how many chromosomes does an elephant's egg cell have ?

A single raindrop illuminated by sunshine disperses the white light into seven colors spectrum.

A white sunlight consists of seven different color components. These color components have different wavelength. The speed of different components is different when they passes through an optically denser medium(e.g.: prism). So each color component gets bent by a certain amount thus causing dispersion.

A raindrop acts like a prism for the sunshine. When a light ray passes through a rain drop, it splits into seven color component which is known as the dispersion of light.  

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The apparent weight of the metal when completely immersed in the liquid is 16.6 N. This can be calculated using the principle of buoyancy, where the buoyant force acting on the metal is equal to the weight of the liquid displaced by the metal.

Explanation:

The weight of the metal in air is given as 20 N. In the liquid, the buoyant force acting on the metal will partially offset its weight. The buoyant force is equal to the weight of the liquid displaced by the metal.

To calculate the weight of the liquid displaced, we need to find the volume of the metal. The volume can be determined using the density of the metal:

density = mass/volume

Rearranging the formula, we have:

volume = mass/density

Let's assume the mass of the metal is 'm' kg. The volume of the metal can be calculated as:

volume = m / (density of metal)

The weight of the liquid displaced is equal to the weight of this volume of liquid, which can be calculated as:

weight of liquid displaced = volume of metal × density of liquid × g

where g is the acceleration due to gravity.

Since the weight of the liquid displaced is equal to the buoyant force acting on the metal, we can equate the two:

weight of liquid displaced = buoyant force = apparent weight of metal in liquid

Therefore, we have:

volume of metal × density of liquid × g = apparent weight of metal in liquid

Rearranging the equation to find the apparent weight:

apparent weight of metal in liquid = volume of metal × density of liquid × g

Substituting the values, we get:

apparent weight of metal in liquid = (m / (density of metal)) × density of liquid × g

Plugging in the given values for the densities and acceleration due to gravity, we can calculate the apparent weight:

apparent weight of metal in liquid = (m / (7.8 × 10³ kg/m³)) × (8.3 × 10² kg/m³) × (9.8 m/s²)

Simplifying this equation will give us the apparent weight of the metal in the liquid, which is approximately 16.6 N.The apparent weight of the metal when completely immersed in the liquid is 16.6 N. This can be calculated using the principle of buoyancy, where the buoyant force acting on the metal is equal to the weight of the liquid displaced by the metal.

The weight of the metal in air is given as 20 N. In the liquid, the buoyant force acting on the metal will partially offset its weight. The buoyant force is equal to the weight of the liquid displaced by the metal.

To calculate the weight of the liquid displaced, we need to find the volume of the metal. The volume can be determined using the density of the metal:

density = mass/volume

Rearranging the formula, we have:

volume = mass/density

Let's assume the mass of the metal is 'm' kg. The volume of the metal can be calculated as:

volume = m / (density of metal)

The weight of the liquid displaced is equal to the weight of this volume of liquid, which can be calculated as:

weight of liquid displaced = volume of metal × density of liquid × g

where g is the acceleration due to gravity.

Since the weight of the liquid displaced is equal to the buoyant force acting on the metal, we can equate the two:

weight of liquid displaced = buoyant force = apparent weight of metal in liquid

Therefore, we have:

volume of metal × density of liquid × g = apparent weight of metal in liquid

Rearranging the equation to find the apparent weight:

apparent weight of metal in liquid = volume of metal × density of liquid × g

Substituting the values, we get:

apparent weight of metal in liquid = (m / (density of metal)) × density of liquid × g

Plugging in the given values for the densities and acceleration due to gravity, we can calculate the apparent weight:

apparent weight of metal in liquid = (m / (7.8 × 10³ kg/m³)) × (8.3 × 10² kg/m³) × (9.8 m/s²)

Simplifying this equation will give us the apparent weight of the metal in the liquid, which is approximately 16.6 N.

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Answer:

Designing experiments to replicate the conditions in which life may have first evolved on Earth

Explanation:

In 1953, Stanley L. Miller and Harold C. Urey conducted an experiment to prove that life started from inanimate objects. The research was conducted by utilizing proposed chemical substances, mixed together through a scientific design process. The outcome of the research is the predicted atmospheric conditions before the pre-living form started on earth.

