How many atoms are there in 14.3 g of xenon?

Answer:

d)Gas syringe and stopclock

Explanation:

Gas syringe is used to measure the volume of gas collected

Stopclock is used to measure the time taken to produce a certain amount of gas thus the rate of reaction:volume vs time can be determined

A first-order reaction is a chemical reaction where the reaction rate depends directly on the concentration of only one of the reactants. The calculated rate constant at 40.1°C was 1.74 s^(-1)

The first-order reaction's reaction rate, k, is calculated using the following equation: ln[A]t = -kt + ln[A]0, where [A]t is the reactant concentration at time t,[A]0 is the reactant concentration at time zero,k is the rate constant in inverse seconds, and t is time. Using the Arrhenius equation, it is possible to calculate the rate constant for a first-order reaction at a different temperature if the rate constant at one temperature is known. The Arrhenius equation is given by:k = Ae^(-Ea/RT), where A is the frequency factor or pre-exponential factor, Ea is the activation energy, R is the universal gas constant, and T is the temperature in Kelvin. We can rearrange the Arrhenius equation to calculate the rate constant for a different temperature:lnk2/k1 = Ea/R × (1/T1 - 1/T2).Substituting the given values,k1 = 0.253, Ea = 91.8 kJ/mol,T1 = 25°C = 298 K,andT2 = 40.1°C = 313.1 K.We can now solve for k2:k2 = k1 × e^(Ea/R × (1/T1 - 1/T2))= 0.253 × e^(91.8 × 10^3 J/mol × (1/(8.314 J/molK) × (1/298 K - 1/313.1 K)))= 1.74 s^(-1).Therefore, the rate constant at 40.1°C is 1.74 s^(-1).

First-order reactions are characterized by their kinetics, which follows a relatively simple pattern. They rely on just one reactant's concentration to determine their rate. They have a mathematical relationship with their rate law, and their half-life is constant over time. The rate constant for a first-order reaction is calculated using the following equation: ln[A]t = -kt + ln[A]0, where[A]t is the reactant concentration at time t,[A]0 is the reactant concentration at time zero,k is the rate constant in inverse seconds, and t is time. The Arrhenius equation is used to calculate the rate constant for a first-order reaction at a different temperature if the rate constant at one temperature is known. The Arrhenius equation is given by:k = Ae^(-Ea/RT), which is the frequency factor or pre-exponential factor, E a is the activation energy, R is the universal gas constant, and T is the temperature in Kelvin. The rate constant for a first-order reaction was given in the problem statement as 0.253 s^(-1) at a temperature of 25°C. The activation energy was also given as 91.8 kJ/mol. We used the Arrhenius equation to calculate the rate constant at a temperature of 40.1°C. The calculated rate constant at 40.1°C was 1.74 s^(-1)

A first-order reaction is a chemical reaction where the reaction rate depends directly on the concentration of only one of the reactants. We calculated the rate constant for a first-order reaction at a different temperature using the Arrhenius equation. We used the given values of the rate constant and activation energy to calculate the rate constant at a different temperature. The calculated rate constant at 40.1°C was 1.74 s^(-1).

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Answeeeeer:

 A. cell

Explanation:

Since A is the smallest in the chart, that would correspond to the cell because thats the smallest out of Tissue, Organ and Organism.

Answer:

1) 7.256 mol Br2 (Cl2)/(Br2)

The Br2 cancels out, so we have 7.256(2)

This is 14.512.

2) Number of moles = mass / molar mass

Number of moles = 239.7 g/ 35.5 g/mol

Number of moles =  6.8 mol

BrCl=13.6 mol

13.6(11.5.357)

1568.9 g

3) Repeat the same process with problem 2, given that there are 6.022x10^23 atoms in a mole.

Explanation:

Br2 + Cl2 → 2BrCl

Answer:

ΔE  = 13.056 ev

Explanation:

Energy associated with nth state is,

En =  -13.6/n²

For n = 1

E₁ = -13.6 / 1²

E₁ = -13.6/1

E₁ = -13.6 ev

Kinetic energy of electron = -E₁ = 13.6 ev

For n = 5

E₅ = -13.6 / 5²

E₅ = -13.6/25

E₅ = -0.544 ev

Kinetic energy of electron = -E₅ = 0.544 ev

Wavelength of radiation emitted:

ΔE = hc/λ = E₅ - E₁

by putting values,

ΔE  = -0.544ev  - (-13.6 ev  )

ΔE  = 13.056 ev

The statement that best describes a scatterplot is that it shows quantitative data that relate two variables (option C).

A scatter plot is a type of graph that displays the relationship between two variables.

The scatter plot is portrayed on a cartesian plane where one of the variables is on an axis called X-axis and the other is on another axis called y-axis.

One of the variables is the independent variable while the other variable is the dependent variable.

Therefore, the statement that best describes a scatterplot is that it shows quantitative data that relate two variables.

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Answer:

A = water has high surface tension

the answer is a hope this helps and plz give me brainlist :)

Answer:

A) Metallic bonding

Explanation:

In metallic bonding, electrons exists as "sea of electrons" which means similar to how waves are free to go anywhere in ocean, these electrons are free to roam around the crystal of the metal.

