How many atoms are in 1.52 moles of strontium

There may be be more than one model describing the same thing because it helps an individual to fully understand an object or system.

This is referred to as a physical and/or mathematical and/or conceptual representation of a system of ideas, events or processes.

In other to fully understand an object or system, multiple models which represents a part of the object or system are important as it helps to provide a real understanding of the subject in view.

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Answer:

picture

Explanation:

i need the picture

we need a picture to

answer this sire

From the first law of thermodynamics, the work done is -36 J.

We are told that the gas is expanding hence it does work while heat is absorbed from the surroundings. This implies that q is positive while w is negative.

Hence;

U = q - w

w = q - U

w =  89J - 125J

w = -36 J

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There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.

The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.

Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:

Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)

Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2

Moles of Al3+ = 0.84 mol Al3+

Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.

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There would 30 g of Pu-239 after the first half life and 7.4 g of Pu-239 after the third half life.

We have to remind ourselves that radioactivity is defined as the process in which there is a spontaneous disintegration of a substance. Now we know that the time that is taken for only half of the original radioactive material that was present in the substances to remain is the half life of the radioactive material.

In accordance with the law of conservation of mass, mass is neither created nor destroyed when we have a radioactive process. As such the nucleus as it is disintegrated forms daughter nuclei in which way mass is not lost.

In this case, we are told that  I start out with 60 g of Pu-239. At the end of one half life, I would have 30 g of Pu-239 and at the end of three half lives, I will have 7.5 g of Pu-239.

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The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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Answer:

The d-block and transition metal are not interchangeable terms because the d-block elements are a subset of the transition metal elements. The transition metals are defined as the elements that have partially filled d orbitals, which includes the d-block elements as well as other elements that have partially filled d orbitals in other blocks, such as lanthanides and actinides. Therefore, while all d-block elements are transition metals, not all transition metals are d-block elements.

Answer:

1.30

Explanation:

The neutralization reaction involved in the titration is:

HClO₄(aq) + KOH(aq) → KClO₄(aq) + H₂O(l)

According to the chemical equation,

1 mol of HClO₄ reacts with 1 mol of KOH (1 equivalent of acid with 1 equivalent of base). The moles are calculated from the product of the molar concentration (M) and the volume in liters.

We have the following moles of acid (HClO₄):

40.0 mL x 1 L/1000 mL = 0.04 L 0.200 mol/L x 0.04 L = 8 x 10⁻³ moles HClO₄

Since HClO₄ is a strong acid (completely dissociated into H⁺ and ClO₄⁻ ions), the moles of HClO₄ are equal to the moles of H⁺.

Then, we can calculate the initial pH:[H⁺] = 0.200 M → pH = -log [H⁺] = -log (0.200) = 0.70

Now, we calculate the pH after the addition of KOH. Since KOH is a strong base, the concentration of KOH is equal to the concentration of OH⁻ ions.

a) 0.0 mLNo KOH is added, so the pH is the initial pH:

0.70

b) 80.0 mL KOH80.0 mL x 1 L/1000 mL = 0.08 L0.100 mol/L x 0.08 L = 8 x 10⁻³ moles KOH = 8 x 10⁻³ moles OH⁻

After neutralization we have: 8 x 10⁻³ moles H⁺ - 8 x 10⁻³ moles OH⁻ = 0The neutralization reaction is complete and there is no remaining H⁺ from the acid.

The concentration of H⁺ is equal to the concentration of H⁺ of water:

[H⁺] = 1 x 10⁻⁷ M → pH = -log [H⁺] = -log (1 x 10⁻⁷) = 7.0

c) 10.0 mL KOH10.0 mL x 1 L/1000 mL = 0.01 L0.100 mol/L x 0.01 L = 1 x 10⁻³ moles KOH = 1 x 10⁻³ moles OH⁻

After neutralization we have: 8 x 10⁻³ moles H⁺ - 1 x 10⁻³ moles OH⁻ = 7 x 10⁻³ moles H⁺

The total volume is:

V = 40.0 mL + 10.0 mL = 50 mL = 0.05 L[H⁺] = 7 x 10⁻³ moles/0.05 L = 0.14  → pH = -log [H⁺] = -log (0.14) = 0.85

d) 100.0 mL KOH100.0 mL x 1 L/1000 mL = 0.1 L0.100 mol/L x 0.1 L = 0.01 moles KOH = 1 x 10⁻² moles OH⁻

After neutralization we have:

1 x 10⁻² moles OH⁻ - 8 x 10⁻³ moles H⁺ = 2 x 10⁻³ moles OH⁻

The total volume is:

