Taking into account the reaction stoichiometry, 2.72 moles of NH₃ are formed when 65.3 grams of N₂H₄ reacts.
Reaction stoichiometryIn first place, the balanced reaction is:
3 N₂H₄ → 4 NH₃ + N₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
N₂H₄: 3 molesNH₃: 4 molesN₂: 1 moleThe molar mass of the compounds is:
N₂H₄: 32 g/moleNH₃: 17 g/moleN₂: 28 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
N₂H₄: 3 moles ×32 g/mole= 96 gramsNH₃: 4 moles ×17 g/mole= 68 gramsN₂: 1 mole ×28 g/mole= 28 gramsMass of NH₃ formedThe following rule of three can be applied: if by reaction stoichiometry 96 grams of N₂H₄ form 4 moles of NH₃, 65.3 grams of N₂H₄ form how many moles of NH₃?
moles of NH₃= (65.3 grams of N₂H₄× 4 moles of NH₃)÷ 96 grams of N₂H₄
moles of NH₃= 2.72 moles
Finally, 2.72 moles of NH₃ are formed.
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Which list places the molecules, from left to right, from most oxidized to least oxidized?A. HCOOH > CH4 > CH3OH > CO2B. CO2 > CHOOH > CH3OH > CH4C. CH2O > CO2 > CH3OH > CH4D. CO2 > CH2O > HCOOH > CH4E. CH4 > CH3OH > CHOOH > CO2
Oxidation is the process of a substance gaining oxygen, losing hydrogen, or losing electrons.
Oxidation states are used to describe how oxidized an atom in a molecule is. Oxidation occurs when electrons are transferred from one atom to another. In organic chemistry, oxidation occurs when a substance gains an oxygen atom, loses a hydrogen atom, or loses an electron. Oxidation states range from -4 to +8, with 0 being the most stable state. The oxidation state of carbon in methane (CH4) is -4, while the oxidation state of carbon in carbon dioxide (CO2) is +4. The oxidation state of carbon in methanol (CH3OH) is -2, while the oxidation state of carbon in formic acid (HCOOH) is +2.Most Oxidized to Least OxidizedHence, the list that places the molecules, from left to right, from most oxidized to least oxidized is CO2 > CH2O > HCOOH > CH4. The most oxidized molecule is CO2, which has an oxidation state of +4, followed by CH2O, which has an oxidation state of 0. HCOOH is less oxidized than CH2O because it has an oxidation state of +2. CH4 is the least oxidized molecule because it has an oxidation state of -4. Therefore, the correct answer is D. CO2 > CH2O > HCOOH > CH4.for more such question on Oxidation
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what makes viruses so dangerous and vaccines so importent
Answer:
they are very dangerous.
Explanation:
they cause disease in humans, animals, crops, and can cause permanent damage to immune systems.
Answer:
viruses can shut your immune system and infect blood cells thus killing you. vaccines will provent this by prepering your immune system so when you get said virus, it will reduce your chance of death
Explanation:
im not smart with health but i hope this is correct!
Determine the daughter nuclide when Ni-78 undergoes beta decay.
A. Co-78
B. Cu-78
C. Fe-76
D. Ni-78
The daughter nuclide when Ni-78 undergoes beta decay - option D. Ni-78 as beta decay cause a change in atomic number only.
Beta decay is the radioactive decay that emits a beta particle from an atomic nucleus. This causes not just beta particle but some gamma radiation as well. It is represented by \(\beta ^{-}\) and notation is ₋₁β⁰
Daughter nucleus contains the same number of nucleons as the parent nucleusone of the neutrons changes into a protonAs the proton number is increased by 1, the atomic number (Z) is increased by oneNi-78, 78 is atomic mass (neutron + proton), as mention above only atomic number change and number of nucleons remain same, which means atomic mass has no change.Thus, the correct answer would be: option D. Ni-78 as beta decay cause a change in atomic number only.
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You are given the reaction Cu + HNO3 Right arrow. Cu(NO3)2 + NO + H2O.
Which element is oxidized?