There would be an increase in the concentration of carbonic acid - this is how an increase in carbon dioxide concentration influences the system.

In chemistry, a dynamic equilibrium lives once a reversible reaction occurs. Substances transition between the reactants and products at equal rates, indicating there is no net change. Reactants and products exist formed at such a rate that the concentration of neither changes. It is a precise example of a system in a steady state. After a time, a reversible reaction in a closed system can get what we call a dynamic equilibrium.

The correct answer is option D.

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sodium hydroxide

cobalt (II) phosphide

lead (IV) carbonate

Magnesium fluoride

lithium sulfite

ammonium phosphate

iron (II) oxide

calcium sulfate

silver nitride

sodium sulfide

The Ksp of AgOH will be "1.98×10^-8"

According to the question,

The chemical reaction is:

AgOH + HCl → AgCL(s) + H2O

As we know the relation,

C₁V₁ = C2V2

(AgOH) (HCI)

By substituting the values, we get

C₁ x 250 mL = 0.0136 × 2.60 mL

C1 = 0.0136×2.60/250 = 0.000141

Now,

AgOH = Ag + OH

AgOH = Ag + OH (s) (s)

hence, The Ksp will be: (s)^2 = (0.000141)² =

1.98 x 10^-8

The Ksp of AgOH will be 1.98×10^-8

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Explanation:

To change from m to cm, divide by 100

\( \frac{98.723}{100} \\ = \: 0.98723cm\)

Answer:

Water is a compound. It contains more than one element

water is homogeneous

Explanation:

water is a compound

water is heterogeneous

The claim that vinyl gloves have a higher leak rate than latex gloves is supported by the study at a significance level of 0.005.

To determine if vinyl gloves have a higher leak rate than latex gloves, we can conduct a hypothesis test.

The z-value is calculated as:

z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))

where p₁ and p₂ are the sample proportions, and n₁ and n₂ are the sample sizes.

Certainly! Let's calculate the z-value to determine if vinyl gloves have a higher leak rate than latex gloves.

For vinyl gloves:

Sample size (n₁) = 240

Leaking gloves (x₁) = 0.63 * 240 = 151.2 (approximated to 151)

For latex gloves:

Sample size (n₂) = 240

Leaking gloves (x₂) = 0.07 * 240 = 16.8 (approximated to 17)

We will calculate the z-value using the formula:

z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))

where p₁ and p₂ are the sample proportions.

p₁ = x₁ / n₁ = 151 / 240 ≈ 0.629

p₂ = x₂ / n₂ = 17 / 240 ≈ 0.071

Calculating the z-value:

z = (0.629 - 0.071) / √((0.629 * (1 - 0.629) / 240) + (0.071 * (1 - 0.071) / 240))

z ≈ 13.239

The calculated z-value is approximately 13.239. To determine if the claim is supported, we compare this value to the critical z-value for a one-tailed test at a significance level of 0.005.

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Approximately 779.33 grams of sodium peroxide would be needed per sailor in a 24-hour period, considering the given rate of CO2 exhaled by the sailor.

To calculate the mass of sodium peroxide needed per sailor in a 24-hour period, we need to determine the number of moles of CO2 produced by the sailor and then use the stoichiometry of the reaction between sodium peroxide (Na2O2) and CO2 to find the corresponding amount of sodium peroxide.

First, let's calculate the number of moles of CO2 produced per minute by the sailor using the ideal gas law:

PV = nRT

Where:

P = pressure (0.830 atm)

V = volume (137.5 mL or 0.1375 L)

n = number of moles of CO2 (to be determined)

R = ideal gas constant (0.0821 L·atm/(K·mol))

T = temperature (23.5°C or 296.65 K)

Rearranging the equation, we have:

n = PV / RT

n = (0.830 atm) × (0.1375 L) / (0.0821 L·atm/(K·mol)) × (296.65 K)

n ≈ 0.00697 moles CO2/min

To find the total moles of CO2 produced in a 24-hour period, we multiply this value by the number of minutes in 24 hours:

Total moles of CO2 = (0.00697 moles CO2/min) × (24 hours × 60 minutes/hour)

Total moles of CO2 ≈ 10.018 moles CO2

Now, let's determine the stoichiometry of the reaction between sodium peroxide (Na2O2) and CO2:

2 Na2O2 + 2 CO2 → 2 Na2CO3 + O2

According to the balanced equation, two moles of sodium peroxide react with two moles of CO2.

Therefore, the number of moles of sodium peroxide required is equal to the number of moles of CO2 produced:

Moles of Na2O2 = Total moles of CO2 ≈ 10.018 moles CO2

Finally, to calculate the mass of sodium peroxide, we need to multiply the moles of Na2O2 by its molar mass, which is 77.98 g/mol:

Mass of Na2O2 = Moles of Na2O2 × Molar mass of Na2O2

Mass of Na2O2 ≈ 10.018 moles × 77.98 g/mol

Mass of Na2O2 ≈ 779.33 g

Therefore, approximately 779.33 grams of sodium peroxide would be needed per sailor in a 24-hour period, considering the given rate of CO2 exhaled by the sailor.

