To solve this problem, we need to use the ideal gas law which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Rearranging this equation, we can solve for n by dividing both sides by RT.
n = PV/RT
Now, we can plug in the given values:
n = (4.2 atm)(128 L)/(0.0821 L*atm/mol*K)(382 K)
n = 16.4 moles
Therefore, 16.4 moles of gas occupy 128L at a pressure of 4.2 atm and a temperature of 382K.
It's important to note that the ideal gas law is only applicable to ideal gases, which follow certain assumptions such as having no intermolecular forces and having particles with negligible volume. Real gases can deviate from these assumptions, especially at high pressures and low temperatures. However, for most practical purposes, the ideal gas law provides a good approximation of gas behavior.
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A reaction between 1. 7 moles of zinc iodide and excess sodium
The percent yield of zinc carbonate is 5.91%. This suggests that the reaction did not go to completion, and there was likely some loss of product during the experiment.
To find the percent yield of zinc carbonate, we need to compare the actual yield (what was obtained in the experiment) to the theoretical yield (what would be obtained if the reaction went to completion).
First, let's calculate the theoretical yield of zinc carbonate:
From the balanced equation, we can see that 1 mole of ZnI2 reacts with 1 mole of \(Na_{2}CO_{3}\) to produce 1 mole of \(ZnCO_{3}\).Since we have 1.7 moles of ZnI2, we would need 1.7 moles of \(Na_{2}CO_{3}\) to react completely.The molar mass of \(ZnCO_{3}\) is 125.39 g/mol, so the theoretical yield of \(ZnCO_{3}\) would be:theoretical yield = 1.7 mol ZnCO3 x 125.39 g/mol = 213.07 gNow, let's calculate the percent yield:
The actual yield \(ZnCO_{3}\) is given as 12.6 g.
The percent yield is calculated as:
percent yield = (actual yield / theoretical yield) x 100%percent yield = (12.6 g / 213.07 g) x 100% = 5.91%Learn more about zinc carbonate
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Full Question: A reaction between 1.7 moles of zinc iodide and excess sodium carbonate yields 12.6 grams of zinc carbonate. This is the equation for the reaction: Na2CO3 + ZnI2 → 2NaI + ZnCO3. What is the percent yield of zinc carbonate? The percent yield of zinc carbonate is %
Question 4 "That oil sands executive is greedy and heartless and therefore can't be trusted when she claims to want to improve her company's environmental record."
O False dilemma
O Ad hominem attack
O Straw man
O Appeal to authority
Question 5 "There is no proof that humans are causing climate change so it must natural causes
O False dilemma
O Appeal to ignorance
Strawman
O Appeal to authority
That oil sands executive is greedy and heartless and therefore can't be trusted when she claims is Ad hominem attack. So, Option B is correct.
4- The argument in question 4 is an example of an ad hominem attack. This is due to the argument's focus on the character of the oil sands executuive rather than the actual problem, which is how to improve the company's environmental record.
The argument holds that the executive cannot be believed when she says she wants to improve the company's environmental record because she is avaricious and callous. This is an error in logic, though, as the executive's character may not necessarily be related to the company's environmental policies.
5- The argument in question 5 is an example of an appeal to ignorance. This is because the argument states that there is no proof that humans are causing climate change, so it must be natural causes. Just because there is no conclusive proof that humans are causing climate change, it does not mean that they are not.
The argument assumes that just because there is no evidence to the contrary, the argument must be true. This is a logical fallacy.
So, Option B is correct.
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3 L of a gas at 250 K is changed to a temperature of 300 K. What is the final volume?
Answer:
you can simply answer vl\t1=v2/t2
Which elements in the periodic table are least likely to combine with other elements?
a. halogens
b. Nobel gases
c. alkaline earth metals
d. transition metals
Answer:
nobel gases
Explanation:
nobel gases elements in the periodic table are least likely to combine with other elements
For every action, there is an equal and opposite reaction.
Does the statement describe a scientific law?
Answer:
yeah its newton's third law
Explanation:
A backdraft explosion can occur when
- There is a lack of fuel in a partially-burned room
- There is a lack of oxygen in a partially-burned room
- A door is opened into a room instead of opening into a hallway or outside
- A fire is very smoky
A backdraft explosion can occur when there is a lack of oxygen in a partially-burned room. This situation can be exacerbated if a door is opened into the room, introducing a sudden supply of oxygen, which then leads to a rapid combustion of the remaining fuel, causing the explosion. A fire being very smoky may also indicate a lack of oxygen, increasing the risk of a backdraft explosion.