Which element is reduced?
Copper (Cu) is oxidized, and Nitrogen (N) is reduced.
Which element is oxidized and is reduced?The element that is oxidized or reduced is calculated as follows;
Cu + HNO3 → Cu(NO3)2 + NO + H2O
Oxidation is the loss of electrons, whereas reduction is the gain of electrons.
In the given reaction, copper (Cu) is oxidized as it loses two electrons, going from an oxidation state of 0 to +2 in Cu(NO3)2.
On the other hand, nitrogen in HNO3 undergoes a change in oxidation state from +5 to +2, indicating that it has gained three electrons and hence, is reduced to NO.
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What is a superconductor?
A. A conductor that operates at room temperature
B. A conductor that allows electricity to flow easily
C. A conductor that conducts electricity faster than common metals
D. A conductor that allows electricity to flow through nonmetal solids
Answer:
its B
Explanation:
a p e x
Answer:
the answer is b. allows electricity to flow easily
how to calculate mass percent of acetic acid in vinegar
The mass percent of acetic acid in vinegar can be calculated by dividing the mass of acetic acid by the total mass of the vinegar solution and multiplying by 100.
To calculate the mass percent of acetic acid in vinegar, you need to determine the mass of acetic acid and the total mass of the vinegar solution. Here are the steps to follow:
1. Obtain the molar mass of acetic acid (CH3COOH), which is approximately 60.05 g/mol.
2. Measure the mass of vinegar used in the calculation.
3. Prepare a known volume of vinegar solution and record the mass of the solution using an analytical balance.
4. Determine the mass of acetic acid in the solution by subtracting the mass of the empty container from the mass of the container with the vinegar solution.
5. Calculate the mass percent of acetic acid by dividing the mass of acetic acid by the total mass of the vinegar solution and multiplying by 100:
Mass percent of acetic acid = (mass of acetic acid / total mass of vinegar solution) x 100
The resulting value will give you the mass percent of acetic acid in the vinegar solution. It represents the percentage of acetic acid by mass in the total solution.
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what are the fundamental particles of an atom
Protons, neutrons, and electrons are the fundamental subatomic particles.
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The freezing point of the solution, given that the solution has a freezing point depression (ΔTf) of 5.58 °C is -5.58 °C
How do i determine the freezing point of the solution?First, we shall list out the given parameters form the question. This is shown below:
Freezing point depression (ΔTf) = 5.58 °CFreezing point of water = 0.00 °C Freezing point of solution =?The freezing point pf the solution can be obtained as follow:
Freezing point of solution = Freezing point of water - Freezing point depression
Freezing point of solution = 0 - 5.58
Freezing point of solution = -5.58 °C
Thus, we can conclude that the freezing point of the solution is -5.58 °C
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2g of magnesium Oreo to excess dilute acid according to the equation Mg(s) + 2H (aq) --- Mg² (aq) + H2 (g) (Realitive atomic mass of Mg= 24, molar mass volume at room temperature and pressure = 24dm³) The volume of hydrogen, measured at room temperature I pressure, that is produced is A) 1000 cm³ B)1500 cm³ C) 2000 ³cm D) 24 000 cm³
Answer:
Option C. 2000 cm³.
Explanation:
We'll begin by calculating the number of mole in 2 g of Mg. This is illustrated below:
Molar mass of Mg = 24 g/mol
Mass of Mg = 2 g
Mole of Mg =?
Mole = mass /Molar mass
Mole of Mg = 2/24
Mole of Mg = 8.33×10¯² mole.
Next, we shall determine the number of mole of H2 produced from the reaction. This is illustrated below:
Mg(s) + 2H^+ (aq) —› Mg^2+(aq) + H2 (g)
From the balanced equation above,
1 mole of Mg reacted to produce 1 mole of H2.
Therefore, 8.33×10¯² mole of Mg will also produce 8.33×10¯² mole of H2.
Finally, we shall determine the volume of H2 produced. This is illustrated below:
1 mole of H2 occupy 24000 cm³ at room temperature and pressure.