Therefore, in this case, the action that might lead scientists to develop new explanations about the universe is "Designing experiments to replicate the conditions in which life may have first evolved on Earth."

The energy of the ejected photoelectron is 1.89 eV.


Energy of radiation, E = 4.2 eV Work function of photocell, φ = 2.31 eV

Energy of ejected photoelectron is given by the difference of the energy of incident radiation and the work function of the metal. That is, KE = hυ - φ where, h is Planck's constant, υ is the frequency of radiation, c = λυ is the speed of lightλ is the wavelength of radiation and c is the speed of light.

From the energy formula of radiation, E = hυE = hc / λ, by substituting h and c values

KE = hc / λ - φ

Given, h = 6.626 x 10^-34 J-s, c = 3 x 10^8 m/s

λ = hc / E

= (6.626 x 10^-34 J-s x 3 x 10^8 m/s) / (4.2 eV x 1.6 x 10^-19 J/eV)

= 4.93 x 10^-7 m

KE = hc / λ - φ

= (6.626 x 10^-34 J-s x 3 x 10^8 m/s) / (4.93 x 10^-7 m) - (2.31 eV x 1.6 x 10^-19 J/eV)

= 1.89 eV

Therefore, the energy of the ejected photoelectron is 1.89 eV.

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Answer:

not sure if this answer helps,

Explanation:

What is caused by the uneven heating of Earth and its atmosphere?

Global winds

This uneven heating produces global circulation patterns. For example, the abundance of energy reaching the equator produces hot humid air that rises high into the atmosphere. ... The air eventually stops rising and spreads north and south towards the Earth's poles.Solar heating of the Earth's surface is uneven because land heats faster than water, and this causes air to warm, expand and rise over land while it cools and sinks over the cooler water surfaces.

THANK YOU AND HAVE A GREAT NIGHT!

Answer: Created Fall 2016 by Ronald Wilson Inductive reasoning uses a set of specific observations to reach an overarching conclusion; it is the opposite of deductive reasoning. So, a few particular premises create a pattern which gives way to a broad idea that is likely true.

Explanation: No explanation lol. But I hope this is helpful!

The source of nutrition that Andrew should consume prior to the match to get the boost of energy he desires is carbohydrate.

Nutrition refers to the organic process by which an organism assimilates food and uses it for growth and maintenance.

There are 6 major classes of nutrients and they are as follows:

Among these classes of nutrients, carbohydrates provide the fastest source of energy in the body and hence, can be recommended for an athlete like Andrew who is preparing for a weight lifting endeavor.

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Answer:

73.1 m/s

Explanation:

Given:

Δx = 160 m

v = 6.9 m/s

t = 4 s

Find: v₀

Δx = ½ (v + v₀) t

160 m = ½ (6.9 m/s + v₀) (4 s)

v₀ = 73.1 m/s

The maximum speed she can tolerate at the low point of her swing is 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body, F = mv²/r = 61.7* v²/11.5 = 5.37 v²

Gravitational force acting on her is

F = mg = 61.7* 9.81 = 605.28 N

Equating the summation of centripetal force and gravitational force with total capable force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Thus, the maximum speed she can tolerate at the low point of her swing is 10.78 m/s.

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Answer:

(1)

H² = B² × L²

H² = (9.2)² × (5.2)²

H² = 84.64 × 27.04

H² = 2288.6656

H = √ 2288.6656

H = 47.84

Answer:

Use Pythagorean theorem

19) A² + B² = C²

5.2² + 9.2² = C²

C = √111.68

C = 10.567875...

C ≈ 10.6

21) A² + B² = C²

B² = C² - A²

B² = 7.2² - 5.3²

B = √23.75

B = 4.873397...

B ≈ 4.9

Answer: It would be 12 m/s.

Explanation: It would be this because If you go from rest to sprint it would be 12 m/s. Also, I did this the other day.

Answer:

Posted Answer and realized it was false. Be back with correct answer soon.