A backdraft explosion can occur under certain conditions such as when there is a lack of fuel in a partially-burned room or a lack of oxygen in a partially-burned room. Additionally, if a door is opened into a room instead of opening into a hallway or outside, it can create a draft that can lead to a backdraft explosion. Furthermore, a fire that is very smoky can also lead to a backdraft explosion as the smoke can build up and ignite when oxygen is suddenly introduced. It is important to be aware of these potential dangers and to take necessary precautions to prevent a backdraft explosion from occurring.
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Suppose you pour a glass of ice water and set it on the kitchen table. After a few minutes, the outside of the glass will be covered with drops of water. Why did this happen?
For condensation to take place there should be noticeable difference between the temperature of the system and the atmosphere. Thus condensation is the reason for clinging of water particles to the side of the glass.
What is condensation?Condensation is a process in which the vapor state converts to liquid state. Condensation is the reverse process of evaporation. Condensation occur at dew point. Dew point is the temperature at which condensation starts.
When the hot air particles collides with the surface of the glass having ice water, then the hot particles that had so much energy or kinetic energy suddenly reduces its energy and converts to water due to the change in temperature and pressure .
Thus condensation is the reason for clinging of water particles to the side of the glass having ice water.
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You notice that your sample begins to boil at 96.20C and the liquid begins to drip into
the collection flask. What is happening?
an exothermic chemical reaction between a solid and a liquid results in gaseous products. spontaneous?
An exothermic chemical reaction between a solid and a liquid results in gaseous products. It is a spontaneous reaction.
What is an exothermic reaction?When a chemical reaction takes place with the release of heat, it is known as an exothermic chemical reaction. An exothermic chemical reaction is a chemical reaction that releases energy in the form of heat, light, or sound during the process. The burning of paper is an example of an exothermic chemical reaction. When paper burns, heat and light are produced, which we can feel or observe.
The reaction is spontaneous if the Gibbs free energy, delta G is negative. A reaction will be spontaneous if its delta G is negative. The reaction will proceed from left to right if delta G is negative, and it will proceed from right to left if delta G is positive. A reaction will be at equilibrium if delta G is zero.The reaction mentioned in the question is an exothermic chemical reaction because it results in the release of heat. As a result, the reaction is spontaneous. The production of gaseous products indicates that a gas is formed during the reaction. Therefore, this reaction is spontaneous.
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Name the following aromatic hydrocarbon:
CH,CH;
CH,CH3
A. 1,4-dimethylbenzene
B. 1,4-dihexylbenzene
C. 2,6-diethylbenzene
D. 1,4-diethylbenzene
Answer:
A. 1,4-dimethylbenzene
Explanation:
The compound CH,CH;CH,CH3 is a benzene derivative with two methyl groups attached to the benzene ring. The positions of the methyl groups on the ring are indicated by the numbers 1 and 4, which correspond to the carbon atoms at the end of the two double bonds in the benzene ring. This compound is therefore 1,4-dimethylbenzene. The other options listed are not correct because they contain the wrong number or type of substituents on the benzene ring.
Salt is both strong and brittle. These properties relate to its atomic bonds. Examine a toothpick and try to bend it. Then imagine hitting the end of an upright toothpick with a hammer. Is a toothpick a good model for showing the strength and brittleness of salt? Explain your answer.
Answer:
Yes, A toothpick can be a good model for showing the strength and brittleness of salt as It will break and splinter just like salt.
What are the properties of salt ?
Salts are ionic in nature due to the presence of ions.
They are brittle, hard and crystalline solids.
Salt is white, odorless and it has a salty taste.
Toothpick will break and splinter just like salt, exclamation, because it breaks easy and if we use a hammer on a tooth pick its gonna break and splinter just like salt.
Therefore , A toothpick can be a good model for showing the strength and brittleness of salt as It will break and splinter just like salt.
Explanation: hope this helps
What will the subscript for NH4 be?
Answer:
2
Explanation:
The subscript on Ammoniumwhich is (NH4) is 2.
Hope this helped!
Part A
Predict the sign of the entropy change, ΔS∘, for each of the reaction displayed.
Drag the appropriate items to their respective bins.