Therefore, 8.33×10¯² mole of H2 will occupy = 8.33×10¯² x 24000 ≈ 2000 cm³ at room temperature and pressure.
Therefore, 2000 cm³ of H2 were obtained from the reaction.
what is the name for these alkenes?
Explanation:
1) 2-methyl prop-1-ene
2) 4-methyl hex-2-ene
3) 2-methyl pent-1-ene
4) 4-propyl hept-3-ene
5) 5-ethyl-4-methyl hept-2-ene
6) 6-methyl-4-propyl oct-1-ene
7) 4,5,6-trimethyl oct-2-ene
Can someone pls pls help ASAP!!
2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l) ΔG°rxn = ? ΔG°f (kJ/mol) -110.9 87.6 51.3 -237.1
Answer:
\(\Delta G_{rxn}=51.0kJ/mol\)
Explanation:
Hello there!
In this case, according to the definition of the Gibbs free energy of reaction in terms of the Gibbs free energy of formation of the involved reactants and products, it is possible for us to compute it as shown below:
\(\Delta G_{rxn}=3\Delta _f G_{NO_2}+\Delta _f G_{H_2O}-2\Delta _f G_{HNO_3}-\Delta _f G_{NO}\)
Thus, by plugging in the given data, it is possible to obtain:
\(\Delta G_{rxn}=3(51.3)+(-237.1)-2(-110.9)-(87.6)\\\\\Delta G_{rxn}=51.0kJ/mol\)
Best regards!
The standard Gibbs free energy change (ΔG°rxn) for the reaction is 76.7 kJ/mol.
The balanced equation for the reaction is:
2 HNO₃(aq) + NO(g) → 3 NO₂(g) + H₂O(l)
The standard free energy change for a reaction ( ΔG0rxn) can be found out using the equation,
ΔG° = Σ ΔG°fproducts - Σ ΔGf° reactants
ΔG°rxn = ΔH°rxn - TΔS0rxn
∆H°rxn = change in enthalpy of reaction
∆S° = Change in entropy of reaction
T = Temperature ( 298 K )
ΔG°rxn = (3 × ΔG°f(NO₂(g)) + ΔG°f(H₂O(l))) - (2 × ΔG°f(HNO₃)aq)) + ΔG°f(NO(g)))
Substituting the given ΔG°f values:
ΔG°rxn = (3 × 51.3 kJ/mol) + (-237.1 kJ/mol) - (2 × (-110.9 kJ/mol)) + (87.6 kJ/mol)
ΔG°rxn = 153.9 kJ/mol - 237.1 kJ/mol + 221.8 kJ/mol + 87.6 kJ/mol
ΔG°rxn = 226.2 kJ/mol - 149.5 kJ/mol
ΔG°rxn = 76.7 kJ/mol
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Solid phosphorus Pand chlorine Cl2 gas react to form solid phosphorus pentachloride PCl5. Suppose you have 9.0 mol of P and 2.0 mol of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol.
The largest amount of PCl5 that could be produced can be determined by the limiting reactant in the reaction between solid phosphorus (P) and chlorine gas (Cl2).The balanced equation for the reaction is: P4 + 10Cl2 → 4PCl5
From the given quantities, we have 9.0 mol of P and 2.0 mol of Cl2.To determine the limiting reactant, we compare the moles of each reactant with their respective coefficients in the balanced equation: Moles of PCl5 from P: 9.0 mol P × (4 mol PCl5 / 1 mol P) = 36.0 mol PCl5. Moles of PCl5 from Cl2: 2.0 mol Cl2 × (4 mol PCl5 / 10 mol Cl2) = 0.8 mol PCl5. Since the moles of PCl5 from Cl2 are lower, chlorine (Cl2) is the limiting reactant. Therefore, the largest amount of PCl5 that can be produced is 0.8 mol (rounded to the nearest 0.1 mol).
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what is 0.1 n hcl standardization?
