Explanation:
Because There are 6.022x10^23 atoms per mole; therefore, (6.022x10^23×3)=18.066x10^23 atoms of titanium.
The only sure evidence for a chemical reaction is
Answer:
that one or more new substances are produced. Temperature Changes Chemical reactions can release energy or absorb energy.
Explanation: .
In Part 1 of this chapter, you learned that USP Chapter <797> has established guidelines for how
often and under what circumstances a detailed hood-cleaning procedure must be performed. With
that in mind, what do these strict regulations indicate about the importance of hood cleaning to
patient health and safety?
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The strict regulations established by USP Chapter <797> regarding hood-cleaning procedures indicate the critical importance of hood cleaning to patient health and safety.
What is hood cleaning?The purpose of these guidelines is to ensure that compounding pharmacies maintain a clean and sterile environment when preparing medications, especially those that will be administered to patients. The guidelines specify the frequency of cleaning and the level of detail required to ensure that the hoods are free of contaminants, which could compromise the quality and efficacy of the compounded products.
Therefore, Failure to comply with these regulations could result in contamination of medications and subsequent harm to patients. Thus, it is crucial to adhere to these guidelines to maintain a safe and sterile environment for compounding medications.
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What is the percent composition of a 16.75 g sample of a compound containing 14.02 g oxygen and 2.73 g hydrogen? Select the correct answer below: 83.7% oxygen, 16.3% hydrogen O 17% oxygen, 13% hydrogen O 68.2% oxygen, 31.8% hydrogen 89.5% oxygen, 10.5% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
Mass of compound = 16.75 g
Mass of Oxygen = 14.02 g
Mass of Hydrogen = 2.73 g
Percentage composition = Mass of element / Mass of compound 100%
Percentage composition of Oxygen = 14.02 g / 16.75 g * 100%
Percentage composition of Oxygen = 0.837 * 100 = 83.7%
Percentage composition of Hydrogen = 2.73 g / 16.75 g * 100%
Percentage composition of Hydrogen = 0.163 * 100 = 16.3%
The correct option is;
83.7% oxygen, 16.3% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
To determine the percent composition we can divide, our mass by total mass and afterwards, multiply by 100.
(Mass of O / Total mass) . 100 = % O
(Mass of H / Total mass) . 100 = % H
Remember that:
% O + % H = 100
Mass of O / Total mass + Mass of H / Total mass = 1
(14.02 g / 16.75g) . 100 = 83.7 %
(2.73 g /16.75g) . 100 = 16.3 %
Please show me how you do and please involve the units
The question requires us to calculate the amount of energy absorbed by the reaction, considering the molar enthalpy for oxygen gas (O2) and that 80.6 g of oxygen were reacting.
The following information was provided by the question:
Balanced chemical reaction:
\(N_{2(g)}+2O_{2(g)}\to N_2O_{4(g)}\)Molar enthalpy of reaction for O2: +499.0 kJ/mol
Mass of O2 reacting: 80.6 g
To solve this problem, we need to calculate the amount of moles that corresponds to the mass of O2 given and then use this value and the molar enthalpy provided to calculate how much heat would be absorbed by the reaction.
First, we need the molar mass of O2. Knowing that the atomic mass of O is 15.99 u:
molar mass (O2) = (2 * 15.99) = 31.98 g/mol
Now, we use the molar mass to calculate the number of moles in 80.6 g of O2:
31.98 g O2 ------------------------ 1 mol O2
80.6 g O2 ------------------------- x
Solving for x, we'll have:
\(x=\frac{(80.6\text{ g O}_2)\times(1\text{ mol O}_2)}{(31.98\text{ g O}_2)}=2.52\text{ mol of O}_2\)There are 2.52 moles of O2 reacting and next we need to calculate the amount of heat absorbed considering this.
The molar enthalpy of O2 tells us how much heat is abosrbed when 1 mol of O2 reacts. Thus, we can use it to calculate the amount of heat absorbed when 2.52 moles of O2 react:
1 mol O2 ----------------------- 499.0 kJ
2.52 mol O2 ----------------- y
Solving for y, we'll have:
\(y=\frac{(2.52\text{ mol O}_2)\times(499.0\text{ kJ)}}{(1\text{ mol O}_2)}=1257.5\text{ kJ}\)Therefore, 1257.5 kJ of energy are absorbed when 80.6 g of O2 are reacting.