V = 40.0 mL + 100.0 mL = 140 mL = 0.14 L[OH⁻] = 2 x 10⁻³ moles/0.14 L = 0.014  → pOH = -log [OH⁻] = -log (0.014) = 1.84pH + pOH = 14 → pH = 14 - pOH = 14 - 1.84 = 12.15

e) 40.0 mL KOH40.0 mL x 1 L/1000 mL = 0.04 L0.100 mol/L x 0.04 L = 4 x 10⁻³ moles KOH = 4 x 10⁻³ moles OH⁻

After neutralization we have: 8 x 10⁻³ moles H⁺ - 4 x 10⁻³ moles OH⁻ = 4 x 10⁻³ moles H⁺

The total volume is:

V = 40.0 mL + 40.0 mL = 80.0 mL = 0.08 L[OH⁻] = 4 x 10⁻³ moles/0.08 L = 0.05 M  → pH = -log [H⁺] = -log (0.05)

= 1.30

Answer:

childhood trauma.

Explanation:

I took the test and the answer i got correct was Childhood trauma.

a. The rate law for this reaction is: Rate = k[Cl] [H₂]. This means that the rate of the reaction is directly proportional to the concentrations of both Cl and H₂ molecules.

Rate law is an equation that describes the rate of a chemical reaction as a function of the concentrations of reactants. The rate law allows us to describe how the rate of a reaction changes when the concentrations of reactants are changed. It is derived from the rate equation, which is a mathematical expression that can be used to calculate the rate of a reaction from the concentrations of the reactants and the rate constant.

b. The rate law for this reaction is: Rate = k[O] [Os]. This means that the rate of the reaction is directly proportional to the concentrations of both O and Os molecules.
c. The rate law for this reaction is: Rate = k[NO₂]₂. This means that the rate of the reaction is directly proportional to the square of the concentration of NO₂ molecules.

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Complete Question:

The equation for the equilibrium constant (K) of the reaction studied in this exercise can be written as follows: K = ([\(CI_20\), 2-] * [\(H_20\)(1)]) / ([\(C0_4^ 2\)-] * [Ht])

In this equation, the concentrations of the species involved in the reaction are represented by the square brackets [ ]. The subscripts indicate the stoichiometric coefficients of each species in the balanced chemical equation.

The reaction being studied involves the following species:

\(C0_4^ 2\)- (ag) + 2Ht (ag) = \(CI_20\), 2- (ag) + \(H_20\)(1)

In the equilibrium constant expression, the concentration of \(CI_20\), 2- is multiplied by the concentration of \(H_20\)(1) and divided by the product of the concentrations of \(C0_4^ 2\)- and Ht. The stoichiometric coefficients in the balanced equation are used as exponents for the concentrations of the respective species.

It is important to note that the concentrations used in the equilibrium constant expression should be in molar units (mol/L) or expressed as partial pressures for gases.

Additionally, the equilibrium constant is specific to a given temperature, and its value provides information about the relative amounts of reactants and products at equilibrium.

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\(\implies\) The correct answer is (B) 0.00037

\(\bf{ \underline{Step \: 1)} :3.7 × 10^{-4 }we \: can \: write \: as \:37 × 10^{-5}}\)

\(\bf{ \underline{Step \: 2)} :37 × 10^{-5 } \: we \: can \: write \: as \: 37 × \frac{1}{10^5}}\)

\(\bf{ \underline{Step \: 3)} :37 × \frac{1}{10^5}\: we \: can \: write \: as \: (37 × \frac{1}{(10)(10)(10)(10)(10)}})\)

\(\bf{ \underline{Step \: 4)} :37 × \frac{1}{(10)(10)(10)(10)(10)} we \: can \: write \: as \: ( 37 × \frac{1}{100000}})\)

\(\bf{ \underline{Step \: 5)} :37 × \frac{1}{100000} \: we \: can \: write \: as \: \frac{37}{100000}}\)

\(\bf{ \underline{Step \: 6)} :\frac{37}{100000} \: we \: can \: write \: as \: 0.000037}\)

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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When investigative officers get to a crime scene, they do not need to collect water samples.

A crime scene is a place where an offence has been committed. It is usually cordoned off to enable investigation of the crime and the collection of samples.

When investigative officers get to a crime scene, they do not need to collect water samples.

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Answer:A

Explanation:.

Answer:

Water forms more hydrogen bonds than HF

Explanation:

The answer to this question goes back to the idea of hydrogen bonding. Hydrogen bonding occurs when hydrogen is bonded to a highly electronegative atom such as fluorine or oxygen.

However, in HF, there are three lone pairs of electrons on fluorine atom and one hydrogen atom bonded to fluorine.

In H2O, there are two lone pairs of electrons on oxygen atom and two hydrogen atoms bonded to oxygen. This simply means that water can form four hydrogen bonds while HF only forms two hydrogen bonds.

