How many grams of CuSO4 is needed to make 1 L of a 0.05% solution? (no units)

The molecular formula of the unknown compound is determined as  C₉H₁₁NO₂.

The molecular formula is calculated as follows;

CHNO  +  O₂ ------------> CO₂  + H₂O

Mass of carbon, C:  = (6.64 x 12)/44 = 1.81 g in 2.77 g sample

Mass of hydrogen, H: = (1.67 x 2)/18 = 0.186 g in 2.77 g sample

Mass of Nitrogen, N: = (2.77 x 0.143)/1.69 = 0.234 g

Mass of oxygen, O:  = 2.77 g - 1.81 g - 0.186 g - 0.234 g = 0.54 g

C = 1.81 g = 0.15 mol

H = 0.186 g = 0.186 mol

N = 0.234 g = 0.017 mol

O = 0.54 g = 0.0337 mol

divide through with the smallest number of moles (0.017 mol);

C = 9

H = 11

N = 1

O = 2

Molecular formula = C₉H₁₁NO₂

Check the molar mass of the compound = (9 x 12) + (11 x 1) + (14) + (2 x 16) = 165 g/mol

Thus, the molecular formula of the unknown compound is determined as  C₉H₁₁NO₂.

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Sodium is a metal that belongs to group 1 of the periodic table.

My favorite element is sodium. Sodium is found in group one of the periodic table. The element is univalent and also forms univalent positive ions. Like every other metal, sodium is able to react with dilute acids to liberate hydrogen gas.

Sodium is a light metal and is known to react with mercury to form the sodium mercury amalgam which is obtained during the electrolysis of sodium chloride. All of the compounds that are formed by sodium are ionic in nature. However the hydrides of sodium are unstable.

Sodium is highly reactive thus it must not be exposed to air since it could ignite spontaneously in air. As such, sodium must be stored under paraffin oil. All the compounds of sodium are ionic in nature.

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The pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C is 2.24 × 10⁰ atm.

The pressure of a substance can be calculated using the following formula;

PV = nRT

According to this question, the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C can be calculated as follows:

P × 2 = 0.1 × 0.0821 × 546

2P = 4.48266

P = 2.24 × 10⁰ atm

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Answer:

A

Explanation:

i got it right

Explanation:The kinetic energy of the wire loop moving in a magnetic field

Answer:

Hubble's law says that the universe is expanding outward.

Explanation:

Actually Hubble's law was discovered before the Big Bang theory was formulated. The Big Bang Theory is an attempt to explain the observations that led to Hubble's Law.Before the 1900s the theory was that the universe was eternal and self existent. The idea was that the universe was in a steady state having always existed and would always continue to exist. Albert Einstein even changed the equations in his general theory of relativity to reflect the idea of a steady state. Later he called putting in a fudge factor to result in a steady state the worse mistake of his life.

Hubble observed that most of the universe has a red shift indicating that the universe is expanding and moving away from itself. The further out that the universe is observed the faster it is moving apart.

These observations were inconsistent with a steady state universe.

The Big Bang theory extrapolated backwards. If the universe is expanding and spreading out from itself then further back in time the universe was closer together. The Theory explained Hubble's observations by the idea that at the beginning of time ( for our universe) all the matter and energy were together in one place.

This super dense ball of matter and energy then exploded outwards creating space and time as it is presently observed. The question was would the forces of gravity and black holes bring the matter and energy back together again. The answer found in 1998 was no. The rate of the expansion of the universe is increasing not slowing down and the universe will not collapse back into the super dense ball of matter that it began as.

The Big Bang Theory postulated based on the empirical evidence that our universe had a beginning and it will eventually cease to exist. The conclusion based on Hubble's observations is that matter and energy are not eternal and self existent.

10. grams of hydrogen gas is equal to 5 moles of hydrogen gas. In order to react with this amount of hydrogen gas, 5 moles of oxygen gas is required, which is equal to 160 grams of oxygen gas.

Hydrogen gas is a colorless, odorless, tasteless, and flammable gas. It is the lightest and most abundant element in the universe, making up around 75% of the universe's elemental mass. Hydrogen can exist in several states, including molecular hydrogen (H2), atomic hydrogen (H), and ionized hydrogen (H+). In its molecular form, hydrogen is a non-toxic and non-polluting gas that can be used to produce electricity, fuel, and other chemicals.

In order to answer this question, you must first understand the stoichiometry of the reaction between hydrogen and oxygen.