We can fill in the boxes to answer the question as it follows:
Answer: 1257.5
Units: kJ
Question 6 (0.04 points)
Read procedure page for electrical conductivity experiment. Which of the following
statement is correct?
A) Sugar (C12H22011) for sure will conduct electricity because it is a covalent
compound.
B) Even if alumina is insoluble in water. I will still test its conductivity.
© NaCl will conduct electricity because it is an ionic compound and it dissolves
in water.
Explain why the balls representing fluorine (teal) and hydrogen (white) have only one peg, while carbon (black) has four.
Answer:
Hydrogen and fluorine form only one bond while carbon forms four bonds to other atoms.
Explanation:
This question brings us to the idea of valency. Fluorine is univalent while carbon is tetravalent.
Univalent means that fluorine can only form one bond to hydrogen while carbon forms as much as four bonds because it is tetravalent.
Hence fluorine and hydrogen have only one peg while carbon has four.
Nitroglycerin, used both in medicine and as an explosive, can be prepared by the carefully controlled reaction of glycerol (C3H8O3) with nitric acid, as symbolized by: C3H8O3 + 3 HNO3 → C3H5N3O9 + 3 H2O What mass of nitric acid is required for the production of 2.8 g of nitroglycerin?
The mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g
We'll begin by calculating the mass of HNO₃ that reacted and the mass of C₃H₅N₃O₉ produced from the balanced equation. This can be obtained as follow:
C₃H₈O₃ + 3HNO₃ —> C₃H₅N₃O₉ + 3H₂O
Molar mass of HNO₃ = 1 + 14 + (16×3)
= 1 + 14 + 48
= 63 g/mol
Mass of HNO₃ from the balanced equation = 3 × 63 = 189 g
Molar mass of C₃H₅N₃O₉ = (12×3) + (1×5) + (14×3) + (16 × 9)
= 36 + 5 + 42 + 144
= 227 g/mol
Mass of C₃H₅N₃O₉ from the balanced equation = 1 × 227 = 227 g
SUMMARY:From the balanced equation above,
227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.
Finally, we shall determine the mass of HNO₃ that will produce 2.8 g of C₃H₅N₃O₉. This can be obtained as follow:
From the balanced equation above,
227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.
Therefore,
2.8 g of C₃H₅N₃O₉ will be produce by = \(\frac{2.8 * 189}{227} \\\\\) = 2.33 g of HNO₃
Thus, the mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g
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ano ang scientific method
Answer:
The scientific method is an empirical method of acquiring knowledge that has characterized the development of science since at least the 17th century. It involves careful observation, applying rigorous skepticism about what is observed, given that cognitive assumptions can distort how one interprets the observation.
ch4+br2 ch3br+hbr which type of reaction does this equation represent
To solve such this we must know the concept of combination reaction. Therefore, the given reaction CH\(_4\)+Br\(_2\) \(\rightarrow\)CH\(_3\)Br+ HBr is a combination reaction.
What is chemical reaction?Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.
CH\(_4\)+Br\(_2\) \(\rightarrow\)CH\(_3\)Br+ HBr
The above reaction is a combination reaction. In combination reaction, more than one reactant combine to form a product. Because new chemicals are created during combination reactions, they are often referred to as synthesis.
Therefore, the given reaction is a combination reaction.
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56.56
Two chemicals react in an endothermic reaction. What can be known about this reaction?
O The new substance will need more energy to form its chemical bonds than the old substance will release.
O More energy will be released from the old substance than the new substance will need to form its chemical bonds.
O A precipitate will form as a result of the reaction.
O A gas will form as a result of the reaction.
Answer:
it's a I took the test
Explanation
Answer:
A) The new substance will need more energy to form its chemical bonds than the old substance will release.
Explanation:
Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that [Sn2+]=0.0624 M, [Fe3+]=0.0437 M, [Sn4+]=0.00655 M, and [Fe2+]=0.01139 M. Standard reduction potentials can be found in this table.