This implies that H2O molecules possess more hydrogen bonding than HF molecules. Hence, the molar enthalpy of vaporization for liquid hydrogen fluoride is lesser than that for water.

HCN, Na2SO4: Combination of compounds.

Mg3N2: Chemical compound.

CO2, H2O: Dissolution or hydration reaction.

Cu, Zn(NO3)2: Single-replacement reaction.

Na, N2: Combination of elements.

Let's analyze each chemical combination to determine the type of reaction involved:

HCN, Na2SO4:

The combination of hydrogen cyanide (HCN) and sodium sulfate (Na2SO4) does not represent a specific chemical reaction. It is simply the combination of two compounds.

Mg3N2:

Mg3N2 represents a chemical compound, magnesium nitride. It does not indicate a specific reaction.

CO2, H2O:

The combination of carbon dioxide (CO2) and water (H2O) represents a chemical reaction known as hydration or dissolution. When carbon dioxide dissolves in water, it forms carbonic acid (H2CO3), which can further dissociate into hydrogen ions (H+) and bicarbonate ions (HCO3-).

Cu, Zn(NO3)2:

The combination of copper (Cu) and zinc nitrate (Zn(NO3)2) represents a single-replacement reaction. Copper displaces zinc from the compound, resulting in the formation of copper nitrate (Cu(NO3)2) and zinc metal (Zn).

Na, N2:

The combination of sodium (Na) and nitrogen gas (N2) does not represent a specific reaction. It is simply the combination of two elements.

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Hey there!

Mass = ?

volume = 105 mL

Density = 2.26 g/mL

Therefore:

D = m / V

2.26 = m / 105

m = 2.26 * 105

m = 237.3 g

Hope this helps!

Answer: Less

Explanation:

Ethane is a non-polar molecule while water is a polar molecule

The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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Answer:

Explanation:

The pH of 0.02 M hydrochloric acid is approximately 1.7.

THANKS

IF THE ANSWER IS CORRECT , THEN MARK ME AS BRAINLIST

Explanation:

s=2

p=6

d=10

f=14

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Answer:

Explanation:

Molal freezing point depression constant of butanol Kf = 8.37⁰C /m

ΔTf = Kf x m , m is no of moles of solute per kg of solvent .

mol weight of butanol = 70 g

235.1 g of butanol = 235.1 / 70 = 3.3585 moles

3.3585 moles of butanol dissolved in 4.14 kg of water .

ΔTf = 8.37 x 3.3585 / 4.14

= 6.79⁰C

Depression in freezing point = 6.79

freezing point of solution = - 6.79⁰C .

You would recover 36.525g of NaCl after evaporating all of the water.

To find the grams of NaCl that would be recovered after evaporating all the water, we can use the following formula:

mass = moles * molar mass

Where:

Moles = Molarity * Volume

Molarity = 0.250 M

Volume = 2500.0 mL = 2.5 L

Molar mass of NaCl = 58.44 g/mol

mass = 0.250 M * 2.5 L * 58.44 g/mol

mass = 36.525 g

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The correct answer is A.

The nuclear equation that correctly characterizes a nuclear reaction is one where the sum of the atomic numbers and the sum of the mass numbers on both sides of the equation are equal.

\(_{92}^{235}\textrm{U}+_{0}^{1}\textrm{n}\rightarrow _{54}^{140}\textrm{Xe}+_{38}^{94}\textrm{Sr}+3_{0}^{1}\textrm{n}\)

         \(_{92}^{235}\textrm{U}+_{0}^{1}\textrm{n}\rightarrow _{54}^{140}\textrm{Xe}+_{38}^{94}\textrm{Sr}+3_{0}^{1}\textrm{n}\)

The correct answer is A.

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Explanation:

45.8 grams of Fe2O3*(1 mole/159.69 g)= moles of Fe2O3

moles of Fe2O3 *(3 moles of O2/2 moles of Fe2O3)=moles of O2

moles of O2*(32.0g of O2/1mole)= mass of O2

Answer:

all objects will remain at rest, or will continue to move at a constant speed in the same velocity unless acted upon by an unbalanced force. This property is called interia

Explanation:

The statement the most abundant isotope of Hydrogen has a mass of 1 amu is wrong.

The average atomic mass could be obtained as the sum of the products of the percentage abundance of each of the hydrogen isotopes and the mass of the isotope.

We know that every element has isotopes. In every sample of the atom, there are various isotopes of the element. Thus the average atomic mass must take into account the masses of all these isotopes.

As such, the statement the most abundant isotope of Hydrogen has a mass of 1 amu is wrong.

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