How many different elements are in the compound c6h12o6.

The conjugate acid is differ from its conjugate base as, conjugate acid is formed by strong base whereas conjugate base is formed by strong acid.

conjugate base is differ from conjugate acids by the presence of the proton. The conjugate acid is formed when proton is added to the bases whereas conjugate bases is formed when proton is released by the acids.

Example of corrugate acids are given below.

\(NH_{3}\) → \(NH_{2} ^{-} +H^{+}\)

In the above example  \(NH_{2} ^{-}\) is conjugate acids.

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Answer:glucose

Explanation:

Energy released during the breakdown of glucose and other organic fuel molecules from carbohydrates, fats, and proteins during glycolysis is captured and stored in ATP.

The ratio between the energy and oxygen based on the equation is 683.5 KJ/mol

From the equation, we obtained the following:

Thus, the ratio of energy to oxygen is given as:

Energy / Oxygen = 1367 / 2

Energy / Oxygen = 683.5 KJ/mol

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Crystals impurities are expected to have high solubility in cold solvents. Hence, option C is correct.

Cold solvent cleaning is a process used to remove grease, wax and other impurities from metal and other parts.

The process is also called degreasing. Cold solvents are sprayed onto the dirty part and it is brushed clean.

Once the filtration process is done the collected crystals should be washed with a little more ice-cold solvent to remove final soluble impurities which would otherwise be left on the surface of the crystals.

Hence, option C is correct.

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Adaptability is the evidence which is used as an indicator of ecosystem health. An ecosystem's health is described metaphorically as being in good shape.

An ecosystem's health is described metaphorically as being in good shape. The health of an ecosystem can fluctuate due to a variety of factors, including fire, flooding, flooding, extinctions, invading species.

There is no set standard for what constitutes a healthy ecosystem; rather, the apparent health state of an ecosystem can change based on the health indicators used to analyse it and the social ambitions that are motivating the evaluation. Adaptability is the evidence which is used as an indicator of ecosystem health.

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Answer:

A.  Cl₂

B.  51.36 g K

C.  245.3 g KCl

Explanation:

Balance the given chemical equation

K  +  Cl₂  ⇒  KCl

2 K  +  Cl₂  ⇒  2 KCl

A. To find the limiting reagent, first convert the mass of each reactant to moles.  The molar masses are 39.10 g/mol for K and 70.91 g/mol for Cl₂.

(180 g)/(39.10 g/mol) = 4.60 mol K

(120 g)/(70.91 g/mol) = 1.69 mol Cl₂

Now, convert moles of each reactant to moles of the product.  You can do this by using the mole ratio in the balanced chemical reaction.  The reactant with the smallest moles of product is the limiting reagent.

(4.60 mol K) × (2 mol KCl/2 mol K) = 4.60 mol KCl

(1.69 mol Cl₂) × (2 mol KCl/1 mol Cl₂) = 3.29 mol KCl

Cl₂ is the limiting reagent.

B.  You need to find out how much excess K you will have.  Since Cl₂ is the limiting reagent, you will only make 3.29 mol of KCl.  Convert this value to moles of K using the mole ratio.

(3.29 mol KCl) × (2 mol K/2 mol KCl) = 3.29 mol K

Now convert moles of K to grams.  The molar mass is 39.10 g/mol.

(3.29 mol K) × (39.10 g/mol) = 128.64 g K

This is how much K will be consumed in the reaction.  Subtract the total amount of K by the amount that will be consumed.

180 - 128.64 = 51.36 g

There will be 51.36 g of excess K.

C.  You know that you will produce 3.29 mol of KCl based on previous calculations.  Convert this to grams.  The molar mass is 74.55 g/mol.

(3.29 mol) × (74.55 g/mol) = 245.3 g KCl

You will produce 245.3 g of KCl.

a. To determine the initial investment outlay for the spectrometer, we need to calculate the cash flows at Year 0. The base price of the spectrometer is $140,000, and the modification cost is $30,000.

