The distance is 1600 km, and the plane's average speed is x km/hr. The Ordinary aeroplane speed is 800 km/hr.
How to find the aeroplane speed calculation?The distance is 1600 km, and the plane's average speed is x km/hr. The time it takes the plane to fly 1600 km at its current speed is =
Time consumed by the plane at the increased speed is equal to x+400 /1600 km/hr because all time is measured in hours, which must be converted to minutes using the formula 60 /40 hr= 3 2 hr.
Considering the query,/x/ 1600 − x+400 /1600 = 3 /2
⇒ 1600[ x(x+400) x+400−x ]= 3/ 2
⇒ x(x+400)/ 400 = 3 /2 × 1600/ 1
⇒ x(x+400)= 2400×3×1600
⇒ x 2 +400x=960000 ⇒ x 2 +400x−960000=0
⇒ x2 +1200x−800x−960000=0
⇒ x(x+1200)−800)x+1200)=0
⇒ (x+1200)(x−800)=0
∴ x=−1200 or x=800
Given that speed cannot be negative.
∴ Ordinary aeroplane speed is 800 km/hr.
The Complete Question is aeroplane speed.
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what is the difference between VELOCITY and SPEED?
Answer:
Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector. ... In its simplest form, average velocity is calculated by dividing change in position (Δr) by change in time (Δt).
Explanation:
A 4.51 kg object is placed upon an inclined plane which has an incline angle of 23.0*. The object slides down the inclined plane with a constant speed. Find the force of gravity and the parallel component of gravity along with the perpendicular component.
The force of gravity is 103.73N and the parallel component of gravity is 40.45N along with the perpendicular component is 95.43N.
How strong is the force of gravity?The gravitational force, which pulls mass-containing objects in the same direction, is the force of gravity. The force of gravity from Earth is something we consider frequently. Your body is held firmly in place by this force. However, every mass-bearing object pulls everything else with mass toward it through gravity.
The force of gravity F = ma
F = 4.51×23
F = 103.73N
F parallel component = F sinθ
F parallel = 103.73 sin 23°
F parallel = 103.73 × 0.390
F parallel = 40.45N
F perpendicular component = F cosθ
F perpendicular = 103.73 × cos 23°
F perpendicular = 103.73 × 0.920
F perpendicular = 95.43N.
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BRAINLY PLS HELP ME!!!
Should the Us government regulate sugar? In once sentence write down what you are preparing to argue or what stance you are going to take. This will help you to create a starting point for your idea
Answer:
yes
Explanation:
Sugar can cause health problems.
I believe that sugar should be regulated by the government since it causes heath problems. As according to this website heathline.com that up to one third of the population in America is obese. As well as that regulating sugar will greatly help lowering that number, seeing that many food products have tons of sugar in them. By lowering the sugar and regulating it can cause less obesity among the average person in the US. As stated by HeathlyFoodAmerca.org consuming too much sugar can cause increased heath problems as shown, heart disease, diabetes, and teeth decay and this is why I believe that the U.S government should regulate sugar more.
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s the ball is 20 m above the ground as he releases it use conservation of energy to find
The mass of the ball is approximately 10.24 kg, found using the conservation of energy principle.
What is the mass of a ball thrown upward with a speed of 10 m/s from a height of 20 m, using the conservation of energy principle?
To find the answer, we can use the conservation of energy principle, which states that the total energy of a system remains constant if there is no net work done on the system.
Initially, the ball has some potential energy due to its height above the ground and kinetic energy due to its motion. As it travels upwards, its potential energy increases while its kinetic energy decreases until it reaches its highest point, at which its kinetic energy is zero and its potential energy is at its maximum. Then, as it falls back down, its potential energy decreases while its kinetic energy increases until it reaches the ground, at which its potential energy is zero and its kinetic energy is at its maximum.