The abbreviation 0.1 N HCl means normal hydrochloric acid.By comparing a solution to a standard solution with a known concentration, standardisation is the process of determining the precise concentration
By comparing a solution to a standard solution with a known concentration, standardisation is the process of determining the precise concentration of the solution. As precise concentration measurements are necessary for many scientific and industrial applications, it is a crucial stage in chemical analysis. In order to determine the concentration of the unknown solution, the standardisation procedure entails mixing a measured amount of the standard solution with a known quantity of the solution being tested. The primary standard, which is a pure material with a known and steady concentration, is often the standard solution. Standardization is used in many disciplines, including chemistry, biology, and engineering, to assure
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what do the formulas, arrow, and plus signs in a chemical equation tell you?
The formulas in a chemical equation represent the different compounds or molecules involved in the reaction. The arrow indicates the direction of the reaction, usually pointing from the reactants to the products.
In a chemical equation, the formulas, arrow, and plus signs convey important information about the chemical reaction taking place. The plus signs indicate that multiple reactants or products are present.
1. Formulas: These represent the chemical compounds involved in the reaction, with each formula showing the elements and their proportions in the compound. The formulas on the left side of the equation are the reactants, and those on the right side are the products.
2. Arrow: The arrow in the equation (→) represents the direction of the reaction, indicating that the reactants on the left side are converted into the products on the right side. It can be read as "yields" or "forms."
3. Plus signs: These denote that two or more reactants or products are involved in the reaction. A plus sign between reactants or products indicates they are separate entities participating in or resulting from the chemical reaction.
In summary, the formulas, arrow, and plus signs in a chemical equation describe the reactants, products, and the process of the chemical reaction taking place.
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What does it mean if EROEI = 1? a. None of the above b. It's early days of fossil fuel exploration c. It's a perfect return on investment d. The efficiency is 100%
When EROEI (Energy Return on Energy Investment) is equal to 1, it means that the energy gained from a particular source is equivalent to the energy invested in obtaining that energy. In other words, the energy return is equal to the energy input. This indicates a situation where the energy extraction process is barely breaking even, with no net gain or loss in energy.
EROEI is a metric used to assess the efficiency and viability of energy sources. It measures the amount of usable energy obtained from a particular energy source divided by the amount of energy invested to extract or produce that energy. A value of 1 means that the energy gained is just enough to offset the energy invested.
In practical terms, an EROEI of 1 implies that the energy source being evaluated is not very efficient. It suggests that the amount of energy required to extract, process, or produce the energy is nearly equal to the energy obtained. Therefore, there is little to no surplus energy available for other uses or to sustain the energy extraction process itself.
An EROEI of 1 is often associated with energy sources in their early stages of development or exploration, where the technology or extraction methods may not be fully optimized. It could also indicate energy sources with high production costs or low energy density.
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Where can we find what the chemical symbols in a compound mean? Example: 0, C, Na, Li
Answer:
The periodic table
Explanation:
I'm not really sure what your question is. . . I'm assuming this is what you're looking for
Pls help.............
a saline solution has a concentration ratio of 0.5 milligrams of salt in 75 millilitres of solution
how many milligrams of salt will be needed to produce 180 millilitres of saline soluyhaving this same concentration
To produce 180 millilitres of a saline solution of the same concentration, we need 1.2 milligrams of salt.
It is given that a ratio of 0.5 milligrams of salt is present in 75 millilitres of solution. Let us assign a variable x to the amount of salt present in 180 millilitres of saline solution.
To maintain the same concentration we can use the method of cross-multiplication:
The following equation can be used to determine the value of x:
0.5 mg / 75 ml = x mg / 180 ml
( 0.5 × 180) / 75 = x mg
x mg = 90 / 75
Hence x is approximately equal to 1.2 mg.
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14. A force acts for 0.2 second on a body of mass 80 kg at rest and produces a velocity of 10 ms¹.Find the magnitude of the force.
The magnitude of the force acting on the body is 4000 Newtons.
To find the magnitude of the force, we can use Newton's second law of motion, which states that the force applied to an object is equal to the product of its mass and acceleration.