Sn2+(aq)+2Fe3+(aq)↽−−⇀ Sn4+(aq)+2Fe2+(aq)
So far my incorrect answers have been:
0.28
0.798
0.178
0.142
0.881
0.61
and 0.812
Answer:
The cell potential for the given galvanic cell is 0.188 V.
Explanation:
To calculate the cell potential, we can use the Nernst equation:
Ecell = E°cell - (RT/nF)ln(Q)
where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.
First, we need to write the half-reactions and their standard reduction potentials:
Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V
Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V
The overall reaction is the sum of the half-reactions:
Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)
The reaction quotient Q can be expressed as:
Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2
Substituting the given concentrations, we get:
Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209
Now we can calculate the cell potential:
Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])
= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)
= 0.188 V
Therefore, the cell potential for the given galvanic cell is 0.188 V.
The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.
How to the cell potential of galvanic cell?To find the cell potential, we take the Nernst equation:
Ecell = E°cell - (RT/nF)ln(Q)
In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.
T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).
Firstly, write the half-reactions and then their standard reduction potentials:
Sn⁴⁺(aq) + 2e⁻ → Sn²⁺(aq) E°red = 0.15 V
Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V
The overall reaction is the sum of the half-reactions:
Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)
The Q reaction quotient can be written as:
Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²
Substituting the given concentrations, we observe:
Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209
Next, we can find the cell potential:
Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])
= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)
= 0.188 V
Thus, the cell potential for the given galvanic cell is 0.188 V.
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What is the PH for a solution that has an H+ ion concentration of 1.0x10^-6 M
Answer: POH=8
Explanation:PH = -log( H+concentration)
PH = 6
POH = 14 - PH = 8
Using energy efficiently and managing it well do not reduce society's impact on Earth.
True or False?
Answer:
False
Explanation:
Using less electricity will result in less fuel being burnt which will result in less fuel needing to be extracted from the earth which will reduce society's impact on earth.
If the caffeine concentration in a particular brand of soda is 2.99 mg/oz, drinking how many cans of soda would be lethal? Assume 10.0 grams of caffeine is a lethal dose, and they are 12 oz in a can
If the caffeine concentration in a particular brand of soda is 2.99 mg/oz, drinking, The number of cans of soda would be lethal is 258 cans.
What is caffeine ?Caffeine is a stimulant. In the brain, it blocks the effects of a chemical called adenosine, which makes you feel sleepy. we then feel more alert and energetic, which is why many people drink soda, coffee or tea to stay awake. Caffeine may keep you awake even if you don't want it to
Given
1000 mg = 1 g10.0 g= 10 000 mgv = 10 000/3.23 =3095.96 oz
Therefore,
Number of cans = 3095.96 /12 =258 cans
If the caffeine concentration in a particular brand of soda is 2.99 mg/oz, drinking, The number of cans of soda would be lethal is 258 cans.
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You are standing outside in a rural area at night, looking up to the sky and observe many stars. If you were to look up to the sky in the city on that exact same night, what would you observe? (2 points)
Group of answer choices
That only the street lights shine in the sky
That there appears to be little to no stars in the sky
That there appears to be many stars in the sky
Answer:
That there appears to be many stars in the sky
Explanation: hope this helps! <33333
Ganciclovir is used to treat cytomegalovirus, a deadly viral infection common in immunocompromised patients. The doctor places an order for a dose of 2.5 mg/kg of body weight. What dose will the nurse administer for a 141 lb patient?
A. 160 mg
B. 56.4 mg
C. 352 mg
D. 124 mg
Answer:
A.160mgs
Explanation:
First you convert the lbs to kgs, 141lbs=63.957kgs
then you divide 63.957kgs by 2.5 which is 159.89
round up to 160, 160mgs is the correct dosage.
The dose that will the nurse administers for a 141 lb patient is 160mgs. The correct option is A.
What is a virus?
A virus is an entity that is only become alive when it gets a living host. It takes survives in its host and affects the body of the host. They are microorganisms that can not be seen by direct eyes. Viruses are harmful microorganisms. They are very deadly and they transmit through breath.
Medication, contain treatment that includes drugs and therapies to recover the patient from the disease. It is a proper process that includes timely procedures.
First, you convert the lbs to kgs, 141lbs = 63.957kgs
Then you divide 63.957 kgs by 2.5 which is 159.89 round up to 160, 160mgs is the correct dosage.
Thus, the correct option is A. 160 mg.
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15.2 grams of CO2 = ? molecules of CO2
Answer:
2.11 molecules of CO₂
Explanation:
Given data:
Mass of CO₂ = 15.2 g
Molecules of CO₂ = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 15.2 g/ 44 g/mol
Number of moles = 0.35 mol
Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ molecules
0.35 mol × 6.022 × 10²³ molecules / 1 mol
2.11 molecules of CO₂
Fructose consists of 40.002% Carbon, 6.714% Hydrogen, and 53.285% oxygen. The molecular mass of fructose is 180.156 g/mol. Determine the empirical and molecular formulas for fructose.
Answer:
Below
Explanation:
For Carbon:
40.002 % * 180.156 = 72.066 gm/mole C per mole of fructose
For Hydrogen:
6.714 % * 180.156 = 12.096 gm H
For Oxygen:
53.285% * 180.156 = 95.966 gm of O
Now use periodic table to find mole wts of each
72.066 / 12.011 = 6 moles of C per mole of fructose ( wt = 12.011)
12.096/ 1.008 = 12 moles of H (wt = 1.008)
95.966/15.999 = 6 moles of O (wt = 15.999)
C6 H12 O6 is MOLECULAR formula divide everything by 6
C H2 O is EMPIRICAL
You are comparing a reaction that produces a chemical change and one that prouduces a physical change. What evidence could you use to determine wich type of change is occurring?
Answer: If the reaction is a chemical change, new substances with different properties and identities are formed. This may be indicated by the production of an odor, a change in color or energy, or the formation of a solid.
hope it helps!!
You come across the following container while working in the lab: Answer the following questions in the space below: 1. Identify the WHMIS symbols. 2. What precautions should you take and why?
Type #1 Flame symbols are among the WHMIS emblems.
Type 2: Symbols with a flame above a circle.
Exploding bomb symbols are of type 3.
Compressed gas symbols are of type 4.
Corrosion symbols are type #5.
Skull and water the water symbols are type #6.
Exclamation mark symbols are type #7.
Health hazard symbols are type #8.
Because workplaces require a defined technique to detect hazardous items, WHMIS labels are crucial.
What does the WHMIS stand for?The national ’s hazard standard for Canada is the Health And Safety At work System (WHMIS). Hazard categorization, cautionary container labeling, the distribution of safety data sheets, and worker information and training programs are the system's main components.
What does WHMIS look like in the US?The U.S. Ohs Hazard Identification Standard and WHMIS are quite similar.
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When a liquid is insoluble in another liquid, the liquids are said to be?
Answer:
immiscible
Explanation:
26.What is the usual oxidation number of the lithium ion?Select one:a. -2b. -1c. +1d. +2
ANSWER
The usual oxidation state of lithium is +1
EXPLANATION
Lithium is a group 1 metal with an atomic number of 3. Its electronic configuration of lithium atom is written below as
\(\text{ }_3\text{Li }\rightarrow\text{ 1s}^22s^1\)In the above configuration, lithium has one electron in its outermost shell. Hence, the valence of electron is 1
During chemical reaction, lithium will lose an electron to attain it octet structure and it will attain the electronic configuration of Helium
Since it will be losing one electron, therefore it usual oxidation number is +1u
Which bond links amino acids together?
glycosidic bond
hydrogen bond
phosphodiester bond
peptide bond
Answer:
Peptide Bonds
Explanation:
Peptide bonds are formed by a biochemical reaction that extracts a water molecule as it joins the amino group of one amino acid to the carboxyl group of a neighboring amino acid.
most abundant alkali metal
What is the rate constant at 700C?
The rate constant at 700°C is not a constant value and will depend on the specific reaction and the reactant concentrations.
What is constant value?A constant value is a fixed value that does not change. It is often used in mathematics and computer programming. Constant values are also used to represent physical quantities that do not vary, such as the speed of light or the mass of a proton. Constant values can be used as part of an equation, or as a comparison point for a variable. They are often used as a reference point in equations, or to make calculations simpler. Constant values can also be used to represent a fixed amount of something, such as a set fee or a fixed number of items. Constant values can help ensure the accuracy of calculations and ensure that the results are consistent.