Let's use the following variables:
m = mass of the ball
v_i = initial velocity of the ball (10 m/s)
v_f = final velocity of the ball (0 m/s at the highest point)
h = height of the ball above the ground (20 m)
g = (9.81 m/s^2)
The total energy of the ball initially is:
E_i = 1/2 * m * v_i^2 + m * g * h
At the highest point, the total energy of the ball is:
E_f = 1/2 * m * v_f^2 + m * g * 2h
Since the ball is at rest at the highest point, its final velocity is zero, so:
E_f = m * g * 2h
By the conservation of energy principle, the total energy of the ball is constant, so:
E_i = E_f
Substituting the expressions for E_i and E_f and solving for the mass of the ball:
1/2 * m * v_i^2 + m * g * h = m * g * 2h
1/2 * v_i^2 + g * h = 2g * h
m = (1/2 * v_i^2 + g * h) / g
m = (1/2 * 10^2 + 9.81 * 20) / 9.81
m = 10.24 kg
Therefore, the mass of the ball is approximately 10.24 kg.
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The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity between t1 = 1.0s and t2 = 4.0s.
Answer: 15m/s
Explanation: Average Velocity is vector describing the total displacement of an object and the time taken to change its position. It is represented as:
\(v=\frac{\Delta x}{\Delta t}\)
At t₁ = 1.0s, displacement x₁ is:
\(x(1)=25+3(1)^{2}\)
x(1) = 28
At t₂ = 4.0s:
\(x(4)=25+3(4)^{2}\)
x(4) = 73
Then, average speed is
\(v=\frac{73-28}{4-1}\)
v = 15
The average velocity of a car between t₁ = 1s and t₂ = 4s is 15m/s
The figure below shows a box with a mass of m = 7.40 kg that starts from rest at point A and slides on a track with negligible friction. Point A is at a height of ha = 5.10 m. An illustration shows a wavy track, starting from a crest, moving to a trough, then again to a crest and trough, and finally to a crest that then moves downward. Three points in the track are highlighted, A, B, and C. Point A is at the top of the track where a box of mass m is placed ready to get released. It is at the height labeled ha from the ground. Point B is shown at the next crest and is at a height of 3.20 meters from the ground. Point C is shown at the following trough and is at a height of 2.00 meters from the ground. (a) What is the box's speed at point B (in m/s)? m/s What is the box's speed at point C (in m/s)? m/s (b) What is the net work (in J) done by the gravitational force on the box as it moves from point A to point C?
Work done by gravity when it moves from A to C will be 288.6 joule
How to calculate the valueApplying conservation of energy between point A and B,
7.4xgx5.9 = 1/2x7.4xv2 + 7.4xgx3.2
873.2 = 7.4v2 + 473.6
v = 7.34 m/s
It should be noted that to find velocity at C, which has come down to a height of 2 meter, it means it has travelled by 5.9-2 =3.9 m
so, v2 = 2gh = 20x3.9 =
v = 8.83 m/s
Work done by gravity when it moves from A to C = mxgx(5.9-2) = 288.6 joule
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please help me quick
Answer:40m East
Explanation:
a water balloon dropped from the top of a building accelerates at 9.8 meters/second/second. If it starts from rest, and falls for 6 seconds before it hits the ground, what will its speed be just before it hits?
The final speed is 58.8 m/s.
What is the final speed?We have to note that if we are to solve the problem that we have here, we have to look at the equations of motion and this is how we can be able to get the final velocity of the object.
Thus we are going to have that;
v = u + gt
v = final speed
u =- initial speed
g = acceleration
t = time
v = gt
v = 9.8 * 6
= 58.8 m/s
The object is going to have a final speed of about 58.8 m/s when we look at the calculations above here.
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A milliammeter whose resistance is 120 ohm has full scale deflection with a current of 5mA. How will you use it to measure a maximum current of 100 A
Answer:
If 99.995 A pass thru a shunt and 5 mA pass thru the meter, the meter will have full scale deflection for a current of 100 A.
By Ohm's Law
99.995 Rs = .005 Rm
Rs = .005 / 99.995 * 120
Rs = .006 ohms
Using a shunt resistance of .006 Ω will produce the required result.
The value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of 0.0012 ohms.
