How many moles are in a balloon that is 50.2L, 755 mmHg and -22.0C?

Answer:

21

Explanation:

bcecause thats the only one

Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Answer:

I'm gonna say D because it says it's for chemistry

Explanation:

just an idea I'm not for sure. God Bless

Answer:

A

Explanation:

It is was used in a movie

Este problema indica el volumen deseado de una solución (250 cm³) cuya concentration es de 5 g/L y pregunta la cantidad de sal que se debe disolver.

De este modo, dado que el volumen y la concentración están en distintas unidades, debemos convertir una de ellas a la de la otra, en este caso los cm³ a L como se muestra a continuación:

\(250cm^3*\frac{1L}{1000cm^3}= 0.250L\)

Seguidamente, multiplicamos el volumen previamente obtenido por la concentración con el fin the encontrar los gramos de sal:

\(0.250L*5\frac{g}{L} \\\\=1.25 g\)

Así, esto indica que se deben disolver 1.25 gramos de sal para este requerimiento.

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Answer:

Бардык белгилүү авиация мыйзамдарына ылайык, аары учуу мүмкүнчүлүгү жок. Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

Explanation:

Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

There are approximately 3.47 x 10²² molecules in 5.657g H₂SO₄.

To calculate the number of molecules in 5.657g H₂SO₄, we need to use the Avogadro's number and the molar mass of H₂SO₄.

The molar mass of H₂SO₄ is 98.079 g/mol.

We need to calculate the number of moles of H₂SO₄:

Number of moles = mass/molar mass

                             = 5.657g / 98.079 g/mol

                            = 0.05767 mol.

Then, we can use Avogadro's number, which is 6.022 x 10²³ molecules/mol, to find the number of molecules:

Number of molecules = number of moles x Avogadro's number

                                   = 0.05767 mol x 6.022 x 10²³ molecules/mol

                                    = 3.47 x 10²² molecules

To calculate the number of molecules in a given sample of a substance, you need to use the Avogadro's number, which is 6.022 x 10²³ molecules/mol. This means that one mole of a substance contains 6.022 x 10²³ molecules.

We are given the mass of H₂SO₄, which is 5.657 g. To calculate the number of molecules, we first need to determine the number of moles of H₂SO₄ in the given sample. The molar mass of H₂SO₄ is 98.08 g/mol. So, the number of moles of H₂SO₄ can be calculated as follows:

moles = mass / molar mass

moles = 5.657 g / 98.08 g/mol

moles = 0.0576 mol

Now, we can use the Avogadro's number to determine the number of molecules of H₂SO₄ in 0.0576 moles:

number of molecules = moles x Avogadro's number

number of molecules = 0.0576 mol x 6.022 x 10²³ molecules/mol

number of molecules = 3.47 x 10²² molecules

As a result, in 5.657 g of the material, there are roughly 3.47 x 1022 molecules of H₂SO₄.

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Answer:

pOH = 11.7

Explanation:

From the question given above, the following data were obtained:

Concentration of Hydrogen ion [H⁺] = 0.005 M

pOH =.?

Next, we shall determine the pH of the solution. This is illustrated below:

Concentration of Hydrogen ion [H⁺] = 0.005 M

pH =?

pH = – Log [H⁺]

pH = – Log 0.005

pH = 2.3

Finally, we shall determine the pOH of the solution as follow:

pH = 2.3

pOH =.?

pH + pOH = 14

2.3 + pOH = 14

Collect like terms

pOH = 14 – 2.3

pOH = 11.7

Therefore, the pOH of the solution is 11.7

Answer:

1.52 g of NaCl

Explanation:

We'll begin by calculating the number of mole of chlorine gas (Cl₂) that occupied 0.3 L at STP. This can be obtained as follow:

Recall: 1 mole of any gas occupy 22.4 L at STP.

1 mole of Cl₂ occupy 22.4 L at STP.

Therefore, Xmol of Cl₂ will occupy 0.3 L at STP i.e

Xmol of Cl₂ = 0.3 / 22.4

Xmol of Cl₂ = 0.013 mole

Thus, 0.013 mole of Cl₂ occupied 0.3 L at STP.

Next, we shall determine the number of mole of NaCl produced from the reaction.

Cl₂ + 2Na —> 2NaCl

From the balanced equation above,

1 mole of Cl₂ reacted to produce 2 moles of NaCl.

Therefore, 0.013 mole of Cl₂ will react to produce = 0.013 × 2 = 0.026 mole of NaCl.

Thus, 0.026 mole of NaCl is produced.