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The electric force between a +3 µC point charge and a –3 µC point charge if they are separated by a distance of 5.0 cm can be calculated by using Coulomb’s law. F = kq1q2 / r²F = (9.0 × 109 N·m2/C2) × (3.0 × 10-6 C) × (-3.0 × 10-6 C) / (0.05 m)²F = -243 N

The electric force between a +3 µC point charge and a –3 µC point charge if they are separated by a distance of 5.0 cm can be calculated by using Coulomb’s law.

Coulomb’s law states that the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Mathematically, F = kq1q2 / r²where, F is the electric forceq1 and q2 are the magnitudes of the two charges is Coulomb’s constant (9.0 × 109 N·m2/C2)r is the separation between the two charges.

Let's use the values from the question to calculate the electric force: F = kq1q2 / r²F = (9.0 × 109 N·m2/C2) × (3.0 × 10-6 C) × (-3.0 × 10-6 C) / (0.05 m)²F = -243 N (the negative sign indicates that the force is attractive)Therefore, the electric force between the two charges is 243 N.

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Answer:

false

Explanation:

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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The weight of picture frame that is hanging by two vertical strings the tensions in the strings are 5.7N and 3.5N is 9.2 N

Since the picture frame is hanging and not moving,

a = 0

The string apply a force upwards and weight is a force that acts downwards.

T1 = 5.7 N

T2 = 3.5 N

∑ Fy = m a

T1 + T2 - W = 0

5.7 + 3.5 - W = 0

W = 9.2 N

Therefore, the weight of picture frame is 9.2 N

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Answer:

Explanation:

3 and 4G networks, Bluetooth, and Wi-Fi technologies. my opinions

The outer planets of our solar system are arranged beyond the asteroid belt and are much larger than the inner planets. The distance between them is measured in astronomical units and can vary slightly due to their elliptical orbits.

The outer planets of our solar system are Jupiter, Saturn, Uranus, and Neptune. These four planets are commonly referred to as the gas giants because they are primarily composed of gas and do not have a solid surface like the inner rocky planets.

In terms of their arrangement, the outer planets are located beyond the asteroid belt and are much larger than the inner planets. Jupiter is the largest planet in the solar system and is located closest to the sun among the outer planets. Saturn is the second largest and is located next to Jupiter. Uranus and Neptune are the farthest out from the sun and are sometimes referred to as the ice giants due to their high water and methane content.

The distance between the outer planets can be measured in astronomical units (AU). An astronomical unit is the average distance between the Earth and the sun, which is approximately 93 million miles. Jupiter is approximately 5.2 AU from the sun, Saturn is 9.5 AU, Uranus is 19.2 AU, and Neptune is 30.1 AU. These distances can vary slightly due to the elliptical orbits of the planets.

To measure the distance between the outer planets, astronomers use a variety of methods including radar and spacecraft measurements, as well as observations of the planets' positions relative to the stars. These measurements are important for understanding the dynamics of the solar system and for planning space missions to explore these distant worlds.

In conclusion, the outer planets of our solar system are arranged beyond the asteroid belt and are much larger than the inner planets. The distance between them is measured in astronomical units and can vary slightly due to their elliptical orbits. Astronomers use a variety of methods to measure these distances, which are important for understanding the dynamics of our solar system.

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The level of sound in the quiet room is 20db and the intensity of sound in the busy street is \(l_{2} = 10^-^5 W\cdot m^-^2\)

Note, β = 10log(I/I₀)

Lets find level of sound in the quiet room given:

I =        10⁻¹⁰ W·m⁻²

I₀ = 1 × 10⁻¹² W·m⁻²

\(\beta = 10log[(10^-^1^0/(1 * 10^-^1^2)] = 10log(10^2) = 10 * 2 = 20 dB\)

Sound level in the quiet room is 20db

Lets find the intensity of sound in the busy street given:

β(street) - β(room) = 50 dB

Let us denote the intensity level equation

\(\beta = 10logI - 10 logl_{0}\)

Let A = the room and B = the road. Then,

(A) β₂ = 10logI₂ - 10logI₀

(B) β₁ = 10logI₁ - 10log I₀

Lets subtract (B) from (A)