The value of the shunt resistor (Rs) is:
Rs = (Rm × Im) ÷ (If - Im)
where:
Rs = Shunt resistor value
Rm = Resistance of the milliammeter
Im = Full-scale current of the milliammeter
If = Maximum current we want to measure
The shunt resistor value:
Rs = (120 × 5 ) ÷ (100 - 5)
Rs = (0.12 ) ÷ (100 - 0.005)
Rs = 0.12 ÷ 99.995
Rs = 0.00120018 ohms
Since the value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of 0.0012 ohms.
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if an object with a mass of 30kg is propelled with a force of 10 N what rate will the object accelrate at
The given scenario involves calculating the acceleration of an object propelled by a force of 10 N with a mass of 30 kg. The object will accelerate at a rate of 0.333 m/s².
The equation for calculating acceleration is:
acceleration = force / mass
where acceleration is measured in meters per second squared (m/s²), force is measured in Newtons (N), and mass is measured in kilograms (kg).
Given:
mass = 30 kg
force = 10 N
To find the acceleration, we can substitute these values into the equation:
acceleration = force / mass
acceleration = 10 N / 30 kg
acceleration = 0.333 m/s²
Therefore, the object will accelerate at a rate of 0.333 meters per second squared. This means that for every second that passes, the object's velocity will increase by 0.333 meters per second.
It's worth noting that the direction of the force is also important in determining the direction of the acceleration. If the force is applied in the same direction as the motion of the object, it will speed up, but if the force is applied in the opposite direction, it will slow down.
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What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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Which temperature is warmer than the freezing point of water?
O A. OK
O B. 33K
O C. 1°C
O D.O°F
Answer:
C 1 degree
Explanation:
The speed of light is the fastest in which medium
In vacuum, going at 2.99×10^8 m/s.
The GPE for a 45 KG person at the top of a 2m slide
Answer:
22.5 J
Explanation:
GPE=wxh- 45kg divided by 2m= 22.5
on Truck drivers in your community load their trucks beyond what is required by traffic rules. They are always arrested and changed for over loading by the traffic police department.Present a sensitization message to truck owners and the police in your community using the scene of turning effect of forces and stability.
The sensitization message to truck owners and the police in my community using the scene of turning effect of forces and stability is Let us work together so that the prioritization of road safety as well as the stability in our community can be secured by the promotion of responsible behavior so that all all road users can be safe.
What is sensitization ?In the non-associative learning process of sensitization, the delivery of a stimulus repeatedly causes a response's volume to gradually increase. In addition to the recurrent stimulus, sensitization is frequently accompanied by an improvement in responsiveness to a whole class of stimuli.
This is a sort of community-level intervention where we work hand-in-hand with the local population using creative means of contact and communication that enable the target audience to relate to the problems on a personal level.
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4. Name three things that all games, no matter where they are played around the world, have in common.
Answer:
Key components of games are goals, rules, challenge, and interaction.
Explanation:
Hope I helped.
Answer:
the name of the games are goals, rules, challenges and interaction and mabe there can be more.
Explanation:
I hope this helped your day better this is the correct answer i got it correct on the test.
While fishing on a lake, a fisherman notices ripples 0.32 m apart, and they are
traveling with a speed of 1.2 m/s. When the ripples hit his bobber, what frequency
will it bob up and down with?
Please answer ASAP Will do brainlest
the main properties of the main wave propertioes include wavelength amplitude, cruest an trough
Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge
A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the distance dfirst traveled by the plane in the first second of its run?
The distance travelled by the plane in the first second of its run is 5m.
What is Velocity?Velocity is defined as the rate of change of a body’s position with respect to time. Velocity is basically speeding in a specific direction. It is a vector quantity, which means we need both magnitude (speed) and direction to define velocity. If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.
From the question;
velocity (acceleration) = 5m/s2
distance = 1800m
so, to find the distance travelled in the first second;
time = 1 second
using the formula; \(velocity = \frac{displacement}{time}\)
therefore; displacement = velocity x time
displacement = 5 x 1
displacement = 5m
In conclusion, the plane travelled 5m in the first second of its run.