Thus, the initial cost is the sum of these two amounts, which is

$170,000 ($140,000 + $30,000).

Additionally, we need to consider the increase in net operating working capital, which is $8,000. Therefore, the initial investment outlay for the spectrometer is

$178,000 ($170,000 + $8,000).

b. In Years 1, 2, and 3, we need to calculate the annual cash flows. Firstly, we consider the savings in before-tax labor costs, which is $50,000 per year. Next, we calculate the depreciation expense using the MACRS depreciation rates provided. In Year 1, the depreciation expense is

$140,000 * 0.33 = $46,200. In Year 2,

it is $140,000 * 0.45 = $63,000.

In Year 3, it is $140,000 * 0.15 = $21,000.

Finally, we subtract the depreciation expense from the before-tax labor cost savings to get the annual cash flows. In Year 1, it is

$50,000 - $46,200 = $3,800. In Year 2,

it is $50,000 - $63,000 = -$13,000. In Year 3,

it is $50,000 - $21,000 = $29,000.

c. To determine whether the spectrometer should be purchased, we need to calculate the net present value (NPV) of the project's cash flows. Using the WACC of 9%, we discount the cash flows in each year. The NPV is the sum of the discounted cash flows. If the NPV is positive, the project is considered favorable.

If it is negative, the project should not be pursued. In this case, we calculate the NPV by discounting the cash flows in Years 1, 2, and 3 at a rate of 9%. The NPV is calculated as: NPV = ($3,800 / (1 + 0.09)^1) + (-$13,000 / (1 + 0.09)^2) + ($29,000 / (1 + 0.09)^3). If the NPV is positive, the spectrometer should be purchased; if it is negative, it should not be purchased.

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Answer:

Three ways I can come up with are increasing the temperature, increased the amount of solvent, and using a solvent with similar polarity as the solute.

Explanation:

The number of moles of NaCl contained in 350 ml of a 0.115 M solution can be calculated by using the formula: moles = volume (in liters) x molarity: moles = 0.35 L x 0.115 M = 0.04025 moles. Therefore, the correct answer is option (b) 0.040.

In the given solution, the volume is converted from milliliters to liters by dividing by 1000 since there are 1000 milliliters in a liter. Then, we multiply the converted volume by the molarity of the solution, which represents the number of moles of solute (NaCl) per liter of solution. By multiplying the volume and molarity, we obtain the number of moles of NaCl present in the solution. Rounding the result to the appropriate number of significant figures, we find that there are approximately 0.040 moles of NaCl in 350 ml of the 0.115 M solution, confirming option (b) as the correct answer.

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The electronic configuration of cobalt 27 is 1s2 2s2 2p6 3s2 3p6 4s2 3d7  

That is here. 1s 2s. 2p. 3s. 3P. 4S, 3d. So, let's plot this against energy, so here it is lowest is 1, so it is 1 as 2 or later we can denote the electrons here. It is 2s the. It is 2p, 3s, there will be 3p, and here is 3 d, and here it is for p like this, it will go and let's write the electrons here. It is 1s2. So it is 1s2 2s2. Then 2p6, so here will be 3s2, then 3p6, then 4s2, then 3d7,

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Answer:

A mixture of molecules is a group of molecules in which there are multiple different elements and atoms, that are in either fixed proportions or random. There are heterogeneous and homogenous mixtures.

Explanation:

Answer:

1 atm

Explanation:

From the question given above, the following data were obtained:

Total mole = 5 moles

Total pressure = 5 atm

Partial pressure for each mole =.?

Next, we shall determine the mole fraction for each mole of the gas. This is illustrated below:

Since the container holds 5 moles of gas, then the mole fraction for each mole of the gas will be 1/5.

Finally, we shall determine the partial pressure for each mole of the gas as follow:

Mole fraction for each mole = 1/5

Total pressure = 5 atm

Partial pressure for each mole =.?

