How many moles of sodium bicarbonate are needed to neutralize 0. 8 ml of sulphuric acid at stp.

The mass of the gold nugget is 71.217 g.

Mass can be defined as the ratio of force to the gravitational acceleration of a body.

To calculate the mass of the nugget gold, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The mass of the gold nugget is 71.217 g

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Based on the information provided, we can conclude that the Cr2O72- ion has a visible absorption spectrum with a peak around 500 nm.

This means that when light with a wavelength close to 500 nm passes through a solution containing the Cr2O72- ion, the ion will absorb some of the light, resulting in a decrease in the intensity of the light passing through the solution at that wavelength.

This property can be used to identify the presence of the Cr2O72- ion in a solution and to determine its concentration using spectrophotometry.

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Answer:

The absorption of light by the Cr2O72- ion at a wavelength of 500 nm indicates that the ion has a visible absorption spectrum.

Explanation:

The absorption spectrum of a molecule or ion can provide information about its electronic structure and chemical properties, which can be useful in many areas of chemistry and physics.

This absorption corresponds to a transition between energy levels in the ion, which may involve the promotion of an electron to a higher energy level..

In addition, the absorption of light by the Cr2O72- ion at this wavelength may be used in analytical techniques such as spectrophotometry to quantitatively determine the concentration of the ion in a sample.

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Explanation: When an atom gains/loses an electron, the atom becomes charged, and is called an ion. Gaining an electron results in a negative charge, so the atom is an anion.

The third law of thermodynamics describes the entropy of a: solid.

The third law of thermodynamics states that the entropy of a pure crystalline substance approaches zero as the temperature approaches absolute zero (0 Kelvin or -273.15 degrees Celsius). This law implies that at absolute zero, a perfectly ordered and pure crystalline solid will have zero entropy.

The third law of thermodynamics is not specific to liquids or gases but applies to solids. In a solid, the molecules are highly ordered and have fixed positions in a regular lattice structure. As the temperature decreases towards absolute zero, the thermal motion of the molecules reduces, and the system becomes more ordered, resulting in a decrease in entropy.

In contrast, liquids and gases have higher entropy compared to solids at absolute zero because their molecules have more freedom of movement and are not as tightly arranged. Therefore, the third law of thermodynamics specifically addresses the entropy of solids and does not apply to liquids or gases.

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Explanation:

I. Because an explosion is a very fast exothermic reaction

ll. it depends on the it's particle size

11,835.76 = 11.83576kg

683,763.88mg = 6.8376388hg

53.7m = 0.0537km

:) hoped this helped

brainlyest maybe?

Wine was produced 37 years ago (1984 as usual year 15,2021) that is shown in the calculations below.

Reaction rate is calculated using the formula rate = Δ[C]/Δt, where Δ[C] is the change in product concentration during time period Δt. The rate of reaction can be observed by watching the disappearance of a reactant or the appearance of a product over time.

The time can be represented as follows:

t= 2.303\∧ log A0/A

∧= 0.693/t 1/2

The rate of a reaction is proportional to the reciprocal of the time taken. Rate α 1 time Rate is inversely proportional to time. Units: s-1, min-1 etc.

The given parameters are as follows:

t1/2=12.3

A0=5.5

A=0.688

t= 2.303/(0.693/12.3) log (5.5/0.688)

t=36.9

t=37 years

Thus, wine was produced 37 years ago (1984 as usual year 15,2021)

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Answer:

I'm sorry, but I don't see an equation in your question to provide a specific answer. However, I can answer your general question.

Nitrogen has one more proton than Carbon because it has one more positively charged particle (proton) in its nucleus. This difference in the number of protons determines the atomic number and identity of the element.

Protons can only come from the nucleus of another atom, through a nuclear reaction. In nature, nitrogen is usually created by nuclear fusion in stars, where lighter elements combine under high pressure and temperature to form heavier elements.