Finally, we shall determine the mass of the NaCl. This can be obtained as follow:

Mole of NaCl = 0.026 mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.026 = mass of NaCl / 58.5

Cross multiply

Mass of NaCl = 0.026 × 58.5

Mass of NaCl = 1.52 g

Therefore, 1.52 g of NaCl were produced from the reaction

Answer:

1. Both

2. Phosphorylation

3. Both

4. Phosphorylation

5. Oxidative.

6. Both

Explanation:

Phosphorylation only occurs in chloroplast and it involves larger electrical component. Both Phosphorylation and oxidative occurs in mitochondria and it involves proton gradient. They occur in plants to produce ATP. Oxidative involves in smaller electrical component.

Photophosphorylation is a process that captures the solar energy from the sun to transform it into chemical energy. It occurs in the chloroplast of a plant cell.

Photophosphorylation is a process of converting solar energy from the sun to ATP needed by plants and other organisms for cellular function and activity. This process takes place in the chloroplast of the plant cell and requires electrical components.

Oxidative Phosphorylation is the process of producing ATP with the help of oxygen and enzymes hence, occurs in aerobic cells. It does not need a larger electrical component.

Both phosphorylation and oxidative phosphorylation occurs in the mitochondria of plants cells and involves a proton gradient for the formation of ATP.

Therefore, oxidative phosphorylation option 5. involves a smaller electrical component, phosphorylation option 2. occurs in the chloroplast, and option 4. needs a larger electrical component.

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Look at the mole ratio in the balanced equation

2CO + O2 ==> 2CO2

3.44 mol O2 x 2 mol CO/mol O2 = 6.88 moles CO

Answer:

1.42 × 10⁻⁹ M

Explanation:

Step 1: Given data

Step 2: Write the reaction for the solution of BaSO₄

BaSO₄(s) ⇄ Ba²⁺(aq) + SO₄²⁻(aq)

Step 3: Calculate the concentration of SO₄²⁻

We will use the following expression.

Ksp = 1.08 × 10⁻¹⁰ = [Ba²⁺] × [SO₄²⁻]

[SO₄²⁻] = 1.08 × 10⁻¹⁰ / [Ba²⁺] = 1.08 × 10⁻¹⁰ / 0.0758 = 1.42 × 10⁻⁹ M

Answer:

Explanation:

We have the three equations:

\(NH_{3(g)} + HCl_{(g)} => NH_4Cl_{(s)} ..... \Delta H = ? (1)\\2HCl_{(g)} => H_{2(g)} + Cl_{2(g)} .... \Delta H = +184.6 kJ (2)\\2H_{2(g)} + 1/2N_{2(g)} + 1/2Cl_{2(g)} => NH_4Cl_{(s)} ..... \Delta H = -314.2 kJ (3)\\ N_{2(g)} + 3H_{2(g)} => 2NH_{3(g)} .... \Delta H = +184.6kJ (4)\)

(can you double check that it is 184.6kJ for both equations 2 and 4 because it seems unlikely). We need to solve for equation 1 by addition and changing equations 2, 3 and 4. After possibly some trial and error, we can find that if we flip equations 4, multiply equation 3 by 2, add the equations together, and then finally divide by 2, we can get equation 1. We will get the answer of -314.2 kJ. However, I am again skeptical about the delta H values for equation 2 and 4 so double check that. This method might be super confusing and it is really hard to explain. So what I would suggest you to watch videos on Hess' law.

Fusion process denotes the combining of two atoms nuclei to form a single nucleus releasing a large amount of energy.

According to Einstein's famous equation \(E=mc^{2}\), this energy is released as a result of the resulting nucleus mass being slightly less than the sum of the masses of the original nuclei.

High pressure and temperature must be applied to the fuel typically a mixture of hydrogen isotopes like deuterium and tritium, in order to start the fusion process. The fuel is contained and compressed to the required levels for fusion to occur, which is frequently used in this process.

Although the fusion process is still in the experimental stage and needs more research and development to become a useful energy source, it has the potential to offer a virtually endless source of clean, sustainable energy.

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Answer:

the answer is a

Explanation:

The product of nuclear fusion is a nucleus that has a greater mass number than the starting materials.

Nuclear fusion occurs when two or more atomic nuclei unite to generate one or more new atomic nuclei and subatomic particles.

The release or absorption of energy is caused by the mass differential between the reactants and products.

Hence a nucleus that has a greater mass number than the starting materials is the product of the nuclear fusion is .

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Answer:

A

Explanation:

B. The movement of basketball players on a court of the following is an example of quantization

The process of translating continuously infinite values to a more manageable collection of discontinuous finite values is known as quantization. It involves estimating real-world values with a digital representation that places restrictions on a value's precision and range in the context of simulation and embedded computing.