The balanced equation for this reaction is:

2H2 + O2 → 2H2O

This means that for every two moles of hydrogen gas, one mole of oxygen gas is required. The molar mass of hydrogen gas is 2.016 g/mol, and the molar mass of oxygen gas is 32.00 g/mol.

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Answer:

Metalloid ; semiconductor

Explanation:

Answer:

you can now deduct which one is greater or smaller and by how much.

Explanation:

no of moles= mass/molar mass

1ai) 0.4 = m/ ( 12 + (16*2)

m= 0.4* 44

m= 17.6g

ii) 0.6= m/( 2*1 + 16)

m= 0.6 *18

m= 10.8g

b) 0.135 = m/ ( 2*1 +32 + (16*4)

m= 0.135* 98

m= 13.23g

ii) 0.5= m/ (1+35.5)

m= 0.5*36.5

m= 18.25g

2. Avogadro's Number = 6.02×10²³

1 mol of any element= 6.02×10²³ particles

a) 0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules

ii) 0.3 mol of CO2= (6.02×10²³) * 0.3

= 1.806 × 10²³ molecules

Ans: 0.3 mol of CO2

bi) 0.25 mol of HCl= (6.02×10²³) * 0.25

= 1.505 × 10²³ molecules

bii) - find the no of moles first:

no of moles= mass/molar mass

n= 3.4g/ 34g →mr of H2S in g=2+32= 34g

n= 0.l mol

- use the Avogadro Number.

0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules.

biii) here you're given the density, use it to find the mass of acetic acid.

ρ = 1049 g/ml

ρ = m/v, where v=5 ml

1049 = m/ 5

m= ρ*v

m= 1049*5

m= 5245 g

• convert this into moles.

mr of CH3COOH= 12 + 3+ 12+ 16+ 16+ 1

= 60

mr in g = 60g

n= m/mr

n= 5245/ 60

n= 87. 41666...

n= 87.4 moles

•using Avogadro's Number:

87.4 moles of acetic acid=(6.02×10²³)*87.4

= 2.25148* 10²⁵

= 2.25 * 10²⁵ molecules

thus, the ans for this is 5 ml of acetic acid.

Answer:

This statement is correct.

Explanation:

When the temperature of a gas is decreased, gas converts into liquid state but when a high pressure is applied on a gas , it also converts into liquid state.

If we lower the temperature of a gas, the particles of the gas loose all the kinetic energy and become less movable. Due to this all the particles of the gas come more close to each other and get condense on any solid surfaces and becomes liquid.

For example, water vapours get condense on the surface of a cold drink bottle when these water vapours get in contact with the cool surface of the bottle.

If we apply the high pressure on a gas, all the particles come very close to each other and become dense and changes into liquid.

The new volume of the balloon after heating it to a temperature of 51 °C is approximately 2.39 L.

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Given that:

Substituting the given values and solve for V₂:

\(V_1T_2 = V_2T_1\\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{2.2\ *\ 324.15}{298.15 }\\ \\V_2 = 2.39 \ L\)

Therefore, the final volume is 2.39 litres.

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Answer:

Florida's Global Pattern.

Explanation:

Because of where Florida sits, the weather in the Gulf of Mexico actually blows enough water to Create tidal waves, and also hurricanes. at least that's what I was told cause I live here :>

1)The new volume at a pressure of 1 atm is 0.25 L.

2)The new temperature of the container at a volume of 2 L is approximately 398°C.

3)The new pressure at 2.5 L is approximately 4.8 atm.

4)The new volume at a temperature of 60°C is approximately 55.8

1)To solve these gas law problems, we can use the ideal gas law equation, which states:

PV = nRT,

where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin.

Balloon volume at a pressure of 0.5 atm:\(V_1\) = 0.5 L, \(P_1\)= 0.5 atm.

New volume at a pressure of 1 atm:\(P_2\) = 1 atm.

We can use the relationship\(P_1V_1 = P_2V_2\) to find the new volume (\(V_2\)).

(0.5 atm)(0.5 L) = (1 atm)(\(V_2\))

\(V_2\) = 0.25 L.

Therefore, the new volume at a pressure of 1 atm is 0.25 L.

2)Container volume: \(V_1\) = 2 L, \(T_1\)= 125°C.

New temperature at the same volume: \(V_2\) = 2 L.

We can use the relationship\(V_1\)/\(T_1\) = \(V_2\)/\(T_2\) to find the new temperature (\(T_2\)).

(2 L)/(125 + 273) K = (2 L)/(\(T_2\) + 273) K

Solving for\(T_2\), we get \(T_2\) ≈ 398°C.

