Answer:
3080mm = 3.08 meters
3080mm = 308 centimeters
Step-by-step explanation:
1 meter = 1000 mm
3080mm = 3080/1000 = 3.08 meters
1 centimeter = 10 mm
3080mm = 3080/10 = 308 centimeters
Solve the following absolute value inequality: |2x – 6| < 4
Answer: X ∈ (1;5)
|2X - 6| < 4
=> -4 < 2X - 6 < 4
<=> 2 < 2X < 10
<=> 1 < X < 5
Step-by-step explanation:
Sketch the graph by hand using asymptotes and intercepts, but not derivatives. Then use your sketch as a guide to producing graphs (with a graphing device) that display the major features of the curve. Use these graphs to estimate the maximum and minimum values. (Round your answers to three decimal places.)
f(x) = (2x+3)²(x-2)^5/x³(x-5)²
The local minima of \(f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}\) are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)
How to determine the local minima?The function is given as:
\(f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}\)
See attachment for the graph of the function f(x)
From the attached graph, we have the following minima:
Minimum = (-1.5, 0)
Minimum = (7.980, 609.174)
The above means that, the local minima are
(x, f(x)) = (-1.5, 0) and (7.980, 609.174)
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Is 1 4/6 an irrational number ?
Yes it is rational number becauseit it s fraction
Graphs. First correct answer will mark brainliest.
30 POINTS!!
The assumption in answering the question is that no student scored 0
The assumptions made in answering the questionFrom the question, we have the following parameters that can be used in our computation:
The bar chart
On the bar chart, we hae
Students that score more than 8 = 5
Students in the class = 33
The (b) is calculated by considering all students that score more than 0 from the histogram
This means that the assumption is that no student scored 0
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graph g(x) = 5|x-6| + 2
Answer + Step-by-step explanation:
\(f(x) = 5|x-6|+2 = \begin{cases}5\left( x-6\right) +2&if\ x\geq 6\\ 5\left( 6-x\right) +2 &if\ x\leq 6\end{cases}\)
\(\Longrightarrow f(x) = \begin{cases}5x-30+2&if\ x\geq 6\\ 30-5x +2 &if\ x\leq 6\end{cases}\)
\(\Longrightarrow f(x) = \begin{cases}5x-28&if\ x\geq 6\\ -5x +32 &if\ x\leq 6\end{cases}\)
case 1: x ≥ 6 → f(x) = 5x - 28
5(6) - 28 = 30 - 28 = 2
Then
the point A(6 ,2) lie on the graph (line) of f
5(7) - 28 = 35 - 28 = 7
Then
the point B(7 ,7) lie on the graph (line) of f
Graphing :
When x ≥ 6 ,the graph of f is the ray [AB) (just connect the points A and B)
case 2: x ≤ 6 → f(x) = -5x + 32
-5(6) +32 = -30 + 32 = 2
Then
the point A(6 ,2) lie on the graph (line) of f
-5(5) +32 = -25 + 32 = 7
Then
the point C(5 ,7) lie on the graph (line) of f
Graphing :
When x ≤ 6 ,the graph of f is the ray [AC) (just connect the points A and C)
Jack is 29 of age he weighs 81kg he works out in a hot day what is the amount of water he will need to drink
Answer:
8 gallons
Step-by-step explanation:
Rotation 90° clockwise about the origin
N
O
G
An image of triangle NOG after a rotation 90° clockwise about the origin is shown below.
What is a rotation?In Mathematics and Geometry, a rotation is a type of transformation which moves every point of the object through a number of degrees around a given point, which can either be clockwise or counterclockwise (anticlockwise) direction.
Next, we would apply a rotation of 90° clockwise about the origin to the coordinate of this triangle NOG in order to determine the coordinate of its image;
(x, y) → (y, -x)
Point N = (-4, -1) → Point N' (-1, 4)
Point O = (-4, -3) → Point O' (-3, 4)
Point G = (0, -1) → Point G' (-1, 0)
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30x + 40y =
what is the answer please help me
Answer:
10(3x + 4y)
Step-by-step explanation:
Help me please please
Step-by-step explanation:
hold on
On circle OOO below, the measure of \stackrel{\LARGE{\frown}}{FJ} FJ ⌢ F, J, start superscript, \frown, end superscript is 84^\circ84 ∘ 84, degrees. The measure of \stackrel{\LARGE{\frown}}{GH} GH ⌢ G, H, start superscript, \frown, end superscript is 76^\circ76 ∘ 76, degrees. What is the measure of \angle HKJ∠HKJangle, H, K, J?