As a general guideline, quantize to the note you've played that is the shortest; for example, if the phrase contains both eighth and quarter notes, use eighth note resolution. Keep in mind that many rhythms may really employ triplets; if things aren't working out, you may try utilising a triplet resolution.

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Answer:

103 mmHg

Explanation:

To find the new pressure, you need to use the Combined Gas Law:

P₁V₁ / T₁ = P₂V₂ / T₂

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. You can find the new pressure (P₂) after converting the temperatures from Celsius to Kelvin.

P₁ = 365.7 mmHg                                        P₂ = ? mmHg

V₁ = 75.1 L                                                    V₂ = 242.9 L

T₁ = 33.2 °C + 273.15 = 306.35 K              T₂ = 6.5 °C + 273.15 = 279.65 K

P₁V₁ / T₁ = P₂V₂ / T₂                                           <----- Combined Gas Law

(365.7 mmHg)(75.1 L) / 306.35 K = P₂(242.9 L) / 279.65 K    <----- Insert values

89.649 = P₂(242.9 L) / 279.65 K                     <----- Simplify left side

25070.433 = P₂(242.9 L)                                 <----- Multiply both sides by 279.65

103 = P₂                                                            <----- Divide both sides by 242.9

Answer:

M= ml - 45301 - 11.59M.

Explanation:

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Answer:

Based on the given question, the dimensions of the plate is 15 cm in length, 12.5 cm in width, and 3.50 mm in thickness (0.350 cm). Now the volume of the plate will be,  

V = 15 cm × 12.5 cm × 0.350 cm = 65.62 cm³

A hole of diameter 2.50 cm is drilled through the center of the plate, at the height of 3.50 mm or 0.350 cm. Now the volume of the hole is π(r)²h,  

= 22/7 × (1.25 cm)² × 0.350 cm = 1.72 cm³

Thus, the volume of the plate will be determined by subtracting the volume of plate with the volume of hole, which will be,  

65.62 cm³ - 1.72 cm³ = 63.9 cm³

The density of the alloy is 8.80 g/cm³, therefore, the mass of the alloy can be determined by using the formula, mass = density * volume  

mass = 8.80 g/cm³ × 63.9 cm³ = 562.32 grams

Of the total alloy, 0.090 percent is Si, that is,  

(0.090/100) × 562.32 g = 0.506 grams of Si

The natural abundance of the element is not determined by mass but by the number of atoms it possess. For this Avogadro's number and atomic mass of Si is used. Now the number of atoms of Si present is,  

(0.506 g) (1 mol/28.0855 g) (6.023 × 10²³ atoms /mol) = 1.08 × 10²² Si atoms

Of these Si atoms, 3.10 percent are Si-30 so,  

= (3.10 / 100) × (1.08 × 10²² atoms) / 1000 = 3.34 × 10²⁰ atoms of Si-30. or 3.4 × 10²⁰ atoms

The structural formula of butanol is C4H9OH. It consists of a chain of four carbon atoms, with a hydroxyl (-OH) group attached to one of the carbon atoms. Butanol has several structural isomers, which have the same molecular formula but different structural formulas.

A structural isomer is a compound that has the same molecular formula as another compound but has a different arrangement of its atoms. A string of 4 C atoms are bonded above, below, left, and right to H, except the second C, which is bonded below to O, which is bonded below to H is a structural isomer of butanol.

This is called butan-2-ol. The structural formula of butan-2-ol is CH3CH(OH)CH2CH3. In this isomer, the hydroxyl group is attached to the second carbon atom in the chain, whereas in butanol, the hydroxyl group is attached to the first carbon atom in the chain.

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Answer:

I think 2

Explanation:

(a) The diagram of the galvanic cell is attached to the image below.

(b) Anode: Magnesium strip (Mg)

Cathode: Nickel strip (Ni)

(c) Direction of electron flow: From the anode (Mg) to the cathode (Ni)

The direction of ion flow: From Beaker A to Beaker B through the salt bridge

(d) Oxidizing agent: Nickel strip (Ni)

Reducing agent: Magnesium strip (Mg)

(e) Half-reactions:

At the anode (oxidation):

Mg(s) → Mg⁺²(aq) + 2e-

(f) Net ionic equation:

Mg(s) + Ni⁺²(aq) → Mg²(aq) + Ni(s)

(g) As the cell operates, the mass of the magnesium strip (anode) will decrease due to the oxidation of magnesium atoms into magnesium ions. Conversely, the mass of the nickel strip (cathode) will increase as nickel ions are reduced and deposited onto the strip.

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Answer:

i want to help but  i   d   k. the answer :( sorry i couldnt help

Explanation:

Standard enthalpy of formation for diamonds is 1.9kJ/mol .