Help
Reset
Ag+(aq)+Cl−(aq)→AgCl(s)
2KClO3(s)→2KCl(s)+3O2(g)
2N2O(g)→2N2(g)+O2(g)
2Mg(s)+O2(g)→2MgO(s)
C7H16(g)+11O2(g)→7CO2(g)+8H2O(g)
H2O(l)→H2O(g)
Positive
Negative
SubmitHintsMy AnswersGive UpReview Part
Part B
Calculate the standard entropy change for the reaction
2Mg(s)+O2(g)→2MgO(s)
using the data from the following table:
Substance ΔH∘f (kJ/mol) ΔG∘f (kJ/mol) S∘ [J/(K⋅mol)]
Mg(s) 0.00 0.00 32.70
O2(g) 0.00 0.00 205.0
MgO(s) -602.0 -569.6 27.00
Express your answer to four significant figures and include the appropriate units.
ΔS∘ =
The standard entropy change for the reaction \(2Mg(s)+O_2(g)\rightarrow 2MgO(s)\) is -405.6 J/(K⋅mol).
What is entropy ?Entropy is a measure of the randomness or disorder in a system. It is a thermodynamic property that can be used to measure the amount of energy that is unavailable for work in a thermodynamic process. Entropy is closely related to the second law of thermodynamics and can be used to assess the direction of a thermodynamic process. Entropy is also a measure of the amount of information contained in a system. High entropy systems have more randomness and disorder, while low entropy systems have less.
The entropy change for the reaction \(2Mg(s)+O_2(g) \rightarrow 2MgO(s)\) is calculated using the following equation: \(\Delta S^\circ = \Sigma S^\circ products -\Sigma S^\circ reactants\)
Substituting the values from the table:
\(\Delta S^\circ = (2 \times 27.00 J/(Kmol)) - (32.70 J/(Kmol) + 205.0 J/(Kmol))\\\Delta S^\circ = -405.6 J/(Kmol) .\)
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Calculate the volume of gas at 175 C degrees if its volume is 132 mL at 24 C degrees at a constant pressure
Answer: volume of gas at 175°C = 18.10mL.
ExplanationsGiven :
• Temperature (T1 = 175°C
,• Volume (V1 ) = 132 mL
,• Temperature (T2) = 24 °C
,• Volume 2 = ....mL?
We will consider Charles law "volume of an ideal gas at constant pressure is directly proportional to the absolute temperature"
• Represented as :
\(\frac{V_1}{T_1}=\text{ }\frac{V_2}{T_2}\)Replacing the given parameters into chales law equation , we get that V2 =
\(\begin{gathered} V_2=\frac{V_1*T_2}{T_1} \\ \text{ = }\frac{132mL\text{ * 24 }\degree C}{175\degree C} \\ \text{ =18.10 mL} \end{gathered}\)This means that the volume of gas at 175 = 18.10mL.
which of the following solutions contains molecules that absorb the highest energy light? note that the colors listed are the colors that are observed for the solutions, not the colors that are absorbed.
The solutions that contains molecules that absorb the highest energy light is purple colour solution.
What determines the amount of light energy a color absorbs?The amount of light energy a colour absorbs determines the amount of heat energy that light can be converted into. For example, the color violet contains more energy than red. That means violet absorbs more light, making it a warmer color than red.
dark colors absorb more light energy, they absorb a lot more heat than brighter hues. In fact, the closer a hue gets to dark, the more heat it absorbs from light sources. Because black clothing reflects little solar light, it also reflects less solar heat, making it hotter. The same thing happens with any color as it approaches black - the darker the hue, the more heat it will absorb.
This is why dark clothes are better for winter and bright clothes are better for summer - when you wear dark colors, you're protecting yourself from the cold in winter and the hot of the sun in summer.
And this is why people who work outside often wear colored gloves - dark colors block out heat, while bright colors block out cold.
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Based on the electron configuration of the two atoms, predict the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound.
magnesium 1s22s22p63s2
bromine 1s22s22p63s23p64s23d104p5
a. 1:1
b. 1:2
c. 2:1
d. 3:1
The ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound is 1:2.
What is electron configuration?The term electron configuration shows the arrangement of electrons in an atom. We have the configurations of the atoms as follows;
magnesium - 1s22s22p63s2
bromine - 1s22s22p63s23p64s23d104p5
We can see that the catio is Mg^2+ and the anioin is Br^- hence the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound is 1:2.
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Will Mark Brainlest ( all the disaster are hazard but all the hazard are not disaster) give reason
Answer:
Explanation to the following question is as follows;
Explanation:
Any phenomenon that would have the potential to cause severe death or property damage is considered a danger. When the potential for devastation is realised, a hazard becomes a disaster. All catastrophes are risks, but not all risks are catastrophes. Hazards do not always result in devastation.
Answer:
I hope this will help you.
which statement describes the movement of carbon dioxide in the carbon cycle?
A. The gas leaves the biosphere as animals breathe in air.
B. The gas leaves the atmosphere as plants use it to make sugar.
C. The gas enters the cryosphere as ice sheets melt.
D. The gas enters the hydrosphere as sugar dissolves in water.
Answer:
C. The gas enters the cryosphere as ice sheets
Answer:
D
Explanation:
what is the most likely ionization state of alanine at ph 11 ?
The alanine molecule has a net negative charge at pH 11, where the amine exists as a neutral base and the carboxyl serves as its conjugate base.
The amino acid alanine is necessary for the synthesis of proteins. Vitamin B-6 and tryptophan are broken down using it. It provides the central nervous system and muscles with energy. It helps the body use glucose and boosts the immune system.
The alanine chemical structure reveals that the backbone is made up of two functional groups: the carboxyl group (COOH C O O H) and the amino group (NH2 N H 2), as well as a carbon atom attached to the side chain, CH3 C H 3.
The majority of proteins contain a large amount of the glycogenic amino acid alanine. Alanine can also be produced from other amino acids, particularly branched chain amino acids (BCAA) like valine, leucine, and isoleucine.
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A sample containing 37. 4 grams of ammonia undergoes combustion with excess oxygen in a bomb (constant volume) calorimeter to form nitrogen monoxide (nitric oxide) and water gas. The heat constant for the calorimeter is 952 J/oC. The specific heat capacity for water vapor is 2. 00 J/ g. OC. The specific heat capacity for nitrogen monoxide is 0. 996 J/ g. OC. During the experiment, the temperature in the calorimeter changes from 22. 9oC to 1772. 9oC.
A. Give the balanced chemical equation that represents this reaction and calculate the number of grams for each product produced.
B. Calculate the amount of heat transferred during this reaction. Be certain to include units and the correct number of significant figures. Ignore the effects of excess oxygen in the bomb calorimeter.
C. Calculate the change in enthalpy in kJ/mol ammonia for this reaction.
D. Is the change in enthalpy equal to the change in internal energy for this reaction? Explain your answer.
E. How would the change in enthalpy for this reaction differ, if the reaction was allowed to occur in an open reaction vessel? Explain
There is a production of 59.14 grammes of water vapour and 65.85 grammes of nitrogen monoxide.
A. The balanced chemical equation for the combustion of ammonia with excess oxygen to form nitrogen monoxide and water gas is:
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g)
According to the equation, for every 4 moles of ammonia, 4 moles of nitrogen monoxide and 6 moles of water gas are produced. To calculate the number of grams of each product produced, we need to find the number of moles of ammonia in the sample:
Molar mass of NH₃ = 14.01 g/mol + 3(1.01 g/mol) = 17.04 g/mol
Number of moles of NH₃ = 37.4 g / 17.04 g/mol = 2.19 mol
Using the mole ratio from the balanced equation, we can calculate the number of moles of each product:
Number of moles of NO = 4/4 x 2.19 mol = 2.19 mol
Number of moles of H₂O = 6/4 x 2.19 mol = 3.28 mol
To find the mass of each product, we can use their molar masses:
Molar mass of NO = 30.01 g/mol
Molar mass of H₂O = 18.02 g/mol
Mass of NO produced = 2.19 mol x 30.01 g/mol = 65.85 g
Mass of H₂O produced = 3.28 mol x 18.02 g/mol = 59.14 g
Therefore, 65.85 grams of nitrogen monoxide and 59.14 grams of water gas are produced.
B. The amount of heat transferred during this reaction can be calculated using the formula:
q = CΔT
where q is the amount of heat transferred, C is the heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter.
From the problem, we are given:
C = 952 J/°C
ΔT = 1750°C - 22.9°C = 1727.1°C
Substituting the values, we get:
q = (952 J/°C) x (1727.1°C) = 1.64 x \(10^{6}\) J
Therefore, the amount of heat transferred during this reaction is 1.64 x \(10^{6}\) J.
C. The change in enthalpy for the reaction can be calculated using the equation:
ΔH = q/n
where q is the amount of heat transferred, and n is the number of moles of ammonia that reacted.
From part A, we know that 2.19 moles of ammonia reacted. Substituting the values, we get:
ΔH = (1.64 x \(10^{6}\) J) / 2.19 mol = 748,858 J/mol = 748.9 kJ/mol
Therefore, the change in enthalpy for the reaction is 748.9 kJ/mol ammonia.
D. The change in enthalpy is not equal to the change in internal energy for this reaction because the bomb calorimeter is a constant volume calorimeter, which means that no work is done during the reaction (Δw = 0). Therefore, the change in enthalpy (ΔH) equals the change in internal energy (ΔU) plus the work done (Δw) by the system:
ΔH = ΔU + Δw
Since Δw = 0 for the bomb calorimeter, ΔH = ΔU.
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the third law of thermodynamics describes the entropy of a: select the correct answer below: solid liquid gas all of the above
The third law of thermodynamics describes the entropy of a: solid.
The third law of thermodynamics states that the entropy of a pure crystalline substance approaches zero as the temperature approaches absolute zero (0 Kelvin or -273.15 degrees Celsius). This law implies that at absolute zero, a perfectly ordered and pure crystalline solid will have zero entropy.
The third law of thermodynamics is not specific to liquids or gases but applies to solids. In a solid, the molecules are highly ordered and have fixed positions in a regular lattice structure. As the temperature decreases towards absolute zero, the thermal motion of the molecules reduces, and the system becomes more ordered, resulting in a decrease in entropy.
In contrast, liquids and gases have higher entropy compared to solids at absolute zero because their molecules have more freedom of movement and are not as tightly arranged. Therefore, the third law of thermodynamics specifically addresses the entropy of solids and does not apply to liquids or gases.
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i need answers for each one of these questions, or an explanation on how to find them on a calculator
Answer:
(9.03x10^-14)x(8.455x10^20)=7.634865x10^7
(5.2x10^11)/(2.10x10^-4)=2.476190x10^15
(7.67x10^12)x(3.8x10^15)=29146000000000000000000000000
(9.237x10^20)/(4.5x10^-6)=2.0526x10^26
Explanation:
Calculate the boiling point (in degrees C) of a solution made by dissolving 7.12 g of anthracene{C14H10} in 70.9 g of benzene. The Kbp of the solvent is 2.53 K/m and the normal boiling point is 80.1 degrees C.
The boiling point of the solution is 81.527°C, which is more than the normal boiling point of benzene.
The boiling point elevation is given by the formula
ΔT = Kbp × b × iwhere,ΔT = boiling point elevation
Kbp = molal boiling point elevation constant b = molality of the solution i = van't Hoff factor
The van't Hoff factor depends on the degree of dissociation or association of the solute. Since Anthracene is a non-electrolyte, the van't Hoff factor i = 1.In order to find the molality of the solution, we use the formula,
molality = number of moles of solute / mass of solvent in kgHere,
Number of moles of Anthracene (C14H10) = 7.12 g / 178.22 g/mol = 0.03995 mol Mass of benzene = 70.9 g
Molar mass of benzene = 78.11 g/mol Molality of the solution = 0.03995 mol / 0.0709 kg = 0.5638 m
Now, the boiling point elevation is given by
ΔT = Kbp × b × i= 2.53 K/m × 0.5638 m × 1= 1.427 K
The boiling point of the solution is the sum of the boiling point elevation and the normal boiling point of the solvent.
Boiling point of the solution = normal boiling point of benzene + boiling point elevation= 80.1°C + 1.427°C= 81.527°C
The boiling point of the solution is 81.527°C, which is more than the normal boiling point of benzene.
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To energize employees and inspire excellence, an organization may set _______________ , which are reasonable yet highly ambitious.
To energize employees and inspire excellence, an organization may set stretch goals, which are reasonable yet highly ambitious.
An organization is a group of people who work together, in an organized way for a shared purpose and planning. For example political party, a business, a charity, etc. To energize the employee or group of people and inspire excellence in an organization may set stretch goals, which will be reason for highly ambitious.
It is important to set the stretch goals for organisation because they inspire teams to think big and accomplish goals they might not consider possible. It benefits to help our team maximize success.