Regarding the second part of your question, without the specific equation you are referring to, I cannot determine the type of reaction depicted. There are many types of chemical reactions, including synthesis, decomposition, combustion, acid-base, and redox reactions, among others.

Answer:

asdd

Explanation:

adsade4223

Answer:

Approx. 20 moles of iron.

Explanation:

There are approx. 6.022 x 10.23 iron atoms per mole of iron. In this quantity, The number of iron atoms has a mass of

55.85 ⋅ g.

The element selenium (Se) with atomic number 34 possesses four p electrons.

Explanation:

In the periodic table, the p-block elements are located in groups 13 to 18, and they have valence electrons in the p orbital. The p orbital can hold a maximum of six electrons, distributed among three suborbital (px, py, and pz) with a maximum of two electrons in each.

Selenium is located in Group 16, also known as Group 6A, which means it has six valence electrons. To determine the number of p electrons, we subtract the number of core electrons (filled energy levels) from the total number of valence electrons. In the case of selenium, the core electron configuration is [Ar] 3d10 4s2 4p4, indicating that it has 28 core electrons.

Subtracting this from the total valence electrons (6), we find that selenium has four p electrons.

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The mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.

To determine the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide, we need to balance the chemical equation and perform stoichiometric calculations.

The balanced chemical equation for the reaction between aluminum and iron (III) oxide can be written as follows:

2 Al + Fe₂O₃ → 2 Fe + Al₂O₃

From the balanced equation, we can see that 2 moles of aluminum react with 1 mole of iron (III) oxide to produce 2 moles of iron and 1 mole of aluminum oxide.

Convert the given masses of aluminum and iron (III) oxide into moles.

Using the molar mass of aluminum (26.98 g/mol) and iron (III) oxide (159.69 g/mol), we can calculate the number of moles for each substance.

Number of moles of aluminum = mass of aluminum / molar mass of aluminum

= 11.0 g / 26.98 g/mol

= 0.408 moles

Number of moles of iron (III) oxide = mass of iron (III) oxide / molar mass of iron (III) oxide

= 30.0 g / 159.69 g/mol

= 0.188 moles

Determine the limiting reactant.

To determine the limiting reactant, we compare the stoichiometric ratio of aluminum to iron (III) oxide. From the balanced equation, we see that 2 moles of aluminum react with 1 mole of iron (III) oxide.

Given that we have 0.408 moles of aluminum and 0.188 moles of iron (III) oxide, we can calculate the moles of iron that can be produced from each reactant.

Moles of iron from aluminum = 2 * 0.408 moles = 0.816 moles

Moles of iron from iron (III) oxide = 0.188 moles

Since the moles of iron from aluminum (0.816 moles) is greater than the moles of iron from iron (III) oxide (0.188 moles), we can conclude that iron (III) oxide is the limiting reactant.

Calculate the mass of iron produced.

To calculate the mass of iron produced, we use the molar mass of iron (55.85 g/mol) and the number of moles of iron from the limiting reactant.

Mass of iron = moles of iron from iron (III) oxide * molar mass of iron

= 0.188 moles * 55.85 g/mol

= 10.48 g

Therefore, the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.

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Answer:

This strand contains nucleotides that are complementary to those in the template sequence. Base pairing ensures that the sequence of nucleotides in the existing template strand is exactly matched to a complementary sequence in the new strand, also known as the anti-sequence of the template strand

We need to find the mass of 1.6x10^20 molecules of carbon monoxide

First, we must find the number of mol in the 1.6x10^20 molecules

For this, we need to use the avogadro's number ( 6.02*10^23 )

Then, we must calculate the molar mass of carbon monoxide

M(CO) = 12 g/mol + 16 g/mol = 28 g/mol

Finally, we must multiply the number of mol by the molar mass to find the mass

ANSWER:

0.007

The first one appear to be a pan with some liquid heating up.

The beginning state is liquid, the phase change type is a vaporization and its ending state is gas.

The second one seems to be a ice cube melting.