Enthalpy of formation of any compound is defined as the amount of energy required to form 1 mole of compound.Enthalpy of formation is usually represented as ΔHf. If the enthalpy of combustion of two reactions is given, then enthalpy of combustion of the overall reaction can be calculated with the help of Hess's Law.

Given Reactions are:-

C(graphite) + O2(g) → CO2(g)  AH°₁= --393.5 kJ/mol C

C(diamond) + O2(g) → CO2(g)

On reversing the second equation:

CO2(g) →  C(diamond) + O2(g) => AH° =-395.4 kJ/mol

C(graphite) →  C(diamond)

AH°(overall) = AH°₁ + AH° =  --393.5 kJ/mol C +-395.4 kJ/mol =               1.9kJ/mol

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The answer is C which is Reading Writing

A student who prefers to study by converting lecture or written information. The learning style of the student is reading writing. Thus option c is correct.

Learning style is defined as the hypothesis that learners can be classified based on how they process information.

It can also be defined as a set of theories aimed at explaining variances in individual learning.

There are basically seven types of learning style.

Reading and writing is one of the best style of learning as by this we can memorize the things for very long time.

Thus, the learning style of the student is reading writing. Thus option c is correct.

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Answer:

39.379 liters

Explanation:

One mole of gas at STP = 22.4 l / mole

22.4 l/mole * 1.758 mole = 39.379 liters

The 3.13 g of K would be needed to completely react with the remaining \(Cl_2\).

To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.

The balanced chemical equation for the reaction between solid potassium and chlorine gas is:

2 K(s) + \(Cl_2\)(g) -> 2 KCl(s)

From the equation, we can see that 2 moles of K react with 1 mole of \(Cl_2\) to form 2 moles of KCl.

First, we need to convert the masses of K and \(Cl_2\) into moles:

moles of K = 15.20 g / 39.10 g/mol = 0.388 mol

moles of \(Cl_2\) = 2.830 g / 70.90 g/mol = 0.040 mol

Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:

Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl

Theoretical yield of KCl from \(Cl_2\): 0.040 mol \(Cl_2\) x (2 mol KCl / 1 mol \(Cl_2\)) = 0.080 mol KCl

We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from \(Cl_2\) is 0.080 mol. Therefore, the limiting reactant is \(Cl_2\), since it produces less product.

To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.

We know that 1 mole of \(Cl_2\) reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining \(Cl_2\) can be calculated as follows:

moles of K needed = 0.040 mol \(Cl_2\) x (2 mol K / 1 mol \(Cl_2\))

                                = 0.080 mol K

This means that 0.080 moles of K would be needed to completely consume the remaining \(Cl_2\). We can convert this to a mass by multiplying by the molar mass of K:

mass of K needed = 0.080 mol K x 39.10 g/mol

                              = 3.13 g K

Therefore, The 3.13 g of K would be needed to completely react with the remaining.

Example verification:

Suppose we had an additional 0.50 g of \(Cl_2\) in the reaction. Would all of the K be consumed, or would there still be excess K?

Moles of additional \(Cl_2\) = mass of \(Cl_2\) / molar mass of \(Cl_2\)

Moles of additional \(Cl_2\) = 0.50 g / 70.90 g/mol

Moles of additional \(Cl_2\) = 0.0070 mol

The theoretical yield of KCl that can be formed from the additional \(Cl_2\) is:

0.0070 mol \(Cl_2\) x (2 mol KCl / 1 mol \(Cl_2\)) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl

Therefore, the total amount of KCl that can be formed from all of the \(Cl_2\) is:

5.95 g + 1.04 g = 6.99 g

The amount of K that would be needed to completely consume all of the \(Cl_2\).

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8.Significant figures

(a) 8.9 x10^8 is correct

(b) 5.6x10^-8 is correct

(c) 0.00048 is correct

(d) 910 0000 is also correct.

Propane gas partial pressure is 300 mm.

Propane gas reaction - C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)

As propane gas is a three-carbon alkali. It has a standard temperature and pressure. It can be compressed into a transport liquid. As per, the gas reacts with the air that is oxygen and gives carbon dioxide. We mix it with the correct ratio then the pressure mix is equal to 300 mm.

The answer is a partial pressure of propane gas 51mmHg and a part of the oxygen gas to be 249 mm. The propane gas is mixed with the oxygen gas and the gas reacts to give out carbon dioxide and thus measuring their correct stoichiometric ratio.

The gas produces a total pressure mix of 300 mg Hg and thus partial pressure is around 51 and that for oxygen is 249 mm. The partial pressure of a gas is 51 mmHg and part of the oxygen gas is 249 mm hg. That of water vapours of 171 mmHg.

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