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A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400 joules of work is done, how much force must have been applied?
100 N
4000 N
1600 N
800 N
600 Joules of work is used to lift a box from the ground to a height of six meters. How much work would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters?
600 J
100 J
72 J
50 J
The work done by using a lever with an effort arm of 12 meters and a load arm of 6 meters is 72 Joules. The force must have applied is 1600 N.
what is the calculation of work done ?The work done (in Joules) = force x distance.In this case, the force is the weight of the box (F = m * g, where m is the mass of the box and g is the acceleration due to gravity) and the distance is the height of 6 meters.Since work done is 600 J,600 J = m * g * 6When a lever is used, the work done is given by the formula:work done = effort distance x effort force = load distance x load forceEffort arm = 12 m, load arm = 6 m, and effort force = load forceSo, effort distance = load distance / (effort arm/load arm) = 6/2 = 3mTherefore, the work done by using lever = 3m x effort force = 3m x load force = 3m x mg = 3mg3 = 72 JAnd now The work done (in Joules) = force x distance.In this case, the force is the weight of the object (F = m * g, where m is the mass of the object) and the distance is the height of 4 meters.Since work done is 400 J,400 J = force * 4And by using the lever, the work done is given by the formula:work done = effort distance x effort force = load distance x load forceEffort arm = 10 m, load arm = 2 m, and effort force = load forceSo, effort distance = load distance / (effort arm/load arm) = 4/5 = 0.8mTherefore, the effort force = work done / effort distance = 400J / 0.8m = 1600 NTo learn more about work done refer:
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Which of following is true statement of self-efficiency
Explanation:
Which of the following best defines self-efficacy? The belief in one's ability to cause an intended event to happen. ... If Bobby does not value athletic skill, his lack of talent will have less impact on his self-esteem than if he highly values athleticism.
On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per hour and drive for an additional two hours.Required:a. How far do you go?b. What is your average x component of velocity?c. Why isn't vavg,x equal to the arithmetic average of your initial and final values of vx, (50+90)/2 = 70 km per hour?
Answer:
A.) 230 km
B.) 76.67 km/h
Explanation:
Given that On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per hour and drive for an additional two hours.
A.) How far do you go?
When driving for an hour, the distance covered will be
Distance = speed × time
Distance = 50 × 1 = 50 km
When driving for additional 2 hours, the distance covered will be
Distance = 90 × 2 = 180 km
Total distance = 180 + 50 = 230 km
b. What is your average x component of velocity?
Average Velocity = total distance/ total time
Average velocity = 230/3
Average velocity = 76.67 km/h
c. Why isn't vavg,x equal to the arithmetic average of your initial and final values of vx, (50+90)/2 = 70 km per hour
They are not equal because of the displacement is the same as distance travelled.
A) How far do you go
You can go as far as 230kmDisplacement is mathematically given asDisplacement = Velocity * time
Total displacement, \(x = 50 * 1 + 90 * 2\)
x = 230km
B) The average velocity is
76.67km/hrAverage velocity is given asaverage velocity = \(\frac{total displacement}{Total time taken}\)
\(Ave velocity = \frac{230}{1+2}\\\\ Ave velocity = \frac{230}{3}\\\\ Ave velocity = 76.67km/hr \)
C) Why isn't vavg,x equal to the arithmetic average of your initial and final values
The arithmetic mean is not a valid way to calculate the average in this situation
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Explain why a lorry loaded with bags of maize packed high up is likely to topple when negotiating a corner.
Answer:
Due to its centre of mass being too high and because of that it is at a high risk of toppling at the corner
A small lead ball, attached to a 1.10-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled at a constant rate of three revolutions per second and is released on the upward part of the circular motion when it is 1.3 m above the ground. The ball travels straight upward. In the absence of air resistance, to what maximum height above the ground does the ball rise
Answer:
1.84 m
Explanation:
For the small lead ball to be balanced at the tip of the vertical circle just before it is released, the reaction force , N equal the weight of the lead ball W + the centripetal force, F. This normal reaction ,N also equals the tension T in the string.
