How many bonding electrons are present in PO43- ?

Explanation:

The temperature which a given solid will melt

Answer:

the temperature at which a given solid will melt.

Explanation:

I don't know how to Explain it. (lol)

Answer: Ammonia (NH3)

Explanation: The other choices include: Vinegar which is Acetic Acid; HCl or Hydrochloric Acid; and HNO3 or Nitric Acid, so by a process of elimination, Ammonia is the only likely answer. A more thorough explanation: ammonia abides by the Brønsted–Lowry definition of a base: wherein it is any compound that can accept a proton from another molecule. It just so happens that, given Ammonia (NH3) in water, Ammonia will accept a proton in the form of H+ from water and form Ammonium (NH4) and Hydroxide ions (OH).

Answer:

125

Explanation:

Answer:

c

Explanation:

Answer: Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution

Explanation: Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution

Answer:

A. A measurement of the concentration of a solution.

Explanation:

The other user was correct. :)

Answer:

Less than 7

Explanation:

during the titration of strong acid and weak base, the weak base is usually kept in the flask and strong acid is kept in the burette. So when we add strong acid slowly drop by drop, slowly the pH level of solution starts to decrease and at equivalence point the acid overpowers the base as a strong acid was taken over a weak base.

If the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77 and the solution is basic.

To calculate the pOH of a solution, we can use the formula:

pOH = -log[OH-]

Given that the [OH-] concentration is 5.9 x 10^(-M), we can substitute this value into the formula:

pOH = -log(5.9 x 10^(-M))

Calculating this expression, we find:

pOH = -log(5.9 x 10^(-M))

pOH ≈ -log(5.9) + (-log(10^(-M)))

Since log(10^(-M)) is equal to -M, the equation simplifies to:

pOH ≈ -log(5.9) - M

Now, we need the value of M (the exponent) to calculate the exact pOH value. It appears that the value of M is missing in the given information. However, assuming M is a positive value, we can continue the calculation.

If we consider M = 6, for instance, the equation becomes:

pOH ≈ -log(5.9) - 6

Now, we can evaluate the expression:

pOH ≈ 1.23 - 6

pOH ≈ -4.77

Therefore, if the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77.

To determine whether the solution is acidic, basic, or neutral, we can use the relationship between pH and pOH. The sum of the pH and pOH of a solution at 25°C is always equal to 14.

Since pOH = -4.77, the pH would be:

pH = 14 - pOH

pH ≈ 14 - (-4.77)

pH ≈ 18.77

A solution with a pH above 7 is considered basic. In this case, the calculated pH is greater than 7. Therefore, the solution is basic.

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Answer: 1s-n=1,l=0

3s-n=3,l=0

2p-n=2,l=1

4d-n=4,l=2

5f-n=5,l=3

Explanation: An electron has 4 quantum numbers .

n-principal quantum number (explains about the shell)

and has values 1,2,3....

l-angular quantum number (shape of the orbital)

and is described by shapes spherical (l=0),polar (l=1),clover leaf (l=2)

l=0(s subshell)

l=1(p subshell)

l=2(d subshell)

l=3(f subshell)

There can be no zero for the main quantum number (n). Therefore, the permitted values for n are 1, 2, 3, 4, and so forth.

Any integer between 0 and n – 1 can serve as the angular quantum number (l). For instance, if n = 3, l can be one of 0, 1, or 2.

Answer:

Explanation:

The n (Principal Quantum Number) and l (Azimuthal Quantum Number) values for the following orbitals are:

a)1s:  n=1 ,  l =0

b) 3s: n=3 ,  l =0

c)2p:  n=2 ,  l =1

d)4d:  n=4 ,  l =2

e)5f:   n=5 ,  l =3

In any orbital there are four different  quantum numbers i.e.,

•Principal Quantum Number

•Azimuthal Quantum Number

•Magnetic Quantum Number

• Spin Quantum Number

Principal Quantum Number tells about the shell and Azimuthal Quantum Number tells us about the shape of orbital.

For any orbital,

n=1,2,3,4,...

And l=0 to(n-1)

For example:

n=1 , l= 0

n=2 , l= 0,1

n=3 ,l=0,1,2

(Here 0 stands for s-orbital ,1for p-orbital, 2 for d-orbital and so on..)