Inspire innovation.Encourage collaboration. Boost motivation. Improve workplace goodness. Decrease in turnover. Peak team performance. Development of company culture.Hence required answer is strech goals.
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A chemist mixes 50.0mL of a 1.0M NaOH solution with 50.0mL of a 1.0M Ba(OH)2 solution. Assuming the two solutions are additive, what is the pH of the resulting solution
Answer:
\(pH=14.2\)
Explanation:
Hello there!
In this case, according to the information in this problem, and considering these two bases are strong, it is necessary for us to calculate the total moles of OH ions as shown below:
\(n_{OH^-}^{from\ NaOH}=0.050L*1.0mol/L=0.050mol\\\\n_{OH^-}^{from\ Ba(OH)_2}=0.050L*1.0mol/L*2=0.10mol\\\\n_{OH^-}^{tot}=0.15mol\)
Now, the as the solutions are additive, the total volume is then 0.100 L and the concentration:
\([OH^-]=\frac{0.15mol}{0.100L}=1.5\)
And therefore, the pH is:
\(pH=14+log(1.5)\\\\pH=14.2\)
Regards!
solve this questions please
Answer:
A
Explanation:
A solid that dissolves in water produce alkaline solutions
ex. sodium reacts with water to form sodium hydroxide – caustic soda
Examine the chemical reaction C3H8+O2 4H2O+3CO2.
What coefficient of O2 should be added so the number of atoms of oxygen is conserved on both sides of the reaction equation?
A: 3
B: 5
C: 7
D: 10
Answer:
B
Explanation:
How many liters of 2.0 M NaCl solution can be made from 0.75 moles of NaCl
A. 2.67 L
B. 0.38L
C. 1.50 L
D. 0.0015 L
You can make 0.38 liters of a 2.0 M NaCl solution using 0.75 moles of NaCl.
To determine how many liters of a 2.0 M NaCl solution can be made from 0.75 moles of NaCl, you'll need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
In this case, you are given the molarity (2.0 M) and the moles of solute (0.75 moles). To find the volume of solution (in liters), rearrange the formula as follows:
Volume of solution (in liters) = \frac{moles of solute }{ molarity}
Now, plug in the values:
Volume of solution (in liters) =\frac{ 0.75 moles }{ 2.0 M}
Volume of solution (in liters) = 0.375 L
As you can see, the answer is 0.375 L, which can be rounded to 0.38 L. Therefore, the correct option is B. 0.38 L.
In summary, you can make 0.38 liters of a 2.0 M NaCl solution using 0.75 moles of NaCl.
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issued this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your etext. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon.
The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.
Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.
Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.
According to the given data;
Decomposition of carbon monoxide (CO);
Oxygen produced = 3.36 g
Carbon produced = 2.52 g
We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;
Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol
Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol
Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;
0.21 mol C / (0.21 mol O) = x
Simplifying the equation, we have;
x = 1
Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.
Decomposition of carbon dioxide (CO₂);
Oxygen produced = 9.92 g
Carbon produced = 3.72 g
Following the same calculations as before;
Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol
Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol
Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;
0.31 mol C / (0.62 mol O) = y
Simplifying the equation, we have;
y = 0.5
Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.
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--The given question is incomplete, the complete question is
"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--
Calculate the pH of a solution that is 0.111 M in sodium formate (NaHCO2) and in formic acid (HCO2H). The Ka of formic acid is 1.77 × 10^-4.
A) 3.387
B) 4.103
C) 14.36
D) 10.61
E) 5.296
The pH of a solution that is 0.111 M in sodium formate (NaHCO2) and formic acid (HCO2H), with a Ka of formic acid of 1.77 × 10^-4, can be calculated using the following these steps:
1. Recognize that this is a buffer solution, as it contains both a weak acid (formic acid) and its conjugate base (sodium formate).
2. Use the Henderson-Hasselbalch equation for buffer solutions: pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the conjugate base (sodium formate) and [HA] is the concentration of the weak acid (formic acid).
3. Calculate the pKa: pKa = -log(Ka) = -log(1.77 × 10^-4) ≈ 3.75
4. Substitute the values into the Henderson-Hasselbalch equation: pH = 3.75 + log(0.111/0.111)
5. Simplify: pH = 3.75 + log(1) = 3.75 + 0 = 3.75
The pH of the solution is approximately 3.75, which is not one of the given options. However, considering the given options, the closest answer is A) 3.387.
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