So, T = mg + mrω² = ma where m = mass of small lead ball, g = acceleration due to gravity = 9.8 m/s², r = length of rope = 1.10 m and ω = angular speed of lead ball = 3 rev/s = 3 × 2π rad/s = 6π rad/s = 18.85 rad/s and a = acceleration of normal force. So,
a = g + rω²
= 9.8 m/s² + 1.10 m × (18.85 rad/s)²
= 9.8 m/s² + 390.85 m/s²
= 400.65 m/s²
Now, using v² = u² + 2a(h₂ - h₁) where u = initial velocity of ball = rω = 1.10 m × 18.85 rad/s = 20.74 m/s, v = final velocity of ball at maximum height = 0 m/s (since the ball is stationary at maximum height), a = acceleration of small lead ball = -400.65 m/s² (negative since it is in the downward direction of the tension), h₁ = initial position of lead ball above the ground = 1.3 m and h₂ = final position of lead ball above the ground = unknown.
v² = u² + 2a(h₂ - h₁)
So, v² - u² = 2a(h₂ - h₁)
h₂ - h₁ = (v² - u²)/2a
h₂ = h₁ + (v² - u²)/2a
substituting the values of the variables into the equation, we have
h₂ = 1.3 m + ((0 m/s)² - (20.74 m/s)²)/2(-400.65 m/s²)
h₂ = 1.3 m + [-430.15 (m/s)²]/-801.3 m/s²
h₂ = 1.3 m + 0.54 m
h₂ = 1.84 m
Water flows at a speed of 15 m/s through a pipe that has a radius of 0.40 m. The water then flows through a smaller pipe at
a speed of 45 m/s. What is the radius of the smaller pipe?
Answer:
Explanation: The volume flow rate of the water remains constant as it flows from the larger pipe to the smaller pipe. Therefore, we can use the equation:
A1v1 = A2v2
where A1 and v1 are the cross-sectional area and velocity of the larger pipe, and A2 and v2 are the corresponding values for the smaller pipe.
The cross-sectional area of a pipe is given by the formula:
A = πr^2
where r is the radius of the pipe.
Substituting the given values, we get:
π(0.4)^2(15) = π(r^2)(45)
Simplifying and solving for r, we get:
r = 0.13 m
Therefore, the radius of the smaller pipe is 0.13 m.
. An aeroplane takes 30 min to travel from Biratnagar to Kathmandu. If the air distance between
the Biratnagar and Kathmandu is 450 km. Find the average velocity of the plane.
Answer:
average velocity = \(\bf 900 \space\ km/h\)
Explanation:
We can find the average velocity using the following equation:
\(\boxed{average \space\ velocity = \frac{total \space\ distance \space\ travelled}{ \space\ time \space\ taken}}\) .
In this case:
• total distance travelled = 450 km
• time taken = 30 min = 0.5 h
Substituting these values into the equation:
\(average \space\ velocity = \frac{450 \space\ km }{ 0.5 \space\ h}\)
⇒ \(\bf 900 \space\ km/h\)
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Which of the following statements is always true?
a. An object attest has no forces acting on it
b. Unbalanced forces lead to a change in speed or
direction
c. Gravity always leads to an unbalanced force
d. The net force on a moving object can never be zero
Answer: B
Explanation:
An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. An unbalanced force is an unopposed force that causes a change in motion.
Answer:B
Explanation:
A slider bearing consists of a sleeve surrounding a cylindrical shaft that is free to move axially within the sleeve. A lubricant (e.g, grease) is in the gap between the sleeve and the shaft to isolate the metal surfaces and support the stress resulting from the shaft motion. The diameter of the shaft is 2.54 cm, and the sleeve has an inside diameter of 2.6 cm and a length of 5.08cm.
a) If you want to limit the total force on the sleeve to less than 2.2 N when the shaft is moving at a velocity of 6.1 m/s, what should the viscosity of the grease be? What is the magnitude of the flux of momentum in the gap, and which direction is the momentum being transported?