So the n(Principal Quantum Number) and l(Azimuthal Quantum Number) values for the following orbitals are:

a)1s:  

n=1 (the 1 from "1s")and

l=0  (as 0 represents s-orbital)

b) 3s:

n=3 (the 3 from "3s")and

l =0 (as 0 represents s-orbital)

c)2p:

n=2 (the 2 from "2p")and

 l =1 (as 1 represents p-orbital)

d)4d:  

n=4 (the 4 from "4d")and

l =2 (as 2 represents d-orbital)

e)5f:  

n=5 (the 5 from "5f")and

 l =3 (as 3 represents f-orbital)

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The purpose of the cotton wool plug on the conical flask is to permit the free passage of air over the edge of the flask and prevent the establishment of semi-anaerobic conditions in the culture. It can also be used to allow gases produced during a reaction to escape while preventing contaminants from entering the flask.

Injecting or smoking cocaine produces a quicker strong high than snorting it.


Cocaine is a powerfully addictive stimulant drug crafted from the leaves of the coca plant local to South the us. despite the fact that healthcare companies can use it for legitimate medical functions, including neighborhood anesthesia for a few surgical procedures, leisure cocaine use is unlawful. As a street drug, cocaine looks as if a best, white, crystal powder. road sellers regularly blend it with things like cornstarch, talcum powder, or flour to growth earnings. they will also blend it with other tablets including the stimulant amphetamine, or synthetic opioids, along with fentanyl. adding synthetic opioids to cocaine is specifically risky whilst humans using cocaine don’t recognize it carries this dangerous additive. increasing numbers of overdose deaths among cocaine users might be related to this tampered cocaine.

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Answer:

Please mark me brainliest

Explanation:

The answer is false.

opaque materials do not reflect any light because they absorb or trap all light that comes in contact with them. No light is able to return from within an opaque material or reflect off its inner surface. Opaqueness is defined by a lack of light reflection, transmission or scattering. Light either disappears or is converted into other forms of energy within opaque substances.

Please let me know if this helps explain why opaque materials do not reflect light or if any part of the description is unclear. I can also provide any additional examples or details if needed.

Answer: 19) False. A totally opaque material does not let any light pass through it.

Engine oil can be divided into four fundamental assortments - manufactured oil, manufactured mix oils, high mileage oil, and ordinary engine oil.

While there are a few variables in looking at engineered versus customary oil and manufactured mix versus full engineered, there are one-of-a-kind qualities and details to assist you with figuring out which oil is the best fit for your vehicle.

Manufactured engine oil has gone through a synthetically designed process. Engineered soil particles are more uniform in shape with fewer contaminations and preferred properties over ordinary oil atoms. By and large, engineered oil has better outrageous high-temperature and low-temperature execution. Manufactured oils are for the most part figured out with higher-performing added substances. High-mileage engine oil is uncommonly planned for late-model vehicles or more up-to-date vehicles with north of 75,000 miles. High mileage engine oil, with its special added substances and detailing, assists with lessening oil consume off and forestalls oil releases that might happen in more seasoned motors. Pennzoil sells numerous sorts of high-mileage engine oil, like Pennzoil Platinum® High Mileage Full Manufactured Engine Oil and Pennzoil® High Mileage Engine Oil.

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Answer: A

Explanation:

You would recover 36.525g of NaCl after evaporating all of the water.

To find the grams of NaCl that would be recovered after evaporating all the water, we can use the following formula:

mass = moles * molar mass

Where:

Moles = Molarity * Volume

Molarity = 0.250 M

Volume = 2500.0 mL = 2.5 L

Molar mass of NaCl = 58.44 g/mol

mass = 0.250 M * 2.5 L * 58.44 g/mol

mass = 36.525 g

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Answer:

Lithium

Explanation:

The 3rd (third) element on the periodic table is Lithium. Lithium is a soft, silvery, light alkali metal denoted with the symbol Li.

Answer:

a)

Explanation:

Osmosis is a process in which there is movement of solvent molecules through a semipermeable membrane to wards the higher concentration of solute or lower concentration of solvent from a lower concentration of solute molecule. Osmosis can occur in different liquids and even in gases.

Also, in osmosis knowing the osmotic pressure can help determine the molar mass of a solute dissolved in a solvent.

Answer: Matter can be broken down into two categories: pure substances and mixtures. Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule :)!

Answer:

rise your words, not your voice rain grows flowers thunder does not.

Explanation:

off the top of my head

Answer:

x = (-4 + √30) / 2, or x = (-4 – √30) / 2

Explanation:

x = (-b ± √b² – 4ac) / 2a →

y = ax² + bx + c

given

y = 2x² + 8x – 7 →

x = (-(8) ± √(8)² – 4(2)(-7)) / 2(2) →

x = (-8 ± √64 + 56) / 4 →

x = (-8 ± √120) / 4 →

x = (-8 ± 2√30) / 4 →

x = (-4 ± √30) / 2 →

x = (-4 + √30) / 2, or x = (-4 – √30) / 2

Given what we know, we can confirm that option A is correct in that Stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter.

IMF is the acronym used to describe intermolecular forces. These forces include all of the forces that bind molecules together, of which water has plenty. This bonding force creates a high adhesion and thus gives water its surface tension which makes it stay together in the shape of a drop.

Therefore, we can confirm that stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter, and therefore that option A is correct.

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Answer:

Energy

Explanation:

Thank me by brainlest?

Answer:

considering the information given, the concentrations at equilbrium are:

CO(g) = 1.30 M

H2O(g) = 1.30 M

CO2(g) = 4.11 M

H2(g) = 4.11 M

Explanation:

The question requires us to calculate the concentration of CO, H2O, CO2 and H2, given the following information:

- number of moles of CO = 2.60 mol

- number of moles of H2O = 2.60 mol

- volume of container = 2.00 L

- temperature = 690°C

- equilibrium constant = 10.0

- balanced chemical equation:

Since the number of moles of CO and H2O were provided, as well as the volume of the container, we can calculate the concentration of this gases in moles per liter:

Also, since we have the equilibrium constant for this reaction and the concetrations of CO2 and H2 at equilibrium will be the same (they have the same stoichiometric coefficient), we can calculate the concentration of the products using the expression for Keq.

First, let's write the Keq expression for this reaction:

Considering,

[CO2] = [H2] = x

and rearranging this equation to calculate x:

Now, applying the value of Keq given by the question, and the values of concentration calculated previously, we'll have:

Therefore, considering the information given, the concentrations at equilbrium are:

CO(g) = 1.30 M

H2O(g) = 1.30 M

CO2(g) = 4.11 M

H2(g) = 4.11 M

Answer:

Mass of NH₃ produced = 34 g

Explanation:

Given data:

Mass of nitrogen = 28 g

Mass of Hydrogen = 12 g

Mass of NH₃ produced = ?

Solution:

Chemical equation:

N₂ +  3H₂    →   2NH₃

Moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 28 g/ 28 g/mol

Number of moles = 1 mol

Moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 12 g/ 2 g/mol

Number of moles = 6 mol

Now we will compare the moles of hydrogen and nitrogen with ammonia.

                            H₂              :               NH₃

                            3                :                2

                            6                :             2/3×6 = 4 mol

                           N₂              :                NH₃

                            1                :                 2

Number of moles of ammonia produced by nitrogen are less thus it will act as limiting reactant.

Mass of ammonia produced:

Mass = number of moles × molar mass

Mass =  2 mol  ×  17 g/mol

Mass = 34 g

Answer:32 grams.

czts

Answer:its a

Explanation: i juts know it is hope it helps

Answer:

Explanation:

Initial:

A. Balance B is more accurate.

B. Balance A is more precise.

To determine which balance is more accurate and which one is more precise, let's analyze the data provided:

A. Accuracy:

To assess accuracy, we need to compare the average measurements from each balance to the true value, which is 5.00 g.

For Balance A:

Average weight measured = (4.2 g + 4.1 g + 4.3 g + 4.2 g) / 4 = 16.8 g / 4 = 4.2 g

For Balance B:

Average weight measured = (5.1 g + 4.9 g + 4.7 g + 5.2 g) / 4 = 20.9 g / 4 = 5.225 g

Comparing the averages to the true value:

Accuracy of Balance A = |4.2 g - 5.00 g| = 0.8 g

Accuracy of Balance B = |5.225 g - 5.00 g| = 0.225 g

Since the accuracy is determined by the difference between the measured values and the true value, Balance B is more accurate as it has a smaller difference.

B. Precision:

Precision refers to how close the measured values are to each other. To assess precision, we can calculate the standard deviation of the measurements from each balance.

For Balance A:

Standard deviation = \(\sqrt([ (4.2 g - 4.2 g)^{2} + (4.1 g - 4.2 g)^{2} + (4.3 g - 4.2 g)^{2} + (4.2 g - 4.2 g)^{2}]/4)\)

Standard deviation = \(\sqrt([0 + (-0.1)^{2} + 0.1^{2} + 0]/4)\) = \(\sqrt(0.02 / 4)\)

= \(\sqrt(0.005)\) ≈ 0.071 g

For Balance B:

Standard deviation = \(\sqrt([ (5.1 g - 5.225 g)^{2} + (4.9 g - 5.225 g)^{2} + 4.7 g - 5.225 g)^{2} + (5.2 g - 5.225 g)^{2}] / 4)\)

Standard deviation = \(\sqrt([0.075 ^{2} + (-0.325)^{2}) + (-0.525)^{2} + (-0.025)^{2}] / 4)\)

≈ 0.213 g

Comparing the standard deviations:

Precision of Balance A ≈ 0.071 g

Precision of Balance B ≈ 0.213 g

Since precision is determined by the spread or variability of the measured values, Balance A is more precise as it has a smaller standard deviation, indicating less variation in the measurements.

The question was incomplete. find the full content below:

A student is weighing a standard 5.00-g weight four times on two different balances to check them for accuracy and precision. The following table shows the data:

Trial - 1,2,3,4

Balance A - 4.2 g, 4.1  g, 4.3 g, 4.2 g

Balance B - 5.1 g, 4.9  g, 4.7 g, 5.2 g

A. Which of the balances is more accurate?

B. Which is more precise?

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To prepare solution E, approximately 100 ml of solution A is needed. The initial volume reading on the burette is 100.0 ml, and the final volume reading is 0.01 ml.

To prepare solution E in the provided volumetric flask by dispensing solution A from the burette, we need to calculate the volume of solution A required and determine the initial and final volume readings on the burette.To find the volume of solution A needed, we can use the formula:

Volume (ml) = (Number of moles * Molar volume) / Molar concentration

Given that the number of moles of solution A is 0.011665 mol and the molar concentration is 0.1166 M, we can substitute these values into the formula:Volume (ml) = (0.011665 mol * 1000 ml/mol) / 0.1166 M ≈ 99.99 ml

Approximately 100 ml of solution A is required to prepare solution E.

The initial volume reading on the burette before dispensing will be the same as the final volume of solution A, which is 100.0 ml. After dispensing the required volume of solution A (approximately 100 ml) into the volumetric flask, the final volume reading on the burette will be 0.01 ml (assuming the burette has a resolution of 0.01 ml).

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Only 0.516 g of the radioisotope are left after 20 years.

Since these percentages are the same for all isotopes, you may compute them once and apply the results to a variety of issues. The half-life and the initial quantity of radioactive atoms present both affect how much radiation is produced by a radioactive source.

N = N0 * (1/2) (t/T)

where:

N = amount remaining after time t

N0 = initial amount

T = half-life

t = time elapsed

We know that after 4 years, only half of the original sample remains:

2.0 g = 4.0 g * (1/2) (4/T)

Simplifying this equation, we get:

1/2 = (1/2) (4/T)

Taking the logarithm of both sides:

log(1/2) = log[(1/2) (4/T)]

log(1/2) = (4/T) * log(1/2)

Solving for T, we get:

T = 4 / [log(1/2)]

T = 4 / 0.301

T = 13.3 years

Therefore, the half-life of this mystery radioisotope is 13.3 years.

To determine how much of the radioisotope remains after 20 years, we can use the same formula:

N = N0 * (1/2) (t/T)

We now have:

N = 4.0 g * (1/2) (20/13.3)

N = 4.0 g * 0.129

N = 0.516 g

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