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If the NaOH is added to 35.0 mL of 0.167 M Cu(NO3)2 and the precipitate isolated by filtration, what is the theoretical yield of the reaction?
Answer:
The correct answer is - 0.570 grams
Explanation:
The balanced chemical reaction is given by
Cu(NO3)2(aq) + 2NaOH(aq) --------> Cu(OH)2(s) + 2NaNO3(aq)
1.0 mole 2.0 mole 1.0 mole 2.0 mole
number of mol of Cu(OH)2,
n = Molarity * Volume
= \(35.0*0.167 = 5.845\) millimoles
As clear in the equation, 1 mole of Cu(NO3)2 gives 1 mole of Cu(OH)2 , So, 5.845 millimoles of Cu(NO3)2 will produce 5.845 millimoles of Cu(OH)2
Mass of Cu(OH)2 = number of mol * molar mass
= \(97.5*5.845*10^-3\)
= 0.570 grams
Thus, the correct answer is - 0.570 grams
Position of metals in reactivity series does not determine the.
A rate of polarization
B. duration light bulb will glow
C. brightness of light
D. nature of bonding
Answer: D. nature of bonding
Explanation:
Done it got 100
Answer:
Explanation:the answer is d
Why are chromosomes important? They play a role in cell division. They pass molecules through the nucleus. They produce food for a plant cell. They provide energy to the cell.
Chromosomes important because they play a role in cell division.
What is cell division?Cell division is described as the process by which a parent cell divides into two daughter cells and usually occurs as part of a larger cell cycle in which the cell grows and replicates its chromosome before dividing.
Chromosomes has another function of ensuring that each new cell receives a complete set of genetic information which is required for proper cell function and development.
In conclusion, there are two types of cell division which are mitosis and meiosis.
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Can you explain in detail how anion exchage occur in soil.
Answer:
With the adsorption of cations like zinc as Zn (OH)+ or ZnCl+ or both, the anion exchange is known to increase. The solid phase has an impact on the anions' concentration in the soil solution. Anions are negatively adsorbed as a result of the exchange complex's overall negative charge.
Correctly write the chemical formula for as many ions and compounds as you can:
1. Copper (11) ion
2. Bromide ion
3. Magnesium ion
4. Phosphide ion
5. Copper (11) Bromide
6. Sulfur Dichloride
7. Barium Fluoride
8. Magnesium Phosphate
9. Lithium Permanganate
10. Strontium Sulfite
11. Nitrogen Monoxide
12. Diselenium Tetraoxide
13. Aluminum Sulfide
14. Tin (IV) lodide
15. Beryllium Oxide
16. Potassium Hydroxide
The chemical formulas for the ions and compounds you listed:
Copper (II) ion: Cu²⁺
Bromide ion: Br⁻
Magnesium ion: Mg²⁺
Phosphide ion: P³⁻
Copper (I) Bromide: CuBr
Sulfur Dichloride: SCl₂
Barium Fluoride: BaF₂
Magnesium Phosphate: Mg₃(PO₄)₂
Lithium Permanganate: LiMnO₄
Strontium Sulfite: SrSO₃
Nitrogen Monoxide: NO
Diselenium Tetraoxide: Se₂O₄
Aluminum Sulfide: Al₂S₃
Tin (IV) Iodide: SnI₄
Beryllium Oxide: BeO
Potassium Hydroxide: KOH
Copper (II) ion: Cu²⁺
Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.
Bromide ion: Br⁻
The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.
Magnesium ion: Mg²⁺
The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.
Phosphide ion: P³⁻
The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.
Copper (I) Bromide: CuBr
Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.
Sulfur Dichloride: SCl₂
Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.
Barium Fluoride: BaF₂
Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.
Magnesium Phosphate: Mg₃(PO₄)₂
Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.
Lithium Permanganate: LiMnO₄
Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.
Strontium Sulfite: SrSO₃
Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.
Nitrogen Monoxide: NO
Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.
Diselenium Tetraoxide: Se₂O₄
Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.
Aluminum Sulfide: Al₂S₃
Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "
2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.
Tin (IV) Iodide: SnI₄
Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.
Beryllium Oxide: BeO
Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.
Potassium Hydroxide: KOH
Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.
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