\(\beta_{2} - \beta_{1} = 10logl_{2} - 10logl_{1}\)

\(50 = 10logl_{2} - 10log(10^-^1^0)\)

Lets divide each side by 10

\(5 = logl_{2} - log(10^-^1^0)\)

\(5 = logl_{2} - (-10)\)

\(5 = logl_{2} + 10\)

Lets subtract 10 from each side:

\(-5 = logl_{2}\)

Collect antilog of each side:

\(l_{2} = 10^-^5 W\cdot m^-^2\)

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Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

\(s=ut-\dfrac{1}{2}at^2\)

Put the value into the formula

\(1200=92t+\dfrac{1}{2}\times4t^2\)

\(2t^2+92-1200=0\)

\(t=10\ sec\)

We need to calculate the velocity

Using equation of motion

\(v=u+at\)

Put the value into the formula

\(v=92+4\times10\)

\(v=132\ m/s\)

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

\(h'=h+ut-\dfrac{1}{2}at^2\)

Put the value into the formula

\(0=1200+132t-\dfrac{1}{2}\times9.8t^2\)

\(4.9t^2-132t-1200=0\)

\(t=34\ sec\)

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

\(t'=34+10\)

\(t'=44\ sec\)

Hence, The rocket above the ground is in 44 sec.

Answer:

One possible reason is that change in velocity is greater for the individual with lower mass.

Explanation:

By Newton's Law of Mechanics, magnitude of the force on two players would be the same in the collision. Let \(F\) denote this magnitude.

Assume that the duration of the collision is \(\Delta t\). In this collision, magnitude of the impulse \(J\) on each player would be the same: \(J = F\, \Delta t\).

At the same time, impulse is equal to the change in momentum. Specifically, if the mass of one player is \(m\) and the change in their velocity is \(\Delta v\), the change in their momentum would be \(m\, \Delta v\). Thus:

\(m\, \Delta v = J = F\, \Delta t\).

Rearrange to obtain an expression for the change in velocity:

\(\begin{aligned}\Delta v &= \frac{J}{m} = \frac{F\, \Delta t}{m}\end{aligned}\).

In other words, in this collision, change in velocity is inversely proportional to the mass of the participant. Hence, even though the two players experienced force of the same magnitude, the participant with a lower mass would experience a greater change in velocity.

Answer with Explanation:

Echo depends on "how sound waves are reflected back." A hard object, like the walls of the multipurpose hall, reflects sound waves well; thus, Seema could easily hear her echo. In addition to this, the walls of the hall are also smooth and this further allows the sound waves to bounce. On the other hand, soft objects like bed cushions in Seema's room absorbs sound. This prevents the sound waves from being reflected. In addition to this, the sound waves have hard time bouncing because there are many objects in Seema's room.

Explanation:

R1=R2=R3=R4=10 ohms

V=IR

V=2.10

V=20v

The mass and magnitude of the second particle are calculated below.

The initial velocity of an object is its velocity prior to the effect of acceleration, which causes the change. The velocity will be the final velocity after accelerating the object for some time. When a particle moves at a constant speed, it can be accelerated. When a point object moves in a horizontal circular path at a constant speed, the direction of its velocity vector changes over time. It means that in a uniform circular motion, the object's velocity vector changes over time.

Distance between the charges, r = 3.2 × \(10^{-3}\)m

initial acceleration of first particle, \(a_{1}\) = 7m / \(s^{2}\)

Initial acceleration of second particle, \(a_{2}\) = 9.0m / \(s^{2}\)

Mass of first particle, \(m_{1}\) = 6.3 × \(10^{-7}\)kg

Mas of second particle, m₂ = ?

a) Since, \(F_{1}=F_{2}\)

∴ \(m_{1}a_{1} = m_{2}a_{2}\)

mass of second particle-\(m_{2}\) =\(\frac{m_{1}\times a_{1}}{a_{2}}\)

= \(\frac{6.3\times10^{-7}\times7.0}{9.0}\)

=4.9 × \(10^{-7}\)Kg

b)As, \(F_{1} = F_{2}\)

       = \(\frac{q_{1}q_{2}}{4\pi E_{0}r^{2}}\) = \(m_{1}a_{1}\)

       = 6.3 × \(10^{-7} \times\) 7.0

       = 44.1 × \(10^{-7}\)

∴ q = 7.1 × \(10^{-11}\)C.

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Answer:

mechanical energy

Explanation:

Sound energy is the result when a force, either sound or pressure, makes an object or substance vibrate. That energy moves through the substance in waves. Those sound waves are called kinetic mechanical energy.

Answer:

The wavelength of the wave in shallow water is 2.91 m.

Explanation:

Given;

frequency of the wave, f = 1.1 Hz

speed of the wave in deep water, v₁ = 5.7 m/s

speed of the wave in shallow water, v₂ = 3.2 m/s

The wavelength of the wave in the deep water is calculated as;

λ₁ = v₁/f

λ₁ = 5.7 / 1.1

λ₁ = 5.18 m

The wavelength of the wave in the shallow water is calculated as;

λ₂ = v₂/f

λ₂ = 3.2 / 1.1

λ₂ = 2.91 m

Therefore, the wavelength of the wave in shallow water is 2.91 m.

Answer:

The correct statement is A nondigital camera uses film to record images, and a digital camera uses sensors.

Explanation:

A non digital camera uses a film and it works on the basis of light which is either produced by the flash light or sunlight. On the other hand a digital camera has its own sensors which has the ability to provide an option of low light compensation and it also allows the user to adjust the light controls digitally with the help of existing sensors.

Composition, energy transport through the surface, temperature, and topography are the factors in  asteroid  that contribute to the yarkovsky effect.

The Yarkovsky effect is a result of the differential heating of an asteroid's sides by sunlight, which can cause a minor thrust force to be exerted. A spacecraft called OSIRIS-REx was launched by NASA in September 2016 with the goal of capturing and collecting samples from the asteroid Bennu. In October 2020, it made a successful landing on the asteroid. In addition to gathering an asteroid sample and bringing it back to Earth, OSIRIS-REx will study the Yarkovsky effect on Bennu in order to create viable methods for diverting asteroids that are headed straight for the planet.

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Answer: If the mass of the object is 178 kg: k = 9.44*10^-5 N/m

Answer for the mass being 82 kg is not complete, because G was not given.

Explanation:

If the mass of the object is 178 kg:

The mass of object (m) = 178 kg

Length of tunnel (l) = 2640 km

***The minimum displacement (its amplitude) of object from its mean position,

A = 2640/2 = 1320 km = 1.320 * 10^6 m

Mass of planet (M) = 4.48 * 10^24 kg

Its Radius (R) = 8.26 * 10^6 m

Gravitational constant (G) = 6.67259 * 10^-11 Nm^2/kg^2

Now, restoring force for given hormonic motion will be

Vector of F = -((GMm)/R^3) * x

Comparing with, vector of F = -k*x, we get

k = (GMm)/R^3

k = (((6.67259*10^-11)*(4.48*10^24)*178)/(8.26*10^6)^3)

k = ((5320.99017*10^(-11+24))/(563.559976*10^18))

k = 9.44*10^(13-18)

k = 9.44*10^-5 N/m

If the mass of the object is 82 kg:

The mass of object (m) = 82 kg

Length of tunnel (l) = 2430 km

***The minimum displacement (its amplitude) of object from its mean position,

A = 2430/2 = 1215 km = 1.215*10^6 m

Mass of planet (M) = 4.16 * 10^24 kg

Its Radius (R) = 7 * 10^6 m

Gravitational constant (G) not given in the photo

Now, restoring force for given hormonic motion will be

Vector of F = -((GMm)/R^3) * x

Comparing with, vector of F = -k*x, we get

k = (GMm)/R^3

k = ((G*(4.16*10^24)*82)/(7*10^6)^3)

Remember that when multiplying two values with exponents, you add the exponents together!

k = ((3.4112*10^26 * G)/(3.43*10^20))

Insert G to solve!