Its beginning phase is solid, the phase change type is fusion, and its ending state is liquid.

The third one is water, or other liquid, making clouds.

The beginning state is liquid, the phase change type is a vaporization and its ending state is gas.

The fourth illustration seems to be an aluminium can. There aren't really a phase change happening, but when we open the aluminium can containing gaseous drink, there are molecules of gas diluted into the liquid and some of it encouter each other to make a bubble of the gas and is released. It is not an actually phase change, it is the reverse process of diluting gas into liquid. Initially it is diluted gas, it gets released and in the end it is in gas phase.

The heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol. To calculate the heat of reaction (ΔH) for the given reaction:

CCl₄(g) + H₂O(g) -> CHCl₃(g) + HCl(g)

You would need the standard enthalpies of formation for each compound involved in the reaction. The standard enthalpy of formation (ΔHf) is the enthalpy change when one mole of a compound is formed from its elements in their standard states.

Here are the standard enthalpies of formation for the compounds involved:

ΔHf[CCl₄(g)] = -135.5 kJ/mol

ΔHf[H₂O(g)] = -241.8 kJ/mol

ΔHf[CHCl₃(g)] = -104.7 kJ/mol

ΔHf[HCl(g)] = -92.3 kJ/mol

To calculate ΔH for the reaction, you need to sum up the enthalpies of formation of the products and subtract the sum of the enthalpies of formation of the reactants:

ΔH = ΣΔHf(products) - ΣΔHf(reactants)

ΔH = [ΔHf[CHCl₃(g)] + ΔHf[HCl(g)]] - [ΔHf[CCl₄(g)] + ΔHf[H₂O(g)]]

ΔH = [(-104.7 kJ/mol) + (-92.3 kJ/mol)] - [(-135.5 kJ/mol) + (-241.8 kJ/mol)]

ΔH = -196.9 kJ/mol - (-377.3 kJ/mol)

ΔH = 180.4 kJ/mol

Therefore, the heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol.

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Answer:

A) 24g soluto y 376g solvente.

B) 16.8g soluto y 39.2g solvente

C) 45g soluto y 405g solvente

D) 10g soluto y 190g solvente

E) 90mL soluto y 360mL solvente

F) 245mL soluto y 735mL solvente

G) 15mL soluto y 35mL solvente

Explanation:

El porcentaje masa/masa (% m/m) se define como la masa de soluto presente en 100g de solución (Soluto + solvente).

De la misma manera, el porcentaje volumen/volumen se define como el volumen de soluto en 100mL de solución:

A) 400 gramos de disolución al 6 % m/m.

400g solución * (6g soluto / 100g solución) = 24g soluto

400g solución - 24g soluto = 376g solvente

b) 56 gramos de disolución al 30 % m/m.

56 gramos de disolución al 30% m/m.

56g solución * (30g soluto / 100g solución) = 16.8g soluto

56g solución - 16.8g soluto = 39.2g solvente

c) 450 gramos de disolución al 10 % m/m

450 gramos de disolución al 10% m/m.

450g solución * (10g soluto / 100g solución) = 45g soluto

450g solución - 45g soluto = 405g solvente

d) 200 gramos de disolución al 5 % m/m

200 gramos de disolución al 5% m/m.

200g solución * (5g soluto / 100g solución) = 10g soluto

200g solución - 10g soluto = 190g solvente

e) 450 mL de disolución al 20 % v/v

450 mL de disolución al 20% m/m.

450 mL * (20mL soluto / 100mL solución) = 90mL soluto

450mL solución - 90mL soluto = 360mL solvente

f) 980 mL de disolución al 25 % v/v

980 mL de disolución al 25% m/m.

980 mL * (25mL soluto / 100mL solución) = 245mL soluto

980mL solución - 245mL soluto = 735mL solvente

g) 50 mL de disolución al 30 % v/v

50 mL de disolución al 30% m/m.

50 mL * (30mL soluto / 100mL solución) = 15mL soluto

50mL solución - 15mL soluto = 35mL solvente

With 35.0 mL of a 0.1 M HCl solution neutralizing 25.0 mL of the NaOH solution, we find that the moles of NaOH are equal to the moles of HCl. Using this information, we calculate the molarity of NaOH to be 0.14 M.

To determine the concentration of the NaOH solution, we can use the concept of stoichiometry and the volume and concentration of the HCl solution used in the neutralization reaction. The balanced chemical equation for the reaction between HCl and NaOH is:

HCl + NaOH → NaCl + \(H_{2} O\)

From the equation, we can see that the mole ratio between HCl and NaOH is 1:1. This means that the number of moles of HCl used in the reaction is equal to the number of moles of NaOH present in the solution.

Given that it takes 35.0 mL of a 0.1 M HCl solution to neutralize 25.0 mL of the NaOH solution, we can use the equation:

Moles of HCl = Molarity of HCl × Volume of HCl solution

Moles of NaOH = Moles of HCl

Molarity of NaOH = Moles of NaOH / Volume of NaOH solution

Substituting the given values:

Moles of HCl = 0.1 M × 35.0 mL = 3.5 mmol

Moles of NaOH = 3.5 mmol

Volume of NaOH solution = 25.0 mL = 0.025 L

Molarity of NaOH = (3.5 mmol) / (0.025 L) = 140.0 mmol/L = 0.14 M

Therefore, the concentration of the NaOH solution is 0.14 M.

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The number of observations for carbon dioxide production in response to adding glucose to the fermentation medium is 8.

In the given context, it is stated that there were 9 wells in the experiment where different amounts of glucose were added to the fermentation medium. It is also mentioned that the initial well with only distilled water was used as a control, implying that it did not contain glucose. Therefore, the number of observations for carbon dioxide production in response to adding glucose would be one less than the total number of wells.

As per the provided procedure, there were a total of 9 wells, so the number of observations would be 8. Each well represents a different condition or amount of glucose, and the carbon dioxide production would be measured or observed for each well. These observations would be used to analyze the effects of glucose concentration on carbon dioxide production in the fermentation medium.

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Answer:

Explanation:

It is not possible to determine if the two substances obtained from different sources that melt at 148-150 degrees celsius are the same based on just their melting point alone. Melting point is a physical property that is widely used as an indicator of chemical purity and identity, however, it is not a definitive test. Two different compounds can have the same melting point.

Melting point is affected by many factors, such as pressure and impurities, which can cause variations in the melting point of a substance. Additionally, polymorphs (different forms of the same substance) can have different melting points.

In order to determine if the two substances are the same, additional tests such as spectroscopy, chromatography, and chemical analysis would be needed to confirm their chemical identity.

Two substances are not always the same only because they melt at the same temperature (148–150°C). A physical attribute of a material that can be utilised as a distinguishing factor is melting point.

It does not follow that two substances that melt at the same temperature (148–150°C) are the same. The physical feature of melting point can be used to identify a material, but it is not the sole factor in determining chemical identification. To compare two substances, it is necessary to take into consideration additional characteristics including chemical composition, solubility, density, and interactions with other compounds. Additionally, compounds with identical melting points can be found in several chemical families and may have various chemical and physical characteristics. In order to validate the chemical identity of two compounds received from various sources, further investigation, such as infrared spectroscopy, X-ray diffraction, or chromatography, may be required.

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When two moles of silver are allowed to react with an unlimited amount of chlorine, 2 moles of silver chloride (AgCl) is produced.

When a chemical reaction takes place, it is important to know the amount of products that will be formed from the reactants used. In order to do this, we need to know the balanced chemical equation for the reaction and the number of moles of reactants used.The balanced chemical equation for the reaction between silver and chlorine gas is given by:

2Ag + Cl2 → 2AgCl

Here, we can see that 2 moles of silver react with 1 mole of chlorine gas to produce 2 moles of silver chloride.Since an unlimited amount of chlorine is allowed to react with 2 moles of silver, the number of moles of silver chloride produced will be equal to the number of moles of silver reacted. Hence, 2 moles of silver chloride will be produced.Therefore, we can say that if 2 moles of silver is allowed to react with an unlimited amount of chlorine, 2 moles of silver chloride will be produced. This is because the balanced chemical equation shows that 2 moles of silver react with 1 mole of chlorine gas to produce 2 moles of silver chloride.

When a chemical reaction takes place, it is important to know the amount of products that will be formed from the reactants used. In this case, we have determined that if 2 moles of silver is allowed to react with an unlimited amount of chlorine, 2 moles of silver chloride will be produced. This is because the balanced chemical equation shows that 2 moles of silver react with 1 mole of chlorine gas to produce 2 moles of silver chloride.

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Answer:

The symbol for an atom can be written to show its mass number at the top, and its atomic number at the bottom. To calculate the numbers of subatomic particles in an atom, use its atomic number and mass number: number of protons = atomic number. number of electrons = atomic number.

Answer:

This molecule is made up of 3 equally spaced sp2 hybrid orbitals arranged at approximately 120o angles. The shape of the orbitals is planar triangular. One orbital contains a lone pair of electrons.

Answer:

Pacific Ring of Fire.

Explanation:

Japan sits in one of the most active earthquake zones on the planet: the Pacific Ring of Fire.

Hope this helps you. :)

Answer: i would say Indonesia.

Explanation:

The empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium, and the remainder oxygen is K₂Cr₂O₇.

The term an Empirical formula is defined as the chemical formula of a compound that gives the ratios of the elements present in the compound but not the actual numbers or arrangement of atoms.

The number of mole of each element in the compound can be identified by dividing each element's percentage with their respective molar weights:

Potassium K = 26.56%

= 26.56 / 39.1        

= 0.68

Chromium, Cr = 35.41%                

= 35.41/52

= 0.68

Oxygen,

O = 100 - 26.56+35.41                      

= 38.03/16

= 2.38

Divide each number of moles by the smallest.

K = 0.68/0.68  

= 1                                                            

Cr = 0.68/0.68

= 1    

O = 2.38/0.68

= 3.5      

Thus, the empirical formula would be KCrO₃.₅

Multiply all by 2 to remove the fraction:

Then the empirical formula would be K₂Cr₂O₇.

Thus, the empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium, and the remainder oxygen is K₂Cr₂O₇.

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A non-covalent interactions between  molecules are van der Waal's forces and hydrogen bonds.

Non-covalent interaction is an interaction which does not involve sharing of electrons and in this aspect it differs from covalent bond.It rather involves dispersed variations  of electromagnetic interactions  which are present between the molecules or within the molecule.

The energy released during the formation of these interactions  is of the order of 1-5 kcal .They are classified as electrostatic, pi effects , van der waals forces  and hydrophobic effects.

They are important in maintaining the three dimensional structure of large molecules such as proteins ,nucleic acids ,etc.They are also involved in biological processes . They heavily influence drug design process and design of materials.

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Question 5

Answer

D - 7.15 g O2

Explanation

Given:

Balanced chemical equation:

mass of Cr = 15.5 g

Required: mass of Oxygen

Solution:

Step 1: Find the moles of Cr

n = m/M where n is the number of moles, m is the mass and M is the molar mass

n = 15.5 g/51,9961g/mol

n = 0.298 mol

Step 2: Use stoichiometry to find the moles of O

The molar ratio between Cr and O is 4:3

Therefore the number of moles of O = 0.298 x (3/4) = 0.224 mol

Step 3: From the moles, we can find the mass of O

m = n x M

m = 0.224 x 31.998

m = 7.168 g which is closer to D = 7.15 g

Answer:

net force

Explanation:

The net force acting on an object is the combination of all of the individual forces acting on it. ... If two forces act on an object in the same direction, the net force is the sum of the two forces.