Partial pressure = mole fraction × total pressure

Partial pressure = 1/5 × 5

Partial pressure = 1 atm

Thus, the partial pressure for each mole of the gas is 1 atm.

Answer:

Organisms become more complex over time.

Explanation:

We all evolved from the first bacteria, which was relatively simple. We see over time that things become more adapted, slowly adding eyes, lungs, behavioral patterns, and consciousness.

ANSWER

EXPLANATION

Firstly, we need to define the word titration.

Titration is defined as a technique that is used to determine the known concentration of an unknown solution.

This normally occurs between an acid and a base

During titration, an indicator changes color when equilibrium has been attained between the two solutions. The solutions are normally acid and base. At equilibrium, the number of moles of acid is equal to the number of base.

Therefore, the correct answer is option C

Answer:

C.) 2 C₂H₂ +5 O₂ --> 4 CO₂ + 2 H₂O

Explanation:

*None of these answers perfectly display the combustion of a hydrocarbon, so I chose the one that looks most similar*

The combustion of a hydrocarbon (CₙH₂ₙ₊₂) occurs when a hydrocarbon reacts with oxygen gas (O₂) and produces carbon dioxide (CO₂) and water (H₂O).

CH₄ + 2O₂ → CO₂ + 2H₂O shows the combustion of a hydrocarbon.

Combustion is the type of reaction in which a substance readily reacts with oxygen to form carbon dioxide and water. The substance which reacts with oxygen is Hydrocarbon.

Hydrocarbons are compounds made only of carbon and hydrogen. It is usually found in crude oil, natural gas. Hydrocarbons are further divided into two types:

Hydrocarbons are generally non-toxic in nature. They are flammable.

Hydrocarbons undergo reactions like:

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Your question was incomplete, but most probably your question was:

Which of the following shows the combustion of a hydrocarbon?

OA. NaOH + HCI → NaCl + H₂O

OB. CO₂ + H₂O → H₂CO3

OC. 2C₂H₂ +502 + 4CO2 + 2H₂O

OD. C₂H4 + Cl₂ ⇒ C₂H4Cl₂

OE. CH₄ + 2O₂ → CO₂ + 2H₂O

Answer:

Oxidation is the loss of electrons or an increase in the oxidation state of an atom, an ion, or of certain atoms in a molecule. Reduction is the gain of electrons or a decrease in the oxidation state of an atom, an ion, or of certain atoms in a molecule.

Explanation:

To solve such this we must know the concept of redox reaction. Therefore, The cause of rejection of classical concept of oxidation and reduction reaction is in any process, oxidation can occur only if reduction is also taking place side by side and vice versa.

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

Oxidation and reduction reaction involves gain of electron and loss of electron simultaneously. This type of reaction is called redox reaction. The cause of rejection of classical concept of oxidation and reduction reaction is in any process, oxidation can occur only if reduction is also taking place side by side and vice versa.

Therefore, the cause of rejection of classical concept of oxidation and reduction reaction is in any process, oxidation can occur only if reduction is also taking place side by side and vice versa.

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Empirical Formula StepsN2O6Sr Strontium Nitrate

Explanation:

Answer:

The mole and Avogadro’s number are two important concepts of science that provide a link between the properties of individual atoms or molecules and the properties of bulk matter. It is clear that an early theorist of the idea of these two concepts was Avogadro. However, the research literature shows that there is a controversy about the subjects of when and by whom the mole concept was first introduced into science and when and by whom Avogadro’s number was first calculated. Based on this point, the following five matters are taken into consideration in this paper. First, in order to base the subject matter on a strong ground, the historical development of understanding the particulate nature of matter is presented. Second, in 1811, Amedeo Avogadro built the theoretical foundations of the mole concept and the number 6.022 × 1023 mol−1. Third, in 1865, Johann Josef Loschmidt first estimated the number of molecules in a cubic centimetre of a gas under normal conditions as 1.83 × 1018. Fourth, in 1881, August Horstmann first introduced the concept of gram-molecular weight in the sense of today’s mole concept into chemistry and, in 1900, Wilhelm Ostwald first used the term mole instead of the term ‘gram-molecular weight’. Lastly, in 1889, Károly Than first determined the gram-molecular volume of gases under normal conditions as 22,330 cm3. Accordingly, the first value for Avogadro’s number in science history should be 4.09 × 1022 molecules/gram-molecular weight, which is calculated by multiplying Loschmidt’s 1.83 × 1018 molecules/cm3 by Than’s 22,330 cm3/gram-molecular weight. Hence, Avogadro is the originator of the ideas of the mole and the number 6.022 × 1023 mol−1, Horstmann first introduced the mole concept into science/chemistry, and Loschmidt and Than are the scientists who first calculated Avogadro’s number. However, in the science research literature, it is widely expressed that the mole concept was first introduced into chemistry by Ostwald in 1900 and that Avogadro’s number was first calculated by Jean Baptiste Perrin in 1908. As a result, in this study, it is particularly emphasised that Horstmann first introduced the mole concept into science/chemistry and the first value of Avogadro’s number in the history of science was 4.09 × 1022 molecules/gram-molecular weight and Loschmidt and Than together first calculated this number.

#CARRY ON LEARNING HOPE IT HELPS

#PLEAS GIVE ME A BRAINLIEST ANSWER FOR

MY APRICIATING WORK

Answer:

To solve this problem, we'll need to use stoichiometry and the molar ratios from the balanced chemical equation. Here's how you can calculate the values:

(a) Mass of the lead nitrate sample:

From the balanced equation, we can see that 2 moles of lead nitrate (Pb(NO3)2) produce 1 mole of oxygen gas (O2). We know that the volume of oxygen gas collected is 112 cm³, which is equal to 112/1000 = 0.112 dm³ (converting cm³ to dm³).

According to the molar volume of gas at STP (22.4 dm³), 1 mole of any gas occupies 22.4 dm³ at STP. Therefore, the number of moles of oxygen gas can be calculated as:

moles of O2 = volume of O2 / molar volume at STP

moles of O2 = 0.112 dm³ / 22.4 dm³/mol = 0.005 mol

Since 2 moles of lead nitrate produce 1 mole of oxygen gas, we can determine the number of moles of lead nitrate as:

moles of Pb(NO3)2 = 2 * moles of O2

moles of Pb(NO3)2 = 2 * 0.005 mol = 0.01 mol

To calculate the mass of the lead nitrate sample, we'll use its molar mass:

mass of Pb(NO3)2 = moles of Pb(NO3)2 * molar mass of Pb(NO3)2

mass of Pb(NO3)2 = 0.01 mol * (207 g/mol + 2 * 14 g/mol + 6 * 16 g/mol)

mass of Pb(NO3)2 = 0.01 mol * 331 g/mol

mass of Pb(NO3)2 = 3.31 g

Therefore, the mass of the lead nitrate sample is 3.31 grams.

(b) Mass of lead(II) oxide produced:

From the balanced equation, we can see that 2 moles of lead nitrate (Pb(NO3)2) produce 2 moles of lead(II) oxide (PbO). So, the number of moles of PbO produced is equal to the number of moles of Pb(NO3)2.

mass of PbO = moles of PbO * molar mass of PbO

mass of PbO = 0.01 mol * (207 g/mol + 16 g/mol)

mass of PbO = 0.01 mol * 223 g/mol

mass of PbO = 2.23 g

Therefore, the mass of lead(II) oxide produced is 2.23 grams.