Therefore, the new temperature of the container at a volume of 2 L is approximately 398°C.

3)Initial volume: \(V_1\)= 4.0 L, \(P_1\) = 3.0 atm.

Final volume: \(V_2\) = 2.5 L.

Since the temperature (T) is constant, we can use the relationship \(P_1\)\(V_1\) = \(P_2V_2\) to find the new pressure (\(P_2\)).

(3.0 atm)(4.0 L) = (\(P_2\))(2.5 L)

\(P_2\) ≈ 4.8 atm.

Therefore, the new pressure at 2.5 L is approximately 4.8 atm.

4)Initial volume: \(V_1\)= 50 mL, \(T_1\) = 25°C.

New temperature: \(T_2\) = 60°C.

We need to convert the temperatures to Kelvin.

\(T_1\)= 25 + 273 = 298 K, \(T_2\) = 60 + 273 = 333 K.

We can use the relationship \(V_1/T_1 = V_2/T_2\) to find the new volume (\(V_2\)).

(50 mL)/(298 K) = (\(V_2\))/(333 K)

\(V_2\) ≈ 55.8 mL.

Therefore, the new volume at a temperature of 60°C is approximately 55.8

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Answer:

b

Explanation:

Answer:

Concentration of the sugar in the solution increases

Answer:

The sugar molecules will begin to crystallize back into a solid at the least provocation

According to the given statement Na of the atoms listed below has the largest radius.

An atom is made up of a core nucleus and one or even more electrons with negative charges that orbit it. The positively charged, comparatively hefty protons and neutrons that make it up the nucleus may be present. The fundamental building components of matter are atoms.

Atoms are made up of a nucleus in the center that is surrounded by protons, neutrons, and electron. Uranium is divided into smaller atoms during the fission process, creating new atoms. The creation or atoms in enormous numbers can be seen in the Big Bang and Supernova phenomena.

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Answer:

8.02 g of HCl could be left over by the chemical reaction

Explanation:

We propose the reaction:

HCl(aq) + NaOH (s) → NaCl (aq) + H₂O (l)

Ratio is 1:1. First of all, we determine the moles of reactants:

14 g . 1mol / 36.45g = 0.384 mol of acid

6.55 g. 1mol / 40g = 0.164 mol of base

If a determined mass of HCl, could be left; this means that the acid is the excess reagent.

For 0.164 moles of NaOH, we need 0.164 moles of HCl.

As we have 0.384 moles, (0.384 - 0.164) = 0.220 moles of acid are left over in the reaction. We convert the moles to mass:

0.220 mol . 36.45 g /1mol = 8.02 g

Answer:

4 millllllermeeters jb

From the idea of the reaction quotient, the direction that the reaction would move is the forward . Option 1

We know that the direction that the reaction would move has to depend on the initial concentrations of the reactants. The implication of this is that the reactants that we find in the reaction would have to combine so as to obtain the products.

Let us note that we can be bale to obtain the reaction quocient of the reacvtion at any time. This is the value that shows the direction that the reaction is going. A large reaction quotient shows that the reaction headed in the right hand side while a low reaction quotient shows that the reaction is headed to the forward or reverse.

We have;

Qp = \(pCO * p H_{2} O/pCO_{2} * pH_{2}\)

Qp = 3.3 * 3.3/4.1 * 2.1

Qp = 1.26

The reaction would move forward.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

1.4 g/cm3

Explanation:

Density = Mass/Volume

Mass = 21g

Volume = 15cm3

Density = 21/15 = 1.4

Answer:

Top answer:

The maximum mass of water (H₂O) produced from the reaction between

Explanation:

Gaseous methane ch4 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 1.44 g of ...

Iodine molecule I2 only intereacts with othe iodine molecules by weak interactions suchs as wan der val forces. The carbon that composes diamond is bonded to each other by covalent links, however they form a lattice structure and not a molecule. Since melting temperature is related to the energy necesasry to break inter molecule forces, is is obvious that weak forces such as the iodine molecule will require lower temperature while diamond structure bonds require higher temperatures.

Answer:

If the reaction is zero order, the rate constant has exactly the same units as the rate of the reaction mol L-1 s -1.

If the reaction is first order, then the concentration of one reactant takes care of the units of concentration, thus the rate constant is simply given in units of reciprocal time, s-1.

If the reaction is second order, then two units of concentration are already present so the rate constant needs reciprocal time plus inverse units of concentration, L mol-1 s-1.

If the reaction is third order, the rate constant should have units of L2 mol-2 s-1.

