How many grams are in 0.0823 moles of Ar? given; unknown:

Answer:

CO2

Explanation:

took the test

Answer:

Co2

Explanation:

Answer:

40.27% Bromide in the original sample

Explanation:

The reaction of bromide ion, Br- with Pb(NO3)2 is:

2 Br- + Pb(NO3)2 → PbBr2(s)

Where the precipitate produced is PbBr2

To solve this question we must find the moles of PbBr2 filtered using its mass. Twice these moles we can find the moles of Br- and its mass. Percent bromide is:

Mass Bromide / Mass Sample (0.5014g) *100

Mass PbBr2:

1.7895g - 1.3258g = 0.4637g PbBr2

Moles -Molar mass: 367.01g/mol-

0.4637g PbBr2 * (1mol / 367.01g) =

0.001263 moles PbBr2 * (2mol Br / 1mol PbBr2) = 0.002527 moles Br

Mass Br -Molar mass: 79.904g/mol-

0.002527 moles Br * (79.904g / mol) =

0.2019g Br

Percent Bromide:

0.2019g Br / 0.5014g * 100 =

Answer:

I just did the assignment it's "decreases"

Explanation:

If you guys came from Ed-genuity (i'm writing it like that because apperantly that is a swear word?) That means the next questions are "As you move from left to right across the periodic table, electronegativity..." and "As you move from top to bottom within a group, the first ionization energy...".

for electronegativity, it's increases and for ionization energy it's decreases. Hope this helps!

Answer:

1. Decreases

2. Increases

3. Decreases

This is a perfect answer

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Answer:

This question appear incomplete

Explanation:

This question appear incomplete because an equation to show the production of sodium chloride from calcium chloride should have been illustrated. However, if the balanced chemical equation showing sodium chloride (NaCl) been a product of a reaction involving calcium chloride (CaCl₂) as a reactant (shown below) is to be used, then we start by writing a complete balanced chemical equation

CaCl₂ + Na₂CO₃  ⇒   CaCO₃ + 2NaCl

From the equation above, it can be deduced that 1 mole of CaCl₂ is required to produce 2 moles of NaCl, thus how many moles of CaCl₂ will be required to produce 6.5 moles of NaCl.

1 mole of CaCl₂ = 2 moles of NaCl

? moles of CaCl₂ = 6.5 moles of NaCl

cross multiply

? moles of CaCl₂ = 6.5 × 1/2

? moles of CaCl₂ = 3.25 moles of CaCl₂

3.25 moles of CaCl₂ will be needed to produce 6.5 moles of NaCl

Answer:

yes any physical substance is matter, solid liquid and gas and a telephone is a solid

Explanation:

Answer: Without more information, it is impossible for me to accurately answer your question. In general, cells transport materials across their cell membrane through a variety of mechanisms, including diffusion, osmosis, facilitated diffusion, and active transport. The type of transport that a cell uses depends on the specific needs of the cell and the materials being transported.

The diagrams of a chemical compound give an idea of the structure and composition of the compound.

Because a molecular formula often does not accurately describe a single molecule, structural formulae must be created for organic compounds. Isomers are different compounds with the same chemical formula, and the abundance of organic isomers is a reflection of carbon's exceptional plasticity in creating stable bonds with both other elements and itself.

We refer to such compounds as constitutional isomers when the atoms that make up the molecules of various isomers are linked together in fundamentally different ways. The formulae share a similar structural element and represent all known and hypothetical C4H10O compounds. No double or triple bonds and no rings exist in any of these structures.

Therefore, the diagrams of a chemical compound give an idea of the compound.

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Answer:

Explanation:

C₇H₁₆ is heptane and it has nine isomers (n-heptane and the remaining 8 constitutional isomers). Constitutional isomers are compounds with the same molecular formula but different structural formula or atom connectivity.

The constitutional isomers of n-pentane are 2-methylhexane, 3-methylhexane, 2,2-dimethylpentane, 2,3-dimethylpentane, 2,4-dimethylpentane, 3,3-dimethylpentane, 3-ethylpentane and 2,2,3-trimethylbutane. There structures are in the picture attached

The metal has a specific heat of about 0.39 J/(g°C).

The equation q = mcT, where m is the sample mass, c is the specific heat, and T is the temperature change and is the linear expansion coefficient, which changes somewhat with temperature, can be used to determine how much heat a sample gains or loses.

q = m * c * ΔT

Where q is the amount of heat that is transmitted, m is the metal's mass, c is its specific heat, and T is the temperature change. Knowing that the heat transferred to metal and water is equal and in the opposing directions, we can:

q metal = -q water

We are also aware of the masses and variations in temperature of the metal and water:

m water = 100.0 g

ΔT water = 23.8 °C - 17.4 °C = 6.4 °C

m metal = 33.6 g

ΔT metal = 23.8 °C - 95.8 °C = -72.0 °C (negative because the metal is losing heat)

Using these values as substitutes and solving for c metal, we arrive at:

q metal = -q water

c metal = -100.0 g * 4.18 J/(g·°C) * 6.4 °C / (33.6 g * (-72.0 °C))

c metal ≈ 0.39 J/(g·°C)

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Question:

Suppose you heat a metal object with a mass of 33.6 g to 95.8 °C and transfer it to a calorimeter containing 100.0 g of water at

17.4 °C. The water and metal reach a final temperature of 23.8 °C.