The given information includes the mass of the body (80 kg) and the resulting velocity (10 m/s). However, since the time duration (0.2 seconds) is also provided, we can use it to calculate the acceleration of the body.
The formula to calculate acceleration is:
Acceleration = Change in Velocity / Time
The change in velocity can be calculated by subtracting the initial velocity (which is 0 m/s as the body is at rest) from the final velocity:
Change in Velocity = Final Velocity - Initial Velocity
Change in Velocity = 10 m/s - 0 m/s
Change in Velocity = 10 m/s
Now, we can calculate the acceleration:
Acceleration = Change in Velocity / Time
Acceleration = 10 m/s / 0.2 s
Acceleration = 50 m/s²
Finally, we can calculate the magnitude of the force using Newton's second law:
Force = Mass x Acceleration
Force = 80 kg x 50 m/s²
Force = 4000 N
Therefore, the magnitude of the force acting on the body is 4000 Newtons.
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Element X has two isotopes. If 72.0% of the element has an isotope mass of 84.9 atomic mass units, and 28.0% of the element has an isotopic mass of 87.0 atomic mass units, the average atomic mass of element X is numerically equal to
Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance
\(\footnotesize \longrightarrow \: \rm Average \: atomic \: mass = \dfrac{ \sum\limits \: \% age \: of \: each \: isotope \times Atomic \: mass }{100} \\ \)
\(\footnotesize \longrightarrow \: \rm Average \: atomic \: mass = \dfrac{ 72 \times84.9 + 28 \times 87 }{100} \\ \)
\(\footnotesize \longrightarrow \: \rm Average \: atomic \: mass = \dfrac{ 6112.8 + 2436 }{100} \\ \)
\(\footnotesize \longrightarrow \: \rm Average \: atomic \: mass = \dfrac{ 8548.8 }{100} \\ \)
\(\footnotesize \longrightarrow \: \bf Average \: atomic \: mass = 85.488 \: amu \\\)
The average atomic mass will be "85.488 amu".
Given:
\(f_1 = 72\)% or \(0.72\)\(f_2 = 28\)% or \(0.28\)\(m_1 = 84.9 \ amu\)\(m_2 = 87 \ amu\)So,
The average atomic mass of element X will be:
= \((0.72\times 84.9)+(0.28\times 87)\)
= \(61.128+24.36\)
= \(85.488 \ amu\)
Thus the above answer is correct.
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You have 2.30 cm3 of Pt. Platinum is selling for $28.10/gram. How much Platinum do you have? Density of platinum is 21.45 g/cm3.
he circles below represent a phase change occurring at constant temperature: h5ani Is the value of each of the following positive (+), negative (−), zero (0), or impossible to determine from the given information? (a) qsys (b) ΔEsys (c) ΔEuniv + − 0 inconclusive + − 0 inconclusive + − 0 inconclusive
(a) qsys: impossible to determine
(b) ΔEsys: 0
(c) ΔEuniv: inconclusive
What is the determination of the changes in qsys, ΔEsys, and ΔEuniv during the phase change?
In the given information, the circles represent a phase change occurring at constant temperature. However, the information provided does not allow us to determine the value of qsys, which represents the heat transfer to or from the system. Without additional data, we cannot ascertain whether heat is being added or removed from the system.
Regarding ΔEsys, which represents the change in internal energy of the system, it is determined to be zero. This indicates that there is no change in the system's internal energy during the phase change occurring at constant temperature.
Lastly, the value of ΔEuniv, which represents the change in the total energy of the system and its surroundings, is inconclusive based on the given information. Without further details, it is not possible to determine whether the phase change results in a change in the total energy of the system and its surroundings.
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The acid-dissociation constantof hydrocyanic acid (hcn) at 25.0c is 4.9x10-10. what is the ph of an aqueous solution of 0.090 m sodium cyanide (nacn)?
The pH of an aqueous solution is 11.11
What is pH ?
The pH scale, which previously stood for "potential of hydrogen," is used to describe how acidic or basic an aqueous solution is. The pH values of acidic solutions are typically lower than those of basic or alkaline solutions.