Answer:
100°
Step-by-step explanation:
The angle between chords is the average of the intersected arc angles.
∠FKJ = ½ (84° + 76°)
∠FKJ = 80°
∠HKJ is supplementary to ∠FKJ.
∠HKJ = 180° − 80°
∠HKJ = 100°
Find the vertex f(x)=8(x-21)²
Answer:
(21,0)
Step-by-step explanation:
The function of the parabola is given in vertex form which is \(f(x) = a(x-h)^{2} +k\)
The vertex is equal to (h,k). Looking the function \(f(x)=8(x-21)^{2}\), we see that the h-value is equal to 21 and that the k-value is 0. So the vertex of the function is (21,0).
Solve 6n - 2 - 3n = 16
9514 1404 393
Answer:
n = 6
Step-by-step explanation:
Add 2 and collect terms
3n = 18
Divide by 3
n = 6
Answer: n=6
Step-by-step explanation:
First combine like terms, 6n and -3n to get 3n. Them add 2 to both sides and get 3n=18. Divide both sides by three amd get n=6
HELP PLS ASAP I WILL AWARD BRAINLIEST!!!
Answer:
32
Step-by-step explanation:
the cofactor of 24 is then subtracted by the diameter of pi and then sent to the power of 2 after that divide by 2 and multiply by 6
A bicycle is on sale for 20% off The bicycle regularly costs $129.95 what is the sale price
Answer:$103.96
Step-by-step explanation: $129.95*0.2= $25.99
129.95-$25.99=$103.96
Answer:
Step-by-step explanation:
find the bearing of a from b
find the bearing of b from a
Answer:
130° and 310°
Step-by-step explanation:
the bearing of A from B is the measure of the clockwise angle from a north line at B to A
the angle at B and A are same- side interior angles and sum to 180°
angle at B = 180° - 50° = 130°
the bearing of A from B is then 130°
the bearing of B from A is the measure of the clockwise angle from the north line at A to B
the complete angle about A = 360° then clockwise angle from north line at A to B is
360° - 50° = 310°
the bearing of B from A is 310°
find the perimeter of 2⅔ spuare
Answer:
Perimeter=2⅔
Step-by-step explanation:
remains the same, for given four sided lengths each of ⅔
What is the constant up a proportionally in a equation y=x/g
Answer:
Step-by-step explanation:
\(y=(\frac{1}{g} )x\)
Constant up a proportionally is \(\frac{1}{g}\).
Which of the following vectors represents u + v?
The vector u+v can be represented as < √85, -41.19° >, which is obtained by adding vector u marked on the y-axis from 0 to 6 and vector v marked on the x-axis from 0 to -7 on a coordinate plane.
To add vectors on the coordinate plane. The vector u is marked on the y-axis from 0 to 6, and the vector v is marked on the x-axis from 0 to -7.
To add them, we start at the tail of u and move horizontally to the left by 7 units (since v has a negative x-component) and then vertically up by 6 units (since u has a positive y-component) to reach the head of the resulting vector. This gives us the vector u+v.
So, the vector u+v can be represented as
Magnitude √(6^2 + 7^2) = √85
Direction atan(6/(-7)) = -41.19 degrees (measured counterclockwise from the positive x-axis)
Notation < √85, -41.19° >
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What is the perimeter of the rectangle?
Answer:
6x+20 cm
Step-by-step explanation:
-formula : perimeter of rectangle=2(L+W)
L=2x+10 W=x
2(2x+10+x)
=2(3x+10) *distribute 2 on 3x ,10*
=6x+20 cm
help me on this, I did one so you don't have to do all of it
Answer:
1: 7
2: 2
3: 5
2 x 0.95 + 5 x 0.99 = 6.85
Determine the average rate of change in braking distance, in ft/mph, between one can traveling at 50 mph and one
traveling at 70 mph. Explain what this rate of change means as it relates to braking distance.
Answer:
306.25-156.25/70-50 =150/20=7.5 ft/mph
Step-by-step explanation:
For every 1 mph over 50 mph a car is traveling, its braking distance increases by 7.5 ft
The required braking distance between the one that can travel at 50 mph and one traveling at 70 mph is 7.5 ft/mph.
What is the rate of change?Rate of change is defined as the change in value with rest to the time is called rate of change.
Here,
Distance traveled when applying brake when speed is 70 mph is 306.25,
Distance traveled when applying brake when speed is 50 mph is 156.25 ft
The rate of change of braking is given as,
= 306.25-156.25/70-50
= 150/20
=7.5 ft/mph
Thus, the required braking distance between the one that can travel at 50 mph and one traveling at 70 mph is 7.5 ft/mph.
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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EASY WORK!!!plz look at the photo.
Answer:
first one is -6 and +6
Step-by-step explanation:
Solve the Pythagorean theorem for a, assuming a, b, and c are positive.
Answer:
\( {a}^{2} + {b}^{2} = {c}^{2} \)
\( {a}^{2} = {c}^{2} - {b}^{2} \)
\(a = \sqrt{ {c}^{2} - {b}^{2} } \)
The correct answer is D.
I NEED YOUR HELP!! I'LL. GIVE YOU BRAINLIEST
Answer: ∠16 and ∠11
Step-by-step explanation:
All of these answer options include ∠16, so we know we're looking for an angle that is corresponding to ∠16. A corresponding angle is an angle that is in the same relative position. We will look at ∠9, ∠11, ∠2, and ∠12 since those are the given answer options, and see which is corresponding.
The correct corresponding angles are ∠16 and ∠11.
Two vacationing families leave New York at the same time. They take 20 and 6 days, respectively, to reach their destination and return to New York. The vacationing families each take continuous trips to and from New York. How many days will pass before the two vacationing families leave New York on the same day again?
Answer:
Step-by-step explanation: evagline has 3/5 of box of nuts.she uses it to fill 6 bowls
If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 4 feet per second, how long will it take the baseball to hit the ground? Use the equation h = −16t^2 + 4t + 4. Round your answer to the nearest hundredth.
0.36
0.39
0.61
0.64
It will take the baseball is 0.64 seconds to hit the ground
How long will it take the baseball to hit the ground?From the question, we have the following parameters that can be used in our computation:
Initial height = 4 feet
Initial velocity = 4 feet per seconds
So, the function is given as
h = −16t^2 + 4t + 4
When it hits the ground, we have
h = 0
So, we have
−16t^2 + 4t + 4 = 0
Divide through by 4
So, we have
-4t^2 + t + 1 = 0
Using a graphing tool, we have
t = 0.64
Hence, the time is 0.64 seconds
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Kate ordered a set of beads. She received 40 beads in all. 12 of the beads were blue. What percentage of the beads were blue?
Answer Qucikly
Answer: 30%
Step-by-step explanation:
12/40 = 3/10 = 0.30
0.30*100 = 30%
For the pyramid below draw the net and then calculate its total surface area using your net. ( picture is uploaded)
The total surface area of the pyramid from the net is 286 square cm
Calculating the total surface area from the netTo calculate the total surface area of a pyramid from its net, you need to add up the areas of all its faces.
The net of a pyramid is a two-dimensional representation of the pyramid, where the edges of the net represent the edges of the pyramid.
In this case, the nets are
Rectangle of: 10 by 7Pair of triangles of: 10 by 12.5, 7 by 13Using the above as a guide, we have the following:
Area = 10 * 7 + 2 * (1/2 * 10 * 12.5 + 1/2 * 7 * 13)
Evaluate
Area = 286
Hence, the surface area is 286 square cm
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what is a regression through the origin
A regression through the origin is a linear regression model where the intercept time period is assumed to be 0, meaning the regression line passes through the starting place.
This version is also referred to as zero-intercept regression or homogeneous regression.
It's far frequently used whilst there's a theoretical foundation to agree with that the relationship among the dependent and unbiased variable passes via the foundation or whilst the information propose that the intercept ought to be 0.
The slope coefficient represents the change within the structured variable for a one-unit increase inside the unbiased variable.
However, this kind of regression may not be appropriate in all cases, and a general linear regression version with an intercept term can be greater suitable.
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