(c) Volume of nitrogen dioxide gas produced at STP:

From the balanced equation, we can see that 2 moles of lead nitrate (Pb(NO3)2) produce 4 moles of nitrogen dioxide gas (NO2). So, the number of moles of NO2 produced is twice the number of moles of Pb(NO3)2.

moles of NO2 = 2 * moles of Pb(NO3)2

moles of NO2 = 2 * 0.01 mol = 0.02 mol

Using the molar volume of gas at STP, we can calculate the volume of nitrogen dioxide gas:

volume of NO2 = moles of NO2 * molar volume at STP

volume of NO2 = 0.02 mol * 22.4 dm³/mol = 0.448 dm³

Therefore, the volume of nitrogen dioxide gas

Answer: 6m/s

Explanation:

Speed is calculated as distance divided by time. Therefore, the speed of the traveling puck would be calculated as the distance travelled by the hockey puck divided by the time taken. This will be:

= 18m / 3s

= 6m/s

The answer is 6 meters per second

Answer:

We know that,

Density= mass upon volume.

mass= 21.93g

Volume= 49.3 - 46.3

= 3 cm³

Density = 21.93÷ 3

= 7.31 g/cm³

Hope it helps :))

A piece of indium with a mass of 21.93 g is submerged in 46.3 cm³ of water in a graduated cylinder. The water level increases to 49.3 cm³. The correct value for the density of indium measured in g/cm3 from these data is 7.31 g/cm³.

The density of a material is defined as its mass per unit volume. Although the Roman letter D can also be used, the most common symbol for density becomes. Mathematically, density is calculated by dividing weight by volume.

Density is frequently loosely defined as weight per unit volume, which is technically wrong; this quantity is actually more accurately characterized as specific weight. One example is the oil and gas industry in the United States.

Density= mass/volume.

mass= 21.93g

Volume= 49.3 - 46.3

           = 3 cm³

Density = 21.93÷ 3

            = 7.31 g/cm³

Therefore,  7.31 g/cm³ is the density.

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The temperature of 1,000 grams of water can also be increased by roughly 10 degrees Celsius with the same amount of heat energy.

Water has a specific heat capacity of 4.18 J/g°C, or joules per gram per degree Celsius. Accordingly, 4.18 joules of energy are required to raise the temperature of 1 gram of water by 1 degree Celsius.

Now let's figure out how much heat energy is needed to increase 100 grams of water by 10 degrees Celsius:

Heat energy = mass × specific heat capacity × temperature change

Heat energy = 100 g × 4.18 J/g°C × 10°C

Heat energy = 41,800 J

Therefore, to raise the temperature of 100 grams of water by 10 degrees Celsius, 41,800 joules of energy would be required.

Rearranging the calculation will allow us to determine how many degrees Celsius 1,000 grams of water can be increased to using the same amount of heat energy (41,800 joules):

Temperature change = heat energy / (mass × specific heat capacity)

Temperature change = 41,800 J / (1,000 g × 4.18 J/g°C)

Temperature change ≈ 10°C

Therefore, The temperature of 1,000 grams of water can also be increased by roughly 10 degrees Celsius with the same amount of heat energy.

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Answer:

s-2 p-6 d-10 f-14

Explanation:

s orbital max can fit 2 electrons

p orbital max can fit 6 electrons

d orbital max can fit 10 electrons

f orbital max can fit 14 electrons

Answer: 3510 J

Explanation:

q = m x Cs x delta T

m = 28.0 g

Cs = 4.18 J/g x ⁰C

delta T = Final temperature - Initial temperature = 60.0⁰C - 30.0⁰C = 30.0⁰C

q = m x Cs x delta T

q = 28.0 g x (4.18 J/g x ⁰C) x 30.0⁰C = 3511.2 J

3510 J for the correct number of significant figures.

Grams and ⁰C cancel and you are left with Joules.

Answer:

C: 4

Explanation:

In every single covalent bond, each atom shares one electron. 1 + 1 = 2. A double bond is just two bonds so, 2 x 2 = 4.

Answer:

mannn i told that little brat to stop taking the goldfish outta the box because i want them so he better hope he dies cuz if he dosent imma shove these goldfish down his throat ~respectfully~

Explanation: