as follows:

\(2 NH_3 + CO_2 - > NH_2CONH_2 + H_2O\)

The stoichiometry of the balanced equation indicates that the ratio of ammonia to urea is 2:1.

We can find the number of moles for each reactant using the following masses:

Moles of ammonia = 122.0 kg / 17.03 g/mol = 7.17 mol

Moles of carbon dioxide = 211.4 kg / 44.01 g/mol = 4.80 mol

It takes 14.34 moles of ammonia to react completely with the available carbon dioxide because the ratio of ammonia to urea is 2:1. But the amount of ammonia we have is less than we need - only 7.17 mol. As a result, ammonia is the limiting reactant.

b. Based on the limiting reactant, it is possible to calculate the theoretical yield of urea. We can use the moles of ammonia, which is the limiting reactant, to calculate the moles of urea:

Moles of urea = 7.17 mol / 2 = 3.58 mol

We can determine the theoretical yield of urea using the molar mass of urea (60.06 g/mol) as a starting point:

Theoretical yield of urea = 3.58 mol * 60.06 g/mol = 215.3 kg

C. The actual yield (185.1 kg) is calculated by dividing it by the theoretical yield (215.3 kg), then multiplying the result by 100%.

Percent yield = (185.1 kg / 215.3 kg) * 100% = 86.0%

D. We can calculate the amount of non-limiting reactant that has not reacted yet to determine the excess reactant. Since ammonia is the limiting reactant, we must determine how much excess carbon dioxide there is:

Moles of excess carbon dioxide = Moles of carbon dioxide initially - Moles of carbon dioxide used

= 4.80 mol - (7.17 mol / 2) = 1.23 mol

We can determine the mass of excess carbon dioxide using the molar mass of carbon dioxide (44.01 g/mol):

Excess carbon dioxide = 1.23 mol * 44.01 g/mol = 54.1 kg

Therefore, the mass of the excess carbon dioxide left is approximately 54.1 kg.

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Answer:

14.007 amu

Explanation:

N-15 has 15 amu, while N-14 has 14 amu.

So average isotope mass = 15(0.7%) + 14(99.3%)

= 15(0.007) + 14(0.993)

= 0.105 + 13.902

= 14.007 amu

Answer:

5N would be the net force if i'm correct 5N and 5N cancle each other out then all your left with would be 5N

Explanation:

BTW whats your

name-

age-

and fav color just tring to meet new people

Answer:

The correct answer is option D

Explanation:

The enzyme enolase is categorized as a metalloenzyme that carries out the catalytic reaction of 2-phosphoglycerate to phosphoenolpyruvate conversion. Several kinetic and spectroscopic methods have been applied to study the role of the divalent metal ions Mg+2 (magnesium ions) involved in the reaction. Both the ions have been shown to coordinate with the carboxylic group of the substrate and product. The coordination provides stability to the intermediate steps in the general base catalysis of enolase (proton abstraction by a base), thereby providing maximum activity to the dimeric molecule.

The enzyme is a molecule that acts as a catalyst while the ions are supposed to facilitate the action of the enzyme. So, option a and b are incorrect. In the reaction, the proton abstraction takes place by a base, not an acid and so, option C is incorrect. The transition state and the intermediate steps are stabilized which facilitates the base catalysis and so, option E is incorrect.

Answer: To facilitate  general base catalysis. Thus option D is correct.

Explanation:

Enolase enzyme is classified as a metalloenzyme that performs the catalytic reaction of converting 2-phosphoglycerate to phosphoenolpyruvate. Various kinetic and spectroscopic methods were used to investigate the role of the divalent Mg+2 metal ions (magnesium ions) involved in the reaction. Both ions were shown to coordinate to the carboxyl group of the substrate and the product. The coordination ensures the stability of the intermediate steps in the general base catalysis of enolase(extraction of the proton by the base) and thus the maximum activity of the dimeric molecule.

An enzyme is a molecule that acts as a catalyst, while ions are believed to facilitate the action of the enzyme .Therefore, options a and b are invalid. The reaction involves the extraction of the proton from the base, not the acid, so option C is incorrect. The transition state and intermediate phases are stabilized, facilitating base catalysis, so option E is wrong.

The primary driving force in the formation of protein tertiary structure is the hydrophobic effect.

When a protein folds into its three-dimensional structure, hydrophobic amino acid residues tend to cluster together in the interior of the protein, away from the surrounding aqueous environment. This is because the hydrophobic residues are nonpolar and have a low affinity for water. By burying these hydrophobic residues in the protein's core, the overall energy of the system is reduced, leading to increased stability. The hydrophobic effect is a result of the tendency of water molecules to form ordered structures around nonpolar molecules, which increases the system's entropy. Other forces such as electrostatic interactions, hydrogen bonding, and van der Waals interactions also contribute to the stabilization of the protein's tertiary structure, but the hydrophobic effect is often the major driving force.

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Answer: 5

Explanation:

The pH of the solution is approximately 4.75.This indicates that the solution is slightly acidic.

To calculate the pH of the solution, we need to determine the concentration of acetate ions and acetic acid. First, let's find the number of moles of sodium acetate:

Mass of sodium acetate = 5.60 g

Molar mass of sodium acetate (CH3COONa) = 82.03 g/mol

Number of moles of sodium acetate = 5.60 g / 82.03 g/mol = 0.068 mol

Next, we need to find the number of moles of acetic acid:

Volume of acetic acid = 15.0 mL = 0.015 L

Concentration of acetic acid = 18.5 M

Number of moles of acetic acid = 18.5 mol/L * 0.015 L = 0.278 mol

Now, we can calculate the total volume of the solution:

Total volume = 1.50 L

The total moles of acetate ions can be calculated by summing the moles of sodium acetate and acetic acid:

Total moles of acetate ions = 0.068 mol + 0.278 mol = 0.346 mol

Now, we calculate the molarity (M) of the acetate ions:

Molarity of acetate ions = Total moles of acetate ions / Total volume

= 0.346 mol / 1.50 L = 0.231 M

Since sodium acetate is a strong electrolyte, it will dissociate completely in water, providing an equal concentration of acetate ions (0.231 M). The concentration of acetic acid is 0.278 M (determined earlier).

The Henderson-Hasselbalch equation can be used to calculate the pH of the solution:

pH = pKa + log([Acetate]/[Acetic Acid])

The pKa of acetic acid is 4.76.

pH = 4.76 + log(0.231/0.278)

≈ 4.75

The pH of the solution is approximately 4.75. This indicates that the solution is slightly acidic. The calculation involved determining the concentrations of acetate ions and acetic acid in the solution and using the Henderson-Hasselbalch equation to calculate the pH.

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Answer:

A dipole exists when there are areas of asymmetrical positive and negative charges in a molecule. Dipole moments increase with ionic bond character and decrease with covalent bond character.

If l = 3, 14 electrons can be contained in all the possible orbitals.

When l = 3, it represents the f orbital. The f orbital has a total of 7 suborbital (or orbitals) labeled as 3f, each with a different orientation. According to the Pauli exclusion principle, each orbital can accommodate a maximum of 2 electrons with opposite spins.

Therefore, when l = 3, the total number of electrons that can be contained in all the possible orbitals is:

7 orbitals x 2 electrons/orbital = 14 electrons.

Hence, the correct answer is C. 14. The f orbital's complex shape and orientation allow for a larger number of electrons compared to s, p, and d orbitals, which have 1, 3, and 5 orbitals respectively.

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Concentration in molarity of an aqueous solution which contains 5.06% by mass ethylene glycol IS 0.847 mol/L

Molarity [=] mol / L

wt% = (g C₂H₆O₂ / g s)×100

⇒ 0.0506 = g C₂H₆O₂ / g s

∴ mm C2H6O2 = 62.07 g/mol

∴ δ s = 1.04 g/mL

assuming: g s = 1 g

⇒ g C₂H₆O₂ = 0.0506 g

⇒mol C₂H₆O₂ = (0.0506 g)(mol/62.07 g) = 8.154 E-4 mol C₂H₆O₂

⇒ V s = 1g s / 1.04 g/mL = 0.9615 mL = 9.615 E-4 L s

⇒ C₂H₆O₂ = (8.154 E-4 )/(9.615 E-4 L s)

⇒  C₂H₆O₂= 0.847 mol/L

In terms of the amount of material per unit volume of solution, molar concentration is a measurement of the concentration of a chemical species, specifically a solute in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units.

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Answer:

Computer.

Explanation:

The computer is moving more than the floor, at least, it's moving when people are typing on it.

Answer:

When atoms have fewer than eight electrons, they have an inclination to react and type a lot of stable compounds.

Thus, associate atom continues to create bonds till associate octet of electrons is formed. this can be called octet rule by Lewis.

Answer: Radio Waves

Explanation:

electromagnet transmit Radio waves

Answer:

3. Triple Beam Balance

Explanation:

A triple beam will be most suitable for measuring the mass of a small stone because it is very accurate, and has a reading error of +/- 0.05 gram.

The density of H2SO4 is 1.119 g/mL, and the molal concentration is 1.94 m.

We can use the following formula to find the molar concentration of the solution:      

    Molality (m) = Moles of solute / Mass of solvent in kg                  

                 = (mass of solute in grams) / (molar mass of solute × mass of solvent in kg)

the molar mass of H2SO4 as follows:

Molar mass of H2SO4 = 2(1.00794 g/mol of H) + 32.066 g/mol of S + 4(15.9994 g/mol of O)                      

            = 98.079 g/mol

Now, we can find the mass of solvent in kg as follows:

    Let's take 1000 g of the solution, and we know that the density of the solution is 1.119 g/mL.

So, 1000 g of solution contains 1000/1.119 = 893.04 mL of the solution, which is equal to 0.89304 L of the solution.

So, mass of solvent in 0.89304 L of the solution = (0.89304 L × 1.119 g/mL) - (mass of solute in 0.89304 L of the solution)                            

          = 1.0 kg (approx)

Now, we can find the number of moles of H2SO4 in 1 kg of the solvent as follows:

     Number of moles of H2SO4 = molality × mass of solvent in kg                      

                        = 1.94 × 1 kg of solvent                      

                        = 1.94 mol

Hence, the molar concentration of the solution is equal to the number of moles of solute per liter of the solution.

Molar concentration of H2SO4 solution = (Number of moles of solute) / (Volume of the solution in liters)                                                                                      

      = 1.94 mol / 0.89304 L                                            

      = 2.18 M

Therefore, the molar concentration of this solution is 2.18 M (Approx).Thus, the detailed answer to this question has been provided.

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The man-made greenhouse gas that has been shown to be decreasing in emissions since the early 2000s is CFCS (chlorofluorocarbons).

CFCS (chlorofluorocarbons) are a type of man-made greenhouse gas that were widely used in various industries, including refrigeration, aerosol propellants, and foam manufacturing. However, due to their harmful effects on the ozone layer, their production and use have been significantly reduced through international agreements such as the Montreal Protocol.

While most greenhouse gases, such as carbon dioxide and methane, continue to exhibit an exponential growth pattern in emissions, CFCS are an exception. The successful implementation of global regulations and efforts to phase out CFCS has led to a decline in their emissions since the early 2000s.

This reduction in CFCS emissions is a positive environmental outcome as these gases contribute to ozone depletion and have a significant global warming potential. The decrease in CFCS emissions showcases the effectiveness of international agreements and the commitment to mitigating their impact on the environment.

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The chance of having children with blood group AB for a couple with the husband of heterozygous A (AO) and the wife of heterozygous B (BO) is 25%. The correct option is A.

The antigens of the ABO blood group are encoded by a single genetic locus, the ABO locus, which has three alternative (allelic) forms A, B, and O.

A child inherits one of the three alleles from each parent, resulting in six genotypes and four blood types.

Blood groups are inherited. They follow a Mendelian pattern, which means they are the result of a single gene.

There are three types of alleles in the ABO gene: A, B, and O. The first two, A and B, are codominant, which means they are equally dominant.

As per the attached Punnett Square, the genotype can be AB, AO, BO, and OO. So, the chance of having children with blood group AB as per the given scenario, will be 25%.

Thus, the correct option is A.

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Answer:

d.the gases x and y are elements ​

Explanation:

Since it is impossible to further break down the gases produced during this electrolytic process, we can conclude that the gases x and y are elements.

An element is a distinct substance that cannot be split up into simpler substances. Such substances are made up of only one kind of atom.

It is impossible through chemical reactions split an element into simpler units.

According to the research, the correct option is C. A scatterplot identifies the problem and its variables showing quantitative data that relate two variables.

It is a control and support tool that shows a geometric design that presents the existing links and the level of correlation between variables and how one variable influences another.

In this sense, given that it is a tool or graphic representation it is widely used in statistics, that helps to identify the possible association between two related sets of data, it seeks to correlate said variables in order to better control the process and improve it.

Therefore, we can conclude that according to the research, the correct option is C. A scatterplot identifies the problem and its variables showing quantitative data that relate two variables.

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\(Al_2O_3\) is most likely to leave some holes vacant when it forms a lattice structure.

When ionic compounds form a lattice structure, some of the lattice sites or positions may remain vacant, especially when the ions of different sizes are involved. This is referred to as a "defective" or "non-stoichiometric" structure, which may affect the physical and chemical properties of the compound.

Among the given options, \(Al_2O_3\)is most likely to leave some holes vacant when it forms a lattice structure. This is because aluminum and oxygen ions have significantly different sizes, and it is difficult to arrange them in a perfect crystalline structure without some vacancies.

In contrast, \(Na_2O\)and \(Na_2S\) have similar-sized ions, and they are expected to form a regular lattice structure without significant defects. Similarly, MnS is expected to form a regular lattice structure since Mn and S ions are relatively similar in size.

However, it is important to note that the formation of defects in a lattice structure is a complex process that depends on several factors such as the size and charge of the ions, the temperature, and the pressure. Therefore, the actual structure of a compound can be more complex than the idealized structures predicted by theoretical models.

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. B) excoriation. An abrasion of the skin by scratching, trauma, or chemicals is termed as Excoriation.  Excoriation refers to a superficial injury to the skin caused by mechanical trauma.

such as scratching, rubbing, or scraping. This can occur due to a variety of reasons, including skin conditions such as eczema or psoriasis, insect bites, or contact with chemicals or other irritants. An abrasion of the skin by scratching, trauma, or chemicals is termed as Excoriation. Therefore, option B is the correct answer. Excoriation refers to a superficial injury to the skin caused by mechanical trauma. Excoriations can range from mild to severe and may be accompanied by pain, itching, or bleeding. Treatment depends on the underlying cause and may include topical medications, dressings, or other interventions to promote healing and prevent infection.

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Answer:

various

Explanation:

A pure substance cannot be separated into 2 or more substances by physical means such as crystallization or distillation nor by mechanical means such as sifting, filtering, or using a magnet. ... Water (H2O) (4) is a pure substance because it can NOT be separated into simpler substances by physical or mechanical means

Answer:

If the temperature of the system is increased, then the equilibrium position would shift to the right side. According to Le Chatelier's principle, when a stress is applied to a system in equilibrium, the system will adjust itself to counteract the stress. In this case, increasing the temperature would be an external stress on the system, and the reaction would shift to consume more of the reactants, namely CH4 and H2S, to create more of the products, CS2 and H2, thus shifting the equilibrium position towards the products.

Explanation:

Explanation:

cooked rice

nutrient

carbohydrate.

Boiler eggs

nutrient

Protein.

Protons, neutrons, and electrons are the principal subatomic particles that comprise an atom.

Three subatomic particles exist: protons, neutrons, and electrons. Protons have a positive charge, while electrons have a negative charge, making up two of the subatomic particles.

They are frequently called subatomic particles because they are the building blocks of atoms. Three subatomic particles exist: protons, neutrons, and electrons. Protons have a positive charge, while electrons have a negative charge, making up two of the subatomic particles.

The heavier constituents of the atom's small, but incredibly dense nucleus, the positively charged protons and the electrically neutral neutrons, are subatomic particles, as are the negatively charged, almost massless electrons that make up the majority of the atom's size.

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At the equivalence point of the titration between a 100 mL solution of 0.25 M NH3(aq) and 0.15 M HCl, the pH of the solution is approximately 7. This is due to the formation of a neutral salt, NH4Cl, which does not exhibit significant acidic or basic properties.

During the titration, the HCl reacts with NH3 to form NH4+ and Cl- ions. At the equivalence point, the moles of NH3 and HCl are stoichiometrically balanced. Since NH4Cl is a salt formed from the reaction of a weak base (NH3) with a strong acid (HCl), the resulting solution is neutral.

At 25°C, the Kb value of NH3 is 1.8 × \(10^{-5}\). NH3 is a weak base, and it undergoes partial ionization in water, resulting in the formation of OH- ions. However, at the equivalence point, the OH- ions produced by NH3 are neutralized by the H+ ions from HCl, leading to a pH of 7, which is considered neutral.

In summary, at the equivalence point of the titration between 0.25 M NH3(aq) and 0.15 M HCl, the pH of the solution is approximately 7. This occurs because the reaction between NH3 and HCl forms a neutral salt, NH4Cl, resulting in a neutral pH at 25°C.

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The subatomic particle that plays the greatest part in determining the properties of an element is the electron (B).

The properties of an element are primarily determined by its atomic structure. Elements are characterized by the number of protons, neutrons, and electrons they possess.

Protons and neutrons are located in the nucleus of an atom, while electrons orbit around the nucleus in energy levels or shells.

The electron configuration of an atom, specifically the arrangement and distribution of electrons in the outermost shell, is what primarily influences the chemical and physical properties of an element. The behavior of atoms in chemical reactions, bonding patterns, and electrical conductivity are all related to the movement and interactions of electrons.

Although protons and neutrons contribute to factors such as atomic mass and stability, the electron's involvement in chemical reactions and interactions is most significant in determining an element's properties.

Therefore, the subatomic particle that plays the greatest part in determining the properties of an element is the electron (B).

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Answer:

540.47g approximately

Explanation:

No. of moles in Na₂CO₃ = 5.4 moles

Mole ratio of Na₂CO₃ : CaCO₃ = 1:1

No. of moles in CaCO₃ = 5.4 moles

Mass of CaCO₃ = 5.4 × 100.0869

= 540.46926g

Answer  b

Explanation:

Answer: B. Isotopes of the same element have the same number of neutrons and a different number of protons.

Explanation: Founders Educere answer.

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