For a first order reaction, the unit of the rate constant is  s^–1 while for  a second order reaction, the unit of the rate constant is M∙s^–1.

The accurate order of reaction can only be determined from experimental values. We have the following orders of reactions;

For a first order reaction, the unit of the rate constant is  s^–1 while for  a second order reaction, the unit of the rate constant is M∙s^–1.

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Answer:

The correct answer is - A. It is the fastest way to reproduce.

Explanation:

Asexual reproduction is the mode of reproduction that does not alter the genes or genetic matter in the offspring and also does not involve the fusion of gametes.

It does not include the genetic variation as it is similar to the parent genetic or sequences. The fastest way to reproduce is asexual reproduction. There is no direct relation between the stability of the environment the asexual reproduction.

Answer:

A. It is the fastest way to reproduce.

Explanation:

well it's only for AP3X users.

Answer:

\(Y=12.2 \frac{gpm}{ft}\)

Explanation:

Hello!

In this case, since we can find that the well produces 280 gpm, and the given drawdown is 23 ft, we need to divide 280 by 23 to obtain the yield in gmp/ft as shown below:

\(Y=\frac{280gpm}{23ft} \\\\Y=12.2 \frac{gpm}{ft}\)

Best regards!

CuO(aq) + H2(g) → H2O(l) + Cu(s)

CuO= 64 + 16= 80g

1 mole of CuO → 1 mole of Cu

80g of CuO → 1 mole of Cu

20.50g of CuO → y

y= 20.50/80= 0.26mole.

Answer:

First, we need to calculate the amount of heat required to raise the temperature of ice from -21°C to 0°C:

q1 = m × C_solid × ΔT = 31 g × 2.09 J/g·°C × (0°C - (-21°C)) = 1341.09 J

Next, we need to calculate the amount of heat required to melt the ice at 0°C:

q2 = m × ΔH_fusion = 31 g × 334 J/g = 10354 J

Then, we need to calculate the amount of heat required to raise the temperature of the liquid water from 0°C to 42°C:

q3 = m × C_liquid × ΔT = 31 g × 4.18 J/g·°C × (42°C - 0°C) = 5201.56 J

Finally, we need to calculate the amount of heat required to vaporize the liquid water at 100°C:

q4 = m × ΔH_vaporization = 31 g × 2260 J/g = 70060 J

The total amount of heat required is the sum of all four steps:

q_total = q1 + q2 + q3 + q4 = 86857.65 J

Converting to kJ:

q_total = 86.85765 kJ

Therefore, the amount of heat required to convert 31 g of ice at -21°C to liquid water at 42°C is approximately 86.9 kJ.

Explanation:

The mass of FeSO4*7H2O in the sample is 1.21 grams.

Calculate moles of Fe2O3

moles of Fe2O3 = mass of Fe2O3 / Molar mass of Fe2O3

moles of Fe2O3 = 0.348 grams / 159.69 g/mole = 0.00218 moles

Calculate moles of Fe

4 Fe + 3O2 → 2Fe2O3

For 4 moles of Fe consumed there is 2 moles of Fe2O3 produced

This means it has a ratio 2:1

So 0.00218 moles of Fe2O3 produced , there is 2*0.00218 = 0.00436 moles of Fe consumed

Calculate moles of FeSO4*7H2O

Fe + H2SO4 + 7H2O → FeSO4*7H20 + H2

For 1 mole of Fe consumed there is 1 mole of FeSO4*7H2O produced

This means for 0.00436 moles there is 0.00436 moles of Fe2SO4*H2O produced

Calculate the mass of FeSO4*7H2O in the sample

mass of FeSO4*7H2O = 0.00436 moles * 278.01 g/mole = 1.212 g

The mass of FeSO4*7H2O in the sample is 1.21 grams.

Complete question: A powder contains FeSO4⋅7H2O (molar mass=278.01 g/mol), among other components. A 3.930 g sample of the powder was dissolved in HNO3 and heated to convert all iron to Fe3+. The addition of NH3 precipitated Fe2O3⋅xH2O, which was subsequently ignited to produce 0.348 g Fe2O3. What was the mass of FeSO4⋅7H2O in the 3.930 g sample?

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Answer:

d. condensation of water on a wind shield of a car

Explanation:

Condensation involves the conversion of moist air into liquid.

Gas has a higher energy compared to liquid. This is why Gas particles move at random motion and faster in relation to solid and liquid particles due to the high energy content.

The conversion of the gas to liquid means that there was loss or release of energy which validates the answer.