CN- + H2O ↔ HCN + OH-
initial 0.09 0 0
change -X +X +X
Equ (0.09-X) X X
so from the equilibrium equation, we can get Ka expression
when Ka = [HCN] [OH-]/[CN-]
when Ka = Kw/Kb
= (1 x 10^-14) / (4.9 x 10^-10)
= 2 x 10^-5
So, by substitution:
2 x 10^-5 = X^2 / (0.09 - X)
X= 0.0013
∴ [OH] = X = 0.0013
∴ POH = -㏒[OH]
= -㏒0.0013
= 2.886
∴ PH = 14 - POH
= 14 - 2.886 = 11.11
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what is chemical reaction?
Answer:
Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.
Explanation:
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N2O4 (g) 2 NO2 (g) what is happening?
N₂O₄(g) ----> 2NO₂(g) is called as the decomposition reaction.
When one reactant in a chemical reaction is decompose to form one or more products then the chemical reaction is said to be decomposition reaction. The reaction is as follows :
N₂O₄(g) ----> 2NO₂(g)
This equation is balanced equation. Dinitrogen tetroxide containing N - N single bond dissociates to form two molecules of nitrogen dioxide. the reaction is called as decomposition reaction . decomposition reaction are generally endothermic reaction because they require heat to decompose. as we know to break the bond energy is absorbed and formation of bond is the release of energy.
Thus, N₂O₄(g) ----> 2NO₂(g) is called as the decomposition reaction.
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Where is osmosis seen in everyday life? Or why is osmosis important to plants or humans please define in your own words it’s for a lab!!
Answer:
Hey buddy!
Explanation:
Keeping the body's conditions stable makes it possible for living things to survive. Osmosis plays an important role in the human body, especially in the gastro-intestinal system and the kidneys. Osmosis helps you get nutrients out of food. It also gets waste products out of your blood.
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why is the electron configuration for sulfur [ne] 3s² 3pâ´
BEcause
Explanation:
Sulfur (or sulphur in BrE) is a chemical element with the symbol S and atomic number 16. It is abundant, multivalent and nonmetallic.
f there is more than one possible site in the molecule/ion, focus on the central or the charged atom. a) b) c)
Answer:
This statement is in the context of Lewis Structures, which are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule. The diagrams show the valence electrons of the atoms that participate in a bond.
When there is more than one possible site in the molecule or ion, the central or the charged atom must be focused on.
To determine which atom is the central or charged atom, you should look at the molecular/ionic structure and identify the atom with the highest electronegativity or charge density.
In general, the atom with the highest electronegativity or charge density is the central or charged atom.
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A glucose molecule is split, converted to ATP (another chemical), which is then used for a runner's sprint. Heat is given off in the process. Describe the changes in energy types from the beginning of the sprint to the end. Would you consider this reaction endothermic
This reaction is exothermic as it releases heat to the surroundings. The total energy released by the reaction is calculated by subtracting the initial energy from the final energy.
When a glucose molecule is split, it is converted to ATP, which provides energy to the runner's sprint. During this process, heat is released, and various changes in energy types occur from the beginning to the end of the sprint. The energy types' changes are classified into exothermic and endothermic reactions. In exothermic reactions, the system releases heat to the surroundings, whereas in endothermic reactions, the surroundings absorb heat from the system. During the initial stages of the sprint, glucose is broken down to form ATP through a process called cellular respiration, which involves glycolysis, the Krebs cycle, and electron transport chain. Glycolysis breaks down glucose into two pyruvate molecules, producing two molecules of ATP. The pyruvate molecule is converted to acetyl-CoA in the Krebs cycle, producing two more ATP molecules and NADH. Finally, the electron transport chain oxidizes NADH, producing a large amount of ATP.During the process of cellular respiration, glucose is converted to ATP, releasing heat. Therefore, the energy type of the process is exothermic. Overall, this reaction is exothermic as it releases heat to the surroundings. The total energy released by the reaction is calculated by subtracting the initial energy from the final energy.
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