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Answer:

2.5

Explanation:

you round up because the numbers behind the tenth spot is above 5

Answer:

2.5 gram

Explanation:

2.498

2.50

I rounded there 9 to 0 and put the 4 to 5 so it is 2.50

Answer:

Evaporation

Explanation:

Students are to mix the solvent to dilute completely,and get and evaporation dish,candle(heat),tripod stand...pour the solution in the evaporation dish and place it on tripod stand above the candle wait for some time the water will change into gas and to get the water they have to cover the evaporating and direct it to a different container to get the water and salt

As the solution turns yellow when re cabbage juice indicator  is added it implies that its base solution so the color of the  solution when hibiscus flower juice added is dark grey to green.

when hibiscus indicator added Anywhere from dark pink to pale pink usually indicates an acid, while dark gray to green colors usually indicate a base.

Dark blue should be the color of  red cabbage indicator. The cabbage indicator's color will shift to red or pink if the solution is an acid, and to green or yellow if the solution is a base. In the event that the test solution is neutral, it will stay purple or blue

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Ammonium Nitrate NH₄NO₃ has greatest % of nitrogen by mass than Ammonium Phosphate (NH₄)₃PO₄.

Two compounds are given, one is Ammonium Nitrate NH₄NO₃ and the other is Ammonium Phosphate (NH₄)₃PO₄.

The mass of Nitrogen is 14 g/mol. The mass of Oxygen is 16 g/mol. The mass of Phosphorous is 31 g/mol. The mass of Hydrogen is 1 g/mol.

Now, calculating the mass of Ammonium Nitrate NH₄NO₃,

Mass = 14+(4x1)+14+(3x16)

Mass = 80 g/mol.

% Nitrogen in Ammonium Nitrate = 14/80 x 100

% Nitrogen in Ammonium Nitrate = 17.5%.

The mass of Ammonium Phosphate (NH₄)₃PO₄,

Mass = 3[14 + (4x1)]+31+(4x16)

Mass = 149 g/mol.

% Nitrogen in Ammonium Phosphate = 14/149 x 100

% Nitrogen in Ammonium Phosphate = 9.39%.

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My idea about what happens to molecules in the liquid, solid, and gas

phase hasn't changed.

State of matter is the state in which particles exist in nature and there are

three main forms which include:

The phases experiences some form of inter-conversion under various

conditions which include:

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Answer:

Density 0.97 g.cm -3 at 20 °C

Melting point 97.5 °C

Boiling point 883 °C

oxidation states +1, −1 (rare)

Explanation:

Have a nice day

The work done during the combustion of 1.0 mol of octane is 10.2 kJ.

The work done during the combustion of a substance is equal to the change in internal energy minus the change in heat energy. Since we are dealing with 1.0 mol of octane at a pressure of 1.0 atm, we can calculate the change in internal energy as 5084.3 kJ.

The change in heat energy is given as 5074.1 kJ. We can calculate the work done during the combustion using the formula W = ΔU - ΔH. Substituting the values we get W = 5084.3 - 5074.1 = 10.2 kJ. This is the work done during the combustion of 1.0 mol of octane at a pressure of 1.0 atm.

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The complete question:

The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is 5084.3 kJ. If the change in heat energy is 5074.1 kJ, how much work is done during the combustion?

Answer:

To be stable an atom will gain, lose, or share electrons to complete the outer most energy level (electron shell). Octet Rule because levels 2 and 3 need 8 electrons to be stable.

For Brackett series, all transitions take place from higher levels to  n = 4 level. 6.85× 10 5 m−1.

Thus, The Brackett series is a collection of emission lines from atomic hydrogen gas that result from electrons moving from electron shells with n > 4 to those with n = 4, or equivalent absorption lines when absorbed electromagnetic radiation (EMR) causes the opposite to happen.

It is a member of the hydrogen line series, which also includes the Lyman and Balmer series, and bears Frederick Sumner Brackett's name.

Johann Balmer made the initial discovery of the series in the year 1885. As a result, the series bears his name. When an electron transitions from a higher energy level (nh=3,4,5,6,7,...) to an energy state with nl=2, the Balmer series is seen.

Thus, For Brackett series, all transitions take place from higher levels to  n = 4 level. 6.85× 10 5 m−1.

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Answer

50 N

Explanation

Answer:

66 km.

Explanation:

88 km / 1 hour = 66 km / 0.75 hours.

You need to just multiply 0.75 by 88.

The answer is 66 km.

Reaction appears to get heavier as molar mass of Magnesium oxide is more than the molar mass of reactants.

Molar mass: It is defined as the sum of atomic mass of each atom in a molecule or compound. If its only an element, then molar mass is same as the atomic mass of that element.

Calculate the molar mass of Magnesium oxide.

\(Molar\ mass\ of\ MgO = Atomic\ mass\ of\ Mg\ +Atomic\ mass\ of\ O\= = 24.305\ g/mol + 16.000\ g/mol\\ Molar\ mass\ of\ MgO = 40.305\ g/mol\)

\(2Mg + O_{2}\)→\(2MgO\)

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