What is the specific heat of the metal?

The order in which atomic orbitals are filled depends on the relative energies of the subshells (1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, and so on).

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The pressure of the environment affects the liquid's boiling point. The boiling point of the liquid is higher when it is under high pressure than when it is under normal atmospheric pressure. For a given pressure, various liquids have different boiling points.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapour all affect its boiling point.

We know that change in temperature of a system is given by the following formula:

Initial boiling point (T₁) = 80.1 °C

ΔT = T₂ - T₁

2.25 = T₂ - 80.1

T₂ = 82.35  °C

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Answer:

82.35

Explanation:

acellus

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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Answer:2

Explanation:

The given instructions outline the steps to follow in a simulation or experiment involving particles A and B. The purpose is to observe and record the number of A and B particles at each minute on the timer. The exact observations and data collection will depend on the specific simulation or experiment being conducted.

Locate the orange reset button: Find the reset button on the bottom right side of the screen and press it to start the reaction over. This ensures that the previous data is cleared and the experiment begins from the initial state.

Drag the ruler: Use the mouse or touch screen to drag the top of the ruler upward until it reaches the 40 mark. This step sets the reference point for measuring the positions of the particles.

Adjust the left platform: Drag the left platform upward until the top of the platform aligns with the 30 mark on the ruler. This step positions the platform for the particles to interact within the desired range.

Toggle the blue play/pause button: Locate the blue play/pause button at the bottom of the screen. Make sure it is in the play position to prevent the reaction from starting before you are ready. This allows you to control the timing of the experiment.

Add 50 A particles: Use the appropriate tool or feature to add 50 A particles to the simulation or experimental setup. This step ensures that the initial condition includes a specific number of A particles.

Start the timer and record observations: Press the play button on the blue box to start the simulation or experiment. Immediately start the timer using the play button on the timer itself. At every minute on the timer, pause the simulation and record the number of A and B particles. This step allows you to track the changes in the particle population over time.

Note: The specific details and actions may vary depending on the simulation or experiment being conducted. It is important to follow the given instructions accurately and record the observations as instructed.

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Answer:

17.94 g

Explanation:

When 7.524 is rounded to 3 significant figures, it will be 7.52.

The process of changing a number to a nearby number with fewer significant digits is known as rounding.

Rounding can be done to the nearest integer, the nearest tenth, the nearest hundredth, and so on.

Here are some pointers on rounding numbers to a certain number of significant digits:If the digit following the last significant digit is less than 5, simply drop it and all following digits.

(round down)For example, 2.832 rounded to two significant digits is 2.8 since the 3 is followed by a 2 which is less than 5.

If the digit following the last significant digit is greater than 5, add 1 to the last significant digit, then drop all of the digits that follow it.

(round up)For example, 4.673 rounded to two significant digits is 4.7 since the 3 is followed by a 7 which is greater than 5.

If the digit following the last significant digit is exactly 5, the preceding digit is odd, and no other digits follow, increase the last significant digit by 1.

If the digit following the last significant digit is exactly 5, the preceding digit is even, and no other digits follow, simply leave the last significant digit alone.

For example, 2.875 rounded to two significant digits is 2.9 since the 5 is followed by an odd number, which means that the 8 should be rounded up, while 2.765 rounded to two significant digits is 2.8 since the 5 is followed by an even number, which means that the 6 should be left alone.

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Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Answer:

A

Explanation:

Bohr proposed that an electron is found only in specific circular paths, or orbits, around the nucleus

Answer:

The number of these organisms in the soil would decrease.

Explanation:

Answer:

it had wings that flapped similat to birds wings

The internal energy of a system : 21.9 kJ

The laws of thermodynamics 1 state that energy can be changed but cannot be destroyed or created  

The equation is:  

ΔU=Q+W    

Energy owned by the system is expressed as internal energy (U)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

The system absorbs 14.73 kJ⇒Q=+14.kJ

The system compressed⇒work done on the gas⇒W=+

W=-PΔV

\(\tt W=-1.54(1-5.720)\\\\W=7.2688\)

\(\tt internal~energy(\Delta U)=Q+W\\\\\Delta U=14.73+7.2688\\\\\Delta U=21.9\)

The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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